A hollow steel tube with an inside diameter of 100mm must carry a tensile load of 400 kn.

Answers

Answer 1

The outer diameter of a hollow steel tube when the stress is limited to 120 MN/m² is  119.35 mm

Axial stress refers to the stress induced in a loaded member along the longitudinal or axial member direction. Calculated mathematically from the ratio of the axial or longitudinal force to the cross-sectional area of ​​the member.

Using the expressions for the axial stress and rated load, the cross-sectional area of ​​the tube can be determined. Substituting the values ​​for the cross-sectional area of ​​the tube and the inside diameter of the tube in the expression for the cross-sectional area of ​​a hollow cylinder yields the outside diameter of the tube.

                                σ = F/A

The formula for calculating the cross-sectional area of ​​a hollow cylinder.

A = π/4(D² – d²)

Here, the inside and outside diameters of a hollow cylinder are d and D.

Step 1

Determine the cross-sectional area of ​​tube (A) using the axial stress expression:

σ = F/A

Here, the axial stress limit is σ = 120 MN/m2 and the tensile load is F = 400 kN

σ = F/A

120 x 10³KN/1 MN = 400 kN/A

A = (400 kN) ÷ (120 x 10³ kN/m²)

A = 3333.33 mm²

Substitute the values ​​for the cross-sectional area of ​​the cylinder and the inside diameter of the cylinder in the equation for the cross-sectional area of ​​the hollow cylinder to calculate the outside diameter of the cylinder.

A = 3333.33 mm²

d = 100 mm

A = π/4(D² – d²)

3333.33 mm² = π/4(D² – 100²)

D² =[tex]\sqrt{ 14244.128}[/tex]

D = 119.35 mm

So, the outside diameter of the hollow is 119.35 mm.

Complete the questions is:

A hollow steel tube with an inside diameter of 100 millimeters must carry a tensile load of 400 kN. What is the outside diameter of the tube if the stress is limited to 120 MN/m²?

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Related Questions

An amusement park ride consists of a rotating circular platform 7.4 m in diameter from which 10 kg seats are suspended at the end of 1.81 m massless chains. When the system rotates, the chains make an angle of 26.6 degree with the vertical. The acceleration of gravity is 9.8 m/sa). what is the speed of each seat? answer in units of m/sb). if a child of mass 49.1 kg sits in a seat, what is the tension in the chain ( for the same angle)? answer in units of N

Answers

The speed of each seat is 4.71 m/sec, if the radius of the rotating platform is 3.7 meter. If a child of 49.5 kg sits in a seat, then the tension in the chain will be 648.4 N.

Mass of each seat, m = 10 kg

Radius of the rotating platform, R = 7.4/2 = 3.7 m

Let the tension in the chain = T₁

Vertical angle made by the chain = 26.6°

There will be two components of the tension in chain. Vertical component of the chain will be balanced by the weight(mg) of the seat.

T×cos26.6 = 10 ×9.81

T = (10×9.81)/cos26.6

T = 109.7 N

Horizontal component of the tension in chain is balanced by the centrifugal force due to the circular motion of radius,

R₁ =  3.7 + 1.81×sin26.6

R₁ = 4.51 m.

Centrifugal force, F = mv²/R₁

(10×v²)/4.51 = 109.7 × sin26.6

(10×v²)/4.51 = 49.12

v² = (49.12 × 4.51)/10

v = 4.71 m/sec

If a child of mass 49.1 sits on the seat, then the total weight on the seat will be, W = (10+49.1) × 9.81 = 579.77 N

This weight will be balanced by the vertical component of the tension in the chain,

579.77 = T×cos26.6

T = 579.77/cos26.6

T = 648.4 N

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The largest moon in the solar system is Ganymede, a moon of Jupiter. Ganymede orbits at a distance of 1.07×109m from the center of Jupiter with an orbital period of about 6.18×105s. Find the mass of Jupiter.

Answers

The moon of Jupiter, Ganymede is the largest moon in the solar system. The mass of Jupiter when the orbital period and the distance from the centre of the orbit are given is calculated to be 1.57 × 10²⁷ kg.

The time required to complete one revolution in an orbit around the planet is known as the Orbital Time period of motion. The orbital distance's cube is directly proportional to the square of the time period.

Given that,

Orbital distance R = 1.07 × 10⁹ m

Time period T = 6.18 × 10⁵ s

We know the formula of time period as,

T² = 4 π² R³/ G M

where, M is the mass of Jupiter

G is the gravitational constant

(6.18 × 10⁵)² = 4 π² (1.07 × 10⁹)³/(6.67 × 10⁻¹¹) M

Making M as subject, we have,

M = 4 π² (1.07 × 10⁹)³/[ (6.67 × 10⁻¹¹) (6.18 × 10⁵)²] = 1.57 × 10²⁷ kg

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Use the information from the graph to answer the
question.
Velocity (m/s)
45
40
35
30
25
20
15
Velocity vs. Time
0 2
4
6 8
Time (s)
10
12
What is the acceleration of the object?
m/s²

Answers

The velocity after 8 seconds 15 m/s. the acceleration of the object m/s² 2.

What is velocity ?

Velocity is a vector quantity that expresses both the speed and direction of an object's motion. It can be described in terms of both magnitude and direction, and is measured in terms of meters per second (m/s). Velocity is an important concept in physics because it is used to describe the motion of objects. In addition, it is used to calculate the force of an object, the acceleration of an object, and the momentum of an object.

Velocity is an important concept in physics and engineering, as it is used to measure the rate at which objects move, as well as the rate of change of an object's motion. Velocity can also be used to calculate the work done on an object and to determine the direction of an object's motion.

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A metal sphere as a charge of +2.3 x 10^-6 C and lies 2 meters away from another metal sphere of unknown charge.

If the attractive force present between the spheres is 0.05 N, what is the charge on the second sphere?

Answers

The charge is on the second sphere  9.67×10⁻⁶ C.

What is charge?

Charge is the product of current and time.

To calculate the charge on the second sphere, we use the formula below

Formula:

Q = Fr²/kq.................. Equation 1

Where:

F = Force on both sphereq = Charge on the first sphereQ = Charge on the second spherer = Distance between the spherek = Coloumb's constant

From the question,

Given:

q = 2.3×10⁻⁶ NF = 0.05 Nr = 2 mk =  8.99×10⁹ Nm²/C²

Substitute these values into equation 1

Q = (0.05×2²)/(8.99×10⁹×2.3×10⁻⁶)Q = 9.67×10⁻⁶ C

Hence, the charge is  9.67×10⁻⁶ C.

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What is MLA formatting used for?

Answers

MLA style is most commonly used to cite sources within the language arts, cultural studies, and other humanities disciplines.

MLA Style Citation Writing Format

The Modern Language Association or better known as the MLA style is a citation issued by MLA with a simple design. The aim is to make it easier for writers to write citations. Usually this style is used in the fields of Humanities and English.

the characteristics of MLA Styles' writing are:

The author's name is written in full with the last name written in front The year of publication is put at the end Quotations on the page simply by writing the last word and the page number of the quote On certain media, information on media type and format can be added, for example print or online On online sources, it is enough to display the month and year accessed without mentioning the online source.

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7. What is the power (in Watts) of the Pokemon Machamp that uses 237 N of force to move a huge boulder 83 m in 5s?

Answers

The power in watts of the Pokemon Machamp that uses 237N of force to move a huge boulder 83 m in 5s is 3,934.2Watts.

How to calculate power?

Power refers to the measure of the rate of doing work or transferring energy.

The quantity that has to do with the rate at which a certain amount of work is done is known as the power. The power of a substance can be calculated using the following formula;

P = Work done ÷ time

Since work = Force × distance

Power = (Force × distance)/time

Power = (237 × 83)/5

Power = 3,934.2Watts

Therefore, 3,934.2Watts is the power of the Pokémon machamp.

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25 bullets about Pierre&Marie Curie,or the creation of the polonium and or Radium

Answers

In 1898, the Curies' study of pitchblende led to the discovery of both the substances radium and polonium.

What was the purpose of pitchblende?

The original purpose of pitchblende extraction was to create coloring agents for the glassmaking industry. By analyzing pitchblende, the German geologist Klaproth discovered uranium in 1789. A.H. Becquerel made the discovery of radioactivity in 1896. A naturally occurring organic substance is pitchblende. It is the main source of uranium ore, which is present there as uranium oxide, or U3O8. Risks include those brought on by radiation and dust particles.

What about pitchblende was unexpected?

Even more astonishingly, Marie discovered that a uranium rock known as pitchblende included two potently radioactive new elements that she dubbed polonium and radium after her native Poland.

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Calculate the change in the kinetic energy (ke) of the bottle when the mass is increased. Use the formula ke = one half. Mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of 0. 8 m will be 4 m/s, and use this speed for each calculation. Record your calculations in table a of your student guide.

Answers

If the mass of the bottle is 0.125 kg, its kinetic energy is 1 Kgm²/s².If the mass of the bottle is 0.250 kg, its kinetic energy is 2 Kgm²/s².If the mass of the bottle is 0.375 kg, its kinetic energy is 3 Kgm²/s².If the mass of the bottle is 0.500 kg, its kinetic energy is 4 Kgm²/s².

Kinetic energy is affected by the mass (m) and speed (v) of an object. If an object with mass m moves with speed v, then it can be said that the object has a kinetic energy of:

                          KE = 1/2 x mv2

In the given problem:

The speed of the soda bottle from a height of 0.8 meters is 4 m/s.

If the mass of the soda bottle is 0.125 kg, the KE is:

KE = 1/2 x mv2

KE = ½ x 0.125 x (4)2

KE = ½ x 0.125 x 16

KE = 1 Kgm²/s²

If the mass of the soda bottle is 0.250 kg, its KE is:

KE = 1/2 x mv2

KE = ½ x 0.250 x (4)2

KE = ½ x 0.250 x 16

KE = 2 Kgm²/s²

If the mass of the soda bottle is 0.375 kg, the KE is:

KE = 1/2 x mv2

KE = ½ x 0.375 x (4)2

KE= ½ x 0.375 x 16

KE = 3 Kgm²/s²

If the mass of the soda bottle is 0.500 kg, its KE is:

KE = 1/2 x mv2

KE = ½ x 0.500 x (4)2

KE = ½ x 0.500 x 16

KE = 4 Kgm²/s²

Complete the questions is:

Calculate the change in the kinetic energy (KE) of the bottle when the mass is increased. Use the formula KE = mv2, where m is the mass and v is the speed (velocity). Assume that the speed of the soda bottle falling from a height of 0.8 m will be 4 m/s, and use this speed for each calculation. Record your calculations in Table A of your Student Guide.

When the mass of the bottle is 0.125 kg, the KE is kg m2/s2. When the mass of the bottle is 0.250 kg, the KE is kg m2/s2. When the mass of the bottle is 0.375 kg, the KE is kg m2/s2. When the mass of the bottle is 0.500 kg, the KE is kg m2/s2.

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Question 3 of 10
Brittany learns that her primary care doctor will be switching to electronic
health records. Although she understands that this will improve her care, she
expresses concern to her doctor. What is likely one of her concerns?
A. The risk of her medical information being misused or shared.
B. Lack of personal access to her files.
C. Loss of revenue by her doctor's office.
D. Increased cost of a doctor visit.
SUBMIT

Answers

At the time of care, giving patients accurate, complete, and current information. facilitating quick access to patient records to improve coordination and effectiveness of service.

Do you believe switching from paper records to electronic records is beneficial to a health care practice why or why not?EHRs have the potential to be more effective than paper records because they permit centralised chart management and quicker access to patient data from any location with condition-specific inquiries.The term "Electronic Health Record" (EHR) refers to an electronic version of a patient's medical history that is kept on file by the healthcare provider over time. It may contain all of the essential administrative clinical data pertinent to that person's treatment by that provider, such as demographics, progress notes, issues, and medication information.contain information on a patient's medical history, diagnosis, prescriptions, treatment plans, dates of vaccinations, allergies, radiology images, and results of lab and test work.Providers should have access to evidence-based instruments that they may use to decide how to treat a patient.Streamline and automate provider workflow.

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Sound waves are examples of

longitudinal waves
transverse waves
electromagnetic waves
tension waves

Answers

A is the correct answer, sound waves are longitudinal waved meaning that the waved propagate by compression PLEASE MARK BRAINLIEST

Answer:

Sound waves are examples of A. or longitudinal waves

If two identical springs are put in parallel (side by side), what exactly
happens to the overall spring constant? Why?

Answers

The springs generate a combination of forces.Therefore, it may be said that when springs are utilized in parallel, their constants add up.

Do springs in parallel experience the same force?

In springs the force must be the same. In parallel circuits the sum of all the currents going through each branch must be equal to the total current going into the branches. In parallel springs, the total force from all the springs must equal the total force from the mass.

When springs are connected in parallel the deflection for each spring is?

2. Springs in Parallel: In parallel combination, force developed in each spring will be different but deflection in each spring will be equal.

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Calculate the wavelength and energy of light that has a frequency of 1. 5 x 1015 hz.

Answers

Answer:

Explanation:

I will assmune that "frequency of 1. 5 x 1015 hz" is actually "frequency of 1. 5 x 10^15 hz"

The wavelength and frequency of light are related by the expression C = λ f  , where C is the speed of light  (3x10^8 m/s), λ is the wavelength (in m), and f is the frequency (in 1/sec or Hz).

   C = λ f  

   (3x10^8 m/s) = λ (1. 5 x 10^15 sec^-1)

   λ =     (3x10^8 m/s)/(1. 5 x 10^15 sec^-1)

   λ =    2.00x10^-7 m

 E=hf, where h is Plank's constant (6.62606957×10-34 J·s)

 E = (6.62606957×10-34 J·s)*(1.5x10^15s^-1)

 E = 9.94x10^-19 J

A person pushes a lawnmower across 20 meters of grass. If the person pushes with 37 Newtons of force while pushing downward at an angle of 15 degrees below the horizontal, what is the amount of work the person does on the lawnmower?

Answers

Therefore, the amount of work done on the lawnmower is: W=Fdcosθ=(37 N)(20 m)cos15∘≈710J if is the amount of work the person.

What is the simple definition of work?

Work is force applied over distance. Examples of work include lifting an object against the Earth's gravitation, driving a car up a hill, and pulling down a captive helium balloon. Work is a mechanical manifestation of energy. The standard unit of work is the joule (J), equivalent to a newton - meter.

What is work and energy?

Work is defined as transferring energy into an object so that there is some displacement. Energy is defined as the ability to do work. Work done is always the same. Energy can be of different types such as kinetic and potential energy.

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A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity.

Answers

A mass on a spring undergoes simple harmonic motion. When the mass passes through the equilibrium position, its instantaneous velocity is maximum.

Simple harmonic motion or SHM is the alternating motion of an object that passes through a certain balance point. SHM has a fixed frequency and amplitude and is periodic, namely movements that occur regularly and are repeated at the same time.

When a spring undergoes simple harmonic motion, the mass accelerates in a direction toward the equilibrium point, then the velocity of the object at the equilibrium point is maximum. The object is accelerating in a direction toward the equilibrium point. Acceleration caused by the force recovered.

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A skydiver is falling at a constant velocity of m/s. Gravity is producing a downward force of n. What is the force of drag acting on the skydiver?.

Answers

The force of drag acting on the skydiver is 795 N upwards.

When a parachutist jumps from a plane, only one force is acting on him, namely the force of gravity (the weight of the parachutist) so that the parachutist moves down. When jumping from a height when parachuting, the force of gravity will pull us down very quickly. Thus, we will freefall very quickly

Given in the questions: Constant velocity = 54.4 m/s

According to Newton's first law, when the net resultant force on an object is 0, the object is moving at a constant speed or is at rest and remains at rest. So, we know the resultant force is 0.

Now we use Newton's second law.

Resultant force = ma

Resultant force = Driving force (acting downwards) - Resistive force (acting upwards)

                       0 = mg (weight) - drag

                  drag = mg

                 drag = 795N upwards

Complete the questions:

A skydiver is falling at a constant velocity of 54.4 m/s. Gravity is producing a downward force of 795 N. What is the force of drag acting on the skydivers?

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A pulse has a speed of 0,5cm.s-¹. How far does it travel in 2,5s?​

Answers

The pulse traveled 1.25 cm in 2.5s. with 0.5 cm/s

From the equation of motion in 2 dimensions d = v*t ...... ( i )

As

v= d/t so d=v*t

where the time taken is 2.5 s

the velocity of pulse is 0.5 cm/s

to find the distance covered in a given time which a velocity of 0.5 m/s

so from equation (i)

d= v*t..........................(from i)d = 0.5 * 2.5d= 1.25

So the distance it will be covered is 1.25 cm

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The free-fall acceleration at the surface of planet 1 is 16 m/s2. The radius and the mass of planet 2 are twice those of planet 1.

Answers

The free-fall acceleration at the surface of planet 2 is g = 8 m/s². The result is obtained by comparing the accelerations due to gravity on planet 1 and planet 2.

What is the formula of free-fall acceleration?

The free-fall acceleration can be counted by the following formula.

g = GM/R²

Where

g = acceleration due to gravity (free-fall acceleration)G = universal gravitational constantM = mass of an objectR = distance from the center of mass of object.

Planet 1 has the free-fall acceleration at its surface of 16 m/s². Planet 2 has the radius and the mass twice those of planet 1.

Find the free-fall acceleration at the surface of planet 2!

If g, M, and R are the parameters of planet 1, let's say g', m, and r are the parameters of planet 2. So,

m = 2Mr = 2R

The acceleration due to gravity on planet 2 is

g/g' = (GM/R²)/(Gm/r²)

g/g' = (M/R²)/(m/r²)

g/g' = Mr²/mR²

g/g' = M(2R)²/(2M)R²

g/g' = 4MR²/2MR²

16/g' = 2/1

g' = 16/2

g' = 8 m/s²

Hence, the acceleration due to gravity on planet 2 is 8 m/s².

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How far would a car travel in 3 s if it's acceleration was 5 m/s²?
12.5 m
22.5 m
15.0 m
0.4 m
1.6 m

Answers

The distance a car will travel in 3 s if it's acceleration was 5 m/s² is 22.5m and is denoted as option B.

What is Acceleration?

This is defined as the rate at which velocity changes with time and is usually in terms of both speed and direction which makes it a vector quantity.

Acceleration = velocity / time

5 m/s² = v / 3s

v = 15m/s.

To calculate the distance we can use:

D = 1/2*a*t²

 =  1/2 × 5 × 3²

= 22.5m.

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Your classmate hernando wants to draw lines that create a sense of energy and movement in his drawing. Which type of line would you recommend to him to best articulate this feeling?.

Answers

I would suggest him to use curved lines to articulate the energy and movement motion n his drawing

Arcs of lines may be referred to as curves segments, rays, or lines depending on how they are linked.

A typical illustration of a curve is the arc of a circle, often known as a circular arc. The term "great arc in a sphere" refers to an arc of a great circle or a great ellipse or a spheroid.

The numerous types of curves include simple curves, closed curves, simple closed curves, transcendental curves, and algebraic curves.

A curved line that encircles a central point is what is referred to be a circle. The line is continuously and uniformly curved. If a circle can be folded into two identical pieces, it is considered to be symmetrical.

Thus curved lines can be used to best articulate the feeling.

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Answer:

Curved

Explanation:

Two pans of a balance are 79 cm apart.
The fulcrum of the balance has been shifted 0.99 cm away from the center by a dishonest shopkeeper.
By what percentage is the true weight of the goods being marked up by the shopkeeper?
Assume the balance has negligible mass.
Answer in units of %.

Answers

The true weight of the goods is being marked up by 0.0126%.

Solving for the  percentage is the true weight of the goods being marked up by the shopkeeper:

The percentage markup can be found using the formula:

distance moved  x 100%

original distance

In this case, the original distance is 79 cm and the distance moved is 0.99 cm, so the formula would be:

= 0.99 x 100%

    79

= 0.0126%

Hence, the true weight of the goods is being marked up by 0.0126%.

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A student gives a quick push to a ball at the end of a massless, rigid rod, as shown in the figure, causing the ball to rotate clockwise in a horizontal circle. the rod's pivot is frictionless.

a. As the student is pushing, is the torque about the pivot postive, negative, or zero?

b. After the push has ended, does the ball's angular velocity:

steadily increase, steadily decrease, hold steady, decrease for a while then hold steady, increase for a while then hold steady

c. Right after the push has ended, is the torque positive, negative, or zero?

Answers

The torque about the pivot is positive, after the push has ended the ball's angular velocity will hold steady, right after the push has ended the torque would be zero.

Torque is a measure of force that can rotate an object around a fixed axis. as the ball is moving in the same direction in which the force is applied. So the torque will be positive. After the push has ended the ball will continue to rotate at the constant angular velocity, as the pivot is frictionless, so no opposing force will decrease the angular velocity of the ball. So the ball's angular velocity will hold steady.

After the push has ended, the torque will be zero. Torque is defined as follows:

Torque = force × distance from the rotation axis

The pushing force is zero so the torque will also be zero.

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A 1.3 kg ball of putty is released from rest and falls vertically 1.2 m until it strikes a hard floor, where it comes to rest in a 0.025s time interval. What is the magnitude of the average force exerted on the ball by the floor during the collision?

Answers

The magnitude of the average force exerted on the ball  is 4992 N.

What is force?

Force is the product of mass and acceleration. The S.I unit of force is newton(N)

To calculate the magnitude of the average force, we use the formula below.

Formula:

F = 2ms/t².................... Equation 1

Where:

F = Forcem = Masss = Distancet = Time

From the question,

Given:

m = 1.3 kgs = 1.2 mt = 0.025 s

Substitute these values into equation 1

F = 2×1.3×1.2/0.025²F = 4992 N

Hence, the average force is 4992 N.

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Efficiency of a machine if energy input is 7.55 and energy output is 5.05

Answers

The efficiency of this machine is 66.67%.

What is efficiency?

Efficiency is a measure of how well a machine or system is able to convert input energy into useful output energy. It is a ratio of the output energy to the input energy, expressed as a percentage.

An efficient machine or system is one that is able to convert a large portion of the input energy into useful output energy, with minimal energy loss. Conversely, an inefficient machine or system is one that loses a significant portion of the input energy as waste heat, sound, or other forms of energy that are not useful to the desired output.

The efficiency of a machine can be calculated using the formula:

Efficiency = (Energy Output / Energy Input) x 100%

In this case, the energy input is 7.55 and the energy output is 5.05, so we can calculate the efficiency as follows:

Efficiency = (5.05 / 7.55) x 100% = 66.67%

Therefore, the efficiency of this machine is 66.67%.

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How did the heavy elements originate and what did they create?

Answers

Heavy elements, such as gold, silver, and mercury, as well as the elements that make up the earth's core, such as iron and nickel, originated in the hearts of stars. They were created through the process of nuclear fusion, which occurs when the temperatures and pressures inside a star are high enough to overcome the electrostatic repulsion between the positively charged nuclei of atoms.

What are  heavy element?

When fusion occurs, the nuclei of the atoms merge, creating a new, heavier element. This process is called nucleosynthesis. The fusion of lighter elements, such as hydrogen and helium, produces heavier elements, such as carbon, oxygen, and neon.

Therefore, most heavy elements, such as gold and platinum, are created in supernovae, massive explosions that occur when the fuel in a star runs out, and the star collapses under its own gravity. The intense pressure and temperatures that are created during the collapse cause the nuclei of atoms to fuse together, creating elements with atomic numbers higher than iron.

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Can anyone help me answer this question?
______ is an instrument that measures small electric currents due to changing magnetic fields.
a) Ammeter
b) Galvanometer
c) Voltmeter
d) Dynanometer

Answers

B is correct -Galvanometer:)

Order the molecules from the strongest intermolecular force (top) to the weakest (bottom). Refer the table of electronegativities to help you.

Answers

The order of intermolecular forces among the given compounds will be as follows: H F > H Cl > H Br > H I

Electronegativity is defined as the property of the element to attract the shared pair of electrons towards itself.

Strongest intermolecular forces of attraction means that the electronegativity difference between the elements forming bond is more, more polar is the bond.

Electro negativities of the elements are:

Hydrogen: 2.1

Fluorine: 3.98

Chlorine: 3.16

Bromine: 2.96

Iodine: 2.66

Electro negativity difference in H F = 3.98 - 2.1 = 1.88

Electro negativity difference in H Cl = 3.16 - 2.1 = 1.06

Electro negativity difference in H Br = 2.96 - 2.1 = 0.86

Electro negativity difference in H I = 2.66 - 2.1 = 0.56

As, the electronegativity difference of H F is the highest, so it has the strongest intermolecular forces of attraction.

Thus, the order of intermolecular forces among the given compounds is H F > H Cl > H Br > H I.

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A load of unknown ma i place in the rear of an 18-wheeler truck. The truck rear hock are intantly compreed 10. 0cm. Conider the hock acting a pring with a pring contant, k = 50,000N/m. What i the ma of the load the 18-wheeler jut picked up?

Answers

The mass of the load is 50,000N/m multiplied by 10.0cm, which is 500,000N.

Hooke's law states that the force (F) required to extend or compress a spring by some distance (x) scales linearly with respect to that distance—that is, Fs = kx, where k is a constant factor characteristic of the spring (i.e., its stiffness) and x is small in comparison to the total possible deformation of the spring.

B. Using Hooke's law, F = kx, where F is the force of the truck's hock, k is the spring constant, and x is the compression of the hock. Rearranging for mass, m = F/g, where g is the acceleration due to gravity. Thus, m = kx/g, or m = (50,000N/m * 10.0cm)/9.8m/s^2, which yields 500,000N.

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A roller coaster car is on a track that forms a circular loop in the vertical plane. If the car is to just maintain contact with track at the top of the loop, what is the minimum value for its centripetal acceleration at this point?.

Answers

The minimum value for the roller coaster car’s centripetal acceleration at the top of the loop is g downward.

When the roller coaster car is going at less than the minimum speed, it means there will be too much force, and the roller coaster car will fall from the track. At the minimum speed, the centripetal force at the top of the loop will be exactly equal to the force of gravity, mg, since no normal force will be needed.

What is normal force?

The normal force is the force which surfaces exert to prevent solid objects from passing through each other. Normal force is a contact force. If two surfaces are not in contact, they cannot exert a normal force on each other.

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A weight suspended from a spring is seen to bob up and down over a distance of 28 cm twice each second. Find the frequency.

Answers

Since frequency is the reciprocal of period, the frequency of the spring is 2 Hz

What is Frequency ?

Frequency can be defined as the number of complete revolution per second made by a vibrating body.

Given that a weight suspended from a spring is seen to bob up and down over a distance of 28 cm twice each second.

This means that its Period T = t/n

Where

t = time taken = 1 sn = number of oscillations = 2

T = 1/2 = 0.5 s

Frequency is an inverse of period. That is,

F = 1/T

F = 1/0.5

F = 2 Hz

Therefore, the frequency of the spring is 2 Hz

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When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1600 kg automobile traveling at 42.8 m/s comes to a halt after its brakes are applied, how much can the temperature rise in each of the four 3.5 kg steel brake disks? Assume the disks are made of iron (cp = 448 J/kg·°C) and that all of the kinetic energy is distributed in equal parts to the internal energy of the brakes.

Answers

The temperature can rise 234° C in each of the four 3.5 kg steel brake disks.

What is law of conservation of energy?

Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.

According to law of conservation of energy:

1/2 × 1600 × 42.8² = 4 × 3.5 × 448 × Δt

Δt = (1600 × 42.8² )/( 2 ×  4 × 3.5 × 448)

Δt = 234° C.

Hence, the temperature can  rise 234° C in each of the steel brake disks.

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