1. Calculate the amount buoyant force that will be
applied to a string of 2 inch OD 1.688 ID open end
tubing when it reaches 7000 ft in a 10700 ft. TVD; 11500
ft. MD well. The density of the working fluid of the well
is 9.6 ppg.
A
B
C
D
10967 lbs
4822 lbs
5183 lbs
3155 lbs

The interest earned on GH 2500 at 5% p.a. for 4 years is GH 500.
The principal that gains an interest of GH 2590 in 5 years at 7% per annum is approximately GH 7400.

What is simple interest ?

Simple interest is a type of interest that is calculated on the principal amount of a loan or investment at a fixed rate for a specified period of time. It is based only on the principal amount, and does not take into account any interest earned on previous periods.

The formula for simple interest is:

I = P * R * T

where:

According to the question:
a) Using the simple interest formula, we have:

I = (P * R * T) / 100

Substituting P = GH 2500, R = 5%, and T = 4 years, we get:

I = (2500 * 5 * 4) / 100 = 500

Therefore, the interest earned on GH 2500 at 5% p.a. for 4 years is GH 500.

b) Using the same formula, we can solve for the principal P:

I = (P * R * T) / 100

2590 = (P * 7 * 5) / 100

2590 = (35P) / 100

35P = 2590 * 100

P = (2590 * 100) / 35

P ≈ GH 7400

Therefore, the principal that gains an interest of GH 2590 in 5 years at 7% per annum is approximately GH 7400.

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The given function rand() % 50 + 5  will generate random numbers in the range of 5 to 54 inclusive.

The code snippet you provided contains a syntax error.

It seems like there is a typo between the '%' and '5' characters.

Assume that it meant to write,

rand() % 50 + 5;

Assuming that rand() function generates a random integer between 0 and RAND_MAX

Which may vary depending on the implementation.

The expression rand() % 50 will generate a random integer between 0 and 49 inclusive.

Then, adding 5 to the result will shift the range of the generated numbers up by 5.

Producing a random integer between 5 and 54 inclusive.

Therefore, the range of the random numbers generated by the code snippet rand() % 50 + 5 will be from 5 to 54 inclusive.

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Answer:

Step-by-step explanation:

t+t+t= 3t

3t = 12

12/3=t

4=t

The answer of the given question based on statistics to find the  most appropriate size of the bin from the data the answer is , the most appropriate bin size for this data set would be A. 69.

Statistics is  the practice of collecting, analyzing, and interpreting the data. It involves  use of mathematical tools and techniques to gather insights and knowledge from numerical and categorical information. Statistics is essential in many fields, like  business, medicine, social sciences, and engineering, as it enables researchers to draw conclusions from data and make informed decisions based on evidence.

It includes topics like probability, hypothesis testing, regression analysis, and data visualization. The application of statistical methods can help identify patterns, relationships, and trends in data, allowing researchers to make predictions and solve problems.

To determine the appropriate bin size, we need to consider the range of values in the data. The range is the difference between the largest and smallest values, which in this case is 192 - 123 = 69.

To get the bin size, we divide the range by the number of bins. So the bin size would be 69/4 = 17.25. However, since we can't have a fraction of a unit for bin size, we should round up to the nearest whole number. Therefore, the most appropriate bin size for this data set would be A. 69.

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The answer of the given question based on statistics to find the  most appropriate size of the bin from the data the answer is , the most appropriate bin size for this data set would be A. 69.

Statistics is  the practice of collecting, analyzing, and interpreting the data. It involves  use of mathematical tools and techniques to gather insights and knowledge from numerical and categorical information. Statistics is essential in many fields, like  business, medicine, social sciences, and engineering, as it enables researchers to draw conclusions from data and make informed decisions based on evidence.

It includes topics like probability, hypothesis testing, regression analysis, and data visualization. The application of statistical methods can help identify patterns, relationships, and trends in data, allowing researchers to make predictions and solve problems.

To determine the appropriate bin size, we need to consider the range of values in the data. The range is the difference between the largest and smallest values, which in this case is 192 - 123 = 69.

To get the bin size, we divide the range by the number of bins. So the bin size would be 69/4 = 17.25. However, since we can't have a fraction of a unit for bin size, we should round up to the nearest whole number. Therefore, the most appropriate bin size for this data set would be A. 69.

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The complete question is as fpllows:

123, 185, 143, 137, 192, 185, 129, 143, 154, 165, 143, 138, 187, 176

A bin size of is most appropriate for the data shown above.

A. 69

B. 2

C. 10

D. 1​

The conditions in which is it not appropriate to assume that the sampling distribution of the sample mean is approximately normal : (C) A random sample of 10 taken from a population distribution that is skewed to the right.

In statistics, the normal or Gaussian distribution is a continuous probability distribution for real-valued random variables.

The normal distribution is important in statistics and is often used in the natural and social sciences to represent real-valued random variables whose distribution is unknown. Their importance is partly due to the central limit theorem. It states that in some cases the average of many samples (observations) of a random variable with finite mean and variance is itself a random variable - whose distribution converges to a normal distribution as the size of the l sample increases.

Now,

If we look at the options given below, we see that the random samples in options A and B are normally distributed, so their sample means will be approximately normally distributed.

Similarly, option E indicates that the population is uniform, so the sample mean will also be approximately normal.

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Answer:

A. For g(x) to be differentiable, the derivative of g(x) must exist at every point in its domain. The derivative of a sin x + b is a cos x, which exists for all values of x. Therefore, any values of a and b will make g(x) a differentiable function.

B. To find the equation of the tangent line to g(x) at x = 2π, we need to find the slope of the tangent line, which is the derivative of g(x) evaluated at x = 2π.

g'(x) = a cos x, so g'(2π) = a cos(2π) = a

Therefore, the slope of the tangent line at x = 2π is a. To find the y-intercept of the tangent line, we can plug in x = 2π into g(x) and subtract a times 2π:

y = g(2π) - a(2π)

= (a sin 2π + b) - a(2π)

= b - 2aπ

So the equation of the tangent line is:

y = ax + (b - 2aπ)

C. We can use the tangent line equation to approximate g(6) by plugging in x = 6 and using the equation of the tangent line at x = 2π.

First, we need to find the value of a. Since g'(2π) = a, we can use the derivative of g(x) to find a:

g'(x) = a cos x

g'(2π) = a cos (2π) = a

g'(x) = a = 2

Now, we can plug in a = 2, b = any value, and x = 2π into the tangent line equation:

y = ax + (b - 2aπ)

g(2π) = 2πa + (b - 2aπ)

a sin 6 + b ≈ 12π + (b - 4π)

Since we don't know the value of b, we can't find the exact value of g(6), but we can use the approximation:

g(6) ≈ 12π + (b - 4π)

The calculated value of the indicated missing length x in the right triangle is 12

Given the right triangle

We can start by calculating the value of x using the following equivalent ratio

x : 9 = 25 - 9 : x

Evaluate the difference

This gives

x : 9 = 16 : x

Next, we express the equivalent ratio as a fraction

So, the ratio becomes

x/9 = 16/x

Cross multiply the equation to calculate x

So, we have the following

x * x = 9 * 16

Evaluate the product

x² = 144

Take the square root of both sides

So, we have the solution to be

y = 12

Hence, the value of x is 12

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For Fund T: Expected Return = 11.32% For Fund U: Expected Return = 8.94%,,For Fund T:Expected return (11.32%) > Our forecasted return (8%) .

Thus, Fund T is priced below the SML and is undervalued. For Fund U Expected return (8.94%) < Our forecasted return (10%) Thus, Fund U is priced above the SML and is overvalued and  Fund T is undervalued and Fund U is overvalued.

a. To calculate the expected return for each mutual fund according to the CAPM, we can use the following formula:

Expected Return = Risk-free rate + (Market Risk Premium × Beta)

For Fund T:

Expected Return = 3.9% + (6.1% × 1.20) = 11.32%

For Fund U:

Expected Return = 3.9% + (6.1% × 0.80) = 8.94%

b. To determine whether Fund T and Fund U are currently priced to fall directly on the security market line (SML), above the SML, or below the SML, we need to compare their expected returns with our own return forecasts. Let's assume that we have forecasted returns of 8% for Fund T and 10% for Fund U.

If the expected return for a mutual fund is higher than our own return forecast, it is considered to be priced below the SML and thus undervalued. Conversely, if the expected return is lower than our own forecast, the mutual fund is considered to be priced above the SML and therefore overvalued. If the expected return and our own forecast are the same, the mutual fund is priced directly on the SML and is considered to be properly valued.

Using the CAPM expected returns calculated in part (a), we can compare with our own return forecasts:

For Fund T:

Expected return (11.32%) > Our forecasted return (8%)

Thus, Fund T is priced below the SML and is undervalued.

For Fund U:

Expected return (8.94%) < Our forecasted return (10%)

Thus, Fund U is priced above the SML and is overvalued.

c. Based on our analysis, Fund T is undervalued and Fund U is overvalued. This suggests that investors should consider buying Fund T, as it is expected to provide higher returns than the market return, while Fund U may not provide sufficient returns to compensate for the higher risk. However, it is important to note that other factors such as fund expenses, management quality, and investment strategy should also be considered when making investment decisions.

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1. Select the negative square root as sine function is negative for sin 195°. 2. Select the positive square root as cosine function is positive for cos 58°. 3. Select the negative square root as tangent function is negative for tan 225°.

4. Select the negative square root as sine function is negative and cosine of 20° is positive for sin(-10°) = √(1-cos(-20°))/2.

1. Since 195° is in the third quadrant, the sine function is negative. Therefore, we should select the negative square root.

2. Since 58° is in the first quadrant, the cosine function is positive. Therefore, we should select the positive square root.

3. Since 225° is in the third quadrant, the tangent function is negative. Therefore, we should select the negative square root.

4. Since -10° is in the fourth quadrant, the sine function is negative. Also, since cosine is an even function, cos(-20°) = cos(20°), which is positive since 20° is in the first quadrant. Therefore, we should select the negative square root.

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Answer:

Table solves f(x)=g(x)

Victor.

Given f(x)=x^2 - 6x + 8 and g(x) = x - 2, solve f(x) = g(x) using a table of values.

Please show your work.

To solve f(x) = g(x) using a table of values, we can create two columns, one for f(x) and one for g(x), and fill in values of x and the corresponding values of f(x) and g(x) until we find a value of x that makes f(x) equal to g(x).

Let's start by creating the table:

x f(x) = x^2 - 6x + 8 g(x) = x - 2

0 8 -2

1 3 -1

2 0 0

3 1 1

4 0 2

5 3 3

Looking at the table, we see that f(2) = 0 and g(2) = 0, so the solution to f(x) = g(x) is x = 2.

Therefore, the solution to f(x) = g(x) is x = 2.

In linear equation, 48720 is  the tread life covered under the warranty.

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

1)  µ = 60,000 and σ = 6000 miles.

P ( X >= 55000 )  = 1 - P ( X < 55000 )

Standardizing the  value

 Z = ( X - μ)/σ

  Z = ( 55000 - 60000 ) / 6000

Z = -0.83

 P((X - μ)/σ > ( 55000 - 60000)/6000

P ( Z > -0.83 )

P ( X >= 55000 )  = 1 - P ( Z < -0.83 )

P ( X >= 55000 )  =  1 - 0.2033

P ( X >= 55000 )  = 0.7967

Part v)   What proportion of the tires will need to be replaced under warranty?

 X ~ N ( μ = 60000 , σ = 6000 )

P ( X < 52000 )

Standardizing the value

  Z = ( X - μ)/σ

  Z = ( 52000 - 60000 ) / 6000

Z = -1.33

   P((X - μ)/σ > ( 55000 - 60000)/6000

P ( X < 52000 ) =  P ( Z < -1.33 )

P ( X < 52000 ) = 0.0918

Part c)  If you buy 36 tires,  what is the probability that the  average life of your 36 tires will exceed  61,000?

     X ~ N ( μ = 60000 , σ = 6000 )

 P ( X > 61000 )  = 1 - P ( X < 61000 )

Standardizing the  value

   Z = ( X - μ)/(σ/√n)

  Z = (61000 - 60000)/(6000/√36)

    Z = 1

 P(( X - μ)/(σ/√n) > (61000 - 60000)/(6000/√36)

P ( Z > 1 )

P ( X > 61000 )  = 1 - P ( Z < 1 )

P ( X > 61000 )  = 1 - 0.8413

P ( X > 61000 )  =  0.1587

Part d)  The manufacturer is willing to replace only 3% of its tires under a warranty program involving tread life.  Find the tread life covered under the warranty.

P ( Z < ? ) = 3% = 0.03

Looking for the probability 0.03 in standard normal table to find the critical value Z

Z = - 1.88

Z = (X - μ)/σ

- 1.88 = ( X - 60000)/6000

 X = 48720

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Answer:

4/3 or d

Step-by-step explanation:

Answer:

We can use similar triangles to solve this problem. Let's denote the height of the tree as h. Then, we can set up the following proportion:

h / 120 = 6 / 10

Cross-multiplying and simplifying, we get:

10h = 720

h = 72

Therefore, the height of the tree is 72 feet

Answer:45

Step-by-step explanation:

Answer:

A' = (1, 0)

B' = (0, -3)

C' = (3, -1)

Step-by-step explanation:

4 units right is adding 4 to the x value.

1 unit up is adding 1 to the y value.

A' = (1, 0)

B' = (0, -3)

C' = (3, -1)

Hope this helps!

Since I added three 4 kg weights and one 1 kg weight to the left side of the fulcrum, the blue mass is 13 kg and is completely balanced. In light of this, the blue mass's mass is 13 kg.

To keep the beam horizontal for a beam balance, a body with gravitational mass m1 and a standard weight of m2 are placed in the left and right pans, respectively. If a1 = a2, then m1 = m2, and vice versa. Alternatively, the gravitational mass of the body in the left pan is equal to the gravitational mass in the right pan.

For calibrating masses between 13 mg and 4+1 = 5 kg, a beam balance is utilised. Depending on the calibre and sharpness of the knife edge used to make the pivot, a given measurement can be made with a given resolution and accuracy.

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The actual question is :

Determine the amount of mass possessed by the blue mass. Show your data and explainyour reasoning or show the math. The amount of the blue mass is 13 kg since I placed three 4 kg and 1 kg on the left side of the fulcrum and it is completely balance . Therefore the mass possessed by the blue mass is 13 kg .

(a) The area under the standard normal curve to the left of 1.73 is 0.9582.

(b) The area under the standard normal curve to the left of -0.69 is 0.2454.

(c) The area under the standard normal curve to the right of 1.3 is 0.0968.

(d) The area under the standard normal curve to the right of -2.82 is 0.9974.

(e) The area under the standard normal curve between -2.22 and 0.52 is 0.6851.

(f) The area under the standard normal curve between -1 and 1 is 0.6826.

(g) The area under the standard normal curve between -4 and 4 is 0.9998.

(a) Using a standard normal table, the area under the standard normal curve to the left of 1.73 is 0.9582.

(b) Similarly, the area under the standard normal curve to the left of -0.69 is 0.2454.

(c) The area to the right of 1.3 is the same as the area to the left of -1.3. Using a standard normal table, this area is 0.0968.

(d) The area to the right of -2.82 is the same as the area to the left of 2.82. Using a standard normal table, this area is 0.9974.

(e) To find the area under the standard normal curve between -2.22 and 0.52, we need to find the area to the left of 0.52 and subtract the area to the left of -2.22. Using a standard normal table, we find that the area to the left of 0.52 is 0.6990 and the area to the left of -2.22 is 0.0139. Therefore, the area between -2.22 and 0.52 is 0.6990 - 0.0139 = 0.6851.

(f) To find the area under the standard normal curve between -1 and 1, we need to find the area to the left of 1 and subtract the area to the left of -1. Using a standard normal table, we find that the area to the left of 1 is 0.8413 and the area to the left of -1 is 0.1587. Therefore, the area between -1 and 1 is 0.8413 - 0.1587 = 0.6826.

(g) The area under the standard normal curve between -4 and 4 is the same as the area to the left of 4 minus the area to the left of -4. Using a standard normal table, we find that the area to the left of 4 is 0.9999 and the area to the left of -4 is 0.0001. Therefore, the area between -4 and 4 is 0.9999 - 0.0001 = 0.9998.

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The cosine of 330 degrees is sqrt(3)/2.

To find the cosine of 330 degrees, we need to use the concept of reference angles. A reference angle is the acute angle formed between the terminal side of an angle and the x-axis.

First, we need to determine the reference angle for 330 degrees. Since 330 degrees is in the fourth quadrant, we can subtract it from 360 degrees to find the equivalent acute angle in the first quadrant

360 degrees - 330 degrees = 30 degrees

Therefore, the reference angle for 330 degrees is 30 degrees.

Next, we need to use the trigonometric function values for angles in special right triangles. For a 30-60-90 degree triangle, the ratios of the sides are

sin(30 degrees) = 1/2

cos(30 degrees) = sqrt(3)/2

tan(30 degrees) = 1/sqrt(3)

Since the reference angle for 330 degrees is 30 degrees, we can use the cosine value of 30 degrees to find the cosine value of 330 degrees

cos(330 degrees) = cos(360 degrees - 30 degrees) = cos(30 degrees) = sqrt(3)/2

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The given question is incomplete, the complete question is:

Use reference angles and the trigonometric function values for angles in special right triangles to find each trigonometric value . cos 330 degrees

Answer:

[tex] 9^{\frac{7}{8}} [/tex]

Step-by-step explanation:

[tex] (9^{\frac{1}{4}})^{\frac{7}{2}} = [/tex]

[tex] = 9^{\frac{1}{4} \times \frac{7}{2}} [/tex]

[tex] = 9^{\frac{7}{8}} [/tex]

The approximate value of R'(5) is -716 vehicles per hour per hour.

To approximate Rʹ(5), we can use the formula for the average rate of change

Rʹ(5) ≈ (R(6) - R(4))/(6-4)

We use the values given in the table to get

R(6) = 3010 vehicles per hour

R(4) = 3442 vehicles per hour

Therefore, Rʹ(5) ≈ (3010 - 3442)/(6-4) = -716 vehicles per hour per hour.

So, the approximate rate of change of the rate at which vehicles cross the bridge at 5:00 a.m. is -716 vehicles per hour per hour. This means that the rate at which vehicles cross the bridge is decreasing at a rate of 716 vehicles per hour every hour around 5:00 a.m.

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The given question is incomplete, the complete question is:

On a certain weekday, the rate at which vehicles cross a bridge is modeled by the differentiable function R for 0 ≤ t ≤ 12, where R(t) is measured in vehicles per hour and t is the number of hours since 7:00 a.m. (t = 0). Values of R(t) for selected values of t are given in the table above. t(hours) 0 2 4 6 8 10 12 R(t) (vehicle per hours ) 2935 3653 3442 3010 3604 1986 2201 . Use the data in the table to approximate Rʹ(5)

The Venn diagram here shows the cardinality of each set. The cardinality of the  n(A∩B∩C) is 6.

Venn diagrams can be used to visually represent many different types of information, such as mathematical relationships, logical relationships, and sets of data. They are a useful tool for organizing and visualizing complex information.

A Venn diagram is a graphical representation of the relationships between different sets of objects. It consists of overlapping circles or other shapes that represent each set. The portions of the circles that overlap represent the objects that are in common to the corresponding sets.

Using the principle of inclusion-exclusion, we have:

n(A∩B∩C) = n(An) + n(B∩C) + n(C∩A) - 2n(A∩B) - 2n(B∩C) - 2n(C∩A) + 3n(A∩B∩C)

Substituting the given values, we get:

n(A∩B∩C) = 10 + 9 + 7 - 2(4) - 2(9) - 2(7) + 3(3) = 6

Therefore, n(A∩B∩C) = 6.

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The nearest whole number, which is 9. So the middle apartment number for house 17 is 9.

An apartment is a self-contained housing unit that occupies only part of a building. Apartments typically consist of one or more bedrooms, a kitchen, a living room, and a bathroom, and usually include amenities such as heating, air conditioning, and appliances. Apartments are usually rented, though some are owned. Living in an apartment can be a great way to save money, as apartments are often more affordable than larger homes.

The rule is to take the house number and divide it by two and round up to the nearest whole number. This will give the middle apartment number. For example, if the house number is 17, divide it by two which equals 8.5, and then round up to the nearest whole number, which is 9. So the middle apartment number for house 17 is 9.

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The difference of the medians as a multiple of the interquartile range is 0.5,So the correct answer is option (A) 0.5.

The median is a measure of central tendency that represents the middle value in a data set when the values are arranged in numerical order.

For example, consider the data set {3, 5, 2, 6, 1, 4}. When the values are ordered from smallest to largest, we get {1, 2, 3, 4, 5, 6}. The median in this case is the middle value, which is 3.

We can first find the medians and interquartile ranges of the two dot plots.

For Mr. Wilson's class:

Median = 12

Q1 = 10

Q3 = 14

IQR = Q3 - Q1 = 14 - 10 = 4

For Mr. Watson's class:

Median = 10

Q1 = 8

Q3 = 12

IQR = Q3 - Q1 = 12 - 8 = 4

The difference of the medians is |12 - 10| = 2. Therefore, the difference of the medians as a multiple of the interquartile range is:

$$\frac{2}{4} = \boxed{0.5}$$

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Marvin won the game by 30 points.

Marvin tossed three times and got the following numbers: 5, 2, 4.

For the first toss, he tossed a 5, which is 4 or above, so he gains 4 times the number that turns up. Therefore, he gains:

4 x 5 = 20

For the second toss, he tossed a 2, which is below 3, so he loses 3 times the number that turns up. Therefore, he loses:

3 x 2 = 6

For the third toss, he tossed a 4, which is 4 or above, so he gains 4 times the number that turns up. Therefore, he gains:

4 x 4 = 16

To find out whether Marvin won or lost the game, we need to add up his gains and losses.

His total gain is:

20 + 16 = 36

His total loss is:

6

Therefore, his net gain is:

36 - 6 = 30

Marvin won the game by 30 points.

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Answer: 32

Step-by-step explanation: got you broski

The best description of that term 29.4 in the expression is the initial velocity of the test shell. That is option B.

A pyrotechnician is defined as the individual that has been trained for safe storage, handling, and functioning of pyrotechnics such as fireworks.

While testing the display of the fireworks, he took note of the following:

The elevation in meters

The time in seconds

The change in velocity should be noted as the velocity of distance covered by a moving object with time.

Therefore, the term 29.4 is the initial velocity of the fireworks he projected.

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Answer:

i think side AC is 14 because if you do subtract BC (18) from EF(12) you get 6, so u add 6 to DF(8) and get 14.

if its confusing ask me questions!!

Answer:

12

Step-by-step explanation:

When triangles are similar, their side ratios are the same. The ratio of EF to BC is 18/12, or 3/2. To find the side AC, we would multiply the corresponding part of DEF by 3/2, the same ratio. The corresponding part of DEF would be DF. DF = 8. 8 times 3/2 is 12. So AC is 12.

Let me know if this helped by hitting brainliest! If not, please comment and I'll get back ASAP.

Answer:

m = 0

Step-by-step explanation:

Slope = rise/run or (y2 - y1) / (x2 - x1)

Pick 2 points (0,2) (1,2)

We see the y stay the same and the x increase by 1, so the slope is

m = 0/1 = 0

So, the slope is 0

[tex]\left[\begin{array}{ccc}0&0\\0&0&\\\end{array}\right][/tex] is the solution of the cayley Hamilton theorem for the matrix .

What does Cayley-Hamilton theorem mean?

Theorem of Cayley-Hamilton: Every square matrix satisfies its own characteristic equation, according to this theorem. For the stress polynomial p(), this means that the scalar polynomial p() = det(I ) also holds true.

A = [tex]\left[\begin{array}{ccc}3&1\\4&1&\\\end{array}\right][/tex]

Cayley Hamilton Theorem states that Every square matrix A must satisfy its characteristic equation | A - kI |.

So, first find characteristic equation.

     ⇒ A - kI

      [tex]\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right][/tex]  - k[tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]

    =  [tex]\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] - \left[\begin{array}{ccc}k&0\\0&k&\\\end{array}\right][/tex]

   =  [tex]\left[\begin{array}{ccc}3 -k&1\\1&4-k&\\\end{array}\right][/tex]

So,

Characteristic equation is given by

  ⇒ l A - kI l = 0

  ⇒ l 3 - k    1       l

      l 1           4 - k l

 = ( 3- k )(4 - k ) - 1 = 0

 = k² - 7k + 11 =0

So, We have to show that A must satisfy

k² - 7k + 11 =0

thus

  A² - 7A + 11I =0

So, Consider

      A² - 7A + 11I =0

     [tex]\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] \left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] - 7\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right] + 11\left[\begin{array}{ccc}3&1\\1&4&\\\end{array}\right][/tex]

    [tex]\left[\begin{array}{ccc}9+1&3+4\\3+4&1+16&\\\end{array}\right][/tex] [tex]- \left[\begin{array}{ccc}21&7\\7&28&\\\end{array}\right] + \left[\begin{array}{ccc}11&0\\0&11&\\\end{array}\right][/tex]

   [tex]\left[\begin{array}{ccc}10&7\\7&17&\\\end{array}\right] + \left[\begin{array}{ccc}-10&-7\\-7&-17&\\\end{array}\right][/tex]

   [tex]= \left[\begin{array}{ccc}0&0\\0&0&\\\end{array}\right][/tex]

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No, the relation is not a function, because for each input there is not exactly one output.

A graph is a visual representation of data that shows the relationship between variables or sets of data. It consists of a set of points, called vertices or nodes, which are connected by lines or curves, called edges or arcs. Graphs are commonly used to display numerical information, such as trends, patterns, or relationships, and can be used to analyze and interpret data.

The relation is not a function because for the input x = -1, there are two different output values, y = 3 and y = -2. A function is a relation where each input has exactly one output, but in this case, the input -1 has two different outputs, violating the definition of a function.

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A. The capacity of most of the trimmer Sara sells is [tex]1\tfrac{1}{5}[/tex]

B. The total gas she needs to fill all trimmers is  [tex]$22 \frac{7}{8}[/tex]

Expressiοns are used extensively in mathematics, including arithmetic, calculus, and geοmetry. They are used in mathematical fοrmula representatiοn, equatiοn sοlutiοn, and mathematical relatiοnship simplificatiοn.

Part A

The capacity of most of the trimmer Sara sells is [tex]1\tfrac{1}{5}[/tex]

Part B

The total gas she needs to fill all trimmers is:

[tex]$\Rightarrow (1 \times 1\frac{1}{2}) + (5 \times 1\frac{5}{8}) + (1 \times 1\frac{7}{8} )+ (3 \times 2\frac{1}{8} ) + (2 \times 2\frac{1}{2} )[/tex]

⇒ [tex]$22 \frac{7}{8}[/tex]

Thus, The total gas she needs to fill all trimmers is  [tex]$22 \frac{7}{8}[/tex]

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