A 0.2 kg baseball is pitched with a velocity of 40 m/s and is then batted to the pitcher with a velocity of 60 m/s. What is the magnitude of change in the ball's momentum?

Answers

Answer 1

Answer:

The magnitude of change in the ball's momentum is 4 kgm/s

Explanation:

Given;

mass of the ball, m = 0.2 kg

initial velocity of the ball, u = 40 m/s

final velocity experienced by the ball, v = 60 m/s

Therefore, the change in momentum of the ball is given as final momentum minus initial mometum;

ΔP = mv - mu

ΔP = m(v-u)

ΔP = 0.2 (60 - 40)

ΔP = 4 kgm/s

Therefore, the magnitude of change in the ball's momentum is 4 kgm/s

Answer 2

The magnitude of the change in the momentum of the baseball is 4 kgm/s.

To solve the problem above we need to use the formula of change in momentum

Change in momentum: This can be defined as the product of the mass and the change in velocity of a body.

The formula of change in momentum is

M = m(v-u).................. Equation 1

Where M = change in momentum, m = mass of the baseball, v = final velocity of the baseball, u = initial velocity of the baseball.

From the question

Given:

m = 0.2 kg v = 60 m/s u = 40 m/s

Substitute these values into equation 1

         M = 0.2(60-40)          M = 0.2(20)          M = 4 kgm/s

Hence, The magnitude of the change in the momentum of the baseball is 4 kgm/s

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Related Questions

What element conducts heat and electricity:

Helium
Potassium
Sulfur
Copper
Arsenic

Answers

The answer is copper
Cooper is the answer question

I WILL GIVE YOU BRAINLIEST!!
Which physical quantity does not change when a piece of copper is heated?

Answers

Answer:

Resistance, resistivity and drift velocity varies with relaxation time which is dependent on temperature.

Number of free electrons in a conductor remains invariant even if its temperature changes.Hence correct option is option D.

1. João tem um tempo de reação de 0,2 s, pedala a bicicleta com velocidade de 5 m/s. Ele se depara com uma situação de emergência e aciona os freios. Qual foi a distância percorrida antes de frear? Tempo = 0,2s Velocidade = 5m/s = ou = ⋅

Answers

Responda:

1 metro

Explicação:

Dado que :

Tempo de reação = 0,2 segundos

Velocidade de deslocamento = 5 m / s

A distância percorrida antes da frenagem pode ser obtida usando a relação:

Distância = velocidade de viagem * tempo de reação

Distância percorrida antes da frenagem = (5 m / s) * (0,2s)

Distância percorrida antes da frenagem = 1 metro

What force acts on a projectile when it is launched in the air?
A. gravity
B. friction

Answers

Friction I think cause gravity would be pulling it down
I believe the answer is A. Gravity.

HEY CAN ANYONE PLS ANSWER DIS I RLY NEED IT!!!

Answers

Answer:

-Covalent compounds are formed when two or more nonmetal atoms bond by sharing valence electrons.

-Ionic compounds are neutral compounds made up of positively charged ions called cations and negatively charged ions called anions.

-One similarity is both ionic and covalent bonding lead to the creation of stable molecules.

Hope this helps:)

What is the mass of an object moving with 80N of force and an acceleration of 8 m/s2?

Answers

Answer:

10 Kg

Explanation:

Force is equal to mass times acceleration

therefore mass is equal to force divided by acceleration

please mark me brainliest

A feather is falling towards the ground at a constant speed. Of the forces listed, identify which act upon the feather.

Answers

Answer:

Gravitational force

Explanation:

Gravitational force is what is making the feather go down. It's pushing the feather down, without the Gravitational force, the feather would have been going up, and not down. Just like us. Gravitational force is what keeps us humans from floating ( unless ur an alien jklol), So yeah Gravitational force is the force that acts upon the feather to fall towards the ground at a constant speed.

Btw, u never listed the forces here just ....

Hope this helped!

A feather is falling towards the ground at a constant speed. Forces act upon the feather is gravitational force.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

When body is falling the net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity  

A feather is falling towards the ground at a constant speed. Forces act upon the feather is gravitational force.

To learn more about force refer to the link:

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Distance = 500 miles

Time = 10 hours

Average Speed = ?????

Answers

Average speed= 50mph

Help pleasseeee URGENT
If a 0.16 kg 8-ball at rest is hit by the 0.17 kg cue ball that is moving at a speed of 2 m/s, what is the speed of the 8-ball if the cue ball is completely stopped after the collision?

Answers

Answer:

The speed of the 8-ball is 2.125 m/s after the collision.

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of masses is conserved unless an external force is applied. The momentum of a body with mass m and velocity v is calculated as follows:

P=mv

If we have a system of masses, then the total momentum is the sum of all the individual momentums:

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

When a collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum is simplified to:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

The m1=0.16 Kg 8-ball is initially at rest v1=0. It is hit by an m2=0.17 Kg cue ball that was moving at v2=2 m/s.

After the collision, the cue ball comes to rest v2'=0. It's required to find the final speed v1' after the collision.

The above equation is solved for v1':

[tex]\displaystyle v'_1=\frac{m_1v_1+m_2v_2-m_2v'_2}{m_1}[/tex]

[tex]\displaystyle v'_1=\frac{0.16*0+0.17*2-0.17*0}{0.16}[/tex]

[tex]\displaystyle v'_1=\frac{0.34}{0.16}[/tex]

[tex]v'_1=2.125\ m/s[/tex]

The speed of the 8-ball is 2.125 m/s after the collision.

What is the frequency of a wave with a wavelength of 2 and velocity of 20m/s?

Answers

Answer:

I think it is 10 Hz

Explanation:

Sorry if it's wrong

Cart A and B are connected by a compressed spring. Cart A has a mass of 0.8 kg and Cart B has a mass of 3.00
kg. When the spring is released, Cart B moves to the right at a speed of 4 m/s. Find the speed of Cart A.
A W
B

Answers

Answer:

?????????????????????????

An object is placed 5 cm away from a lens of magnification 3.2.

How far away from the lens is the image formed?

Answers

Answer:

16 cm

Explanation:

Magnification (M)= v/u

where V = image distance from lens

u = object distance from lens

Given that the object is 5 cm away from the lens

The magnification of the lens is 3.2

image distance from lens (v) = magnification * object distance = 3.2 * 5 =16cm

Hair sticking to a balloon after it
has been rubbed on a girl's head is
an example of

Answers

Answer:

Friction

Explanation:

Answer:

It causes electrostatic charging, which makes it stick to your hair,

How far does a car travel in 30.0 s while its velocity is changing from 50.0 km/h to 80.0 km/h at a uniform rate of acceleration?

Answers

Answer:

The car will travel 541.67 m

Explanation:

Uniform Acceleration

When an object changes its velocity at the same rate, the acceleration is constant.

The relation between the initial and final speeds is:

[tex]v_f=v_o+a.t[/tex]

Where:

vf  = Final speed

vo = Initial speed

a   = Constant acceleration

t   = Elapsed time

The acceleration can be computed by solving for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

And the distance traveled is calculated as follows:

[tex]\displaystyle x=v_o.t+\frac{a.t^2}{2}[/tex]

The car travels during a time of t=30 s, and its speed changes from vo=50 Km/h to vf=80 Km/h.

Converting the speeds to m/s:

vo=50 Km/h * 1000/3600 = 13.89 m/s

vf=80 Km/h * 1000/3600 = 22.22 m/s

Both numbers are shown with a 2-decimal precision but they will be used with higher accuracy in further calculations.

Calculating the acceleration:

[tex]\displaystyle a=\frac{22.22-13.89}{30}[/tex]

[tex]a = 0.28\ m/s^2[/tex]

Now for the distance:

[tex]\displaystyle x=13.89*30+\frac{0.28.30^2}{2}[/tex]

[tex]x=416.67\ m+125\ m[/tex]

x = 541.67 m

The car will travel 541.67 m


Which example best
describes Newton's 3rd Law?
A. Paddling a canoe to make the boat move
B. A large truck takes longer to
slow down than a car
C. Falling forward in a train that is slowing down quickly

Answers

Answer:

A

Explanation:

paddling a canoe to make the boat move

a tiger moving with constant accleration covers the distance between two points 70 meter apart in 7 seconds . its speed as it pass the second point 15 meter per second . 1) what is the speed at the first point. 2) what us its accleration​

Answers

Answer:

a = 1.428 [m/s²]

v₀ = 5 [m/s]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]x=x_{o}+v_{o}*t+\frac{1}{2}*a*t^{2}[/tex]

where:

x = final point [m]

x₀ = initial point [m]

v₀ = initial velocity [m/s]

a = acceleration [m/s²]

t = time [s]

But we need to use this additional equation.

[tex]v_{f}=v_{o}+a*t[/tex]

where:

vf = final velocity = 15 [m/s]

Now we can use this equation, replacing it, in the first one. We must bear in mind that the difference among x - x₀ is equal to 70 [m]

[tex]x-x_{o}=v_{o}*t+\frac{1}{2}*a*t^{2} \\x-x_{o}=(v_{f}-a*t)*t+\frac{1}{2} *a*t^{2}\\70=(15-a*t)*t+\frac{1}{2}*a*t^{2}\\70=15*t-a*t^{2} +\frac{1}{2}*a*t^{2} \\70=15*t-\frac{1}{2}*a*t^{2}\\70=15*(7)-\frac{1}{2} *a*(7)^{2}\\105-70=0.5*a*49\\35=24.5*a\\a=1.428[m/s^{2} ][/tex]

Now replacing this value in the second equation, we can find the initial velocity.

[tex]15=v_{o}+1.428*7\\v_{o}=5[m/s][/tex]

Calculate the time needed to drive a car 100 kilometers if the car is traveling at a speed of 70 km/hr.
A.14 hours
B. 7 hours
C. .7 hours
D.1.4 hours

Answers

Answer:

D.1.4 hours

Explanation:

[tex]d\ =\ vt[/tex]

[tex]t\ =\ \frac{d}{v}[/tex]

[tex]t\ =\ \frac{100}{70}[/tex]

[tex]t\ =\ 1.42857142857[/tex]

Therefore, the answer is D 1.4 hours

What is a Cell?

Don't look it up PLEASE... I WILL GIVE BRAINLIEST

Answers

Answer:

well

Explanation:

A cell is the basic functional and structural unit of life

Answer:

Cells are the basic building blocks of all living things

Explanation:

What are the 2 types of crystallization ?

Answers

Answer:

evaporative crystallization

cooling crystallization from solution or the melt

Answer:

I think this may helps you

Pls help me!! Thank u sm

Answers

Answer:

D

Explanation:

Dylan has two cubes of iron. The larger cube has twice the mass of the smaller cube. He measures the smaller cube. Its mass is 20 grams, and its density is 7.87 g/cm3. What’s the larger cube’s volume? The larger cube’s volume is about cm3.

Answers

Answer:

5.08cm³

Explanation:

Given parameters

The larger cube has twice the mass of the smaller cube

Mass of smaller cube = 20g

Mass of the larger cube = 2 x 20  = 40g

Density of the smaller cube  = 7.87g/cm³

Unknown:

Volume of the larger cube = ?

Solution:

Density is the mass per unit volume of substance. For all samples of a substance, the density value is the same.

So, the density of the small and large iron is the same

   Density  = [tex]\frac{mass}{volume}[/tex]  

        Volume  = [tex]\frac{mass}{density}[/tex]  

 So;

  Volume of larger cube  = [tex]\frac{40}{7.87}[/tex]  = 5.08cm³

Answer:

5.08cm^3

Explanation:

In the data table , distance is measured in meters and time is in seconds. Calculate the mans average velocity using the equation (average velocity= total distance/total time.

Answers

Answer:

3.626 m/s

Explanation:

v=d/t

1. -0.02/0 = 0 m/s

2. 0.86/0.2 = 4.3 m/s

3. 1.71/0.4 = 4.275 m/s

4. 2.54/0.6 = 4.23 m/s

5. 3.32/0.8 = 4.15 m/s

6. 4.08/1.0 = 4.08 m/s

7. 4.79/1.2 = 3.99 m/s

8. 5.48/1.4 = 3.91 m/s

9. 6.15/1.6 = 3.84 m/s

10. 6.76/1.8 = 3.76 m/s

11. 7.37/2.0 = 3.66 m/s

12. 7.92/2.2 = 3.6 m/s

13. 8.45/2.4 = 3.52 m/s

14. 8.96/2.6 = 3.45 m/s

the mean of these numbers is 3.626

his average velocity ks 3.626 m/s

Free fall differs from terminal velocity, in that during free fall

A.
only air resistance is acting on an object

B.
only gravity is acting on an object

C.
air resistance and gravity are acting on an object with unequal magnitudes

D.
air resistance and gravity are acting on an object with equal magnitudes

Answers

Answer:

B

Explanation:

Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, and E, in a straight line across the path of flow. A and E are closest to the edges of the glacier. C is in the center of the glacier. B and D are between A and C and C and E respectively. How would the scientists predict the motion of each of the markers relative to the edges of the valley down which the glacier flows? What pattern would they predict in the markers over time?

Answers

Answer: c a d b

Explanation:

Glaciologists use Glen–Nye Flow Law, to predict the movements of glaciers thus, The pattern they predict in the markers over time would be C D A B.

How would the scientists predict the moving glacier of the markers relative to the edges of the valley down which the glacier flows?

In some parts of the world, glaciers are an important natural resource because the nature and behaviour of glaciers are an impact the hydrologic, geologic, and ecological systems of their immediate location.

Due to this, Glaciologists monitor and try to predict the movement and morphology of glaciers.

One of the techniques used by "Glaciologists" in the monitoring and prediction of glaciers in the use of markers.

The movement of markers is measured relative to the edges of the valley down which the glacier flows.

Thus, The movement of the markers are then predicted using the GlenNye Flow Law.

The pattern they predict in the markers over time would be C D A B.

Learn more about the glacier here;

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What are the forces on a feather falling down gravity normal force friction push force pull force?

Answers

It would be gravity! Make sure you put commas so people understand the question! :)

given a force of 88n and an acceleration of 4m/s2 what is the mass​

Answers

Answer:

The mass is 22 kilograms

Explanation:

[tex]F=ma[/tex]

[tex]88N = m(4m/s/s)[/tex]

[tex]m=\frac{88N}{4m/s^{2} }[/tex]

[tex]m=22kg[/tex]

Explain the significance of the thermometer, the electric heater, and the power supply.

Answers

Answer:

This question appear incomplete

Explanation:

This question appear incomplete. However, the significance/functions of the "instruments" mentioned (in the completed question) can be predicted since these "instruments" generally have specialized function.

A thermometer is used to determine the temperature of a substance or an object. The electric heater uses electricity to produce heat (which can be utilized for different purposes). The power supply is used to supply electricity for instruments/appliances that may require electricity to function.

a fire woman dropped a person onto the safety net. right before the person hit the net he had a velocity of 11.2m/s and 1800j of kinetic energy

Answers

Answer: 28.699

Explanation:

KE=1/2(mv²)

1800=1/2m (125.44)

14.349=2m

m=28.699

Answer:

28.699

Explanation:

Which star is closest to our solar system (after the Sun)?

Answers

Alpha Centauri A

The two main stars are Alpha Centauri A and Alpha Centauri B, which form a binary pair. They are an average of 4.3 light-years from Earth. The third star is Proxima Centauri. It is about 4.22 light-years from Earth and is the closest star other than the sun

Have a nice Day , Hope this helped you I would appreciate it if you could mark my answer brainliest

Answer:

The answer is A

An inner city revitalization zone is a rectangle that is twice as long as it is wide. The width of the region is growing at a rate of 24 m per year at a time when the region is 300 m wide. How fast is the area changing at that point in time

Answers

Answer:

[tex]\frac{dA}{dt} = 28800 \ m^2/year[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Equality Properties

Geometry

Area of a Rectangle: A = lw

Algebra I

Exponential Property: [tex]w^n \cdot w^m = w^{n + m}[/tex]

Calculus

Derivatives

Differentiating with respect to time

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Explanation:

Step 1: Define

Area is A = lw

2w = l

w = 300 m

[tex]\frac{dw}{dt} = 24 \ m/year[/tex]

Step 2: Rewrite Equation

Substitute in l:                    A = (2w)wMultiply:                              A = 2w²

Step 3: Differentiate

Differentiate the new area formula with respect to time.

Differentiate [Basic Power Rule]:                                                                   [tex]\frac{dA}{dt} = 2 \cdot 2w^{2-1}\frac{dw}{dt}[/tex]Simplify:                                                                                                           [tex]\frac{dA}{dt} = 4w\frac{dw}{dt}[/tex]

Step 4: Find Rate

Use defined variables

Substitute:                    [tex]\frac{dA}{dt} = 4(300 \ m)(24 \ m/year)[/tex]Multiply:                        [tex]\frac{dA}{dt} = (1200 \ m)(24 \ m/year)[/tex]Multiply:                        [tex]\frac{dA}{dt} = 28800 \ m^2/year[/tex]

Answer:

28,800 m²/yr

Explanation:

This rectangle has dimensions such that:

width = wlength = 2w  

We are given [tex]\displaystyle \frac{dw}{dt} = \frac{24 \ m}{yr}[/tex] and want to find [tex]\displaystyle \frac{dA}{dt} \Biggr | _{w \ = \ 300 \ m} = \ ?[/tex] when w = 300 m.

The area of a rectangle is denoted by Area = length * width.

Let's multiply the width and length (with respect to w) together to have an area equation in terms of w:

[tex]A=2w^2[/tex]

Differentiate this equation with respect to time t.  

[tex]\displaystyle \frac{dA}{dt} =4w \cdot \frac{dw}{dt}[/tex]

Let's plug known values into the equation:

[tex]\displaystyle \frac{dA}{dt} =4(300) \cdot (24)[/tex]

Simplify this equation.

[tex]\displaystyle \frac{dA}{dt} =1200 \cdot 24[/tex] [tex]\displaystyle \frac{dA}{dt} =28800[/tex]

The area is changing at a rate of 28,800 m²/yr at this point in time.

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