1. The length of each side of a square increased by 40%. By what percent does the area of the square increase?
2. The length of a rectangle increases by 20%, and the width decreases by 20%. What is the overall percent change in the area of the rectangle?

(they are two separate questions)

5

she gave her sister 5 toys.

Correction to the question - It is not 15 it 1/5th.

According to the given question Cynthia had 25 toys and she gave 1/5th of her toys to her little sister.

So, The total number of toys is 25 to find 1/5th of it we need to multiply the total number of toys she had and the fraction she gave.

(25 x 1/5) = 5. so the number of toys she gave away to her little sister is 5.

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Answer:

First Option, log 3x is equivalent to the expression shown

Answer:

15-14=1

Step-by-step explanation:

1 apple left

Answer:

1 apple

Step-by-step explanation:

15-14=1

Hope the helps!

Answer: - 0.3

Step-by-step explanation:

Correct me if I am incorrect.

Answer:

8.

9y-3y=6

-4x-(-5x)=1

the slope is 6

9.

you start at the 0 axis and go up 3 on the y.Once you did that you want to go up 2 on the y axis then 3 to the right on the x axis,then go up 2 then 3 to the right.

Step-by-step explanation:

Answer:

Rational

Step-by-step explanation:

It isnt whole because its a decimal,

It isnt an Integer because its a decimal

It isnt natural because its a decimal

Meaning it can only be rational

Answer:

It would be 1 whole

Step-by-step explanation:

1/2 - 1/2 is 0 the only thing left is one whole

Answer:

4a(3a+5)

We take H.C.F of both number and the variables then we compare the HCF number and variable with our question and equate and write the answer about how much should be multiplied from the H.C.F answer to get the question.

Answer:

solution given :

Since opposite side and side of a congruent triangle are equal.

Now

the statement which is true is:

<HDG=~ <HFE

I'll do the first two parts to get you started.

=====================================================

Part (i)

We can show that the operation [tex]\nabla[/tex] is not commutative by picking two random and different real numbers for a,b. In other words, I'm using a counter-example.

Let's say we go for a = 1 and b = 2

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\1 \nabla 2 = \frac{3*1+2}{5} - 1\\\\1 \nabla 2 = \frac{5}{5} - 1\\\\1 \nabla 2 = 1 - 1\\\\1 \nabla 2 = 0\\\\[/tex]

Now let's swap the values. We'll try a = 2 and b = 1

[tex]a \nabla b = \frac{3a+b}{5} - 1\\\\2 \nabla 1 = \frac{3*2+1}{5} - 1\\\\2 \nabla 1 = \frac{7}{5} - 1\\\\2 \nabla 1 = 1.4 - 1\\\\2 \nabla 1 = 0.4\\\\[/tex]

We can see that [tex]1 \nabla 2[/tex] and [tex]2 \nabla 1[/tex] are not the same value. In general, [tex]a \nabla b \ne b \nabla a[/tex] Therefore, the operation [tex]\nabla[/tex] is not commutative.

The only time [tex]a \nabla b = b \nabla a\\\\[/tex] is true is when [tex]a = b[/tex], since,

[tex]\frac{3a+b}{5}-1 = \frac{3b+a}{5}-1\\\\\frac{3a+a}{5}-1 = \frac{3a+a}{5}-1\\\\\frac{4a}{5}-1 = \frac{4a}{5}-1\\\\[/tex]

It's when [tex]a \ne b[/tex] is where the operation becomes noncommutative.

Another way to arrive at the [tex]a = b[/tex] condition is to solve the original equation for either 'a' or b.

=====================================================

Part (ii)

Using the previous part as inspiration, we'll do a counter-example to show that the operation is not associative. Pick 3 random values for a,b,c. Here are the values I'll pick.

Then,

[tex]d = b \nabla c = \frac{3b+c}{5}-1 = \frac{3*2+3}{5}-1 = 0.8\\\\a \nabla (b \nabla c) = a \nabla d = \frac{3a+d}{5}-1 = \frac{3*1+0.8}{5}-1 = -0.24\\[/tex]

Next, we can say:

[tex]d = a \nabla b = \frac{3a+b}{5}-1 = \frac{3*1+2}{5}-1 = 0\\\\(a \nabla b) \nabla c = d \ \nabla c = \frac{3d+c}{5}-1 = \frac{3*0+3}{5}-1 = -0.4[/tex]

Let's compare the two outputs:

[tex]a \nabla (b \nabla c) = -0.24\\\\(a \nabla b) \nabla c = -0.4[/tex]

They don't match up, so [tex]a \nabla (b \nabla c) \ne (a \nabla b) \nabla c[/tex] when (a,b,c) = (1,2,3).

In general, the operation is not associative in R.

Answer:

-1.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

Assuming the density is the same for both lollipops, we can calculate what volume is required to make the 2158.7kg the same density of the smaller lollipop.  

Small Lollipop

r = 2cm

V=4 /3πr^3

V = 33.51 cm^3

Mass is 50 g in 33.51 cm^3, so the density is:

50g/(33.51 cm^3) = 1.492 g/cm^3

We have 2158.7kg in the larger lollipop.  That is 2158700 grams.

Find the volume required to contain 2158700 grams with a density of 1.492 g/cm^3.  :

       (2158700 grams)/(1.492 g/cm^3) = 1446775 cm^3

V=4 /3πr^3

1446775 cm^3 = (4/3)*π*r^3

r = 70.12 cm

Answer:

1) -15/4

2) -15/2

Step-by-step explanation:

1) Let u=4t. Then the limits become u=4(0)=0 and u=4(4)=16. Also du=4 dt upon differentiating the equation.

So the integral can be written as

Integral( 1/4 f(u) , u=0 to u=16)

We are given Integral( f(u) , u=0 to u=16) is -15. So a fourth of that is our answer for the first question.

2) Let u=t^2. Then the limits become u=(0)^2=0 and u=(4)^2=16. Also upon differentiating we obtain equation du =2 t dt.

So the integral becomes

Integral( 1/2 f(u) , u=0 to u=16).

We are given Integral( f(u) , u=0 to u=16) is -15. So a half of that is our answer for the second question.

Answer:

3/16

Step-by-step explanation:

3/4÷4=3/16

Since there are 4 people, not 3, divide the remaining pizza by 4.

Answer:

it is A bacause the fractions for that one are correct

Step-by-step explanation:

Answer:

Step-by-step explanation:

65%

Step-by-step explanation:

Given: Full capacity= 200000 litres

          Amount of fuel used during flight= 130000 litres

Now, finding percentage of fuel used on the flight.

∴ Percentage of fuel used=  

Solving it, we will get  

∴ 65% of fuel capacity been used in this flight.

Answer:

65%.

Step-by-step explanation:

(130,000/200.000) * 100

= 0.65 * 100

= 65%.

Answer:

Step-by-step explanation:

[tex]g(x) = {x}^{2} - 2[/tex]

To find g(2) - 2 first find g(2) by substituting the value of x that's 2 into the original expression after that subtract 2 from the final answer obtained.

We have

[tex]g(2) = {2}^{2} - 2 \: \: \: \: \: \: \: \: \: \: \\ = 4 - 2 = 2 \\ \\ \\ g(2) - 2 = 2 - 2 = 0[/tex]

We have the final answer as

Hope this helps you

Step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

Answer:

what the

Step-by-step explanation:

Answer:

81.5

Step-by-step explanation:Cube has all sides of equal dimensions and like that it has 6 faces.

So total surface area of cube is equal to the combined area of all the six faces.

Now each face has equal dimensions so same area

Therefore,

area of a single face =side²

Therefore, area of entire cube = 6 times the area of a single face

= 6 * side²

.

Answer:

31/99

Step-by-step explanation:

Becuase the numerator is lesser than the denominator

Answer:

C. 31/99

Step-by-step explanation:

It's C because a proper fraction is a fraction with a numerator that is less that it's denominator in its lowest terms

Answer:

This is indeed a function!

Step-by-step explanation:

Answer:

1/3

Step-by-step explanation:

-2-4 = -6

-7-11 = -18

a.

The rate of the plane in still air is 700 km/h

Let V = rate of plane in still air and v = rate of wind.

When flying against the wind, an airplane travels 5220 kilometers in 9 hours, we have that since distance = speed × time

(V - v) × 9 = 5220

V - v = 5220/9

V - v = 580  (1)

Also, flying with the wind, the same plane travels 6560 kilometers in 8 hours, we have that since distance = speed × time

(V + v) × 8 = 6560

V + v = 6560/8

V + v = 820 (2)

Adding equations (1) and (2), we have

V - v = 580  (1)

+

V + v = 820 (2)

2V = 1400

V = 1400/2

V = 700 km/h

So, the rate of the plane in still air is 700 km/h.

b.

The rate of the wind is 120 km/h

Substituting V into (1), we have

V - v = 580  (1)

700 - v = 580  

v = 700 - 580

v = 120 km/h

So, the rate of the wind is 120 km/h

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Answer:

x = 5

Step-by-step explanation:

2x+15 = 4x+5 (because they are corresponding angles)

10 = 2x

x = 5

Answer:

x = 5

Step-by-step explanation:

Answer:

b) you need one set of | | for the inside of the logarithm only.

c) pi^2 /56

Step-by-step explanation:

For b, you just need | | instead of ( ) for the inside of the natural logarithm part... .

For c...

Integral( arcsin(7/6x)/sqrt(36-49x^2),x=0..6/7).

Lets go ahead and fix up the the denominator so the multipler on x is the same as it is in numerator.

Factor our sqrt(36) on bottom. Note sqrt(36)=6.

1/6Integral(arcsin(7/6x)/sqrt(1-(7x/6)^2),x=0..6/7)

Let 7/6x=sin(v). Then 7/6 dx=cos(v) dv.

If x=0 then we solve 7/6(0)=sin(v) giving us v=0. Note sin(0)=0.

If x=6/7 then we solve 7/6(6/7)=sin(v) giving us v=pi/2. Note sin(pi/2)=1...and I chose this particular value for v so the sine curve didn't have a chance to make a new or start a new cycle.

1/6×6/7Integral(v/sqrt(1-(sinv)^2) cos(v)),v=0..pi/2)

Next step invokes the Pythagorean Identity sin^2(v)+cos^2(v)=1:

1/7Integral(v/cos(v) cos(v), v=0..pi/2)

1/7Integral(v, v=0..pi/2)

1/7(v^2/2, v=0..pi/2)

1/7((pi/2)^2/2-(0)^2/2)

1/7(pi^2/4/2)

1/7(pi^2/8)

pi^2/56

Answer:

2.45

Step-by-step explanation: