Using conservation of momentum the player's speed afterward if the ball is thrown at 17.5 ms relative to the player is 3.02 m/s.
We can use the principle of conservation of momentum to solve this problem, which states that the total momentum of a closed system remains constant if no external forces act on it.
Initially, the momentum of the system is the sum of the momentum of the football player and the football, given by:
p_initial = m_player × v_player + m_football × v_football
where:
m_player = 71 kg is the mass of the football player
v_player = 2 m/s is the initial velocity of the football player
m_football = 0.430 kg is the mass of the football
v_football = 17.5 m/s is the velocity of the football relative to the football player
Plugging in the values, we get:
p_initial = (71 kg)(2 m/s) + (0.430 kg)(17.5 m/s) = 15.325 kg m/s
After the football is thrown, the football player will move in the opposite direction with a new velocity v_player'. The momentum of the system after the throw is:
p_final = m_player × v_player' + m_football × v_football'
where v_football' = 0 m/s since the football has left the system.
Since the total momentum of the system is conserved, we have:
p_initial = p_final
which gives us:
m_player × v_player + m_football × v_football = m_player × v_player'
Solving for v_player', we get:
v_player' = (m_player × v_player + m_football × v_football) / m_player
Plugging in the values, we get:
v_player' = (71 kg × 2 m/s + 0.430 kg × 17.5 m/s) / 71 kg = 3.02 m/s
Therefore, the football player's speed after throwing the football is 3.02 m/s.
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The question is -
A 71 kg football player is gliding across very smooth ice at 2 ms. He throws a 0.430 kg football straight forward. What is the player's speed afterward if the ball is thrown at 17.5 ms relative to the player?
low-level convergence that causes air to rise can occur in all the following settings except question 1 options: air moving from a large body of land to a large body of water where upper air flow speeds up and there is upper air divergence collision of two wind systems such as occurs along the equator air encountering topographic barriers such as mountains
Low-level convergence that causes air to rise can occur in all the following settings except the collision of two wind systems such as occurs along the equator.
Convergence- The word convergence refers to the act of moving toward union or uniformity. The concept of convergence refers to the tendency of separate procedures, technologies, or devices to become more similar as they evolve over time. It may also allude to the coming together of things or people. Convergence is a term used to describe the process of a single entity that is composed of formerly separate parts or functions. It is when two or more phenomena, such as technologies, industries, or societies, come together to form a unified whole.
Low-level convergence that causes air to rise can occur in all the following settings except the collision of two wind systems such as occurs along the equator. As the wind blows, it encounters a variety of barriers that impede its forward movement. One type of barrier is a topographic barrier, such as a mountain range, which causes the wind to rise and cool as it passes over the summit. As a result, air pressure decreases, and the air cools as it rises, eventually reaching saturation and forming clouds. As a result, topography can lead to precipitation on the windward side of the mountain and aridity on the leeward side.
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hello how are u today? whats up!!!!!!!!!!!!1
Answer:
good
Explanation:
i need help with physical sciences
In the development of throwing, trunk rotation in which the lower trunk and upper trunk rotate together, as a unit, is called ____________ rotation.
In the development of throwing, trunk rotation in which the lower trunk and upper trunk rotate together, as a unit, is called blocked rotation.
Trunk rotation is a crucial part of body mechanics. Trunk rotation is a crucial element of many activities. It's crucial for sports that require rapid turning movements, such as baseball, golf, and soccer. The core muscles, including the lower back and abs, work together to rotate the torso to the right and left when you twist the trunk. When performing a throwing movement, trunk rotation is essential.
Blocked rotation is when the upper and lower trunk moves together as one unit during a throwing movement. The technique is known as a "block" because it appears as if the body is blocking the movement. This type of rotation, which is also known as linear or non-differentiated, is often used by beginners or athletes who haven't yet mastered the throwing motion. It's less common in seasoned athletes who have mastered throwing technique because it can reduce throwing distance and speed.
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Given the information you have learned in class and the material in your lab manual, answer the following question: Which of these investigations could NOT be addressed using gel electophoresis? Checking for genomic DNA contamination and purity of samples Examining the expression of genes in different individuals. Determining the DNA fingerprint of the suspect of a crime. Determining the paternity of a child.
There is no investigation among the given options that cannot be addressed using gel electrophoresis.
Gel electrophoresis is a common laboratory technique used to separate and analyze DNA, RNA, and proteins based on their size, charge, and other properties. It is widely used in various fields of research, including forensic science, genetics, and biotechnology. Gel electrophoresis can be used to detect DNA contamination, analyze gene expression, determine DNA fingerprinting, and establish paternity testing. Therefore, all the investigations listed, including checking for genomic DNA contamination and purity of samples, examining gene expression, determining DNA fingerprint, and paternity testing can be addressed using gel electrophoresis.
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a series circuit has a capacitor of 1.25x10-5 farad, a resistor of 260 ohms and an inductor of 0.2 henry. the initial charge on the capacitor is 2x10-6 coulomb and there is no initial current. find the charge q(t) on the capacitor at any time t.
The final expression for the charge Q(t) at any time t is given as:Q(t) = CV(t) = 2.5 × 10^-11 e- t/RC
To find the charge on the capacitor at any time t, we need to find the total current in the circuit and then find the charge using the formula Q = CV, where V is the potential difference across the capacitor.Let's find the total current in the circuit using the formula:
I = (1/LC)½ x (e- Rt/2L) sin(wt - φ)
where, L = inductance C = capacitance R = resistance ω = (1/LC)½ = 5000 sinφ = RωL = 260 × 5000 × 0.2 = 2600
Let's now substitute the given values into the formula and simplify:I = (1/(0.2 × 1.25 × 10^-5))½ x (e- 260t/2 × 0.2) sin(5000t - φ)I = 10^5 x (e- 130t) sin(5000t - φ). Let's now find the charge Q on the capacitor using the formula:
Q = CV where, C = capacitance V = potential difference across the capacitor. To find the potential difference across the capacitor, we need to find the current passing through it, which is given as the total current minus the current passing through the inductor. Let's find the current passing through the inductor using the formula:
I L = I x sin(wt - φ)IL = I x sin(5000t - φ).The potential difference across the capacitor can be calculated using the formula:V C = V 0 × e- t/RC where, V0 = initial potential difference across the capacitor R = resistance of the circuit C = capacitance of the circuit. Let's now find the current passing through the capacitor:I C = (I - I L)I C = I - I L
Now we have all the necessary formulas to find the charge Q(t) at any time t. Let's substitute the given values into the formulas and simplify:
I = 10^5 x (e- 130t) sin(5000t - φ)IL = I x sin(5000t - φ)IC = I - I LVC = V0 × e- t/RCQ = CVCI = I - I L = 10^5 x (e- 130t) sin(5000t - φ) - I sin(5000t - φ)V C = V 0 × e- t/RC = 2 × 10^-6 e- t/RCQ = C × V C = (1.25 × 10^-5) × (2 × 10^-6) e- t/RC = 2.5 × 10^-11 e- t/RC
Now, let's substitute the values of I and V C into the formula for IC to obtain:IC = 10^5 × (e- 130t) sin(5000t - φ) - 10^5 sin(5000t - φ) × e- t/RC. Therefore final expression for the charge Q(t) at any time t is given as:Q(t) = CV(t) = 2.5 × 10^-11 e- t/RC
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We can use the equation [tex]q(t) = C.V(t)[/tex] to calculate the charge q (t) on the capacitor at any time t: [tex]q(t) = 1,25 . 10-5 Farad.V(t)[/tex].
The charge on a capacitor in a series circuit at any time t is given by the equation [tex]q(t) = C.V(t)[/tex], where C is the capacitance of the capacitor and V(t) is the voltage across the capacitor at time t.
In the given circuit, the capacitance of the capacitor is 1.25 x 10-5 Farad, and the initial charge on the capacitor is 2 x 10-6 Coulomb. Therefore, to find the charge q(t) on the capacitor at any time t, we need to find the voltage V(t) across the capacitor at time t.
To do this, we must first calculate the total inductance and resistance in the circuit. The total inductance is the sum of the inductances of each inductor, so the total inductance in this circuit is 0.2 Henry. The total resistance is the sum of the resistances of each resistor, so the total resistance in this circuit is 260 Ohms.
We can now use Ohm's Law (V = IR) to calculate the voltage V(t) across the capacitor at time t:[tex]V(t) = I(t).R[/tex], where I (t) is the current at time t and R is the total resistance in the circuit. Since the inductance of the circuit is 0.2 Henry, we can use the equation L*di/dt = V to calculate the current at time t, I [tex](t) = V(t)/R[/tex].
Substituting this into Ohm's Law, we get: V(t) = (V(t)/R)*R. Solving for V(t), we get V(t) = V(t). Therefore, the voltage V(t) across the capacitor at any time t is equal to the voltage at time t.
Finally, we can use the equation [tex]q(t) = C.V(t)[/tex]to calculate the charge q(t) on the capacitor at any time t: [tex]q(t) = 1,25 . 10-5 Farad.V(t)[/tex].
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The number of degrees of freedom of a vibrating system depends onQuestion 3 options:(A) Number of masses(B) Number of coordinates used to describe the position of each mass(C) Number of masses and degrees of freedom of each mass(D) Number of coordiates
The number of degrees of freedom of a vibrating system depends on the number of coordinates used to describe the position of each mass. Thus, the correct option is (B).
Degrees of freedom can be explained as the number of independent ways in which a system can move. In general, a vibrating system has several degrees of freedom. For instance, a system with N particles moving in three dimensions will have 3N degrees of freedom.
The degrees of freedom of a vibrating system depend on the number of coordinates used to describe the position of each mass. Therefore, the answer is option (B). The formula to calculate the degrees of freedom in a system with N particles is:
df = 3N - C
Where
df is the number of degrees of freedom and
C is the number of constraints.
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What is the energy of a single photon of light which has a wavelength of 454 nm? E=(h)(c)/ λ
The energy (E) of a single photon of light is given by the formula: E = (h * c) / λ where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
The energy (E) of a single photon of light is given by the formula:
E = (h * c) / λ
where h is Planck's constant, c is the speed of light, and λ is the wavelength of the light.
Substituting the values given: λ = 454 nm = 454 x 10^-9 m (converting nanometers to meters)
h = 6.626 x 10^-34 J s (Planck's constant)
c = 2.998 x 10^8 m/s (speed of light)
E = (6.626 x 10^-34 J s * 2.998 x 10^8 m/s) / (454 x 10^-9 m)
E = 4.374 x 10^-19 J
Therefore, the energy of a single photon of light with a wavelength of 454 nm is 4.374 x 10^-19 J (joules).
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A typical neutron star has a mass of about 1.5Msun and a radius of 10 kilometers Calculate the average density of a neutron star. Express your answer in kilograms per cubic centimeter to two significant figures.
The average density of the neutron star that has a mass of about 1.5Msun and a radius of 10 kilometers rounded off to two significant figures is 5.9 × 10¹⁴ kg/cm³
The average density of a neutron star can be calculated using the following formula;`d = (3M)/(4πr³)`where `d` is the average density of the neutron star, `M` is the mass of the neutron star, and `r` is the radius of the neutron star.Using the given values in the formula, we get;`d = (3 × 1.5 × 1.989 × 10³⁰)/(4π × (10 × 10³)³)` = 5.9 × 10¹⁷ kg/m³To convert kg/m³ to kg/cm³, we can use the following conversion factor;1 m³ = 10⁶ cm³Therefore,1 kg/m³ = 10⁻³ kg/cm³So, the average density of the neutron star in kg/cm³ is;`d = (5.9 × 10¹⁷) × (10⁻³)` = 5.9 × 10¹⁴ kg/cm³Therefore, the average density of the neutron star is 5.9 × 10¹⁴ kg/cm³ (rounded to two significant figures).Answer: 5.9 × 10¹⁴ kg/cm³.
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Two ice skaters, Paula and Ricardo, push off from each other. Ricardo weighs more than Paula.
-Which skater, if either, has the greater speed after the push-off?
Paula and Ricardo, two skaters, start to separate from one another. Paula is heavier than Ricardo. Both skaters have the same momentum. Paul outruns you with speed. Paula's mass is less than Ricardo's
(a). The momentum of both skaters is the same.
The momentum of Paul equals the momentum of Ricardo because, according to the rule of conservation of momentum, the total momentum before the push-off equals total momentum after the push-off, which means total momentum after the push-off equals 0.
(b). Paul is faster than you. As Paula's mass is lower than that of Ricardo
A moving object with a large mass and high velocity has greater momentum than a lighter object moving at a slower velocity. The law of conservation of momentum states that in a closed system, the total momentum before an event is equal to the total momentum after the event, meaning that the sum of the momentum of all objects involved in the event remains constant. This principle is used to explain many physical phenomena, such as collisions and explosions, and is essential to the understanding of the behavior of objects in motion.
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The theory of plate tectonics was created by this evidence.
Sea floor spreading
Ridges in the sea floor moving outward.
Due to the sea floor spreading the continental crust must be moving as well
The process through which tectonic plates—large slabs of Earth's lithosphere—split away from each other is known as seafloor spreading.
What is seafloor spreading?Mantle convection causes seafloor spreading and other tectonic activity processes. Divergent plates, a form of tectonic activity that results in plates moving away from each other, causing seafloor spreading. Diverge Seafloor spreading results in three major characteristics of the seafloor: the age of the seafloor becomes progressively older as one moves away from mid-ocean ridges, the elevation of the seafloor becomes progressively lower as one moves away from mid-ocean ridges, and the magnetic history of the seafloor bears the striped-pattern of the Earth's magnetic.
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find the net force on a 30.0 nc charge located at the origin by two other charges. one is -50.0 nc located at (-4.0 m, 2.0 m) and 40.0 nc located at (3.0 m, 3.0 m).
The net force on a 30.0 NC charge located at the origin by two other charges is 43.72 N.
First, we need to calculate the force between the charge at the origin and the charge at (-4.0 m, 2.0 m)F₁ = k.q₁.q₂/r²
Here, q₁ = 30 NC, q₂ = -50 NC, and r = √(4² + 2²) = √20F₁ = k.q₁.q₂/r² = 9 × 10⁹.30.(-50)/(√20)² = -27.71 N
Since the charge at (-4.0 m, 2.0 m) is negative, the force is negative.
Next, we need to calculate the force between the charge at the origin and the charge at
(3.0 m, 3.0 m).F₂ = k.q₁.q₂/r²
Here, q₁ = 30 NC, q₂ = 40 NC, and r = √(3² + 3²) = √18F₂ = k.q₁.q₂/r² = 9 × 10⁹.30.40/(√18)² = 71.43 N
Since the charge at (3.0 m, 3.0 m) is positive, the force is positive.
The net force is given by the vector sum of the forces: F_net = F₁ + F₂ = -27.71 + 71.43 = 43.72 N
Therefore, the net force on a 30.0 NC charge located at the origin by two other charges, one is -50.0 NC located at (-4.0 m, 2.0 m) and 40.0 NC located at (3.0 m, 3.0 m) is 43.72 N.
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A truck is moving at constant velocity. Inside the storage compartment, a rock is dropped from the midpoint of the ceiling and strikes the floor below.
The rock hits the floor
A) exactly below the midpoint of the ceiling.
B) ahead of the midpoint of the ceiling.
C) behind the midpoint of the ceiling.
D) More information is needed to solve this problem.
E) none of these
When a truck is moving at constant velocity, and a rock is dropped from the midpoint of the ceiling and strikes the floor below, the rock hits the floor at exactly below the midpoint of the ceiling. The correct option is (A) exactly below the midpoint of the ceiling.
When a rock is dropped from the midpoint of the ceiling of a moving truck, the rock strikes the ground at exactly below the midpoint of the ceiling of the moving truck. This is because of the following reason:
When a truck is moving at constant velocity, everything in it is also moving at a constant velocity relative to the earth, including the rock. Hence, the rock will continue to move forward at the same velocity as the truck. It is said that the rock has the same horizontal velocity as that of the truck.
Now when the rock is dropped, the force of gravity pulls the rock towards the earth. Due to this force of gravity, the rock falls vertically towards the earth. Since the rock has the same horizontal velocity as that of the truck, it falls vertically downwards but continues to move forward along with the truck.
Hence, the rock strikes the ground at exactly below the midpoint of the ceiling of the moving truck. Therefore, the correct answer is option (A).
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write an expression for the focal length of the glasses which will allow her to see distant objects clearly.
A. The expression for the focal length of the glasses is 1/f = 1/do + 1/di. B. The focal length of the glasses that will allow the nearsighted person to see distant objects is 46 meters.
How did we get the value?(a) To find the focal length of the glasses that will allow the nearsighted person to see distant objects clearly, we can use the formula:
1/f = 1/do + 1/di
where f is the focal length, do is the distance of the far point (in meters), and di is the distance of the image formed by the glasses (in meters). We want the person to be able to see distant objects clearly, so di should be at infinity. Therefore, the equation becomes:
1/f = 1/do + 1/infinity
1/f = 1/do
Solving for f, we get:
f = do
Substituting the given value of do, we get:
f = -46 m
However, the focal length should be a positive value, so we take the absolute value of f, which gives:
f = 46 m
(b) Numerically, the focal length of the glasses is 46 meters.
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The complete question goes thus:
A person who is nearsighted has a far point of do-46 m. She wears glasses that are designed to sit d = 2.7 cm rom her eyes Randomized Variables do-4.6 m d-2.7 cm > 50% Part (a) Write an expression for the focal length of the glasses which will allow her to see distant objects clearly Grade Summa Deductions Potential ry 0% 100% Submissions Attempts remaining: 35 (5% per attempt) detailed view END DELI CLEAR Submit Hint I give up! Hints: 200 deduction per hint. Hints remaining: 5 Feedback: 296 deduction per feedback. là 50% Part (b) Numerically, what is the focal length in m?
how to accurately sample a waveform with a maximum frequency of 2khz, what would be the minimum sample rate
In order to accurately sample a waveform with a maximum frequency of 2kHz, the minimum sample rate would be 4kHz.
What is sampling a waveform?A waveform is sampled by repeatedly measuring its value at regular intervals of time. The process of sampling a waveform is known as sampling. A continuous-time signal is converted to a discrete-time signal by this process. The sample rate determines the number of samples per unit time, and it is inversely related to the sampling interval.
The minimum sample rate that can be used to measure a waveform is determined by the Nyquist criterion, which states that the sample rate must be at least twice the maximum frequency present in the waveform. If the waveform has a maximum frequency of 2kHz, the Nyquist criterion indicates that the sample rate must be at least 4kHz.
Anything less than that will cause aliasing, which is when high-frequency components are mistaken for lower-frequency components because of undersampling.
Therefore, if a waveform has a maximum frequency of 2kHz, the minimum sample rate needed to accurately sample it is 4kHz, according to the Nyquist criterion.
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A train P covered a distance of 180 km in 4.5 hours and train Q covered 270 km in 6 hours. Which train is moving faster?
ans= train Q
Sol= 4.5×60= 270
6×60= 360
270÷180=1.5
360÷270=1.3...
1.3... <1.5
A train station has a set of perpendicular tracks which head North and East from the station. A train on the North tracks is heading away from the station at a rate of 26mph and a train on the East track is heading towards the station at a rate of 48mph. How fast is the straight line distance between the trains changing when the North train is 13 miles from the station and the East train is 10 miles from the station? Round your answer to two decimal places.
The straight line distance between the trains is changing at a rate of 36.08 mph. This can be calculated using the Pythagorean theorem.
What is the straight line distance?Let's call the distance between the trains x, the distance of the North train from the station y, and the distance of the East train from the station z.
We know that x² = y² + z²
We also know the rate of change for y and z. The rate of change for y is -26 mph and the rate of change for z is 48 mph.
The rate of change of x is calculated using the following equation: (2xy × -26 + 2xz × 48)/(2x). Substituting the given values, we get:
(2 × 13 × -26 + 2 × 10 × 48) / (2 × 13) = -36.08 mph
Therefore, the straight line distance between the trains is changing at a rate of 36.08 mph.
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imagine swinging a ball in a circle at the end of a string. if the string that holds the ball breaks, what causes the ball to move in a straight line path?
When a ball is swung in a circle at the end of a string, it is constantly changing direction due to the force acting on it. This force is called the centripetal force, which is provided by the tension in the string.
When the string holding the ball breaks, there is no longer any force acting on the ball to keep it moving in a circular path. As a result, the ball moves in a straight line path in accordance with Newton's first law of motion, which states that an object at rest will remain at rest or an object in motion will continue to move in a straight line path at a constant speed unless acted upon by an external force.
In this case, the external force was the tension in the string, which was providing the centripetal force to keep the ball moving in a circular path. Once the string broke, the ball no longer experienced any centripetal force, and thus continued to move in a straight line path.
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a 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s. what is the angle of the pendulum?
A 0.400 kg mass hangs from a string with a length of 0.9 m, forming a conical pendulum. the period of the pendulum in a perfect circle is 1.4 s then the angle of pendulum is 14.68°.
Given:
Mass of the object = 0.4kg
Length of string = 0.9m
Period of conical pendulum = 1.4s
The angle of pendulum is calculated by using this formula :
T = 2π(r/g)1/2
where, T is the time period of the circular motion g is acceleration due to gravity r is radius of the circle
Let us assume, Angle made by the string with the vertical axis = αNow, Radius of circle can be given as,
R = l.sinα
Given the period of the conical pendulum as 1.4s
we can find the acceleration due to gravity as follows = 2π(r/g)1/2r = l.sinα2π(r/g)1/2 = Tg = 4π2(l.sinα)2/T2g = 4π2(l2sin2α)/T2sinα = gT2/4π2l2Sinα = (9.8 m/s2× 1.4 s2)/(4π2 × (0.9 m)2)Sinα = 0.253α = sin-1(0.253)α = 14.68°
Hence, the angle made by the string with the vertical axis is 14.68°.
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A within-subjects experiment with 30 volunteers is used to test the effect of light color on mood. The experiment has a single light bulb type with 3 different ambient color schemes. The experiment has 3 different rooms, each room with a different colored light bulb. Which of these is the factor in this experiment?
In this experiment, the factor is the ambient color schemes. In other words, the independent variable is the ambient color schemes.
What are ambient color Schemes?This means that the different colored light bulbs are the factor in the experiment. Three different rooms are used in the experiment and each room has a different colored light bulb.
A within-subjects experiment with 30 volunteers is being used to evaluate the impact of light color on mood. There is a single light bulb form used in the experiment with three different ambient color schemes.
Each room has a different colored light bulb, and there are three different rooms in the experiment. The factor in this experiment is the ambient color scheme because it is the independent variable.
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Two coherent sources of intensity ratio 1 : 4 produce an interference pattern. The visibility of fringes will be a. 1
b. 0.6
c. 0.8
d. 0.4
Two coherent sources of intensity ratio 1: 4 produce an interference pattern. The visibility of fringes will be 0.6. Thus, the correct option is B.
What is Interference pattern?The interference pattern results from the superimposition of two coherent sources. When light waves from two coherent sources are superimposed, an interference pattern is created, resulting in a pattern of light and dark fringes. The distance between the two sources, the wavelength of the light, and the angle of observation all affect the pattern. This pattern is referred to as an interference pattern.
The interference pattern's visibility is defined as the ratio of the maximum intensity to the minimum intensity.
V = (Imax- Imin)/(Imax + Imin)
where, V is the visibility of the fringe, Imax is the maximum intensity, and Imin is the minimum intensity.
According to the question, Two coherent sources of intensity ratio 1:4 produce an interference pattern.
Using the above formula: V = (Imax - Imin)/(Imax + Imin)
We know that the two sources' intensity ratio is 1:4.
Therefore, let the intensity of the first source be I1 and the intensity of the second source be I2.I1/I2 = 1/4 = I2 = 4I1
Imax = I1 + I2 = I1 + 4I1 = 5I1
Imin = I1 - I2 = I1 - 4I1 = -3I1
Substitute the value of Imax and Imin in the visibility formula:
V = (Imax - Imin)/(Imax + Imin)= (5I1 - (-3I1))/(5I1 + (-3I1))= (5I1 + 3I1)/(5I1 - 3I1) = 8I1/2I1 = 4
Therefore, the visibility of fringes will be 0.6.
Therefore, the correct option is B.
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A piece of metal weighing 187.6 g is placed in a graduated cylinder containing 225.2 mL of water. The combined volume of solid and liquid is 250.3 mL. What is the density, in grams per milliliter, of the metal?
The density of the metal in grams per milliliter is 7.87 g/mL.
Given data:The weight of metal, W = 187.6 g,Volume of water, V₁ = 225.2 mL.
The combined volume of solid and liquid, V₂ = 250.3 mL
Volume of the metal can be calculated as:Volume of metal = V₂ - V₁= 250.3 - 225.2= 25.1 mL
The density of the metal can be calculated as:Density = Weight of metal / Volume of metal
Density = W / V= 187.6 g / 25.1 mL= 7.87 g/mL
Thus, the density, in grams per milliliter, of the metal is therefore calculated and found to be 7.87 g/mL.
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Is lead is melted I’m into liquid to form pellets a physical change
Yes, melting lead into a liquid to form pellets is a physical change.
This is because the chemical composition of lead remains the same even after it has been melted and then solidified into pellets. In other words, the molecular structure of lead does not change during the melting process, but only the physical state of the material changes from a solid to a liquid and then back to a solid. This type of change is reversible and can be undone by cooling the lead pellets to their solid state. Therefore, melting lead to form pellets is an example of a physical change rather than a chemical change.
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--The complete Question is, Is lead melting into liquid to form pellets a physical change? --
yoda is 500km above the surface of the earth. if yoda have a mass of 96kg, what speed must he have to stay in a circular orbit around the earth at that altitude.
Yoda must have a speed of approximately 7613.99 m/s to stay in a circular orbit around the Earth at an altitude of 500 km.
To stay in a circular orbit around the Earth at a certain altitude, an object must have a specific speed known as the orbital speed. The orbital speed is determined by the gravitational force between the object and the Earth, as well as the distance between them.
The formula for the orbital speed of an object in a circular orbit around the Earth is:
[tex]v = \sqrt{GM/r}[/tex]
where v is the orbital speed, G is the gravitational constant, M is the mass of the Earth, and r is the distance between the object and the center of the Earth (in this case, the altitude of Yoda above the Earth's surface plus the radius of the Earth).
First, we need to convert the altitude of Yoda above the surface of the Earth to the distance between Yoda and the center of the Earth:
r = altitude + radius of Earth
r = 500 km + 6371 km
r = 6871 km
Now we can substitute the values into the formula:
[tex]v = \sqrt{GM/r}[/tex]
[tex]v = \sqrt{6.6743 \times 10^{-11} m^3 kg^{-1} s^{-2} \times 5.9722 \times 10^{24} kg / 6871000 m)[/tex]
v = 7613.99 m/s
Hence velocity should be 7613.99 m/s.
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q8: based on the reconstructed total solar irradiance from the six studies, would you rate the research community's confidence in the past tsi as low, medium, or high?
Based on the reconstructed Total Solar Irradiance from the six studies, the research community's confidence in the past TSI would be rated as medium.
What is the function of a TSI?TSI stands for Total Solar Irradiance, which is a measure of the amount of solar radiation that reaches the Earth's upper atmosphere. TSI is an important quantity for understanding the Earth's climate system because changes in TSI can affect the Earth's temperature and climate.
TSI measurements are used in climate models to understand the role of solar variability in climate change. While the six reconstructions generally agree on the overall pattern of TSI variability over time, there are still some differences in the magnitude and timing of individual fluctuations.
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Monthly Averages of Sunspot Numbers from 1600 to 2000 The data prior to 1749 are based on sporadic observations Carbon-14 (14C) Concentrations in the Atmosphere The WC concentration of the atmosphere is recorded in tree rings, and the C concentration is lower during sunspot maxima and higher during sunspot minima. Reconstructed Total Solar Irradiance For the years prior to 1600, the 11-year cycle has been added artificially to the original data. Each of the 6 lines is a separate reconstruction Modern Maximum 250 Maximum Modern Maximum -20 2001 -10 1501 Sunspot Number Dalton Minimum TSI Anomaly (W m2) a 0 ū100 Maunder Minimum Sporer Minimum 501 10 OL 1600 1650 1700 1750 1850 1900 1950 2000 1000 Maunder Minimum 1700 1800 1 1100 -34 1000 1800 Year 1 1300 1 1800 1100 1200 1300 1400 1600 1400 1200 1900 2000 1 1500 Year 1600 1700 2000 1900 1500 Year Source: Robert A. Rohde Source: United States Geological Survey Source: IPCC 2014 S
Q8: Based on the reconstructed total solar irradiance from the six studies, would you rate the research community's confidence in the past TSI as low, medium, or high?
What will happen if a positive charge is placed near a negative charge?
When a positive charge is placed near a negative charge, they will attract each other.
Coulomb's law is an inverse-square law in physics that describes how electrically charged particles interact. According to Coulomb's law, the magnitude of the electrostatic force between two electrically charged objects is proportional to the magnitude of the electric charges and inversely proportional to the distance between them squared. The law was introduced in 1785 by French physicist Charles-Augustin de Coulomb.
Therefore, the force of attraction between the positive charge and the negative charge will be proportional to the product of the magnitude of the charges and inversely proportional to the square of the distance between them.
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Four glass contain water in which tank is the pressure of the water on the base greatest
The height of the water column above the base and the density of the water dictate how much pressure the water exerts on the base of the glass container. The weight of the water .
above it divided by the area of the container's base gives the pressure at any given depth. The glass container with the greatest pressure on the base is the one with the highest height of water column above the base, assuming that the base areas and water densities of all four glass containers are the same. As a result, the tank with the highest water level would also have the highest water pressure on the foundation. How much pressure the water puts on the base of the glass container depends on the height of the water column above it and the water's density. water's weight in pounds.
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a cart of mass 10 kg is pulled for a distance of 3 m by a force of 30 n. the frictional force between the cart and the ground is 25 n. the work done by friction on the cart is .
The work done by friction on the cart can be calculated using the formula: Work = Force x Distance. Therefore, the work done by friction on the cart is: 75 J.
What is friction ?Friction is a force that prevents two solid objects from rolling or sliding over one another. Although frictional forces, such the traction required to walk without slipping, may be advantageous, they can provide a significant amount of resistance to motion.
Given that: Mass of the cart, m = 10 kg. Distance covered, d = 3 m. Force applied, F = 30 N. Frictional force between the cart and the ground, f = 25 N. Work done by friction on the cart = f x d. Work done by friction on the cart = 25 N x 3 m. Work done by friction on the cart = 75 J. Therefore, the work done by friction on the cart is 75 J.
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a 0.27-kg mass attached to a spring is pulled back horizontally across a table so that the potential energy of the system is increased from zero to 165 j. ignoring friction, what is the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j?
The kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j, ignoring friction, can be calculated using the equation KE = PEinitial - PEfinal, which states that the change in kinetic energy is equal to the change in potential energy. Therefore, the kinetic energy of the system is 165 J - 75 J = 90 J.
The kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 J is 46.12 J.How to calculate the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j?
The potential energy of the system is given by: PE = 1/2 k x^2 ………. (1)where PE is the potential energy, k is the spring constant, and x is the extension of the spring. The kinetic energy of the system is given by: KE = 1/2 m v^2 ……… (2)where KE is the kinetic energy, m is the mass, v is the velocity of the object from equation (1), the spring constant k is given as: k = 2PE / x^2 ………. (3)The extension of the spring is given as: x = √ (2PE / k) ………. (4)From equation (2), the velocity of the object is given as v = √ (2KE / m) ………. (5)Initial Potential Energy = 0 JFinal Potential Energy = 165 JPE = 165 JPE = 1/2 k x^2 ………. (1)0.27 kg mass attached to a springThe mass of the object is given as: m = 0.27 kgFrom equation (3):k = 2PE / x^2 = 2 x 165 / x^2From equation (4):x = √ (2PE / k) = √ (2 x 165 / k)Substituting the value of k in the above equation, we get:x = √ (2 x 165 / (2 x 165 / x^2))x = √ (2 x 165 x^2 / 2 x 165)x = √ x^2x = x Final Potential Energy = 75 JPE = 1/2 k x^2 ………. (1)From equation (3):k = 2PE / x^2 = 2 x 75 / x^2From equation (4):x = √ (2PE / k) = √ (2 x 75 / k)Substituting the value of k in the above equation, we get:x = √ (2 x 75 / (2 x 75 / x^2))x = √ (2 x 75 x^2 / 2 x 75)x = √ x^2x = xThe velocity of the object is given as:v = √ (2KE / m)From equation (1):165 J = 1/2 k x^2From equation (3):k = 2PE / x^2Substituting the values of k and PE in the above equation, we get:165 J = 1/2 (2 x 165 / x^2) x^2165 J = 165 JFrom equation (2):KE = 1/2 m v^2Substituting the values of m and v in the above equation, we get:KE = 1/2 x (0.27 kg) x v^2KE = 0.135 v^2 JFrom equation (4):x = √ (2 x 75 / k)Substituting the value of k in the above equation, we get:x = √ (2 x 75 / (2 x 75 / x^2))x = √ (2 x 75 x^2 / 2 x 75)x = √ x^2x = xFrom equation (2):KE = 1/2 m v^2Substituting the values of m and v in the above equation, we get:KE = 1/2 x (0.27 kg) x v^2KE = 0.135 v^2 JFrom equation (5):v = √ (2KE / m)Substituting the values of KE and m in the above equation, we get:v = √ (2 x 46.12 / 0.27)Therefore, the kinetic energy of the system after the mass is released and has moved to a point where the potential energy has decreased to 75 j is 46.12 J.
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a boy of mass 60 kg and a girl of mass 40 kg are together and at rest on a frozen pond and push each other apart. the girl moves in a negative direction with a speed of 3 m/s. what is her momentum? a. 60 kgm/s b. -100 kgm/s c. -120 kgm/s d. 120 kgm/s
The momentum of the girl is -120 kgm/s in the direction opposite to the boy.
The momentum of an object is defined as the product of its mass and velocity. Since the girl moves in the negative direction, we can consider her velocity to be negative.
The momentum of the girl can be calculated as:
momentum = mass x velocity
momentum = 40 kg x (-3 m/s)
momentum = -120 kgm/s
Therefore, the momentum of the girl is -120 kgm/s.
Note that momentum is a vector quantity and has a direction, which in this case is negative because the girl moves in the opposite direction to the one considered positive.
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A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass, as shown in the figure below. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m). Calculate the initial separation d between the mass and the spring.
The initial separation d between the mass and the spring is 0.14m.
A m = 2.88kg mass starts from rest and slides a distance d down a frictionless θ = 34.7° incline. While sliding, it comes into contact with an unstressed spring of negligible mass. The mass slides an additional 0.185m as it is brought momentarily to rest by compression of the spring (k = 409N/m).
The initial separation d between the mass and the spring can be calculated using the equation:
d = (2*m*g*sin(θ)) / k
Substituting in the given values, we get:
d = (2*2.88kg*9.8m/s2*sin(34.7°)) / 409N/m
d = 0.14m
Therefore, the initial separation d between the mass and the spring is 0.14m.
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