A 75.0-kg athlete performs a single-hand handstand. If the area of the hand in contact with the floor is 125 cm2, what pressure is exerted on the floor

Answer:

It's B (electrical force and magnetic force) I just took the test.

The two forces can Danielle's device produce will be an electrical force and magnetic force. Daniel forms a coil resulting in both forces.

Electric Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force. it is the ratio of voltage to the distance between them.

Danielle took an iron nail and wrapped thin copper wire around it, then connected the ends of the copper wire to a battery.

A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire. Which generates a magnetic field when an electric current is passed through the coil.

A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.

The two forces can Danielle's device produce will be an electrical force and magnetic force. Daniel forms a coil resulting in both forces.

Hence option B is correct.

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Answer:

Explanation:

Gravity

Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.

Answer:

3.5 KJ

Explanation:

Energy balance equation is given as;

E_in - E_out = ΔE_system

Thus;

Q_in = (m_2•u_2) - (m_i•h_i)

Now, m_i = m_2

Tbus;

Q_in = (m_2•u_2) - (m_2•h_i)

Q_in = m_2(u_2 - h_i)

Now mass of the air in the bottle is given as;

m_2 = (P_2•V)/(R•T2)

From table A-1 attached, R = 0.287 KJ/Kg.k

We are given;

P_2 = 100 kPa

V = 35 L = 0.035 m³

T2 = 22°C = 22 + 273 K = 295 K

Thus;

m_2 = (100 × 0.035)/(0.287 × 295)

m_2 = 0.04134 kg

Now, from table A-17 attached, at Temperature of 295 K, we have;

Internal energy; u2 = 210.49 KJ/Kg

Enthalpy; h_i = 295.17 KJ/Kg

From earlier, we saw that;

Q_in = m_2(u_2 - h_i)

Thus;

Q_in = 0.04134(210.49 - 295.17)

Q_in = -3.5 KJ

Thus, Q_out = 3.5 KJ

So, the net heat transfer = 3.5 KJ

As the skater descends his kinetic energy increases and his potential energy decreases. The total energy remains constant.

Energy is the ability to do work. Types of energy are potential, kinetic, thermal and so on.

Potential energy is the energy stored in an object due to its position relative to another object. Kinetic energy is the energy due to the motion of an object.

As the skater descends his kinetic energy increases and his potential energy decreases. The total energy remains constant.

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Have you seen my dad?

Answer:

No :)

Explanation:

Given that,

Initial speed, u = 20 km/s

Acceleration of plane, a = 2.4 km/h²

Time, t = 59 s

We need to find the expression to find the final velocity of an object.Let the final velocity is v.

Using the second equation of kinematics:

[tex]\Delta s=ut+\dfrac{1}{2}at^2[/tex]

a is acceleration, [tex]a=\dfrac{v-u}{t}[/tex]

So,

[tex]\Delta s=ut+\dfrac{1}{2}\times \dfrac{v-u}{t}\times t^2\\\\\Delta s=ut+\dfrac{1}{2}(v-u)t\\\\\Delta s=\dfrac{2ut+vt-ut}{2}\\\\\Delta s=\dfrac{vt+ut}{2}\\\\\Delta s=(\dfrac{v-u}{2})t[/tex]

We can use the above formula to find the final velocity (v) of the plane.

the amount of work that the student needs to do in order to climb the stairs is 3185 J

Work can be defined as the product of force and distance.

To calculate the amount of work that the student needs to do in order to climb the stairs, we use the formula below

Formula:

Where:

From the question,

given:

Substitute these values into equation 1

Hence, the amount of work that the student needs to do in order to climb the stairs is 3185 J.

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The net force on the car for either case will be zero, since the car is moving at a constant velocity.

The net force on the car is the sum of all the forces acting on the car.

∑F = ma

When the car is on a level road, the only two forces acting on the car is the applied force and frictional force of the road.

F - Ff = 0

The net force will be zero, since the car is moving at a constant velocity.

The forces acting on the car at the uphill is the applied force, weight of the car acting downwards and the frictional force acting opposite direction.

F - Wsinθ - μFₙcosθ = 0

The net force will be zero, since the car is moving at a constant velocity.

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Hi there!

Recall the following.

Capacitors in series:
[tex]C_T = \frac{1}{C_1} + \frac{1}{C_2} +...+ \frac{1}{C_n}[/tex]

Capacitors in parallel:

[tex]C_T = C_1 + C_2 + ... + C_n[/tex]

Begin by solving for the resulting capacitance of both paths.

Path on the left:
[tex]\frac{1}{C_T} = \frac{1}{2C} + \frac{1}{C} = \frac{3}{2C}\\C_T = \frac{2C}{3}[/tex]

Path on the right:
[tex]\frac{1}{C_T} = \frac{1}{C} + \frac{1}{3C} = \frac{4}{3C}\\\\C_T = \frac{3C}{4}[/tex]

Now, since we ADD capacitors in parallel, we can add the resulting capacitances together:
[tex]C_T = \frac{2C}{3} + \frac{3C}{4}[/tex]

Substitute in 12 F for C and solve.

[tex]C_T = \frac{2(12)}{3} + \frac{3(12)}{4} = \frac{24}{3} + \frac{36}{4} = 8 + 9 = \boxed{17F}[/tex]

Answer:

{2,4,6,8,10,12}

Explanation:

Even Numbers

Any number that can be exactly divided by 2 is called an even number.

The even numbers between 3 and 13, written in set notation, are:

{2,4,6,8,10,12}

Answer:

4, 6, 8 , 10, 12

Explanation:

List the even numbers between 3 and 13 in set

notation

[4, 6, 8 , 10, 12]

thanks

The distance of the canoeist from the dock is equal to length of the canoe, L.

The principle of conservation of linear momentum states that the total momentum of an isolated system is always conserved.

v(m₁ + m₂) = m₁v₁ + m₂v₂

where;

v is the velocity of the canoeist and the canoe when they are together

The distance traveled by the canoeist from the back of the canoe to the front of the canoe is equal to the length of the canoe.

Thus, the distance of the canoeist from the dock is equal to length of the canoe, L.

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Answer:

23.4 cm

Explanation:

15 : 50 = x : 78

15*78 = 50x

x = 15*78/50 = 23.4 cm

The spring stretch is, 23.4 cm.

According to the question:

15 : 50 = x : 78.

15×78 = 50x.

x = 15×78/50.

  = 23.4 cm.

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Answer:

yes

Explanation:

yes to my best known knowledge I am thinking that your answer is correct

Answer:

nothing lol

Explanation:

nothing changes in a physical change, particles stay the same unless a chemical change happens

Answer:

Explanation:

Mica dielectric constant (k) is approximately 3. The distance between the plates is 5 mm = [tex]5\times10^{-3}[/tex] m = d and the area of each plate is[tex]A = 0.1\times 0.2=2\times 10^{-2} m^{2}[/tex]. So, the capacitance of that capacitor is:

[tex]C=\frac{\epsilon_{0}kA}{d}=\frac{(8.85\times10^{-12})(3)(2\times10^{-2}}{5\times10^{-3}}=10.62\times10^{-11} =1.062\times10^{-10} F[/tex]

or approximately 0.106 nF.

Answer:

3.34x10*5

Explanation:

this is just a example.

take 3 sig.fig

The resistive force from load of the kettle lifted by the arm is determined from principle of moment and the magnitude is 71 kg.

The moment of force about a point is the product of applied force and the perpendicular distance of the force action. The moment of force about a point is equal to the torque exerted by the force.

τ = Fr

where;

F₁r₁ = F₂r₂

925(22.86) = F₂(30.38)

696 N = F₂

in kg, m = 696/9.8 = 71 kg

Thus, the resistive force from the applied force and distance is 71 kg.

The complete question is below:

If she wants the elbow flexors to exert 925 N of force during an isometric contraction, what should the resistance force be at 90 deg of flexion (the upper arm is vertical and the forearm is parallel to the ground) in kg

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Answer:

0.21 SECONDS

Explanation:

THE CAR TRAVELS AT A SPEED OF 140M/S AND A DISTANCE AS THE PREVIOUS = 3M THEREFOR S=D/T, T=D/S= 3/140= 0.12 SEC

Answer:

pls first attach the fig.

The graph in the figure shows the position of a particle as it travels along the x-axis. The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s. Therefore, option B is correct.

The term average speed is defined as the total distance traveled by the object in a particular time interval.

In the kinematics studies the movement of bodies, give the relationships between position, velocity and acceleration. In the special case that the acceleration is zero the motion is known as uniform motion.

       v = Δ x / Δt

Where v is the velocity, Δx is the position variation and Δt is the time variation in the analyzed interval.

Therefore,

v =  2.0 - ( - 2.0 ) / 4.0 - 1.0

v = 1.33 m / s          

Thus, The magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s is 1.3 m / s, option B is correct.

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Your question is incomplete, most probably your question was

The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of the average speed of the particle between t = 1.0 s and t = 4.0 s?

Please help!! The graph in the figure shows the position - 1, Graph is attache below in image.

Answer:

true

Explanation:

look it up

hope this helped u ;)

Answer:

True

Explanation:

Took The Test

Answer:

A team of scientists in Geneva, headed by Professor of Physics Carlo Rubbia, has found evidence of a sixth kind of quark, one of the most sought after discoveries in modern physics. ... Rubbia developed this particular proton collision method and has been working with it since the late 1970s

Answer:

Am doing well am fine thank you

[tex]\longrightarrow \sf Indigo [/tex]

The color and their corresponding wavelength ranges are given in the table below.

[tex]\begin{gathered}\begin{gathered}\boxed{\begin{array}{c|c} \bf colour & \bf wavelength\\ \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf red & \sf 650 - 700 \\ \\ \sf orange & \sf 600 - 650 \\ \\ \sf yellow & \sf \: 580 - 600 \\ \\ \sf green & \sf 550 - 580 \\ \\ \sf cyan & \sf 500 -550 \\ \\ \sf \: blue& \sf450 - 500\\ \\ \sf indigo & \sf 425- 450\\ \\ \sf violet & \sf 380 - 425 \end{array}} \\ \end{gathered}\end{gathered}[/tex]

After observing the table, we can predict that wave is most likely appear Indigo.

Note- The wavelengths boundaries between the colours are not very sharp and they form a continuous spectrum.

Answer:

Wavelength = 6m

Explanation:

Given that,

→ Transverse wave = 15 m/s

→ Frequency = 2.5 Hz

Then the required wavelength is,

→ Transverse wave ÷ Frequency

→ 15 ÷ 2.5

→ 15/2.5 = 6m

Hence, the wavelength is 6m.

Answer:d

Explanation:

Answer:

D

Explanation:

Furthermore, the magnetic pole near earth's geographic north pole is actually the south magnetic pole. When it comes to magnets, opposites attract. This fact means that the north end of a magnet in a compass is attracted to the south magnetic pole, which lies close to the geographic north pole.

Answer:

a pandemic?

Explanation:

i dont know if there is like a A answer and it can kill lot of people

Explanation:

10 ......

.....

.....

.....

.....

Answer:

Forces of attraction between a liquid and a solid surface are called adhesive forces. ... Water wets glass and spreads out on it because the adhesive forces between the liquid and the glass are stronger than the cohesive forces within the water.

Answer:

a

   [tex]a =  12.32 \  m/s^2[/tex]

b

 [tex]F = 1017.52 \  N[/tex]

Explanation:

From the question we are told that

  The  length of the Chinook salmon is  [tex]l =  1.50 \  m[/tex]

   The mass of the Chinook salmon is [tex]m  =  46.0 \ kg[/tex]

   The  upward velocity in water is  [tex]u =  3.00 \ m/s[/tex]

    The  upward velocity in air is [tex]v =  5.80 \ m/s[/tex]

Generally from kinematic equations

     [tex]v^2  =  u^2 +  2as[/tex]

=>    [tex] 5.80^2  =  3.00^2 +  2  *  a *  [ [\frac{2}{3} * l ][/tex]

=>   [tex] 5.80^2  =  3.00^2 +  2  *  a *  [ [\frac{2}{3} * 1.5 ][/tex]

=>   [tex] 5.80^2  =  3.00^2 +  2  *  a *  [1 ][/tex]      

=>    [tex]a =  12.32 \  m/s^2[/tex]

Generally magnitude of the force F during this interval in N  is mathematically represented as

      [tex]F  =  m (a + g )[/tex]

=>    [tex]F  =  46.0 (12.32 + 9.8 )[/tex]

=>    [tex]F = 1017.52 \  N[/tex]