Answer:
0.028571429 or 1/35
Or if you meant 315 divided by 9 it’s 35
Step-by-step explanation:
9 ÷divided by 315 equals 0.02857 (rounded to five decimal places) or approximately 0.03.
When dividing 9 by 315, we set up the division equation: 9 ÷ 315. To perform the division, we start by dividing the first digit, 9, by the first digit of 315, which is 3. Since 3 can be divided evenly into 9, the quotient is 3.
Next, we bring down the next digit, 1, making the current dividend 15. We continue dividing 15 by 3, resulting in a quotient of 5. Finally, there are no more digits to bring down, so the division is complete.
Therefore, 9 ÷ 315 equals 0.02857 (rounded to five decimal places) or approximately 0.03.
Learn more about division here
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HELP PLEASE I GIVE BRAINLIEST
Answer:
30
Step-by-step explanation:
Perimeter of rectangle = 5y - 1 + 4y + 2 + 5y - 1 + 4y + 2
= 18y + 2
18y + 2 = 128
18y = 128 - 2
= 126
y = 126 ÷ 18
y = 7
Length of AD = 4y + 2
= 4(7) + 2
= 28 + 2
= 30
Decide whether the normal sampling distribution can be used. If it can be used, test the claim about the population proportion p at the given level of significance alpha using the given sample statistics. Claim: p is not equal to 0.22; Alpha = 0.01; Sample statistics: p = 0.15, n = 180Can the normal sampling distribution be used? A. No, because np is less than 5. B. No, because nq is less than 5. C. Yes, because both np and nq are greater than or equal to 5. D. Yes, because pq is greater than alpha = 0.01. State the null and alternative hypotheses. Determine the critical value(s).Find the z-test statistic.
Answer:
A
The correct option is C
B
The value of z-test is [tex]z = -2.267[/tex]
Step-by-step explanation:
From the question we are told that
The null hypothesis [tex]H_o : p = 0.22[/tex]
The alternative hypothesis [tex]H_a : p \ne 0.22[/tex]
The level of significance is [tex]\alpha = 0.01[/tex]
The sample proportion is [tex]\^ p = 0.15[/tex]
The sample size is n = 180
Generally from central limit theorem
if np and nq are > 5 then normal sampling distribution can be used
So
np = 180 * 0.22 = 39.6 > 5
and
nq = 180 * (1 -0.22) = 140.4 > 5
So normal sampling distribution can be used
Generally the z-test is mathematically represented as
[tex]z = \frac{\^ p - p }{ \sqrt{\frac{ p(1- p ) }{n } } }[/tex]
=> [tex]z = \frac{ 0.15 - 0.22 }{ \sqrt{\frac{ 0.2(1- 0.22 ) }{ 180 } } }[/tex]
=> [tex]z = -2.267[/tex]
2x squared times 6 =
A:10x squared
B:8x squared
C:12x squared
Answer:
C: 12x squared
Step-by-step explanation:
the equation would look like [tex]2x^{2}[/tex] · [tex]6[/tex] or [tex]6(2x^{2})[/tex]
you only multiply the coefficients, leave the exponent alone for this one
so 2 times 6 would be 12 and the [tex]x^{2}[/tex] remains the same giving you [tex]12x^{2}[/tex]
Alec types
3
5
of a paragraph in
2
3
minute. If he continues at the same rate, what fraction of a paragraph can Alec complete in 1 minute?
Answer:
9/10 of a paragraph in a minute
Step-by-step explanation:
find out how much he can type in 1/3 of a minute
(3/5)/2 3/5=6/10 (6/10)/2 3/10
(3/10)*3=9/10
Answer:
9/10
Step-by-step explanation:
hope it worked
Just do q1-4 and hurry...... he’s coming for me!
1.order of operations
2.12 or variable
3.error
4.Line(12¨
hope this helps
plz consider marking brainliest
please solve needed asap
Answer:
x = 56°
Step-by-step explanation:
Base angles of an isosceles triangle are equal.
This:
The angle of the triangle to our right, which is the third unequal angle = 180 - 2(31)
= 180 - 62
= 118°
The base angle of the triangle to our left = 180 - 118 (angles on a straight line)
= 62°
x = 180 - 2(62)
x = 180 - 124
x = 56°
put the numbers in order from least to greatest.
5 * 10^6
4000000
5 * 10^5
0.6 * 10^7
75 * 10^5
A yoga instructor offers two options for classes. Option 1: $40 joining fee and $20 per class Option 2$0 joining fee and $25 per class After how many classes will both options have the same cost?
Answer:
The indifference point is 8 classes.
Step-by-step explanation:
Giving the following information:
Option 1:
$40 joining fee and $20 per class
Option 2:
$0 joining fee and $25 per class
First, we establish the total cost formulas:
Option 1= 40 + 20x
Option 2= 0 + 25x
x= number of classes
Now, we equal both formulas and isolate x:
40 + 20x = 25x
40=5x
8=x
The indifference point is 8 classes.
Prove:
Option 1= 40 + 20*8= $200
Option 2= 0 + 25*8= $200
Find the x and y intercepts of the following equation. 3x - 8y = 24
Please help me fast!!!. Joe and his family are touring Chicago. They want to visit the Willis Tower, hang out at Navy Pier, and shop on Michigan Avenue before their dinner reservations at 5:10 P.M. They plan to spend 1 hour and 10 minutes at the Willis Tower, 3 hours and 10 minutes at Navy Pier, and 1 hour and 15 minutes shopping. What is the latest time Joe's family can start their tour of Chicago and still make it to dinner on time?
Include A.M. or P.M. in your answer.
Answer:
11:10 am.
Step-by-step explanation:
The first thing I'm going to do is to add all the given time together
Total time = time spent at Willis tower + time spent at Navy Pier + time spent shopping
Total time = 1 HR and 10 minutes + 3 HR and 10 minutes + 1 hour and 15 minutes
Total time = (1 + 3 + 1) hr + (10 + 10 + 15) minutes
Total time = 5 hours + 35 minutes
The question doesn't make mention of how long they spent making the journey so, I'm assuming they spent 35 minutes driving around from Willis to the Pier and finally while shopping
Time = total time + time spent driving
Time = 5 hours 35 minutes + 35 minutes
Time = 6 hours and 10 minutes
Now, this time we've calculated, is what we're going to subtract from the dinner time to get our final answer
Needed time = dinner time - time
Needed time = 5:10 pm - 6:10
Needed time = 17:10 - 6:10
Needed time = 11:10
This means that they ought to start their tour by 11:10 am, so that they can meet their dinner
Need help with this one will mark brainliest
Answer:
circle 3
Step-by-step explanation:
Write an equation of the line that passes through the given point and is (a) parallel and (b) perpendicular to the given line.
a. y=
b. y=
Answer:
(a). y = - 4x + 19 ; (b). y = [tex]\frac{1}{4}[/tex] x + 2
Step-by-step explanation:
Slope "m" of given line is
m = - 4
Slope of parallel line is ( - 4) and perpendicular line is [tex]\frac{1}{4}[/tex]
P(4, 3)
y - [tex]y_{P}[/tex] = m( x - [tex]x_{P}[/tex] )
(a). y - 3 = - 4 (x - 4)
y = - 4x + 19
(b). y - 3 = [tex]\frac{1}{4}[/tex] ( x - 4 )
y = [tex]\frac{1}{4}[/tex] x + 2
In the figure below, APQR is a reflection of ATSA.
Two students describe the given triangles as shown:
Student I: Because reflections preserve side lengths, OR a SR, PO TS, and PR TR.SO APORATSR by SSS.
Student II: Because reflections preserve both side lengths and angle measures, ZROP ZRST, OR SR. and PO = TS. SO APOA - ATSR by SAS.
Who has proven APOR - ATSR correctly?
only studenti
only student II
o
both student I and student II
o
neither student I nor student II
Answer:
both student one and student two
Step-by-step explanation:
With the properties of congruent triangle we conclude that the statement of both student I and student II are correct.
Congruent triangle-If the sides of two triangle measure same lengths and the angle have same measures then the two triangle are said to be congruent.
Given-
Statement of student 1-Because reflections preserve side lengths,
[tex]QR \cong SR[/tex],
[tex]PQ \cong TS[/tex],
[tex]PR \cong TR.[/tex] so,
[tex]\bigtriangleup PQR \cong \bigtriangleup TSR[/tex]
In all the three sides of one triangle are equivalent to the corresponding three sides of the second triangle, then the two triangle are said to be congruent by the side side side (SSS) rule. Hence, the above statement is correct.
Statement of student 2- Because reflections preserve both side lengths and angle measures,
[tex]\angle RQP \cong \angle RST[/tex]
[tex]QR \cong SR[/tex]
[tex]PQ \cong TS[/tex]
[tex]\bigtriangleup PQR \cong \bigtriangleup TSR[/tex]
In any two sides and the angle included between the sides of one triangle are equivalent to the corresponding two sides and the angle between the sides of the second triangle, then the two triangle are said to be congruent by the side angle side (SAS) rule. Hence the above statement is correct.
Hence, with the properties of congruent triangle we conclude that the statement of both student I and student II are correct.
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Fernando loves to make music playlists. He likes to keep the same ratio of country songs to rock songs. On his summer playlist, he has 100 country songs and 24 rock songs. On his road trip playlist, Fernando has 25 country songs.
How many rock songs are on Fernando's road trip playlist?
Answer:
There are 6 rock songs on Fernando's road trip playlist.
Step-by-step explanation:
Given that he keeps the ratio same
This means that the ratios for both summer playlist and trip playlist will be the same
Let
c1 be the country songs in summer playlist
r1 be the rock songs in trip playlist
Similarly,
c2,r2 will be the country and rock songs in trip playlist
Both will be equal so
[tex]\frac{c_1}{r_1} = \frac{c_2}{r_2}[/tex]
Putting the values
[tex]\frac{100}{24} = \frac{25}{r_2}\\100r_2 = 25*24\\100r_2 = 600r_2 = \frac{600}{100}\\r_2 = 6[/tex]
Hence,
There are 6 rock songs on Fernando's road trip playlist.
Answer:
6 songs
Step-by-step explanation:
21. Transportation A youth group with 26 members is going skiing. Each of the five
chaperones will drive a van or sedan. The vans can seat seven people, and the
sedans can seat five people. Assuming there are no empty seats, how many of each
type of vehicle could transport all 31 people to the ski area in one trip?
Answers:
2 sedans and 3 vans
=====================================================
Work Shown:
s = number of sedans
v = number of vans
1 sedan = 5 seats
s sedans = 5s seats
1 van = 7 seats
v vans = 7v seats
5s+7v = all seats
5s+7v = 31
Let's go through all the values of s to see which values of v work.
If s = 0, then the equation turns into 7v = 31, but the solution for v isn't an integer.If s = 1, then the equation turns into 5+7v = 31 and that solves to v = 26/7 = 3.71 which also isn't an integerIf s = 2, then the equation becomes 10+7v = 31 and that solves to v = 3. So we found the answer. This means we need 2 sedans and 3 vans.As a check:
2 sedans = 5*2 = 10 seats
3 vans = 7*3 = 21 seats
10+21 = 31 seats total
This confirms the answer.
The number of vans used is three and the number of sedans is two
Let :
v represent the number of vans
s represent the number of sedans
The following equations can be gotten
7v + 5s = 31 equation 1
v + s = 5 equation 2
The elimination method would be used to solve for v and s
Multiply equation 2 by 7
7v + 7s = 35 equation 3
Subtract equation 1 from 3
2s = 4
s = 4/2
s = 2
Substitute for s in equation 2
v + 2 = 5
v = 5 - 2
v = 3
To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults
66 and 2/3% as a fraction and decimal
Answer:
Answer are right here
Step-by-step explanation:
66 as a fraction is 33/50 and as a decimal, it would be 0.66
2/3 as a fraction would be 2/3 and as decimal it would be 0.66666667
F(x)=x/2 +8, what is f(x) when x = 10?
4
ОООО
13
36
Answer:
13
Step-by-step explanation:
Just replace x with 10, so F(10) = 10/2 + 8. Which is 5 + 8.
Gabriel earned $238.40 at His job when he word for 16 hours what was his hourly wage in dollars per hour?
Answer:
$14.9
Step-by-step explanation:
238.40 / 16 = $14.9 hourly
Answer:
Gabriel earns $14.90 per hour
Step-by-step explanation:
238.4 divided by 16 gives you 14.9
Hope this helps
What is the value of p in the proportion below?
StartFraction 20 over 6 EndFraction = StartFraction p over 12 EndFraction
Answer:
20/6=p/12
cross multiply
20*12=6p
240=6p
divide both sides by 6
p=40
Answer:
C - 40
Step-by-step explanation:
The accompanying table shows the number of cars of two different brands sold at a dealership during a certain month. The number of coupes and sedans is also shown.
Vehicle Brand 1 Brand 2 Total
Coupe
100
240
340
Sedan
200
85
285
Total
300
325
625
If one of these vehicles is selected at random, determine the probability that it was a coupe, given that the vehicle selected was Brand 1.
The probability that a vehicle was a coupe, given that it was Brand 1.is
(Round to four decimal places as needed.)
Answer:
0.5440
Step-by-step explanation:
Given that ;
Brand 1 : Couple Brand 2: Sedan Total
100 200 300
240 85 325
Total : 340 285 625
The probability that a vehicle selected at random is a couple given that it was brand 1 will be;
The probability that a selected vehicle is a couple is 340/625
=0.5440
which of the following represents the equation with a slope of 3 and a y-intercept of 2?
Answer:
c is the correct answer
Step-by-step explanation:
For a recent evening at a small, old-fashioned movie theater, 35% of the moviegoers were female and 65% were male. There were two movies playing that evening. One was a romantic comedy, and the other was a World War II film. As might be expected, among the females the romantic comedy was more popular than the war film: 70% of the females attended the romantic comedy. Among the male moviegoers, the romantic comedy also was more popular: 60% of the males attended the romantic comedy. No moviegoer attended both movies. Let F denote the event that a randomly chosen moviegoer (at the small theater that evening) was female and ¯F denote the event that a randomly chosen moviegoer was male. Let R denote the event that a randomly chosen moviegoer attended the romantic comedy and ¯R denote the event that a randomly chosen moviegoer attended the war film. Fill in the probabilities below, and then answer the question that follows. Do not round any of your responses
P(F)=0.35
P(F and R)=
P(F and ¯R)=
P(¯R|F)=
P(R|¯F)=0.60
P(¯F and R)=
P(¯F and ¯R)=
P(¯F)=
What is the probability that a randomly chosen moviegoer attended the romantic comedy?
Answer:
[tex]P(F\ and\ R) = 0.21[/tex]
[tex]P(F\ and\ R^{-}) = 0.14[/tex]
[tex]P(R^{-}|F)= 0.40[/tex]
[tex]P(F^{-} and\ R) = 0.39[/tex]
[tex]P(F^{-}\ and\ R^{-}) =0.26[/tex]
[tex]P(F^{-}) =0.65[/tex]
Step-by-step explanation:
The variables have been defined in the question as:
[tex]F = Female\ Moviegoer[/tex]
[tex]F^{'} = Male\ Moviegoer[/tex]
[tex]R = Romantic\ Comedy[/tex]
[tex]R^{'} = War\ File[/tex]
Also, we have the following given parameters:
[tex]P(F) = 0.35[/tex]
[tex]P(F^{-}) =0.65[/tex]
[tex]P(R) =0.60[/tex]
[tex]P(R^{-}) = 0.40[/tex]
The solution is as follows:
[tex]a.\ P(F\ and\ R)[/tex]
[tex]P(F\ and\ R) = P(F) * P(R)[/tex]
Substitute values for P(F) and P(R)
[tex]P(F\ and\ R) = 0.35 * 0.60[/tex]
[tex]P(F\ and\ R) = 0.21[/tex]
[tex]b.\ P(F\ and\ R^{-})[/tex]
[tex]P(F\ and\ R^{-}) = P(F) * P(R^{-})[/tex]
Substitute values for P(F) and P(R-)
[tex]P(F\ and\ R^{-}) = 0.35 * 0.40[/tex]
[tex]P(F\ and\ R^{-}) = 0.14[/tex]
[tex]c.\ P(R^{-}|F)[/tex]
[tex]P(R^{-}|F)=\frac{P(R^{-}\ and\ F)}{P(F)}[/tex]
[tex]P(R^{-}|F)=\frac{P(R^{-})\ *\ P(F)}{P(F)}[/tex]
Substitute values for P(F) and P(R-)
[tex]P(R^{-}|F)=\frac{0.40 * 0.35}{0.35}[/tex]
[tex]P(R^{-}|F)= 0.40[/tex]
This implies that both events are independent
[tex]d.\ P(F^{-} and\ R)[/tex]
[tex]P(F^{-} and\ R) = P(F^{-}) * P(R)[/tex]
Substitute values for P(F-) and P(R)
[tex]P(F^{-} and\ R) = 0.65 * 0.60[/tex]
[tex]P(F^{-} and\ R) = 0.39[/tex]
[tex]e.\ P(F^{-}\ and\ R^{-})[/tex]
[tex]P(F^{-}\ and\ R^{-}) =P(F^{-}) * P(R^{-})[/tex]
Substitute values for P(F-) and P(R-)
[tex]P(F^{-}\ and\ R^{-}) =0.65 * 0.40[/tex]
[tex]P(F^{-}\ and\ R^{-}) =0.26[/tex]
[tex]f.\ P(F^{-})[/tex]
[tex]P(F^{-}) =0.65[/tex] --- Given
Waiting Line Models:Movies tonight is a typical video and dvd movie rental outlet for home-viewing customers. During the weeknight evening, customers arrive at Movies Tonight with an arrival rate of 1.25 customers per minute. The checkout clerk has a service rate of 2 customers per minute/ Assume Poisson arrivals and exponential service times.a. What is the probability that no customers are in the system?b. What is the average number of customers waiting for service?c. What is the average time a customer waits for service to begin?d. What is the probability that an arriving customer will have to wait for service to begin?e. Do the operating charachteristics indicate that the one-clerk checkout system provides and acceptable level of service?
Answer:
Probability [No customers in system] = 0.375Customers waiting for service = 25/24Average time customer wait = 1.25/1.5May be waitPer customer average time = 1.33 (Approx)Step-by-step explanation:
Given:
Arrival rate λ = 1.25 min
Mean μ = 2
Computation:
(a) Probability [No customers in system]
Probability [No customers in system] = 1-[λ/μ]
Probability [No customers in system] = 1-[1.25/2]
Probability [No customers in system] = 0.375
(b) Customers waiting for service
Customers waiting for service = λ²/ [μ(μ-λ)]
Customers waiting for service = 1.25²/ [2(2-1.25)]
Customers waiting for service = 25/24
(c) Average time customer wait
Average time customer wait = λ / [μ(μ-λ)]
Average time customer wait = 1.25/ [2(2-1.25)]
Average time customer wait = 1.25/1.5
(d) May be wait because Customers waiting for service = 25/24
(e) Per customer average time
Per customer average time = 1/(μ-λ)
Per customer average time = 1/(2-1.25)
Per customer average time = 1.33 (Approx)
find the decimal equivalent of the following percent: 0.45%
2. Which of the following is the correct value of (0.22) - (0.4)? Show your reasoning. c. 0.088 d. 0.0088 w
Answer:
C
Step-by-step explanation:
there would have to be one more zero between 0 and 8 for both of them
25 yd. 4 in. Divided by 8
Answer:
113 inches or 3.13889 yards
Bea's catering charges $3 per person and a $60 clean-up fee to cater banquets. Write an equation to find the number of students (n) that could attend the French clubs banquet if they had a budgeted $200 for catering
Answer:
The required equation will be:
200 = 3n + 60Step-by-step explanation:
We know the slope-intercept form of the line equation
[tex]y = mx+b[/tex]
where 'm' is the slope or rate of change and 'b' is the y-intercept of the equation
Let 'n' represents the number of students (n).Let 'c' represents the cost budget.Given that Bea's catering charges $3 per person.
Thus, the slope or rate of change = m = 3 dollars per personGiven that the clean-up fee to cater banquets = $60
In other words, $60 is the initial condition or y-intercept.
Thus, the y-intercept b = 60Given that the cost budget = c = $200
Thus, the equation becomes
c = mn+b
substituting c = 200, m = rate of cgange = 3, b = 60
200 = 3n + 60 ∵ comparing with y = mx+b
Thus, the required equation will be:
200 = 3n + 60The equation that determines the no of students should be 200 = 3n + 60
Equation need to be used:Here we assume n be the number of students
And, c be the the cost budget.
So, we know the equation should be formed by applying the following expression
c = mn+b
Here c = 200, m = r = 3, b = 60
Therefore, the equation is 200 = 3n + 60
Hence, The equation that determines the no of students should be 200 = 3n + 60
Learn more about an equation here; https://brainly.com/question/18510004
What is the answer to this?
Answer:
65 reaminder 85
Step-by-step explanation:
u divided it and theres a big remainder so i did the two first reinders i found
4,0000000000×10,00000000
Answer:
yes 40
Step-by-step explanation:
she got it correct
Two airplanes leave Columbus at the same time and fly in opposite directions. One plane travels 70 miles per hour faster than the other plane. After 4 hours they are 3800 miles apart. What is the rate of each plane?
Hint: Distance equals rate times time. (d = r t)
Answer:
it goes 4233 miles
Step-by-step explanation:
sorry if am wrong luv!