Answer:
Approximately [tex]106\; \rm m[/tex], [tex](1/16)[/tex] of the original distance, assuming that the acceleration is constant.
Explanation:
Let [tex]v[/tex] and [tex]u[/tex] denote the final and initial velocity of the vehicle ([tex]v = 0\; \rm m \cdot s^{-1}[/tex] since this vehicle has come to a stop.)Let [tex]a[/tex] denote the acceleration of the vehicle (a constant under the assumption.) Let [tex]x[/tex] denote the displacement of the vehicle.If the acceleration on this vehicle is constant, the SUVAT equations would apply:
[tex]\displaystyle v^{2} - u^{2} = 2\, a\, x[/tex].
Rearrange this equation to find an expression for [tex]x[/tex], the displacement required for the vehicle to come to a stop:
[tex]\begin{aligned} x &= \frac{v^{2} - u^{2}}{2\, a} \\ &= \frac{-u^{2}}{2\, a} && (\text{$v = 0\; \rm m \cdot s^{-1}$})\end{aligned}[/tex].
Thus, under these assumptions, [tex]x[/tex] would be proportional to [tex]u^{2}[/tex]. In other words, the distance required for this vehicle to come to a stop would be proportional to the square of the initial velocity of this vehicle.
If the initial velocity [tex]u[/tex] is reduced to [tex](1/4)[/tex] (a quarter) of the initial value, the distance required for stopping this vehicle would be [tex](1/4)^{2} = (1/16)[/tex] of the initial value:
[tex]\begin{aligned}1,\!697\; {\rm m} \times \frac{1}{16} \approx 106\; \rm m\end{aligned}[/tex].
At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned
The fundamental frequency, wavelength of the wave, and mass per unit
length of the string, determines the tension in the string.
The tension to which the D-string must be tuned is approximately 19.718 NewtonsReasons:
From a similar question, we have;
Fundamental frequency, f₁ = 146.8 Hz
Oscillating length on the D-string, λ₁ = 0.61 m
Mass of the string = 1.5 × 10⁻³ kg.
We have;
[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]
Therefore;
[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]
Which gives;
[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]
The tension to which the D-string must be tuned, T ≈ 19.718 Newtons
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The parameters given in a similar question obtained online are;
The fundamental frequency of the tone, f₁ = 146.8 Hz
The oscillating length on the D-string, λ₁ = 0.61 m
The mass of the string = 1.5 × 10⁻³ kg.
2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?
Answer:
3.125 Kilometers
Explanation:
To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.
Find the volume of this figure.
4 dm
2 dm
3 dm
Answer:
4×2×3= 24dm^3
.......................
A potted plant falls from the window of an apartment building. It falls for 2.0 s and then hits the ground. What is the speed of the plant just before it hits the
ground? Assume only gravity is acting on it.
A) 20m/s
B)9.8m/s
C)2.0m/s
D)4.9m/s
Answer:
D) 4.9 m/s
Explanation:
Speed of Object in Free Fall
s = Rate of Acceleration, Due to Gravity × Length of Time
s = 9.8 × 2.0
s = m/s (Round Up to The Nearest Whole Number)
--
m/s = 9.8 ÷ 2.0 = 4.9 m/s
A truck with a mass of 1500 kg is decelerated at a rate of 5m/s2.how much force did this require ?
Answer:
6500N
Explanation:
F = ma so therefore Were given mass (m) = 1500 kg, acceleration (a) = 5 m/s2, well have to calculate the force to be:
1500 x 5 = 6500 N
The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.
The vectors point along the axis of rotation with a direction determined by an arrow.
What is a vector?There are two types of physical quantity one is a scaler and another one is a vector.
The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.
The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.
The angular quantities L, omega, and alpha are vector quantities.
Hence arrow is the correct answer for the blank.
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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.
What is right hand rule?Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.
Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.
Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.
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how to find the latitude and longitude of an address
Answer:
To get the latitude of the address in cell B2, use the formula = GetLatitude (B2) To get the longitude of the address in cell B2, use the formula = GetLongitude (B2) To get both the latitude and longitude of the address in cell B2, use the formula = GetCoordinates (B2)
Explanation:
CAN I GET BRAINLIEST
Wire coils spinning between two magnets will produce …?
A: cold
B : electricity
C: chemicals
D: Steam
Answer:
B
Explanation:
I don't know but its b
if you have 3 moles of iron, how many grams of iron do you have?
Answer:
55.84 look at periodic table
so 55.84*3= 167.52gFe
Can Hotspots can be found at the edges of tectonic plates?
Answer:
No.
Explanation:
Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.
A cyclist sitting still at the top of a hill displays gravitational potential energy. What makes it possible for the cyclist to have this type of energy?
Explanation:
because its speed (v) is 0
PLEASE HELP!!!!!!!!!!!
A 12 volt car battery produces more current than a 1.5 volt battery for a TV remote because
A. The TV remote has a greater difference in electric potential energy
B. The car battery has more kinetic energy
C. The TV remote has more kinetic energy
D. The car battery has a greater difference in electric potential energy
A 12 volt car battery will produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy than a 1.5 Volt battery. The correct answer is D
The potential difference between any two point in a circuit is the work done when one coulomb of charge moves from one point to the other. Potential difference is a kind of electrical pressure difference between two point.
The difference in electric potential in a 12 Volt battery is greater than the difference in electric potential in a 1.5 Volt battery.
According to Ohm's law, Voltage supplied is proportional to current produced. That is, V = lR. Where R = resistance.
A 12 volt car battery will produces more current than a 1.5 volt battery for a TV remote because the car battery has a greater difference in electric potential energy than a 1.5 Volt battery.
Therefore, the correct answer is the option D
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The reading on a metronome indicates the number of oscillations per minute. What are the frequency and period of the metronome's vibration when the metronome is set at 180?
Answer:
Period: 1/3= 0.33 seconds.
The frequency and period of the metronome's vibration when the metronome is set at 180 is 3Hz and 0.33 s.
What is the frequency?Frequency is the number of oscillations per second.
The time period is the reciprocal of the frequency.
Given is the metronome set at 180.
The reading of metronome = frequency in seconds = 180 / 60 = 3 Hz
The time period of the metronome's vibration T = 1/3 = 0.33 seconds.
Thus, the frequency and the time period is 3Hz and 0.33 s.
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I couldn't answer this question may someone please help me
Distance (s) =20 m
Initial velocity =0 m/s
g=10 m/s²
By using the formula:
v²= u²+ 2as
v²=0²+ 2×10×15
v²= 300
V= 10root over 3
[tex]10 \sqrt{3} [/tex]
For calculating time,
v= u+ at
10 root over 3 = 0+ 10t
10 root over= 10t
t = 1 root over 3
t = 1.73 s
[tex]1 \sqrt{3} [/tex]
The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.
What can the magnetic fields influence?
A) It can cause objects to be pulled towards the magnet and pushed away from the magnet.
B) It only causes a repel force between the magnets.
C)It cause only an attraction force.
Explanation:
Magnetic fields are areas where an object exhibits a magnetic influence. The fields affect neighboring objects along things called magnetic field lines. A magnetic object can attract or push away another magnetic object. You also need to remember that magnetic forces are NOT related to gravity.
Hello guys! Can u please help me with physics. I translated it in English. Can yall help me please how much u can!!
A body 60 m above the ground shall be thrown vertically upwards at an initial speed of 20 m / s. Air resistance can be ignored!
1. How high will the body fly from the point of ejection?
2. What is the maximum height it will reach above the ground?
3. How long does it take for the body to reach its highest point from the moment of expulsion?
4. After how long after the expulsion will the body fall to the ground?
5. What is the speed of the body at the moment of falling to the ground?
1. Since the body is thrown vertically upward, the only force acting on it as it rises and falls is gravity, which causes a constant downward acceleration with magnitude g = 9.8 m/s². Because this acceleration is constant, we can use the formula
v² - u² = 2a ∆x
where
u = initial speed
v = final speed
a = acceleration
∆x = displacement
At its maximum height, some distance y above the point where the body is launched, the body has zero velocity, so
0² - (20 m/s)² = 2 (-9.8 m/s²) y
Solve for y :
y = (20 m/s)² / (2 (9.8 m/s²)) ≈ 20.4 m
2. Relative to the ground, the body's maximum height is 60 m + 20.4 m ≈ 80.4 m.
3. At any time t ≥ 0, the body's vertical velocity is given by
v = 20 m/s - gt
At the highest point, we have
0 = 20 m/s - (9.8 m/s²) t
and solving for t gives
t = (20 m/s) / (9.8 m/s²) ≈ 2.04 s
4. The body's height y above the ground at any time t ≥ 0 is given by
y = 60 m + (20 m/s) t - 1/2 gt²
Solve for t when y = 0 :
0 = 60 m + (20 m/s) t - 1/2 (9.8 m/s²) t²
Using the quadratic formula,
t = (-b + √(b² - 4ac)) / (2a)
(and omitting the negative root, which gives a negative solution) where a = -1/2 (9.8 m/s²), b = 20 m/s, and c = 60 m. You should end up with
t ≈ 6.09 s
5. At the time found in (4), the body's velocity is
v = 20 m/s - g (6.09 s) ≈ -39.7 m/s
Speed is the magnitude of velocity, so the speed in question is 39.7 m/s.
Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)
The velocity of the red cart after the collision is 2 m/s
From the law of conservation of momentum, initial momentum of system = final momentum of system.
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.
Substituting the values of the variables into the equation, we have,
m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄
4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s
16 kgm/s + 0 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s = 4v₃ + 8 kgm/s
16 kgm/s - 8 kgm/s = (4 kg)v₃
(4 kg)v₃ = 8 kgm/s
Divide both sides by 4 kg, we have
v₃ = 8 kgm/s ÷ 4 kg
v₃ = 2 m/s
The velocity of the red cart after the collision is 2 m/s.
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When waves are closer together and there are more waves, then the wave has a higher ____________.
Answer:
When waves are closer together and there are more waves, then the wave has a higher frequency.
Explanation:
Hoped this helped.
Answer:
frequency
Explanation:
What is the kinetic energy of a 3-kilogram bali that is rolling at 2 meters per second
Answer:
6J
Explanation:
simply apply kinetic energy definitoon:
[tex]k = \frac{1}{2} mv {}^{2} = \frac{1}{2} 3 \times 2 {}^{2} = 6[/tex]
3.
If the specific heat of iron = 0.46 J/g Cº, how much heat is needed to warm 50 g of
iron from 20° C to 100° C?
Answer:
1.84 kJ (kilojoules)
Explanation:
A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.
If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:
Heat = (specific heat)*(mass)*(temp change)
Heat = (0.46 J/g Cº)*(50g)*(100° C - 20° C)
[Note how the units cancel to yield just Joules]
Heat = 1840 Joules, or 1.84 kJ
[Note that the number is positive: Energy is added to the system. If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C). The number is -1.84 kJ: the negative means heat was removed from the system (the iron).
Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between them tripled. What is the force between the masses?
If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.
What is gravitational force?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
Given data:
The gravitational force = 30 N
Mass 1 =m₁
Mass 2=m₂
Distance between charges = R
Condition given:
Mass 1 = 2m₁
Mass 2= 2m₂
Distance between charges = 3R
[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]
Case 2;
[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]
Hence, the forces between the masses will be 13..33 N.
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Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, this gun accelerates a 5.6-kg projectile from rest to a speed of 3.5 × 103 m/s. The net force accelerating the projectile is 2.5 × 105 N. How much time is required for the projectile to come up to speed?
Answer:
7.84 s
Explanation:
Ok, one step at a time. We know the mass of the projectile, we know the force. Acceleration is easily obtained from Newton second law:
[tex]\vec F = m\vec a[/tex][tex]2.5\times 10^5 = 5.6a \rightarrow a = (2.5/5.6) \times 10^5 = 4.46 \times 10^4 ms^-^2[/tex].
At this point, we know the acceleration, we know initial and final velocity, we can time the ammount of time it took to get there.
[tex]v= v_0 +at \rightarrow 3.5\times10^3 = 0 + 4.46\times10^4 t\\t= \frac{3.5\times10^3}{4.46\times10^4} = 7.84 s[/tex]
10C of charge flow through a resistor in 4 seconds. What is the current?
Answer:
Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.
Explanation:
The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps
Given Data
Charge = 10 Columbs
Time = 4 seconds
Current = ?
Current, charge and time RelationshipElectrical current is defined by how much electric charge has been transferred per second, giving the following relationship:
Charge = Current*Time
Rearranging this we get:
Current = Charge/Time
The symbol for charge is Q , it is measured in coulombs (C).
The symbol for current is I , it is measured in amperes (A).
The symbol for time is T, it is measured in seconds (s).
Substituting our given Data into the expression we have
Current = 10/4
Current = 2.5 Amps
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given. force of 88N and an acceleration of 4 m/s 2 what is the mass?
Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.
Answer:
hi I don't know sorry sorry forgive me
Explanation:
sorry
a girl runs once around a circular track with a radius of 100m at speed of 10m/s.
calculate her displacement
Answer:
0 m
Explanation:
Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.
Where is the natural light display called aurora borealis located?
The natural light display called aurora borealis is located in the northern
hemisphere.
There are two types of aurora which are called aurora borealis and aurora
australis. The aurora borealis is located in the Northern hemisphere while
the aurora australis is located in the Southern hemisphere.
They receive their energy through the interaction of charged particles
on the Sun and Earth to produce the light display. An example
of the interaction involves solar wind with atoms of the upper atmosphere.
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Answer:
northern and southern hemisphere
Explanation:
What generates the energy produced when small light atoms are combined into heavier ones
A. Fusion reactions
B. Chemical reactions
C. Fission reactions
D. Nuclear chain reactions
Answer:
A. Fusion Reactions
Explanation:
PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
jogging
Explanation:
Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.
A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?
Answer:
35N
Explanation:
force=mass×gravity
the mass is 5 and the gravity is 7 therefore:
force=7×5
=35N
I hope this helps