1. A book resting on a shelf was found
to have a gravitational potential energy
of 12 J relative to the ground. If the
book falls to the ground, neglecting air
resistance, what is the kinetic energy of
the book just as it was about to hit the
ground?

Answer:

How will you infer with the help of an experiment that the same current flows through every part of the circuit containing three resistors R1 ,R2 and R3 in series connected to a battery of V volt.

we can connect voltmeter across each resistor

V = V1 + V2 + V3

I1 = current across resistor R1

I1 = V1/R1

similarly

I2 = current across resistor R2

I2= V2/R2

I3 = current across resistor R3

I3 = V3/R3

we will see that

I1 = I2 = I3

also it will be equal to V/(R1 + R2+R3)

Answer:

 Using the Fundamental Equation of Wave, we have:

Explanation:

Answer:

zoom in

Explanation:

Answer:

well for me

Explanation:

I think

Big Chungus is the greatest game know to man currently it is only available on ps4, dispite the fact I am loyal to Xbox I couldn’t help but buy a ps4 for it I have found a review from a Redditor

And also he's presence scared everyi

Answer:

big chungus is not funny, its just a big rabbit.

Explanation:

Answer:

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.

Answer:

Due to brown knob which controls its angle.

Explanation:

When water comes out at an angle instead of going straight up, water does not shoot as high as before because its speed is controlled by the brown knob in order to throw water in another angle. If we adjust the brown knob present at the opening of hose pipe in a straight angle the water shoot very high because water moves with high pressure and no barrier is present between its way.

Answer:

Dark matter:

- Doesn't interact with baryonic matter.

- It has not been observed directly

- dark matter does not absorb, reflect or even emit light, thereby making it to be extremely hard to spot. Therefore, it does not interact with electromagnetic radiation.

Explanation:

Dark matter:

- Doesn't interact with baryonic matter.

- It has not been observed directly

- dark matter does not absorb, reflect or even emit light, thereby making it to be extremely hard to spot. Therefore, it does not interact with electromagnetic radiation.

Baryonic matter:

- Has been observed directly because it includes nearly all the matter that we see in the world daily.

- It interacts with baryonic matter

- interacts with electromagnetic radiation

Dark Matter:

Baryonic Matter:

Dark matter can be defined as often invisible substances that are difficult to spot because they don't absorb, emit or reflect light.

Hence, dark matter do not affect human view because they do not interact or interfere with electromagnetic radiation (force).

Although, humans can see right through the (weakly interacting) dark matter but it has not been observed directly.

Baryonic matter can be defined as a dark matter that is made up of baryons such as neutrons, and protons. Also, they are ordinary matter (both fermions and hadrons), as distinct from exotic forms.

In conclusion. baryonic matter has been observed directly and it can interact with electromagnetic radiation.

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Answer: the value of the required thickness is 41.4 cm

Explanation:

Given that;

R1 = 17

R2 = 44

L1 = 16

L2 = ?  

we know that, from thermal conductivity formula

P = 1 / R

P = k / L  

1 / R = k / L    

since k of a distinct material  is constant,

we can take

L / R = constant

L1 / R1 = L2 / R2  

L1R2 = L2R1

L2 = (L1 × R2) / R1  

so we substitute

L2 = (16 × 44) / 17

L2 = 704 / 17

L2 = 41.4 cm  

Therefore the value of the required thickness is 41.4 cm  

Answer:

Time, t = 5 seconds.

Explanation:

Given the following data;

Initial velocity = 30m/s

Final velocity = 55m/s

Acceleration = 5m/s²

To find the time, we would use the first equation of motion;

[tex] V = U + at[/tex]

Where;

Making time, t the subject of formula, we have;

[tex] t = \frac{V - U}{a}[/tex]

Substituting into the equation, we have;

[tex] t = \frac{55-30}{5}[/tex]

[tex] t = \frac{25}{5}[/tex]

Time, t = 5 seconds.

Therefore, it would take the bike 5 seconds to reach the final velocity.

Answer:

The density of the block is 1113.216 kilograms per cubic meter.

The weight of the block is 43669.237 newtons.

Explanation:

According to the Archimedes' Principle, the drag force experimented by the metal block is equal to the weight of the volume of water displace by the block. Besides, the block has a weight that cannot be neglected and experiments a tension from the cable. Given that the metal block is suspended, then we could consider that block is at rest.

From Newton's Laws of Motion we obtain the following equation of equilibrium:

[tex]\Sigma F = T-\rho_{m}\cdot V_{m}\cdot g + \rho_{w}\cdot V_{m}\cdot g = 0[/tex] (1)

Where:

[tex]T[/tex] - Tension on the cable, measured in newtons.

[tex]\rho_{w}[/tex], [tex]\rho_{m}[/tex] - Densities of salt water and the metal block, measured in kilograms per cubic meter.

[tex]V_{m}[/tex] - Volume of the metal block, measured in cubic meters.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]T = 42600\,N[/tex], [tex]\rho_{w} = 1030\,\frac{kg}{m^{3}}[/tex], [tex]V_{m} = 4\,m^{3}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the density of the block is:

[tex]T+\rho_{w}\cdot V_{m}\cdot g = \rho_{m}\cdot V_{m}\cdot g[/tex]

[tex]\rho_{m} = \frac{T+\rho_{w}\cdot V_{m}\cdot g}{V_{m}\cdot g}[/tex]

[tex]\rho_{m} = \frac{42600\,N+\left(1030\,\frac{kg}{m^{3}} \right)\cdot (4\,m^{3})\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{(4\,m^{3})\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\rho_{m} = 1113.216\,\frac{kg}{m^{3}}[/tex]

The density of the block is 1113.216 kilograms per cubic meter.

Lastly, the weight of the block ([tex]W[/tex]), measured in newtons:

[tex]W = \rho_{m}\cdot V_{m}\cdot g[/tex] (2)

[tex]W = \left(1113.216\,\frac{kg}{m^{3}}\right)\cdot (4\,m^{3}) \cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]

[tex]W = 43669.237\,N[/tex]

The weight of the block is 43669.237 newtons.

Answer:

C. Nuclear fission of uranium-235

Answer:

C. Nuclear fission of uranium-235

Explanation:

Give thanks to above me

Answer:

The distance between gas species are assumed to be large.

Explanation:

Hello!

In this case, since the ideal gas condition is a hypothetical state of gases at which they are at low pressure and high temperature, because it is assumed the molecules are neither attracted nor repelled by each other, we can infer that the correct statement is "the distance between gas species are assumed to be large" because the low pressure and high temperature ensure the molecules are far away from each other and therefore allowing the ideal equation to be used to model the case, otherwise a rigorous equation of state such as Peng-Robinson, Redlich-Kwong and other should be used to model it as gases actually undergo interaction between their molecules.

Best regards!

The angle between incident ray and reflected ray is 60 degree. the value of angle of incidence and angle of reflection is 30 degree

what do u need help with here?

Answer:

1500kg

Explanation:

Assuming that the women push the car in the same direction, then the total force is:

Fnet = 425 N ⋅  3

= 1275 N

To find the mass, we use Newton's second law of motion, which states that,

F = ma

where:

   ·F is the force applied in newtons

   ·m is the mass of the object in kilograms

   ·a is the acceleration of the object in meters per second squared.

So we get:

        F

m=  ⁻⁻⁻⁻⁻

        a

     1275N

= ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

  0.85 m/s²

=  1500 kg

Answer:

10,30,40,50 and above

The average volume of each of the coin is 2.5 × 10⁻⁶m³.

Given the data in the question;

To determine the average volume of each coin, we calculate change in volume after the coins were dropped into the graduated cylinder.

[tex]\delta V = v_2 - v_1\\\\\delta V = 1.0*10^{-4}m^3 - 7.5*10^{-5}m^3\\\\\delta V = 2.5*10^{-5}m^3\\[/tex]

Hence, [tex]\delta V = volume\ of\ the\ 10 coins[/tex]

Now, volume of each of the coins will be;

[tex]V_{each\ coins} = \frac{\delta V}{n_c} \\\\V_{each\ coins} = \frac{2.5*10^{-5}m^3}{10} \\\\V_{each\ coins} = 2.5*10^{-6}m^3[/tex]

Therefore, the average volume of each of the coin is 2.5 × 10⁻⁶m³.

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Answer:

is this for a project im a little confused

Answer:

Some of the hot water evaporated and became a gas called water vapor and created condensation on the sides of the bottle. It rose to the top of the solid ice cube and the cold cooled the gas turning it back into a liquid.

Explanation:

Answer:

The kinetic energy lost in the collision is 48 J

Explanation:

Given;

mass of the first ball, m₁ = 2.0 kg

mass of the second ball, m₂ = 6.0 kg

initial speed of the first ball, u₁ = 12 m/s

initial speed of the second ball, u₂ = 4 m/s

let v be the final velocity of the two balls after the inelastic collision

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

2 x 12 + 6 x 4 = v(2 + 6)

48 =  8v

48 / 8 = v

v = 6 m/s

The initial kinetic energy of the balls is calculated as;

K.E₁ = ¹/₂m₁u₁² + ¹/₂m₂u₂²

K.E₁ = ¹/₂(2)(12²) + ¹/₂(6)(4)²

K.E₁ = 144 + 48

K.E₁ = 192 J

The final kinetic of the balls is calculated as;

K.E₂ = ¹/₂(m₁ + m₂)(v²)

K.E₂ = ¹/₂(2 + 6)(6²)

K.E₂ = ¹/₂(8)(6²)

K.E₂ = 144 J

The lost in kinetic energy of the balls is K.E₂ - K.E₁ = 144 J - 192 J = -48 J

Therefore, the kinetic energy lost in the collision is 48 J

Answer:

[tex]162\ N[/tex]

Explanation:

[tex]We\ are\ given\ that,\\Mass\ of\ the\ box=72\ kg\\Distance/Displacement\ travelled\ by\ the\ box\ during\ the\ application\ of\\ Force=13\ m\\Time\ taken\ for\ it\ to\ displace=3.4 \seconds\\Now,\\As\ we\ know\ that,\\Force=Mass*Acceleration\\In\ order\ to\ know\ force\ we\ need\ to\ know\ the\ acceleration.\ Lets\ find\\ that\ out.\\We\ would\ use\ Newton's\ Third\ Equation\ Of\ Motion\ and\ Newton's\\ First\ Equation\ Of\ Motion:\\2as=v^2-u^2\\v=u+at[/tex]

[tex]Hence,\\First\ lets\ consider\ Newtons\ First\ Equation\ Of\ Motion:\\v=u+at\\v-u=at\\Hence\ now\ lets\ move\ on\ to\ Newton's\ Third\ Law\ Of\ Motion:\\2as=v^2-u^2\\2as=(v+u)(v-u)\\Substituting\ (v-u)=at,\\2as=at(v+u) \\Hence,\ as\ the\ body\ moves\ from\ rest,\ u=0\\So,\\2as=at*v\\Cancelling\ a\ at\ both\ the\ sides\ we\ get,\\2s=vt\\Hence,\\Lets\ plug\ in\ the\ values\ of\ Displacement\ and\ Time,\ Shall\ we?\\Hence,\\2*13=3.4v\\26=3.4v\\\frac{26}{3.4}=v\\v \approx 7.647\ m/s[/tex]

[tex]Now,\\As\ we\ know\ that,\\a=\frac{v-u}{t} [Equation\ for\ acceleration]\\Hence,\\a=\frac{v}{t} [As\ u=0]\\Hence,\\Acceleration=\frac{7.647}{3.4} \\Acceleration \approx 2.25\ m/s^2\\[/tex]

[tex]Hence,\\Now,\\As\ by\ using\ expression\ for\ Force,\\Force= Mass*Acceleration\\Here,\\Force\ exerted\ on\ the\ box=72*2.25= 162 N[/tex]

Explanation:

Sodium is a chemical element with the symbol Na (from Latin "natrium") and atomic number 11. It is a soft, silvery-white, highly reactive metal. Sodium is an alkali metal, being in group 1 of the periodic table. ... The free metal does not occur in nature, and must be prepared from compounds.

Explanation:

Sodium is an alkali metal, being in group 1 of the periodic table.

Answer:

too slow

Explanation:

so its d

To solve this we must be knowing each and every concept related to continent. Therefore, the correct option is option D among all the given options.

A huge landmass that is distinguished from other landmasses by seas is referred to be a continent. Seven continents make up the Earth's land mass. Some are connected and split merely by an arbitrary line, while others, like a large island, are completely encircled by sea.

Millions of years is required for the formation of a continent. The lithosphere's separate plates move apart from one another at a pace of three to twenty centimeters (1 to 8 inches) every year. Scientists might use a model to show the movement of the continents as the actual movement is too slow.

Therefore, the correct option is option D among all the given options.

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                                    ...................

Answer:

Width of a box, [tex]l=6.41\times 10^{-15}\ m[/tex]

Explanation:

The ground level energy of a proton in a box is, E = 5 MeV

[tex]E =5\times 10^6\ eV\\\\=5\times 10^6\times 1.6\times 10^{-19}\\\\=8\times 10^{-13}\ J[/tex]

Energy in a box is given by :

[tex]E=\dfrac{n^2h^2}{8ml^2}[/tex]

For ground state, n = 1

m is mass of proton

h is Planck's constant

l is width of the box

[tex]l^2=\dfrac{n^2h^2}{8mE}\\\\l^2=\dfrac{1^2\times (6.63\times 10^{-34})^2}{8\times 1.67\times 10^{-27}\times 8\times 10^{-13}}\\\\l=\sqrt{\dfrac{1^{2}\times(6.63\times10^{-34})^{2}}{8\times1.67\times10^{-27}\times8\times10^{-13}}}\\\\l=6.41\times 10^{-15}\ m[/tex]

So, the width of the bx is [tex]6.41\times 10^{-15}\ m[/tex].

The width of the box, for the ground level energy with which the particles in a nucleus are bound, is 6.41×10⁻¹⁵ m.

The energy in a box can be calculated with the following formula.

[tex]E=\dfrac{n^2h^2}{8mL^2}[/tex]

Here, (E) is the energy at the nth state, (n) n is the quantum number, (h) is plank's constant and (L) is the width of the box.

The proton is in a box of width L. The width of the box be for the ground level energy to be 5.0 MeV, a typical value for the energy with which the particles in a nucleus are bound.

The energy of the box is at ground level. Then the value of nth state will be 1. It is known that the value of plank's constant is 6.63×10⁻³⁴ m²kg/s.

Put this values in the above formula as,

[tex]8\times10^{-13}=\dfrac{(1)^2(6.63\times10^{-34})^2}{8(1.67\times10^{27})(l)^2}\\l=6.41\times10^{-15}\rm\; m[/tex]

Thus, the width of the box, for the ground level energy with which the particles in a nucleus are bound, is 6.41×10⁻¹⁵ m.

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Answer:

The room become bright in the day by a process call scattering of light or Rayleigh scattering.

Explanation:

It is called Rayleigh scattering or scattering of light because Rayleigh scattering is the scattering if light or electromagnetic radiation by smaller particles which have radius of less than 110 nanometer in a medium and the wavelengths of the electromagnetic. Wave or light remain unchanged. The scattering of light occur in the day time in the room and this bring of brighten up of the room.

Answer:

641 nm.

Explanation:

Given that,

A transmission grating has 5200 slits/cm.

We need to find the longest wavelength that can be observed in the third order. Using grating equation as follows :

[tex]d\sin\theta=m\lambda[/tex] ...(1)

d is slit spacing

No fo slit per unit length :

[tex]N={5200}\ slit/cm\\\\=520000\ slits/m[/tex]

We know that, N = 1/d

For longest wavelength, θ = 90°

From equation (1)

[tex]\dfrac{\sin\theta}{m\lambda}=\dfrac{1}{d}\\\\520000=\dfrac{\sin(90)}{3\lambda}\\\\\lambda=\dfrac{1}{520000\times 3}\\\\=6.41\times 10^{-7}\ m\\\\=641\ nm[/tex]

Hence, the longest wavelength in third order for a transmission grating is 641 nm.

Answer:

57.6

Explanation:

"Significant figures" refer to figures that have an actual contribution to a number's value.

They refer to all digits except those with "leading zero," which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are 234.

The rule for adding and subtracting significant figures is to round off the answer to the least number of decimal places. However, when it comes to multiplying and dividing significant figures, you have round off the answer to the least number of significant digits.

Let's solve.

 21.4

+15

 17.17

 4.003

57.573

Let's now round off to the least number of decimal places, which is the tenths. Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6

Explanation:

In quantum tunneling through a brier, the energy of the tunneled particle is same but the probability amplitude is decreased.

The expression for the probability of tunneling is expressed as follows:

[tex]T=16 \frac{E}{U_{0}}\left(1-\frac{E}{U_{0}}\right) e^{-2 \sqrt{\frac{2 m\left(U_{0}-E\right)}{h}} L}[/tex]

Here, T is the transmission probability; E is the kinetic energy, U_{0} is the barrier height, $m$ is the mass of the electron, and L is the width of the barrier.