—5 + 3x + 2 = 12
Solve for x

Answer:

fx=3x+7 gx=5x-8

Step-by-step explanation:

here i hope this helps im not 100% sure this is what you want but its what I think

Answer:

Step-by-step explanation:

              Statements                        Reasons

1). UW bisects ∠VUX               1). Given

2). UW bisects ∠VWX             2). Given

3). ∠VUW ≅ ∠WUX                 3). Definition of angle bisector

4). ∠UWV ≅ ∠UWX                 4). Definition of angle bisector

5). UW ≅ UW                           5). Reflexive property

6). ΔUVW ≅ ΔUXW                 6). ASA postulate of congruence

Answer: 146n is the answer 100%

Answer:

8

Step-by-step explanation:

since u first do six + 8 which is 14. Then u do 14 - 4 which is 10

Plz mark as brainliest

Answer:

x=2

Step-by-step explanation:

x = the number

x + 6 = 6x - 4

Solve for x and get

5x = 10

Answer:

C. Positive 6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

because we find the reciprocal and 9 divided by -3 and 8 divided by -4

9 divided by -3 is  -3 and 8 divided by -4 is -2

so -3 times -2 is 6

Answer:

Each piece weighed 1/10 of a pound.

Step-by-step explanation:

We have 3/5 of a pound and we want to divide it by 6 equal pieces for each student. 6 equal pieces is the same as 6/1.

In order to divide 3/5 by 6/1 we need to invert the 6/1 and multiply. So, it becomes 3/5 x 1/6. First, we multiply the numerators: 3x1=3 then we multiply the denominators: 5x6=30. The result is 3/30, which can be reduced by dividing both the numerator and denominator by 3. 3/3=1 and 30/3=10. So, the result is 1/10.

Answer:

LP = 18

Step-by-step explanation:

Given that,

In ΔLPN,

LQ = 6, LM = 11 and MN = 22

We need to find the length of LP.

As QM ║PN, let QP = x

[tex]\dfrac{LQ}{LP}=\dfrac{LM}{LN}\\\\\dfrac{6}{6+x}=\dfrac{11}{11+22}\\\\\dfrac{6}{6+x}=\dfrac{11}{33}\\\\198=66+11x\\\\198-66=11x\\\\132=11x\\\\x=12[/tex]

LP = 6+x

= 6+ 12

= 18

Hence, the length of LP is 18.

Answer:

Option A

Step-by-step explanation:

for right angle triangle a²+b²= c²

60²+80²= 10000

√10000= 100

hope it helps!

AAAAAAAAAAAAAAAAAAAA

The answer A.

A as in Apple.

Answer: He is Incorrect, It's 38

Work: For this question, I did the Cross-Product Method. The Cross Product Method is when you solve equation via to fractions. With the CPM, One one side of the fraction, I had x / 20 (Twenty being the whole number) and on the other side, I had 190/100 (190 being the percent) After setting this up, I made the equation. 190 times 20 is 3800, and the other multiplication is 100 times x which is 100x. So, the new equation is 3800 = 100x. I divided both sides by 100, and the answer is 38 = x

I hope this helps, and Happy Holidays! :)

Answer:

No, Marcus is not correct. He converted the percent to a decimal correctly and he multiplied correctly, but he put the decimal in the wrong place in the answer. There should be two decimal places in the answer, so the answer should be 38.

Step-by-step explanation:

I took the assingment in edge 2020

9514 1404 393

Answer:

  g(f(x)) = x . . . so the functions are inverses

Step-by-step explanation:

Two functions f and g are inverses of each other if ...

  g(f(x)) = x   or   f(g(x)) = x

We are asked to evaluate g(f(x)). That will be x if the functions are inverses.

  g(f(x)) = g((x+1)/2) = 2((x +1)/2) -1 = (x +1) -1

  g(f(x)) = x . . . . the functions are inverses

Given:

A linear function starting at point C at (3, –2) and ending at point D at (–2, 3).

To find:

The rate of change and the initial value.

Solution:

If a linear function passes through two points [tex](x_1,y_1)\text{ and }(x_2,y_2)[/tex], then the equation of linear function is

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

The given linear function passes through (3,-2) and (-2,3). So, the equation is

[tex]y-(-2)=\dfrac{3-(-2)}{-2-3}(x-3)[/tex]

[tex]y+2=\dfrac{3+2}{-5}(x-3)[/tex]

[tex]y+2=\dfrac{5}{-5}(x-3)[/tex]

[tex]y+2=-(x-3)[/tex]

Subtracting 2 on both sides, we get

[tex]y=-x+3-2[/tex]

[tex]y=-x+1[/tex]

On comparing this equation with slope intercept form [tex]y=mx+b[/tex], where, m is slope and b is y-intercept, we get

[tex]m=-1[/tex] and [tex]b=1[/tex]

Therefore, the rate of change is -1 and the initial value is 1.

Answer:

$1

Step-by-step explanation:

Answer: -1/2

Step-by-step explanation: whenever a line is perpendicular you take the opposite reciprocal of the current slope.

Hello!

Perpendicular lines have slopes that are opposite reciprocals.

It means we take a number, flop it over and then make it negative.

So if we have 2, we flop it over:

[tex]\frac{1}{2}[/tex]

Then, we make it negative:

[tex]-\frac{1}{2}[/tex]

That is the slope. Hope it helps

If you have any query, please ask me! :)

~A forlorn girlie

[tex]MagicalNature[/tex]

Answer:

1.

Step-by-step explanation:

The line goes through positive 2

Answer:

2

Step-by-step explanation:

the slope has to intercept at y=2 and slope is rise over run so you would go up 1 and over 2.

Answer:

100/65 because 0.65 is a decimal number

Step-by-step explanation:

hope this helped

have a great day

Answer:

D. All real numbers

Step-by-step explanation:

Answer:

x = 1

Step-by-step explanation:

Answer:

y=-1x-6

Step-by-step explanation:

you can also use y=-x-6 but its your choice

Answer:

A: 0

B: pi/3

E: 5pi/3

Step-by-step explanation:

The solution to the trigonometric equation is 0 , π/3 , 5π/3

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

Let the trigonometric equation be represented as A

sin ( x/2 ) + cos ( x ) - 1 = 0

sin ( x/2 ) - ( 1 - cos ( x ) ) = 0

On further simplification , we get

( 1 - cos ( x ) ) = 2sin² ( x/2 )

So , sin ( x/2 ) - 2sin² ( x/2 ) = 0

Taking sin ( x/2 ) as the common factor , we get

sin ( x/2 ) ( 1 - 2sin ( x/2 ) ) = 0

So , the solutions to the equation are

sin ( x/2 ) = 0

x = 0 , 2π

And , ( 1 - 2sin ( x/2 ) ) = 0

sin ( x/2 ) = 1/2

x = π/3 , 5π/3

Hence , the solutions are x = 0 , π/3 , 5π/3

To learn more about trigonometric relations click :

https://brainly.com/question/14746686

#SPJ2

Answer: Andy completed 7 problems.

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

ed 2020. I went back to check the answer so 100% right.

Answer:

tru

Step-by-step explanation:

Answer:

cosФ is [tex]-\frac{\sqrt{7}}{4}[/tex]  ⇒ B

Step-by-step explanation:

Let us solve the question using one of the identities of trigonometry

∵ sin²Ф + cos²Ф = 1

∵ sinФ = [tex]\frac{3}{4}[/tex]

→ Substitute it in the rule above to find cos Ф

∴ ([tex]\frac{3}{4}[/tex])² + cosФ² = 1

∴ [tex]\frac{9}{16}[/tex] + cosФ² = 1

→ Subtract [tex]\frac{9}{16}[/tex]  from both sides

∴ cos²Ф = [tex]\frac{7}{16}[/tex]

→ Take √ for both sides

∴ cosФ = ± [tex]\frac{\sqrt{7}}{4}[/tex]

∵ Angle Ф lies on the second quadrant

∴ cosФ is a negative value

∴ cosФ = [tex]-\frac{\sqrt{7}}{4}[/tex]  

∴ cosФ is [tex]-\frac{\sqrt{7}}{4}[/tex]  

Answer:

!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Answer:

[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]

Therefore;

[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]

Step-by-step explanation:

Given that we have;

[tex]x^2 - 2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} }[/tex]

[tex]x^2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} } + 2 = \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]

[tex]x^2 = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]

[tex]x = 3 ^{-\frac{1}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} = 3 \cdot x + \dfrac{10}{3} = 3 \times \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } +\dfrac{10}{3} = \dfrac{ 3 ^{\frac{5}{3} } + 3 }{3 ^{\frac{1}{3} } } + \dfrac{10}{3}= \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} =\dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } } = \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{5}{3} }+ 10 }{3 } } } = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]

Therefore;

[tex]x^3 = \dfrac{9 \cdot x + 10}{3}[/tex]

[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]

Answer:

6 days

Step-by-step explanation:

Given that Reilly works every other day (This means that she works every 2 days) while Samantha works every third day. Today both of them are working together.

The next day none of them will be working, on the second day only Reilly would be working, on the third day only Samantha would be working, on the fourth day only Reilly would be working, on the fifth day none will be working and on the sixth day both Reilly and Samantha would be working.

This is the same as finding the least common multiple (LCM) of 2 days and 3 days which is 6 days

Answer:

k=8

Step-by-step explanation:

For 2 lines to be parallel, they must have the same slope. First, let's isolate y.

5y=2x+2

y=2/5x+2/5

Now, in our second equation, we must make it so that the slope is 2/5.

5(4)=20

2(4)=k

k=8

y=8/20x+10

If you simplify that, then the slope will be 2/5.

Answer:

reflect over x axis

x+3  y+3

Step-by-step explanation: