A certain spring stretches 15 cm when a load of 50.0 N is suspended from it. How much will the spring stretch if 78N is suspended from it

Answer:

B

Explanation:

Answer:

i think it's either B or C

Explanation:

Open star clusters tend to orbit within the disk. Globular star clusters contain hundreds of thousands of stars, and some – like Omega Centauri, shown above – contain millions of stars. Open star clusters tend to contain only hundreds of stars.

The force of attraction between the balloon and the rod is 9 x 10⁻³ N.

The force of attraction between the balloon and the rod is calculated by applying Coulomb's law as shown below;

[tex]F = \frac{kq_1 q_2}{r^2}[/tex]

where;

F = (9 x 10⁹) x (2.0 x 10⁻⁸)²/(0.02)²

F = 9 x 10⁻³ N

Thus, the force of attraction between the balloon and the rod is 9 x 10⁻³ N.

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[tex]\:\:\:\:\:\:\:\:\:\:\star [/tex]We can calculate the force between the balloon and the rod applying "Coulomb's Law". Which states-

[tex]\:\:\:\:\:\:\:\:\:\:\star\:\sf \underline{F_{(air)} = K\times \dfrac{ q_1 q_2}{r^2}} \\ [/tex]

[tex] \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]

Where-

As per question, we are given that -

Now that required values are given, so we can substitute the values into the formula and solve for Force -

[tex] \:\:\:\:\:\:\:\:\:\:\star\:\sf\underline{F_{(air)} = \dfrac{1}{4\pi \epsilon_{0} } \dfrac{q_1q_2}{r^2} }\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= 9\times 10^9 \times \dfrac{-2\times 10^{-8}\times 2\times 10^{-8} }{(0.02)^2}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{4\times10^{-16}}{4\times 10^{-4}}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)}= -9\times 10^9 \times\dfrac{\cancel{4}\times10^{-16}}{\cancel{4}\times 10^{-4}}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-16} \times 10^{4}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-16+4} \\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^9 \times 10^{-12} \\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^{9-12}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf Force_{(air)} = -9\times 10^{-3}\\ [/tex]

[tex] \:\:\:\:\:\:\:\longrightarrow \sf \underline{Force_{(air)} = -9\times 10^{-3}\:N}\\ [/tex]

The efficiency of a carnot engine with absorb temperature and exhaust temperature is 13%. The correct option is A.

The efficiency is defined as the work done by the engine divided by the heat supplied.

So, efficiency η = 1 - T₁/T₂

Where T₁ is the lower temperature and T₂ is the higher temperature.

A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C

Substitute the value into the expression , we get

η = 1 -(77+273)  / (127+273) x 100 %

η = 12.5 %

or

η = 13 %

Thus, the efficiency of the carnot engine is 13%.

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Answer:

Explanation:

frequency = 10/8 = 1.125 Hz

The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.

Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.

Generally, the Magnetic area points internal the airplane so through fleming left hand rule is

F = q ( V x B). Ie

hence

qVB = qE

V= E/B then no deflection.

V > E/B then magnetic pressure is dominant over electric powered force.

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See the flash fictions are small nov.els with para.graphs where as ch*.t story is a storyline that just look like some c

c.h.*.t.s.

Both "text-talk novels" and "flash fiction" are forms of written literature, but they have distinct characteristics and purposes.

Text-Talk Novel:

A text-talk novel, also known as a "chat novel" or "text-message novel," is a narrative written in the style of text messages or chat conversations. These novels are typically composed of short, informal messages exchanged between characters, presented in a way that resembles conversations on messaging apps. Text-talk novels often use emojis, abbreviations, and informal language to create a sense of immediacy and relatability. They are designed to be read on mobile devices and appeal to readers who are used to communication through texting and social media platforms. Text-talk novels often cater to a younger audience and can cover various genres, from romance to mystery.

Flash Fiction:

Flash fiction, also known as "microfiction," "short-short stories," or "sudden fiction," refers to extremely short works of fiction characterized by their brevity. Flash fiction stories are typically no longer than 1,000 words, and often much shorter. Despite their limited length, flash fiction stories aim to convey a complete narrative, evoke emotions, and leave a lasting impact on the reader. Due to their concise nature, flash fiction stories often focus on a single idea, moment, or theme, and they require skillful crafting to create a meaningful story within a tight word count. Flash fiction can cover a wide range of genres and styles, and its brevity challenges writers to distill their storytelling abilities to essentials.

Hence, a "text-talk novel" is a novel written in the style of text messages or chat conversations, aiming to engage readers familiar with mobile communication. On the other hand, "flash fiction" refers to very short stories that convey complete narratives or ideas within a limited word count, challenging writers to create impactful stories in a condensed format.

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The work done by the object is 831.69 J.

Work can be defined as the product of mass and distance.

To calculate the work done by the object, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The work done by the object is 831.69 J.

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Answer:

Acceleration = 4 m/s

Explanation:

Acceleration = force divided by mass

So;

a = 200 ÷ 50 = 4

Given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton

Given the data in the question;

To determine the magnitude of the force of friction acting on the mass,

From Newton's laws of motion

[tex]F = m\ *\ a[/tex]

Where F is the force applied, m is the mass of the object and a is the acceleration of the object.

Now, we know that Kinetic Friction is always opposite of the direction of motion.

So, in the question, the force applied overcomes the friction to produce an acceleration of [tex]1.5 m/s^2[/tex]

Hence

[tex]F = F_k + ma[/tex]

Where [tex]F_k[/tex] is the kinetic friction

Now, we substitute our given values into the equation

[tex]10N = F_k +\ ( 5kg\ *\ 1.5m/s^2)\\\\10N = F_k +\ 7.5kg.m/s^2[/tex]

We know that, A newton is defined as [tex]1 kg.m/s^2[/tex]

Hence;

[tex]10N = F_k\ *\ 7.5N\\\\F_k = 10N \ -\ 7.5N\\\\F_k = 2.5N[/tex]

Therefore, given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton.

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This question involves the concept of artificial gravity.

The effective gravitational strength at outer rims is "0.9 g".

The effective gravitational strength at the outer rims can be given by the following formula:

[tex]v=\frac{1}{2\pi}\sqrt{\frac{a_c}{r}}\\\\a_c=4\pi^2v^2r[/tex]

where,

Therefore,

[tex]a_c = 4\pi^2(0.0167\ rev/s)^2(804.672\ m)\\a_c =8.82\ m/s^2\\\\In\ terms\ of\ g:\\\\a_c=(8.82\ m/s^2)(\frac{g}{9.81\ m/s^2})\\\\a_c = 0.9g[/tex]

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Answer: I'm not very good at all. I need help with determine the velocity of an object just before it hits the ground, given the object's mass and the distance it falls. For example, a .060 kg (or 60 g) ball falls from a 12 meter building. Also, assume it is free falling (no air resistance) and the average time it takes to hit the ground it 1.16 seconds.

Explanation:

Answer:

Explanation:

initial velocity, u = 43 m/s

final velocity, v = 3.38 m/s

time, t = 70 sec

acceleration, a = v - u / t

3.38 - 43 / 70

= -39.62/ 70

= -0.56 m/s^2

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Explanation:

The mechanical energy can be expressed as kinetic and potential energy, given by the equation;

ME=KE+PE

but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0

ME=KE

The equation of KE=0.5mv²

ME=0.5mv²

32 000=0.5(1600)v²

[tex]v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} [/tex]

[tex]v {}^{2} = \frac{32 \: 000}{800} [/tex]

[tex] {v}^{2} = 40[/tex]

[tex]v = \sqrt{40} = 6.324[/tex]

v=6.324 m/s :)

Answer:

0.5 m/s²

Explanation:

F=ma
F is force
m is mass
a is acceleration

F=ma
5 =  10 x a
a = 5/10
a = 0.5 m/s²

Answer:

ratio

Explanation:

Apex Verified

Answer:

2 m/s2

Explanation:

Newton's 2nd law:

F=ma

20 N= (10 kg)a

a= 2 m/s2

International system of measurements in helpful because all scientists can use them

International System of measurement abbreviated SI is the modern most widely accepted system of unit of measurement

The change in the internal energy of the system is 110 kJ.

Internal energy is defined as the energy associated with the random, disorder motions of molecules.

calculate the change in internal energy, we apply the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The change in the internal energy of the system is 110 kJ.

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Answer:

110.0kJ

Explanation:

The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.

.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.

ΔE=q+w

In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.

ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ

Answer:

19.5

Explanation:

16,17,18,18,21,24,24,29

(fourth (18) and fifth(21)) ÷2=

(18+21)÷2=

39÷2=

19.5 is median

Answer:

use math.way

Explanation:

i solved it.

The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as

P=16.6pascal, Option D is correct

Generally, the equation for the Pressure   is mathematically given as

P=force/Area

Therefore, In considering the one with the most pressure we look at the one with the most force/Area

In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides

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Answer:

it means absorption by a presynaptic nerve ending of a neurotransmitter that it has secreted.

Explanation: I hoped that helped please leave a 5 rate and thanks. Have a great day .

The factor increase in the relativistic energy  is 0.129.

The relativistic kinetic energy of the spacecraft is determined as follows;

[tex]K = (\frac{1}{\sqrt{1- \frac{v^2}{c^2} } } )mc^2[/tex]

where;

At 0.255 speed of light, the relativistic kinetic energy is calculated as follows;

[tex]K = (\frac{1}{\sqrt{1- \frac{(0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.065c^2}{c^2} } } )mc^2\\\\K = 1.034mc^2[/tex]

When the speed doubles, v = 2(0.255c)

[tex]K = (\frac{1}{\sqrt{1- \frac{(2 \times 0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.261c^2}{c^2} } } )mc^2\\\\K = 1.163mc^2[/tex]

ΔK = 1.163mc² - 1.034mc²

ΔK = 0.129mc²

Thus, the factor increase in the relativistic energy  is 0.129.

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Answer:

perpendicular

Explanation:

The projectile motion of an object can be described by two independent vector components that are horizontal and vertical motion.

The motion of an item hurled or projected into the air, subject only to gravity's acceleration, is known as projectile motion.

The item is known as a projectile, and the course it takes is known as a trajectory. Falling object motion is a simple one-dimensional kind of projectile motion with no horizontal movement.

The projectile's motion is divided into two parts: horizontal and vertical motion.

Because perpendicular motion components are independent of one another, these two motion components may be treated individually.

Hence two independent vector components are horizontal and vertical motion.

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Answer:

The earth rotates from West to east

Explanation:

For a bumper car A (296 kg) moving +3.74 m/s, and a bumper car B (222 kg) moving +1.85 m/s, the velocity of car A after the collision is mathematically given as

V1=4.977m/s

Generally, the equation for the Velocity of car A  is mathematically given as

[tex]V1=\frac{m1-m2v1}{m1+m2}v1 +\frac{2m_2}{m1+m2}v2[/tex]

Therefore

[tex]V1=\frac{296-222}{296+222}*23.74+\frac{2*222}{296+222}*1.85[/tex]

V1=4.977m/s

In conclusion, The velocity of car A after the collision

V1=4.977m/s

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Answer:3.74

Explanation:

it was given same goes for bumper car b