3. If 98 out of 200 individuals in a population express the recessive phenotype, what percent of the population
are heterozygotes?

Answer:

Explanation:

Q:

If 98 out of 200 individuals in a population express the recessive phenotype, what percent of the population would be heterozygotes?

A:

0.42 or 42%

The recessive phenotype is the phenotype that is expressed only when the recessive condition is found in both alleles.

The percent of the population that would be heterozygous is 42%

If 98 out of 200 individual express the recessive allele = 98/200 = 0.49. This is the phenotypic frequency of the recessive allele (q²)... q = 0.7 (√0.49)

Since p + q = 1

1 - 0.7 = 0.3 = p

To find the percent of heterozygous...p² + 2pq + q² = 1

Where 2 x 0.3x0.7= 0.42

Therefore, the percent of the population that are heterozygous is 42%

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