In a vacuum, a feather and a coin will fall with equal acceleration, but not with equal forces, momentum, or kinetic energy.
What is kinetic energy?The drag force created by the air causes the feather to descend more slowly than the coin when there is air present. Both objects will descend with the same acceleration owing to gravity if there is no air present since there will be no air resistance.
Because the acceleration caused by gravity is constant, all objects in free fall will experience the same acceleration, which is around 9.8 m/s2, regardless of their mass. This implies that in a vacuum, the feather and the coin will descend at the same pace.
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11. A car travels 30 km at a uniform speed of 40 km/hr and the next 30 km at a uniform speed of 20 km/hr. Find its average speed.
Answer:
The average speed of the car is 26.66kmh−1.
Explanation:
Tama po yan promise
Answer:
The average speed of the car can be calculated using the formula: average speed = total distance / total time.
Let's call the time taken to travel the first 30 km t1 and the time taken to travel the next 30 km t2. We know that:
t1 = 30 / 40 = 0.75 hours
t2 = 30 / 20 = 1.5 hours
The total distance is 60 km and the total time taken is t1 + t2 = 0.75 + 1.5 = 2.25 hours.
So the average speed is 60 / 2.25 = 26.67 km/hr.
Explanation:
In a hydraulic garage lift, the small piston has a radius of 5. 0 cm and the large piston has a radius of 15 cm. What force must be applied on the small piston in order to lift a car weighing 20,000 n on the large piston? assume the pistons each have negligible weight.
The force applied on the small piston in order to lift 20,000N on the large piston is 0.8×10³ N.
According to Pascal's law, the pressure distribution in the confined fluid is equal in all directions. Therefore, if the cross-sectional area of the output cylinder is larger than the input cylinder, then the output force is larger than the input force. The ratio of the output force to the input force on the input piston is called the mechanical advantage, and if it is greater than one, then force multiplication takes place.
Given, F₁=20000 N is the weight of the car
r₂=4.0 cm is the radius of the small piston
r₁=20cm is the radius of the large piston
F₂ is the force applied on the small piston.
Pressure in the large cylinder = Pressure in the smaller cylinder,
P₁=P₂
F₁/A₁=F₂/A₂
F₂= 0.8×10³ N.
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what angular resolution would you need to see the sun and jupiter as distinct points of light?
To see the Sun and Jupiter as distinct points of light from a distance of 10 light-years, we would need an angular resolution of approximately 0.57 arcseconds.
To calculate the angular resolution required to see the Sun and Jupiter as distinct points of light from a distance of 10 light-years, we can use the formula:
θ = 1.22 λ/D
Where θ is the angular resolution in radians, λ is the wavelength of the light being observed, and D is the diameter of the telescope lens or mirror.
Assuming that we are observing in visible light with a wavelength of 550 nanometers, and using the diameter of the Hubble Space Telescope's primary mirror as an example (which is approximately 2.4 meters), we can plug in these values to get:
θ = 1.22 (550 × 10^-9 meters) / 2.4 meters
θ ≈ 2.8 × 10^-9 radians
To convert this to arcseconds (a more commonly used unit of angular resolution), we can multiply by the conversion factor of 206,265 arcseconds/radian:
θ ≈ 0.57 arcseconds
Therefore, to see the Sun and Jupiter as distinct points of light from a distance of 10 light-years, we would need an angular resolution of approximately 0.57 arcseconds. This is an extremely high level of resolution, beyond the capabilities of most ground-based telescopes, but it can be achieved with space-based observatories like the Hubble Space Telescope.
Complete question:
Suppose you were looking at our own Solar System from a distance of 10 light-years: What angular resolution would you need to see the Sun and Jupiter as distinct points of light?
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Which one of the following properties most fundamentally distinguishes mechanical waves from electromagnetic waves?A)Mechanical waves have crests and troughs. B)Mechanical waves require a medium for propagation. C) Mechanical waves have well-defined wavelengths. D)Mechanical waves move at a finite speed
'Mechanical waves require a medium for propagation' is the statement which most fundamentally distinguishes mechanical waves from electromagnetic waves. Correct option is B.
A wave's height (amplitude), frequency, and length are all ways to describe it. Any wave can be thought of as an energy-transferring disturbance.
Compared to mechanical waves, electromagnetic waves are different. The electromagnetic waves can move in vacuums since they have the ability, but sound waves and water cannot, so they require a medium to spread.
Electric and magnetic fields oscillate along with electromagnetic waves in a manner that is perpendicular to the direction of propagation.
Thus, mechanical waves require a medium for propagation.
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If you were looking for exploding stars, which wavelength band would you likely like to observe?
I would look for these wavelengths since exploding stars mostly produce gamma-rays and X-rays.
What types of telescopes see using gamma rays?Two primary instruments make up the Fermi telescope. It has a sizable telescope that discovers gamma rays with energies between 10 million and 300 billion times that of visible light. Moreover, the spacecraft carries detectors for observing gamma-ray bursts. Gamma ray bursts are short gamma ray flashes.
What wavelengths are employed to investigate star-forming areas?IR perspective Dust is significantly easier for infrared light to penetrate than optical light. For this reason, infrared astronomy is best suited for gaining knowledge of the universe's dusty regions. Star-forming areas are one instance.
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How do you convert Kelvin to Celsius formula?
Answer:
Below
Explanation:
To convert K to °C just subtract 273.15 from the K value
What is the light source for a telescope?
The light for a telescope comes from astronomical objects like stars, galaxies, and planets, not from an internal source.
The main job of the telescope is to gather and concentrate this light, enlarging and enhancing the image via a variety of mirrors or lenses.
The light is collected and focused at a focal point by the telescope's objective lens or primary mirror, where it is enlarged by an eyepiece or camera.
Depending on the user's intended use of the telescope for scientific or observational purposes, telescopes may be built to focus on a particular kind of light, such as visible light, infrared, ultraviolet, or radio waves.
To reduce interference from the Earth's atmosphere, telescopes can also be installed on the surface of the earth or in orbit.
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A star that begins with a mass 8 to 20 times that of the Sun’s mass will
A star that begins with a mass between about 8 and 20 times the Sun's mass will end up with a core that is too massive to be supported by electron pressure. Such a star comes to a violent end. Neutron star form when fusion ends.
What is a neutron star?
A type of celestial object known as a neutron star is created from the remains of a massive star that has experienced a supernova explosion. With a mass comparable to that of the sun but squeezed into a sphere about 20 kilometres in diameter, neutron stars are extraordinarily dense. Because of this tremendous density, the gravitational field is approximately one billion times greater than on Earth.Neutrons are non-charged subatomic particles that make up nearly the whole mass of neutron stars. The neutron star is effectively a huge atomic nucleus since these neutrons are crammed so closely together.To know more about neutron star, click the link given below:
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Over the course of a year, stars should appear to move back and forth, with stars closer to us moving a larger distance. however, they did not measure stellar parallax—the stars did not appear to move back and forth at all over the course of a year. what is the most likely reason for this apparent lack of motion?
The most likely reason for apparent lack of motion is that the stars are too far away to measure their parallax.
What is the reason for this apparent lack of motion?Reason for apparent lack of motion is that stars are too far away to measure their parallax.
Stellar parallax is the apparent shift in star's position due to the Earth's motion around the Sun. Size of this shift is proportional to the distance of star, so it is easier to measure parallax for stars that are closer to us. For stars that are too far away, parallax is too small to measure with the current technology and they appear to be fixed in place. So, lack of apparent motion for stars over the course of a year could be due to the great distances from Earth and making it difficult to detect their parallax.
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The most likely reason for apparent lack of motion is that the stars are too far away to measure their parallax. What is the reason for this apparent lack of motion?Reason for apparent lack of motion is that stars are too far away to measure their parallax. Stellar parallax is the apparent shift in star's position due to the Earth's motion around the Sun. Size of this shift is proportional to the distance of star, so it is easier to measure parallax for stars that are closer to us. For stars that are too far away, parallax is too small to measure with the current technology and they appear to be fixed in place. So, lack of apparent motion for stars over the course of a year could be due to the great distances from Earth and making it difficult to detect their parallax.To know more about parallax, refer
A pendulum has a period of 5 seconds. If the length of the string of the pendulum is quadrupled,
what is the new period of the pendulum?
A mass of 0. 40 kg, hanging from a spring with a spring constant of 160 n/m, is set into an up-and-down simple harmonic motion. What is the speed of the mass when moving through the equilibrium point? the starting displacement from equilibrium is 0. 10 m.
Given:
[tex]m=0.40kg[/tex]
[tex]k=160\frac{N}{m}[/tex]
[tex]A=0.10m[/tex]
We know that the velocity of a mass attached to a spring is greatest when passing through equilibrium. Using the following formulas we can compute velocity.
[tex]v_{max} =\pm Aw[/tex] and [tex]w=\sqrt{\frac{k}{m} }[/tex] [tex]\Longrightarrow v_{max} =\pm A\sqrt{\frac{k}{m} }[/tex]
[tex]\Longrightarrow v_{max} =\pm A\sqrt{\frac{k}{m} }[/tex]
[tex]\Longrightarrow v_{max} =\pm (0.10)\sqrt{\frac{160}{0.40} }[/tex]
[tex]\Longrightarrow v_{max} =\pm (0.10)(20) }[/tex]
[tex]\Longrightarrow v_{max} =\pm 2.0\frac{m}{s}[/tex]
what did newton do in an attempt to separate the visible light spectrum?
Answer:
He used a prism.
Explanation:
Newton set up a prism near his window, and projected a beautiful color spectrum 22 feet onto the far wall.
the first basic step in solving force and motion problems generally involves identifying all of the forces acting on an object. this tactics box provides a step-by-step method for identifying each force in a problem.
true/false
The statement "the first basic step in solving force and motion problems generally involves identifying all of the forces acting on an object" is true because the first step of question is to draw FBD.
A free body diagram (FBD) is a visual representation that shows all the forces acting on an object. It is a simple sketch that isolates an object of interest and shows all the forces acting on it, including the direction and magnitude of each force.
Free body diagrams are commonly used in physics and engineering to analyze and solve problems related to force and motion. By drawing a free body diagram, one can easily identify all the forces acting on an object and determine their net effect on the object's motion.
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A student measures the mass of a solution before and after a chemical reaction takes place. In both cases the students measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. The student realizes that the ranges of uncertainty for each measurement overlap exactly. Which claim can the student make? The mass definitely stayed the same because the measurement of 50.25 g was obtained each time. The mass definitely stayed the same because the ranges of uncertainty overlap exactly. We can’t know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainty overlap.
The correct option for chemical reaction is "The mass definitely stayed the same because the ranges of uncertainty overlap exactly."
As given that student measures the mass of a solution before and after a chemical reaction takes place that is he measure the mass which is 50.25g with uncertainty of 0.05g. In this case the mass would be same .
Mass is a quantitative measure of inertia in physics and a fundamental property of all matter. In effect, it is the resistance that an object offers to changes in velocity or position when a force is applied.
The greater the mass of an object, the smaller the change caused by an applied force. The unit of mass in the International System of Units (SI) is the kilogram, which is defined by Planck's constant and is equal to 6.62607015 × 10−34 joule-seconds.
One joule is equal to one kilogram square meter per second. Seconds and meters are already defined by other physical constants, so kilograms are determined by the exact measurement of Planck's constant.
(Until 2019, the kilogram was defined by a platinum iridium cylinder called the International Prototype Kilogram held at the International Bureau for Weights and Measures in Sèvres, France.)
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Classify the conditions given as indicating that a reaction is at equilibrium, is not at equilibrium, or that the conditions may occur in either state. At equilibrium Not at equilibrium May or may not be at equilibrium The forward and reverse reactions occur at equal rates. The concentration of reactants is slowly increasing. The products and reactants have equal concentrations. The concentration of products greater than the concentration The concentrations of productsThe forward reaction is is and reactants are constant. occurring at a very slow rate. of reactants.
The reaction is at equilibrium are option a, c, d. The reaction is not at equilibrium are choices b, e. The reaction that may or may not be at equilibrium are choices f.
a. The forward and reverse reactions occur at equal rates. - The reaction is at equilibrium.
b. The concentration of reactants is slowly increasing. - The reaction is not at equilibrium.
c. The products and reactants have equal concentrations. - The reaction is at equilibrium.
d. The concentration of products and reactants are constant. - The reaction is at equilibrium.
e. The concentrations of products is greater than the concentration of reactants. - The reaction is not at equilibrium.
f. The forward reaction is occurring at a very slow rate. - It is not possible to determine the equilibrium state of the reaction as the rate of the forward reaction depends on the concentration of the reactants and the activation energy of the reaction.
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--The complete question is, Classify the conditions given as indicating that a reaction is at equilibrium, is not at equilibrium, or that the conditions may occur in either state.
a. The forward and reverse reactions occur at equal rates.
b. The concentration of reactants is slowly increasing.
c. The products and reactants have equal concentrations.
d. The concentration of products and reactants are constant
e. The concentrations of products is greater than the concentration of reactants
f. The forward reaction is occurring at a very slow rate.--
how does a van de graaff generator relate to lightning?
Although the accumulation and release of static electricity occurs in both lightning and a Van de Graaff generator, their complexity and size are different.
There are some significant distinctions between a Van de Graaff generator and lightning, despite the fact that both involve the accumulation and release of static electricity.
Using a moving belt, a Van de Graaff generator builds up a lot of static charge on a metal sphere or other item. The metal and the belt's friction move electrons from one surface to the other, causing a buildup of charge. A visible spark or even a minor arc can be produced between the sphere and another conductor when the charge accumulates up to a certain level.
On the other hand, lightning is a natural occurrence that happens when there is a buildup of static charge.
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Only two forces act on an object (mass = 3. 00 kg), as in the drawing. Find the magnitude and direction (relative to the x axis) of the acceleration of the object.
The magnitude of the acceleration of the object is 17.6 m/s2 and the direction is 30.2° relative to the x axis.
What is accelaration?Acceleration is the rate if we object increases speed velocity of rate and change it is the change of the position of an object is relation can be either positive when the speed of an object increasing a negative in the speed of the object is decreasing.
The magnitude and direction of the acceleration of the object can be found by using Newton's Second Law of Motion. Newton's Second Law states that the net force on an object is equal to the mass of the object multiplied by its acceleration. Therefore, the net force of the two forces acting on the object (F1 and F2) can be found using the equation: Fnet = ma.
For this problem, we can assume that the mass of the object is 3.00 kg, so the equation becomes: Fnet = 3.00 kg × a.
We can now solve for the acceleration by substituting the values of the two forces (F1 and F2) into the equation. The two forces can be found by using the equation for the magnitude of a force: F = ma.
For force F1, we can assume that its magnitude is 10 N and its direction is 45° relative to the x axis. Therefore, the equation for F1 becomes: F1 = (3.00 kg) × (10 N) × cos(45°).
For force F2, we can assume that its magnitude is 8 N and its direction is -30° relative to the x axis. Therefore, the equation for F2 becomes: F2 = (3.00 kg) × (8 N) × cos(-30°).
Substituting these two equations into the equation for net force (Fnet = ma), we get:
Fnet = (3.00 kg) × (10 N × cos(45°) + 8 N × cos(-30°)).
Solving for the acceleration, we get: a = (10 N × cos(45°) + 8 N × cos(-30°))/3.00 kg.
Therefore, the magnitude of the acceleration of the object is 17.6 m/s2 and the direction is 30.2° relative to the x axis.
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The displacement (in meters) of a particle moving in a straight line is given by the equation of motion s = 8 t2 , where t is measured in seconds. Find the velocity (in m/s) of the particle at times t = a, t = 1, t = 2, and t = 3.
The velocity of the particle is 0 m/s since the displacement is 0 when t = a.
What is the velocity ?Velocity is a measure of the rate and direction of change in the position of an object. It is a vector quantity, consisting of both speed and direction. Velocity is most commonly expressed in terms of distance traveled per unit of time. The average velocity of an object over a period of time is its displacement divided by the time duration. Speed, on the other hand, is a scalar quantity and is the magnitude of the velocity vector. It is the rate of change in position of an object, regardless of direction.
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The velocity variates different at different time i.e. when
t = 1, v = -16m/s
t = 2, v = -2.25m/s
t = 3, v = -1.77m/s
What is Velocity?The concept of velocity refers to the rate and direction of motion of a point. For instance, the orientation of a circular path is always perpendicular to the line that connects a point to the center of the circle. A point always advances down a route that is perpendicular to it (a radius). The magnitude of the velocity is the rate of motion of the point along its path through time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. For instance, the average speed of a train traveling 100 kilometers in two hours is 50 km/h.
v(t) =ds / dt = d(8/t²) / dt = -16/t³
Velocity of the particle at time t = a
v(a)= - 16 / a³
Velocity of the particle at time t = 1
v(1) = -16m/s
Velocity of the particle at time t = 2
v(2) = -2.25m/s
Velocity of the particle at time t = 3 v(3) = - 1.77m/s
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What are some disadvantages of a vertical axis wind turbine?
Vertical axis wind turbines (VAWTs) have some disadvantages compared to horizontal axis wind turbines (HAWTs). Here are a few:
What are the disadvantages ?Lower efficiency: VAWTs have lower efficiency than HAWTs, meaning that they produce less electricity per unit of wind energy. This is partly due to the fact that VAWTs operate at lower wind speeds, and partly due to their design.Higher maintenance: VAWTs have more moving parts than HAWTs, which can make them more expensive to maintain over time.Higher cost: Because VAWTs are less common than HAWTs, they can be more expensive to manufacture and install.Noise and vibration: Some VAWTs can be noisier and produce more vibration than HAWTs, which can be a problem in residential areas.To know more about VAWT , check out :
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Sort each item into the correct bin based on whether it describes lunar eclipses or solar eclipses.
- occurs when the Moon is on the direct opposite side of Earth from the Sun
- occurs when Earth's shadow falls on the Moon
- can occur only at full moon
- can be seen by anyone on Earth's night side at the time
- occurs when the Moon comes directly between Earth and the Sun
- occurs when the Moon's shadow falls on Earth
- can occur only at new moon
- can be seen only along a relatively narrow path on Earth
Sort each item into the correct bin based on whether it describes lunar eclipses or solar eclipses.
- occurs when the Moon is on the direct opposite side of Earth from the Sun
What exactly is a lunar eclipse and a solar eclipse?Traditionally, eclipses are classified into two types: solar and lunar. Solar eclipses occur when the Moon passes between Earth and the Sun, casting a moving shadow on the Earth's surface. Lunar eclipses occur when the Earth passes between the Sun and the Moon, producing a shadow on the Moon.
A lunar eclipse is sometimes referred to as a blood moon since the only sunlight reaching the moon during an eclipse travels via Earth's atmosphere.
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the space between the parietal layer and visceral layer of the pericardium contains ______.
Answer: serous fluid
Explanation: The space between these two serous layers, the parietal and the visceral, is the pericardial cavity, which contains pericardial fluid.
Which type of forces are subjected in truss?
Tension and compression forces act on diagonal and vertical members respectively in a truss structure.
A truss is a construction that comprises of a progression of interconnected triangles, intended to disperse stacks and give security. The powers that follow up on a bracket can be characterized into two kinds: pressure and pressure powers.
Tension powers are powers that draw on a part, like a rope or link. In a support, strain powers follow up on the corner to corner individuals that structure the triangles. These individuals are under pressure since they are being pulled separated.
Compression forces are forces that push on a part, like a segment or shaft. In a support, pressure powers follow up on the upward individuals that associate the top and base harmonies of the bracket. These individuals are under pressure since they are being crushed together.
Notwithstanding pressure and pressure powers, brackets can likewise be exposed to twisting minutes and shear powers, which are brought about by outer burdens following up on the support.
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A box sits on the horizontal bed of a truck accelerating to the left. Static friction between the box and the truck keeps the box from sliding around as the truck accelerates. The work done on the box by the static friction force as the accelerating truck moves a distance D to the left is:a. positiveb. zeroc. negatived. dependent on the speed of the truck
The work done on the box by the static friction force is zero.
What is work done ?Work is a measure of the energy transferred to or from an object by a force when the object is displaced. The amount of work done is defined as the product of the magnitude of the force and the distance over which the force is applied. It could be written as
Work (W) = Force (F) x Distance (d) x cos(theta)
where theta is the angle between the force and the displacement.
When a force is applied to an object, work is done if there is displacement in the direction of the force. If there is no displacement, no work is done. If the force is perpendicular to the displacement, no work is done, as the cosine of 90 degrees is zero.
Work is a scalar quantity and is measured in joules (J) in the SI system. One joule of work is done when a force of one newton (N) is applied over a distance of one meter (m) in the direction of the force.
Work can be either positive or negative, depending on the direction of the force and the displacement. When the force and displacement are in the same direction, the work is positive. When the force and displacement are in opposite directions, the work is negative.
The work done on the box by the static friction force is zero.
This is because the static friction force acts perpendicular to the displacement of the box. Therefore, the angle between the static friction force and the displacement of the box is 90 degrees. In this case, the work done by the static friction force is given by the dot product of the force and the displacement, which is equal to Fdcos(theta), where theta is the angle between the force and the displacement. Since cos(90) = 0, the work done by the static friction force is zero.
Note that although the static friction force does no work on the box, it does provide the necessary force to keep the box in place and prevent it from sliding around as the truck accelerates.
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Suppose that 8 J of work is needed to stretch a spring from its natural length of 9 m to a length of 11 m.
(a) How much work is needed to stretch the spring from 16 m to 19 m?
(b) How far beyond its natural length will a force of 72 N keep the spring stretched?
The work done to stretch the spring from 16m to 19m will be 18 Joules and the natural length with which a force of about 72 N is used to keep the spring stretched will be 7.5m.
What is Spring force?Spring force can be defined as the force which acts in the opposite direction to the displacement of the object. In order to stretch or compress the spring some amount of work has to be done. Which is given as,
where k = spring constant of the spring
x = compression of spring
W= Work required or spring work
Initial length is given by 9m
final length is given by 11m
When spring is stretched change in the length occurs denoted by x
x = final length - initial length = (11 - 9) = 2m
W = 1/2Kx²
W = 1/2 K (2)²
8×2 = 4K
16/4 = K
K = 4 N/m
(a) work is needed to stretch the spring from 16m to 19m
stretching length from 16 to 19m will be 3m
stretching length from cm to 30 is 40 cm is 10 cm which is 0.1m
x = final stretch of the spring = 16 - 19 = 3m
Work needed to stretch the spring from 16m to 19m is given
W = (0.5)K(3²)
W = (0.5)(4)(3²)
W = 2.0 × 9
W = 18 Joules
x is stretch of the spring beyond natural length
F = force = 72 N
Spring force is given as
F = k x
30 = (4) x
x = 7.5m
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A balloon is filled with 35. 0 l of helium in the morning when the temperature is 20. 00 c. By noon the temperature has risen to 45. 00 c. What is the new volume of the balloon?.
To solve this problem, we need to use the ideal gas law, which states that the pressure (P), volume (V), number of moles of gas (n), and temperature (T) of a gas are related by the equation PV = nRT.
What is ideal gas law ?We can write: Assuming that the pressure and amount of helium moles remain constant.P1V1/T1 = P2V2/T2
where P1 denotes the starting pressure, V1 the starting volume, T1 the starting temperature, P2 the ending pressure, V2 the ending volume, and T2 the ending temperatureInputting the values provided yields:
P1V1/T1 = P2V2/T2
As long as the pressure and helium moles are constant, we can write:V₁/T₁ = V₂/T₂
Inputting the values provided yields:
V2 = V1 (318.15 K/293.15 K) (T2/T1) = 35.0 L 38.1 L
The balloon's new capacity is 38.1 L as a result.
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Two coherent sources of radio waves, A and B, are 5.00 meters apart. Each source emits waves with wavelength 6.00 meters. Consider points along the line connecting the two sources.1) At what distance from source A is there constructive interference between points A and B?2) At what distances from source A is there destructive interference between points A and B? Note that there will be two separate interference fringes between point A and point B.
Constructive interference is exactly at source A. Distance from source A to points of destructive interference are 3.00 meters and 10.50 meters.
When two coherent sources, A and B, emit radio waves with the same wavelength and are separated by a certain distance, they can interfere constructively or destructively at different points along the line connecting the sources. To determine the distances at which constructive interference and destructive interference occur, we can use the following equations:
For constructive interference:
d = mλ
For destructive interference:
d = (m + 1/2)λ
where d is the distance from source A to the interference fringe, λ is the wavelength of the radio waves, and m is an integer representing the order of the interference fringe.
To find the distance from source A to the point of constructive interference, we can use the equation for constructive interference with m = 0 (the first order of interference):
d = mλ = 0 x 6.00 m = 0 m
This means that the first point of constructive interference is exactly at source A.
At what distances from source A is there destructive interference between points A and B?
To find the distances from source A to the points of destructive interference, we can use the equation for destructive interference with m = 0 (the first order of interference) and m = 1 (the second order of interference):
For the first order of interference:
d = (m + 1/2)λ = (0 + 1/2) x 6.00 m = 3.00 m
For the second order of interference:
d = (m + 1/2)λ = (1 + 1/2) x 6.00 m = 10.50 m
Therefore, the distances from source A to the points of destructive interference are 3.00 meters and 10.50 meters, respectively. These are the two separate interference fringes that occur between point A and point B.
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a 5 ohm resistor is connected across a battery of 6 volts. Calculate the current flowing through the resistor and the energy dissipated as heat in 10 seconds
Answer:
To calculate the current flowing through the resistor, we can use Ohm's Law, which states that V = IR, where V is the voltage, I is the current, and R is the resistance.
In this case, the voltage is 6 volts and the resistance is 5 ohms, so:
I = V/R = 6/5 = 1.2 amps
To calculate the energy dissipated as heat in 10 seconds, we can use the formula:
E = I^2Rt, where E is the energy, I is the current, R is the resistance, and t is the time.
Substituting the values we have:
E = (1.2)^2 x 5 x 10 = 72 joules
Therefore, the current flowing through the resistor is 1.2 amps, and the energy dissipated as heat in 10 seconds is 72 joules.
A car starts from rest on a curve with a radius of 130m and tangential acceleration of 1.3m/s2 .Through what angle will the car have traveled when the magnitude of its total acceleration is 2.2m/s2 ?
the car's angle of travel be when its entire acceleration is 2.2m/s2 = 23.58°
What causes acceleration?Acceleration is the change in speed that occurs quickly. Generally speaking, but not always, acceleration denotes a shift in speed. Even while it travels in a circular motion, an object's velocity direction is changing, thus it keeps gaining speed.
What is velocity, and what is the SI unit of acceleration?In physics, acceleration is the rate at which an object's velocity varies in relation to time. The result of all forces acting on an item is its acceleration, according to Newton's Second Law. The SI unit for acceleration is the metre squared (m s2).
According to the given information:Tangential acceleration, at = 1.2 m/s²
Total acceleration, a = 3 m/s²
Let the angle is Ф.
According to the formula
a² = a[tex]_t[/tex]² + ar²
9 = (1.2)² + ar²
ar =3 m/s²m
tanФ = 0.4364
Ф = 23.58°
the car's angle of travel be when its entire acceleration is 2.2m/s2 = 23.58°
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Find the net electric force that the two charges would exert on an electron placed at point on the x -axis at x = 0. 200 m.
The net electric force that the two charges would exert on an electron placed at point x = 0.200 m is:F = -2.40 x 10-9 N.
What is force?Force is an infants that causes an object to change its motion direction say for other physical quantity force can be caused by physical contact or they can be created by feels like rabbit in magnetism for skin also be internal such as force of fraction tension in compression.
The net electric force that the two charges would exert on an electron placed at point x = 0. 200 m is calculated using Coulomb’s law. Coulomb’s law states that the magnitude of the force between two point charges is directly proportional to the product of the charges, and inversely proportional to the square of the distance between them.
The equation for the electric force is F = k * q1 * q2 / r2, where k is Coulomb’s constant (8.99 x 109 Nm2/C2), q1 and q2 are the two charges, and r is the distance between them.
In this case, the two charges are q1 = +4.0 x 10-8 C and q2 = -4.0 x 10-8 C. The distance between them is r = 0.2 m.
Therefore, the net electric force that the two charges would exert on an electron placed at point x = 0.200 m is:
F = (8.99 x 109 Nm2/C2) * (4.0 x 10-8 C) * (-4.0 x 10-8 C) / (0.2 m)2
F = -2.40 x 10-9 N
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The net electric force that the two charges would exert on an electron placed at point x = 0.200 m is:[tex]F = -2.40 \times 10^{-9} N.[/tex]
What is force?Force is an infants that causes an object to change its motion direction say for other physical quantity force can be caused by physical contact or they can be created by feels like rabbit in magnetism for skin also be internal such as force of fraction tension in compression.
The net electric force that the two charges would exert on an electron placed at point x = 0. 200 m is calculated using Coulomb’s law. Coulomb’s law states that the magnitude of the force between two point charges is directly proportional to the product of the charges, and inversely proportional to the square of the distance between them.
The equation for the electric force is[tex]F = k \times q1 \times q2 / r^2,[/tex] where k is Coulomb’s constant ([tex]8.99 \times 10^9 Nm^2/C^2[/tex]), q1 and q2 are the two charges, and r is the distance between them.
In this case, the two charges are q1 = +4.0 x 10-8 C and q2 = -4.0 x 10-8 C. The distance between them is r = 0.2 m.
Therefore, the net electric force that the two charges would exert on an electron placed at point x = 0.200 m is:
[tex]F = (8.99 \times 10^9 Nm^2/C^2) \times (4.0 \times 10-8 C) \times (-4.0 \times 10^{-8} C) / (0.2 m)^2 \\F = -2.40 \times 10-9 N[/tex]
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What does the change in the period with respect to the semimajor axis tell you about the dependence of the period on the semimajor axis?
The change in the period with respect to the semi major axis tells that as the semi major axis of an object's orbit increases, its period will increase as well. (Kepler's Third Law of Planetary Motion)
What is Kepler's Third Law of Planetary Motion?Kepler's Third Law of Planetary Motion, also known as the "Harmonic Law," states that the square of the period of an object in orbit around a central body is proportional to the cube of its semi major axis. In other words, the longer the average distance of an object from the central body, the longer its orbital period will be.
This law applies to all objects in orbit around a central body, including planets, moons, asteroids, and comets. It is based on the laws of gravitation and provides important information about the dynamics of objects in orbit. By using this law, we can calculate the average distance of an object from a central body, its orbital period, and other orbital characteristics.
The relationship can be expressed as:
[tex]T^2 = k * a^3[/tex]
where T is the period of the object, a is its semi major axis, and k is a constant of proportionality.
Therefore, a change in the period with respect to the semi major axis can provide information about the dependence of the period on the semi major axis, specifically that the period increases as the semi major axis increases. This relationship is a direct result of Kepler's Third Law and the laws of gravitation, and provides important insights into the behaviour of objects in orbit.
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