2. A test reveals that 150 J of work is required to lift an object 3 m at a
constant speed. What is the weight of the object?
0 50 N
25N
55N
O 75N

Answer:

50 protons 50 electrons and 69 neutrons...

Explanation:

the number of protons is equal to number of electrons. then mass number is the sum of protons and neutrons in a nucleus so for we to get the number of neutrons we take the mass number subtract the protons number.

Answer:

the answer is c

Explanation:

see the light appears from there and with the dotted lines you can clearly see the green line touches the dot okay, then the light appears smaller because of water and light source

Answer:

Ai. Speed of the fragment with mass mA= 1.35 kg is 34.64 m/s

Aii. Speed of the fragment with mass mB = 0.270 kg is 77.46 m/s

B. 475.3 m

Explanation:

A. Determination of the speed of each fragment.

I. Determination of the speed of the fragment with mass mA = 1.35 kg

Mass of fragment (m₁) = 1.35 kg

Kinetic energy (KE) = 810 J

Velocity of fragment (u₁) =?

KE = ½m₁u₁²

810 = ½ × 1.35 × u₁²

810 = 0.675 × u₁²

Divide both side by 0.675

u₁² = 810 / 0.675

u₁² = 1200

Take the square root of both side.

u₁ = √1200

u₁ = 34.64 m/s

Therefore, the speed of the fragment with mass mA = 1.35 kg is 34.64 m/s

II. I. Determination of the speed of the fragment with mass mB = 0.270 kg

Mass of fragment (m₂) = 0.270 kg

Kinetic energy (KE) = 810 J

Velocity of fragment (u₂) =?

KE = ½m₂u₂²

810 = ½ × 0.270 × u₂²

810 = 0.135 × u₂²

Divide both side by 0.135

u₂² = 810 / 0.135

u₂² = 6000

Take the square root of both side.

u₂ = √6000

u₂ = 77.46 m/s

Therefore, the speed of the fragment with mass mB = 0.270 kg is 77.46 m/s

B. Determination of the distance between the points on the ground where they land.

We'll begin by calculating the time taken for the fragments to get to the ground. This can be obtained as follow:

Maximum height (h) = 90.0 m

Acceleration due to gravity (g) = 10 m/s²

Time (t) =?

h = ½gt²

90 = ½ × 10 × t²

90 = 5 × t²

Divide both side by 5

t² = 90/5

t² = 18

Take the square root of both side

t = √18

t = 4.24 s

Thus, it will take 4.24 s for each fragments to get to the ground.

Next, we shall determine the horizontal distance travelled by the fragment with mass mA = 1.35 kg. This is illustrated below:

Velocity of fragment (u₁) = 34.64 m/s

Time (t) = 4.24 s

Horizontal distance travelled by the fragment (s₁) =?

s₁ = u₁t

s₁ = 34.64 × 4.24

s₁ = 146.87 m

Next, we shall determine the horizontal distance travelled by the fragment with mass mB = 0.270 kg. This is illustrated below:

Velocity of fragment (u₂) = 77.46 m/s

Time (t) = 4.24 s

Horizontal distance travelled by the fragment (s₂) =?

s₂ = u₂t

s₂ = 77.46 × 4.24

s₂ = 328.43 m

Finally, we shall determine the distance between the points on the ground where they land.

Horizontal distance travelled by the 1st fragment (s₁) = 146.87 m

Horizontal distance travelled by the 2nd fragment (s₂) = 328.43 m

Distance apart (S) =?

S = s₁ + s₂

S = 146.87 + 328.43

S = 475.3 m

Therefore, the distance between the points on the ground where they land is 475.3 m

Answer:

247.5 N

Explanation:

From the question,

The expression of centriputal force is given as

F = mv²/r..................... Equation 1

Where m = mass of the runner, v = velocity of the runner, r = radius of the runner

Given: m = 55 kg, v = 9 m/s, r = 18 m

Substitute these values into equation 1

F = 55(9²)/18

F = 247.5 N.

Hence the centriputal force of the runner is

247.5 N

With rising heat, the steam pressure inside the pot builds up beyond atmospheric pressure, allowing the temperatures to rise well above boiling point. This design enables to save time, energy, and resources. The temperature inside a pressure cooker can well go beyond 110° C, which reduces the time needed to cook food.

Answer: I think $20 billion a year it’s worth the cost. The reasoning behind that is because we can conduct research on various things that could help out humanity. Therefore we can conclude that’s spending billions of dollars every year is worth it.

Explanation:

Answer:

4.4 m

Explanation:

We are told the light from his flashlight, 1.3 m above the water level. Thus; h1 = 1.3m

Also,we are told that the light shone 2.5 m from his foot at the edge of the pool. Thus, L1 = 2.5 m

Angle of incidence θ1 is given by;

tan θ1 = L1/h1

tan θ1 = 2.5/1.3

tan θ1 = 1.9231

θ1 = tan^(-1) 1.9231

θ1 = 62.53°

Using Snell's law, we can find the angle of refraction from;

Sin θ2 = (η_air/η_water) Sin θ1

Where;

η_air is Refractive index of air = 1

η_water is Refractive index of water = 1.33

Thus;

Sin θ2 = (1/1.33) × sin 62.53°

Sin θ2 = 0.6671

θ2 = sin^(-1) 0.6671

θ2 = 41.84°

We want to find where the spot of light hit the bottom of the pool if the pool is 2.1 m deep. Thus, h2 = 2.1 m

Now, the spot can be found from;

L = L1 + L2

Where L2 = (h2) tan θ2

L = 2.5 + 2.1 tan 48.84

L = 2.5 + (2.1 × 0.8954)

L ≈ 4.4 m

Answer:

algm sabe tô precisando muito

This question is not complete, the complete question is;

A railroad handcar is moving along straight, frictionless tracks with negligible air resistance.

In the following cases, the car initially has a total mass (car and contents) of 170 kg and is traveling east with a velocity of magnitude 4.60 m/s.

Find the final velocity of the car in each case, assuming that the handcar does not leave the tracks.

Part A

An object with a mass of 22.0 kg is thrown sideways out of the car with a speed of 2.50 m/s relative to the car's initial velocity.

Part B

An object with a mass of 22.0 kg is thrown backward out of the car with a velocity of 4.60 m/s relative to the initial motion of the car.

Answer:  

Part A) the final velocity of the car is  4.6 m/s

Part B) the final velocity of the car is 5.28 m/s

Explanation:

Given the data in the question;

Total mass (m₁+m₂) = 170 kg

velocity of magnitude Vx = 4.60 m/s

PART A)

An object with a mass of 22.0 kg is thrown sideways out of the car with a speed of 2.50 m/s relative to the car's initial velocity,

i.e

m₂ = 22.0 kg

so m₁ = 170 - 22 = 148 kg

so, we apply conservation of momentum

since the object thrown out of the car, it has nothing to do with the car's velocity.

(m₁+m₂)Vx = m₁Vx₁ + m₂Vx₂

we substitute

(170)4.60 = 148Vx₁ + 22(4.60)

782 = 148Vx₁ + 101.2

148Vx₁ = 782 - 101.2

148Vx₁ = 680.8

Vx₁ = 680.8 / 148

Vx₁ = 4.6 m/s

Therefore, the final velocity of the car is  4.6 m/s

Part B)

An object with a mass of 22.0 kg is thrown backward out of the car with a velocity of 4.60 m/s relative to the initial motion of the car.

Vx = V(m₁+m₂) / ((m₁+m₂) - m₁)

we substitute

Vx = 4.60(170) / ((170) - 22)

Vx = 782 / 148

Vx = 5.28 m/s

Therefore, the final velocity of the car is 5.28 m/s

Answer:

Δθ = 15747.37 rad.

Explanation:

       [tex]\omega_{f1} = \alpha * \Delta t = 2.38*e-3rad/s2*2.04e3s = 4.9 rad/sec (1)[/tex]

       [tex]\omega_{f1}^{2} = 2* \alpha *\Delta\theta (2)[/tex]

       [tex]\theta_{1} = \frac{\omega_{f1}^{2}}{2*\alpha } = \frac{(4.9rad/sec)^{2}}{2*2.38*e-3rad/sec2} = 5044.12 rad (3)[/tex]

       [tex]\theta_{2} =\omega_{f1} * \Delta_{t2} = 4.9 rad/s * 1.48*e3 s = 7252 rad (4)[/tex]

       [tex]\omega_{f2}^{2} - \omega_{o2}^{2} = 2* \alpha *\Delta\theta (5)[/tex]

      [tex]\theta_{3} = \frac{(\omega_{f2})^{2}- (\omega_{f1}) ^{2} }{2*\alpha } = \frac{(2.42rad/s^{2}) -(4.9rad/sec)^{2}}{2*(-2.63*e-3rad/sec2)} = 3451.25 rad (6)[/tex]

Answer:

The friction of the string and its pivotal anchor point cannot be eliminated. The precise measurement of the length of the pendulum is difficult to take by using meter sticks or rulers. The value of the acceleration due to gravity g in the locality is not constant and must be obtained from reliable sources.

You cannot completely remove the friction between the string and its key anchor point. Using meter sticks or rulers makes it challenging to take an accurate measurement of the pendulum's length. Since it is not constant, it is necessary to get accurate information on the local gravity acceleration related to g.

The body is suspended from a central object to act as a pendulum that swings back and forth as a result of gravity. Because the period—the amount of time between each full oscillation—is constant, pendulums are employed to control the movement of clocks. The formula for a pendulum's period T is T = 2 Square root of L/g, where L is the pendulum's length and g is the acceleration brought on by gravity.

Galileo, an Italian scientist, made the first observation about the consistency of a pendulum's period by contrasting the motion of a swinging lantern in a cathedral in Pisa with his heart rate.

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Answer:

No.

Explanation:

Given that Kevin decides to soup up his car by replacing the car's wheels with ones that have 1.4 times the diameter of the original wheels. Note that the speedometer in a car is calibrated based on the tire's diameter and on the distance the tire covers in each revolution. (a) Will the reading of the speedometer change ?

Considering the formula

V = wr

Where

V = linear speed

W = angular speed

r = radius of the wheel.

But W = 2πrf

Where the the 2 and pi are constant. The radius of the first wheel will be small but counter balance with the larger frequency.

While the radius of the second wheel may be large but it will be of a small frequency.

We can therefore conclude that the reading on the speedometer will not change. Because speedometer will read the linear speed V.

Answer:

the responding variable is the water boiling

Explanation:

a responding variable is the same thing as a dependent variable and an independent variable you change the independent variable is the amount of salt, the control group is how long water takes to boil without adding salt, and a constant is the same amount of water

Answer:

Resistance = 1.5 ohms

Explanation:

Given:

Potential difference = 3v

Current flow = 2 A

Find:

Resistance

Computation:

Resistance = Potential difference / Current flow

Resistance = 3 / 2

Resistance = 1.5 ohms

Answer:

37.5 m/s

Explanation:

Using,

Formula

v = ωr....................... Equation 1

Where ω = instantaneous angular velocity, v = instantaneous linear velocity, r = radius or distance from the sweet spot of the bat to the axis of rotation.

From the question,

Given: ω = 30 rad/s, r = 1.25 m

Substitute these values into equation 1

v = 30(1.25)

v = 37.5 m/s.

Hence the instantaneous linear velocity of the sweet spot at the instant of ball contact is 37.5 m/s

Answer:

0.518 m/s

Explanation:

To solve this question, we would use the Law of conservation of momentum.

It is stated that the skateboard and the person were at rest initially, this means that their initial momentum is 0. Since they aren't moving.

And from the law if conservation of momentum, we know that initial momentum must be equal to final momentum.

The final momentum of the bricks will be 2* 0.9 * 19 = 34.2 kg m/s.

This means that the momentum of the person and that of the skateboard has to be 34.2 kg m/s also, although, it will be in the opposite direction.

Mass of the person plus that of the skateboard is

64 + 2 = 66 kg,

If we divide the momentum of the person and that of the skateboard by the mass of the both of them, we get the speed at which they are moving after the bricks are thrown

Recoil speed = (34.2 kg m/s)/(66 kg) = 0.518 m/s.

The recoil speed of the person is 0.518 m/s

As per the conservation of momentum, the initial momentum should be equivalent to the final momentum

So, here the final momentum should be

=  2* 0.9 * 19

= 34.2 kg m/s.

Now the mass of the person should be

= 64 + 2

= 66 kg,

Now the recoil speed should be

Recoil speed = (34.2 kg m/s)/(66 kg)

= 0.518 m/s.

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Answer:

The specific heat capacity of steel is lower than the specific heat capacity of wood

Explanation:

THERE IS ONLY 1 ON MY assignment i geot dis right  please brainlyist

The specific heat capacity of steel is lower than the specific heat of a piece of wood. Therefore, option (2) is correct.

Specific heat can be defined as the heat energy required to change the temperature of one unit mass of a substance of a constant volume by 1 °C. The S.I. unit of the specific heat capacity of a material is KJ/Kg.

The thermal capacity of a material is defined as a physical property of a substance. The amount of heat is given to a given mass to create a change in unit temperature.

The mathematical expression of specific heat capacity can be written as :

Q = m C ΔT      Where C is the heat capacity.

The specific heat capacity is an intensive property of a substance as it does not depend upon the size of the material.

A steel metal fence post feels colder than a wooden fence post of similar size because the specific heat of steel is lower than the specific heat capacity of wood.

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Explanation:

Plate tectonics is the scientific theory explaining the movement of the earth's crust. ... The movement of these tectonic plates is likely caused by convection currents in the molten rock in Earth's mantle below the crust. Earthquakes and volcanoes are the short-term results of this tectonic movement.

Answer:

The theory of plate tectonics describes the movement of the plates across the Earth's lithosphere (the crust and upper mantle) through immense periods of time. Earth's litoshphere is composed of 7 (or 8, depending on how they are defined) major plates and many more minor plates.

The movement is attributed to different phenomena stemming from Earth's rotation, gravity, and mantle dynamics. All of these forces play a role in influencing the size, shape, and positioning of the different landmasses that currently shape our continents and islands.

Answer:

533.33 nm

Explanation:

Since dsinθ = mλ  for each slit, where m = order of slit and λ = wavelength of light. Let m' = 10 th order fringe of the first slit of wavelength of light, λ = 640 nm and m"= 12 th order fringe of the second slight of wavelength of light, λ'.

Since the fringes coincide,

m'λ = m"λ'

λ' = m'λ/m"

= 10 × 640 nm/12

= 6400 nm/12

= 533.33 nm

Answer:

It is the best conducter of thermal and electrical energy

Answer:

its B

Explanation:

Answer:

Centripetal Acceleration = 88826.44 m/s²

RCF = 9054.7

Explanation:

First, we will find the value of the centripetal acceleration by using the following formula:

[tex]Centripetal\ Acceleration = \frac{v^2}{r}\\[/tex]

where,

v = linear speed of liquid or separator = rω

ω = angular speed of liquid or separator = (9000 rpm)(2π rad/rev)(1 min/60 s) = 942.48 rad/s

r = radius of seperator = diameter/2 = 20 cm/2 = 10 cm = 0.1 m

Therefore,

[tex]Centripetal\ Acceleration = \frac{(r\omega)^2}{r}\\Centripetal\ Acceleration = r\omega^2\\Centripetal\ Acceleration = (0.1\ m)(942.48\ rad/s)^2\\[/tex]

Centripetal Acceleration = 88826.44 m/s²

Now, for the RCF:

[tex]RCF = \frac{Centripetal\ Acceleration}{g}\\RCF = \frac{88826.44\ m/s^2}{9.81\ m/s^2}\\[/tex]

RCF = 9054.7

Answer: B

Explanation:

Answer:

C. Sigmund Freud . . . Carl Jung

Explanation:

edge 2021

C.Sigmund Freud and Carl Jung both heavily relied on dream analysis in their treatment of patients.

Freud is well-known for inventing and developing the approach of psychoanalysis; for articulating the psychoanalytic idea of motivation, intellectual infection, and the structure of the unconscious; and for influencing medical and popular conceptions of human nature by using positing both everyday and strange thought.

Sigmund Freud was an Austrian neurologist who's perhaps maximum known as the founding father of psychoanalysis. Freud advanced a fixed of therapeutic strategies centered on communication therapy that worried the use of techniques that include transference, loose affiliation, and dream interpretation.

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Answer: Mature red blood cells don't have nuclei.

Explanation: " Platelets are irregularly shaped, have no nucleus, and typically measure only 2–3 micrometers in diameter. "

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