(1 point) how many 3 -element subsets containing the letter a can be formed from the set {a,b,c,d,e,f,g} ?

Answers

Answer 1

From the set a, b, c, d, e, f, g, we can derive 15 3-element subsets having the letter "a".

We can select 2 more elements from the set's remaining 6 components to create a 3-element subgroup that includes the letter "a": a, b, c, d, e, f, g.

The binomial coefficient indicates the number of possible methods to select 2 elements from a set of 6:

C(6,2) = 6! / (2! * (6-2)!) = 15

The positive numbers that appear as coefficients in the binomial theorem are known as binomial coefficients in mathematics. A binomial coefficient is frequently written as ( ) and is indexed by the pair of numbers n k 0.displaystyle "tbinom" nk. It is the multiplicative formula that can be used to calculate the coefficient of the xk component in the polynomial expansion of the binomial power (1 + x)n.

Thus, from the set a, b, c, d, e, f, g, we can derive 15 3-element subsets having the letter "a".

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Related Questions

Click “show your work” and graph the absolute value function shown below.

f(x) =|x – 4| + 1

Answers

Graph the absolute value using the vertex and a few selected points.

This is the graph:

Find x, y, and z such that x³+y³+z³=k, for each k from one to 100.

Answers

Answer:

The answer is:-

Step-by-step explanation:

x^3+y^3+z^3=k

xyz^9=k

xyz/9=k

xyz=9k

Hence, k=9 and, x, y and z are 1.

Please help I dont understand this thank you

Answers

Answer:17x25 i think

Step-by-step explanation:

Using Company A's calling plan, the cost of an overseas phone call is a $0.95 connection fee plus 33 cents
per minute. If the total cost of the call is $11.84, how long is the phone call?
minutes

Answers

The total duration of the phone call was 33 minutes.

Given that, by using Company A's calling plan, the cost of an overseas phone call is a $0.95 connection fee plus 33 cents per minute. If the total cost of the call is $11.84 and we have to calculate the time how long was the phone call.

Let the number of minutes a phone call held be x.

Now, we will be representing the above given information in terms of linear equation and then solve for the value of x which will give us the number of minutes the phone call held.

[tex]Total[/tex] [tex]cost=[/tex] $[tex]0.95[/tex] [tex]+[/tex] $[tex]0.33x[/tex]

$[tex]11.84=[/tex] $[tex]0.95[/tex] [tex]+[/tex] $[tex]0.33x[/tex]

[tex]11.84=0.95+0.33x[/tex]

[tex]11.84-0.95=0.33x[/tex]

[tex]0.3=0.33x[/tex]

[tex]\frac{0.3}{0.33}=x[/tex]

[tex]33=x[/tex]

Therefore, the call will go 33 minutes long.

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Lesson 4.1: Steps in a Simulation Study.) Which steps are regarded asessential for a successful simulation study? (There may be more than onecorrect answer.)
a. Problem formulation
b. Model validation
c. Model verification
d. Experimental design
e. Output analysis

Answers

The steps regarded essential for a successful simulation study are:

a. Problem formulation

b. Model validation

c. Model verification

d. Experimental design

e. Output analysis

To give any solution to the problem the very first step necessary is to understand the problem . Now through the observations of the process the problem is defined and formulated .

Keeping in mind the real life solutions and necessities a model is developed . Now the further process of verification and validation is carried out . In verification we make sure that the model works as we thought through animation whereas validation makes sure that the model reflects reality .

Experimental design multiple similar models are compared with minute changes and the performance are compared to find the best suited model.

Finally the results of the study are discussed in output analysis through written reports , documents or presentation and the best product is chosen .

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F and H are sets of real numbers defined as follows.

Answers

F ∩ H = [4, 9)

FUH= ∞

What is the interval?

Generally, To find the intersection of F and H, denoted as F ∩ H, we need to identify the values that are in both sets F and H.

From the definitions of F and H, we have:

F = {v | v=4 or v>4}

H = {v | v<9}

The values that are in both F and H are those that satisfy both conditions, i.e., v=4 or v>4 and v<9. This is equivalent to just the condition v=4, since any value that satisfies v<−4 will also satisfy v>4 and v<9.

Therefore, F ∩ H = {v | 4}.

In interval notation, we can write this as:

F ∩ H = [4, 9)

To find the union of F and H, denoted as F ∪ H, we need to identify all the values that are in either set F or set H or both.

From the definitions of F and H, we have:

F = {v | v=4 or v>4}

H = {v | v<9}

this denotes

F=  {v | v=4> x > ∞}

H = {v |-∞ <v<9}

FUH= ∞

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i need with this question

Answers

The height of the wall is 14 feet

What are similar triangles?

Similar triangles are triangles that have the same shape, but their sizes may vary. All equilateral triangles, squares of any side lengths are examples of similar objects. In other words, if two triangles are similar, then their corresponding angles are congruent and corresponding sides are in equal proportion.

Therefore ;

TH/ JS = TV/VS

4/JS = 6/21

21× 4 = 6 JS

JS = 21× 4/6

JS = 84/6

JS = 14 feet

therefore the height of the wall is 14 feet

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Someone help me with these math problems

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1. Two lines are MT and UW. 2. Two segments are SX and SY. 3. A pair of congruent angles is ∠QNT and ∠QNM. 4. Four right angles are ∠QNT and ∠QNM. ∠TNY and ∠MNY.

What are obtuse vertical angles?

Angles that are both vertical and obtuse are known as obtuse vertical angles. In order to comprehend what obtuse vertical angles are, we must first learn the definitions of each of these kinds of angles.

Angles that cross one other at the junction of two lines are known as vertical angles. There is always an equal amount of vertical angles.

With these definitions, we get that obtuse vertical angles are angles that are in front of one another at the intersection between two lines, and both of which share a comparable measure that is between 90° and 180°.

From the given figure we observe that:

1. Two lines are MT and UW.

2. Two segments are SX and SY.

3. A pair of congruent angles is ∠QNT and ∠QNM.

4. Four right angles are ∠QNT and ∠QNM. ∠TNY and ∠MNY.

5. Two pairs of obtuse vertical angles ∠MSW and ∠UST. ∠VNT and ∠PNM.

6. Two pairs of adjacent supplementary angles are ∠MSW and ∠WST. ∠WNM and WNT.

7. Two pair of complementary angles are ∠TNP and ∠PNY. ∠QNW and ∠WNM.

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I will give brainliest and ratings if you get this correct ​

Answers

The first derivative of the composite function r(x) = √[x + √(x + √x)] is equal to r' (x) = [1 / [2 · √[x + √(x + √x)]]] · [1 + [1 / [2 · √(x + √x)]] · [1 + 1 / (2 · √x)]].

How to determine the first order derivative of a composite function

In this problem we find the case of a composite function of the form:

f ° g ° h (x) = f [g [h (x)]]

Whose first derivative must be found by means of the following differentiation rules:

Chain rule

d [f [u (x)]] / dx = (df / du) · (du / dx)

Derivative of a square root

d (√x) / dx = 1 / (2√x)

And the first order derivative of the function r(x) = √[x + √(x + √x)] is:

r' (x) = [1 / [2 · √[x + √(x + √x)]]] · [1 + [1 / [2 · √(x + √x)]] · [1 + 1 / (2 · √x)]]

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Find an equation for the surface with all points which are equidistant of (−1,0,0)and the plane x=1. Draw the surface.

Answers

The equation for the surface with all points which are equidistant of (−1,0,0)and the plane x=1 is x² - 2x + y² + z² = 2.

In mathematics, an equation is a statement that asserts the equality of two expressions. An equation typically consists of two sides separated by an equal sign (=).

To start with, let's consider the given information. We have been given that all points on the surface are equidistant from (-1,0,0) and the plane x=1. This means that the distance between any point on the surface and (-1,0,0) is the same as the distance between that point and the plane x=1.

We can use the formula for the distance between a point and a plane to derive an equation for the surface. The formula for the distance between a point (x1, y1, z1) and a plane Ax + By + Cz + D = 0 is given by:

distance = |Ax1 + By1 + Cz1 + D| / √(A² + B² + C²)

In our case, the plane is x=1, which can be written as x - 1 = 0. So, A=1, B=0, C=0, and D=-1. The point (-1,0,0) can be substituted as x1=-1, y1=0, and z1=0.

We can simplify the distance formula to:

distance = |x-1|

Now, since all points on the surface are equidistant from (-1,0,0) and x=1, we can set up the following equation:

|x-1| = √( (x+1)² + y² + z² )

Squaring both sides and simplifying, we get:

(x-1)² = x² + 2x + 1 + y² + z²

Rearranging and simplifying, we get the final equation for the surface:

x² - 2x + y² + z² = 2

This is the equation of the surface that contains all points that are equidistant from (-1,0,0) and x=1.

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pls help I GIVE BRAINIEST.In the graph above, determine where the image for vertices A, B, C, and D will be located after Quadrilateral ABCD is reflected over the y = 0 mirror line and then dilated using a scale factor of 2.5.

Answers

Step-by-step explanation:

reflect the shape, will give you:

A = (-1,0)

B= (3, -5)

C= (-6, -7)

D= (-4, -1)

If a point A(x, y) is dilated by a factor P, the new point would be at

A'(Px, Py).

A = -1/2.5 = -0.4             0/2.5= 0

= ( - 0.4, 0)

B = 3/2.5 =  1.2              -5/2.5 = -2

= (1.2, -2)

C = -6/2.5= -2.4       -7/2.5 = -2.8

= ( -2,4, -2.8)

D = -4/2.5 = -1.6.     -1/2.5 = -0.4

= ( -1.6, -0.4)

You're Welcome!

Answer:

Step-by-step explanation:

( -1.6, -0.4)

The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two time periods of an equal length. It is known that the mean number of occurrences in ten minutes is 5.3. (please show work)
1. Refer to Exhibit 2. The random variable x satisfies which of the following probability distributions?
a. normal b. Poisson c. binomial d. Not enough information is given to answer this question.
2. Refer to Exhibit 2. The probability that there are 8 occurrences in ten minutes is
a. .0241 b. .0771 c. .1126 d. .9107
3. Refer to Exhibit 2. The probability that there are less than 3 occurrences is
a. .0659 b. .0948 c. .1016 d. .1239

Answers

The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.

Given,

The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two time periods of an equal length. It is known that the mean number of occurrences in ten minutes is 5.3.

1) A Poisson distribution characterizes the random variable x that is provided.

2) Having 8 occurrences in 10 minutes is likely based on the following formula:

P(X = 8) = (e^(-5.3) * 5.3^8) / 8! = 0.0241 (rounded to four decimal places) (rounded to four decimal places)

Consequently,

(a) 0.0241 is the correct response.

3) The likelihood that there are fewer than 3 occurrences is as follows:

P(X 3) = P(X = 0), P(X = 1), and P(X = 2) = (e(-5.3) * 5.30), (e(-5.3) * 5.31), and (e(-5.3) * 5.32), respectively, / 0!, / 1/1, and / 2/ respectively, / 2! = 0.0659 (rounded to four decimal places)

Accordingly,

(a) 0.0659 is the correct response.

The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.

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The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.

Given,

The random variable x is the number of occurrences of an event over an interval of ten minutes. It can be assumed that the probability of an occurrence is the same in any two time periods of equal length. It is known that the mean number of occurrences in ten minutes is 5.3.

1) A Poisson distribution characterizes the random variable x that is provided.

2) Having 8 occurrences in 10 minutes is likely based on the following formula:

P(X = 8) = ([tex]e^(-5.3)[/tex] * [tex]5.3^8[/tex]) / 8! = 0.0241 (rounded to four decimal places) (rounded to four decimal places)

Consequently,

(a) 0.0241 is the correct response.

3) The likelihood that there are fewer than 3 occurrences is as follows:

P(X 3) = P(X = 0), P(X = 1), and

P(X = 2) = ([tex]e(-5.3)[/tex]* 5.30), ([tex]e(-5.3)[/tex]* 5.31), and ([tex]e(-5.3)[/tex] * 5.32),

respectively, / 0!, / 1/1, and / 2/ respectively, / 2! = 0.0659 (rounded to four decimal places)

Accordingly,

(a) 0.0659 is the correct response.

The random number x satisfies Poisson distribution of probability and the probability that there are 8 occurrences in ten minutes is 0.0241 and The probability that there are less than 3 occurrences is 0.0659.

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given the following list of prices (in thousands of dollars) of randomly selected trucks at a car dealership, find the median. 20,46,19,14,42,26,33 provide your answer below: $$median

Answers

The median of the randomly selected list of prices of trucks will be 26 thousands dollars.

To find the median , first we need to arrange the list in either ascending form or descending form. Let us arrange the list in ascending form  :

List before sorting : 20,46,19,14,42,26,33

List after sorting it in ascending form : 14,19,20,26,33,42,46

Here, the number of observations is 7 which is odd. So, The formula to find the median term from a given number of "Odd" observations in a set is :

⇒ {(n+1) / 2}th term (where n is the number of observations in a set)

⇒({7+1}/2)

⇒8/2

⇒4th term

Therefore, the 4th term in our list of prices of trucks is the median which is 26 thousand dollars

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Two circles are internally tangent at a point T and have radii of 1 and 3. The maximum possible area for a triangle with one vertex at T, another vertex on the small circle, and the third on the large circle can be expressed in the form a √(b)/c, where a,b, and c are positive integers, b is not divisible by the square of any prime, and a and c are relatively prime. Find a+b+c.

Answers

The maximum possible area of such a triangle is $\frac{1}{2} \cdot \sqrt{4 + 2\sqrt{3}} = \frac{\sqrt{12 + 6\sqrt{3}}}{2} = 3\sqrt{3} + 3$, and $a + b + c = 3 + 3 + 3 = \boxed{9}$.

Let O and O' be the centers of the circles with radii 1 and 3, respectively, and let P and Q be points on the small and large circles, respectively, such that TPQ is a triangle. ]

Since the radius of the small circle is 1, we have TP = 1. Let R be the midpoint of PQ, so that TR is the altitude of triangle TPQ from T. Let x = TP = 1, y = TQ, and z = TR.  [asy]

unit size(0.6 cm);

pair O, OO, P, Q, R, T;

O = (0,0);

OO = (4,0);

T = (0,3);

P = intersection points(Circle(O,1),Circle(T,2))[1];

Q = intersection points(Circle(OO,3),Circle(T,2))[0];

R = (P + Q)/2;

draw(Circle(O,1));

draw(Circle(OO,3));

draw(T--P--Q--cycle);

draw(T--R);

label("$O$", O, SW);

label("$O'$", OO, SE);

label("$P$", P, NW);

label("$Q$", Q, NE);

label("$R$", R, S);

label("$T$", T, N);

label("$x$", (T + P)/2, W);

label("$y$", (T + Q)/2, E);

label("$z$", (T + R)/2, W);

[/asy]

Then we have TR = z, and by the Pythagorean Theorem in right triangle TPQ we have

\begin{align*}

TQ^2 - 1 &= TR^2 = z^2, \

TQ^2 + 9 &= (TQ + TR)^2 = (TQ + z)^2.

\end{align*}Solving for TQ in the first equation and substituting into the second, we obtain

[(1 + z)^2 + 9 = (1 + z)^2 + 4z^2,]which simplifies to $z^2 - 2z - 2 = 0$. The positive root of this quadratic equation is $z = 1 + \sqrt{3}$, so $TQ = \sqrt{4 + 2\sqrt{3}}$. Then the area of triangle TPQ is

[\frac{1}{2} \cdot TP \cdot TQ = \frac{1}{2} \cdot \sqrt{4 + 2\sqrt{3}}.]Thus the maximum possible area of such a triangle is $\frac{1}{2} \cdot \sqrt{4 + 2\sqrt{3}} = \frac{\sqrt{12 + 6\sqrt{3}}}{2} = 3\sqrt{3} + 3$, and $a + b + c = 3 + 3 + 3 = \boxed{9}$.

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thhis is my question

Answers

Both items have different rate of change, m₁ = -2, m₂ = -1/2, Item 1 is steeper.

Correct option is C.

What is slope?

The slope of a line is defined as the change in y coordinate with respect to the change in x coordinate of that line. The net change in y coordinate is Δy, while the net change in the x coordinate is Δx. So the change in y coordinate with respect to the change in x coordinate can be written as,

m = Δy/Δx

where,m is the slope

Slope of line denotes rate of change and steepness.

Given,

A) a line with y-intercept (0,0) and passes through point (-2 , 4).

slope of the line

= (y₂ - y₁)/(x₂ - x₁)

= (4 - 0)/(-2 - 0)

= 4/-2

m₁ = -2

B) In the graph, line passes through (2, -1) and (-2 , 1 )

slope of the line

= (y₂ - y₁)/(x₂ - x₁)

= (1 - -1)/(-2 - 2)

= 2/-4

m₂ = -1/2

Hence, by the calculation

Items have different rate of change, Item 1 is steeper.

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assume a child is under observation by a researcher. he is given 6 blocks uniquely labeled a, b, c, d, e, and f. the child is equally likely to choose any of the blocks. find the probability the child arranges the blocks in such a way that block f is in either the 1st position or the last position.

Answers

The probability the child arranges the blocks in such a way that block f is in either the first position or the last position is found to be 1/3.

The child under observation of the researcher is given 6 unequally labelled block that are number as, a, b, c, d, e and f.

Now, the total number ways in which the child can arrange these block is,

Total possible ways = 6 x 5 x 4 x 3 x 2 x 1

Total possible ways = 720

Now, if the position of the block labelled f is fixed at either 1st or the last position then, total such ways are,

= 2 x 5 x 4 x 3 x 2 x 1

= 240

So, the probability that the child arranges the blocks in such a way that block f is in either the 1st position or the last position,

P = 240/720

P = 1/3

So, the probability is found to be 1/3.

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Question Help Error Analysis On a math test a student, Jake, has to identify all the coefficients and constants of the expression 9m +4+y. Jake says that 9 is a coefficient and 4 is a constant. Identify all the coefficients and constants of the expression. What error might Jake have made? The coefficient(s) of the expression is/are. (Use a comma to separate answers as needed.)​

Answers

The error which Jake made is likely to be a result of confusion or oversight in identifying the variable y as having a coefficient of 1.

What error might Jake have made?

The coefficients of an expression are the numerical factors that multiply the variables, while the constants are the numerical values that do not contain any variables.

In the expression 9m + 4 + y, the coefficients are 9 and 1 (which is the implied coefficient for y since there is no visible numerical factor), and the constant is 4.

So Jake correctly identified 9 as a coefficient and 4 as a constant, but missed the implied coefficient of 1 for the variable y. The error that Jake made is likely to be a result of confusion or oversight in identifying the variable y as having a coefficient of 1, rather than assuming it is a constant or neglecting it entirely.

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Mr. Phil T. Rich had a boat load of money. He decided to leave it to his family. But wanted to make sure his goldfish, Bubbles was taken care of too. He decided to leave 1/2 of his estate to his wife 30,000$ to his daughter, half of what was left over for his butler, Niles half of what was left to bubbles (his goldfish). He realized 8,000$ remaking, so he donated it to charity. What was the original value of his estate? GO STEP BY STEP. WORK BACKWARDS

Answers

If Mr. Phil T. Rich had a boat load of money. The original value of his estate is $152,000.

How to find the original value?

Let's call the original value of Mr. Phil T. Rich's estate "x".

After he gave 1/2 of the estate to his wife, he was left with x/2.

After he gave 30,000 to his daughter, he was left with x/2 - 30,000.

After he gave half of what was left to his butler Niles, he was left with (x/2 - 30,000)/2.

After he gave half of what was left to Bubbles, he was left with (x/2 - 30,000)/4.

Finally, after he donated the 8,000 to charity, he was left with (x/2 - 30,000)/4 - 8,000.

We know that the final amount after all these transactions was $0, so we can set up an equation to solve for x:

0 = (x/2 - 30,000$)/4 - 8,000

Multiplying both sides by 4 to isolate x/2:

0 * 4 = (x/2 - 30,000) - 8,000 * 4

Expanding the right side:

0 = (x/2 - 30,000) - 32,000

Adding 30,000 and 32,000 to both sides:

30,000+ 32,000 = (x/2)

Dividing both sides by 1/2:

62,000 * 2 = x

Multiplying both sides by 2:

62,000* 2 * 2 = x * 2

Expanding the left side:

62,000* 4 = x

Dividing both sides by 4:

62,000 * 4 / 4 = x / 4

Expanding the left side:

$62,000 = x

Therefore the original value of Mr. Phil T. Rich's estate was $62,000.

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b) Would this circle work for the pony's path? Why or why not? Explain your
answer by using the equation, the location of the stake, and the length of the
rope to support your reasoning. (2 points)

Answers

The equation for the pony's path is -

(x - 8)² + (y - 8)² = 128.

What is the equation of a circle?

The general equation for a circle is -

(x - h)² + (y - k)² = r²

where (h, k) is the center and (r) is the radius.

Given is that the pony is staked at the coordinate point (8, 8).

The general equation for a circle is -

(x - h)² + (y - k)² = r²

We can write the equation for the pony's path as -

(x - 8)² + (y - 8)² = 128

Therefore, the equation for the pony's path is -

(x - 8)² + (y - 8)² = 128.

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Help will be greatly appreciated :}

Answers

Answer:

  4.5 mm

Step-by-step explanation:

You want the length of AB in similar triangles ACE and BCD, given BD is parallel to AE, and AC=36 mm, ED=9 mm, EC=72 mm.

Proportion

Corresponding segments in the two triangles are proportional, so we have ...

  AB/ED = AC/EC

  AB/(9 mm) = (36 mm)/(72 mm) = 1/2

  AB = (9 mm)(1/2) = 4.5 mm . . . . . multiply by 9 mm

The length of segment AB is 4.5 mm.

home realty claims that it can sell a detached, residential house faster than any other realty company. with the aim of examining home's claim, you sample customers who sold a detached, residential house through home and record the selling times (in days) of the houses. your data are summarized in the following histogram.

Answers

The proportion of selling times in the sample that are greater than or equal to 10 days is 0.85.

As per the data given:

HOME Realty claims that it can sell a detached, residential house faster than any other realty company.

With the aim of examining HOME's claim, you sample 20 customers who sold a detached.

The data has been summarized in the histogram(attached at the end of solution)

Here we have to determine the proportion of selling times in the sample that are greater than or equal to 10 days.

Selling Time Frequency

0 - 10                    3

10 - 20                  4

20 - 30                 7

30 - 40                 3

40 - 50                 3

Frequencies for which selling times are 10 or greater

= 4 + 7 + 3 + 3

= 17

Total frequencies = 3 + 4 + 7 + 3 + 3

= 20

Proportion for which selling times are 10 or greater

= [tex]$\frac{17}{20}[/tex]

= 0.85

Therefore the proportion is 0.85.

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HOME Realty claims that it can sell a detached, residential house faster than any other realty company. With the aim of examining HOME's claim, you sample 20 customers who sold a detached, residential house through HOME and record the selling times (in days) of the houses. Your data are summarized in the following histogram(attached at the end of solution):

Based on the histogram, find the proportion of selling times in the sample that are greater than or equal to 10 days. Write your answer as a decimal, and do not round your answer.

Question 1
A store owner want to develop a new snack mix by mixing chocolate and trail mix. How many pounds of
chocolate costing $8.20 per pound should be mixed with trail mix costing $3.40 per pound to create a 23
mixture worth $5.49. (round to the nearest pound)

Answers

The number of pounds of chocolate costing $8.20 per pound should be mixed with trail mix is; 18 pounds

How to solve Algebra Word Problems?

Let c represent the pounds of chocolate needed.

The weight of the snack mix is c + 23.

Thus, the algebraic expression here is;

8.2c + 3.4(23) = 5.49(c + 23)

8.2c + 78.2 = 5.49c + 126.27

8.2c - 5.49c = 126.27 - 78.2

2.71c = 48.07

c = 48.07/2.71

c ≈ 18 pounds

This value represents the number of pounds of chocolate costing $8.20 per pound should be mixed with trail mix

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Rosa has $300. Suppose she spends 1/4 of the money on art supplies and 2/5 of the remainder on a pair of boots. How much did she spend on the arts supplies?
How much on the boots? How much money does she have left after makina both purchases?

WILL GIVE BRAINLIST
PLS HELP ASAPPPPP

Answers

Let's call the amount of money Rosa spent on art supplies "x". Since Rosa spent 1/4 of her money on art supplies, we can write the equation:

x = (1/4) * 300

x = 75

So Rosa spent $75 on art supplies.

Now we can find out how much money she had left after spending the $75 on art supplies.

remaining = 300 - 75

remaining = 225

And we can find out how much she spent on the boots.

boots = (2/5) * remaining

boots = (2/5) * 225

boots = 90

So Rosa spent $90 on the boots.

Let's call the amount of money Rosa spent on art supplies "A". Since Rosa spent 1/4 of her original $300 on art supplies, we can write the equation:

A = 1/4 * $300

A = $75

So, Rosa spent $75 on art supplies.

Next, let's find out how much money she had left after buying the art supplies. We can subtract the amount she spent on art supplies from her original $300:

$300 - $75 = $225

Now, let's find out how much she spent on the boots. We know that she spent 2/5 of the remainder on the boots, so we can write the equation:

B = 2/5 * $225

B = $90

So, Rosa spent $90 on the boots.

This figure was created with three different rectangles. Find the total area in square centimeters.

Answers

The total area for the figure is given as follows:

288 cm².

How to obtain the area of a rectangle?

The area of a rectangle is given by the multiplication of the width and the length of the triangle, as follows:

A = lw.

The dimensions of each rectangle are given as follows:

8 cm and 9 cm.9 cm and 12 cm.9 cm and 12 cm.

Hence the total area is given as follows:

A = 8 x 9 + 2 x 9 x 12

A = 288 cm².

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On November 28, 2024, Shocker receives a $3,450 payment from a customer for services to be rendered evenly over the next three months. Deferred Revenue is credited. Record the adjusting entry for deferred revenue at its year-end of December 31

Answers

The adjusting entry for deferred revenue at its year-end of December 31 is $1,150

How to calculate simple interest amount?

If the initial amount (also called as principal amount) is P, and the interest rate is R% annually, and it is left for T years for that simple interest, then the interest amount earned is given by:

[tex]I = \dfrac{P \times R \times T}{100}[/tex]

We are given that;

The amount of payment=$3,450
Now,

The adjusting entry for deferred revenue at its year-end of December 31

Debit: Deferred Revenue $1,150 (which is one-third of the total payment received)

Credit: Revenue $1,150 (which represents the portion of the service that has been provided in December)

Therefore, by the given interest answer will be $1,150

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if one of these 1 million people is selected randomly, find the following probabilities: (a) p(b1), (b) p(a1), (c) p(a1 | b2), and (d) p(b1 | a1). (e) in words, what do parts (c) and (d) say?

Answers

The probability of carrying the AIDS virus in B1 is 0.5%

Probability is a fundamental concept in understanding the ELISA test results for AIDS diagnosis.

The probability of carrying the AIDS virus (B1) can be calculated by dividing the number of people who carry the virus by the total number of people who were tested.

From the contingency table, we can see that the number of people who carry the virus is 5000. Therefore, the probability of carrying the virus can be expressed as:

=> P(B1) = Number of people who carry the virus / Total number of people tested

=> 5000 / 1000000

=> 0.005 or 0.5%

This means that out of 1 million people who were tested, only 0.5% were found to be carrying the AIDS virus.

In this context, probability helps us understand the likelihood of carrying the virus and the accuracy of the test results. It also allows us to estimate the prevalence of the virus in a population and make informed decisions about public health policies and interventions.

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Complete Question:

A common test for AIDS is called the ELISA(enzyme-linked immunosorbent assay) test. Among 1 million peoplewho are given the ELISA test. we can expect results similar tothose given in the following table:

                     B1: Carry AIDS Virus       B2: Do not Carry AIDS Virus  Totals

A1: Test          4885                                73630                                       78515

Positive

A2: Test         115                                    921370                                   921485

Negative

Totals           5000                                995000                               1000000

If one of these 1 million people is selected randomly, find the value of P(B1).

What is 32/34 in simplest form

Answers

Answer:

Step-by-step explanation:16/17

Answer:

16/17 is the simplest form

Two buses leave Nashville at the same time traveling in opposite directions. One bus travels at 54mph and the other at 55mph. How soon will they be 490.5 miles apart?

Answers

6.6miles apart 55 hours in a sec 2-3 =.22

The students in the choir were lined up in rows of 9. The chorimaster rearranged them into equal number of rows and columns. There were more than 10 and fewer than 50 students in the choir. How many sutdents were there in the choir?

Answers

Answer: 36

Step-by-step explanation:

It must be a multiple of 9 for them to be in rows of 9 at the beginning therefore it can only be one of  18, 27, 36, 45 as it has to be bigger than 10 and smaller than 50 it cant be 9 or 54

It must also be a square number in order to have an equal amount of rows and column.

So it must be 36 as it is both a multiple of 9 and a square number.

the shop has 1100 ounces of cranberry juice and 680 ounces of passion fruit juice.if the juices are used to make crazy cranberry smoothies, which juice will run out first?how much of the other juice will be left over?

Answers

Answer: The passion fruit will run out first and 420 ounces left.

Step-by-step explanation: If you put the same amount of cranberry and passion fruit in each juice than they will be using an equal amount each time. We know that there are more ounces of cranberry than passion fruit which already tells us that there will be more cranberry when the passion fruit runs out. In order to find how much is left we can simply subtract the amount of cranberry and passion fruit.

1100-680=420

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