1- Un avión vuela horizontalmente con una velocidad cuya magnitud es de 100 m/s y deja caer un proyectil desde una altura de 400 m con respecto al suelo. Determinar: a) El tiempo que transcurre antes de que el proyectil se impacte en el suelo. b) ¿Qué distancia horizontal recorre el proyectil después de iniciar su caída?

2- Se lanza horizontalmente un objeto con una velocidad de 80 m/s desde una altura de 160 m. Calcular: a) El tiempo que tarda en llegar al suelo b) La magnitud de la velocidad vertical que lleva a los 3 segundos. c) La distancia horizontal a la que cae el objeto a partir del punto desde que fue arrojada.

3- Se lanza un proyectil con una velocidad inicial de 80 m/s y una inclinación, sobre la horizontal, de 30°. Calcular: a) ¿Cuál es la altura máxima que alcanza la bala? b) ¿Cuáles son las posiciones, x y y, cuando han transcurrido 5 segundos?


4- Un joven patea una pelota contra un arco con una velocidad inicial de 20 m/s y con un ángulo de 45°. Determinar: a) cual es el alcance total

Assume R is measured in meters (m) and M in kilograms (kg). Then

R ² / (GM) = [m]² / ([N•m²/kg²] [kg]) = m•kg / N = m•kg / (kg•m/s²) = s²

so t ² is indeed proportional to R ²/(GM).

Answer:

dₒ/dᵢ = 0.32

Explanation:

From the question given above, the following data were obtained:

Object height (Hₒ) = 4 mm

Image height (Hᵢ) = 1.25 cm

Ratio of object distance (dₒ) to image distance (dᵢ) [dₒ/dᵢ] =?

Next, we shall convert 4 mm to cm. This can be obtained as follow:

10 mm = 1 cm

Therefore,

4 mm = 4 mm × 1 cm / 10 mm

4 mm = 0.4 cm

Next, we shall determine the magnification of the lens. This can be obtained as follow:

Object height (Hₒ) = 4 mm

Image height (Hᵢ) = 1.25 cm

Magnification (M ) =?

M = Hᵢ/Hₒ

M = 1.25 / 0.4

M = 3.125

Finally, we shall determine the ratio of object distance (dₒ) to image distance (dᵢ). This can be obtained as follow:

Magnification (M) = 3.125

Ratio of object distance (dₒ) to image distance (dᵢ) [dₒ/dᵢ] =?

Magnification (M) = image distance (dᵢ) / object distance (dₒ)

M = dᵢ/dₒ

Invert

1/M = dₒ/dᵢ

1/3.125 = dₒ/dᵢ

dₒ/dᵢ = 0.32

Therefore, the ratio of object distance (dₒ) to image distance (dᵢ) [dₒ/dᵢ] is 0.32

Answer:

4

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Answer:

16.5

Explanation:

Answer:

d)

Explanation:

the only one that makes sense

Answer:

Explanation:

Begin by remembering that at the stone's max height, the final velocity there is 0. Being in possession of that information along with the fact that the pull of gravity due to acceleration is -9.8 m/s/s, we can use the equation

[tex]v^2=v_0^2+2a[/tex]Δx where v is the final velocity, v₀ is the initial velocity, a is the pull of gravity, and Δx is the displacement. Filling in:

[tex]0^2=v_0^2+2(-9.8)(5.0)[/tex]

0 = v₀² - 98 so

98 = v₀² and

v = 9.9 m/s Now we can put that into the KE equation.

[tex]10=\frac{1}{2}m(9.8)[/tex] and

[tex]m=\frac{2(10)}{98}[/tex] so

m = .20 kg

Answer:

Depends: Is it tennis or volleyball?

Explanation:

If it's volleyball, it's C, the other teams point.

If it's tennis, it's A, you get a re-do.

Answer:

The acceleration (a) is the gravitational constant (g), so 9.81 or 9.8 or 10 (9.81 in this case)

Final velocity:

Vf = vi (0 in this situation ) + gt

Vf = 9.8 * 260 (time in seconds)

Vf = 2548

(I am not sure why here it is 4.6, but since that is the only option after we answer the other two questions, it is.)

Height: Same formula as previous.

h = 1/2gt^2

h = 331240 meter (a lot) (I converted minutes to second by multiplying 4 my 60 + the other 20 sec) (The answer is a bit different because I used 9.8 as gravitational constant and they used 9.81)

Answer:

Gravitational force -an attractive force that exists between all objects with mass; an object with mass attracts another object with mass; the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects.

Explanation:

hope it helped

The weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

The given parameters:

The gravitational force on the satellite is calculated by applying Newton's law of universal gravitation is calculated as;

[tex]F = \frac{Gm_1m_2}{R^2} \\\\F_1 R_1^2 = F_2R_2^2\\\\F_2 = \frac{F_1 R_1^2 }{R_2^2} \\\\F_2 =\frac{200 \times R_1^2}{(2R_1)^2} \\\\F_2 = \frac{200 \times R_1^2 }{4R_1} \\\\F_2 = 40 \ N[/tex]

Thus, the weight of the satellite at a distance of one Earth radius above the surface of Earth is 40 N.

Learn more about Newton's law of universal gravitation here: https://brainly.com/question/9373839

Answer:

Explanation:

This is a classic Law of Momentum Conservation problem. For us the equation will look like this:

[tex][(m_yv_y+m_bv_b)]_b=[(m_y+m_b)v_{both}]_a[/tex] Filling in with our given info:

[tex][(70.0)(0)+(.40)(10.0)]_b=[(70.0+.40)v_{both}]_a[/tex] and

4.0 = 70.4v and

v = .06 m/s

Answer:

Explanation:

If the passage of the waves is one crest every 2.5 seconds, then that is the frequency of the wave, f.

The distance between the 2 crests (or troughs) is the wavelength, λ.

We want the velocity of this wave. The equation that relates these 3 things is

[tex]f=\frac{v}{\lambda}[/tex] and filling in:

[tex]2.5=\frac{v}{2.0}[/tex] so

v = 2.5(2.0) and

v = 5.0 m/s

Answer:

Laser light however contains only one wavelength. This property makes lasers monochromatic, meaning of one color. Another property of lasers is that all the wavelengths are in phase, meaning they wave together. This property is called coherency. Laser light travels in the same direction, parallel to one another.

Answer:

m

Explanation:

.

Answer: on jupiter you would weigh the most  and on mars you would weigh the least

Explanation:

no net force axting on it

Answer:

I think none of above

Explanation:

hioe it's right answer

Answer:

Workdone = 19600 Nm

Explanation:

Given the following data;

Mass = 40 kg

Distance = 50 meters

We know that acceleration due to gravity is equal to 9.8 m/s².

To find the work done;

First of all, we would determine the force being exerted by the construction worker.

Force = mass * acceleration due to gravity

Force = 40 * 9.8

Force = 392 Newton

Next, we would determine the work done;

Workdone is given by the formula;

[tex] Workdone = force * distance[/tex]

[tex] Workdone = 392 * 50 [/tex]

Workdone = 19600 Nm

Answer:

Explanation:

3.75 * 10^-7

=3.75 * 1/10^7

=3.75/10000000

=3/800000000

any base which has it's power negative do it's reciprocal then the power will be positive.

Answer:

3.44×10-27 joules.

Explanation:

E = h * c / λ = h * f,

E is the energy of a photon

h is the Planck constant

c is the speed of light

λ is the wavelength

Answer:

Yes

Explanation:

If there were to be a supernova of a star or a planet/meter that was directed at earth, then we would know in advance and make a plan to stop it

Answer:

1.17

Explanation:

Given that,

The refractive index of ice wrt air = 1.31

The refractive index of rock salt wrt air = 1.54

We need to find the refractive index of rock salt with respect to ice.

We know that,

refractive index = (speed of light in air or vaccum)/( speed of light in that medium)

So,

The speed of light in ice = c/(1.31)

The speed of light in rock salt = c/(1.54)

So, the refractive index of rock salt with respect to ice​ is :

[tex]\mu=\dfrac{1.54}{1.31}\\\\=1.17[/tex]

So, the required refractive index of rock salt wrt ice is 1.17.

Answer:

G is universally constant

Explanation:

The Gravitational constant G, is a proportionality constant for all objects in the universe with a value of ; G = 6.67*10^-11 m³kg^-1s^-2.

According to the the Newton's Law of Universal Gravitation ; Every object in the universe attracts one another with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distances between them.

F α m1m2 α 1/r²

F α m1m2/r²

F = Gm1m2 / r²

m1 and m2 are the masses ; r = distance between them

G = Gravitational constant.

Answer:

313kelvin

Explanation:

40 degree celcius plus 273=313K

Answer:

Charge quantization is the principle that the charge of any object is an integer multiple of the elementary charge

Answer: Charge quantization is the principle that the charge of any object is an integer multiple of the elementary charge. Thus, an object's charge can be exactly 0 e, or exactly 1 e, −1 e, 2 e, etc., but not, say, 12 e, or −3.8 e

Explanation:

Answer:

the velocity is zero, the acceleration is directed downward, and the force of gravity acting on the ball is directed downward

Explanation:

Is this exercise in kinematics

          v = v₀ - g t

where g is the acceleration of the ball, which is created by the attraction of the ball to the Earth.

At the highest point

velocity must be zero.

The acceleration depends on the Earth therefore it is constant at this point and with a downward direction.

The force of the earth on the ball is towards the center of the Earth, that is, down

all other alternatives are wrong

Answer: Gas-liquid

Explanation:

Seltzer water is also called “sparkling water” or “carbonated water,” and it refers to the water which has been infused with carbon dioxide gas, which then causes it to bubble.

The type of solution that seltzer water is "gas liquid". Here, the solution is liquid while the solute is gas.

Answer:

gas - liquid

Explanation:

i took the quiz

Ohm's law states that :

the terms used are :

let's solve for electric current :

[tex]\mathfrak{good\: \: luck \: \: for \: \: your \: \: assignment}[/tex]

that's according to ma observation