A 508-g sample of sodium bicarbonate (NaHCO3) contains how many moles of sodium bicarbonate (NaHCO3)?

Answers

Answer 1

molar mass = (22.99) + (1.01) + (12.01) + 3(16.00)

molar mass = 84.01 g/mol

//

(508g)(1 mol/84.01 g) = 6.0

There are 6.0 moles of sodium bicarbonate

Answer 2

A 508-g sample of sodium bicarbonate (NaHCO3) contains 0.6 moles of sodium bicarbonate (NaHCO3)

What is mass?

Mass is defined as a dimensionless quantity representing the amount of matter in a particle or object. The SI unit of mass is kg.

Mole is defined as a standard scientific unit for measuring large quantities of very small entities

Molar mass = 22.99 + 1.01 + 12.01 + 3x16.00

                   = 84.01 g/mole

Moles of NaHCO3

= 508 g x 1 mole / 84.01

= 6.0 moles

Thus, 508-g sample of sodium bicarbonate (NaHCO3) contains 0.6 moles of sodium bicarbonate (NaHCO3)

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Related Questions

In the following reaction, what element is losing mass?
Mg(s) + CuSO4(aq) -> MgSO4(aq) + Cu(s)
A. Mg
B. Cu
C.O
D. S

Answers

The element which is losing mass from the above reaction is Cu

Mg(s) + CuSO4(aq) -> MgSO4(aq) + Cu(s)

What is a compound?

A compound simply refers to a chemical compound which contains two contains two or more elements which are chemically combined together.

So therefore, the element which is losing mass from the above reaction is Cu

Mg(s) + CuSO4(aq) -> MgSO4(aq) + Cu(s)

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what is the name of p214

Answers

diphosphorus tetraiodide is the name of the p2I4 compound.

What is the name of p2I4?

The name of p2I4 is diphosphorus tetraiodide because there are two atoms with phosphorus and four atoms with iodine. We know that 'di' word is used for two while on the other hand, tetra word is used for four.

So we can conclude that diphosphorus tetraiodide is the name of the p2I4 compound.

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a gas has a density of 3.21 g/L at stp what is the gas

Answers

The gas is bromine. (This is a fact)

State which substance is undergoing oxidation and which substance is undergoing reduction in the following reaction:

N2 (g) + 3 H2 (g) ---> 2 NH3 (g)

Answers

Answer:

H₂(g) = oxidized

N₂(g) = reduced

Explanation:

Oxidized substances lose electrons and increase in oxidation number. Reduced substances gain electrons and decrease in oxidation number.

Lone elements always have an oxidation number of 0. So, N₂(g) and H₂(g) have oxidation numbers of 0.

Within compounds, hydrogen generally always have an oxidation of +1. Therefore, the hydrogen in NH₃(g) has an oxidation number of +1. In order to make the overall compound neutral, the nitrogen in NH₃(g) must have an oxidation number of -3 (to balance the +3 from the 3 hydrogens).

Since H₂(s) is losing electrons (goes from 0 to +1), it is being oxidized. Since N₂(g) is gaining electrons (goes from 0 to -3), it is being reduced.

Which is the number of moles of carbon dioxide produced from the complete combustion of 4.3 moles of ethanol?

Answers

The number of moles of carbon dioxide produced will be 8.6 moles.

Stoichiometri mole ratios

First, let's look at the balanced equation of the reaction. The complete combustion of ethanol gives carbon dioxide and water as follows:

[tex]C_2H_5OH + 3O_2 --- > 2CO_2 + 3H_2O[/tex]

We can see from the equation that the burning of 1 mole of ethanol produces 2 moles of carbon dioxide. In other words, the mole ratio is 1:2.

Thus, with 4.3 moles of ethanol, the amount, in moles, of carbon dioxide that will be produced will be:

                            4.3 x 2 = 8.6 moles

In other words, 8.6 moles of carbon dioxide will be produced from the complete combustion of 4.3 moles of ethanol.

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(Yield Problem)
3Mg+2FeCl3=2Fe+3MgCl2
When 20.5 g of Mg reacts with an excess of FeCl3, 25.9 g of Fe is produced. What is the percent
yield of the reaction?

Answers

Answer:

Percent Yield Fe  =  82.5%

Explanation:

The actual yield is the value produced after an experiment is conducted. The theoretical yield is the value calculated using the balanced chemical equation and atomic/molar masses.

To find the percent yield of iron (Fe), you need to (1) convert grams Al to moles Al (via atomic mass), then (2) convert moles Al to moles Fe (via mole-to-mole ratio from equation coefficients), then (3) convert moles Fe to grams Fe (via atomic mass), and then (4) calculate the percent yield. It is important to arrange the ratios in a way that allows for the cancellation of units. The final answer should have 3 sig figs to reflect the sig figs of the given values.

Atomic Mass (Mg): 24.305 g/mol

Atomic Mass (Fe): 55.845 g/mol

3 Mg + 2 FeCl₃ -----> 2 Fe + 3 MgCl₂

20.5 g Mg           1 mole              2 moles Fe            55.845 g
-----------------  x  -----------------  x  ----------------------  x  -----------------  =  
                           24.305 g           3 moles Mg             1 mole

=  31.4 g Fe

                                     Actual Yield
Percent Yield  =  ----------------------------------  x  100%
                                 Theoretical Yield

                               25.9 g Fe
Percent Yield  =  --------------------  x  100%
                               31.4 g Fe

Percent Yield  =  82.5%

The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release 235.0 kJ of energy?

Answers

The mass of melted gold to release the energy would be  3, 688. 8 Kg

How to determine the mass

It is important to note that the formula for  energy is

Q = n × HF

Where

n = number of moles

HF = heat of fusion

Let's find number of moles

235.0 = n × 12.550

number of moles = [tex]\frac{235}{12. 550}[/tex] = 18. 725 moles

The molar mass of Gold is 197g/ mol

We have that;

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Substitute the values

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be  3, 688. 8 Kg

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How many moles of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas?

Answers

Taking into account the reaction stoichiometry, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

Reaction stoichiometry

In first place, the balanced reaction is:

CO₂ + 4 H₄  → CH₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CO₂: 1 moleH₄: 4 moles   CH₄: 1 moleH₂O: 2 moles

Moles of CH₄ formed

The following rule of three can be applied: if by reaction stoichiometry 1 mole of CO₂ form 4 moles of CH₄, 85.1 moles of CO₂ form how many moles of CH₄?

[tex]moles of CH_{4} =\frac{85.1 moles of CO_{2}x4 moles of CH_{4} }{1 moles of CO_{2}}[/tex]

moles of CH₄= 340.4 moles

Then, 340.0 moles  of methane are produced when 85.1 moles of carbon dioxide gas react with excess hydrogen gas

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The question is in the photo

Answers

The concentration of LiOH in the reaction is 0.103 M

What is the concentration of lithium hydroxide?

This is a neutralization reaction and the equation of the reaction is written as; H2SO4(aq) + 2LiOH(aq) ---->Li2SO4(aq) + H2O(l)

The average volume of acid used is obtained from;

8.54 + 8.51 + 8.68/ 3 = 8.58 mL

CA = 0.150 M

VA = 8.58 mL

CB = ?

VB= 25.0 mL

NA = 1

NB = 2

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CB = CAVANB/VBNA

CB = 0.150 * 8.58 * 2/25.0 * 1

CB = 0.103 M

The concentration of LiOH in the reaction is 0.103 M

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A[?] is a heterogeneous mixture which settles on standing and its components can be separated by filtration. colloid suspension​

Answers

I think it should be suspension.

What is common to solving all mola mass problems?

Answers

All you need to do is to follow these 3 steps.

1. Estimate the number of each kind of atom present in the compound using the chemical formula in order to determine the molar mass of the molecule.

Divide each element's atomic weight (found in the periodic table) by the quantity of that element's atoms in the compound.Add up the total, then follow the number with the units of grams/mole.

eg. Water

2 hydrogen atoms and 1 oxygen atom make up the chemical formula H20.H- 1's atomic weightO-16's atomic weightNumber of H atoms overall in formula 2Number of O atoms overall in formula 1The molar mass will thus be as follows: H 2 x 1= 2 O 1 x 16= 16 16+2= 18Water's molar mass is 18 g/mol as a result.

How many moles of chlorine gas at 120. °C
and 33.3 atm would occupy a vessel of 11.5
L?

Answers

Answer:

11.9 moles Cl₂

Explanation:

To find the number of moles, you need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = constant (0.0821 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation, you first need to convert Celsius to Kelvin.

P = 33.3 atm                         R = 0.0821 L*atm/mol*K

V = 11.5 L                              T = 120. °C + 273.15 = 393.15 K

n = ? moles

PV = nRT

(33.3 atm)(11.5 L) = n(0.0821 L*atm/mol*K)(393.15 K)

382.95 = n(0.0821 L*atm/mol*K)(393.15 K)

382.95 = (32.2776)n

11.9 = n

what are the factors affecting qualitative analysis in chemistry​

Answers

Answer:

Techniques and Tests

Qualitative analysis typically measures changes in color, melting point, odor, reactivity, radioactivity, boiling point, bubble production, and precipitation.

what is the solubility of KCI?

Answers

Answer:

Potassium chloride.

Identify the Brønsted–Lowry acid and the Brønsted–Lowry
base on the left side of each of the following equations, and
also identify the conjugate acid and conjugate base of each
on the right side:
HCOOH(aq) + PO43-(aq) gives HCOO-(aq) + HPO42-(aq)

Answers

The following applies to the above equation:

Brønsted–Lowry acid - HCOOHBrønsted–Lowry base - PO43-Conjugate acid - HPO42-Conjugate base - HCOO-

What is Bronsted-Lowry acid and base?

Brønsted-Lowry acid is the any chemical species that acts as a donor of protons while Brønsted-Lowry base is any chemical species that acts as a proton acceptor.

In the following equation: HCOOH(aq) + PO43-(aq) = HCOO-(aq) + HPO42-(aq)

HCOOH is the proton (H+) donor, hence, is the Brønsted-Lowry acidPO43- is the donor acceptor, hence, is the Brønsted-Lowry baseHCOO- is the conjugate base that forms from the acidHPO42- is the conjugate acid that forms from the base

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Select all the correct answers.
A worker is holding a filled gas cylinder still. Which two sentences are true about the energy of the filled gas cylinder?

A man in a blue dress holding a red color cylinder

It has no energy because it’s being held still.
It has gravitational potential energy because of its height.
Its atoms and molecules have thermal energy.
It has motion energy because it will fall if let go.
Its kinetic energy is being converted to potential energy.
Reset Next

Answers

The true statements are:

It has gravitational potential energy because of its height.Its atoms and molecules have thermal energy.What is energy?

Energy is the ability to do work.

Energy can exist in many form, two of which are kinetic and potential energy.

The worker is holding a filled gas cylinder still gives the gas potential energy by lifting it above the ground.

The molecules of the gas also has kinetic energy by virtue of their constant random motion resulting in thermal energy.

In conclusion, the energy of the filled gas is both potential and kinetic.

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Question 8
If I have an unknown quantity of gas at a pressure of 3.85 atm, a volume of 32.4 liters, and a temperature of
80.4°C, how many moles of gas do I have?

Answers

Answer:

4.30 moles

Explanation:

You need to use the Ideal Gas Law. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 atm*L/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation and simplify to find "n", you need to convert Celsius to Kelvin. The final answer should have 3 sig figs to match the sig figs of the given values.

P = 3.85 atm                        R = 0.08206 atm*L/mol*K

V = 32.4 L                            T = 80.4 °C + 273.15 = 353.55 K

n = ? moles

PV = nRT

(3.85 atm)(32.4 L) = n(0.08206 atm*L/mol*K)(353.55 K)

124.74 = n(29.012313)

4.30 = n

How do you separate Sand Potassium Nitrate and Champhor

Answers

Heating & Cooling: The mixture is heated to get a saturated solution and it crystallises on cooling. Now since, potassium nitrate is more soluble it gets filtered out from the hot saturated solution and recrystallised in hot water and then dried. This separates the two mixtures into crystals.

How is the kinetic energy of the particles of a substance affected during a phase change?

O Kinetic energy increases during exothermic changes and decreases during endothermic changes.

O Kinetic energy decreases during exothermic changes and increases during endothermic changes.

O Kinetic energy does not change, but the potential energy does.

O Kinetic energy changes in the opposite way that the potential energy changes.

Answers

Answer:

O Kinetic energy does not change, but the potential energy does

How can mechanical waves help in the treatment of cancer?

Answers

Mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.

What is mechanical wave?

A mechanical wave is a wave that requires material medium for its propagation, example include;

water waves, sound waves, and seismic waves.

Mechanical waves in treatment of cancers

Sound wave in example of mechanical wave because it requires material medium for its propagation.

High-frequency sound waves (HIFU) is used in the  treatment  of cancer because the strong beam generates heat which is directed to a specific part of a cancer.

The heat generated destroys the cancer cells.

Thus, mechanical waves can help in the treatment of cancer due to heat generated by the high frequency waves.

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Analyze the following reaction and the given scenarios to discuss the relationship between volume and reaction rate. Determine which reaction will happen at a faster rate and explain why.

NH3(g) + 2O2(g) → HNO3(l) + H2O(l)

The first reaction is started in a gas chamber with a volume of 10 L. The second reaction is started in a gas chamber with a volume of 5 L.

Answers

The second reaction with the volume of 5L will occur faster as compared to the first reaction of volume 10L.

Volume is inversely proportional to the rate of reaction.

As volume increases rate of reaction decreases and as volume decreases rate of reaction increases.

Let's consider a reaction A   →  B.

r is rate of reaction and K is rate constant, A is the concentration of reaction.

r = k(A)

r is directly proportional to the A.

But the concentration of A is in Moles/liters (i.e. moles per unit volume)

r is inversely proportional to the volume of vessel or chamber.

 Hence as volume increases rate of reaction decreases.

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A mixture contains NaHCO3
together with unreactive components. A 1.68 g sample of the mixture reacts with HA
to produce 0.561 g of CO2

.

The molar mass of NaHCO3
is 84.01 g/mol
and the molar mass of CO2
is 44.01 g/mol.
What is the percent by mass of NaHCO3
in the original mixture?

Answers

Answer: 63.75 %

Explanation:

The balanced chemical equation for this reaction is:

NaHCO3 + HA = NaA + H2O + CO2

According to the chemical equation, one mole of NaHCO3 will react with one mole of HA to form one mole of NaA, H2O and CO2. All the components are in same mole ratio of 1:1:1:1

So,

Moles of CO2 = weight/molar mass = 0.561/44 = 0.01275 moles

Moles of CO2 will be equal to moles of NaHCO3 = 0.01275 moles

Moles = weight/mass

Weight = moles × mass

So the weight of NaHCO3 = 0.01275 × 84.01 = 1.071 g

The percentage mass of NaHCO3 in the original mixture =(1.071/1.68)× 100% = 63.75 %

Therefore, the percent by mass of NaHCO3 in the original mixture was 63.75 %

Balance the following reactions
a) Ca (s) + H₂O (1)→ Ca(OH)2 (aq) + H₂ (g)
b) Al2O3 (s) + C(s) + Cl₂ (g) → AICI3 (s) + CO (g)
c) FeCl3 (aq) + H₂S (g) → Fe2S3 (s) + HCI (aq)
d) CaCO3 (s) + HCI (aq) → Ca Cl₂ (aq) + CO2 (g) + H₂O (1)

Answers

Answer:

a) Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)

b) Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) --->  2 AICI₃ (s) + 3 CO (g)

c) 2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)

d) CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)

Explanation:

For an equation to be balanced, there must be an equal amount of each type of atom on both sides of the reaction. The reactants are on the left side and the products are on the right side.

a) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Ca (s) + H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)

Reactants: 1 calcium, 2 hydrogen, 1 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

The balanced equation:

Ca (s) + 2 H₂O (l) ---> Ca(OH)₂ (aq) + H₂ (g)

Reactants: 1 calcium, 4 hydrogen, 2 oxygen

Products: 1 calcium, 4 hydrogen, 2 oxygen

b) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

Al₂O₃ (s) + C (s) + Cl₂ (g) --->  AICI₃ (s) + CO (g)

Reactants: 2 aluminum, 3 oxygen, 1 carbon, 2 chlorine

Products: 1 aluminum, 1 oxygen, 1 carbon, 3 chlorine

The balanced equation:

Al₂O₃ (s) + 3 C (s) + 3 Cl₂ (g) --->  2 AICI₃ (s) + 3 CO (g)

Reactants: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine

Products: 2 aluminum, 3 oxygen, 3 carbon, 6 chlorine

c) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

FeCl₃ (aq) + H₂S (g) ---> Fe₂S₃ (s) + HCI (aq)

Reactants: 1 iron, 3 chlorine, 2 hydrogen, 1 sulfur

Products: 2 iron, 1 chlorine, 1 hydrogen, 3 sulfur

The balanced equation:

2 FeCl₃ (aq) + 3 H₂S (g) ---> Fe₂S₃ (s) + 6 HCI (aq)

Reactants: 2 iron, 6 chlorine, 6 hydrogen, 3 sulfur

Products: 2 iron, 6 chlorine, 6 chlorine, 3 sulfur

d) ------------------------------------------------------------------------------------------------------

The unbalanced equation:

CaCO₃ (s) + HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)

Reactants: 1 calcium, 1 carbon, 3 oxygen, 1 hydrogen, 1 chlorine

Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine

The balanced equation:

CaCO₃ (s) + 2 HCI (aq) ---> CaCl₂ (aq) + CO₂ (g) + H₂O (l)

Reactants: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine

Products: 1 calcium, 1 carbon, 3 oxygen, 2 hydrogen, 2 chlorine

Modeling Periodic Trends 1:
Why are periodic trends useful?
What are some examples of periodic trends?
What is ionization energy?
What was the purpose of creating your three-dimensional model?
Answer these questions in the discussion and conclusion of your Lab Report:

How does your model represent ionization energy?
What happens to the ionization energy of elements as you move from left to right across a period? Explain the trend.
What happens to the ionization energy of elements as you move down a group? Explain the trend.
In reactions between metals and nonmetals, metals tend to form cations while nonmetals tend to form anions. How does your model show this trend?

Answers

The periodic trend is very useful because it helps is understand the properties and reactivities of elements in chemical reactions

Some examples of periodic trends are:

Melting and boiling pointIonization energyElectron affinityElectronegativityAtomic size/ radiusIonic size / radius

What is ionization energy?

Ionization energy can simply be defined as that energy required to remove a valence electron from an atom of an element in a gaseous state to form a gaseous ions l

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A 36.65g sample of solid is placed in a flask. Toluene in which the solid is insoluble ,is added to the flask so that the volume of solid and liquid together is 50.00mL.The solid and toluene together weigh 58.58 g .The density of toluene at temperature of the experiment is 0.864g/ml .what is the density of the solid?

Answers

The density of the solid is =0.3076g/ml

Calculation of the density of solid

The mass of solid in flask = 36.65g

The volume of both solid and Toluene = 50ml

The mass of both solid and Toluene = 58.58g

The density of toluene = 0.864g/ml

The density of the solid = X

Note: The density of the solid is calculated from the density of both the solid and toluene.

But the density of solid+ toluene;

=mass/volume

= 58.58g/50ml

= 1.1716g/ml

Therefore the density of solid alone = density of both solid +toluene - density of toluene.

= 1.1716g/ml - 0.864g/ml

= 0.3076g/ml

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How many moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa)?

A. 163.2
B. 0.28
C. 152.3
D. 0.30

Answers

0.28 moles of nitrogen gas are there in 6.8 liters at room temperature and pressure (293 K and 100 kPa).

Ideal gas law :

An ideal gas is a gas in which atoms dose not exert any force on each other even after collision which walls and other atoms (inelastic collisions).

Mole definition:

The mole is the amount of compound present in a given system which has molecular mass as that of the mass of carbon12 .carbon 12

Using ideal gas law ,

PV=nRT

Given,

pressure = P = 100kPa

Volume = V = 6.8 Lit

Temperature = room temperature = T = 293 K

R= universal gas constant = 8.314

n= moles = ?

∴[tex]n = \frac{PV}{RT}[/tex]

∴ n = 100 × 6.8 / 8.314 × 293

∴n = 0.28 moles

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If you react 9.10g of vinyl chloride with 7.80g of oxygen, what is the theoretical yield of carbon dioxide

Answers

The theoretical yield of the CO2 produced is 4.22 g.

What is the theoretical yield of carbon dioxide?

The balanced reaction equation is;

2C2H3Cl + 5O2 ------>2CO2 + 2H2O + 2HCl

Number of moles of  vinyl chloride =  9.10g /62 g/mol = 0.15 moles

Number of moles of oxygen = 7.80g/32 g/mol = 0.24 moles

Now;

2 moles of C2H3Cl reacts with 5 moles of oxygen

0.15 moles of C2H3Cl reacts with 0.15 moles * 5 moles / 2 moles

= 0.375 moles

Hence oxygen is the limiting reactant;

5 moles of oxygen produces 2 moles of CO2

0.24 moles of oxygen produces 0.24 moles * 2 moles /5 moles

= 0.096 moles

Mass of CO2 produced = 0.096 moles * 44 g/mol

= 4.22 g

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please help me with this question

Answers

1. The resulting concentration will be 0.00044 mol/L

2. The minimum mass of sodium sulfite to add will be 0.4032 grams.

Stoichiometric problems

1. Using m1v1=m2v2

  m1 = 0.01 mol/L, v1 = 20 mL, v2 = 450 mL

 

       m2 = m1v1/v2 = 0.01 x 20/450 = 0.00044 mol/L

2. [tex]Na_2SO_3 + Ca(NO_3)_2 --- > 2NaNO_3 + CaSO_3[/tex]

Mole ratio of the reactants = 1:1

Mole of 80 mL, 0.0400 mol/L Ca(NO3)2 = 80/1000 x 0.0400 = 0.0032 mol

Equivalent mole of Na2SO3 = 0.0032 moles

Mass of 0.0032 moles Na2SO3 = 0.0032 x 126 = 0.4032 grams

Thus, the minimum mass of sodium sulfite to be added must be 0.4032 grams.

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A gaseous compound containing hydrogen and carbon is decomposed and found to contain 90.00% carbon and 10.00% hydrogen by mass. The mass of 371 mL of the gas, measured at 415 mm Hg and 41°C, is found to be 0.315 g. What is the molecular formula of the compound?

Answers

The molecular formula of the compound is C₃H₄.

What is the molecular formula of the compound?

The molecular formula of the compound is determined from the molecular mass of the compound.

The molecular mass of the compound is derived using the general gas equation as follows:

P₁V₁/T₁ = P₂V₂/T₂

V₂ = P₁V₁T₂/P₂T₁

Volume at STP, V₂ = (415 * 371 * 298(760 * 314)

V₂ = 192.26 mL = 0.192 L

Molar mass of gas = 22.4/0.192 * 0.315 = 36.75 g

Molecular formula is then determined from the mole ratio of the elements;

Carbon = 0.9 * 36.75/12 = 3

Hydrogen = 0.1 * 40/1 = 4

Thus, the molecular formula of the compound is C₃H₄.

In conclusion, the molecular formula of the gas is derived from the molecular mass.

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Answers

The concentration will be 12 M. The first option is the correct one.

Concentration

It is calculated by dividing the number of moles of solute present in a solution by the volume of the solution.

In this case, the number of moles of solute = 1.2 mols

volume of solvent = 100 mL or 0.1 L

Concentration of the solution = 1.2/0.1 = 12 mol/L or 12 M

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