[tex]\huge\color{pink}\boxed{\colorbox{black}{Answer ☘}}[/tex]
12 mC
Explanation:We are given that...
[tex]C_{1} = 4mF \\ V_{1} = 50v \\ C_{2} = 6mF \\ V_{2} = 30v \\ \\ we've \: to \: find \: the \: final \: charge \: on \: the \: 6mF \\capacitor \:- \\ \\ we \: know \: that ,\: \\ Q = CV \\ \\ using \: the \: formula \: \\ Q_{1} = 4 \times 50 = 200mC \\ Q_{2} = 6 \times 30 = 180mC \\ \\ total \: charge , \: Q_{1} - Q_{2} = 200 - 180 = 20mC \\ \\ let \: V \: be \: the \: final \: potential \: \\ 4V + 6V = 20mC\\ 10V = 20mC \\ V = \frac{20}{10} = 2V \\ final \: charge \: Q = CV = 6 \times 2 = 12mC[/tex]
therefore,
✯ σptíσn ( d ) íѕ cσrrєct!hope helpful~
~Be Brainly!VERY EASY QUESTION FOR HIGH SCHOOL STUDENTS:
Which of the following frequencies would you expect a young person to be able to hear? 500 Hz, 6000 Hz, 25000 Hz, 15 Hz, 15000 Hz
Answer:
Explanation: 6000z
How many joules of energy does a 100-watt light bulb use per hour? How fast would a 70-kg person have to run to have that amount of kinetic energy?
Answer:
*1) 100 Joule energy
*2) 101.2 m/s
Explanation:
*1) 1J = 1w
100J = 100w
*2) A 70-kg person will have to run at a speed of 101.2 m/s to have that amount of kinetic energy.
E
D
С
B
A
Column
Column
1.
Electron Cloud
B
2
Nucleus
b. A
3.
Electron
CD
4.
Neutron
d.
5.
Proton
ec
Answer:
1. D electron cloud
2. A nucleus
3. E electron
4. B neutron
5. C proton
Explanation:
electrons are located outside the nucleus. The nucleus holds the protons and neutrons. Protons have a positive symbol (+). electron cloud holds the electrons.
Explanation:
Electron cloud : D
Nucleus : A
Electron : E
Neutron : B
Proton : C
hope this helps you.
True or False. Father of a multitude" obeyed God's command to kill His son because the Ten Commandments had not yet been given.
Answer:
Explanation:
The father of the Multitude was Abraham. And he did precede the 10 commandments. But the story really has nothing to do with the 10 commandments.
He obeyed God's Command because it was God who issued it. Abraham had complete faith in God's ability to make things come out right. The sacrifice of Isaac was a test of faith.
I would advise you to answer true, but whoever wrote the question employed a twisted kind of logic. The sacrifice of Isaac had nothing to do with the 10 commandments. Thou Shalt not murder is not really covered by this circumstance.
So true might not be the correct answer. The question is very complex and does not lend itself to a simple True/ False answer.
A 4.0 ohm resistor has a current of 3.0 A for 5.0 min. How many electrons pass through the resistor during this time interval?
a. 7.5 x 10^21
b. 3.8 x 10^21
c. 8.4 x 10^21
d. 2.1 x 10^21
e. 5.6 x 10^21
Answer:
e. 5.6 x 10^21 electrons.
Explanation:
In order to calculate the charge Q passing through the resistor for in a definite amount of time is
[tex]Q \ (\mathrm{coulombs}) \ = \ I \ (\mathrm{amperes}) \ \times \ t \ (\mathrm{seconds}) \\ \\ \-\hspace{2.22cm} = \ 3.0 \ \mathrm{A} \ \times \ 5.0 \ \mathrm{min} \ \times \ \displaystyle\frac{60 \ \mathrm{sec}}{1 \ \mathrm{min}} \\ \\ \-\hspace{2.22cm} = \ 900 \ \mathrm{C}[/tex]
Thus, using the law of quantization of electric charge, the number of electrons passing through the resistor during this time interval can be calculated.
[tex]Q \ = \ n \times e \\ \\ n \-\hspace{0.18cm} = \ \displaystyle\frac{Q}{e} \\ \\ n \-\hspace{0.18cm} = \displaystyle\frac{900 \ \mathrm{C}}{1.6 \times 10^{-19} \ \mathrm{C}} \\ \\ n \-\hspace{0.18cm} = 5.6 \times 10^{21} \ \ \mathrm{electrons}[/tex], where n denotes the number of electrons and e is the unit charge of an electron ([tex]1.6 \times 10^{-19} \ \mathrm{C}[/tex]).
1. The acceleration equation of a certain particle is a=2t, after 4s, its velocity reaches 20m/s, then the initial velocity of the particle movement is ) ms B Sms 2.
Answer:
Change in velocity is the integral of all the differential accelerations acting over the period of acceleration.
[tex]20 = u + \int\limits^4_0 {2t} \, dt[/tex]
20 = u + t²[tex]\left \{ {{4} \atop {0}} \right.[/tex]
20 = u + 4² - 0²
20 = u + 16
u = 4 m/s
An Astronaut lands on an Earthlike planet and drops a small lead ball with a mass from the top of her spaceship. The point of release is 25 m above the surface of the planet and the ball takes 5 s to reach the ground. The astronaut's mass is 80 kg. Astronaut weight on the planet is
PLEASE NO LINKS, REAL ANSWERS DON'T WASTE TIME.
First we have to find out the gravity on that planet. We use Newton second equation of motion. It is given as,
s = ut +(gt^2)/2
Distance s = 25m
Time t = 5 s
Velocity u = 0
By putting these values,
25 = 1/2.g.(5)²
g = 2
So the gravity on that planet is 2. Lets find out the weight of the astronaut.
Mass of the astronaut on earth m = 80 kg
Weight of astronaut on earth W = mg = (80)(9.8) = 784 N
Weight of astronaut on earth like planet = (80)(2) = 160 N
x = 160N
Who did the ram caught in the thicket (Genesis 22:13) represent?
Answer:
I'm no Bible person, but I think it stands for i-dont-give-a-donkey-poop.
and suck-dog-nuts.
Lisa runs up 4 flights of stairs in 22 seconds. She weighs 510 Newtons. If each flight rises 310 cm: (a) What is her change in potential energy? (b) What average power (watts) was required during the 22 s?
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
Potential energy is the amount of energy possessed by a body due to its position relative to another object.
a) Potential energy = weight * height = 510 N * 4 flight * 3.1 m per flight
Potential energy = 6324 Joules
b) Power = Energy / time = 6324 Joules / 22 seconds = 263.5 Watts
The change in potential energy is 6324 Joules while the power is 263.5 Watts.
Find out more on potential energy at: https://brainly.com/question/14427111
A block slides on a rough 45 degree incline. The coefficient of friction is µk what is the ratio of acceleration when the block accelerates down the incline to the acceleration when the block is projected up the incline
Answer:
[tex]\frac{a_{d}}{a_{i}} = \frac{(1 -mu)}{mu}[/tex]
= (1 - μ)/μ
Explanation:
Always draw a diagram!
Up the incline:
[tex]Fr_{max}[/tex] = maximum friction
[tex]Fr_{max}[/tex] = μk
k = R = mg.cos(45) = mg.sin(45)
Resolution of forces parallel to the slope:
F (Fp in the diagram) = force of propulsion
g = gravity
[tex]F - Fr_{max} = ma_{i}[/tex]
[tex]F -[/tex] μ.mg.cos(45) [tex]= ma_{i}[/tex]
Down the decline:
Resolution of forces:
[tex]mg.sin(45) - Fr_{max} = ma_{d}[/tex]
[tex]mg.sin(45) -[/tex] μ.mg.cos(45) [tex]= ma_{d}[/tex]
Then, find the ratio:
[tex]\frac{ma_{d}}{ma_{i}} = \frac{mg.sin(45) - mu.mg.cos(45)}{-F + mu.mg.cos(45)} \\\\ \frac{a_{d}}{a_{i}} = \frac{k - k.mu}{-F + k.mu} \\\\ = \frac{k(1 -mu)}{-F + k.mu}[/tex]
Potentially, there is no need to consider F in this situation, in which case:
[tex]\frac{a_{d}}{a_{i}} = \frac{k(1 -mu)}{k.mu} \\\\ = \frac{(1 -mu)}{mu}[/tex]
= (1 - μ)/μ
2. What is the oxidation number of oxygen in most compounds?
A. 6
B.-2
C. 8
D.O
Answer:i am pro
kExplanation:
A block of wood
wood, with mass 1.34 kg rests stationary
on horizontal ground.
The coefficient of Kinetic
friction between the block and the ground is 0.966.
A bullet, with mass 0.250kg, moving horizontally
hits and sticks into the block of wood. We find
that the speed of the block of wood, with the
ballet embedded in it, just after collision is 11.9 m/s.
A) calculate the speed of the bullet before hitting the block of wood.
it, just after the collision
is 11-9mis.
as calculate the speed of the bullet before
s
hitting the block of wood.
Answer:
Explanation:
conservation of momentum
m(u) + M(0) = (m + M)v
u = (m + M)v/m
u = (0.250 + 1.35)(11.9) / 0.250
u = 76.16
u = 76.2 m/s
That's a fairly massive, and slow, bullet.
20 PTS!
If an object is moving at a constant velocity, which must be true?
Its acceleration is zero.
Its acceleration in decreasing.
Its acceleration is increasing,
Its acceleration is a non-zero constant.
[tex]\huge \bf༆ Answer ༄[/tex]
The Correct choice is ~ A
[tex] \textsf{its \: acceleration \: is \: zero}[/tex]If an object moves at a constant velocity, then the change in velocity over the time is 0, Acceleration is defined as rate of change in velocity but since there is no change in velocity, the value of Acceleration is equal to Zero.
How far has a 15 kg object moved, when a force of 22 N is applied for 5 seconds if it started at 3 m/s?
How much work is done on a 30 kg object when 20 Newton’s of force is exerted for a distance of 5 meters
Answer:
Work = force * displacement
= 50 N * 20 Meter
=1000 Newton meter = 1000 joule .
Explanation:
I need help with us history
Answer:
English is the language
Answer: im most likely wrong but i think its A
Explanation:
Select the correct answer. Chloe is playing the flute some distance away from a crowd. If the atmospheric temperature is 15°C, what is the speed of the sound traveling from the flute? A. 340 meters/second B. 330 meters/second C. 320 meters/second D. 310 meters/second E. 300 meters/second
Answer:
A. 340 meters/second
I think this is the right answer.
Which one is it??? The question and the choice are in the photo.
The answer is:
That they are switched on
The potential difference between the (high-voltage) inner shell of a Van de Graaff accelerator and a point where the charge is injected into the moving belt is 3.4 MV. What is the minimum power required to pull the belt when the belt transfers the charge to the case at 2.8 mC/s?
Explanation:
this is the answer to the questions
Would it be possible to predict the speeds that a coaster will reach before it’s ever placed on the track?
Yes, it's possible to predict the speeds that a coaster will reach before it’s
ever placed on the track.
This is usually calculated with the potential energy which is
Potential energy = m g h
where m is mass, g is acceleration due to gravity and h is height.
The given formula above is used in predicting the speeds that a coaster will
reach before it’s ever placed on the track.
Read more about Speed here https://brainly.com/question/14298262
an electron moves in a circular path in a region os space filled with a uniform magnetic field B= 0.4 T. to double the radius of the electron’s path, the magnitude of the magnetic field must become:
a. 0.8 T
b. 0.2 T
c. 0.1 T
d. 0.3 T
e. zero
Answer:
[tex]0.2\; {\rm T}[/tex], assuming that the speed of the electron stays the same.
Explanation:
Let [tex]v[/tex] denote the speed of this electron. Let [tex]q[/tex] denote the electric charge on this electron. Let [tex]m[/tex] denote the mass of this electron.
Since the path of this electron is a circle (not a helix,) this path would be in a plane normal to the magnetic field.
Let [tex]B[/tex] denote the strength of this magnetic field. The size of the magnetic force on this electron would be:
[tex]F = q\, v\, B[/tex].
Assuming that there is no other force on this electron. The net force on this electron would be [tex]F = q\, v\, B[/tex]. By Newton's Second Law of motion, the acceleration of this electron would be:
[tex]\begin{aligned}a &= \frac{F}{m} \\ &= \frac{q\, v\, B}{m}\end{aligned}[/tex].
On the other hand, since this electron is in a circular motion with a constant speed:
[tex]\begin{aligned} a = \frac{v^{2}}{r} \end{aligned}[/tex].
Combine the two equations to obtain a relationship between [tex]r[/tex] (radius of the path of the electron) and [tex]B[/tex] (strength of the magnetic field:)
[tex]\begin{aligned}\frac{q\, v\, B}{m} = \frac{v^{2}}{r}\end{aligned}[/tex].
Simplify to obtain:
[tex]\begin{aligned}r &= \frac{m\, v^{2}}{q\, v\, B} \\ &= \frac{m\, v}{q\, B} \\ &= \left(\frac{m\, v}{q}\right)\, \frac{1}{B}\end{aligned}[/tex].
In other words, if the speed [tex]v[/tex] of this electron stays the same, the radius [tex]r[/tex] of the path of this electron would be inversely proportional to the strength [tex]B[/tex] of the magnetic field. Doubling the radius of this path would require halving the strength of the magnetic field (to [tex]0.2\; {\rm T}[/tex].)
Using the figure shown, if I₃= 1.17 A, then (I₁ , I₂) A is:
a- (3.17 , 2.00)
b- (1.33 , 0.17)
c- (1.67 , 0.50)
d- (1.27 , 0.10)
The value of the current in each arm of the circuit is given by Kirchhoff's
Rules.
The correct option for (I₁, I₂) is; b-. [tex]\underline{(1.33, \ 0.17)}[/tex]Reasons:
By Kirchhoff's junction rule, we have that the sum of current at a junction is given as follows;
[tex]\displaystyle \mathbf{ \sum \limits_{k = 1}^ n I_K} = 0[/tex]Which by the direction of the currents in the given circuit diagram, we have;
I₁ - (I₃ + I₂) = 0Therefore;
I₁ = I₃ + I₂
According to Kirchhoff's loop rule theory, we have;
[tex]\displaystyle \mathbf{\sum \limits_{k = 1}^ n V_K} = 0[/tex]In the loop having the 2 Volts emf., we have;
-I₃·R₁ + 2 + I₂·R₂ = 0
I₃ = 1.17 A
R₁ = 2 Ω
R₂ = 2 Ω
Which gives;
-1.17 × 2 + 2 + I₂×2 = 0
I₂ × 2 = 2.34 - 2 = 0.34
I₂ = 0.34 ÷ 2 = 0.17
I₂ = 0.17 A
From the loop having the 7 Volts emf. we have;
7 - 0.17×2 - I₁ × 4 - I₁ × 1 = 0
Which gives;
7 - 0.34 - 5·I₁ = 0
5·I₁ = 7 - 0.34 = 6.66
I₁ = 6.66 ÷ 5 = 1.332
Therefore;
[tex]\underline{\mathbf{(I_1, \, I_2)} = (1.33, \, 0.17)}[/tex]Learn more about electric circuits here:
https://brainly.com/question/2608877
An electrician reads a resistance of 65 ohms and when energize the circuit runs 1.77 amps. what voltage to the system run on?
Answer:
115.05 Volts
Explanation:
We can use Ohm's Law!
V=IR
V= 1.77 * 65
V=115.05 Volts
Identify the types of motion:-
the movement of the snail on the ground
the strings of the guitar
the whirling of stone tied with a thread
Answer:
the movement of snail on the ground is in random motion.
the strings of the guitar is in oscillatory motion.
the whirling of stone tied with a thread is in circular motion.
What capacitance is needed to store 3μC of charge at a voltage of 120V?
Answer:
C = 0.025F
Explanation:
Charge =q=3×[tex]10^{-6}[/tex]C
Voltage=V=120V
Q=CV
C=Q/V
=3×[tex]10^{-6}[/tex]/120
=1/40×[tex]10^{-6}[/tex]
C = 0.025F
C=2.5 [tex]10^{-4}[/tex]C 0r 25 ×[tex]10^{-3}[/tex]F
What is the significance of Isaac's name?
Answer:
ghgivjgifigo ra together aigig disgust u hoodie
A woman skis from rest down a hill 20 m high. If friction is negligible, what is her speed at the bottom of the slope? Select one: O a. 20 m/s O b. 12 m/s O c. 400 m/s O d. 6 m/s
Hi there!
We can use the work-energy theorem to solve.
Recall:
[tex]\large\boxed{E_i = E_f}}[/tex]
Initial energy = final energy
The initial energy is purely potential (she starts from rest), and, if we assign the bottom of the slope as the 0 line, her energy at the bottom is purely kinetic.
PE = mgh
KE = 1/2mv²
We can begin by setting the two equal:
mgh = 1/2mv²
Cancel out the mass and rearrange to solve for velocity:
2gh = v²
v = √2gh
Plug in given values and use g ≈ 10 m/s²:
v = √2(10)(20) = 20 m/s
If 90J of energy are available for every 30C of charge, what is the potential difference?
Enter your answer as a number
V
Answer:
3 v
Explanation:
12- Calculate the power when a force of 60N moves an object over a distance of 0.6 km in 20
minutes
A. 100watts
B. 6,000 watts
C. 0.25watts
D. 30 watts
Hi there!
To solve, we must begin by calculating the total WORK done on the object.
W = F · d (Force · displacement)
Plug in the given values. Remember to convert km to m:
1 km = 1000 m
0.6 km = 600 m
W = 60 · 600 = 36000 J
Now, we can solve for power:
P = W/t
Convert minutes to seconds:
1 min = 60 sec
20 min = 1200 sec
P = 36000/1200 = 30 W ⇒ Choice D.
Blonde hair is produced by inheriting double recessive alleles (bb) from one’s parents. What is the probability of their offspring having blonde hair?
plz help
Answer:
25%
Explanation: