The expected value of the area of t is 1/12.
The length of the hands of the clock is 1. If a time of day is chosen uniformly at random, what is the expected value of the area of t?
The area of the triangle is given by the formula
A=1/2 ab sinC.
Here, we use Law of cosines to determine the angle C, which is enclosed by the hour and minute hands.
[tex](\cos C)_{h,m}=\frac{h^2+m^2-1}{2hm}[/tex]
So, we can write the expected value of the area of t as
[tex]\begin{aligned}E[A]&=\int_{0}^{2\pi}\frac{1}{2}(1)(1)sinC\left(\frac{1}{12}+\frac{1}{720}((Cos C)_{h,m})^2\right)dC \\ &=\frac{1}{24\pi}\int_{0}^{2\pi}(sinC+sin(11C))dC \\ &=\frac{1}{12}\end{aligned}[/tex]
Hence, the expected value of the area of t is 1/12.
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Values of 'x' satisfying: (x - 1)/(2 - x) >= 0
The values of x which satisfies the fractional inequality (x - 1) / (2 - x) ≥ 0 is x ≥ 1
What values of x satisfies the inequality?(x - 1) / (2 - x) ≥ 0
This is a fractional inequality whose numerator is (x - 1) and the denominator is (2 - x)
(x - 1) / (2 - x) ≥ 0
cross product
(x - 1) ≥ 0 × (2 - x)
(x - 1) ≥ 0
x - 1 ≥ 0
Add 1 to both sides
x ≥ 1
Therefore, x ≥ 1 satisfies the inequality.
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Work out the recipricol of 0.5
Answer:
the answer is 2
Step-by-step explanation:
this answer will be 200⁰0000000000⁰00000⁸⁰643367897⁶43677443⁵=5.0
The food service manager conducted a random survey of 200 students to determine their preference for new lunch menu items. There are 1,500 students in the school. Select all the manager’s predictions that are supported by the data
There are several predictions that the food service manager may make based on the data from the survey of 200 students regarding their preference for new lunch menu items. Let's examine some of these predictions and see if they are supported by the data.
The majority of students will like the new menu items.
The food service manager may predict that the majority of students in the school will like the new menu items, based on the positive responses from the 200 surveyed students. However, it's important to note that the sample size of 200 is relatively small compared to the total student population of 1,500. Therefore, it's possible that the preferences of the 200 surveyed students may not be representative of the preferences of the entire student population. To make a more accurate prediction, the manager may need to conduct a larger survey or pilot program to test the new menu items with a larger group of students.
Certain menu items will be more popular than others.
Based on the survey data, the food service manager may be able to identify which new menu items are more popular among the surveyed students. For example, if a majority of students indicate that they would like to see more vegetarian options, the manager may predict that introducing more vegetarian menu items will be popular among the broader student population. However, it's important to keep in mind that the preferences of the 200 surveyed students may not be representative of the preferences of the entire student population, so the manager may need to conduct additional research or testing to confirm these predictions.
The introduction of new menu items will increase overall satisfaction with the school lunch program.
If the survey data shows that a significant number of students are excited about the new menu items, the food service manager may predict that introducing these items will increase overall satisfaction with the school lunch program. However, it's important to note that satisfaction is a complex concept that can be influenced by many factors beyond just the menu items, such as the quality of service, cleanliness of the cafeteria, and overall atmosphere. Therefore, the manager may need to consider these other factors when predicting the impact of the new menu items on overall satisfaction with the lunch program.
In summary, while the data from the survey of 200 students can provide valuable insights into student preferences for new lunch menu items, it's important to interpret these results with caution and consider additional factors that may influence the broader student population. Conducting further research or testing can help to confirm these predictions and make more accurate decisions about the school lunch program.
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if two indistinguishable dice are rolled, what is the probability of the event {(3, 3), (2, 3), (1, 3)}? hint [see example 2.]
If two indistinguishable dice are rolled, what is the probability of the event {(3, 3), (2, 3), (1, 3)}The probability of the event {(3, 3), (2, 3), (1, 3)}
If two indistinguishable dice are rolled, it is 3/36 or 1/12.
Explanation: Indistinguishable dice are dice that appear identical to one another but do not have unique markings. As a result, indistinguishable dice will have the same number of faces, but the values on each face will be identical.
The total number of possible outcomes is 6 * 6 = 36 because there are six possible outcomes for each roll of a single die.
The probability of rolling the numbers (3, 3), (2, 3), or (1, 3) can be determined as follows: 3/36 or 1/12
For each die, there are six possible outcomes, so there are 6*6, or 36 possible outcomes for two dice.
Because (3, 3), (2, 3), and (1, 3) are the only possible ways to obtain a 3 on one of the dice and a 3, 2, or 1 on the other, the probability is 3/36 or 1/12.
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Find the Laplace transform Y(s) of the solution of the given initial value problem. Then invert to find y(t) . Write uc for the Heaviside function that turns on at c , not uc(t) .y'' + 16y = e^(?2t)u2y(0) = 0 y'(0) = 0Y(s) =y(t) =
The Laplace transform is a mathematical technique used to solve differential equations and analyze signals and systems in engineering, physics, and other fields. It is named after the French mathematician Pierre-Simon Laplace.
The Laplace transform of the given initial value problem is given by:
Y(s) = (2s^2 + 16) / (s^2(s^2+16))
Inverting the Laplace transform to find y(t) gives us:
y(t) = e^(-8t) * (1-cos(4t)) + 2sin(4t) + u2(t)
Where u2(t) is the Heaviside function that turns on at t = 2.
To find the Laplace transform of y(t), we first take the Laplace transform of both sides of the differential equation:
L(y''(t)) + 16L(y(t)) = L(e^(-2t)u_2(t))
Using the property L(y''(t)) = s^2Y(s) - sy(0) - y'(0) and noting that y(0) = 0 and y'(0) = 0, we can simplify to get:
s^2Y(s) + 16Y(s) = L(e^(-2t)u_2(t))
Using the property L(e^(-at)u_c(t)) = 1/(s + a) * e^(-cs), we can substitute to get:
s^2Y(s) + 16Y(s) = 1/(s + 2)^2
Now we can solve for Y(s):
Y(s) = 1/(s^2 + 16) * 1/(s + 2)^2
To find y(t), we need to take the inverse Laplace transform of Y(s). We can use partial fraction decomposition to simplify the expression:
Y(s) = A/(s^2 + 16) + B/(s + 2) + C/(s + 2)^2
Multiplying both sides by the denominator and solving for A, B, and C, we get:
A = 1/8
B = -1/4
C = 1/8
Substituting these values, we get:
Y(s) = 1/8 * 1/(s^2 + 16) - 1/4 * 1/(s + 2) + 1/8 * 1/(s + 2)^2
Taking the inverse Laplace transform of each term, we get:
y(t) = (1/8)sin(4t) - (1/4)e^(-2t) + (1/4)te^(-2t)
Therefore, the solution to the initial value problem y'' + 16y = e^(-2t)u_2(t), y(0) = 0, y'(0) = 0 is y(t) = (1/8)sin(4t) - (1/4)e^(-2t) + (1/4)te^(-2t).
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1. An Estate dealer sells houses and makes a commission of GHc3750 for the first house sold. He
receives GHc500 increase in commission for each additional house sold. How many houses must
she sell to reach a total commission of GHc6500?Arithmetic progression
The estate dealer must sell 13 houses to reach a total commission of GHc6500
What is number?Number is a mathematical object used to count, measure, and label. It is an abstract concept that is used in many different contexts. Numbers can be used to represent a variety of different things, including quantities, values, and relationships. They are also used to represent abstract concepts such as time and money. In mathematics, numbers are used to represent sets, operations, and relationships between elements. Numbers play a crucial role in almost all areas of mathematics, from the simple counting to the study of complex equations.
Arithmetic progression is a mathematical process
which involves adding a constant number to a sequence of numbers. In this case, the constant
number is GHc500, and the sequence of numbers is the commission of GHc3750 for the first house
sold.
To find the total number of houses that must be sold to reach a commission of GHc6500, we
need to use arithmetic progression. To do this, we need to calculate the arithmetic mean of the
two numbers GHc3750 and GHc6500. This is done by adding the two numbers and dividing by two.
The arithmetic mean is GHc5125.
We then subtract the initial commission of GHc3750 from the arithmetic mean to find the
increment in the commission for each additional house sold. This gives us the amount of GHc500
for each additional house sold.
To find the total number of houses that must be sold to reach a commission of GHc6500, we
then need to divide the total commission of GHc6500 by the GHc500 increment. This gives us
13 houses. Therefore, the estate dealer must sell 13 houses to reach a total commission of GHc6500.
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The trip from Winston to Carver takes 8 min longer during rush hour, when the average speed is 75 km/h, than in off-peak hours, when the average speed is 90 km/h. Find the distance of between the two towns
The trip from Winston to Carver takes 8 min longer during rush hour, when the average speed is 75 km/h, than in off-peak hours when the average speed is 90 km/h. the distance between the two towns is 60 km.
Considering the distance between the Winston and carver be "d", since here we got that during off-peak hours, the average speed is 90 km/h. so by using the formula of distance which is distance =speed x time=> d = 90t.
Whereas in rush hour, the average speed is 75 km/h, we also know that the trip takes 8 minutes longer during rush hour. calling the time it takes to travel during rush hour "t+8/60"( since 8 minutes is 8/60 of an hour). Now using the same formula as before:
d = 75(t + 8/60), since here we have two equations for d we can equal them to each other then we get :
90t = 75(t + 8/60)
=>90t = 75t + 10
=>90t-75t=10
=>t = 2/3
Since during the off-peak hours, it takes 2/3 hours or 40 minutes to travel the distance between Winston and carver. now using either equation to find the distance we get
d = 90t = 90(2/3) = 60 km or d = 75(t + 8/60) = 75(2/3 + 8/60) = 60 km
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NEED ANSWER IN THE NEXT 45 MINS PLSSS HELP
4. A venue sold 800 tickets to an event. If it cost
$2,500 to put on the event and the venue
profited at least $12,500, find c, the cost per
ticket.
A. c≥ $18.75
B. c≤ $18.75
C. c≥ $12.50
D. c≤ $12.50
Answer: the answer is A
Step-by-step explanation:
The value of 5^2000+5^1999/5^1999-5^1997
Answer:
Step-by-step explanation:
We can simplify the expression by factoring out a common factor of 5^1999 from the numerator:
5^2000 + 5^1999
= 5^1999(5 + 1)
= 5^1999(6)
And we can also factor out a common factor of 5^1997 from the denominator:
5^1999 - 5^1997
= 5^1997(5^2 - 1)
= 5^1997(24)
So the entire expression simplifies to:
(5^2000 + 5^1999) / (5^1999 - 5^1997)
= (5^1999 * 6) / (5^1997 * 24)
= (6/24) * 5^2
= 5/2
Therefore, the value of the expression is 5/2.
What’s the area?
7 yd
4 yd
7 yd
3 yd
The area is 49 square yards.
7 more than twice a number is 35.
Answer:
Let's call the number "x".
Then, we can write the equation:
7 + 2x = 35
To solve for x, we need to isolate x on one side of the equation.
Subtracting 7 from both sides:
2x = 28
Dividing both sides by 2:
x = 14
Therefore, the number is 14.
Step-by-step explanation:
* A chord PQ of a circle of radius 5 cm subtends an angle of 70° at the centre. Calculate the following: a) b) c) the length of the chord PQ the length of the arc PQ the perimeters of sector and segment.
Check the picture below.
so let's get the chord using the pythagorean theorem hmmm using sine
[tex]\sin(35^o )=\cfrac{\stackrel{opposite}{x}}{\underset{hypotenuse}{5}}\implies 5\sin(35^o )=x\implies 2.87\approx x~\hfill \underset{ PQ }{\stackrel{ 2.87+2.87 }{\approx \text{\LARGE 5.74}}}[/tex]
now let's get the arc
[tex]\textit{arc's length}\\\\ s = \cfrac{\theta \pi r}{180} ~~ \begin{cases} r=radius\\ \theta =\stackrel{degrees}{angle}\\[-0.5em] \hrulefill\\ \theta =70\\ r=5 \end{cases}\implies s=\cfrac{(70)\pi (5)}{180}\implies s\approx \text{\LARGE 6.11}[/tex]
and the perimeters, keeping in mind that for the sector is just the arc plus the radii, and for the segment is simply the arc plus the chord.
[tex]\stackrel{ \textit{sector's perimeter} }{5+5+6.11 ~~ \approx ~~} \text{\LARGE 16.11}\hspace{5em}\stackrel{ \textit{segment's perimeter} }{5.74+6.11 ~~ \approx ~~} \text{\LARGE 11.85}[/tex]
$21,000 is invested for 3 years with an APR of 3% and daily compounding. What is the balance after 3 years?
The balance after 3 years with daily compounding at an APR of 3% is $23,284.94.
To calculate the balance after 3 years with daily compounding, we need to use the formula for compound interest,
A = P(1 + r/n)^(nt)
Where,
A = the balance after 3 years
P = the initial investment, which is $21,000 in this case
r = the annual percentage rate, which is 3%
n = the number of times the interest is compounded per year. In this case, since it's daily compounding, n = 365 (the number of days in a year).
t = the number of years, which is 3 years.
Substituting the given values in the formula, we get
A = 21000(1 + 0.03/365)^(365×3)
A = $23,284.94
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The arrival time of an elevator in a 12 story dormitory is equally likely at any time range during the next 4.7 minutes. o. Calculate the expected arrival time. (Round your answer to 2 decimal place.) Expected arval time b. What is the probability that an elevator arrives in less than 1.8 minutes? (Round intermediate calculations to at least 4 decimal places and final answer to 3 decimal places.) c. What is the probability that the wait for an elevator is more than 1.8 minutes? (Round intermediate c places and final answer to 3 decimal places.)
a. Calculate the expected arrival time:
Given: Time range for arrival of elevator during the next 4.7 minutes is equally likely. The expected value of a discrete random variable is calculated by multiplying each possible value by its probability and adding up the products. So, we can calculate the expected value of the elevator arrival time by integrating the value of the probability density function (which is a straight line in this case) over the given interval. The area under the curve of the probability density function over the entire interval of possible values is 1. The expected arrival time (E) of the elevator is given by: E = (1/4.7) ∫(0 to 4.7) tdt= (1/4.7) [t²/2] [from 0 to 4.7]= 2.3596 minutes or 2.36 minutes (rounded to 2 decimal places)Therefore, the expected arrival time is 2.36 minutes.
b. Probability that an elevator arrives in less than 1.8 minutes:
To calculate the probability of an event happening, we need to find the area under the probability density function (pdf) over the given interval (in this case, less than 1.8 minutes). The pdf is a straight line with a slope of 1/4.7, so the equation of the line is: f(t) = (1/4.7) t. The probability of the elevator arriving in less than 1.8 minutes is: P(T < 1.8) = ∫(0 to 1.8) f(t) dt= ∫(0 to 1.8) (1/4.7) t dt= (1/4.7) [t²/2] [from 0 to 1.8]= 0.56765 (rounded to 4 decimal places)Therefore, the probability that an elevator arrives in less than 1.8 minutes is 0.568 (rounded to 3 decimal places).
c. Probability that the wait for an elevator is more than 1.8 minutes: The probability that the wait for an elevator is more than 1.8 minutes is the complement of the probability that it arrives in less than 1.8 minutes. P(T > 1.8) = 1 - P(T < 1.8) = 1 - 0.56765= 0.43235 (rounded to 3 decimal places)Therefore, the probability that the wait for an elevator is more than 1.8 minutes is 0.432 (rounded to 3 decimal places).
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A sphere is to be designed with a radius of 72 in. Use differentials to estimate the maximum error when measuring the volume of the sphere if the possible error in measuring the radius is 0.5 in. 4 (Hint: The formula for the volume of a sphere is V(r) = ²³.) O 452.39 in ³ O 16,286.02 in ³ O 65,144.07 in ³ O 32,572.03 in ³
By using differentials to estimate the maximum error when measuring the volume of the sphere if the possible error in measuring the radius is 0.5. It will be 32,572.03 in³. Which is option (d).
How to measure the maximum error while measuring the volume of a sphere?The possible error in measuring the radius of the sphere is 0.5 in
The formula for the volume of a sphere is given by V(r) = 4/3πr³
The volume of the sphere when r=72 in is given by V(72) = 4/3π(72)³
When r= 72 + 0.5 in= 72.5 in, the volume of the sphere can be calculated using the formula:
V(72.5) = 4/3π(72.5)³
The difference between these two volumes, V(72) and V(72.5), gives us the maximum error while measuring the volume of a sphere. It can be calculated as follows:
V(72.5) - V(72) = 4/3π(72.5)³ - 4/3π(72)³= 4/3π [ (72.5)³ - (72)³ ]= 4/3π [ (72 + 0.5)³ - 72³ ]= (4/3)π [ 3(72²)(0.5) + 3(72)(0.5²) + 0.5³ ]≈ (4/3)π [ 777.5 ]= 3.28 × 10⁴ in³
Therefore, the maximum error while measuring the volume of a sphere with a radius of 72 in, where the possible error in measuring the radius is 0.5 in, is approximately 3.28 × 10⁴ in³ or 32,572.03 in³. Therefore coorect option is (D).
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Describe the error in finding the distance between A(6, 2) and B(1,−4)
The error is the substitution of coordinates. Coordinates are ordered pairs of points that help us locate any point in a 2D plane or 3D space.
Cartesian coordinates, also known as the coordinates of a point in a 2D plane, are two integers, or occasionally a letter and a number, that identifies a specific point's precise location on a grid. This grid is referred to as a coordinate plane.
The distance between two points A(x₁, y₁) and B(x₂, y₂) is given by
[tex]AB = \sqrt{(x_{1} , x_{2})^{2} + (y_{1} - y_{2})^{2} }[/tex]
Observe that the x-coordinate of B is subtracted from the x-coordinate of A. This goes with the y-coordinates.
Therefore, the error is the substitution of coordinates.
The correct computation is
[tex]AB = \sqrt{(6-1)^{2} + [2 - (-4)]^{2} }[/tex]
[tex]= \sqrt{5^{2} + 6^{2} }[/tex]
[tex]= \sqrt{25 + 36} \\[/tex]
[tex]= \sqrt{61}[/tex]
≈ 7.81
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The complete question is as follows:
Describe and correct the error in finding the distance between A(6, 2) and B(1, -4). AB = √[(6 - 2)² + {2 - (-4)}²] = √(4² + 5²) = √(16 + 25) = √41 ≈ 6.4.
porter
Con
multiple CIVILE
all day
1. Write a ratio in simplified form of the vertical length to the horizontal length for the red triangle. (1 point)
02:3
03:2
01:1
Onone of the above
2:3 is a simple ratio of the red triangle's vertical and horizontal lengths.
Explain about the ratio?In order to put numbers into the proper perspective and so simplify difficulties, ratios are widely used in daily life.
A ratio is a tool used only to compare the sizes of two or much more numbers in relation to one another in mathematics. By making amounts easier to understand, ratios enable us to measure but also express quantities.
When translating from one currency to another, ratios are used.
Ratios can be used, for instance, to transform pound to euros or dollars.A ratio is used to determine wager winnings.Ratios can be used to determine how many drink bottles you'll require to host a party.In a recipe, ratios can be employed to produce a particular dish.For the red triangle:
horizontal length = 3 units
vertical length = 2 units
vertical length / horizontal length = 2/3
Thus, 2:3 is a simple ratio of the red triangle's vertical and horizontal lengths.
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Please help!!!!!!!
What is the axis of symmetry of the quadratic function below?
Answer:
x = -1
Step-by-step explanation:
The axis of symmetry is a line that divides the two sides of a parabola through the vertex.
which of the contexts below could be modeled by a linear function? the amount of a certain medication in a person's bloodstream decreases by 1/3 every week. a town's population shrinks at a rate of 2.2% every year. a certain population of 4 aggressive zombies quintuples every hour. snow was falling at a rate of 2 inches per hour.
The context that could be modeled by a linear function is "snow was falling at a rate of 2 inches per hour."
What is function?In mathematics, a function is a relation between a set of inputs and a set of possible outputs with the property that each input is related to exactly one output. In other words, a function takes an input and produces a corresponding output. It is often represented as a mathematical equation or a graph. Functions are used to model real-world phenomena and are an important tool in many areas of mathematics, science, and engineering.
Here,
A linear function describes a constant rate of change, and in this context, the rate of snowfall is constant at 2 inches per hour. The other contexts involve exponential or percentage change, which cannot be modeled by a linear function.
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Suppose E and F are two events, with the following probability table F F’
E 0.1 0.3 E' 0.2 0.4 a) Compute P(EF). b) Are E and F independent? Explain. c) Are E and F mutually exclusive? Explain.
a) With the following probability table F F, Let’s apply the formula for the intersection of events to solve the first part of the problem.
P(EF) = P(E) x P(F|E).We know that P(E) = 0.1 and that P(F|E) = 0.3. Therefore,P(EF) = P(E) x P(F|E) = 0.1 x 0.3 = 0.03.b) Two events E and F are independent if and only if their intersection is equal to the product of their individual probabilities.
P(EF) = P(E) x P(F) if and only if E and F are independent. We know that P(E) = 0.1 and that P(F) = 0.1 + 0.3 = 0.4. Therefore, P(EF) = 0.03, which is different from 0.1 x 0.4 = 0.04.
Since P(EF) is different from P(E) x P(F), it means that E and F are not independent.c) Two events E and F are mutually exclusive if and only if their intersection is the null set.P(EF) = ∅ if and only if E and F are mutually exclusive. We know that P(EF) = 0.03, which is not equal to the null set. Therefore, E and F are not mutually exclusive.
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Draw a diagram to help you set up an equation(s). Then solve the equation(s). Round all lengths to the neatest tenth and all angles to the nearest degree. (number 2)
The angle of elevation of the sun is approximately 22.6 degrees.
What is trigonometry?The partnerships between the sides and angles of triangles are the subject of the mathematical discipline of trigonometry. It is used exhaustively in fields such as physics, engineering, and assessing.
In a right triangle, the side opposite the right angle is called the hypotenuse, while the other two sides are called the legs.
Given that, 7.6 m flagpole casts an 18.2 m shadow.
Using trigonometric ratio we have:
tan(θ) = h / s
Substituting the values:
tan(θ) = 7.6 / 18.2
tan(θ) ≈ 0.417
θ ≈ 22.6°
Hence, the angle of elevation of the sun is approximately 22.6 degrees.
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The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10 .35 .40.10 Compute the following: E(X), E(X2), V(X), E(3x + 2), E (3X² + 2), V (3x + 2), E(X +1), V(X + 1).
To solve the question asked, you can say: Therefore, the final answers expressions are: E(X) = 5.8; E(X²) = 59.8; V(X) = 21.16 and E(3X + 2) = 20.4
what is expression ?In mathematics, an expression is a set of numbers, variables, and mathematical operations such as addition, subtraction, multiplication, division, and exponentiation that represent quantities or values. Expressions can be as simple as "3 + 4" or as complex as they can contain functions like "sin(x)" or "log(y)" . Expressions can be evaluated by substituting values for variables and performing mathematical operations in the order specified. For example, if x = 2, the expression "3x + 5" is 3(2) + 5 = 11. In mathematics, formulas are often used to describe real-world situations, create equations, and simplify complex math problems.
To calculate these values, we first need to compute the mean (expected value) and variance of X, which are given by:
E(X) = ∑[x * p(x)]
= 1 * 0.05 + 2 * 0.10 + 4 * 0.35 + 8 * 0.40 + 16 * 0.10
= 5.8
E(X²) = ∑[x² * p(x)]
= 1² * 0.05 + 2² * 0.10 + 4² * 0.35 + 8² * 0.40 + 16² * 0.10
= 59.8
V(X) = E(X²) - [E(X)]²
= 59.8 - 5.8²
= 21.16
E(3X + 2) = 3E(X) + 2
= 3(5.8) + 2
= 20.4
E(3X² + 2) = 3E(X²) + 2
= 3(59.8) + 2
= 179.4
V(3X + 2) = V(3X)
= 9V(X)
= 9(21.16)
= 190.44
E(X + 1) = E(X) + 1
= 5.8 + 1
= 6.8
V(X + 1) = V(X)
= 21.16
Therefore, the final answers are:
E(X) = 5.8
E(X²) = 59.8
V(X) = 21.16
E(3X + 2) = 20.4
E(3X² + 2) = 179.4
V(3X + 2) = 190.44
E(X + 1) = 6.8
V(X + 1) = 21.16
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Jack owns a company which sells handmade greetings cards.
Last year, the company sold 2340 cards and made a total profit of £3510.
This means the average profit per card was £1.50.
This year, Jack is aiming for the company to make 18% more total profit
than last year.
If the average profit per card is 22% lower than last year, how many cards
will Jack's company need to sell this year in order to make their target
profit?
Answer:
Jack's company needs to sell 3540 cards this year in order to make their target profit.
Step-by-step explanation:
Given the average profit per card last year was £1.50, and the average profit per card is 22% lower this year, this year's average profit per card will be:
[tex]\begin{aligned}\implies \sf Average\;profit\;per\;card&= \£1.50 - (22\% \;\text{of}\; \£1.50)\\&=\£1.50-0.22 \times \£1.50\\&=\£1.50-\£0.33\\&=\£1.17\end{aligned}[/tex]
Given the total profit Jack is aiming for this year is 18% more than last year's profit of £3510, this year's target profit is:
[tex]\begin{aligned}\implies \sf Target\;profit&=\£3510 + (18\%\;\text{of}\;\£3510)\\&=\£3510 + 0.18 \times \£3510\\&=\£3510 + \£631.80\\&=\£4141.80\end{aligned}[/tex]
To calculate how many cards Jack's company needs to sell to make this target profit, divide the total target profit by the average profit per card:
[tex]\begin{aligned}\implies \sf Number\;of\;cards&=\dfrac{4141.80}{1.17}\\\\&=3540\end{aligned}[/tex]
Therefore, Jack's company needs to sell 3540 cards this year in order to make their target profit.
Sparx 4: Item C
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This data is going to be plotted on a scatter graph.
Distance (km)
37 6 71 28
Height (m) 61 32 94 48
The start of the Distance axis is shown below.
At least how many squares wide does the grid need to be so that the data fits on
the graph?
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In response to the stated question, we may state that To accommodate scatter plot the provided data on the scatter graph, the grid must be at least 65 squares wide and 62 squares height.
What exactly is a scatter plot?"Scatter plots are graphs that show the association of two variables in a data collection. It is a two-dimensional plane or a Cartesian system that represents data points. The X-axis represents the independent variable or characteristic, while the Y-axis represents the dependent variable. These plots are sometimes referred to as scatter graphs or scatter diagrams."
To plot the supplied data on a scatter graph, we must ensure that the distance and height values are both within the grid.
The given distances are 37, 6, 71, and 28. As a result, the distance axis's minimum and maximum values are 6 and 71, respectively.
Height values are as follows: 61, 32, 94, 48. As a result, the lowest and maximum height axis values are 32 and 94, respectively. To ensure that all of the height values fit on the graph, we need a grid at least 94-32 = 62 squares tall.
To accommodate the provided data on the scatter graph, the grid must be at least 65 squares wide and 62 squares height.
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what is this pls help
Answer:
x = 45.
Step-by-step explanation:
We know the full angle of this is 180 degrees.
Given: (2x+45) + x = 180
First, collect like terms ( in this case 2x and x, 180 and 45 )
2x + x = 180 - 45
Then calculate:
3x = 135. ( Divide both sides by 3 )
x = 45
Find the perimeter of a polygon with
Points A (4,2) B (-4,8) C (-7,4) and D (-1,-4)
The required perimeter is 25+√61 units.
How to find perimeter?We can find the distance between each pair of consecutive points and then add them up to get the perimeter of the polygon.
Using the distance formula, the distance between points A and B is:
[tex]$$AB = \sqrt{(x_B - x_A)^2 + (y_B - y_A)^2} = \sqrt{(-4 - 4)^2 + (8 - 2)^2} = \sqrt{100} = 10$$[/tex]
Similarly, the distances between the other pairs of points are:
[tex]$$BC = \sqrt{(x_C - x_B)^2 + (y_C - y_B)^2} = \sqrt{(-7 + 4)^2 + (4 - 8)^2} = 5$$[/tex]
[tex]$$CD = \sqrt{(x_D - x_C)^2 + (y_D - y_C)^2} = \sqrt{(-1 + 7)^2 + (-4 - 4)^2} = 10$$[/tex]
[tex]$$DA = \sqrt{(x_A - x_D)^2 + (y_A - y_D)^2} = \sqrt{(4 + 1)^2 + (2 + 4)^2} = \sqrt{61}$$[/tex]
Therefore, the perimeter of the polygon is:
[tex]$$AB + BC + CD + DA = 10 + 5 + 10 + \sqrt{61}$$[/tex]
= 25+√61
Thus, required perimeter is 25+√61.
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The area of the composite figure is ? Round to two decimal places. (for example, 6.76)
Answer:
83219083219389238293829381293
Step-by-step explanation:
according to my calculations i am not smart
Suppose that 30 students take a quiz worth 30 points. The SD of the scores is 1 point. Which of the following gives the most reasonable description of the distribution of quiz scores?
A) All of the individual scores are one point apart.
B) The difference between the highest and lowest score is 1.
C) The difference between the 1st and 3rd quartile marks is 1.
D) A typical score is within 1 point of the mean.
The statement that gives the most reasonable description of the distribution of quiz scores is "A typical score is within 1 point of the mean." The correct answer is Option D.
What is Standard deviation?The standard deviation (SD) is a measure of the variability of data in a population. Standard deviation is a measure of how much each value differs from the mean (average) value of the data set.
What is the range?The difference between the highest and lowest values in a dataset is known as the range. It's a quick way to see the data's spread. If the range is big, it implies that the data is more diverse, while if it's small, it implies that the data is more consistent.
What is the first quartile?The first quartile (Q1) is the value that splits the lowest 25% of a data set from the rest of the data set. If we order the dataset from smallest to largest, the first quartile is the value at the 25th percentile.
What is the third quartile?The third quartile (Q3) is the value that splits the highest 25% of a data set from the rest of the data set. If we order the dataset from smallest to largest, the third quartile is the value at the 75th percentile.
What is the mean?The sum of all values in a dataset divided by the total number of values in the dataset is known as the mean. The mean, often known as the arithmetic mean, is one of the most basic measures of central tendency in statistics.
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Determine whether the Mean Value theorem can be applied to f on the closed interval [a, b]. (Select all that apply.) f(x) = 9x3, [1, 2] Yes, the Mean Value Theorem can be applied. No, because f is not continuous on the closed interval [a, b]. No, because fis not differentiable in the open interval (a, b). None of the above. If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = - w f(b) – f(a) 2. (Enter your answers as a comma-separated list. If the Mean Value Theorem cannot Ent b - a be applied, enter NA.) C=
Answer: Yes, the Mean Value Theorem can be applied to f(x) = 9x^3 on the closed interval [1, 2].
To find all values of c in the open interval (1, 2) such that f'(c) = (f(b) - f(a))/(b - a), we first find the derivative of f(x):
f'(x) = 27x^2
Then, we can use the Mean Value Theorem to find a value c in the open interval (1, 2) such that:
f'(c) = (f(2) - f(1))/(2 - 1)
27c^2 = 9(2^3 - 1^3)
27c^2 = 45
c^2 = 5/3
c = +/- sqrt(5/3)
Therefore, the values of c in the open interval (1, 2) such that f'(c) = (f(b) - f(a))/(b - a) are:
c = sqrt(5/3), -sqrt(5/3)
Note that these values are not in the closed interval [1, 2], as they are not between 1 and 2, but they are in the open interval (1, 2).
Step-by-step explanation:
A sample of automobiles traversing a certain stretch of highway is selected. Each automobile travels at a roughly constant rate of speed, though speed does vary from auto to auto. Let x = speed and y = time needed to traverse this segment of highway. Would the sample correlation coefficient be closest to 0.9,0.3,-3,or -0.9? Explain.
The right answer is -0.9, but I do not know the reason.
The sample correlation coefficient would be closest to -0.9.
Here's why:
Correlation Coefficient: The correlation coefficient is a statistical measure of the degree of correlation (linear relationship) between two variables. Pearson’s correlation coefficient is the most widely used correlation coefficient to assess the correlation between variables.
Pearson’s correlation coefficient (r) ranges from -1 to 1. A value of -1 denotes a perfect negative correlation, 1 denotes a perfect positive correlation, and 0 denotes no correlation. There is a negative correlation between speed and time. As the speed of the car increases, the time needed to traverse the segment decreases. So, the sample correlation coefficient would be negative.
Since the sample size is large enough, the sample correlation coefficient should be close to the population correlation coefficient. The population correlation coefficient between speed and time should be close to -1, which implies that the sample correlation coefficient should be close to -1.
Therefore, the sample correlation coefficient would be closest to -0.9.
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