∠A and \angle B∠B are vertical angles. If m\angle A=(3x-21)^{\circ}∠A=(3x−21) ∘ and m\angle B=(2x-13)^{\circ}∠B=(2x−13) ∘ , then find the value of x

Answer:

A. Line of reflection is a perpendicular bisector

B. 90 degree angles, equal lines

C. Pre-image an image are on the same circle.

Step-by-step explanation:

I hope this helped you in any way possible. :)

Answer:

well if a is 12 it means that would become 144/12. simplified to a whole number is 12. so 12-2.4 would = 9.6

Step-by-step explanation:

Answer:

9.6

[tex]12^{2}[/tex]/12 cancels out

12-2.4=9.6

Responder:

$ 288750

Explicación paso a paso:

Dados los ingresos mensuales de los pesos chinos expresados ​​como;

I (x) = 20.000x - 50x² donde;

x es el número de relojes reparados.

Para calcular los ingresos obtenidos si se reparan 15 relojes, simplemente sustituiremos x = 15 en la ecuación modelada como se muestra;

Yo (15) = 20.000 (15) - 50 (15) ²

Yo (15) = 300 000-50 (225)

Yo (15) = 300.000-11250

I (15) = $ 288,750

Answer:

a = 9 + b - c → D

Step-by-step explanation:

To cancel the square root of one side of an equation square the two sides

Examples:

If [tex]\sqrt{x}[/tex] = 5, to find x square the two sides to cancel the square root

([tex]\sqrt{x}[/tex] )² = (5)², then x = 25

If [tex]\sqrt{a+b}[/tex] = 7, to find a + b square the two sides to cancel the square root

([tex]\sqrt{a+b}[/tex] )² = (7)², then a + b = 49

Now let us solve the question

To solve it for a square the two sides then keep a on the left side and move b, c to the other side

∵ [tex]\sqrt{a-b+c}[/tex] = 3

→ Square the two sides to cancel the square root

∴ ([tex]\sqrt{a-b+c}[/tex])² = (3)²

∴ a - b + c = 9

→ Add b to both sides to move b from the left side to the right side

∴ a - b + b + c = 9 + b

∴ a + c = 9 + b

→ Subtract c from both sides to move c from the left side to the right side

∴ a + c - c = 9 + b - c

∴ a = 9 + b - c

Answer:

(2d +3d) + 3-12 equals to 5d - 9

Step-by-step explanation:

you try collecting like terms

Answer:

[tex]5d-9[/tex]

Step-by-step explanation:

Given the following question:

[tex](2d + 3) + (3d-12)[/tex]

To find the answer remove the parentheses, group like terms, and solve by using inverse of operations.

[tex](2d + 3) + (3d-12)[/tex]
[tex]2d+3+3d-12[/tex]
[tex]2d+3d+3-12[/tex]
[tex]3-12=-9[/tex]
[tex]2d+3d+-9[/tex]
[tex]2d+3d=5d[/tex]
[tex]5d-9[/tex]

Your answer is "5d - 9."

Hope this helps.

Answer:

-5/2

Step-by-step explanation:

Slope intercept form = y=mx+b

M=Slope

B=y-intercept

Answer:

-5/2 is the slope

Step-by-step explanation:

the form that it is currently in is slope intercept form

( y= mx+b ) m is the is the slope and x is a variable. -5 is the y intercept.

Answer:

4080.01

Step-by-step explanation:

V = 6 A2/3/36 square rooted = 6 × 1532 2/3/36 square rooted = 4080.01042

Answer:

(j-8)years is the answer to the question

Answer: The two numbers are 39 and 41

==================================================

Work Shown:

x = some odd number

x+2 = next odd number

eg: x = 3 and x+2 = 3+2 = 5

Add up those two expressions, set the sum equal to 80, and solve for x

(x) + (x+2) = 80

2x+2 = 80

2(x+1) = 80

x+1 = 80/2

x+1 = 40

x = 40-1

x = 39

----------

Another way to solve is to do this

2x+2 = 80

2x = 80-2

2x = 78

x = 78/2

x = 39

-----------

Either way, the solution is x = 39 which means the next odd number up is x+2 = 39+2 = 41

To check the answer, add up the two values

39+41 = 80

This confirms we have the right answer.

Answer:

320$

Step-by-step explanation:

Since it's 4%
4000 * 0.04 = 160

24 months = 2 years

annually = 1 year

160 * 2 = 320$

Hope this helps!

Answer:

4000*0.04 = 160

24/12=2

160*2 = 320 interste receveid after 24 mounths

4000+320=4320

Step-by-step explanation:

Answer:

x=8.2

Step-by-step explanation:

First, figure out which trig function you are going to use.

In this problem you are dealing with the opposite side to the angle and the hypotenuse, and if you remember SOH CAH TOA, this requires sine.

sin (55) =opposite/hypotenuse

sin (55) =x/10

multiply both sides by 10 to get 10 * sin (55) = x

10 * sin (55) = 8.2

The possible value of x from the inequality 3/5x > 6 is 10; Luke got it right

3/5x > 6

x > 6 ÷ 3/5

x > 6 × 5/3

x > 30/3

x > 10

Generally in mathematics, inequality in mathematics is a statement which shows or describes orders of relationship between two values with regards to greater than, less than or equals to.

Therefore, the student which has a correct response to Mrs. Mueller’s inequality is Luke

Learn more about inequality:

https://brainly.com/question/11234618

Answer:

s=33

r=57

Step-by-step explanation:

12x-3+7x-2+90

19x-5=90

19x=95

x=5

12(5)-3=57

7(5)-2=33

Hey there!

Option answer: C

----------------------------------------------------------------

Answer:

x=9

Step-by-step explanation:

a undefined line is a straight line so the y value does not matter sence it goes through all the y values

Answer:

Step-by-step explanation:

Slope formula is

When Δx = 0 the denominator of the fraction is zero, hence it is undefined

So this is a vertical line

A vertical line passing through the point (9, -5) is x= 9

So the answer is x= 9

Answer:

The first transformation occurs when we add a constant d to the parent function \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​ , giving us a vertical shift d units in the same direction as the sign. For example, if we begin by graphing a parent function, \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​ , we can then graph two vertical shifts alongside it, using \displaystyle d=3d=3: the upward shift, \displaystyle g\left(x\right)={2}^{x}+3g(x)=2

​x

​​ +3 and the downward shift, \displaystyle h\left(x\right)={2}^{x}-3h(x)=2

​x

​​ −3. Both vertical shifts are shown in Figure 5.

Graph of three functions, g(x) = 2^x+3 in blue with an asymptote at y=3, f(x) = 2^x in orange with an asymptote at y=0, and h(x)=2^x-3 with an asymptote at y=-3. Note that each functions’ transformations are described in the text.

Figure 5

Observe the results of shifting \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​  vertically:

The domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞) remains unchanged.

When the function is shifted up 3 units to \displaystyle g\left(x\right)={2}^{x}+3g(x)=2

​x

​​ +3:

The y-intercept shifts up 3 units to \displaystyle \left(0,4\right)(0,4).

The asymptote shifts up 3 units to \displaystyle y=3y=3.

The range becomes \displaystyle \left(3,\infty \right)(3,∞).

When the function is shifted down 3 units to \displaystyle h\left(x\right)={2}^{x}-3h(x)=2

​x

​​ −3:

The y-intercept shifts down 3 units to \displaystyle \left(0,-2\right)(0,−2).

The asymptote also shifts down 3 units to \displaystyle y=-3y=−3.

The range becomes \displaystyle \left(-3,\infty \right)(−3,∞).

Graphing a Horizontal Shift

The next transformation occurs when we add a constant c to the input of the parent function \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​ , giving us a horizontal shift c units in the opposite direction of the sign. For example, if we begin by graphing the parent function \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​ , we can then graph two horizontal shifts alongside it, using \displaystyle c=3c=3: the shift left, \displaystyle g\left(x\right)={2}^{x+3}g(x)=2

​x+3

​​ , and the shift right, \displaystyle h\left(x\right)={2}^{x - 3}h(x)=2

​x−3

​​ . Both horizontal shifts are shown in Figure 6.

Graph of three functions, g(x) = 2^(x+3) in blue, f(x) = 2^x in orange, and h(x)=2^(x-3). Each functions’ asymptotes are at y=0Note that each functions’ transformations are described in the text.

Figure 6

Observe the results of shifting \displaystyle f\left(x\right)={2}^{x}f(x)=2

​x

​​  horizontally:

The domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞), remains unchanged.

The asymptote, \displaystyle y=0y=0, remains unchanged.

The y-intercept shifts such that:

When the function is shifted left 3 units to \displaystyle g\left(x\right)={2}^{x+3}g(x)=2

​x+3

​​ , the y-intercept becomes \displaystyle \left(0,8\right)(0,8). This is because \displaystyle {2}^{x+3}=\left(8\right){2}^{x}2

​x+3

​​ =(8)2

​x

​​ , so the initial value of the function is 8.

When the function is shifted right 3 units to \displaystyle h\left(x\right)={2}^{x - 3}h(x)=2

​x−3

​​ , the y-intercept becomes \displaystyle \left(0,\frac{1}{8}\right)(0,

​8

​

​1

​​ ). Again, see that \displaystyle {2}^{x - 3}=\left(\frac{1}{8}\right){2}^{x}2

​x−3

​​ =(

​8

​

​1

​​ )2

​x

​​ , so the initial value of the function is \displaystyle \frac{1}{8}

​8

​

​1

​​ .

A GENERAL NOTE: SHIFTS OF THE PARENT FUNCTION \DISPLAYSTYLE F\LEFT(X\RIGHT)={B}^{X}F(X)=B

​X

​​

For any constants c and d, the function \displaystyle f\left(x\right)={b}^{x+c}+df(x)=b

​x+c

​​ +d shifts the parent function \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​

vertically d units, in the same direction of the sign of d.

horizontally c units, in the opposite direction of the sign of c.

The y-intercept becomes \displaystyle \left(0,{b}^{c}+d\right)(0,b

​c

​​ +d).

The horizontal asymptote becomes y = d.

The range becomes \displaystyle \left(d,\infty \right)(d,∞).

The domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞), remains unchanged.

HOW TO: GIVEN AN EXPONENTIAL FUNCTION WITH THE FORM \DISPLAYSTYLE F\LEFT(X\RIGHT)={B}^{X+C}+DF(X)=B

​X+C

​​ +D, GRAPH THE TRANSLATION.

Draw the horizontal asymptote y = d.

Identify the shift as \displaystyle \left(-c,d\right)(−c,d). Shift the graph of \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​  left c units if c is positive, and right \displaystyle cc units if c is negative.

Shift the graph of \displaystyle f\left(x\right)={b}^{x}f(x)=b

​x

​​  up d units if d is positive, and down d units if d is negative.

State the domain, \displaystyle \left(-\infty ,\infty \right)(−∞,∞), the range, \displaystyle \left(d,\infty \right)(d,∞), and the horizontal asymptote \displaystyle y=dy=d.

Step-by-step explanation:

Answer:

common fraction is written in the form of two whole numbers, one above the ... For example 3/7 would be 3 divided by 7 = 0.428 571 .

Mr Green: [tex]4(3a+1+2b) = 12a + 4 + 8b[/tex]

Mrs Green: [tex]6(5a-a)+4(2+4b)=6*4a + 8 + 16b = 24a +16b + 8[/tex]

Keith: [tex]4(2+4b+6a) = 8 + 16b + 24a=24a+16b + 8[/tex]

Kevin: [tex]4(6a+2)+8b + 2 = 24a + 8 + 8b + 2 = 24a + 8b + 10[/tex]

Thus Mrs Green and Keith has the expression that is equivalent to

'24a + 16b + 8'

Hope that helps!

Answer:

[D] $63.55

Step-by-step explanation:

GIven;

To FInd:

What was her after-tax total?

Note:

After-tax total = Include tax

Solve;

$59.95 × 6%=3.597

Round ⇒ 3.60

$59.95 + 3.60 = 63.55

Hence, Joan after-tax total is [D} $63.55

~Learn with Lenvy~

Answer:

Step-by-step explanation:

Find the exact value using trigonometric identities.

Exact Form:

241

200

Decimal Form:

1.205

Mixed Number Form:

1

41

200

Answer:

26.17

Step-by-step explanation:

a^2+b^2=c^2

Answer:

I wish I've known, but try using Symbo-Lab or Math-Way. They help a lot.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Given sequence

This is a GP with

Formula for nth term is:

Answer:

2 may be the greatest one.

Answer:

12

Step-by-step explanation:

12

As all of the bundles have the same content inside, so assuming that there is x number of Fiction books and y number of Non-fiction books in each bundle.

Let n be the total number of bundles that my team can send.

There are 64 Fiction books, so

nx=64 ...(i)

Or x=64/n ...(ii)

also, there are 48 Non-Fiction books, so

ny=48 ...(iii)

Or y=48/n ...(iv)

Observing that the numbers x, y, and n are counting numbers and from equations (i) and (iii), n is the common factor of 64 and 48.

The possible common factors of 64 and 48 are,

n=1,2,4,8, and 16.

So, my team can send 1,2,3,4,8 or 16 bundles of books.

Now, from equations (ii) and (iv),

For n=1:

x=64/1=64

y=48/1=48

So, for 1 bundle the number of Fiction and Non-fictions books are 64 and 48 respectively.

For n=2:

x=64/2=32

y=48/2=48

So, for 2 bundles, the number of Fiction and Non-fictions books are 32 and 24 respectively.

For n=4:

x=64/4=16

y=48/4=12

So, for 4 bundles, the number of Fiction and Non-fictions books are 16 and 12 respectively.

For n=8:

x=64/8=8

y=48/8=6

So, for 8 bundles, the number of Fiction and Non-fictions books are 8 and 6 respectively.

For n=16:

x=64/16=4

y=48/16=3

So, for 16 bundles, the number of Fiction and Non-fictions books are 4 and 3 respectively.

Solution (1):

[tex]0 > -2 + \dfrac{b}{7}[/tex]

[tex]0 + 2 > \dfrac{b}{7}[/tex]

[tex]2 > \dfrac{b}{7}[/tex]

[tex]2 \times 7 > b[/tex]

[tex]\boxed{\bold{14 > b}}[/tex]

Solution (2):

[tex]\dfrac{v}{14} - 2 < -3[/tex]

[tex]\dfrac{v}{14} < -3 + 2[/tex]

[tex]\dfrac{v}{14} < -1[/tex]

[tex]v < -1 \times 14[/tex]

[tex]\boxed{\bold{v < -14}}[/tex]

Solution (3):

[tex]13 < \dfrac{n}{4}+ 9[/tex]

[tex]13 - 9 < \dfrac{n}{4}[/tex]

[tex]4 < \dfrac{n}{4}[/tex]

[tex]4 \times 4 < n[/tex]

[tex]\boxed{\bold{16 < n}}[/tex]

Solution (4):

[tex]138 > -6+9n[/tex]

[tex]138 + 6 > 9n[/tex]

[tex]144 > 9n[/tex]

[tex]\dfrac{144 }{9} > \dfrac{9n}{9}[/tex]

[tex]\boxed{\bold{16 > n}}[/tex]

Solution (5):

[tex]-9 + \dfrac{x}{2} > -14[/tex]

[tex]\dfrac{x}{2} > -14 + 9[/tex]

[tex]\dfrac{x}{2} > -5[/tex]

[tex]x > -5 \times 2[/tex]

[tex]\boxed{\bold{x > -10}}[/tex]

Solution (6):

[tex]-6 > -9 + \dfrac{k}{4}[/tex]

[tex]-6 + 9 > \dfrac{k}{4}[/tex]

[tex]3 > \dfrac{k}{4}[/tex]

[tex]3 \times 4 > k[/tex]

[tex]\boxed{\bold{12 > k}}[/tex]

Solution (7):

[tex]-11 > \dfrac{a}{2} -2[/tex]

[tex]-11 + 2 > \dfrac{a}{2}[/tex]

[tex]9 > \dfrac{a}{2}[/tex]

[tex]-9 \times 2 > a[/tex]

[tex]\boxed{\bold{-18 > a}}[/tex]

Answer:

the 13th term, if you plug in 13 for n and solve you would get 20 :)

Answer:

13th term

Step-by-step explanation:

Given:

The total cost of the order is

[tex]T=6b+2w[/tex]

where, T is the total cost, b is the number of bath towels, and w is the number of wash cloths.

Her budget is $85.

To find:

The constraints, so that she can order a maximum of washcloths or bath towels.

Solution:

We have,

[tex]T=6b+2w[/tex]

Her budget is $85. So, total cost is less than or equal to 85.

[tex]6b+2w\leq 85[/tex]       ...(i)

For maximum number of bath towels, the number of wash cloths is 0.

[tex]6b+2(0)\leq 85[/tex]

[tex]6b\leq 85[/tex]

Divide both sides by 6.

[tex]b\leq \dfrac{85}{6}[/tex]

[tex]b\leq 14.167[/tex]

For maximum number of wash cloths, the number of bath towels is 0.

[tex]6(0)+2w\leq 85[/tex]

[tex]2w\leq 85[/tex]

Divide both sides by 2.

[tex]w\leq \dfrac{85}{2}[/tex]

[tex]w\leq 42.5[/tex]

Therefore, the required constraints for maximum of washcloths or bath towels are [tex]w\leq 42.5[/tex] and [tex]b\leq 14.167[/tex] respectively.

Cylinder volume = base area x height

                            = pi x r² x h

d = 7 yd => r = 7:2 = 3,5 yd

and h = 4 yd

to be calculed

V = 3,14 x 3,5² x 4