6. What are the dimensions of this matrix?

Answer:

[tex]y=-\frac{22}{7}[/tex]

Step-by-step explanation:

If a basketball player makes 65% of all free throws in her first 5 seasons. The observed proportion is higher than the expected proportion, indicating that the player performed better than expected in her 6th season.

The expected frequency of successful free throws in the 6th season can be calculated based on the player's overall success rate in the first 5 seasons. Since the player made 65% of all free throws in her first 5 seasons, we can expect her to make 65 out of 100 free throws in any given season. Therefore, the expected frequency of successful free throws in the 6th season would be:

Expected frequency = (65/100) * 150 = 97.5

The observed frequency of successful free throws in the 6th season is 105.

To compare the observed and expected frequencies, we can calculate the standardized residual (z-score) as follows:

z-score = (observed frequency - expected frequency) / sqrt(expected frequency * (1 - expected frequency / total sample size))

total sample size = 150

expected frequency = 97.5

observed frequency = 105

z-score = (105 - 97.5) / sqrt(97.5 * (1 - 97.5/150)) = 1.28

The z-score of 1.28 suggests that the observed frequency is 1.28 standard deviations above the expected frequency. This indicates that the player's success rate in the 6th season is higher than what would be expected based on her overall success rate in the first 5 seasons.

Possible explanations for the difference in frequencies could be due to factors such as improvements in the player's technique, changes in the player's physical or mental state, or random variation. It is also possible that the sample size of 150 free throws in the 6th season is not large enough to draw definitive conclusions about the player's success rate in that season.

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Answer:pop

Step-by-step explanation:

Answer:

14:28

Step-by-step explanation:

Answer:

19min

Step-by-step explanation:

Answer:

this is the answer

Step-by-step explanation:

1125=11×425×4=44100=0.44

Answer:

[tex]7^2+6[/tex]

7 to the 2nd power is 49

49+6

55

Answer:

Approximately [tex]21.9\; \rm ft[/tex] (assumption: this tree is perpendicular to the ground.)

Step-by-step explanation:

Refer to the diagram attached (not drawn to scale.)

Label the following points:

Segment [tex]\rm SB[/tex] would then denote the wire between the tree and the stake. The question states that the length of this segment would be [tex]24\; \rm ft[/tex]. Segment [tex]\rm AB[/tex] would represent the [tex]1.5\; \rm ft[/tex] between the top of this tree and the point where the wire was connected to the tree.

The question is asking for the height of this tree. That would correspond to the length of segment [tex]\rm AC[/tex].

If this tree is perpendicular to the ground, then [tex]\rm \angle A\hat{C}S =90^\circ[/tex]. Triangle [tex]\rm \triangle BCS[/tex] would be a right triangle with segment [tex]\rm SB[/tex] as the hypotenuse.

The question states that the angle between the wire (segment [tex]\rm SB[/tex]) and the ground (line [tex]\rm SC[/tex]) is [tex]58^\circ[/tex]. Therefore, [tex]\rm \angle A\hat{S}C = 58^\circ[/tex].

Notice, that in right triangle [tex]\rm \triangle BCS[/tex], segment [tex]\rm BC[/tex] is the side opposite to the angle [tex]\rm \angle B\hat{S}C = 58^\circ[/tex]. Therefore, the length of segment [tex]\rm BC\![/tex] could be found from the length of the hypotenuse (segment [tex]\rm SB[/tex]) and the cosine of angle [tex]\rm \angle B\hat{S}C = 58^\circ\![/tex].

[tex]\displaystyle \cos\left(\rm \angle B\hat{S}C\right) = \frac{\text{length of $\mathrm{BC}$}}{\text{length of $\mathrm{SB}$}} \quad \genfrac{}{}{0em}{}{\leftarrow\text{opposite}}{\leftarrow \text{hypotenuse}}[/tex].

Rearrange to obtain:

[tex]\begin{aligned}& \text{length of $\mathrm{BC}$} \\ &= (\text{length of $\mathrm{SB}$}) \cdot \cos\left(\angle \mathrm{B\hat{S}C}\right)\\ &= \left(24\; \rm ft\right) \cdot \cos\left(58^\circ\right) \approx 20.35\; \rm ft\end{aligned}[/tex].

In other words, the wire is connected to the tree at approximately [tex]20.3\; \rm ft[/tex] above the ground.

Combine that with the length of segment [tex]\rm AB[/tex] to find the height of the entire tree:

[tex]\begin{aligned}&\text{height of the tree} \\ &= \text{length of $\mathrm{AC}$} \\ &= \text{length of $\mathrm{AB}$} + \text{length of $\mathrm{BC}$}\\ &\approx 20.35\; \rm ft + 1.5\; \rm ft \\ &\approx 21.9\; \rm ft\end{aligned}[/tex].

Answer:

9.72 x 10^2

Step-by-step explanation:

Answer:

Step-by-step explanation:

The price of the shirt at the store is $16

12 x .25 = 4

4 + 12 = 16

Answer:

Uhh eventully it is not so no

Step-by-step explanation:

Answer:

38

Step-by-step explanation:

Answer:

8 gallons equals 64 pints since there are 8 pints in a gallon

Step-by-step explanation:

take care

Answer:

where is the shaded part?

Step-by-step explanation:

Answer: We can't answer the question without a shape or an expatiation.  Please try again with an image or at least tell the answers and image in detail.

Step-by-step explanation:

Answer:

first four terms are 2, 7, 12, 17

Step-by-step explanation:

use this formula:  [tex]a_{n}[/tex] = [tex]a_{1}[/tex] + (n - 1)· d

where 'n' equals the position in the sequence the term is in and 'd' is the common difference

if [tex]a_{1}[/tex] = 2 and d = 5 are given, plug those into formula

[tex]a_{1}[/tex] = 2

[tex]a_{2}[/tex] = 2 + (2 - 1)·5 = 2+5 = 7

[tex]a_{3}[/tex] = 2 + (3 - 1)·5 = 2+2(5) = 12

[tex]a_{4}[/tex] = 2+(4 - 1)·5 = 2+3(5) = 17

The first four terms of the arithmetic sequence are 2, 7, 12, and 17.

It is a sequence where the difference between each consecutive term is the same.

We have,

First term = 2

Common difference = 5

First term = 2

Second term = 2 + 5 = 7

Third term = 7 + 5 = 12

Third term = 12 + 5 = 17

Thus,

The first four terms of the arithmetic sequence are 2, 7, 12, and 17.

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Answer:

Step-by-step explanation:AOPED

Answer:

[tex]\sin \theta = \frac{40}{41}[/tex], [tex]\cos \theta = \frac{3}{82}[/tex], [tex]\tan \theta = \frac{80}{3}[/tex], [tex]\cot \theta = \frac{3}{80}[/tex], [tex]\sec \theta = \frac{82}{3}[/tex], [tex]\csc \theta = \frac{41}{40}[/tex]

Step-by-step explanation:

We notice that figure represents a right triangle, the hypotenuse has a length of 164 units and the leg opposite to [tex]\theta[/tex] has a length of 160 units. The sine of [tex]\theta[/tex] is:

[tex]\sin \theta = \frac{160}{164}[/tex]

[tex]\sin \theta = \frac{40}{41}[/tex]

The leg adjacent to [tex]\theta[/tex] is determine by the Pythagorean Theorem:

[tex]r = \sqrt{164^{2}-160^{2}}[/tex]

[tex]r = 6[/tex]

Then, the cosine of [tex]\theta[/tex] is:

[tex]\cos \theta = \frac{6}{164}[/tex]

[tex]\cos \theta = \frac{3}{82}[/tex]

Lastly, we determine the remaining trigonometric ratios by using these identities:

[tex]\tan \theta = \frac{\sin \theta}{\cos \theta}[/tex] (1)

[tex]\cot \theta = \frac{1}{\tan \theta}[/tex] (2)

[tex]\sec \theta = \frac{1}{\cos \theta}[/tex] (3)

[tex]\csc \theta = \frac{1}{\sin \theta}[/tex] (4)

If we know that [tex]\sin \theta = \frac{40}{41}[/tex] and [tex]\cos \theta = \frac{3}{82}[/tex], then the trigonometric ratios are, respectively:

[tex]\tan \theta = \frac{\frac{40}{41} }{\frac{3}{82} }[/tex]

[tex]\tan \theta = \frac{80}{3}[/tex]

[tex]\cot \theta = \frac{1}{\frac{80}{3} }[/tex]

[tex]\cot \theta = \frac{3}{80}[/tex]

[tex]\sec \theta = \frac{1}{\frac{3}{82} }[/tex]

[tex]\sec \theta = \frac{82}{3}[/tex]

[tex]\csc \theta = \frac{1}{\frac{40}{41} }[/tex]

[tex]\csc \theta = \frac{41}{40}[/tex]

Answer:

x+2=10

x-4=4

3x=24

x/8=1

Step-by-step explanation:

Answer:

237.5 calories

Step-by-step explanation:

One serving has 95

so 2.5 serving has

2.5×95= 237.5

Plz mark brainliest

thanks

Answer:

Option D is the correct answer

Step-by-step explanation:

Since, diagonals of a rhombus bisects at right angles.

[tex]\therefore m\angle STP = 90\degree \\ [/tex]

9514 1404 393

Answer:

  D)  m∠STP = 90°

Step-by-step explanation:

In general, the diagonals of a rhombus are different lengths and the corner angles are not 90°. (The exception in both cases is when the rhombus is a square.)

However, it is always true that the diagonals are perpendicular bisectors of each other, so all angles at T are 90°.

  m∠STP = 90°

Answer:

28.2

Step-by-step explanation:

Answer:

20% is 4.70

New total with tip = 28.20

Step-by-step explanation:

23.50 x .20

4.70

Answer:

B

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

So its three girls and each of them get the same amount. All you really have to do is divide 21 by 3 which is 7.

They each get to spend $7.

Answer:

Step-by-step explanation:

35

Answer:

∴ x= 17

Step-by-step explanation:

the total of angel in 90°

∴ 2x+3+3x+2 =90

∴ 5x +5 =90

  5x=90-5

  5x = 85  (divide both side by 5)

∴ x= 17

Answer:17

Step-by-step explanation:

big brain knowledge

Correct Question :-

Given :-

We need to find :-

Solution :-

Using proportion ,

By means & extremes ,

=> - 7x = - 21 × 9

=> x = ( - 21 × 9 ) / - 7

=> x = 3 × 9

=> x = 27

Hence , when y = 9 → x = 27

Answer:

is this a question......

Answer:

0.2 +-4

Step-by-step explanation:

The required probability is 0.8826 that the number x of correct answers is fewer than 4.

Probability is defined as the possibility of an event being equal to the ratio of the number of favorable outcomes and the total number of outcomes.

There are n equals 6 ​trials, each with a probability of success​ (correct) given by p equals 0.2.

This is a direct application of Binomial distribution with sample size (n) = 6 and P(success) = p = 0.35

Let X be a Binomial random variable.

X ~ Binomial (n = 6, p = 0.35)

We have to determine, P(X < 4)

Using Excel we discover this probability,

⇒ P(X < 4) = P(X ≤ 3) = BINOMDIST (3, 6, 0.35, 1) = 0.8826

⇒ P(X < 4) = 0.8826

Therefore, the required probability is 0.8826

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Answer:

The domain is the set of all the values of x, so it would be -3, -5, -6, -9, 0. The range would be every set of y, so it would be 7, -8, -1, -3. Finally, this relation is indeed a function.

Domain: -3, -5, -6, -9, 0

Range: 7, -8, -1, -3

Is it a function? Yes