Answer:
[tex]\huge\boxed{\sf Time = 10 \ seconds}[/tex]
Explanation:
Given:
Initial Velocity = [tex]\sf V_{i}[/tex] = 8.0 m/s
Final Speed = [tex]\sf V_{f}[/tex] = 28.0 m/s
Acceleration = a = ?
Required:
Time = t = ?
Formula:
[tex]\sf a = \frac{V_{f} - V_{i}}{t}[/tex]
Solution:
[tex]\sf 2 = \frac{28-8}{t} \\\\2 = \frac{20}{t} \\\\t = \frac{20}{2} \\\\t = 10 \ seconds\\\\\rule[225]{225}{2}[/tex]
Hope this helped!
~AH1807How does music affect our brain ?
Answer:
it makes us less stressful and more calm so we can do things easier
Explanation:
Assume that 10 waves pass a fixed point in 5 seconds. What is the frequency of the waves in hertz?
Answer:
2 hz
Explanation:
Hertz is cps or cycles per second. 10/5= 2 cps
The frequency of the waves when 10 waves pass a fixed point in 5 seconds is 2Hz.
What is wave ?Wave is a disturbance in a medium that carries energy as well as momentum . wave is characterized by amplitude, wavelength and phase. Amplitude is the greatest distance that the particles are vibrating. especially a sound or radio wave, moves up and down. Amplitude is a measure of loudness of a sound wave. More amplitude means more loud is the sound wave.
Wavelength is the distance between two points on the wave which are in same phase.
Phase is the position of a wave at a point at time t on a waveform.
There are two types of the wave longitudinal wave and transverse wave.
Longitudinal wave : in which, vibration of the medium (particle) is parallel to propagation of the wave. Sound wave is a longitudinal wave.
Transverse wave : in which, vibration of the medium (particle) is perpendicular to propagation of the wave. Light wave is a transverse wave.
Frequency is nothing but numbers of revolution or number of cycles or number of waves in one second. its is expressed in Hertz (Hz) in SI unit.
Given,
Number waves = 10 waves
time = 5 seconds
Frequency = ?
Frequency = No of waves ÷ time
Frequency = 10 ÷ 5
Frequency = 2 Hz
Hence frequency of the wave is 2 Hz.
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Why would the solstice be important to
an ecosystem?
Answer:
marks an important milestone. It's the shortest day of the year and the longest night of the year, and signals a powerful transition point between seasons that is impossible to ignore. ... In Pagan times the winter solstice was referred to as Yule and was a celebration of the Goddess (Moon) energy
Explanation:
Bernoulli's principle is responsible for most of the lift produced by an airplane wing.
True
False
Answer:
huiiiiuuu beautiful...
What is string theory? Need answer in own word
Answer:
When point particals are replaced by string like particals
Explanation:
An icicle falls off of a skyscraper from rest and falls for 34 seconds. How fast will that icicle be moving after that time? Show all work and units. (a = g = 9.81 m/s^2) *
Answer:
The icicle will be moving at 333.54 m/s
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.81 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The icicle falls from rest for 34 seconds. We need to find the speed after that time:
vf = 9.81*34
vf = 333.54 m/s
The icicle will be moving at 333.54 m/s
1.
A car is moving in a circle or radius r = 25 meters, in a parking lot at 10 m/s. What is the car's
centripetal acceleration?
The (nonconservative) force propelling a 1.50 103-kg car up a mountain road does 5.10 106 J of work on the car. The car starts from rest at sea level and has a speed of 24.0 m/s at an altitude of 2.20 102 m above sea level. Obtain the work done on the car by the combined forces of friction and air resistance, both of which are nonconservative forces.
We know, Work done by all the forces is equal to change in potential energy :
[tex]W_{friction} + W_{air} + W_{engine} = \dfrac{(mv_f^2 + mgh_f)}{2}-\dfrac{(mv_i^2+mgh_i)}{2}[/tex]
Here,
[tex]h_i=0\ m\\\\v_i = 0\ m/s[/tex]
Putting all given values, we get :
[tex]W_{friction} + W_{air} + 5.10\times 10^6 = m\dfrac{(v_f^2 + gh_f)}{2}-0\\\\W_{friction} + W_{air} =1.5\times 10^3 \times \dfrac{(24^2 + (9.8\times 2.2\times 10^2))}{2}-5.10\times 10^6\\\\W_{friction} + W_{air} = -3.051\times 10^6\ J[/tex]
Hence, this is the required solution.
A 2.0 kg block is released from rest at the top of a curved incline in the shape of a quarter of a circle of radius R = 3.0 m. The block then slides onto a horizontal plane where it finally comes to rest a distance D from the beginning of the plane. The curved incline is frictionless, but there is a coefficient of friction, μ = 0.5, on the horizontal plane. Determine the velocity of the box at maximum kinetic energy
The block has maximum kinetic energy at the bottom of the curved incline. Since its radius is 3.0 m, this is also the block's starting height. Find the block's potential energy PE :
PE = m g h
PE = (2.0 kg) (9.8 m/s²) (3.0 m)
PE = 58.8 J
Energy is conserved throughout the block's descent, so that PE at the top of the curve is equal to kinetic energy KE at the bottom. Solve for the velocity v :
PE = KE
58.8 J = 1/2 m v ²
117.6 J = (2.0 kg) v ²
v = √((117.6 J) / (2.0 kg))
v ≈ 7.668 m/s ≈ 7.7 m/s
The velocity of the block at maximum kinetic energy is 7.668 m/s.
From potential energy formula,
PE = m g h
Where,
m = mass = 2 kg
g -gravitational acceleration = 9.8 m/s²
h - height = 3 m
Put the values in the formula,
PE = (2.0 kg) (9.8 m/s²) (3.0 m)
PE = 58.8 J
Since,
PE = KE
Thus,
58.8 J = 1/2 m v ²
117.6 J = (2.0 kg) v ²
v = √((117.6 J) / (2.0 kg))
v = 7.668 m/s
Therefore, the velocity of the block at maximum kinetic energy is 7.668 m/s.
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Lila is a track and field athlete. She has to complete four laps around the track, which is 400 meters. The race took her 6 minutes to complete. What is her average speed to the first decimal point in m/s?
Answer:
4.44m/s
Explanation:
Given parameters:
Number of laps = 4
Length of track = 400m
Time taken = 6min
Unknown:
Average speed = ?
Solution:
The average speed is the total distance covered divided by the time taken.
It is mathematically expressed as;
Average speed = [tex]\frac{total distance}{time taken}[/tex]
Total distance = number of laps x length of track = 4 x 400 = 1600m
Now convert the time to seconds;
60s = 1 min
6 minutes will be 6 x 60 = 360s
So;
Average speed = [tex]\frac{1600}{360}[/tex] = 4.44m/s
If an object is resting on a surface it "crunches" the atoms underneath it. According to Newton's Third Law the surface pushes back on the object. What is the name given to this force that acts perpendicular to the surface?
Answer:
Normal force
Explanation:
Normal force is the force that surfaces employ so that solid objects are disallowed from passing through each other.
4) Bunny pushes on Monkey to the right with a 95N force while Deer pushes on Monkey Tom Lee
with a 75N force. Monkey weighs
50N.
Answer:
-30N to the left
Explanation:
Step one:
Given data
the mass of the monkey is 50N
Step two:
Required is the net force acting on the monkey
Now to the right Bunny is applying 95N,
Deer pushes on Monkey Tom Lee
with a 75N the net force acting on the monkey to move it is
= 95-50-75= -30N to the left
the other user said:
-30N to the lefthow can 23.78 x 10 to the power of negative 6 metre cube per mole changed to meter cube?
Answer:
We multiply [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex] by the amount of mole to change units to cubic meters.
Explanation:
Let [tex]x = 23.78\times 10^{-6}\,\frac{m^{3}}{mol}[/tex], we change the unit to cubic meters by multiplying this number by the amount of moles of the sample. For instance, let [tex]n = 1\,mol[/tex], then the obtain the following result:
[tex]m = x\cdot n[/tex] (1)
[tex]m = \left(23.78\times 10^{-6}\,\frac{m^{3}}{mol} \right)\cdot (1\,mol)[/tex]
[tex]m = 23.78\times 10^{-6}\,m^{3}[/tex]
What is the acceleration of a car initially traveling at -5m/s and
reaching -22m/s in 3s.
Answer:
[tex]a=-5.67\ m/s^2[/tex]
Explanation:
Given that,
Initial velocity, u = -5 m/s
Final velocity, v = -22 m/s
Time, t = 3s
We need to find the acceleration of the car. The formula of it is given by :
Acceleration,
[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2[/tex]
So, the acceleration of the car is [tex]-5.67\ m/s^2[/tex].
Anyone.... help with this two questions...
The sun shines equally on both hemispheres during the summer and winter solstices.
True
False
how does a plane mirror work
Answer:
Plane mirrors work because the light rays create a virtual image behind the mirror. Light rays from the object strike the mirror and reflect according to the law of reflection. ... Therefore, our eye and brain track the light rays backward to a position from which they appear to have come.
You have a cup full of water and a bathtub full of water. Both samples of water have a temperature of 30°C. Which sample has greater amount of heat?
Answer:
temperature is -10
Explanation:
URGENT )If you drive your 1,000 kg car from sea level up to the mountain, which is 366 m above sea level, how much will you have increased your car's potential energy?(consider : g=10m/s2)
1 point
a) 366,000 J
b) 3,660,000 J
c) 2.73 J
d) 20.73 J
Answer:
(B) the increase in the car's potential energy is 3,660,000 J
Explanation:
Given;
mass of the car, m = 1,000 kg
height through the car was drove, h = 366 m
acceleration due to gravity, g = 10 m/s²
The increase in the car's potential energy is calculated as;
P.E = mgh
P.E = 1000 x 10 x 366
P.E = 3,660,000 J
Therefore, the increase in the car's potential energy is 3,660,000 J
Two go-carts, A and B, race each other around a 1.0 track. Go-cart A travels at a constant speed of 20.0 /. Go-cart B accelerates uniformly from rest at a rate of 0.333 / ଶ . Which go-cart wins the race and by how much time?
Complete Question
Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?
Answer:
Go-cart A is faster
Explanation:
From the question we are told that
The length of the track is [tex]l = 1.0 \ km = 1000 \ m[/tex]
The speed of A is [tex]v__{A}} = 20 \ m/s[/tex]
The uniform acceleration of B is [tex]a__{B}} = 0.333 \ m/s^2[/tex]
Generally the time taken by go-cart A is mathematically represented as
[tex]t__{A}} = \frac{l}{v__{A}}}[/tex]
=> [tex]t__{A}} = \frac{1000}{20}[/tex]
=> [tex]t__{A}} = 50 \ s[/tex]
Generally from kinematic equation we can evaluate the time taken by go-cart B as
[tex]l = ut__{B}} + \frac{1}{2} a__{B}} * t__{B}}^2[/tex]
given that go-cart B starts from rest u = 0 m/s
So
[tex]1000 = 0 *t__{B}} + \frac{1}{2} * 0.333 * t__{B}}^2[/tex]
=> [tex]1000 = 0 *t__{B}} + \frac{1}{2} 0.333 * t__{B}}^2[/tex]
=> [tex]t__{B}} = 77.5 \ seconds[/tex]
Comparing [tex]t__{A}} \ and \ t__{B}}[/tex] we see that [tex]t__{A}}[/tex] is smaller so go-cart A is faster
help!!!! please!!! i’m not sure what the answer is for both questions please
Answer:
a.) 600N
b.) 2 m/s^2
Explanation:
a.)
In order to solve for the needed force, you must use Newton's 2nd law which states that a force is equal to mass multiplied by acceleration.
Basically: Force = mass * acceleration ; F = ma
Since both mass and acceleration are already given, just plug them into the formula and solve for force:
Mass = 200kg
Acceleration = 3m/s^2
F = m * a = 200 * 3 = 600kg * m/s^2 = 600N
b.)
In order to find the acceleration, like the hint already says, you need to find the net force first and then use Newton's 2nd law.
To calculate net force:
Since both forces are parallel (affect the same axis) and in opposite directions, you can subtract the two in order to find resultant magnitude. The resultant direction is the direction of the force with the large magnitude.
Net Force: 8N - 4N = 4N
Net Force Direction: since 8N > 4N, the direction is in the same direciton as the 8N force = Left
Finally, you find acceleration using newton's 2nd law, F = ma.
Since you already know mass and net force, plug in to solve for acceleration:
4N = 2kg * a
a = 4 N / 2kg = 2m/s^2
A grinding wheel, initially at rest, is ro-tated with constant angular acceleration of2.52 rad/s2for 7.03 s. The wheel is thenbrought to rest with uniform deceleration in11.9 rev.Find the angular acceleration required tobring the wheel to rest. Note that an in-crease in angular velocity is consistent with apositive angular acceleration.Answer in units of rad/s2.
Starting from rest, the wheel accelerates to an angular velocity of
ω = (2.52 rad/s²) (7.03 s) ≈ 17.7 rad/s
then undergoes a new acceleration α until it comes to a rest. It does so in 11.9 revolutions, or with an angular displacement of (11.9 rev) • (2π rad/rev) = 23.8π rad. So α satisfies
0² - ω² = 2 α (23.8π rad)
α = - ω² / (47.6π rad)
α ≈ -2.10 rad/s²
1 point
Which will hit the ground first, if both objects are dropped from the same
height at the same time IN AIR?*
O an icicle
O a snow flake
O both hit the ground at the same time
Answer:
an icicle
Explanation:
and icicle has less air resistance compared to that of a snow flake
HELP ASAP!! WILL TRY TO GIVE BRAINLIEST
Outline the cell cycle
Answer:
The cell cycle has four stages: during the first three, the cell is in interphase, and in the last one, the cell is dividing itself. Also, there is a resting stage when the cell is not preparing itself for the division.
G0: the cell is not in the cell cycle. It is resting and not preparing itself for the division.
G1: the cell grows and synthesizes proteins and other elements that the cell will need for the next stage.
S: In this phase, which is called Synthesis, the cell synthesizes the DNA.
G2: the cell continues to grow. It synthesizes more proteins, RNA, and other elements that it will need for mitosis.
Mitosis: the division of the cell takes place, and as a result, there are two daughter cells. This phase has four stages, prophase, metaphase, anaphase, and telophase.
Explanation:
The cell cycle has four stages. Each of them has a role in the division of the cell. The first one is Gap 1 or G1, then the Synthesis or S phase follows, after S, Gap 2 takes place, and finally, Mitosis.
We can divide the cell cycle into two big groups: interphase, which includes G1, S, and G2, and the changes that the cell suffer can not be appreciated. The other group is the One where the cell division happens, and it includes Mitosis.
G0 is not part of the cell cycle. It is a state where the cell doe not prepares itself for the division. It is resting.
I am traveling at 100 m/s, I hit the brakes and my speed goes down to 50 m/s. It took 30 seconds to slow down. What was my acceleration?
A.5 m/s2
B.-5 m/s2
C.1.7 m/s2
D.-1.7 m/s2
Answer:
D. -1.7m/s2
Explanation:
the car starts at 100m/s so this is the initial velocity. It ends at 50m/s so this is the final velocity. it took 30 seconds so the time is 30.
[tex]v_{f}=v_{i}+at[/tex]
[tex]a=\frac{\left(v_{f}-v_{i}\right)}{t}[/tex]
[tex]a=\ \frac{\left(50-100\right)}{30}[/tex]
[tex]a=-1.66666666667[/tex][tex]m/s^{2}[/tex]
Therefore, the answer is D
Mr. Davis is riding his bike at a speed of 5 meters per second for 3600 seconds how far did he ride?
Answer:18,000 meters
Explanation:3600x5=18,000.
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Identify the structure that separates the nuclear contents from the cytoplasm.
Answer:nuclear membrane
Explanation:
Answer:
Nuclear envelope. Hope this helps.
PLS HELP ME
I NEED HELP ASAP
Answer:
In order to find average velocity we use the equation: [tex]avg = \frac{change \: in \: x}{change \: in \: time} [/tex]She went from 4.0m to 16.0 m making her delta x = 12.0 m She did that in 4sHence 12/4 = 3 m/s Radioisotopes often emit one or more types of radiation, including alpha particles, beta particles, and gamma rays. The distance the radiation travels through matter before being absorbed increases in order from alpha to gamma. Which statement describes the best radioisotope that can be used for radioisotope imaging and for radionuclide therapy?
It emits only gamma rays.
It emits only alpha particles.
It emits alpha and beta particles.
It emits beta particles and gamma rays.
Answer:
The most correct option is the last option
Explanation:
During radioisotope/nuclear imaging in diagnosis, the radioisotope must emit gamma rays from within the body. However, in the case of radionuclide therapy, most radionuclides emit beta particles while some others also emit gamma rays.
Answer:
D
Explanation:
The negatively charged particle in an atom is a(n):
Answer: Electron
Explanation:A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.
Hope this helps!!Brainlist?