A path 2 m wide surrounds a large flowerbed.

Answer:

0.7769 = 77.69% probability that the owner will experience at least one Category III hurricane during the mortgage period

Step-by-step explanation:

We have only the mean, so we use the Poisson distribution to solve this question.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

In which

x is the number of sucesses

e = 2.71828 is the Euler number

[tex]\mu[/tex] is the mean in the given interval.

It uses the estimate that the probability of a named Category III hurricane or higher striking that particular region of the coast in any one year is 0.05.

This means that [tex]\mu = 0.05n[/tex], in which n is the number of yeas.

If a homeowner takes a 30-year mortgage on a recently purchased property, what is the likelihood that the owner will experience at least one Category III hurricane during the mortgage period

30 years means that [tex]\mu = 0.05*30 = 1.5[/tex].

This probability is:

[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]

In which

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-1.5}*(1.5)^{0}}{(0)!} = 0.2231[/tex]

[tex]P(X \geq 1) = 1 - P(X = 0) = 1 - 0.2231 = 0.7769[/tex]

0.7769 = 77.69% probability that the owner will experience at least one Category III hurricane during the mortgage period

Let X become a variable refer to the number of Category ll hurricanes that occurred during the mortgage period. As per the information given, the variable x has a random variable.

For point a:

     [tex]\to P(X > 1) = 1 - P(X = 0)\\\\ \to P(X > 1) = 1^{-30} C_o (0.05)^0 (1 -0.05)^{30}\\\\ \to P(X > 1) = 0.7854[/tex]

For point b:

[tex]\to P(X > 2) = 1 - P(X =0) - P(X = 1)\\\\ \to P(X > 2) = 1 ^{-30} C_0(0.05)^0 (1 -0.05)^{30 -30} C_1 (0.05)^1+(1 - 0.05)^{29}\\\\ \to P(X > 2) = 0.4465[/tex]

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Answer:

There is not convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes

Step-by-step explanation:

The null hypothesis is:

[tex]H_{0} = 4[/tex]

The alternate hypothesis is:

[tex]H_{1} < 4[/tex]

The test statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.

From a random sample of 41 orders, the mean time was 3.75 minutes with a standard deviation of 1.2 minutes.

This means that [tex]n = 41, \mu = 3.75, \sigma = 1.2[/tex]

The test-statistic is:

[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

[tex]z = \frac{3.75 - 4}{\frac{1.2}{\sqrt{41}}}[/tex]

[tex]z = -1.33[/tex]

[tex]z = -1.33[/tex] has a pvalue of 0.0918, looking at the z-table.

0.0918 > 0.05, which means that the null hypothesis is accepted, and that there is not convincing evidence at the a = 0.05 significance level that the true mean service time during the early morning shift is less than 4 minutes

Answer: 144π

Step-by-step explanation: First. find the area of the bases. To do this, you must solve for the area of a circle with a radius of 4. Since the formula for finding the area of a circle is area=πr² squared, the area of the circles are 16π. Next, you must multiply the area of the base, 16π, by the height of the cylinder, 9. 16π times 9 is 144π, or about 452.4, if rounded to the nearest tenth, or 452.39, if rounded to the nearest hundredth.

Answer:

5/6

Step-by-step explanation:

x > 1

x = 2,3,4,5,6

( quantity of 2,3,4,5,6)/(total)

5/6

Answer:

On the y cordnate go up 14.5

Step-by-step explanation:

Answer:

i dont see a picture?

Step-by-step explanation:

Step-by-step explanation:

the student who has the highest grades in a particular group of students and who gives the valedictory speech at a graduation ceremony compare salutatorian.

Step-by-step explanation:

Given

x² - 9x + 20 = 0

x² - ( 4 + 5) x + 20 = 0

x² - 4x - 5x + 20 = 0

x ( x - 4 ) - 5 (x - 4 ) = 0

(x - 4 ) ( x - 5 ) = 0

Either

x - 4 =0

x = 4

or

x - 5 =0

x = 5

x = 4 and 5

Hope it will help :)

[tex].)[/tex]

Answer: hope this helps. Check out the image.. and can u give me brainliest pls and I also have explanation

Step-by-step explanation:

Answer:i dont know :(

Step-by-step explanation:

im sorry :(

Answer:

1. true

2. false

3. false

4. false

Step-by-step explanation:

hope this helps

please mark brainiest

please give 5 stars

thank you

Answer:

A

Step-by-step explanation:

its a bec count how many student are their an see if they add IP to 30

The Venn diagram which shows the number of students who play basketball and baseball is option A.

Venn diagram is a diagram denoting two or more sets which is drawn using circles inside a rectangle where the part where the two circle meet denotes the intersection of two sets.

Let A denotes the students playing baseball and B denotes the student playing basketball.

N(A) = 18

N(B) = 17

N(A ∪ B) = 30

We know,

N(A ∩ B) = N(A) + N(B) - N(A ∪ B)

              = 18 + 17 - 30

              = 35 - 30

              = 5

Number of students who play both baseball and basketball = 5

Number of students who plays only baseball = 18 - 5 = 13

Number of students who plays only basketball = 17 - 5 = 12

This is shown in A.

Hence the correct option is A.

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Answer:

33.97 m

Step-by-step explanation:

Given that,

The height of a man = 2 m

He stands on a horizontal ground 30m from a tree.

The angle of elevation of the top of the tree from his eyes is 28°.

We need to find the distance between the man eyes to the top of the tree. Let the height of the tree be h

Using trigonometry to find such that,

 [tex]\tan28=\dfrac{h}{30}\\\\h=\tan28\times 30\\\\h=15.95[/tex]

Now let us consider that the distance between the man eyes to the top of the tree is x. Using Pythagoras theorem,

[tex]x^2=30^2+15.95^2\\\\x=33.97\ m[/tex]

So, the distance between the man eyes to the top of the tree is 33.97 m.

Answer:

3 gallons

Step-by-step explanation:

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Answer:

13

Step-by-step explanation:

500 - 302=198

198 divided by 15 = 13. 2   round down to 13. 13 guests.

Answer:

Dimensions = 21 centimeters by 4.2 centimeters.

Step-by-step explanation:

Let the length of the rectangle be L.

Let the width of the rectangle be W.

Given the following data;

Perimeter of rectangle = 50cm

Translating the word problem into an algebraic expression, we have;

L = 5W

To find the dimensions of the rectangle;

Perimeter of rectangle = 2L + 2W

50 = 2L + 2W

50 = 2(5W) + 2W

50 = 10W + 2W

50 = 12W

W = 50/12

W = 4.2 cm.

To find the length;

L = 5W

L = 5*4.2

L = 21 cm.

Answer:

15 + 2 = 17

Step-by-step explanation:

Expand the polynomial using the FOIL method.

3 x 2 + 17 x + 10

I do know the first figure is 24 square feet.

To get your answer,

Count the amount of the blocks stacked on top each other to make the length, in this case the first photo would be 3, and the width of the block, which is 8. To get the area, you would multiply the length and width together.

Image Form:

l x w = a

(length x width = area)

I hope this is a clear explanation!

Answer:

first one is 24

second one is 12

third one is 9

fourth one is 18

Step-by-step explanation:

Answer:

the sum of three consecutive odd number is less than 54.

Answer:

distance between these point is 8

Step-by-step explanation:

d=

[tex] \sqrt{( 3- - 5) ^{2} + (3 - 3)^{2}} [/tex]

Answer:

8 is the distance between them

FYI distance formula is the square root of (x2 -x1)^2 = (y2- y1)^2

Step-by-step explanation:

Answer:

[tex]\frac{1}{5}[/tex]

Step-by-step explanation:

[tex]\frac{9}{10} -\frac{7}{10} =\frac{2}{10} =\frac{1}{5}[/tex]

Answer:

25x2-36

1-16x2

Step-by-step explanation:

Answer:

$546000

Step-by-step explanation:

($65000×8%)(2)

Answer:

[tex]\frac{6}{\sqrt 2}= 3\sqrt 2[/tex]

Step-by-step explanation:

Given

[tex]\frac{6}{\sqrt 2}[/tex]

Required

Rationalize

[tex]\frac{6}{\sqrt 2}[/tex]

To do this, we simply multiply by [tex]\frac{\sqrt 2}{\sqrt 2}[/tex]

[tex]\frac{6}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}[/tex]

This gives:

[tex]\frac{6 * \sqrt 2}{\sqrt 2 * \sqrt 2}[/tex]

[tex]\frac{6 \sqrt 2}{2 }[/tex]

[tex]3\sqrt 2[/tex]

Hence:

[tex]\frac{6}{\sqrt 2}= 3\sqrt 2[/tex]

Step-by-step explanation:

y>3-8

y>-5

The solutions are in the interval ]-5,○○[

Answer:

28:32:36

Step-by-step explanation:

you add the ratios up all together and divide your answer by 96 the answer you get there you multiply it with the ratios