Answer:
5.25 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 0.15 × 35
We have the final answer as
5.25 kg.m/sHope this helps you
Queremos un cilindro de simple efecto que utilice en su funcionamiento un volumen de aire a presión atmosférica de 13,122 litros, cuya presión de trabajo sea de 8,5Kgf/ cm2 y cuya longitud sea de 20 cm. -hallar el diámetro de este cilindro. - calcular las fuerzas de este cilindro.
Answer:
1) El diámetro es de aproximadamente 913,987 cm.
2) La fuerza del cilindro es 5576850 kgf
Explanation:
1) Los parámetros dados son;
El volumen del aire = 13,122 litros = 13122000 cm³
La presión de trabajo = 8.5 kgf / cm²
La longitud del cilindro = 20 cm.
Por lo tanto, tenemos;
El área de la base del cilindro = π · r² = 13122000 cm³ / (20 cm) = 656100 cm²
r = √ (656100 / π) ≈ 456,994 cm
El diámetro = 2 × r ≈ 2 × 456.994 ≈ 913.987 cm
El diámetro ≈ 913,987 cm
2) La fuerza del cilindro = El área de la base del cilindro × La presión de trabajo
∴ La fuerza del cilindro = 656100 cm² × 8.5 kgf / cm² = 5576850 kgf
La fuerza del cilindro = 5576850 kgf
Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?
Answer:
30 Watts
Explanation:
Power = Work/Time
Work = Force*Distance
Power = Force * Distance / Time
Power = 15 N * 20 meters / 10 sec
Power = 30 Watts
In her lab, Mrs. Smith is pulling a 28 N block across a surface with a constant speed. If
she must pull with a force of 4.0 N, what is the coefficient of sliding friction between the
block and the lab table?
Answer:
0.14 is the friction coefficient.
Explanation:
The equation for the friction coefficient is friction coefficient = force/normal force. The force is 4N, and the normal force is 28N. 4/28=0.14.
Question 4 of 10
The pendulum below swings in periodic motion between point A and point B.
А
B
C
D
Answer: C
Explanation:
The pendulum will have the most energy at the bottom of its swing
c. At point C the pendulum have the most kinetic energy.
What is Kinetic energy?Kinetic energy is a form of energy that an object or a particle has by reason of its motion.
If work, which transfers energy, is done on an object by applying a net force, the object speeds up and thereby gains kinetic energy.
Kinetic energy is defined as:
⇒E = 1/2mv²
Here, the mass of the pendulum bob won't change, the only way for kinetic energy to change is for the speed of the pendulum to change. Kinetic energy is highest when the velocity is the highest.
This occurs at the bottom of the pendulum. An active pendulum has the most kinetic energy at the lowest point of its swing when the weight is moving fastest.
Therefore,
At point C the pendulum have the most kinetic energy.
Learn more about Kinetic energy here:
https://brainly.com/question/999862
#SPJ5
An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?
Answer:
You need to put the diagrams. repost and include the diagrams
liquids that do not mix form into layers when they have_ densities
Answer:
different
Explanation:
A body moving in a straight line has a uniform motion if it travels ---------- distance in -------- intervals og time
Answer:
uniform an uniform
please fill it like yhis
Two soccer players run toward each other. One player has a mass of 85 kg
and runs west with a speed of 8 m/s, while the other has a mass of 105 kg
and runs east with a speed of 7 m/s. What is the total momentum of the
system made up of the two players?
Answer:
Total momentum, p = 55 kg-m/s
It is given that,
Mass of player 1, m₁ = 85 kg
Mass of player 2, m₂ = 105 kg
Speed of player 1, v₁ = -8 m/s (west)
Speed of player 2, v₂ = 7 m/s (east)
Momentum is equal to the product of mass and velocity. For this system, momentum is given by :
p=m_1v_1+m_2v_2p=m
1
v
1
+m
2
v
2
p=85\ kg\times (-8\ m/s)+105\ kg\times 7\ m/sp=85 kg×(−8 m/s)+105 kg×7 m/s
p = 55 kg-m/s
The total momentum of the system made up of the two players is 55 kg-m/s.
Answer:
p = 55 kg * m/s east
Explanation:
The answer above explains it neatly, but leaves the direction out of the answer. The player heading east has more momentum, so the net momentum of the system is east.
A student attaches a block to a force sensor and pulls it across a frictionless table. The sensor measures the block's acceleration What type of mass does the student measure ?
a. gravitational mass
b. inertial mass
c. neither
Answer:Inertial mass
Explanation:When we measure gravitational mass we find the strength of an object's interaction with a gravitational field.
When we measure inertial mass we find an object's resistance to being accelerated by a force.
An object's gravitational mass and inertial mass are the same.
We apply a force and measure the resulting acceleration, so we can use Newton’s second law to find the inertial mass.
If it requires E joules of energy to raise a mass from the surface of the Earth to an altitude of 6,000 km above the Earth, how much energy is required to raise it from the surface to an altitude of 12,000 km?
Answer:
To raise the mass to an altitude of 12,000 Km 2E joules are required.
Explanation:
Gravitational Potential Energy
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity, or [tex]9.8 m/s^2[/tex].
If a mass has a height h1, its potential energy is
[tex]U_1=m.g.h_1[/tex]
If a mass has a height h2, its potential energy is
[tex]U_2=m.g.h_2[/tex]
The ratio of both potential energies is:
[tex]\displaystyle \frac{U_2}{U_1}=\frac{m.g.h_2}{m.g.h_1}[/tex]
Simplifying:
[tex]\displaystyle \frac{U_2}{U_1}=\frac{h_2}{h_1}[/tex]
Solving for U2:
[tex]\displaystyle U_2=U_1.\frac{h_2}{h_1}[/tex]
Since U1=E:
[tex]\displaystyle U_2=E.\frac{12,000~Km}{6,000~Km}[/tex]
[tex]U_2 = 2E[/tex]
To raise the mass to an altitude of 12,000 Km 2E joules are required.
Cellular respiration occurs in the body 24 hours per day. During exercise, the rate of cellular respiration increases. Why does increased cellular respiration cause people to breathe faster?
More oxygen is needed to produce energy, and more carbon dioxide waste must be removed from the body.
More nutrients are needed to produce more energy, and more oxygen must be removed from the body.
More heat is generated by the body, and breathing cools the body quickly.
More water is lost from the body, and breathing hydrates the body.
Answer: I think is C
Explanation:
Answer: more oxygen is needed to produce energy
Mr. D's dog Gromit jumped out of a second story window (through the screen) and fell to the ground below. The window is 15 feet high, the acceleration of gravity is 9 m/s', and there are 3.28 feet in each meter. What was the final velocity of this crazed dog? (True story, don't worry he's fine and now he knows about gravity)
Answer:
Vf = 9.46 m/s
Explanation:
In order to find the final velocity of the dog we can use third equation of motion:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height of window = (15 ft)(1 m/3.28 ft) = 4.57 m
Vf = Final Velocity of Dog = ?
Vi = Initial Velocity of Dog = 0 m/s
Therefore,
(2)(9.8 m/s²)(4.57 m) = Vf² - (0 m/s)²
Vf = √(89.572 m²/s²)
Vf = 9.46 m/s
here avarose566 you need this
Answer:
ooooooooooooooooo
Explanation:
*makes holy water*
True or false Adding salt to a pot of water will decrease the temperature that water boils at.
Answer:water gets hot at 212 so incress
Explanation:
Answer:
False
Explanation:
It will increase
Please help me I swear will mark you brainiest
Answer:
B
Explanation:
I hope this helps!!! <3
Answer:
B.......
Explanation:
Hope this helped
A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?
Answer:
either its 12 or 0.402
Explanation:
PLZ HELP I DONT GET IT
A sealed can of your favorite soda has a carbon dioxide gas (CO2) volume of 0.05 L. When it is refrigerated, the pressure is 207 kPa. When you open it, the pressure drops to 101 kPa. After opening, what will the new volume of the carbon dioxide gas be?
Answer:
0.1 L
Explanation:
From the question given above, we obtained the following data:
Initial volume (V₁) = 0.05 L
Initial Pressure (P₁) = 207 KPa
Final pressure (P₂) = 101 KPa
Final volume (V₂) =?
We can obtain the new volume (i.e the final volume) of the gas by using the Boyle's law equation as illustrated below:
P₁V₁ = P₂V₂
207 × 0.05 = 101 × V₂
10.35 = 101 × V₂
Divide both side by 101
V₂ = 10.35 / 101
V₂ = 0.1 L
Thus, the new volume of the gas is 0.1 L
A teacher pushes a cart, while a student pushes a second, heavier cart
with the same amount of force. If the student's cart has three times the
mass as the teacher's, which of the following is true? *
Answer:
frictional force acting on the cart 450 N.
Given:
mass of cart = 50 kg
acceleration = 3
To find:
Frictional force = ?
Formula used:
F - = 600 N
F = ma
= frictional force
Solution:
Force on the block is given by,
F - = 600 N
F = ma
= frictional force
= 600 - m a
= 600 - (50 × 3)
= 600- 150
= 450 N
According to the given data the frictional force acting on the cart 450 N.
An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.
Answer:
The final velocity, [tex]v_{f}[/tex], is gd.
Explanation:
The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;
[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs
where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.
Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.
So that;
[tex]v_{f}[/tex] = 0 + 2gd
= 2gd
[tex]v_{f}[/tex] = 2gd
When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.
Then;
[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]
[tex]v_{f}[/tex] = g x d
When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.
A 10kg box is sliding at 50m/s. Find the momentum
Answer:
The momentum of the ball is 500 kg·m/s
Explanation:
The momentum is given by Mass × Velocity
The given parameters are;
The mass of the box = 10 kg
The velocity by which the box is sliding = 50 m/s
Therefore, the momentum of the ball is given as follows;
The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s
The momentum of the ball = 500 kg·m/s
solvent that can be used to remove ink from clothes and cleaning greasy
hands
Answer:
Rubbing Alcohol
Explanation:
If an arrow is fired from a bow with a perfectly horizontal velocity of 60.0 m/s and the arrow had a vertical velocity of 6m/s just before it hit the ground, how long will it take to strike the ground ?
Answer:
t = 1,28 s
Explanation: This problem is a projectile motion problem.
V₀ₓ = V₀ * cosθ
Vₓ = constant all the way
Vₓ = V₀ₓ
tanθ = Vyi/Vxi that means in any point of the trajectory
tanθ = 6 / 60 ( just before touching the ground )
tanθ = 0,1 then arctan 0,1 ≈ 6⁰
sin 6⁰ = 0,1045
cos 6⁰ = 0,9945
V₀ₓ = V₀ * cosθ ⇒ V₀ = V₀ₓ / cosθ ⇒ V₀ = 60 / 0,9945
V₀ = 60,33 m/s
V₀y = V₀ * sin θ ⇒ V₀y = 60,33 * 0,1045 ⇒ V₀y = 6,30 m/s
Vy = V₀y - g * t
At maximum y Vy = 0 ( the middle of the trajectory)
g*tm = V₀y ⇒ tm= V₀y / g
tm = 6,30 / 9,8
tm = 0,64 s ( time to reach maximum y )
Then the time of fligh is twice 0,64 s
t = 0,64 * 2
t = 1,28 s
A car with a mass of 900 kg is traveling at a
speed of 25 m/s. What is the kinetic energy
from the car's motion?
Explanation:
Kinetic Energy
= 0.5mv²
= 0.5(900kg)(25m/s)²
= 281,250J.
A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.
Calculate;
1)The work done by the effort
2)The efficiency of the system
3)The effort applied
Answer:
1) 4000Joules
2) 25%
3) 320N
Explanation:
A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.
Calculate;
1)The work done by the effort
2)The efficiency of the system
3)The effort applied
1) Workdone by the effort is the work input = Load * distance moved by the Load
Workdone by the effort = 400 * 10
Workdone by the effort = 4000Joules
2) Efficiency = Work output/Work input * 100
Work output = work done against friction = 100 Joules
Efficiency = 100/4000 * 100
Efficiency = 10000/4000
Efficiency = 25%
Hence the Efficiency of the system is 25%
3) Using the efficiency formula:
efficiency = MA/VR * 100
Velocity ratio = 5
MA = Load/Effort
efficiency = (L/E)/5 * 100
25 = 400/E/5 * 100
25/100 = 400/5E
0.25 = 400/5E
0.25 * 5E = 400
1.25E = 400
E = 400/1.25
E = 320N
hence the effort applies is 320N
plzzzz help me will mark u brainiest
Answer:
D
Explanation:
If _______________ is disregarded all objects dropped near surface of planet fall with same acceleration.
Answer:
Escape speed (the speed that is different about any planet.)
- During a certain period, the angular position of a rotating object is given by: = − + , where is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.
The question is not complete. The complete question is :
During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.
Solution :
Given :
Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]
∴ Angular speed is [tex]$\omega = \frac{d \theta}{dt}$[/tex]
ω = 10 + 4t
And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]
α = 4
a). At time, t = 0.00 seconds :
Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]
[tex]$\theta =2(0)^2 +10(0)+5$[/tex]
= 5 rad
Angular speed is ω = 10 + 4t
ω = 10 + 4(0)
= 10 rad/s
Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]
b). At time, t = 3.00 seconds :
Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]
[tex]$\theta =2(3)^2 +10(3)+5$[/tex]
= 53 rad
Angular speed is ω = 10 + 4t
ω = 10 + 4(3)
= 22 rad/s
Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]
State two devices that transfer heat out of a cool environment into a warm environment
Answer:
Heat pump
Refrigerators
Explanation:
Some devices like heat pump and refrigerators used transfers of thermal energy in a cool region to warm other region.
These types of devices used for transferring heat energy by thermal conduction method.
quit my nose so you have a bad guy really good guy
Answer:
hmmmmmmmmmmmmmmm
yes.
what is the correct answer?
Answer:
harder daddy
Explanation: