A 16 g ball at the end of a 1.4 m string is swung in a horizontal circle. It revolves once every 1.09 s. What is the magnitude of the string's tension?



Answer and I will give you brainiliest

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Answer:

7/ m5sec per minute ckvhxrsuvj

Answer:

The bar of colors = Chemical composition of stars

All the blue stars, (image 2) = Distance of stars

All the different color stars =Temperature of stars

Explanation:

I did this same exact thing just now and i got it correct.

Answer:

acceleration =

[tex]8.33ms {}^{ - 2} [/tex]

Explanation:

we know,

force = mass × acceleration

8.33 m/s² quickly would a 60kg object accelerate if the person applied a 500N force.

Acceleration the rate at which speed and direction of a moving object vary over time. A point or object moving straight ahead is accelerated whenever it accelerates or decelerates. Even if the speed remains constant, motion on the a circle accelerates so because direction is constantly shifting.

An item that is slowing down will always have a negative acceleration if the current direction of motion is constantly selected as positive.

Force = mass × acceleration

500 = 60 × a

a = 500 / 60

a = 50 / 6

a = 8.33 m/s²

To know more about Acceleration visit:

https://brainly.com/question/12550364

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Answer:

The frequency of the wave would come out to be 110 Hz.

Frequency is the number of completed wave cycles per second. By using the simplest frequency equation, f = 1 / T, you get the answer I provided above.

Answer:

New force = 12 N

Explanation:

The gravitational force between two masses is given by :

[tex]F=\dfrac{Gm_1m_2}{d^2}[/tex]

Where

d is the distance between masses

Initial force, F₁ = 3 B

Initial distance, d₁ = 10 m

Final distance, d₂ = 5 m

According to the above relation,

[tex]\dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\\\\F_2=\dfrac{F_1r_1^2}{r_2^2}\\\\F_2=\dfrac{3\times 10^2}{5^2}\\\\F_2=12\ N[/tex]

So, the new force is 12 N.

Answer:

a. Acceleration = 1.75 m/s²

b. Force = 105 Newton.

Explanation:

Given the following data:

Mass = 60kg

Final velocity = 7m/s

Time = 4 seconds

Required to find the acceleration and force of the body;

a. To find the acceleration;

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Where;

Since the elevator is starting from rest, its initial velocity is equal to 0m/s.

Substituting into the equation, we have;

[tex]Acceleration = \frac{7 - 0}{4}[/tex]

[tex]Acceleration = \frac{7}{4}[/tex]

Acceleration = 1.75 m/s²

b. To find the force;

[tex] Force = mass * acceleration [/tex]

Substituting into the equation, we have;

[tex] Force = 60 * 1.75[/tex]

Force = 105 Newton.

Answer:

actually ships are made in newtons third law of motion.it states to every action there is equal and opposite reaction. curved is made in downwards to maintain upthrust and to made balance.

actually it prevents ships from drowning and to move with a heavy mass.

The train has covered 13,500 meters of track.

We don't know its position, because we don't know where it started from, and we don't know how straight the track is.

Gravitational energy

Snow and sleet when they fall to the ground is gravitational force.

"While snow, sleet and freezing rain are familiar precipitation types to most people, one that may be lesser known is graupel, also known as snow pellets. Graupel forms when snowflakes are coated with a layer of ice. Graupel is typically white and opaque. A comparison of sleet and graupel."

"According to Newton's universal law of gravitation, The force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them."

Know more about gravitational force here

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Answer:

2,760watts

Explanation:

Power of the kettle = current * voltage

P = IV

Given

I = 12A

V = 230V

Substitute into the formula

Power of the kettle = 12*230

Power of the kettle = 2,760watts

Answer:

to be completely honest I have no idea however I tried calculating it on a calculator and umm...

I think the frequency is...

17,229,452

but ya know I could be totally wrong so if I am sorry

Explanation:

dont know so sorryyyyyyyyy

Explanation:

where is the question

I did not understood this question

Answers:

Here are the answers for the U2L9: Temperature & Heat Unit Test

1. Which describes how radiation moves?

  B) Radiation moves from a warmer object to a cooler object

2. Which material most likely gets warmer when places in the Sun?

  C) brown mulch

3. A thermogram of a house shows high amounts of thermal energy around the windows but not around the roof. Which conclusion is best supported by the thermogram?

  C) The windows are not energy efficient, but the roof is.

4. Which best describes convection?

  D) It is driven by temperature differences within a fluid.

5. A student heats a liquid on a burner. What happens to the portion of liquid that first begins to warm?

  Any answer you choose is correct on Connexus (look at the screenshot)

6. Convection only occurs in ____.

  B) fluids

7. Conduction involves the transfer of electric charge or ____.

  A) thermal energy

8. A scientist designed a foam container to help keep frozen foods from melting. Which best explains how the foam works?

  D) It reduces the amount of thermal energy that is transferred from the inside to the outside of the container.

9. The diagram shows movement of thermal energy. In which areas of the diagram does conduction occur? (look at the screenshot)

  B) X and Z

10. Nuclear reactions in a reactor produce a lot of thermal energy. That energy then flows and warms up water, which boils and produces steam. The stream then turns turbines that generate electricity. Which statement below can be made about the production of electricity in a nuclear reactor?

  B) Heat flows from the reactor to the water.

11. A stovetop burner on medium reaches 200° C. Which other objects will heat from the burner flow to?

     Any answer you choose is correct on Connexus (look at the screenshot)

12. Heat transfer between two substances is affected by specific heat and the

  D) amount of time and area of physical contact between the substances.

13. Which of these results in kinetic energy of an object?

  B) motion

14. Carmen is heating some water and trying to measure the temperature of water using a Celsius thermometer. Which measurement can she expect once the water begins to boil?

  B) 100° C

15. Which shows the formula for converting from degrees to Celsius to degrees Fahrenheit?

   A) °F = (9/5 × °C) + 32

16. Which of these indicates that a liquid has transferred thermal energy to the air?

  D) The liquid decreases in temperature, and its particles lose kinetic energy.

I took the test ALL of these answers are 100% correct on Connexus (they should be the same for everyone tho)

You're welcome and hope this helps!! :)

Answer:

industrial revolution

Explanation:

Answer:

Ф = 4.5176x10⁵ N . m² / C

Explanation:

In this case, we need to use two expressions in order to calculate the electric flux of the sphere.

First the Electric flux is calculated using this expression:

Ф = E * A  (1)

Where:

E: Electric field

A: Area of the sphere

To get the electric field E, we use this expression:

E = K * q / r²    (2)

If we replace (2) into (1) we have the following:

Ф = K * q * A / r²    (3)

Finally, we need to know the expression to get the area of a sphere which is the following:

A = 4πr²   (4)

Replacing into (3):}

Ф = K * Q * 4πr² / r²       discarting r²:

Ф = K * Q * 4π   (5)

Now, all we need to do is replace the given values and solve for the electric flux of the sphere:

Ф = 8.98755x10⁹ * 4x10⁻⁶ * 4 * π

Hope this helps

Answer:

5N

Explanation

convert grams to kg and multipy with 10 (.5 *10)=5N

Answer:

6.378 * 10^6 m

Explanation:

Radius = 6378 km

Changing in metres

6378 km = 6378000 m

Now in scientific notation

= 6.378 * 10 ^ 6 m

Answer:

50.96 N

Explanation:

weight = mass x gravity

We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.

w = m x g

w = 5.2 kg x 9.8 m/s^2

w = 50.96 N

The weight of the object is 50.96 N (newtons). Hope this helps, thank you !!

Answer:

The resistance that will provide this potential drop is 388.89 ohms.

Explanation:

Given;

Voltage source, E = 12 V

Voltage rating of the lamp, V = 5 V

Current through the lamp, I = 18 mA

Extra voltage or potential drop, IR =  E- V  

                                                    IR = 12 V - 5 V = 7 V

The resistance that will provide this potential drop (7 V) is calculated as follows:

IR = V

[tex]R = \frac{V}{I} = \frac{7 \ V}{18 \times 10^{-3} A} \ = 388.89 \ ohms[/tex]

Therefore, the resistance that will provide this potential drop is 388.89 ohms.

Answer:

3 × 10^8 meter/second

300000000 meter/second

Answer:

22 s

Explanation:

time = distance / velocity

We know that distance = 770 m and velocity = 35 m/s.

t = d / v

t = 770 m / 35 m/s

t = 22 s

It takes 22 seconds to cover 770 m. Hope this helps, thank you !!

Answer:

Its not d or e

Explanation:

Answer:

d

Explanation:

I am smart

Answer:

The force between Earth and the moon is 1.99x10²⁶ N.

Explanation:

The force between Earth and the moon can be found using the Gravitational Force equation:

[tex] F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} [/tex]

Where:

d: is the distance between Earth and the moon = 3.84x10⁵ m

G: is the gravitational constant = 6.67x10⁻¹¹ Nm²/kg²

[tex]m_{E}[/tex]: is the Earth's mass = 5.98x10²⁴ kg

[tex]m_{m}[/tex]: is the moon's mass = 7.36x10²² kg

Hence, the force is:

[tex] F_{g} = \frac{Gm_{E}m_{m}}{d^{2}} = \frac{6.67 \cdot 10^{-11} Nm^{2}/kg^{2}*5.98\cdot 10^{24} kg*7.36\cdot 10^{22} kg}{(3.84\cdot 10^{5} m)^{2}} = 1.99 \cdot 10^{26} N [/tex]

Therefore, the force between Earth and the moon is 1.99x10²⁶ N.

I hope it helps you!          

Answer: 294J

Explanation:

[tex]U_g=mg(y_f-y_i)[/tex]

[tex]U_g=(15)(9.8)(2-0)=294J[/tex]

Answer:

294.3 J

Explanation:

U = mgh

U = energy

m = mass

g = gravity

h = height

so

U = 15kg * 9.81 m/s^2 * 2m

294.3 J (joules) [kg *m^2/s^2]

Answer:

Then she only traveled 1km

Vehicle driving round a curve