Answer:
I'm not sure if the directions affect the speed tho
but I think it's 4? cause it's the speed relative to the ground
hope this helps:))
Which of the following is sensory information received from the middle ear related to movement and balance?
Oral perception
Auditory perception
Vestibular
Proprioceptive
Answer:
vestibular
Explanation:
1)
How much time does it take to lift a box using 18.0 J of work and 20.89 Watt of power?
Answer:.
Explanation:
Z
Please help me, I beg you
Answer:
40g
Explanation:
Solubility of Copper sulfate at 90°=60g
Solubility of potassium bromide at 90°=100g
100g-60g=40g
What is the amount of work required to increase a 1100 kg car's speed from 20.0 m/s to 30.0 m/s?
Answer:
250,000 im not really sure about this answer but this is what I got
The amount of work required to increase the speed of the car is 275000 J.
To calculate the amount of work required to increase the speed of the car, we use the formula below.
Formula:
W = m(v²-u²)/2................ Equation 1Where:
W = amount of work needed to increase the speed of the carm = mass of the caru = initial speed of the carv = final speed of the car.
From the question,
Given:
m = 1100 kgu = 20 m/sv = 30 m/sSubstitute these values into equation 1
W = 1100(30²-20²)/2W = 1100(900-400)/2W = 1100(500)/2W = 1100×500/2W = 275000 JHence, The amount of work required to increase the speed of the car is 275000 J.
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work and power!
______is the amount of work done over time a. Efficiency C. Power b. Newton d. Horsepower
Answer:
The work done in a unit of time is C. Power.
Explanation:
Hope this helps
8. What is the frequency of green light waves that have a wavelength of 5.2 x 10-7 m.? The speed of light is 3.0 x 108 m/s
Answer:
[tex]f=5.76\times 10^{14}\ Hz[/tex]
Explanation:
We need to find the frequency of green light having wavelength o[tex]5.2\times 10^{-7}\ m[/tex]. It can be calculated as follows :
[tex]c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{5.2\times 10^{-7}}\\\\f=5.76\times 10^{14}\ Hz[/tex]
So, the required frequency of green light is equal to [tex]5.76\times 10^{14}\ Hz[/tex].
To drive your car from Auburn to Atlanta (173.8 km) takes a significant amount of work. Assuming the force of friction between the tires and the road is 10290 N, how much work needed to drive that far? Express your answer in megajoules (MJ).
Answer:
1788.402 MJ
Explanation:
Work done = Force (N) x distance (m)
First we have to convert distance into metres:
173.8 x 1000 = 173,800 m
Then plug these values into the equation above:
173,800 x 10290 = 1788402000 J
The reason it's Joules (the unit for energy) is because work done = energy transferred
Now we have to convert Joules into Mega Joules:
1 J = 1/1000000 MJ
1788402000 J = 1788402000/ 1000000 = 1788.402 MJ
5. In which image below is the most work being wasted as heat?
A. Image A
B. Image B
C. Image C
D. Image d
Answer:
C
Explanation:
The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
What will be the speed of the rock?Initial speed of the rock, u = 40m/s
Final position of the rock s = 0m taking the release point as reference. The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
Nuclear energy is a useful source of power but has disadvantages. The disadvantage of nuclear energy is it produces dangerous waste.
Initial speed of the rock, u = 40m/s
Final position of the rock s = 0m taking the release point as reference
From the second equation of motion:
solving above we get:
t = 0s or t = 8.16s, t =0 seconds is neglected since it represents the initial position which is the same as the final position at t = 8.16s
So, the rock takes 8.16 seconds to return to the release point.
Therefore, The rock takes 8.16s to return to its release point. Given that the elastic band provides a speed of 40m/s to the rock in 10 cm stretch.
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What is the mass of an object that has a weight of 52N?
Answer:
5.2Kg
Explanation:
mass=weight/gravitational pull
m=52/10
m=5.2kg
The basic unit of time is second - is it true or false ??
what steps should be taken to increase the amount of current produce a generator
Answer:
The maximum potential difference or current can be increased by:
1. increasing the rate of rotation.
2. increasing the strength of the magnetic field.
3. increasing the number of turns on the coil.
Answer:
It depends. Remember that power is voltage x current. So, do you have enough voltage? You can buy modules that increase and decrease voltage. That is one possibility. Please check all safety guidelines of the generator before doing this. modifying the voltage to a generator without making sure it can take more voltage can be counterproductive
10 pointss
For a two way mirror to work properly, light must be ___ on one side and ____ through the other side
a. reflected - transmitted
b. refracted - absorbed
c. absorbed- reflected
d. absorbed- transmitted
Chan released a stone from a cliff of 10m height.
a)Determine the time taken for the stone to reach the bottom of the cliff.
b)Determine the velocity of the stone just before it touches the ground ignore air resistance.(g＝9.81ms-2)
Thanks
Answer:
a) time taken = 1.427 s
b) final speed before hitting the ground = 14 m/s
Explanation:
height of cliff = 10 m
acceleration due to gravity = 9.81 [tex]m/s^{2}[/tex]
time taken for stone to reach bottom of cliff = ?
velocity of stone just before hitting the ground = ?
To find the time taken, we will use Newton's equation of motion
using
[tex]v^{2} = u^{2} + 2as[/tex]
where
v = final speed of stone before hitting the ground
u = initial speed of the stone (u = 0 since the stone started falling from rest)
a = acceleration due to gravity = 9.81 [tex]m/s^{2}[/tex]
s = height of the cliff = 10 m
Solving, we have
[tex]v^{2} = 0^{2} + 2(9.81 * 10)[/tex]
[tex]v^{2} = 2*98.1[/tex]
[tex]v^{2} = 196.2[/tex]
[tex]v=\sqrt{196.2} = 14 m/s[/tex]
From the first equation of motion,
[tex]v = u + at[/tex]
where t = time taken for stone to reach bottom of cliff
imputing values, we have
[tex]14 = 0 + (9.81 * t)[/tex]
[tex]t = \frac{14}{9.81} = 1.427 s[/tex]
Determine la densidad de un objeto cuya masa es de 10 kg y tiene un volumen de 120 cm3
Answer:
dttydghcghcghdytdftygfvghxk,ghc
Explanation:
10. How much total work do you do when you lift a 50 kg microwave 1.0 m off the ground and then push it 1.0 m
across a counter with a force of 50 N?
Work formula:
[tex]W = Fd\cos(\theta)[/tex]
F = 50N, d = 1.0 m
When you lift something straight up, the angle of the force is 90º
cos(90º) is 0, so there's no work done when you lift the microwave off the ground
[tex]W = (50N)(1.0)(0) = 0[/tex]
F = 50N, d = 1.0 m
When you push the microwave, the angle is 0º and cos(0º) is 1. So there is work done here:
[tex]W = (50 N)(1.0m)(1)[/tex]
[tex]W = 50[/tex]
total work = 50 joules
The fire alarm goes off, and a 75 kg firefighter slides down a pole with a constant acceleration of a = 6 m/s square. What is the upward force F exerted by the pole on the firefighter? *
Answer:
450N
Explanation:
Given data
Mass m= 75kg
Acceleration= 6m/s^2
From the Newtons first law, F=ma
substitute
F=75*6
F= 450N
Hence the force is 450N
A flashlight bulb connected to a 6 V battery draws a 0.5 current. What is the
power used by the flashlight bulb?
A. 3W
B. 12 W
C. 0.8 W
D. 5.5 W
Please answer this ASAP
Answer:
A 3W
Explanation:
Have a good day!
hehee
Power = (voltage) x (current)
Power = (6 V) x (0.5 Amp)
Power = 3 watts
Empty inverted glass is not immersed in water, why?
Answer:
It is hard to push the empty upside down mug inside the water as it has air present inside its cavity which prevents the water from entering inside the mug.
I hope this helps a little bit.
SCS_20-21_SCI_GR7_CFA2 answers
spheres are not perfect in space. But <> is in the cause of their shape.
Answer:
[tex] \boxed { \tt{gravitational \: pull(force)}}[/tex]
A wave with a wavelength of 4.0 m has a frequency of 2 Hz. Calculate the speed of this wave.
O 2 m/s
O 8 m/s
O 6 m/s
O 0.5 m/s
Answer:
8m/s
Explanation:
because frequency×wavelength
What causes the pressure in a fluid
Answer:
The pressure in a liquid is due to the weight of the column of water above. Since the particles in a liquid are tightly packed, this pressure acts in all directions. For example, the pressure acting on a dam at the bottom of a reservoir is greater than the pressure acting near the top.
Answer:
Fluid pressure can be caused by gravity, acceleration, or forces in a closed container. Since a fluid has no definite shape, its pressure applies in all directions.
Explanation:
At which point on this graph do reactants begin to produce products as they collide?
Answer:b
Explanation:
i just did the quiz i was look for it too then got it
The point on this graph do reactants begin to produce products as they collide is B.
What is chemical reaction?The chemical reaction is the reaction between two reactants which led to the formation of products.
The products are substances which forms after reaction. The reactants are the substances which are original materials.
This graph shows how the reactants are reacted and products are formed in a chemical reaction.
As the reaction proceeds, the potential energy is higher when reactants begin to produce products.
Thus, the point on this graph do reactants begin to produce products as they collide is B.
Learn more about chemical reaction.
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The speed of sound at sea level is normally about 340 m/s. A stationary fire alarm has a frequency of 15,000 Hz. An observer running towards the fire alarm hears a frequency of 15,300 Hz. What is the velocity of the observer?
Answer:
The velocity of the observer is 6.8 m/s
Explanation:
Doppler effect equation is given by the formula:
[tex]f'=\frac{v+v_o}{v-v_s} f\\\\where\ f'\ is \ the\ observed \ frequency=15300\ Hz,v_o\ is\ the\ velocity\ of\ the\ observer,\\v_s\ is\ the\ velocity\ of \ source=0,v\ is\ the\ velocity\ of\ sound=340\ m/s\ and\ f\ is\ actual\\frequency=15000\ Hz.\\\\substituting:\\\\15300=15000(\frac{340+v_o}{340} )\\\\340+v_o=346.8\\\\v_o=6.8\ m/s[/tex]The velocity of the observer is 6.8 m/s
Which of the following are examples of etiquette? Check all of the boxes that apply.
prioritizing tasks
writing a note about a patient’s medical condition
following an employer’s dress code
following a company’s policy of addressing patients by their last names
Answer:
C& D
Explanation:
ON EDG2020
Answer: Its C and D
Explanation:
edge
You're watching a movie and all of a sudden the main character slips and pushes the cake he was holding into the ground. The equal but opposite reaction to the cake hitting the ground is...
A. The ground pushing against the main character
B. The cake pushing against the main character
C. The main character pushing against the cake
D. The ground pushing against the cake
Answer:
C?
Explanation:
I think its c cuz the character would be falling and cakes don't bounce when they fall, they just splat
also can we pretend i was watching demon slayer when this happens
What should food workers do to prevent chemical hazards from contaminating food?
A. Wash their hands after taking out the garbage
B. Wear a hair net when working for food preparation areas
C. Store cleaning solutions and bottles away from food storage areas
D. Clean and San at is equipment and utensils for after hours of continuous use
mass = 20Kg
velocity = 10m/s
what is the kinetic energy
Answer:
kinetic energy = 1 / 2 mv²
kinetic energy = 1 / 2 × 20 × 10 ²
kinetic energy = 1000 joules
.........
5. A cable is attached 32.0 m from the base of a flagpole that is about to
be raised. The raising of the pole is temporarily halted when the pole is
at an angle of 60.0° with respect to the ground. If the cable exerts a ver-
tical force of 1.233 x 104 N downward and a horizontal force of 1.233 x
104 N to the left, what is the length of the flagpole?
Answer:
The length of the flagpole is approximately 87.43 m
Explanation:
The given parameters of the cable attached to the flagpole are;
The point along the flagpole at which the cable is attached = 32.0 m
The angle with respect to the ground at which the raising of the flagpole is halted = 60.0°
The downward force exerted by the cable, [tex]F_v[/tex] = 1.233 × 10⁴ N
The force exerted by the cable to the left = 1.233 × 10⁴ N
Let 'W' represent the weight of the flagpole, at equilibrium, we have;
The sum of vertical forces = 0
Therefore;
[tex]F_v[/tex] + W - R = 0
W - R = -1.233 × 10⁴ N
Taking moment about the support at the base of the pole, we get;
1.233 × 10⁴ × d × cos(60.0°) - 1.233 × 10⁴ ×d× sin(60.0°) + W × d/2 ×cos(60.0°) = 0
∴ W × d/2 ×cos(60.0°) ≈ 4513.093·d
W = 2 × 4513.093/(cos(60.0°)) ≈ 18,052.373 N
R = 18,052.373 + 1.233 × 10⁴ ≈ 30,382.373
R ≈ 30,382.373 N
Taking moment about the point of attachment of the cable to the ground, we have;
W × ((d/2) × cos(60.0°) + 32) = R × 32
∴ (d/2) = ((30,382.373 × 32/18,052.373) - 32)/(cos(60.0°)) ≈ 43.71281
d = 2 × 43.71281 ≈ 87.43
The length of the flagpole, d ≈ 87.43 m
5. You are running at your maximum speed of 6m/s to catch a bus which is
standing at the bus stop. The bus move off with an acceleration of 1m/s when
you are 20 m from it.
A. Can you catch the bus?
B. Show graphically.