Answer:
static electricity and then lightning rod
1. friction
2. Lightning rod/conductor
How many oxygen (O) atoms are in a molecule of Cg H,O3?
A. 1
B. 3
C. 10
D. 4
Answer:
B. 3
Explanation:
What indicates that an area in the Northern Hemisphere is experiencing summer?
O The Sun is at its lowest point in the sky,
O The Sun is directly over Earth's north end,
The Northern Hemisphere receives fewer direct rays from the Sun.
The northern end of Earth's axis is tilted away from the Sun.
Answer:
b
Explanation:
Answer:
its b, the sun is directly over earths north end
Explanation:
A cannon is fired horizontally at 243 m/s off of a 62 meter tall, shear vertical cliff. How
many seconds will have elapsed before the cannon ball strikes the ground?
Horizontal component of ball, u = 0 m/s.
Height from which it thrown, h = 62 m.
By equation of motion :
[tex]s=ut+\dfrac{at^2}{2}[/tex]
Putting all given equation, we get :
[tex]62=0\times t+\dfrac{10t^2}{2}\\\\t=\sqrt{12.4}\ s\\\\t = 3.52\ s[/tex]
Therefore, time taken is 3.52 s.
Hence, this is the required solution.
Which events may occur when ocean salinity increases? check all that apply. mass of water increases freezing point of water decreases sunlight in deeper locations decreases buoyancy of objects in the water increases amount of dissolved gases in water increases
The mass of water increases, the freezing point of water decreases. and the buoyancy of objects in the water increases may occur when the ocean sanity increases.
What is ocean sanity?Seawater is salty due to a variety of substances. The majority of them arrive via rivers, which bring chemicals dissolved from rock and soil. The most common is sodium chloride, also known as salt.
The most popular approach to quantify salinity is to count the amount of salt in 1,000 g of water, which is referred to as ppt. The majority of the ocean has a salinity of 34 to 36 parts per thousand.
Salinity makes water colder and denser by lowering its temperature. The chilly water sinks to the ocean's depths. Slow currents carry it throughout the marine basins.
Because the items have a lower density, they flow across the water's surface. As a result, the buoyancy of items in water improves.
So the events that may occur when ocean salinity increases will be;
1)The mass of water increases.
2) Freezing point of water decreases.
3) buoyancy of objects in the water increases.
Hence the masses of water increase, the freezing point of water decreases. and the buoyancy of objects in the water increases may occur when the ocean sanity increases.
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please help i really need it right now
Try the suggested option, all the details are in the attachment.
Explanation:
1) to calculate the moles of CCl₄;
2) to calculate the moles of HF;
3) to calculate the mass of CCl₂F₂;
4) to calculate the mass of ureacted HF.
The initial velocity of a ball sent upward from the ground, is 12 m/s. What will its final velocity be before it hits the ground
O 12 m/s
0-12 m/s
0 -9.8 m/s
O 9.8 m/s
Answer:
The final velocity s 12 m/s.
For the upwards trajectory: (using the positive value of g in the downward direction)
Vf = Vi - g t = 0 where Vi is initial velocity and Vf the velocity at max height
Vf = 12 - g t = 0 t = 12 / g time to reach max height
For the downwards trajectory
Vf = Vi + g t = 0 + g t = g * 12 / g = 12 where t was found above
We know the from 2 g h = Vf^2 - Vi^2, since the height is the same in both directions, that the ball reaches the ground with at the same speed at which it was sent.
Also, conservation of energy shows that the ball must return to the ground with the speed with which was projected.
(e) The National Grid supplied a house with 18 000 000 J of energy. in 1 hour. What was the average current supplied to the house during that hour? Write any equations that you use.
Answer:
Explanation:
4.0/5
10
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Electrical power = (voltage) x (current)
Electrical energy = (power) x (time)
Combine those definitions:
Energy = (voltage) x (current) x (time)
Divide each side by (voltage x time), and we have
Current = Energy / (voltage x time)
You told us that
Energy = 1.8 x 10⁷ joules
Time = 1 hour = 3,600 seconds
so we have
Current = (1.8 x 10⁷) / (voltage x 3,600).
If you live in the US, Canada, or Mexico, your voltage is 120 volts.
Current = (1.8 x 10⁷) / (120 x 3,600) = 41-2/3 Amperes
If you live practically anywhere else in the world, your voltage is 240 volts.
Current = (1.8 x 10⁷) / (240 x 3,600) = 20-5/6 Amperes.
Come on! Please answer... :( WILL GIVE BRAINLYEST TO BEST ANSWER!!! PLEASE PLEASE PLEASE PLEASE ANSWER!!!
How do the potential and kinetic energy of the cart change at each point in the diagram?
Answer:
Potential -> Kinetic -> Potential ->
Explanation:
Point A is potential becuase it's stopped (its energy isn't released). Point B is where that potential energy is released and turned into Kinetic energy. And point C is where potential energy is stored again. Same with point D.
It's not D
10 Select the correct answer.
A stability ball can be used in yoga to do which of the following?
A. Provide support
В. Make a move more challenging
C. Make a move easier
D. All of the above
Dennis the Menace uses his slingshot to shoot a small rock at his neighbor's flowerpots. The rock travels a distance of 12.5 cm from the point at which he pulls it back to the point at which it leaves the slingshot. It leaves the slingshot at a velocity of 6.24 m/s. Find the average acceleration of the rock.
Answer:
[tex]a=155.750\ m/s^2[/tex]
Explanation:
It is given that,
A small rock is shoot at Dennis' neighbor's flowerpots. The rock travels a distance of 12.5 cm from the point at which he pulls it back to the point at which it leaves the slingshot.
Final velocity of the rock, v = 6.24 m/s
The initial velocity of the rock, u = 0 (as it was at rest)
Let a is the acceleration of the rock. It can be calculated using the equation of kinematics as follows :
[tex]v^2-u^2=2ad\\\\\text{Put u = 0 }\\\\v^2=2ad\\\\a=\dfrac{v^2}{2d}\\\\a=\dfrac{(6.24)^2}{2\times 12.5\times 10^{-2}}\\\\a=155.750\ m/s^2[/tex]
So, the average acceleration of the rock is [tex]155.750\ m/s^2[/tex].
A gas has an initial pressure of 50kpa at a temperature of -67°c. calculate
the final pressure of this gas if its temperature is increased to 398°c at a
constant volume.
Answer:
the pressure will be 297.01 kpa
A rock is dropped from a cliff that is 80 m above the ground. What is the velocity of the rock when it hits the ground? (hint: acceleration due to gravity g = 9.81 m/s2)
Answer:
45.1 m/s
Explanation:
use the equation v = u + at substitute the values v = 0 + 9.8×4.6 v = 45.08 round to about 3 s.f v = 45.1 m/s I do apologize if I'm incorrect.
What are the Planets in order and how far away are they from the Sun?
what are the invisible forces of nature
Answer:
Gravity, Friction, Air resistance, magnetism, static electricity
Explanation:
Answer:
gravity friction air resistant are a few
A man walks 23 km east and then
turns around and heads west for 46
km, then east for 23 km. What is his
displacement?
A) 92 km
B) 0 km
C 46 km west
D) 46 km East
what two elements take up the most space in the universe
Answer:
helium and hydrogen
Explanation:
Thermal energy is the_____
energy of particles in an object.
Answer:
sum of the kinetic and potential energy
Explanation:
Convert 0k temperature into Celsius fahrenhet
and Reumer scale.
Answer:
-273.15 celcius
−218.52 Réaumur
Explanation:
273. 15 kelvin = 0 degrees celcius
C + 273.15 =k
08. Degrees celcius = 1 Réaumur
C x 0.8 = rea
Which characteristics describe a spiral galaxy? check all that apply. is shaped like a pinwheel has no new star formation contains a lot of gas and dust is smaller than other types of galaxies has sites of active star formation within its arms
It is shaped like a pinwheel describing a spiral galaxy. A flat, rotating disk containing stars, gas, and dust, as well as a central concentration of stars known as the bulge, makes up most spiral galaxies.
What is a spiral galaxy?Spiral galaxies are a type of galaxy first described by Edwin Hubble are part of the Hubble sequence.
A flat, rotating disk containing stars, gas, and dust, as well as a central concentration of stars known as the bulge, makes up most spiral galaxies.
Many of these are surrounded by a fainter halo of stars, many of which are found in globular clusters.
The Pinwheel Galaxy is a spiral galaxy located approximately 21 million light-years from Earth. M101 is the name given to this swirling galaxy by scientists.
In the Northern Hemisphere, it can be found in the constellation Ursa Major, also known as the "Big Dipper." Binoculars or a small telescope can be used to see if the sky is clear and dark.
Hence it is shaped like a pinwheel describing a spiral galaxy.
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What is the correct definition of acceleration?
a) the change of velocity over time
b) the change of inertia over time
c) the change of velocity over distance
d) the change of speed over time
Answer:
Hello
a) the change of velocity over time
Answer:
c.the change of velocity over distance
Love, which can’t be observed or measured directly, is an example of a psychological construct.
Please select the best answer from the choices provided
T
F
Answer:
f
Explanation:
Spring compressed 10cm by 100N force and held in place with Pin. Pin is pulled and block is pushed Up the incline. Uk(coefficient of kinetic energy)=. 39
Determine the speed of block after the Spring extends forward 7cm,
Determine the height at which the block will stop moving
Determine the length of the incline such that the leading edge of the block is stopped when the block reaches the end of the incline.
The compression of 10 cm by a 100 N force on the plane that has a
coefficient of friction of 0.39 give the following values.
The velocity of the block after the Spring extends 7 cm is approximately 1.73 m/sThe height at which the block stops rising is approximately 1.1415 mThe length of the incline is approximately 1.536 mHow can the velocity and height of the block be calculated?Mass of the block, m = 3 kg
[tex]Spring \ constant, K = \dfrac{100 \, N}{0.1 \, m} = \mathbf{ 1000\, N/m}[/tex]
Coefficient of kinetic friction, [tex]\mu_k[/tex] = 0.39
Therefore, we have;
Friction force = [tex]\mathbf{\mu_k}[/tex]·m·g·cos(θ)
Which gives;
Friction force = 0.39 × 3 × 9.81 × cos(48°) ≈ 7.68
Work done by the motion of the block, W ≈ 7.68 × d
The work done = The kinetic energy of the block, which gives;
[tex]\mathbf{\dfrac{1}{2} \times k \cdot x^2 }= 7.68 \cdot d[/tex]
The initial kinetic energy in the spring is found as follows;
K.E. = 0.5 × 1000 N/m × (0.1 m)² = 5 J
The initial velocity of the block is therefore;
5 = 0.5·m·v²
v₁ = √(2 × 5 ÷ 3) ≈ 1.83
Work done by the motion of the block, W ≈ 7.68 N × 0.07 m ≈ 0.5376 J
Chane in kinetic energy, ΔK.E. = Work done
ΔK.E. = 0.5 × 3 × (v₁² - v₂²)
Which gives;
ΔK.E. = 0.5 × 3 × (1.83² - v₂²) = 0.5376
Which gives;
The velocity of the block after the Spring extends 7 cm, v₂ ≈ 1.73 m/sThe height at which the block will stop moving, h, is given as follows;
[tex]At \ the \ maximum \ height, \ h, \ we \ have ; \ \dfrac{1}{2} \times 1000 \times 0.1^2 = 7.68 \times x[/tex]
Which gives;
[tex]Length \ of \ the \ incline \ at \ maximum \ height, \ x_{max} =\dfrac{ 7.68 }{ \dfrac{1}{2} \times 1000 \times 0.1^2 } \approx 1.536[/tex]
The distance up the inclined, the block rises, at maximum height is therefore;
[tex]x_{max}[/tex] ≈ 1.536 m
Therefore;
h = 1.536 × sin(48°) ≈ 1.1415
The height at which the block stops rising, h ≈ 1.1415 mFrom the above solution for the height, the length of the incline is he
distance along the incline at maximum height which is therefore;
Length of the incline, [tex]x_{max}[/tex] = 1.536 mLearn more about conservation of energy here:
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You are designing a pendulum clock to have a period of 1.0 s. How long should the
pendulum be?
For an accurate design of the pendulum that will match the period, the length of the pendulum clock must be 0.25 m.
Period of oscillation of simple pendulumThe period of oscillation of simple pendulum is calculated as follows;
[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]
where;
L is the length of the pendulumg is acceleration due to gravityT is the period of the oscillationMake "L" the subject of the formula in the above equation.
[tex]\frac{T}{2\pi} = \sqrt{\frac{l}{g }} \\\\\frac{T^2}{4\pi^2} = \frac{l}{g} \\\\l = \frac{gT^2}{4\pi ^2} \\\\l = \frac{(9.8)(1)^2}{4\pi ^2} \\\\l = 0.25 \ m[/tex]
Thus, the length of the pendulum clock is 0.25 m.
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A man who weights 900N stands on a platform scale in a elevator. The elevator has a mass of 4000kg; the reading scale is 700N. What is the direction of the net force acting in the man
Hi there!
We know that there are TWO forces acting on the man.
Force due to gravity: Acts DOWNWARDNormal force due to the elevator floor: UPWARDWe can express this in an equation. Let DOWN be NEGATIVE, and UP be POSITIVE.
[tex]F_{net} = N - F_g[/tex]
Recall that a SCALE measures the NORMAL FORCE, NOT the WEIGHT. Therefore:
N = 700 N
W = 900 N
[tex]F_{net} = 700 - 900 \\\\F_{net} = -200N[/tex]
Since downward is negative, the net force is acting DOWNWARD.
What is meant by solenoid? How does a current carrying solenoid behave?
•Question⟿What is meant by solenoid?
•Answer⟿If a conducting wire is wound in form of a cylindrical coil whose diameter is less in comparison to its length, the coil is called a solenoid. It looks like a helical spring.
•Question⟿How does a current carrying solenoid behave?
•Answer⟿
The magnetic field lines of a current carrying solenoid are similar to the magnetic field lines of a bar magnet. Thus, a current carrying solenoid behaves just like a bar magnet.A current carrying solenoid when suspended freely sets itself in the north south direction exactly in the same manner as a bar magnet does.A current carrying solenoid also acquires that attractive property of a magnet. If iron fillings are brought near the current carrying solenoid, it attracts them.Explanation:
Hope it helps you!!
current carrying solenoid behaves as an electromagnet. The uniform magnetic field inside it may magnetise a steel rod permanently. Detailed Answer: A coil of many circular turns of insulated copper wire wrapped closely in the shape of a cylinder is called a Solenoid.
hope it helps you :)
why acceleration is a derived unit?
The acceleration is derived from the some other quantities like change in velocity / time take . If we see carefully that formula of acceleration you find that it is basically derived from fundamental quantities therefore acceleration is called a derived quantities.
A car is moving from rest and attained a velocity of 80 m/s. Calculate the acceleration of the car after 5 s?
Answer:
400 m/s
Explanation:
If it is moving at a velocity of 80 m/s from rest, then after 5 s it would be at 400 m/s.
80 x 5 = 400
what is a joule in science? and how does it relate to work? helppp I need an answer!!! (no links)
Answer: joule, unit of work or energy in the International System of Units (SI); it is equal to the work done by a force of one newton acting through one metre.
Explanation:
This is a unit used to measure energy or work. One joule is the amount of energy required to produce one watt of power for one second. It's also the work done by a force equal to one newton exerted over a distance of one meter.
Hope this helps!
How do you calculate the total current of a parallel circuit?
Answer:
The total current in the circuit is the current that travels thru a single conductor that connects to the parallel circuit (current from a electromotive source, etc.)
I = I1 + I2 + I3 ...... In
If n items are in parallel with another, then I is the total current passing thru these items
The dehydration butanol on alumina is carried out over a silica-alumina catalyst at 680 K.
CH3CH2CH2OH →CH3CH = CHCH3 + H2O
The rate law iswith k = 0. 054 mol/gcat·h·atm and KBu = 0. 32 atm^–1. Pure butanol enters a thin-tubed, packed-bed reactor at a molar flow rate of 50 kmol/hr and a pressure of 10 atm (1013·kPa).
Required:
a. What PBR catalyst weight is necessary to achieve 80% conversion in the absence of pressure drop?
b. What "fluidized CSTR" catalyst weight is necessary to achieve 80% conversio?
A) The PBR catalyst weight that is required to achieve 80% conversion in the absence of pressure drop is : 370 mg
B) The fluidized CSTR catalyst weight necessary to achieve 80% conversion is : 995.025 g
A) Determine the PBR catalyst weightTo calculate the PBR catalyst weight required to achieve 80% conversion in the absence of pressure drop we will apply the equation below
w = [tex]\frac{V_{o} }{KC_{ao}(1/x - 1 ) }[/tex] ---- ( 1 )
insert values into equation ( 1 )
w = [tex]\frac{50 kmol}{0.54 * 10 (\frac{1}{0.8}) * 1 }[/tex]
PBR catalyst weight ( w ) = 370 mg
B) Determine the fluidized CSTR catalyst weight necessary to achieve 80% conversion
applying the equation below
W = [tex]\frac{Fbwx}{-r'Bu}[/tex]
= [tex]\frac{50kmol/r * 0.8}{0.042mol/gcat.h}[/tex]
= 995.025 gcat
Hence we can conclude that The PBR catalyst weight that is required to achieve 80% conversion in the absence of pressure drop is : 370 mg The fluidized CSTR catalyst weight necessary to achieve 80% conversion is : 995.025 g.
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