1) Suppose you place an object in front of a concave mirror. Which of the following statements must be true? (There could be more than one correct choice.) A) The image of the object will always be smaller than the object. B) No matter where you place the object, a real image of the object will be formed. C) The image of the object will always be inverted. D) If you position the object between the mirror and the focal point of the mirror, its image must be upright and virtual. E) No matter where you place the object, the image of the object will always be virtual and upright.

Answer:

mesa

Explanation:



A mesa is a flat-topped mountain or hill. It is a wide, flat, elevated landform with steep sides. ... Spanish explorers of the American southwest, where many mesas are found, used the word because the tops of mesas look like the tops of tables.

So, your science teacher has given your class the classic "mousetrap car" assignment: to make, design, and build a small vehicle powered by the snapping action of a mousetrap to make your car travel as far as possible. If you want to come out ahead of all the other students in your class, you'll need to make your car as efficient as possible so you can squeeze every last inch out of your "car". With the right approach, it's possible to streamline your car's design for maximum distance using only common home materials. You could also buy a mousetrap car kit from any craft store and skip wondering if it will work.

Use large rear wheels. Large wheels have greater rotational inertia than small wheels. In practice, this means that once they start rolling, they're harder to stop rolling. This makes large wheels perfect for distance-based contests — theoretically, they'll accelerate less quickly than smaller wheels, but they'll roll much longer and they'll travel a greater distance overall. So, for maximum distance, make the wheels on the drive axle (the one the mousetrap is tied to, which is usually the rear one) very large. The front wheel is a little less important — it can be large or small. For a classic drag racer look, you'll want big wheels in the back and smaller ones in front.

Use thin, light wheels. Thinner wheels have less friction and may go farther if the distance is what you want or need with your mousetrap racer. It's also important to take the weight of the wheels themselves into account — any unneeded weight will ultimately slow your car down or lead to added friction. In addition, it's worth noting that wide wheels can even have a small negative effect on the car's drag due to air resistance. For these reasons, you'll want to use the thinnest, lightest wheels available for your car.

Old CDs or DVDs work fairly well for this purpose — they're large, thin, and extremely light. In this case, a plumbing washer may be used to reduce the hole size in the middle of the CD (to fit the axle better).

If you have access to old vinyl, these also work extremely well, though they may be too heavy for the smallest mousetraps.

Use a narrow rear axle. Assuming your car is a rear-wheel-drive car, each time your rear axle turns, the rear wheels turn. If your rear axle is extremely skinny, your mousetrap car will be able to turn it more times for the same length of string than it would if it were wider. This translates to turning your rear wheels more times, meaning greater distance! For this reason, it's a wise idea to make your axle out of the skinniest material available that can still support the weight of the frame and wheels.

Narrow wooden dowel rods are a great, easily-accessible choice here. If you have access to thin metal rods, these are even better — when lubricated, they usually have less friction.

Create traction by giving the edges of the friction of the wheels. If the wheels slip against the ground when the trap is sprung, energy is wasted — the mousetrap works to make the wheels turn, but you don't get any extra distance. If this happens with your car, adding a friction-inducing material to the rear wheels may reduce their slippage. To keep your weight requirements down, use only as much as is necessary to give the tips of the wheels some grip and no extra. Some suitable materials are:[1]

Electrical tape

Rubber bands

Additionally, placing a piece of sandpaper under the rear wheels at the start line can reduce slippage as the car begins to move (when it is most likely)

Answer:

Work can be calculated with this equation: Work = Force x Distance. The SI unit for work is the Newton meter (N m). One joule equals the amount of work that is done when 1 N of force moves an object over a distance of 1 m.

Explanation:

Answer:

D

Explanation:

A is wrong as the direction of the car changes, implying velocity is changing and not constant.

B and C are wrong as both the change in speed and direction contribute to the change in velocity

Answer:

Explanation:

The acceleration of an object given only it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass in kg

From the question

m = 2400 kg

f = 740 N

We have

[tex]a = \frac{740}{2400} = \frac{74}{240} \\ = 0.308333...[/tex]

We have the final answer as

Hope this helps you

The force exerted on the cart 2 during the collision is 2 N.

The given parameters:

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart 1 is equal in magnitude to the force exerted on cart 2 but in opposite direction.

[tex]F_1 = -F_2[/tex]

[tex]F_2 = -F_1\\\\F_2 = -2 \ N\\\\|F_2| = 2 \ N[/tex]

Thus, the force exerted on the cart 2 during the collision is 2 N.

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Answer:

The reaction force is the water pushing the swimmer in the rightward direction.

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Doubt clarification - use comment section.

Explanation:

hope this may help you

have a nice day

The total momentum of the system is conserved and the momentum did not change.

The given parameters:

The initial momentum of the system is calculated as follows;

[tex]P_i = m_1 u_1 + m_2 u_2\\\\P_i = 0.17 \times 4 \ + \ 0.16(0)\\\\P_i = 0.68 \ kg m/s[/tex]

The final momentum of the system is calculated as follows;

[tex]P_f = m_1 v_1 + m_2 v_2 \\\\P_f = 0.17 (0) \ + 0.16(4.25)\\\\P_f = 0.68 \ kg m/s[/tex]

Thus, the total momentum of the system is conserved and the momentum did not change.

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Inside the bar magnet, the magnetic field points from north to south. Statement A is correct.

Magnetic Field:

It is defined as a vector field or the influence of the magnet on the electric current, charges and ferromagnetic substance.

The strength of magnetic field is depends up on the numbers of magnetic field lines per unit area.

Therefore, inside the bar magnet, the magnetic field points from north to south.

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Answer:b

Explanation:

Explanation:

1. By Newton's 3rd Law, both forces are equal and opposite. Hence both forces are of the same magnitude.

2. The reaction force is the force of arrow on bowstring.

3. Forward force of fish on water and vice versa?

4. The mass of the person is very small as compared to mass of earth. Hence the force exerted is very small amd hence the recoil is not noticed.

5. Reaction force is the force of ball against the bat. By Newton's Third Law, they form an action reaction pair. Hence, they are equal in magnitude and opposite in direction.

6. The reaction force will also decreases as both forces are equal in magnitude.

7 im nt sure sorry Ahahah

Answer: b. equal to or the same

In Law of Conservation of mass,  the mass of the product equals the mass of the reactant. A reactant is the chemical reaction of two or more elements to make a new substance, and a product is the substance that is formed as the result of a chemical reaction.

pls mark brainliest! i really need one :(

Using law of conservation of momentum

[tex]\\ \sf\Rrightarrow m_1v_1-m_2v_2=(m1+m2)v_3[/tex]

[tex]\\ \sf\Rrightarrow 1500(5)-3000(7)=(1500+3000)v_3[/tex]

[tex]\\ \sf\Rrightarrow 7500-21000=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow -13500=4500v_3[/tex]

[tex]\\ \sf\Rrightarrow v_3=-3m/s[/tex]

Answer:

I think you ask for another way of writing the joule (J). It can be expressed as the product between a force applied to a body and the deployment of the body (not necessarily caused by that force applied), so N*m (newton * meter).

The quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).

The quantity with a constant magnitude that is used to measure the magnitudes of other quantities of the same type is referred to as a unit in physics.

Unit of work is that of energy, that is, Joule (J).

Again, work = force × displacement

Unit of work = Unit of force × Unit of displacement = Newton . meter (N.m).

Hence, the quantity work—which has units of energy—was defined, another unit for energy, equivalent to the joule (j), is Newton ·meter (N· m).

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The magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

The given parameters:

The vector is represented with arrow pointing out from south-east represented in a Cartesian coordinate.

Thus, the magnitude and the position of the 350 N vector can be represented using arrow pointing out from the South-East of a Cartesian coordinate.

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Hi there!

I. They are the same.

Due to the Conservation of Momentum, an explosion as such means that the TOTAL momentum of the system (all of the pieces) is conserved.

Answer:

We know that ΔK = Kf - Ki = 1/2 m Vf^2 - 1/2 m Vi^2 = 1/2m(Vf^2-Vi^2) = 1/2 m ΔV^2.

The mass remains the same, just calculate the difference of squared velocities and multiply it by half of the mass.

A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.

Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.

In Science, the motion of an object or physical body is described in terms of the following parameters:

Furthermore, there are three (3) forms of motion based on dimension and these include:

1. Motion in one dimension

2. Motion in two dimension

3. Motion in three dimension

A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.

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Answer:1590 N

Explanation:

Impulse =  change in momentum/time

change in momentum = 0 - 50 x 35 = -1750

-1750/1.1 = 1590 (3s.f.) N

3. Distance is a quantity that is always a vector.

B.

Answer:

This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h

24.29m/s or 87.4km/h

Explanation:

Let's find the acceleration of the car:

let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s

a = (vf-vi)/Δt

a = (16.67m/s-0)/8.0

a = 2.08m/s^2

Now we can use this acceleration to find vf in the second part:

50km/h is 13.89m/s

a = (vf-vi)Δt

vf = aΔt + vi

vf = 2.08m/s^2*5.0+13.89m/s

vf = 24.29m/s (87.4km/h)

Answer:

Matter

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

I hope this helps:)

Explanation:

good luck:)

Answer:

The effects of radiation depend on the type, energy, and location of the radiation source, and the length of exposure.

Answer:

less than.

Explanation: because Friction is the resistance to motion of one object moving relative to another. which means it cant be greater because how would it be greater if its pushing forward when friction is the resistance.

THANKS FOR THE POINTS :D

The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.

Given to us,

the charge [tex]q[/tex] =  [tex]5\times 10^{-7}[/tex] C,

the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex]  m/sec,

the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,

angle between the direction of v and B [tex]\theta[/tex] = 0,

Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by

[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]

Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N

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