A 6.0 kg object is moving at 5.0 m/s along the x axis in the positive direction. It collides
with and sticks to a 2.0 kg object moving also along the x axis. After the collision the
composite object is moving 2.0 m/s along the x axis in the negative direction.
Determine the velocity (magnitude and direction) of the 2.0 kg object before the collision.

Answers

Answer 1

Answer:

V2 =  23 [m/s] to the left.

Explanation:

In order to solve this problem, we must use the definition of conservation of linear momentum. That is, the momentum is conserved before and after the collision. The values before the collision will be taken to the left of the equality, and the values after the collision will be taken to the right of the equality, in this way we have:

Σbefore = Σafter

ΣPbefore = ΣPafter

where:

P = m*v

The positive momentum will be taken to the right and the negative momentum is to the left in this way we formulate the following equation:

[tex](m_{1}*v_{1}) + (m_{2}*v_{2})=-(m_{1} +m_{2})*v_{3}\\[/tex]

where:

m1 = mass of the first object = 6 [kg]

v1 = velocity of the first object = 5 [m/s]

m2 = mass of the stick = 2 [kg]

v2 = velocity of the stick [m/s]

v3 = velocity of the composite object = - 2 [m/s]

(6*5) + (2*V2) = - (6 + 2)*2

30 + (8*2) = - 2*V2

46 = - 2*V2

V2 = - 23 [m/s]

Note: the negative sign means the stick moves to the left


Related Questions

Megan walks 100 m east and then travels 70 m north followed by 140 m
east. What is the total distance she travels? Show/explain how you
calculate. *

Answers

Answer:

I think it's just 100+70+140

A 10,000 kg freight car moving at 2 m/s collided with a stationary 30,000 kg freight car. The two cars couple together and move off at what speed?

Answers

Answer:

Explanation:

Momentum conservation:

10,000 x 2 = (10,000 + 30,000) x v

so

v = 0.5 m/s

The speed after collision will be = 0.5m/s

What is conservation of momentum ?

The conservation of momentum states that the amount of momentum remains constant , momentum is neither be created nor be destroyed but only changes through the actin of forces as described by newton's law of motion

since , momentum should be conserved before and after the collision

so , from momentum conservation we can write ,

m1 = mass of moving freight car = 10000kg

v1 = speed of moving freight  car = 2m/s

m2 = mass of stationary freight car  = 30000 kg

v2 = speed of stationary freight car   = 0 (since , at rest )

M = mass of coupled cars after collision

V = velocity  coupled cars  after collision

momentum before collision = momentum after collision

m1*v1 + m2*v2 = MV

10000 * (2) + 30,000 * 0 = (10000 + 30000) V

20000 = 40000V

V = 0.5 m/s

The speed after collision will be = 0.5m/s

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Forces in action worksheet. Need help with this, it's due tomorrow by 8:30am, please help! If you do the bottom 2 for me as well, I will mark brainliest :)

Answers

For the bottom you can put a kid being in a swing putting the arrows up and down. For the other one you can put someone jumping that goes up and down too. Hope this helps

What is it called when two waves meet?

Question 1 options:

frequency


resonance


amplitude


superposition

Answers

Superposition is the most correct option


When two waves meet it is generally called inteference. Superposition occurs when the waves adds up to form a stronger wave. This is called constructive interference


hope this helps....

A compact car can climb a hill in 10 s. The top of the hill is 30 m higher than the
bottom, and the car's mass is 1,000 kg What is the power output of the car?

Answers

Answer:

29.4 kW

Explanation:

time t = 10 s, height h = 30 m, mass m = 1,000 kg

power output = work done/time

work done = increase in potential energy = mgh = 1,000 * 9.8 * 30 = 294,000 J = 294 kJ

power output = 294/10 = 29.4 kW

How does
friction affect the motion of
two objects sliding past
each other

Answers

Make it slowdown .in other words,lost Energy

Friction affects the motion of two objects sliding past each other. This frictional force results into the loss of energy and hence slow down the motion of the two objects in contact.

What is the Frictional force?

Frictional force is the force that is resisting the relative motion of solid surfaces, fluid layers, and the two material elements which are sliding against each other. There are several types of friction such as dry friction, it is a force that opposes the relative lateral motion of the two solid surfaces which are in contact.

Frictional force generates when the two surfaces slide past one another in motion. The force of friction opposes the motion of an object which is in contact, causing the moving objects to lose energy and slow down. The frictional force is important as it helps us in walking, driving a car, and in doing other works.

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A child in a boat throws a 6.6kg package out horizontally with a speed of 10.2m/s. Calculate the velocity of the boat immediately after, assuming it was initially at rest. The mass of the child is 29.9kg, and that of the boat is 44.7kg. Ignore water resistance.

Answers

Answer:

[tex]-0.902 \frac ms[/tex]

Explanation:

We apply conservation of momentum here. Before the toss, everything was still, so the momentum was 0. After the toss, we have the sum of the momentum of the package (1st term) and the boat+child combo (2nd term). Let's call v the velocity of the boat.

[tex]0= 6.6kg \cdot 10.2\frac ms + (29.9+44.7)kg\cdot v\\v= - \frac{6.6 \cdot 10.2 }{74.6} \frac ms \approx -0.902 \frac ms[/tex]

The term is negative since it expresses the boat+child system is going the opposite way from where the package flew.

find the kenitic energy before and after the collision

Answers

Answer:

The total system kinetic energy before the collision equals the total system kinetic energy after the collision. If total kinetic energy is not conserved, then the collision is referred to as an inelastic collision.

Explanation:

Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.

Which of these factors determine the brightness of a star?*
O The size of the star
The surface temperature of the star
The distance the star is from the Earth
O All of the above

Answers

Answer:

All of Above

Explanation:

The surface temperature

Describe how a sound wave travels through a medium to create sound.

Answers

A soundwave will go through a medium but once it goes through, the sound that you hear is muffled or not as clear usually just like sound going through a wall. The soundwaves will be something like moved and the sound you hear might not be the same or as clear as the original sound was

Answer:

sound waves

Explanation:

The sound waves can go through different mediums depending on the crest and trough

Consider the interference pattern produced by two parallel slits of width a and separation d, in which d = 3a. The slits are illuminated by normally incident light of wavelength λ.

Required:
a. First we ignore diffraction effects due to the slit width. At what angles θ from the central maximum will the next four maxima in the two-slit interference pattern occur?
b. If the intensity at θ = 0 is I0, what is the intensity at each of the angles in part (a)?
c. Which double-slit interference maxima are missing in the pattern?

Answers

Answer:

a)   m =1  θ = sin⁻¹  λ  / d,  m = 2        θ = sin⁻¹ ( λ  / 2d) ,   c)     m = 3

Explanation:

a) In the interference phenomenon the maxima are given by the expression

         d sin θ = m λ

the maximum for m = 1 is at the angle

          θ = sin⁻¹  λ  / d

the second maximum m = 2

          θ = sin⁻¹ ( λ  / 2d)

the third maximum m = 3

        θ = sin⁻¹ ( λ  / 3d)

the fourth maximum m = 4

       θ = sin⁻¹ ( λ  / 4d)

b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

       I = I₀ cos² (Ф) (sin x / x)²

       Ф = π d sin θ /λ

       x = pi a sin θ /λ

where a is the width of the slits

with the values ​​of part a are introduced in the expression and we can calculate intensity of each maximum

c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present

maximum interference       d sin θ = m λ

first diffraction minimum    a sin θ = λ

we divide the two expressions

                       d / a = m

In our case

                   3a / a = m

                    m = 3

order three is no longer visible

(a)  The next four angles from the central maxima are sin⁻¹  λ  / d, sin⁻¹  λ  / 2d , sin⁻¹  λ  / 3d, and sin⁻¹  λ  / 4d respectively.

(b)   With the values ​​of part a are the expression of intensity of each maximum can be calculated accordingly.

(c)   The third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.

a)

In the interference phenomenon the maxima are given by the expression

d sin θ = m λ

Here,

d is the slit separation and m is the order of interference.

The maximum for m = 1 is at the angle is,

θ = sin⁻¹  λ  / d

For the second maximum m = 2

θ = sin⁻¹ ( λ  / 2d)

For the third maximum m = 3

θ = sin⁻¹ ( λ  / 3d)

For the fourth maximum m = 4

θ = sin⁻¹ ( λ  / 4d)

Thus, we can conclude that the next four angles from the central maxima are sin⁻¹  λ  / d, sin⁻¹  λ  / 2d , sin⁻¹  λ  / 3d, and sin⁻¹  λ  / 4d respectively.

b)

Considering the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.

I = I₀ cos² (Ф) (sin x / x)²

Where Ф is the phase angle, and its value is,

 Ф = π d sin θ /λ

x = π  a sin θ /λ

Here a is the width of the slits

Thus, with the values ​​of part a are introduced in the expression the  intensity of each maximum can be calculated accordingly.

c)

The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present.

For the maximum interference:        

d sin θ = m λ

For the first diffraction minimum:    

a sin θ = λ

Dividing both the expressions as,

d / a = m

Since, d = 3a. Then,

3a / a = m

m = 3

Thus, we can conclude that the third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.

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PLEASE HELP WILL GIVE BRAINLIEST
A cheetah can run at instantaneous speeds of 64 km/hr or 17.8 m/sec. How much time does it take a cheetah to run 2 m?

0.1 seconds
0.1 m/s
35.6 seconds
0.03 seconds

Answers

0.1 seconds (rounded to nearest dp)
0.1 seconds .........

PLEASE HELP QUICKLY
Jason shoots a nerf dart at 13 m/s horizontally, while Jake drops
same time. Which dart hits the ground first?
O Jason's
O Jake's
O There is not enough information to know
They both hit at the same time

Answers

Answer:

they both hit at the same time

In size, composition, and color, which other planet is Saturn most like?
A) Jupiter
B) Earth
C) Venus
D) Mercury

Answers

The answer is A. Jupiter.

Read the following selections from the section "Mickey Guyton's Star-Spangled Banner."
The Grammy Award-nominated country singer delivered a soaring, emotional version of the anthem largely on bet
own. A small choir and piano later joined her.
Guyton did not appear to drop or flub any words. She wore a royal blue gown.
What conclusion is BEST Supported by the selections?

A- Mickey Guyton has performed at some of the previous Super Bowls.

B- Mickey Guyton spent a great deal of time practicing for her performance.

C- Mickey Guyton was nervous about singing the national anthem mostly on her own.

D- Mickey Guyton put her personal touch on an anthem that came off without a hitch.


Answers

Answer:

C

Explanation:

What causes the shock you receive from when you touch a doorknob?


Neutrons being pulled from one
surface to another

Protons being pulled from one surface to another

Electrons being pulled from one surface to another

Positrons being pulled from one surface to another

Answers

Answer:

Electrons being pulled from one surface to another

Explanation:

The movement of electrons creates electrical charge.

Dominic made the table below to organize his notes about mixtures. A 1-column table. The first column labeled properties of mixtures has entries has no set composition, must have more than one state of matter, must have more than one substance. What mistake did Dominic make? The title should read “Properties of Solutions” because some mixtures do not have all of the properties listed. There is a definite recipe to make each mixture, so the composition of a mixture is set. Although it is possible to have more than one state, it is also possible to have only one state. A single substance can be used to make a mixture if the substance is composed of more than one element.

Answers

Answer:

The is: Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

Hope this helps! ;-)

Answer:

Although it is possible to have more than one state, it is also possible to have only one state.

Explanation:

A) The motor speed is less than wheel speed.

B) The output power of the motor is positive during hill climbing.

C) The wheel torque is more than motor torque.

Answers

For the following statements

A) The motor speed is less than wheel speed.

B) The output power of the motor is positive during hill climbing.

C) The wheel torque is more than motor torque

These assertions are given respectively as

falsetruefalseWhat are speed, power, and Torque?

Speed: defined as the ratio of operation with respect to distance and time

Power: defined as the ability to work

Torque: This is the speed of a rotating object

Generally, the equation for Speed, Power, Torque  is mathematically given as

V=m/s

P=w/t

T=rfsin\theta

In conclusion

For a moving car, the wheels speed is in equilibrium with the motor speed Hence false

The output power during a hill climb is positive cause work is been done, Hence true

The wheel torque also is in equilibrium with the motor Torque, Hence false

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How would the conduction of someone’s hand holding the cold water jar affect the jar’s temperature?

Answers

Answer:

The person's hand will warm up the jar

Explanation:

Thermal energy will be conducted from his hand to the jar

At t = 0, Ball 1 is dropped from the top of a 22 m-high building. At the same instant Ball 2 is thrown straight up from the base of the building with an initial velocity of +12 m/s. Assume that Ball 1 starts from rest and that air friction can be ignored. At what height will the two balls pass each other? What is the velocity of each ball at the moment they are at the same height?

Answers

Answer:

The two balls pass each other at a height of 5.53 m

vf1=17.97 m/s

vf2=-5.96 m/s

Explanation:

Vertical Motion

An object thrown from the ground at speed vo, is at a height y given by:

[tex]y=vo.t-g.t^2/2[/tex]

Where t is the time and [tex]g=9.8\ m/s^2[/tex]

Furthermore, an object dropped from a certain height h will fall a distance y, given by:

[tex]y=g.t^2/2[/tex]

Thus, the height of this object above the ground is:

[tex]H = h-g.t^2/2[/tex]

The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.

We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:

[tex]vo.t-g.t^2/2=h-g.t^2/2[/tex]

Simplifying:

[tex]vo.t=h[/tex]

Solving for t:

[tex]t=h/vo=22/12=1.833\ s[/tex]

The height of ball 1 is:

[tex]H = 22-9.8.(1.833)^2/2[/tex]

H = 5.53 m

The height of ball 2 is:

[tex]y=12\cdot(1.833)-9.8\cdot(1.833)^2/2[/tex]

y=5.53 m

As required, both heights are the same.

The speed of the first ball is:

[tex]vf1=g.t=9.8\cdot 1.833=17.97\ m/s[/tex]

vf1=17.97 m/s

The speed of the second ball is:

[tex]vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s[/tex]

vf2=-5.96 m/s

This means the second ball is returning to the ground when both balls meet

What are the two types of techniques used when playing tennis? Please provide your answer using a complete sentence.

Answers

The serve, forehand groundstroke, backhand groundstroke, forehand volley, backhand volley, and overhead smash are the six basic strokes in tennis. The 6 basic "strokes" are the basic actions a tennis player makes to hit the ball.

Stay safe & humble <3

What do you think you could do to help prevent or stop cyberbullying? List at least two ideas.

Answers

Answer:

1. You can block the person bullying you.

2. Tell an adult about whats going on.

3. Try to stay off any social media apps. (turn off all notifications)

4. Don't respond to any of the comments or post. (Ignore them)

Explanation:

Hope this helps.

Which item has the most thermal energy?

Answers

Answer:

room temperature water

Explanation:

Answer:

In the figure, the particles of cocoa are moving faster than the particles of bathwater. Therefore, the cocoa has a higher temperature. However, the bath water has more thermal energy because there is so much more of it. It has many more moving particles.

Explanation:

$3.49/ gallon and other is $1.25/L which container of milk is a better deal

Answers

$3.49/ gallon is the better deal

1 gallon = 3.785 liters
$1.25 x 3.785 = $4.73
$3.49 < $4.73

Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at

while the Invalid expressions are;  v = a/t and  d = at

Explanation:

Given expressions

1) v = a/t

2) t = ∛(d²/va)

3) d = at

4) a = d/t²

5) a = √(vd/t³)

6) v = at

First we get our units of parameters

V = m/s, t = sec, d = m, a = m/s²

so

1)

v = a/t

we substitute in our units of parameters

v = m/s² / s = m/s² × 1/s = m/s³

v ≠ m/s³

therefore it is false

2)

t = ∛(d²/va)

we substitute

t = ∛(m² / m/s × m/s²)

t = ∛(m² / m²/s³)

t = ∛(s³)

t = s

correct, the expression is true

3)

d = at

we substitute

d = m/s² × s

d = m/s² × s/1 =  ms/s² = m/s

d ≠ m/s (because d = m)

so expression is false

4)

a = d/t²

we substitute

a = m / s² = m/s²

correct

the expression is true

5)

a = √(vd/t³)

we substitute

a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³)  = √(m²/s⁴) = m/s²

so a = m/s²

correct

the expression is true

6)

v = at

we substitute in the units

v = m/s² × s = m/s² ×s/1 = ms/s² = m/s

v = m/s

correct

the expression is correct

If the man has a mass of 90kg, where would he experience greater gravitational force? On Earth or Moon? Calculate and explain

Answers

Answer: You feel the gravitation on the Earth greater

Explanation:

Because the mass of the Earth is heavier than the Moon, you can replace specifi number of the weight of the Moon and the man compare the weight of the Earth and the man into the formula!

ANSWER PLS
Heat moves from the land to the air through the process of

conduction
convection
radiation
refraction

Answers

Answer:

Conduction

Explanation:

conduction is one of the three main ways that heat energy moves from place to place the other two ways heat moves around our radiation and convection conduction is the process by which heat energy is transmitted through Collisons between neighboring atoms or molecules.

hope this helps :)

Answer:

A

Explanation:

what does the area between the line and the x axis represent on a velocity vs time graph

Answers

the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period

Thank you

The area between the line and the x axis represent on a velocity vs time graph is the displacement.

The area under velocity-time graph is known as displacement.

In velocity-time graph, the y-axis represents the velocity axis while the x-axis represents the time axis.

Velocity is defined as the change in displacement per change in time.

[tex]v = \frac{dx}{dt}[/tex]

where;

[tex]dx[/tex] is the change in displacement[tex]dt[/tex] is the change in time

The integration of the velocity gives the area under the curve and that will be equal to the displacement.

[tex]\int\limits^a_b {v} \, dt = x[/tex]

Thus, the area between the line and the x axis represent on a velocity vs time graph is the displacement.

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A pulley of radius 8.0 cm is connected to a motor that rotates at a rate 7000 rad s-1 and then decelerate uniformly at a rate of 2000 rad s-1 within 5 s.
a. Calculate its angular acceleration.
b. What is the number of rotations within the time range?
c. How long is the string that winds it within the time range?
d. Determine the tangential acceleration of the string.
[15 marks]​

Answers

Answer:

(a) α = - 1000 rad/s²

Negative sign represents deceleration.

(b) θ = 3581 rotations

(c) L = 1800 m

(d) a = - 80 m/s²  

Explanation:

(a)

using First equation of motion for angular motion:

ωf = ωi + αt

where,

ωf = Final Angular Speed = 2000 rad/s

ωi = Initial Angular Speed = 7000 rad/s

α = Angular Acceleration = ?

t = time = 5 s

Therefore,

2000 rad/s = 7000 rad/s + α(5s)

α = (2000 rad/s - 7000 rad/s)/5 s

α = - 1000 rad/s²

Negative sign represents deceleration.

(b)

Using second equation of motion:

θ = ωi t + (1/2)αt²

where,

θ = No. of Rotations = ?

Therefore,

θ = (7000 rad/s)(5 s) + (1/2)(- 1000 rad/s²)(5 s)²

θ = 35000 rad - 12500 rad

θ = (22500 rad)(1 rotation/2π rad)

θ = 3581 rotations

(c)

Length of String = L = (Circumference of Pulley)(θ)

L = [2π(0.08 m)][3581 rotations]

L = 1800 m

(d)

Tangential Acceleration = a = rα

a = (0.08 m)(-1000 rad/s²)

a = - 80 m/s²

3. What kinds of electromagnetic waves have the lowest frequencies? What kinds have the highest frequencies?​

Answers

Answer:

Explanation:

from highest to lowest frequency

gamma-ray, x-ray, ultraviolet, visible light, infrared, microwave, radio

hope this helps have a good day :)

The electromagnetic waves with the lowest frequencies are the ones we call "radio" waves.

The electromagnetic waves with the highest frequencies are the ones we call "gamma rays".

In between those are all the others . . . the microwaves, the heat ('thermal') waves, the infrared waves, the light waves, the ultraviolet waves, and the X-rays.

A 2-kg ball is moving with constant speed of 5 m/s in a horizontal circle whose radius is 50 cm. What is the magnitude of the net force on the ball

Answers

For a 2-kg ball moving with a constant speed of 5 m/s in a horizontal circle whose radius,  the magnitude of the net force on the ball is 50 cm. is mathematically given as

F= 100 N

What is the magnitude of the net force on the ball?

Generally, the equation for the Net force   is mathematically given as

F = m*r*w^2

Where

w = angular velocity

w= 5/r

w= 10 rad/s

Therefore

F = 2/0.5/10^2

F= 100 N

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