Answer:
Its B square pyramid
Step-by-step explanation:
Because
What is the inverse of 2x-3?
Step-by-step explanation:
the inverse of 2x-3 is
[tex] \frac{1}{2x - 3} [/tex]
if this helped pls give brainliest
Order the measures of mass from least to greatest.
Answer:
18 grams,160 grams,2,100 grams,2 kilograms,17 kilograms,208 kilograms.
The measure from least to greatest is 18 gm < 10 gm< 17 Kg < 2Kg < 2300 gm < 208 Kg.
What is Ascending Order?The arrangement of numbers or other things in increasing order from least to greatest is known as ascending order. Ascending order is demonstrated by numbers on a number line, which are listed from left to right.
Given:
18gm, 17 Kg, 100 gm, 2 Kg, 2300 gm, 208 Kg
Converting all the units into gram we have
18 , 1700, 100, 2000, 2300, 208000
So, the mass from least to greatest.
18 < 100 < 1700< 2000< 2300 < 208000
Hence, 18 gm < 10 gm< 17 Kg < 2Kg < 2300 gm < 208 Kg.
Learn more about Ascending order here:
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A study was designed to investigate the effects of two variables(1) a student's level of mathematical anxiety and (2) teaching methodon a student's achievement in a mathematics course. Students who had a low level of mathematical anxiety were taught using the traditional expository method. These students obtained a mean score of 440 with a standard deviation of on a standardized test. Assuming no information concerning the shape of the distribution is known, what percentage of the students scored between 360 and 520 ?
Using Chebyshev's Theorem, considering a standard deviation of 40, we have that at least 75% of the students scored between 360 and 520.
What does Chebyshev’s Theorem state?When we have no information about the population distribution, Chebyshev's Theorem is used. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.At least 89% of the measures are within 3 standard deviations of the mean.An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].In this problem, considering a standard deviation of 40, we have that:
440 - 2 x 40 = 360.
440 + 2 x 30 = 520.
Within 2 standard deviations of the mean, no information about the distribution, hence, at least 75% of the students scored between 360 and 520.
More can be learned about Chebyshev's Theorem at https://brainly.com/question/25303620
what does Y=
what does x=
Answer:
Step-by-step explanation:
The equation factors into
(x^2 + 14x + 49) =16 Factor
(x + 7)^2 = 16 Take the square root of both sides
√(x + 7)^2 = √16
x + 7 = +/- 4
x + 7 = + 4 Subtract 7 from both sides
x = 4 - 7
x = - 3
x + 7 = - 4 Subtract 7 from both sides.
x = - 4 - 7
x = - 11
x1 = -11
x2 = - 3
Find the exact value of sin(255∘)
Check the picture below.
[tex]\textit{Sum and Difference Identities} \\\\ sin(\alpha + \beta)=sin(\alpha)cos(\beta) + cos(\alpha)sin(\beta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ sin(255^o)\implies sin(135^o+120^o) \\\\\\ sin(135^o)cos(120^o)~~ + ~~cos(135^o)sin(120^o) \\\\\\ \left( \cfrac{\sqrt{2}}{2} \right)\left( -\cfrac{1}{2} \right)~~ + ~~\left( -\cfrac{\sqrt{2}}{2} \right)\left( \cfrac{\sqrt{3}}{2} \right)\implies -\cfrac{\sqrt{2}}{4}~~ - ~~\cfrac{\sqrt{6}}{4}\implies \cfrac{-2-\sqrt{6}}{4}[/tex]
Please help, has t toy cars. Zachary has 3 times as many toy cars as Oliver. Write an expression
that shows how many toy cars Zachary has.
Answer:
z=3t
Step-by-step explanation:
multiply it by 3
Diego's soccer team played in a tournament. The tournament started at 8:07 A.M. It ended at 3:44 P.M. How long did the soccer tournament last?
Answer:
Step-by-step explanation:
7 hours and 37 minuties
Answer:
5 hours
Step-by-step explanation:
it lasted 5 hours for the tournament
Which of the following is NOT a characteristic of a plane?
A. thickness
B. width
C. flat surface
D. length
Answer:
A). thickness are correct
Horatio weighs three times as much as Kimberly and together they weigh a total of 95
Diana can earn money for the tickets she sells. Which of the following statements describes the variables in this situation correctly?
The amount of money earned is the independent variable because it affects the number of tickets sold.
The amount of money earned is the dependent variable because it affects the number of tickets sold.
The number of tickets sold is the independent variable because it affects the amount of money earned.
The number of tickets sold is the dependent variable because it affects the amount of money earned.
Answer:
Option 3 is the correct answer.
Answer: The number of tickets sold is the independent variable because it affects the amount of money earned.
Step-by-step explanation: I just took test got 100%
The number of tickets sold is the independent variable because it affects the amount of money earned.
Can someone please help me
Answer:
When it's negative when it goes to the other side it becomes a positive.....
Y=(x-4)(x-1)
Make y 0 when your calculating for x
Make x 0 when your calculating for y
0=(x-4)(x-1)
Therefore x=4 or x=1
Oxygen flows through one tube into a liter flask filled with air, and the mixture of oxygen and air (considered well stirred) escapes through another tube. Assuming that air contains 4% oxygen, what percentage of oxygen will the flask contain after 5 L have passed through the intake tube?
The amount of oxygen in the flask through the intake tube illustrates proportions
The flask 99.35% will contain of oxygen after 5L have passed through the intake tube
How to calculate the percentage of oxygen?
To do this, we make use of the following representations
P for the proportion of oxygenV for te volume of oxygenx for the proportion of oxygen in the flask after 5 L passed throughSo. we have the following derivative
dP = dV - P * dV
Divide through by dV
dP/dV = 1 - P
Next, we set up the integral
[tex]\int\limits^x_{0.040} \frac {1}{1 - P}dP= \int\limits^5_0 {dV}[/tex]
Integrate both sides
[tex]-\ln(|P - 1|)|\limits^x_{0.04} = 5[/tex]
Expand
-ln(|x - 1|) + ln(|0.04 - 1|) = 5
Evaluate the difference
-ln(|x - 1|) + ln(|-0.96|) = 5
Express as a fraction
ln(0.96/|x - 1|) = 5
Express both sides as exponents with a base of 2
e^ln(0.96/|x - 1|) = e^5
Solve for x
x = 1 - 0.96/e^5
Evaluate the difference
x = 0.9935
Express as percentage
x = 99.35%
Hence, the flask 99.35% will contain of oxygen after 5L have passed through the intake tube
Read more about proportions at:
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I’m stuck pls help me
Answer:
B and E
Step-by-step explanation:
What is the value of the expression (–5) -3?
1. Apply the negative exponents rule:
1
(−5)3
2. Expand the power:
1
(−5)(−5)(−5)
3. Simplify:
1
x
What is the value of x?
x =
Answer:
15 :)
Step-by-step explanation:
brainliest please
Answer:
The answer is -125
Proof:
There are only 7 days left until the launch of our new product and we only have $668 left and Ira promotion budget we need to spend $85 on the last day can you please calculate how many dollars we can spend on the remaining days
Answer:
97.16
Step-by-step explanation:
in total, you have $668.00.
To reserve enough for the last day, you need to subtract the last day's budget:
This means that, for the remaining 6 days in the week, you have $583.00.
Assuming an equal amount is being spent each day, you can calculate the daily budget by dividing the remaining total by the number of days left.
To avoid going over budget, you can spend $97.16 per day for the other six days.
find the square root of 576 and do it in factorizing method and your answer is going to be in index form
Answer:
24.
Step-by-step explanation:
Solution,
By Prime Factorisation method,
576 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3
576 = (2)² × (2)² × (2)² × (3)²
Now,
By Taking square roots on both the sides,
√576 = √ (2)² × (2)² × (2)² × (3)²
√576 = 2 × 2 × 2 × 3
√576 = 24.
Please help me. I really need help. and I'm not smart
A researcher weighed watermelons grown across a certain region. The data are rounded to the nearest pound and displayed in this histogram.
What does the fourth bin represent?
Select from the drop-down menu to correctly complete the statement.
Four watermelons weigh:
at least 12 pounds but less than 16 pounds
at least 12 pounds but no more than 16 pounds
more than 12 pounds but less than 16 pounds
.
more than 12 pounds but no more than 16 pounds
.
In the given histogram, the correct option regarding the representation of the fourth bin is:
at least 12 pounds but less than 16 pounds.
What is an histogram?An histogram is a graph that shows the number of times each element of x was observed. The lower bound is inclusive, while the upper bound is exclusive.
Hence, considering the inclusiveness and exclusiveness of the bounds, the correct option regarding the fourth bin, given by [12, 16) is:
at least 12 pounds but less than 16 pounds.
More can be learned about histograms at https://brainly.com/question/25836450
Answer:
The answer is "at least 12 pounds but less than 16 pounds"
Explanation:
I took the quiz! Hope this helps! :)
solve this plsssssss
Let's see
LHS
(-8/9×1/-5)+(-8/9×-7/11)Keep it stay
RHS
-8/9(1/-5+-7/11)Use distributive law
(-8/9×1/-5)+(-8/9×-7/11)Hence proved
8. Anita recorded the amount of rainfall in
her area each day for 14 days. What was
the total amount of rainfall in the 14 days?
A 40 cm
B 36 cm
C 13.5 cm
D 12.5 cm
How to determine the total amount of rainfall
From the dot plot, we have the following frequency table
Rainfall Frequency
0 4
1/8 5
1/4 1
3/8 2
1/2 1
1 1/4 1
= 3/8 inches
The polygon given below is a regular pentagon.
A. 54°
B. 108°
C. 135°
D. 540°
Answer:
Step-by-step explanation:
In a regular pentagon, all the angles and sides are equal. So, to find an angle, divide 540 by 5.
Sum of all angles of regular pentagon = 540
measurement of one angle = 540 ÷ 5
= 108°
∠N = 108°
Answer:
B
Step-by-step explanation:
Help picture below problem 3
angle ksp+61=108(being straight angle)
or,angle ksp=180-61
angle ksp=119
f Daria repeats the experiment 50 more times, how many of those times should she expect to pull a yellow marble?
Answer:
it matters how many colors are there
How do you graph y=3x-2
Answer:
The graph should look almost exactly like this. I used a virtual graphing chart to assist, since it is capable of showing more than paper alone.
Answer:
Here is your answer.
Step-by-step explanation:
What is the range? 6 7 8 7 10
Step-by-step explanation:
Range -6
Range is a higherd number
10-4=6
there were 63 fewer pears than apples in the supermarket. After 37 pears were sold, how many fewer pears than apples ?
Step-by-step explanation:
63/37 = 1.702 = 1.7
#Ihopethishleps
Solve the following equation for p: 6/p=x+a
[tex]\dfrac 6p = x+a\\\\\implies \dfrac 6p \times\dfrac 16 = (x+a) \times\dfrac 16 ~~~~~~;\left[\text{Multiply both sides by}~ \dfrac 16 \right]\\\\\implies \dfrac 1p = \dfrac{x+a}6\\\\\implies p= \dfrac{6}{x+a}~~~~~~~~~~~~~~~~~~~~;[\text{Cross multiply}][/tex]
What are the solutions to the equation 30/x=6
Answer:
the answer will be 5
Step-by-step explanation:
30/x=630=6×x 30/6 =x (where 6×5 =30 )so, x=5What is the length for X
Answer:
x = 5
Step-by-step explanation:
3^2 + 4^2 = x^2
9 + 16 = x^2
25
Now we need to find the square root of 25 :)
The answer is 5
X = 5
Have a great day!!
Please rate and mark brainliest!!
Find the average of this set of numbers.16, 20, 30, 30
A) 14
B) 15
C) 25
D) none of the above
Answer:
D) none of the above
Step-by-step explanation:
16+20+30+30=96
96/4 =24
General solution of: (1-xy)^-2 dx + [y^2 + x^2 (1-xy)^-2]dy = 0
show two solution on your answer
nonsense answer deleted
[tex] \Large \bold{SOLUTION\ 1:} [/tex]
[tex] \small \begin{array}{l} \text{First, we need to check if the given differential} \\ \text{equation is exact.} \\ \\ (1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \quad M(x, y) dx + N(x, y) dy = 0 \end{array} [/tex]
[tex] \small \begin{array}{l l}\tt\: M(x,y) = \dfrac{1}{(1 - xy)^2}, & N(x,y) = y^2 + \dfrac{x^2}{(1-xy)^2}\\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{-2(-x)}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^2} + \dfrac{-2(-y)x^2}{(1 - xy)^3} \\ \\\tt \dfrac{\partial M}{\partial y} = \dfrac{2x}{(1 - xy)^3}, & \dfrac{\partial N}{\partial x} = \dfrac{2x(1 - xy)+2x^2y}{(1 - xy)^3} \\ \\\tt \: & \dfrac{\partial N}{\partial x} = \dfrac{2x}{(1 - xy)^3} \end{array} [/tex]
[tex] \small \begin{array}{l} \tt\dfrac{\partial M}{\partial y} = \dfrac{\partial N}{\partial x} \implies \text{Differential equation is exact.} \\ \\\tt \dfrac{\partial F}{\partial x} = M(x, y) = \dfrac{1}{(1 - xy)^2} \\ \tt\displaystyle F(x, y) = \int \dfrac{1}{(1 - xy)^2} \partial x = -\dfrac{1}{y} \int \dfrac{1}{(1 - xy)^2}(-y)\partial x \\ \\ \tt\:F(x, y) = \dfrac{1}{y(1 - xy)} + h(y) \\ \\ \tt\dfrac{\partial F}{\partial y} = N(x, y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\\tt \dfrac{\partial}{\partial y}\left[\dfrac{1}{y(1 - xy)} + h(y)\right] = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - xy + y(-x)}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ \tt-\dfrac{1 - 2xy}{y^2(1 - xy)^2} + h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} \\ \\ h'(y) = y^2 + \dfrac{x^2}{(1-xy)^2} + \dfrac{1 - 2xy}{y^2(1 - xy)^2} \\ \\ \tt\:h'(y) = y^2 + \dfrac{x^2y^2 - 2xy + 1}{y^2(1-xy)^2} = y^2 + \dfrac{1}{y^2} \\ \\ h(y) = \dfrac{y^3}{3} - \dfrac{1}{y} + C \\ \\ \tt\text{Substituting to }F(x,y),\text{we get} \\ \\ \dfrac{1}{y(1 - xy)} + \dfrac{y^3}{3} - \dfrac{1}{y} = C \\ \\ \quad \quad \text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]
[tex] \Large \bold{SOLUTION\ 2:} [/tex]
[tex] \small \begin{array}{l} \tt\text{Since we already know that the equation is exact,} \\ \text{we can then continue solving for the solution by} \\ \text{inspection method or by algebraic manipulation.} \\ \\ \tt(1-xy)^{-2} dx + \big[y^2 + x^2 (1-xy)^{-2}\big]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + \left[y^2 + \dfrac{x^2}{(1-xy)^2}\right]dy = 0 \\ \\ \tt\dfrac{dx}{(1-xy)^2} + y^2 dy + \dfrac{x^2}{(1-xy)^2} dy = 0 \\ \\ \tt\dfrac{dx + x^2dy}{(1-xy)^2} + y^2 dy = 0 \\ \\ \tt\text{Divide both numerator and denominator of the} \\ \tt\text{fraction by }x^2. \end{array} [/tex]
[tex] \small \begin{array}{c}\tt \dfrac{\dfrac{1}{x^2}dx + dy}{\dfrac{(1-xy)^2}{x^2}} + y^2 dy = 0 \\ \tt\\ \tt\dfrac{\dfrac{1}{x^2}dx + dy}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt-\dfrac{\left(-\dfrac{1}{x^2}dx - dy\right)}{\left(\dfrac{1}{x}-y\right)^2} + y^2 dy = 0 \\ \\ \tt\displaystyle {\large{\int}} -\frac{d\left(\dfrac{1}{x}-y\right)}{\left(\dfrac{1}{x}-y\right)^2} + \int y^2 dy = \int 0 \\ \\ \tt\implies\tt \dfrac{1}{\dfrac{1}{x}-y} + \dfrac{y^3}{3} = C \\ \\\text{or} \\ \\ \tt\red{\boxed{\dfrac{x}{1 - xy} + \dfrac{y^3}{3} = C} \Longleftarrow \textit{Answer}} \end{array} [/tex]
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