A 2.2 kg model rocket is shot straight up in the air from the ground, with an initial velocity of 36.4 m/s. The rocket reaches its maximum height, and falls back to the ground. What is the maximum height of the rocket? Round your answer to 2 decimal places.

The density of the metal is ρ = 8.0g/cm³.

The measure of material how densely it is packed together is called density. As the mass per unit volume, it has that definition. Symbol for density: D or Formula for Density: When is the density, m is the object's mass, and V is its volume, the equation is: = m/V.

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. As long as an object's density is lower than the liquid's density, it will often float.

To the given equation we have :

mass of the bar = 256g

volume of metal bar = 32cm³

So according to the formula of density

ρ = m/V

So, putting values

ρ = 256g /32cm³

ρ = 8.0g/cm³

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Answer:

Explanation:

Conservation of momentum

In the x direction

2(15) + 2(-10) = 2(-5) + 2(vBfx)

vBfx = 10 m/s

In the y direction

2(30) + 2(5) = 2(20) + 2(vBfy)

vBfy = 15 m/s

vBf = 10i + 15j

KEi = ½(2)(15² + 30²) + ½(2)(-10² + 5²) = 1250 J

KEf =  ½(2)(-5² + 20²) + ½(2)(10² + 15²) = 750 J

KEf - KEi = 750 - 1250 = -500 J

Answer:

Cellular respiration that uses oxygen is called ​Cellular respiration

Explanation:

Without oxygen, it's call fermentation.

Answer:

Explanation:

vA / vB = √(TA/(m/L)) / √(TB/(m/L))

The lengths are the same, so the L divides out to 1

The material is identical so the mass will be directly proportional to the cross sectional area of the string

vA / vB = √(TA/(πdA²/4)) / √(TB/(πdB²/4))

π/4 is common so divides out to 1

vA / vB = √(TA/dA²) / √(TB/dB²)

vA / vB = √(410/0.489²) / √(809/1.27²)

vA / vB = 41.407 / 23.396

vA / vB = 1.8488961...

vA / vB = 1.85

Answer:

Explanation:

Ignoring friction, the acceleration will double

F = ma

2F = m(2a)

Answer:

[tex]19.64N[/tex]

Explanation:

Let's remember that if a mass describes a circle of radius [tex]l[/tex] with a constant speed of [tex]v[/tex], it has an angular velocity [tex]\omega=\frac vl[/tex]. in our case, our angular velocity will be of [tex]12/1.1= 10.91 rad/s[/tex].

Now that same mass will be subject of a centripetal acceleration [tex]a_c[/tex], caused of the tension of the string, equal to [tex]a_c=\omega^2l[/tex], which, in our situation, will be [tex](10.91)^2\times1.1=130.91 m/s^2[/tex]

We're almost done. We got mass, we got acceleration, the tension has to be their product: [tex]T= ma=130.91\times0.15=19.64N[/tex]

Answer:

I think some drawbacks are that since there are no solid walls meaning it is weak and if murphy's law is in place, the water will destroy the substance. Tsunami waves also happen very quickly so even if the water can travel thru the substance quickly, it probably won't be quick enough. This design could help if the wave is smaller because less destruction would occur.

Explanation:

yeah

Theprojectile launch allows to find the correct answer for the question about the direction of the ball when it hits the ground is:

       D)  θ = 37º measured clockwise from the x-axis.

projectile launch is an application of kinematics where there is no acceleration on the horizontal axis and the acceleration on the vertical axis is the gravity acceleration.

The horizontal distance traveled until it reaches the ground is

          x = v₀ₓ t

The height of the bullet is

          y = y₀ + [tex]v_o_y[/tex]  t - ½ g t²

The initial vertical velocity is zero and when it reaches the ground its height is zero.

         0 = y₀ - ½ g t²

         t = [tex]\sqrt{\frac{2y_o}{g} }[/tex]  

We substitute

          [tex]x = v_{ox} \ \sqrt{\frac{2y_o}{g} }[/tex]  

They indicate that the distance is:

          x = [tex]\frac{8}{3} \ y_o[/tex]  

We substitute

          [tex]\frac{8}{3} y_o = v_{ox} \sqrt{\frac{2y_o}{g} }[/tex]  

          [tex]v_{ox} = \frac{8}{3} \sqrt{\frac{y_o g}{2} }[/tex]  

The vertical speed when reaching the ground is:

         [tex]v_y = v_{oy} - g t \\v_y = - g t \\v_y = - g \sqrt{\frac{2y_o}{g} }[/tex]

Let's use trigonometry for the direction at the point of hitting the ground.

         tan θ = [tex]\frac{v_y}{v_x}[/tex]  

          θ = tan⁻¹ ( [tex]- \frac{3}{8} \ \frac{\sqrt{2y_o/g}}{\sqrt{y_o g /2} }[/tex] )

          θ = tan⁻¹ ( [tex]tan ^{-1} (- \frac{3}{8} \sqrt{4} )= tan^{-1 } \ (- \frac{3}{4} )[/tex]

          θ = -36.9º

The negative sign indicates that the angle is clockwise from the x-axis.

In conclusion, using the projectile launch we can find the correct answer for the question about the direction of the bullet when it hits the ground is:

      D) θ = 37º measured clockwise from the x-axis.

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Answer:False

Explanation:

the intensity of the sound wave decreases with increasing distance from the source.

[tex]\large\huge\green{\sf{Yes}}[/tex]

The average momentum of Cart 1 during the entire time shown before the collision is 0.24 kgm/s.

The given parameters:

The average velocity of the cart 1 before collision is calculated as follows;

[tex]v = \frac{\Delta x}{\Delta t} \\\\v = \frac{0.55 - 0.31}{0.5 - 0} \\\\v = 0.48 \ m/s\\\\[/tex]

The average momentum of Cart 1 during the entire time shown before the collision is calculated as follows;

[tex]P = mv\\\\P = 0.5 \times 0.48\\\\P = 0.24 \ kgm/s[/tex]

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Negative

Because the car is moving up and the bug is moving down. but it also depends on the weather so choice between one of those two I think is Negative but I may be wrong.

Happy Holidays!

Recall the equation for kinetic energy:

[tex]\large\boxed{KE = \frac{1}{2}mv^2 (J)}}[/tex]

m = mass (Kg)

v = velocity (m/s)

KE = kinetic energy (Nm or J)

We can find the kinetic energy for both the bowling ball and baseball:

Bowling ball:

[tex]\large\boxed{KE = \frac{1}{2}(4)(10^2) = 200 J}[/tex]

Baseball:

[tex]\large\boxed{KE = \frac{1}{2}(.25)(50^2) = 312.5 J}[/tex]

Since 312.5 J > 200 J, the BASEBALL has the greater kinetic energy. Thus, it would exert a greater impact force than the bowling ball, so it would hurt more.

Answer:

the wind carries abrasive materials

Explanation:

such as sand and salt over time theses small particles slowly strip way at the land form sculpting it by eroding the softer layers first

The initial temperature of the metal bolt is 80.8 °C

We'll begin by calculating the heat absorbed by the water.

Q = MCΔT

Q = 0.15 × 4184 × 4

Q = 2510.4 J

Finally, we shall determine the initial temperature of the metal bolt.

Q = MC(T₂ – T₁)

–2510.4 = 0.050 × 899 (25 – T₁)

–2510.4 = 44.95 (25 – T₁)

Clear bracket

–2510.4 = 1123.75 – 44.95T₁

Collect like terms

–2510.4 – 1123.75 = –44.95T₁

–3634.15 = –44.95T₁

Divide both side by –44.95

T₁ = –3634.15 / –44.95

T₁ = 80.8 °C

Thus, the initial temperature of the metal is 80.8 °C.

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Answer:

Increasing the number of trials reduces the impact of any one imprecise measurement. … To increase the number of attempts, you can find an average result for the experiment, as well as find and discrepancies as human error if you perform an experiment several times.

Explanation:

hope it helps :)

Answer:

It is because the increase in the number of trials reduces the impact of any one imprecise measurement. Using an average value for data points provides a better representation of the true value.

Answer:

b rugby and basketball

Explanation:

basket ball was made by a white man

American Football originated from Soccer and Rugby. Hence, option (A) is correct.

American football, sometimes known as gridiron, is a team sport played by two teams of eleven players on a rectangular field with goalposts at each end. It is known simply as football in the United States and Canada. The defense, the team without the ball, seeks to halt the offense's movement and seize control of the ball for themselves.

The offence, the team in possession of the oval-shaped football, attempts to advance down the field by running with the ball or throwing it. The offence is awarded a new set of four downs to resume the drive if they successfully gain at least 10 yards in four downs or plays. If they fail, they forfeit the ball to the defense.

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The speed of the block at point B = 6.36 m/s

Given data :

Mass ( m ) = 10 kg

Angle of inclination ( θ ) = 30°

Length of incline = 5 m

Determine the speed of the block at a point B on the incline

First step : Calculate the work done by frictional force

given that there is no friction on the horizontal plane. Vinclined = Vhorizontal

∴ Work done by frictional force ( Wf ) = F * L cos 180

                                                              = - ( μ_k * N ) L

                                                              = - (0.1 * 84.86   ) * 5  = - 42.4 Joule

where N = mg cos 30°

              = 10 * 9.8 * 0.866 = 84.86

Next step : Calculate the speed of the block at point B

applying work energy theorem

Wf = ΔK.E + ΔP.E

     = ( 1/2 mv² - 0 ) + ( 0 - mgh )

∴ - 42.48  = 1/2 mv² - mgh

1/2 mv² = mgh - 42.48

            = 10 * 9.8 * 5 sin 30° - 42.4

       v²  = 40.52

V ( speed of the block at point B ) = 6.36 m/s

Hence we can conclude that the speed of the block at point B = 6.36 m/s

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Attached below is the complete question related to your question

Answer:

Explanation:

Q1) d) A is not correct; R is correct (sort of) but is not the reason for A.

A vector may be resolved into an infinite number of components.

Breaking a projectile motion into the vertical and horizontal components is the EASIEST way to solve it because acceleration can be assumed to be constant in both directions. Zero for horizontal and g(ravity) in the vertical. However it is not the ONLY way to do it. Other ways are much more complex.

Q2) a) Both A and R are correct; R is the correct explanation of A  (sort of)

A is correct. Speed is constant in uniform circular motion.

R is correct if you call CENTRIPETAL acceleration constant. It is only constant in magnitude. The direction is always changing as the vector always points toward the center of rotation.

Explanation:

1) If you spot something you think might be hazardous in your workplace, report it to your employer and safety rep straight away. Your employer should then decide what harm the hazard could cause and take action to eliminate, prevent or reduce that harm. Read more about risk assessments .

2) Complex hazards are understood as various combinations of sources of hazards that lead to the accident occurrences. ... The term "natural-technological" applies to both human-induced intensification of natural risks and any accidents in the technosphere triggered by natural processes or phenomena.

3)Risk Evaluation : To determine who may be harmed. Risk Control : Taking preventive measures to control the impact of risk.

In general, to do an assessment, you should:

Identify hazards.

Determine the likelihood of harm, such as an injury or illness occurring, and its severity. ...

Identify actions necessary to eliminate the hazard, or control the risk using the hierarchy of risk control methods.

Answer:Progression is the way in which an individual should increase the load. It is a gradual increase either in frequency, intensity, or time or a combination of all three components.

Explanation:

σ = F/A = F/ (πD²/4) = 20000 / (π0.10²/4) = 2.55 MN/m²

Answer:

n/a

Explanation:

this question is not feasible

An artistic statement should be written from your own perspective.

An artist's statement, also known as an artist statement, is a written summary of their creative output. The brief essay serves as an explanation of and a defense of their own work for the spectator. As a result, it is didactic, descriptive, or reflective in nature and seeks to inform, connect with an artistic environment, and reveal the inspiration behind the work.

The writing created by the artist aims to contextualize, justify, extend, and/or explain their body of work. It situates—or tries to situate—the piece in relation to art history, art theory, the contemporary art scene, and the times. The statement also demonstrates that the artist is aware of their aims, their practice, its place within the parameters of art, and the debate that surrounds it.

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Answer:

D. High frequency and short wavelengths.

Explanation:

If a wave is high in energy it will have a higher frequency.

High frequency = short wavelengths

Assuming each trial represents 1000years, and rock samples were found, the rock sample will be given half-life of

We know that the parent Isotope remaining is given by the expression

[tex]\frac{1}{2}^n[/tex]

where,

n = number of half lives passed

From the question, the parent Isotope remaining is [tex]25\%[/tex] lokium

[tex]0.25 = \frac{1}{4} = \frac{1}{2^2} = \frac{1}{2}^2[/tex]

Therefore,

[tex]\frac{1}{2}^2[/tex] means 2 half lives have passed.

If from the question,

1 half life = 1000years

Therefore,

The rock sample's age = [tex]2*1000 = 2000years[/tex]

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Answer:

1.108 ×  [tex]10^{-3}[/tex]J

Explanation:

v=21.0v

Q=52.8×  [tex]10^{-6}[/tex]

E=?

V=E/Q

E=v ×Q

 =21 ×52.8 ×[tex]10^{-6}[/tex]

 =1108.8   ×[tex]10^{-6}[/tex]

E= 1.108 ×  [tex]10^{-3}[/tex]J

Answer:

a

Explanation:

i took the test 100%

Answer:

n

Explanation:

TWO outcomes can be predicted the students will find:

When a constant mass of gas is cooled, its volume falls, and when the temperature is raised, its volume grows. The volume of the gas rises by 1/273 of its initial volume at 0 °C for every degree of temperature rise.

In layman's words, the volume of a fixed mass of gas is exactly proportional to temperature at constant pressure.

The teacher took two latex balloons and blew them up with helium gas to the same size. As she placed Balloon A in a -15° C freezer, its temperature decreases and that's why, the size of balloon A becomes smaller. Again she  placed Balloon B in the sun on 30° C day, its temperature increases and that's why, the size of balloon B becomes larger.

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