15 Mary needs to work out the size of angle x in this diagram.
DO NOT WRITE IN THIS AREA
63°
X
B
С
She writes
x = 63° because base angles of an isosceles triangle are equal.
Mary is wrong.
(a) Explain why.

Answers

Answer 1

Mary is wrong because ∠A = ∠B = 63°, while ∠C = x ≠ 63°

What is a triangle?

A triangle is a polygon with three sides and three angles. Types of triangles are equilateral, isosceles and right angled.

An isosceles triangle is a triangle in which two sides and two angles are equal.

From the diagram:

∠A = ∠B (base angles)

Mary is wrong because ∠A = ∠B = 63°, while ∠C = x ≠ 63°

Find out more on triangle at: https://brainly.com/question/17335144

15 Mary Needs To Work Out The Size Of Angle X In This Diagram.DO NOT WRITE IN THIS AREA63XBShe Writesx

Related Questions

Fastest answer gets brainliest (must provide an explanation and steps for proof)

Answers

Answer:

[tex]\sf g(x+5) = \dfrac{x+6}{4x+17}[/tex]

explanation:

g(x + 5) || this function refers to x = x + 5

solving steps:

[tex]\sf g(x) = \dfrac{1+x}{-3+4x}[/tex]

[tex]\rightarrow \sf g(x+5) = \dfrac{1+(x+5)}{-3+4(x+5)}[/tex]

[tex]\rightarrow \sf g(x+5) = \dfrac{6+x}{-3+4x+20}[/tex]

[tex]\rightarrow \sf g(x+5) = \dfrac{x+6}{4x+17}[/tex]

Answer:

Given function:

[tex]g(x)=\dfrac{1+x}{-3+4x}[/tex]

To find  [tex]g(x+5)[/tex], substitute  [tex]x+5[/tex]  into the function in place of [tex]x[/tex]:

[tex]\implies g(x+5)=\dfrac{1+(x+5)}{-3+4(x+5)}[/tex]

                     [tex]=\dfrac{1+x+5}{-3+4x+20}[/tex]

                     [tex]=\dfrac{x+6}{4x+17}[/tex]

Write a formula that only works if the angle in the formula is given in radians.

Answers

To convert degrees to radians, first convert the number of degrees, minutes, and seconds to decimal form. Divide the number of minutes by 60 and add to the number of degrees. So, for example, 12° 28' is 12 + 28/60 which equals 12.467 degrees. Next multiply by π and divide by 180 to get the angle in radians. Did it help?

Find the domain and range of the function shown.

Please help I’ll mark brainliest thank you.

Answers

Answer:

A

Step-by-step explanation:

Remember domain is input and range is output.

Input: All real numbers

Output: [0, infinity)

A

Janie has $3. She earns $1.20d for each chore she does and can do fractions of chores. She wants to earn enough money to buy a CD for $13.50.
Write an inequality to determine the number of chores, c, Janie could do to have enough money to buy the CD.

Answers

Answer:

3+1.20c > 13.50

Step-by-step explanation:

hope this helps

​Triangle A′B′C′​ is a dilation of ​triangle ABC​ .
What is the scale factor?
Enter your answer in the box.

Answers

Answer:

1/2

Step-by-step explanation:

The scale factor is 1/2 because each side length of [tex]\triangle{A'B'C'}[/tex] is 1/2 of the length of the side lengths of [tex]\triangle{ABC}[/tex].

Hope this helps :)

Answer:

1/2

Step-by-step explanation:

took the test

Solve for b.
-3b + 2.5 = 4

Answers

Answer: b = -0.5

Step-by-step explanation:

Given

-3b + 2.5 = 4

Subtract 2.5 on both sides

-3b + 2.5 - 2.5 = 4 - 2.5

-3b = 1.5

Divide -3 on both sides

-3b / -3 = 1.5 / -3

[tex]\boxed{b=-0.5}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

[tex]\Longrightarrow: \boxed{\sf{b=-0.5}}[/tex]

Step-by-step explanation:

To solve this problem, all you have to do is isolate the term of b from one side of the equation.

-3b+2.5=4

First, you have to subtract by 2.5 from both sides.

→ -3b+2.5-2.5=4-2.5

Solve.

Add or subtract the numbers from left to right.

→ -3b=1.5

Then, you divide by -3 from both sides.

→ -3b/-3=1.5/-3

Solve.

Divide the numbers from left to right.

→ 1.5/-3=-0.5

b=-0.5

Therefore, the correct answer is b=-0.5.

I hope this helps! Let me know if you have any questions.

the legnth of a rectangle is three times its width. if the perimeter of the rectangle is 64 in, find the length and width

Answers

Step-by-step explanation:

According to the question,

Let the width of rectangle be x and length of rectangle be 3x

Perimeter of Rectangle :- 2(L+B) = 64 in

Putting the values we get ,

2(3x+x) = 64 in

8x = 64 in

x = 8 in

Putting the value of x ,

Width :- 8 Inch

Length :- 24 inch

Given:-

[tex]\rightarrow[/tex] Length(l) of the rectangle is three times it's width(w) = 3w.

[tex]\rightarrow[/tex] Width(w) of the rectangle = w.

[tex]\rightarrow[/tex] Perimeter of the rectangle = 64in.

To Find:-

[tex]\rightarrow[/tex]Length and width of the rectangle.

Solution:-

[tex]\rightarrow[/tex] Perimeter of rectangle = [tex]\sf{2(l+w)}[/tex] putting the value of perimeter, l and w from the above given)

[tex]\rightarrow[/tex] 64 = [tex]\sf{2(3w+w)}[/tex]

[tex]\rightarrow[/tex] 64 = [tex]\sf{2(4w)}[/tex]

[tex]\rightarrow[/tex] 64 = [tex]\sf{8w}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{\frac{64}{8}}[/tex]= [tex]\sf{w}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{8}[/tex]= [tex]\sf{w}[/tex]

Therefore, width of the rectangle = 8in.

And Length = 3(8)in. = 24in.

To check whether the answer is correct or not, we can put the value of length and width in the formula = [tex]\sf{2(l+w)}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{=\: 2(24+8)}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{=\: 2(32)}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{=\: 64in.}[/tex]

Since, the perimeter of the rectangle is same as given in the question, therefore the value of length and width are correct.

_______________________________

Hope it helps you:)

What percent of 1/4 is 1/5
5%
16%
24%
80%

Answers

[tex]\text{Let it be x percent}\\ \\\dfrac 14 \times x\% = \dfrac 15\\\\\\\implies\dfrac 14 \times \dfrac x{100} = \dfrac 15\\ \\\\\implies x = \dfrac{400}{5} = 80\\\\\\\text{Hence the answer is}~ 80\%[/tex]

Am I right??? Please help me

Answers

Function: y = 2x²-5

Find y-intercept:

y = 2(0)²-5

y = -5

Find x-intercept:

2x²-5 = 0

2x² = 5

x² = 2.5

x = ±√2.5

x = -1.5811 , 1.5811

Graph plotted:

Answer:

Vertex and y-intercept (0, -5)

x-intercepts (-1.58, 0)  (1.58, 0)

opens upwards

other plot points: (-2, 3) (-1, -3) (1, -3) (2, 3)

Step-by-step explanation:

The graph is not quite correct - it's a little too narrow and doesn't go through the points on the graph.

The y-intercept is when x = 0:

f(0) = 2(0)² - 5

      = - 5

Therefore, the y-intercept is at (0, -5)

We also know that the y-intercept is the vertex since the equation is in the form [tex]f(x)=ax^2+c[/tex]

The x-intercepts are when f(x) = 0:

[tex]\implies 2x^2 - 5 = 0[/tex]

[tex]\implies x^2 =\dfrac52[/tex]

[tex]\implies x=\pm1.58113883...[/tex]

As the leading coefficient is positive, the parabola opens upwards.

Finally, input values -2 ≤ x ≤ 2 to find plot points:

(-2, 3)

(-1, -3)

(0, -5)

(1, -3)

(2, 3)

Find the area of the shaded polygons.

Answers

Answer: 372 sq. un

Step-by-step explanation:

7+24=31

Divided by 2 = 15.5

15.5x24 = 372

Which is the graph of 25x2 + 4y2 = 100?

Answers

Answer:

nasa pic yung answer

Step-by-step explanation:

hope its help

correct me if im wrong

In a circle, a 270° sector has area 300s in? What is the radius of the circle?
.

Answers

[tex]\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ A=300\pi \\ \theta =270 \end{cases}\implies 300\pi =\cfrac{(270)\pi r^2}{360}\implies 300\pi =\cfrac{3\pi r^2}{4} \\\\\\ 1200\pi =3\pi r^2\implies \cfrac{1200\pi }{3\pi }=r^2\implies 400=r^2\implies \sqrt{400}=r\implies 20=r[/tex]

solve the question in the picture​

Answers

Answer:

n = 7

Step-by-step explanation:

simplify the logs according to their bases

Answer:

n = 7

Step-by-step explanation:

[tex]\sf \log_4(64)^{n+1}=log_5(625)^{n-1}[/tex]

Change 64 to an exponent with base 4 and 625 to an exponent with base 5:

[tex]\implies \sf \log_4(4^3)^{n+1}=log_5(5^4)^{n-1}[/tex]

Using exponent rule [tex](a^b)^c=a^{bc}[/tex]

[tex]\implies \sf \log_4(4)^{3(n+1)}=log_5(5)^{4(n-1)}[/tex]

Using log rule:  [tex]\log_a(b^c)=c \log_a(b)[/tex]

[tex]\implies \sf 3(n+1)\log_4(4)}=4(n-1)log_5(5)[/tex]

Using log rule: [tex]\sf \log_a(a)=1[/tex]

[tex]\implies \sf 3(n+1)=4(n-1)[/tex]

[tex]\implies \sf 3n+3=4n-4[/tex]

[tex]\implies \sf 3+4=4n-3n[/tex]

[tex]\implies \sf n=7[/tex]

3+(-7)×2-10÷(-5)
please step by step0​

Answers

[tex]\left[3+(-7)\times 2\right] - \left[10 \div(-5)\right]\\\\=(3-14) +\left(10\times \dfrac 15\right)\\\\=-11+2\\\\=-9[/tex]

solve to get brainiest ​

Answers

3.

[tex] \frac{3}{10 } = 0.3[/tex]

[tex]0.25 < 0.3 < 0.333[/tex]

[tex] \frac{32}{100} = \frac{8}{25} = 0.32[/tex]

[tex]0.25 < 0.32 < 0.333[/tex]

[tex] \frac{26}{100} = \frac{13}{50} = 0.26[/tex]

[tex]0.25 < 0.26 < 0.333[/tex]

[tex] \frac{28}{100} = \frac{7}{25} = 0.28[/tex]

[tex]0.25 < 0.28 < 0.333[/tex]

[tex] \frac{252}{1000} = \frac{63}{250} = 0.252[/tex]

[tex]0.25 < 0.252 < 0.333[/tex]

5.

[tex] \frac{ \frac{ - 2}{5} + \frac{1}{2} }{2} = \frac{ \frac{ - 4 + 5}{10} }{2} = \frac{ \frac{1}{10} }{2} = \frac{1}{20} [/tex]

PLEASE HELP!

The scatter plot shows the number of years of experience, x, and the
amount charged per hour, y, for each of 25 dog sitters in Texas.

(a) Write an approximate equation of the line of best fit for the data. It doesn't have to be the exact line of best fit.

(b) Using your equation from part (a), predict the amount charged per hour by a dog sitter with 18 years of experience.

Answers

Answer:

(a) [tex]\sf y=\dfrac{11}{20}x+7[/tex]

(b) $16.90

Step-by-step explanation:

Part (a)

Add a line of best fit (see attached).

Find two points on the line:  (7, 0) and (20, 18)

Use these points to find the slope of the line:

[tex]\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{18-7}{20-0}=\dfrac{11}{20}[/tex]

Use the found slope and one of the points in the point-slope form of the linear equation to find an equation for the line of best fit:

[tex]\sf\implies y-y_1=m(x-x_1)[/tex]

[tex]\sf\implies y-7=\dfrac{11}{20}(x-0)[/tex]

[tex]\sf\implies y=\dfrac{11}{20}x+7[/tex]

Part (b)

Substitute x = 18 into the equation and solve for y:

[tex]\sf\implies y=\dfrac{11}{20}(18)+7=\$16.90[/tex]

- Critique Reasoning Tanya recorded the ages
of 10 local babysitters: 20, 16, 18, 13, 14, 13,
12, 16, 22, 18. She says that the box plot below
shows the distribution of ages. What error did
she make?
Babysitters
HHHHHH
12
14
10
16
18
20
22
24
Age in Years

Answers

The error made by Tnaya in constructing the box plot is the first quartile and third quartile depicited is wrong.

What is a box plot?

A box plot is used to study the distribution and level of a set of data. The box plot consists of two lines known as whiskers and a box. The first whisker represents the minimum value and the last whisker represents the maximum value.

On the box, the first line to the left represents the first quartile. 25% of the score represents the lower quartile. The next line on the box represents the median. 50% of the score represents the median. The third line on the box represents the third quartile. 75% of the scores represents the third quartile.

For the data given, the:

Minimum value = 12 Maximum value = 22Median = 16 First quartile  = 11/4 = 2.75 = 13 Third quartile = 3/4 x 11 = 8.25 = 23

To learn more about median, please check: https://brainly.com/question/20434777

Carlos is saving for a new bike. he is paid $6.60 an hour and works 10 hours per week at his after-school job. If he saves 75% of the money he earns, how much does he save each week?

Answers

Answer:

16.50 per week

Step-by-step explanation:

6.60 times 10 equals 66 minus 75% equals 16.50

sketch the graph of y=2x^2-3x-4​

Answers

There is your answer

The response to a question has three alternatives: A, B, and C. A sample of 120 responses provides 60% A, 23% B, and 37% C. Show the frequency and relative frequency distributions

Answers

Answer:

0.5,0.2,0.3

Step-by-step explanation:

divide 60,23,37 by 120

HELLLPP ME PLEASSEEE!!!!!

Consider the two circles shown.


To show that circle P is similar to circle Q, circle P is translated t units to the right. The image is then dilated about its center by a scale factor of s.
What are the values of t and s?
Show me:
(t) What is the horizontal distance between the center of circle P to the center of circle Q?
(s) What is the scale factor dilating from circle P to circle Q?

Answers

The similar circles P and Q can be made equal by dilation and translation

The horizontal distance between the center of circles P and Q is 11.70 unitsThe scale factor of dilation from circle P to Q is 2.5

The horizontal distance between their centers?

From the figure, we have the centers to be:

P = (-5,4)

Q = (6,8)

The distance is then calculated using:

d = √(x2 - x1)^2 + (y2 - y1)^2

So, we have:

d = √(6 + 5)^2 + (8 - 4)^2

Evaluate the sum

d = √137

Evaluate the root

d = 11.70

Hence, the horizontal distance between the center of circles P and Q is 11.70 units

The scale factor of dilation from circle P to Q

We have their radius to be:

P = 2

Q = 5

Divide the radius of Q by P to determine the scale factor (k)

k = Q/P

k = 5/2

k = 2.5

Hence, the scale factor of dilation from circle P to Q is 2.5

Read more about dilation at:

https://brainly.com/question/3457976

Given the function
[tex]f(x) = (x + 4){(x - 2)}^{2} [/tex]
Determine the end behavior of the graph of the function. Show all/any work​

Answers

[tex]lim \: f(x) = ( \infty + 4)( \infty - 2) {}^{2} \\ x - > \infty [/tex]

[tex]lim \: f(x) = \infty \times \infty \\ x - > \infty [/tex]

[tex]lim \: f(x)= \infty \\ x - > \infty [/tex]

[tex]lim \: \frac{f(x)}{x} = \frac{x(1 - \frac{4}{x})(x - 2) {}^{2} }{x} \\ x - > \infty [/tex]

[tex]lim \: \frac{f(x)}{x} = (1)( \infty - 2) {}^{2} \\ x - > \infty [/tex]

[tex]lim \: \frac{f(x)}{x} = \infty \\ x - > \infty [/tex]

We can then say that the function f(x)=(x-4)(x-2)² admits an asymptotic direction parallel to the y-axis at + and - as well since we have to follow the same steps.

Please help me with these. God bless you

Answers

Counting all of the lines, there is About 17

Answer:

The lines of symmetry in the wheel is infinite.

Explanation:

Since there are an infinite number of lines through the center, a circle has an infinite number of lines of symmetry.

Which rectangles have the same areas but greater perimeters than the one shown below? Choose all that apply.

A rectangle is shown with a length and height of 6 ft.

A.
12 feet long and 3 feet wide

B.
9 feet long and 4 feet wide

C.
8 feet long and 3 feet wide

D.
7 feet long and 4 feet wide

E.
18 feet long and 2 feet wide

Answers

The  rectangles have the same areas but greater perimeters are 12 ft by 3 ft, 9 ft by 4 ft and 18 ft by 2 ft.

What is area?

Area is the amount of space occupied by a two dimensional shape or object.

A rectangle is shown with a length and height of 6 ft. Hence:

Area = (6 * 6) = 36 ft²

Perimeter = 2(6 + 6) = 24 ft

For 12 ft by 3 ft:

Area = (12 * 3) = 36 ft²

Perimeter = 2(12 + 3) = 30 ft

For 9 ft by 4 ft:

Area = (9 * 4) = 36 ft²

Perimeter = 2(9 + 4) = 26 ft

For 8 ft by 3 ft:

Area = (8 * 3) = 24 ft²

Perimeter = 2(8 + 3) = 24 ft

For 7 ft by 4 ft:

Area = (7 * 4) = 28 ft²

Perimeter = 2(7 + 4) = 26 ft

For 18 ft by 2 ft:

Area = (18 * 2) = 36 ft²

Perimeter = 2(18 + 2) = 40 ft

The  rectangles have the same areas but greater perimeters are 12 ft by 3 ft, 9 ft by 4 ft and 18 ft by 2 ft.

Find out more on area at: https://brainly.com/question/25292087

Q. If A is a square matrix such that A² = A, then write the value of 7 A −(I + A)³, where I is an identity matrix.​

Answers

Since [tex]A^2=A[/tex], we have

[tex](I + A)^2 = I^2 + IA + AI + A^2 = I + A + A + A = I + 3A[/tex]

[tex](I + A)^3 = (I + A) (I + 3A) = I^2 + 3IA + AI + 3A^2 = I + 3A + A +  3A = I + 7A[/tex]

Then the target expression is

[tex]7A - (I + A)^3 = 7A - (I + 7A) = \boxed{-I}[/tex]

A dairy farmer plans to enclose a rectangular pasture adjacent to a river. To provide enough grass for the herd, the pasture must contain 18 square meters. No fencing is required along the river. What dimensions will use the least amount of fencing?

Answers

Answer:

390 m (perpendicular to river) x 780 m (parallel to river)

Step-by-step explanation:

Let y be the length of the side parallel to the river, and let x be the length of the sides perpendicular to the river.

The total area and length of fence required are given by:

Rewriting the length of fence as a function of only x:

The value of x for which the derivate of L(x) is zero is the length of x that uses the least amount of fencing:

If x = 390 m, then:

The dimensions that will use the least amount of fencing are 390 m x 780 m

.
If two complementary angles are placed side by side, they form a(n)
angle. Side-by-side angles that share a ray and a vertex are called
angles.
of comnlementary angles you can solve for the

Answers

Answer:

Two angles whose sides are opposite rays are called vertical angles. Two coplanar angles with a common side, a common vertex, and no common interior points are called adjacent angles.

Further explanation

Adjacent Angles are two angles that share a common vertex, a common side, and no common interior points. They share a vertex and side, but do not overlap. The example is shown in the picture below.  

Where ∠1 and ∠2 are adjacent angles, ∠ABC and ∠1 are NOT adjacent angles because ∠ABC overlaps ∠1.

Vertical Angles are two angles whose sides form two pairs of opposite rays (straight lines). Vertical angles are located across from one another in the corners of the "X" formed by the two straight lines.  The example is shown in the picture below.

Where ∠1 and ∠2 are vertical angles, ∠3 and ∠4 are vertical angles, Vertical angles are not adjacent.  ∠1 and ∠3 are not vertical angles (they are a linear pair) and Vertical angles are always equal in measure.

Step-by-step explanation:

An ice cream shop sold 352 scoops of ice cream.25% of the scoops sold were strawberry ice cream.how many scoops of strawberry ice cream were sold

Answers

Answer:

88 scoops

Step-by-step explanation:

Hello!

If 25% of 352 scoops were strawberry, we find 25% of 352

Solve:

25% of 3520.25 * 35288

This means 88 scoops of strawberry were sold.

Image attatched for conversion of decimals, percents, and fractions.

Write an equation in standard form of an ellipse that is 10 units high and 8 units wide. The center of the ellipse is (0, 0).

Answers

Answer:

[tex]\frac{x^2}{25} + \frac{y^2}{16} = 1[/tex]

Step-by-step explanation:

Great, so the question already tells you that you're using the standard form of an ellipse. All you gotta do is apply your knowledge of the characteristics of an ellipse graph.

The standard form of an ellipse is:

[tex]1 = \frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2}[/tex]

[tex]h[/tex] and [tex]k[/tex] are the offset, or the coordinates of the center of the ellipse. The center of the ellipse will always be on (h,k). Now because the question says the center is (0,0), we can make h and k equal to 0 in the equation giving:

[tex]1 = \frac{x^2}{a^2} + \frac{y^2}{b^2}[/tex].

Now, the height of the ellipse will always be equal to 2a. The width will be equal to 2b.

Since we are told what the height and width should be, we can find the a and b values quite easily using algebra.

So first, height:

[tex]10 = 2a\\5 = a[/tex]

Now width:

[tex]8 = 2b\\4 = b[/tex]

Subbing for a and b in the equation give you:

[tex]1 = \frac{x^2}{5^2} + \frac{y^2}{4^2}\\=\\1 = \frac{x^2}{25} + \frac{y^2}{16}[/tex]

hello help me with this question thanks in advance​

Answers

Question #38 Answer

D. 40 ft.

Explanation:

Based on the given conditions, formulate:

[tex]30\times20\div15[/tex]

Calculate

[tex]\frac{30\times20}{15}[/tex]

Cross out the common factor

[tex]2\times20[/tex]

Calculate the product or quotient

[tex]40[/tex]

___________________________________________________

Question #39 Answer

C. Yes, Right Triangle Similarity Theorem

Explanation:

[tex]-\ If\ an\ altitude\ is\ drawn\ to\ the\ hypotenuse\ of\ a\\ right\ triangle,\ then\ the\ two\ triangles\ formed\ are\\ similar\ to\ the\ original\ triangle\ and\ to\ each\ other.[/tex]

____________________________________________________

Question #40 Answer (Picture attached)

D. 23.40 ft.

Explanation:

[tex]height\ of\ tree:x[/tex]

[tex]\frac{x}{s_0-d_0}=\frac{39}{50}[/tex]

[tex]x=\frac{30.39}{50}[/tex]

[tex]=23.40ft[/tex]

[tex]\left \{ {{calculate\}[/tex]

I hope this helps you

:)

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