Answer:
60m/s
Explanation:
v=u+at
v=36+(2×12)
v=36+24
v=60m/s
A) The motor speed is less than wheel speed.
B) The output power of the motor is positive during hill climbing.
C) The wheel torque is more than motor torque.
For the following statements
A) The motor speed is less than wheel speed.
B) The output power of the motor is positive during hill climbing.
C) The wheel torque is more than motor torque
These assertions are given respectively as
falsetruefalseWhat are speed, power, and Torque?Speed: defined as the ratio of operation with respect to distance and time
Power: defined as the ability to work
Torque: This is the speed of a rotating object
Generally, the equation for Speed, Power, Torque is mathematically given as
V=m/s
P=w/t
T=rfsin\theta
In conclusion
For a moving car, the wheels speed is in equilibrium with the motor speed Hence false
The output power during a hill climb is positive cause work is been done, Hence true
The wheel torque also is in equilibrium with the motor Torque, Hence false
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At t = 0, Ball 1 is dropped from the top of a 22 m-high building. At the same instant Ball 2 is thrown straight up from the base of the building with an initial velocity of +12 m/s. Assume that Ball 1 starts from rest and that air friction can be ignored. At what height will the two balls pass each other? What is the velocity of each ball at the moment they are at the same height?
Answer:
The two balls pass each other at a height of 5.53 m
vf1=17.97 m/s
vf2=-5.96 m/s
Explanation:
Vertical Motion
An object thrown from the ground at speed vo, is at a height y given by:
[tex]y=vo.t-g.t^2/2[/tex]
Where t is the time and [tex]g=9.8\ m/s^2[/tex]
Furthermore, an object dropped from a certain height h will fall a distance y, given by:
[tex]y=g.t^2/2[/tex]
Thus, the height of this object above the ground is:
[tex]H = h-g.t^2/2[/tex]
The question describes that ball 1 is dropped from a height of h=22 m. At the same time, ball 2 is thrown straight up with vo=12 m/s.
We want to find at what height both balls coincide. We'll do it by finding the time when it happens. We have written the equations for the height of both balls, we only have to equate them:
[tex]vo.t-g.t^2/2=h-g.t^2/2[/tex]
Simplifying:
[tex]vo.t=h[/tex]
Solving for t:
[tex]t=h/vo=22/12=1.833\ s[/tex]
The height of ball 1 is:
[tex]H = 22-9.8.(1.833)^2/2[/tex]
H = 5.53 m
The height of ball 2 is:
[tex]y=12\cdot(1.833)-9.8\cdot(1.833)^2/2[/tex]
y=5.53 m
As required, both heights are the same.
The speed of the first ball is:
[tex]vf1=g.t=9.8\cdot 1.833=17.97\ m/s[/tex]
vf1=17.97 m/s
The speed of the second ball is:
[tex]vf2=vo-gt=12-9.8\cdot 1.833=-5.96\ m/s[/tex]
vf2=-5.96 m/s
This means the second ball is returning to the ground when both balls meet
Consider the interference pattern produced by two parallel slits of width a and separation d, in which d = 3a. The slits are illuminated by normally incident light of wavelength λ.
Required:
a. First we ignore diffraction effects due to the slit width. At what angles θ from the central maximum will the next four maxima in the two-slit interference pattern occur?
b. If the intensity at θ = 0 is I0, what is the intensity at each of the angles in part (a)?
c. Which double-slit interference maxima are missing in the pattern?
Answer:
a) m =1 θ = sin⁻¹ λ / d, m = 2 θ = sin⁻¹ ( λ / 2d) , c) m = 3
Explanation:
a) In the interference phenomenon the maxima are given by the expression
d sin θ = m λ
the maximum for m = 1 is at the angle
θ = sin⁻¹ λ / d
the second maximum m = 2
θ = sin⁻¹ ( λ / 2d)
the third maximum m = 3
θ = sin⁻¹ ( λ / 3d)
the fourth maximum m = 4
θ = sin⁻¹ ( λ / 4d)
b) If we take into account the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.
I = I₀ cos² (Ф) (sin x / x)²
Ф = π d sin θ /λ
x = pi a sin θ /λ
where a is the width of the slits
with the values of part a are introduced in the expression and we can calculate intensity of each maximum
c) The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present
maximum interference d sin θ = m λ
first diffraction minimum a sin θ = λ
we divide the two expressions
d / a = m
In our case
3a / a = m
m = 3
order three is no longer visible
(a) The next four angles from the central maxima are sin⁻¹ λ / d, sin⁻¹ λ / 2d , sin⁻¹ λ / 3d, and sin⁻¹ λ / 4d respectively.
(b) With the values of part a are the expression of intensity of each maximum can be calculated accordingly.
(c) The third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.
a)
In the interference phenomenon the maxima are given by the expression
d sin θ = m λ
Here,
d is the slit separation and m is the order of interference.
The maximum for m = 1 is at the angle is,
θ = sin⁻¹ λ / d
For the second maximum m = 2
θ = sin⁻¹ ( λ / 2d)
For the third maximum m = 3
θ = sin⁻¹ ( λ / 3d)
For the fourth maximum m = 4
θ = sin⁻¹ ( λ / 4d)
Thus, we can conclude that the next four angles from the central maxima are sin⁻¹ λ / d, sin⁻¹ λ / 2d , sin⁻¹ λ / 3d, and sin⁻¹ λ / 4d respectively.
b)
Considering the effect of diffraction, the intensity of the maximums is modulated by the envelope of the diffraction of each slit.
I = I₀ cos² (Ф) (sin x / x)²
Where Ф is the phase angle, and its value is,
Ф = π d sin θ /λ
x = π a sin θ /λ
Here a is the width of the slits
Thus, with the values of part a are introduced in the expression the intensity of each maximum can be calculated accordingly.
c)
The interference phenomenon gives us maximums of equal intensity and is modulated by the diffraction phenomenon that presents a minimum, when the interference reaches this minimum and is no longer present.
For the maximum interference:
d sin θ = m λ
For the first diffraction minimum:
a sin θ = λ
Dividing both the expressions as,
d / a = m
Since, d = 3a. Then,
3a / a = m
m = 3
Thus, we can conclude that the third order maxima (m = 3) is missing from the pattern obtained through the double-slit experiment.
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A compact car can climb a hill in 10 s. The top of the hill is 30 m higher than the
bottom, and the car's mass is 1,000 kg What is the power output of the car?
Answer:
29.4 kW
Explanation:
time t = 10 s, height h = 30 m, mass m = 1,000 kg
power output = work done/time
work done = increase in potential energy = mgh = 1,000 * 9.8 * 30 = 294,000 J = 294 kJ
power output = 294/10 = 29.4 kW
What is it called when two waves meet?
Question 1 options:
frequency
resonance
amplitude
superposition
Superposition is the most correct option
When two waves meet it is generally called inteference. Superposition occurs when the waves adds up to form a stronger wave. This is called constructive interference
hope this helps....
Describe how a sound wave travels through a medium to create sound.
A soundwave will go through a medium but once it goes through, the sound that you hear is muffled or not as clear usually just like sound going through a wall. The soundwaves will be something like moved and the sound you hear might not be the same or as clear as the original sound was
Answer:
sound waves
Explanation:
The sound waves can go through different mediums depending on the crest and trough
PLEASE HELP QUICKLY
Jason shoots a nerf dart at 13 m/s horizontally, while Jake drops
same time. Which dart hits the ground first?
O Jason's
O Jake's
O There is not enough information to know
They both hit at the same time
Answer:
they both hit at the same time
What causes the shock you receive from when you touch a doorknob?
Neutrons being pulled from one
surface to another
Protons being pulled from one surface to another
Electrons being pulled from one surface to another
Positrons being pulled from one surface to another
Answer:
Electrons being pulled from one surface to another
Explanation:
The movement of electrons creates electrical charge.
A 2-kg ball is moving with constant speed of 5 m/s in a horizontal circle whose radius is 50 cm. What is the magnitude of the net force on the ball
For a 2-kg ball moving with a constant speed of 5 m/s in a horizontal circle whose radius, the magnitude of the net force on the ball is 50 cm. is mathematically given as
F= 100 N
What is the magnitude of the net force on the ball?Generally, the equation for the Net force is mathematically given as
F = m*r*w^2
Where
w = angular velocity
w= 5/r
w= 10 rad/s
Therefore
F = 2/0.5/10^2
F= 100 N
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How would the conduction of someone’s hand holding the cold water jar affect the jar’s temperature?
Answer:
The person's hand will warm up the jar
Explanation:
Thermal energy will be conducted from his hand to the jar
Dominic made the table below to organize his notes about mixtures. A 1-column table. The first column labeled properties of mixtures has entries has no set composition, must have more than one state of matter, must have more than one substance. What mistake did Dominic make? The title should read “Properties of Solutions” because some mixtures do not have all of the properties listed. There is a definite recipe to make each mixture, so the composition of a mixture is set. Although it is possible to have more than one state, it is also possible to have only one state. A single substance can be used to make a mixture if the substance is composed of more than one element.
Answer:
The is: Although it is possible to have more than one state, it is also possible to have only one state.
Explanation:
Hope this helps! ;-)
Answer:
Although it is possible to have more than one state, it is also possible to have only one state.
Explanation:
Which item has the most thermal energy?
Answer:
room temperature water
Explanation:
Answer:
In the figure, the particles of cocoa are moving faster than the particles of bathwater. Therefore, the cocoa has a higher temperature. However, the bath water has more thermal energy because there is so much more of it. It has many more moving particles.
Explanation:
What are the two types of techniques used when playing tennis? Please provide your answer using a complete sentence.
The serve, forehand groundstroke, backhand groundstroke, forehand volley, backhand volley, and overhead smash are the six basic strokes in tennis. The 6 basic "strokes" are the basic actions a tennis player makes to hit the ball.
Stay safe & humble <3
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A cheetah can run at instantaneous speeds of 64 km/hr or 17.8 m/sec. How much time does it take a cheetah to run 2 m?
0.1 seconds
0.1 m/s
35.6 seconds
0.03 seconds
What do you think you could do to help prevent or stop cyberbullying? List at least two ideas.
Answer:
1. You can block the person bullying you.
2. Tell an adult about whats going on.
3. Try to stay off any social media apps. (turn off all notifications)
4. Don't respond to any of the comments or post. (Ignore them)
Explanation:
Hope this helps.
3. What kinds of electromagnetic waves have the lowest frequencies? What kinds have the highest frequencies?
Answer:
Explanation:
from highest to lowest frequency
gamma-ray, x-ray, ultraviolet, visible light, infrared, microwave, radio
hope this helps have a good day :)
The electromagnetic waves with the lowest frequencies are the ones we call "radio" waves.
The electromagnetic waves with the highest frequencies are the ones we call "gamma rays".
In between those are all the others . . . the microwaves, the heat ('thermal') waves, the infrared waves, the light waves, the ultraviolet waves, and the X-rays.
If the man has a mass of 90kg, where would he experience greater gravitational force? On Earth or Moon? Calculate and explain
Answer: You feel the gravitation on the Earth greater
Explanation:
Because the mass of the Earth is heavier than the Moon, you can replace specifi number of the weight of the Moon and the man compare the weight of the Earth and the man into the formula!
what does the area between the line and the x axis represent on a velocity vs time graph
the area bounded by the line and the axes of a velocity-time graph is equal to the displacement of an object during that particular time period
Thank you
The area between the line and the x axis represent on a velocity vs time graph is the displacement.
The area under velocity-time graph is known as displacement.
In velocity-time graph, the y-axis represents the velocity axis while the x-axis represents the time axis.
Velocity is defined as the change in displacement per change in time.
[tex]v = \frac{dx}{dt}[/tex]
where;
[tex]dx[/tex] is the change in displacement[tex]dt[/tex] is the change in timeThe integration of the velocity gives the area under the curve and that will be equal to the displacement.
[tex]\int\limits^a_b {v} \, dt = x[/tex]
Thus, the area between the line and the x axis represent on a velocity vs time graph is the displacement.
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How does
friction affect the motion of
two objects sliding past
each other
Friction affects the motion of two objects sliding past each other. This frictional force results into the loss of energy and hence slow down the motion of the two objects in contact.
What is the Frictional force?Frictional force is the force that is resisting the relative motion of solid surfaces, fluid layers, and the two material elements which are sliding against each other. There are several types of friction such as dry friction, it is a force that opposes the relative lateral motion of the two solid surfaces which are in contact.
Frictional force generates when the two surfaces slide past one another in motion. The force of friction opposes the motion of an object which is in contact, causing the moving objects to lose energy and slow down. The frictional force is important as it helps us in walking, driving a car, and in doing other works.
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find the kenitic energy before and after the collision
Answer:
The total system kinetic energy before the collision equals the total system kinetic energy after the collision. If total kinetic energy is not conserved, then the collision is referred to as an inelastic collision.
Explanation:
Initial kinetic energy KE = 1/2 m1v12 + 1/2 m2v22 = joules. The following calculation expects you to enter a final velocity for mass m1 and then it calculates the final velocity of the other mass required to conserve momentum and calculates the kinetic energy either gained or lost to make possible such a collision.
A pulley of radius 8.0 cm is connected to a motor that rotates at a rate 7000 rad s-1 and then decelerate uniformly at a rate of 2000 rad s-1 within 5 s.
a. Calculate its angular acceleration.
b. What is the number of rotations within the time range?
c. How long is the string that winds it within the time range?
d. Determine the tangential acceleration of the string.
[15 marks]
Answer:
(a) α = - 1000 rad/s²
Negative sign represents deceleration.
(b) θ = 3581 rotations
(c) L = 1800 m
(d) a = - 80 m/s²
Explanation:
(a)
using First equation of motion for angular motion:
ωf = ωi + αt
where,
ωf = Final Angular Speed = 2000 rad/s
ωi = Initial Angular Speed = 7000 rad/s
α = Angular Acceleration = ?
t = time = 5 s
Therefore,
2000 rad/s = 7000 rad/s + α(5s)
α = (2000 rad/s - 7000 rad/s)/5 s
α = - 1000 rad/s²
Negative sign represents deceleration.
(b)
Using second equation of motion:
θ = ωi t + (1/2)αt²
where,
θ = No. of Rotations = ?
Therefore,
θ = (7000 rad/s)(5 s) + (1/2)(- 1000 rad/s²)(5 s)²
θ = 35000 rad - 12500 rad
θ = (22500 rad)(1 rotation/2π rad)
θ = 3581 rotations
(c)
Length of String = L = (Circumference of Pulley)(θ)
L = [2π(0.08 m)][3581 rotations]
L = 1800 m
(d)
Tangential Acceleration = a = rα
a = (0.08 m)(-1000 rad/s²)
a = - 80 m/s²
$3.49/ gallon and other is $1.25/L which container of milk is a better deal
Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at
while the Invalid expressions are; v = a/t and d = at
Explanation:
Given expressions
1) v = a/t
2) t = ∛(d²/va)
3) d = at
4) a = d/t²
5) a = √(vd/t³)
6) v = at
First we get our units of parameters
V = m/s, t = sec, d = m, a = m/s²
so
1)
v = a/t
we substitute in our units of parameters
v = m/s² / s = m/s² × 1/s = m/s³
v ≠ m/s³
therefore it is false
2)
t = ∛(d²/va)
we substitute
t = ∛(m² / m/s × m/s²)
t = ∛(m² / m²/s³)
t = ∛(s³)
t = s
correct, the expression is true
3)
d = at
we substitute
d = m/s² × s
d = m/s² × s/1 = ms/s² = m/s
d ≠ m/s (because d = m)
so expression is false
4)
a = d/t²
we substitute
a = m / s² = m/s²
correct
the expression is true
5)
a = √(vd/t³)
we substitute
a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³) = √(m²/s⁴) = m/s²
so a = m/s²
correct
the expression is true
6)
v = at
we substitute in the units
v = m/s² × s = m/s² ×s/1 = ms/s² = m/s
v = m/s
correct
the expression is correct
Which of these factors determine the brightness of a star?*
O The size of the star
The surface temperature of the star
The distance the star is from the Earth
O All of the above
Answer:
All of Above
Explanation:
ANSWER PLS
Heat moves from the land to the air through the process of
conduction
convection
radiation
refraction
Answer:
Conduction
Explanation:
conduction is one of the three main ways that heat energy moves from place to place the other two ways heat moves around our radiation and convection conduction is the process by which heat energy is transmitted through Collisons between neighboring atoms or molecules.
hope this helps :)
Answer:
A
Explanation:
Read the following selections from the section "Mickey Guyton's Star-Spangled Banner."
The Grammy Award-nominated country singer delivered a soaring, emotional version of the anthem largely on bet
own. A small choir and piano later joined her.
Guyton did not appear to drop or flub any words. She wore a royal blue gown.
What conclusion is BEST Supported by the selections?
A- Mickey Guyton has performed at some of the previous Super Bowls.
B- Mickey Guyton spent a great deal of time practicing for her performance.
C- Mickey Guyton was nervous about singing the national anthem mostly on her own.
D- Mickey Guyton put her personal touch on an anthem that came off without a hitch.
Answer:
C
Explanation:
A child in a boat throws a 6.6kg package out horizontally with a speed of 10.2m/s. Calculate the velocity of the boat immediately after, assuming it was initially at rest. The mass of the child is 29.9kg, and that of the boat is 44.7kg. Ignore water resistance.
Answer:
[tex]-0.902 \frac ms[/tex]
Explanation:
We apply conservation of momentum here. Before the toss, everything was still, so the momentum was 0. After the toss, we have the sum of the momentum of the package (1st term) and the boat+child combo (2nd term). Let's call v the velocity of the boat.
[tex]0= 6.6kg \cdot 10.2\frac ms + (29.9+44.7)kg\cdot v\\v= - \frac{6.6 \cdot 10.2 }{74.6} \frac ms \approx -0.902 \frac ms[/tex]
The term is negative since it expresses the boat+child system is going the opposite way from where the package flew.
In size, composition, and color, which other planet is Saturn most like?
A) Jupiter
B) Earth
C) Venus
D) Mercury
Megan walks 100 m east and then travels 70 m north followed by 140 m
east. What is the total distance she travels? Show/explain how you
calculate. *
Answer:
I think it's just 100+70+140
. Satisfied with the jeweler’s method, the customer next takes out a large and rigid bracelet, adds it to the measuring container and records the new mass and the volume level of the liquid, planning to use the same method to determine what it is made of. Unfortunately, the customer failed to notice that the bracelet was much larger than the ring, and was not fully submerged, but was partially protruding above the surface of the water. Do you believe that the density the customer calculated was higher or lower than the actual density of the bracelet? Explain how you came to your conclusion.
Answer:
value is obtained than the real one.
ρ > ρ_real
Explanation:
A widely used method to determine the density of a body is to measure its mass and measure its volume by immersing it in a transparent liquid, to measure its volume by the difference in volumes of the liquid then use the relationship
ρ = m / V
In this case, part of the body remains the force of the liquid, in this case using Archimedes' principle that establishes that the weight of the desalted liquid is equal to the thrust, let's use the equilibrium equation
B - W = 0
B = W
ρ_liquid g V_submerged = ρ_body g V_body
V_submerged = (ρ_body /ρ-liquid) V_body
We can see that the volume is only a fraction of the volume of the body, therefore when performing the division a higher value is obtained than the real one.
Forces in action worksheet. Need help with this, it's due tomorrow by 8:30am, please help! If you do the bottom 2 for me as well, I will mark brainliest :)