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Kam Scheela MARIO MARTINEZ-HTPhysics.pdf
Test BGK
HW#10
Question: A pinball machine's plunger has a spring constant of 22
N/m and is compressed by 0.04 m to start a 0.006 kg pinball.
1. What is the elastic potential energy before the ball is released?
2. What is the kinetic energy of the pinball the instant it leaves the
spring?
3. What is the speed of the pinball the instant it leaves the spring?
4. If the pinball is moving at 1.3 m/s as it is deflected horizontally
across the top of the pinball machine, how much higher above the
ground is this part of its path when compared to its starting
position?
Squation
Drawing
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Instructions.
Answers
Answer:
1. The elastic potential energy is 0.0176 Joules
2. The kinetic energy of the pinball the instant it leaves the spring is 0.0176 Joules
3. The speed of the pinball the instant it leaves the spring is approximately 2.42212 m/s
4. The height of the part where the pinball is located on the machine above the ground is approximately 0.213 meters
Explanation:
The spring constant of the pinball machine's plunger, k = 22 N/m
The amount by which the pinball machine's plunger is compressed, x = 0.04 m
The mass of the pinball ball, m = 0.006 kg
1. The elastic potential energy, P.E. = 1/2·k·x²
By substitution, we get;
P.E. = 1/2 × 22 N/m × (0.04 m)² = 0.0176 J
The elastic potential energy, P.E. = 0.0176 J
2. At the instant the pinball leaves the spring, the plunger and therefore the force of the plunger no longer acts on the pinball
Since there are no external forces acting on the pinball to increase the speed of the pinball after it leaves the spring, the velocity reached is its maximum velocity, and therefore, the kinetic energy, K.E. is the maximum kinetic energy which by the conservation of energy, is equal to the initial potential energy
Therefore;
K.E. = P.E. = 0.0176 J
The kinetic energy of the pinball the instant it leaves the spring, K.E.= 0.0176 J
3. The kinetic energy, K.E., is given by the following formula;
K.E. = 1/2·m·v²
Where;
v = The speed or velocity of the object having kinetic energy K.E.
Therefore, from K.E. = 0.0176 J, and by plugging in the values of the variables, we have;
K.E. = 0.0176 J = 1/2 × 0.006 kg × v²
v² = 0.0176 J/(1/2 × 0.006 kg) = 88/15 m²/s²
v = √(88/15 m²/s²) ≈ (2·√330)/15 m/s ≈ 2.42212 m/s
The speed of the pinball the instant it leaves the spring, v ≈ 2.42212 m/s
4. The height of the pinball is given by the following kinematic equation of motion;
[tex]v_h[/tex]² = u² - 2·g·h
Where;
[tex]v_h[/tex] = The velocity of the pinball at the given height = 1.3 m/s
u = v ≈ 2.42212 m/s (The initial velocity of the pinball as it the spring)
g = The acceleration due to gravity ≈ 9.8 m/s²
h = The height of the pinball above the ground
We get;
[tex]v_h[/tex]² = 1.3² = 2.42212² - 2 × 9.8 × h
∴ h = (2.42212² - 1.3²)/(2 × 9.8) ≈ 0.213
The height of the part where the pinball is located on the machine above the ground, h ≈ 0.213 m
Related Questions
How much potential energy does a 4 kg object have that is 5 meters off the ground?
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196 J
Explanation:
GPE= ham
GPE= (5)(9.8)(4)
GPE= 196 J
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Answer:
No. If you apply a force in a chair, for example, you only will be able to move the chair if you beat the static frictional force. So, with that example, we can see that is not any type of force that can produce movement. The only force that produces movement is a result force which is non-zero.
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Question 4 (1 point)
How far does a sound wave travel in 3 seconds if the air temperature is 30 degrees
Celsius?
a) 114.33 m
b) 1047 m
c) 1029 m
d) 116.33 m
Answers
Answer:
B
Explanation:
v=349m/s
d=vt
d=349*3
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WHY 349??
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Velocity of sound is about 343 m/s at 20 degrees C, so 0.6*10=6 more m/s, or 349 m/s. Kinda cool how temperature alters the speed of sound!
The kinetic energy of a body moving at a speed of 10 m / s is equal to 1000 J. What is the body mass
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Answer:
m = 20 kg
Explanation:
Given that,
The speed of a body, v = 10 m/s
Kinetic energy of the body, K = 1000 J
We need to find the mass of the body. The formula for the kinetic energy of a body is given by :
[tex]K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 1000}{(10)^2}\\\\m=20\ kg[/tex]
So, the mass of the body is equal to 20 kg.
The brakes of a 2000 kg car apply a force of 250 N to slow down a car as it comes off of an exit ramp. What is the acceleration of the car?
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Answer:
Explanation:
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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (30pts)
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Answer:
5
Explanation:
From the attachement,
M.A = Load(L)/Effort(E)
M.A = L/E...................... Equation 1
Where M.A = .Mechanical Advantage, L = Load, E = Effort.
Given: L = 500 N, E = 100 N
Substitute these values into equation 1
M.A = 500/100
M.A = 5.
Hence the actual mechanical advantage of the pulley is 5
A car weighs 11000 N on Earth. What is its mass?
A) 300 kg
B) 1122 kg
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Use the periodic table on the next page to complete the following
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the nuclide number
Element and Chemicol Atomic Mass
Number Number
of
of
Hudito
isotope
number
Symbol.
number
notation
profons neutrons
2 4 나
Helium-4
He
Beryllium-9
Nitrogen-14
N
Oxygen 10
0
Phosphorus 32
P
Chlorine-35
Potassium 39
Tungston-150
w
Lead 90
PU
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Answer:
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Answers
Answer:
Angular acceleration [tex]= 0.167[/tex] rad/s^2
Explanation:
Given
Initial Angular velocity (w1) [tex]= 5[/tex] rad/s
Final Angular velocity (w2) [tex]= 0[/tex] rad/s
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Which two statements describe what happens in both nuclear fusion and
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A. Each nucleus formed has fewer protons than the original nucleus
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B. Nuclei with small masses combine to form nuclei with larger
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C. Radiation is released from the nuclei that undergo a reaction.
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Answer:
C. Radiation is released from the nuclei that undergo a reaction.
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Hope this helps!!
PLEASE HELP! WILL MARK BRAINLIEST!
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Answer:
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Momentum of a system is constant if there are no external forces acting on the system.
As they crash into each other and hold onto each other so that they move as one mass and no other force is acting on them, so conservation of momentum can be applied here.
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Explanation:
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Explanation:
ls xgfmc!hchlvb! jt?bjgchfb j
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A proton moves perpendicularly to a magnetic field that has a magnitude of 4.20 x 10-2 T. What is the speed of the particle if the magnitude of the magnetic force on it is 2.40 x 10-14 N?
Answers
Answer:
V=3.57 × 10^6 m/s
hope it is helpful..
The speed of the proton in the magnetic field is 3.57×10⁶ m/s.
To determine the speed of the proton, we need to know about the magnetic force experienced by a charged particle in a magnetic field.
What is the magnetic force on a charge particle in a magnetic field?From lorentz law, the magnetic force on a charge particle is given asF=q×v×B
where, q= charge of the particle
v= speed of the particle
B= magnetic field
What will be the speed of the charge particle, proton, if the magnetic field and force are given?Magnetic force(F)= q×v×Bv=F/(q×B)
Here, B= 4.20×10⁻²TF=2.40×10⁻¹⁴N
q= 1.6×10⁻¹⁹C
Then, v= 2.40×10⁻¹⁴/ ( 4.20×10⁻²× 1.6×10⁻¹⁹)
= 3.57×10⁶ m/s.
Thus, we can conclude that the speed of the proton in the magnetic field is 3.57×10⁶ m/s.
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