The minimum initial velocity of the rock is V = 8.56 m/sec.
What is Conservation of Energy?According to the rule of conservation of energy, energy can only be transformed from one form of energy to another and cannot be created or destroyed. This indicates that unless energy is added from the outside, a system always has the same quantity of energy.
Calculate the rock's minimal initial velocity in meters/second as it exits the slingshot at a distance of 6 feet [tex]$\left(h_{2}=6\right.ft.)[/tex] above the ground.
Using the provided information, the net height of the limb is calculated as shown below.
[tex]$$h &=h_{1}-h_{2}$$[/tex]
h = 18.3 - 6
h = 12.3
Now, using the conservation of energy the minimum initial velocity of the rock is computed as shown below,
Kinetic energy of the rock = Potential energy the rock
[tex]$$\begin{aligned}\frac{1}{2} m V^{2} &=m g h \\\frac{1}{2} V^{2} &=g h \\\frac{1}{2} V^{2} &=\left(32.1 \mathrm{ft} / \mathrm{s}^{2}\right)(12.3 \text { feet }) \\V &=\sqrt{2\left(32.1 \mathrm{ft} / \mathrm{s}^{2}\right)(12.3 \mathrm{feet})}\end{aligned}$$[/tex]
V = 28.10 [tex]\frac{ft}{s}[/tex].
The minimal initial velocity in meter/second is 8.56.
Therefore, the minimum initial velocity of the rock is 8.56 m/sec
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In which direction is the magnetic force acting on the charge? into the screen out of the screen up down
The direction in which the magnetic force is acting on the charge is upwards.
What is Magnetic force?This is the attraction and repulsion which usually occurs during the motion of electrically charged particles.
In the magnetic field, the charge is moving to the left. Therefore the direction the magnetic force is acting on the charge is upwards which is gotten via right hand rule.
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What combination of ester and bromo-grignard reagent could you use to prepare the following tertiary alcohol?.
Combination to prepare tertiary alcohol:
A Grignard reagent interacts first with an ester to produce a ketone, which then undergoes further reactions to produce tertiary alcohol.
Process to form tertiary alcohol:
Methyl esters react with two moles of a Bromo-Grignard reagent to give tertiary alcohol.A ketone is produced when one mole of Grignard reagent is added to the carbon-oxygen double bond, creating an unstable intermediate. Then, a second mole of the reagent is added to the ketone, resulting in tertiary alcohol with at least two identical groups linked to the hydroxyl-bearing carbon. With acid halides and anhydrides, an identical series of reactions take place.Learn more about Grignard reagent here,
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Monochromatic light with wavelength 590 nm passes through a single slit 2. 30 ?m wide and 1. 90 m from a screen. Find the distance between the first- and second-order dark fringes on the screen.
The distance between the first and second-order dark fringe is 0.441 m.
Diffraction of a single slit:
When the light wave passes through a single slit of width which is comparable to the wavelength of the light, then the light wave bends at the edges of the slit. This is called diffraction.
Note: It is assumed that the slit is 3*10^(-3) mm wide. 1 nm = 10^(-9) m and 1mm = 10^(-3) m.
The dark fringes are obtained at the position which satisfies the equation,
d*sinθ = mλ
where d is the slit width, λ is the wavelength of the wave, θ is the angle of diffraction and m denotes the order of the dark fringe.
For first order fringe (m=1), the angle of diffraction θ₁ is,
d*sinθ₁ = λ
sinθ₁ =λ/d
Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.
sinθ₁ =(590 nm)/(3*10^(-3) mm)
sinθ₁ =(590*10^(-9))/ (3*10^(-3)*10^(-3) m)
sinθ₁ =0.196
θ₁ =11.03 degree
Similarly, for second-order fringe (m=2), the angle of diffraction θ₂ is,
d*sinθ₂= 2λ
sinθ₂ =2λ/d
Substitute λ=590 nm, d=3*10^(-3) mm, and solve it.
sinθ₂ =(2*590 nm)/(3*10^(-3) mm)
sinθ₂ =(2*590*10^(-9))/ (3*10^(-3)*10^(-3) m)
sinθ₂ =0.393
θ₂ =23.14 degree
From geometry, the positions x₁ and x₂ of the first and second-order dark fringe from the center of the screen are x₁=Dtanθ₁ and x₂= Dtanθ₂ where D is the distance of the screen from the slit. The distance s between the first-order and second-order dark fringe is then given by,
s=D(tanθ₂-tanθ₁)
Substitute D=1.90 m, θ₁=11.03 degree, and θ₂=23.14 degree in this equation and solve it.
s=1.90*(tan(23.14)-tan(11.03))
s=1.90*(0.427-0.195)
s=0.441 m
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Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, what is the magnitude of the force of attraction (in newtons) between the objects
Answer: Two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg. If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN
Explanation: To find the answer we need to know more about the Newton's law of gravitation.
What is Newton's law of gravitation?Gravitation is the force of attraction between any two bodies.Every body in the universe attracts every other body with a force.This force is directly proportional to the product of their masses and inversely proportional to the square of the distance between these two masses.Mathematically we can expressed it as,[tex]F=\frac{GMm}{r^2} \\where, G=6.67*10^-11Nm^2kg^-2[/tex]
How to solve the problem?Here, we have given with the data's,[tex]M=8.22*10^9kg\\m=1.38*10^8 kg\\r=1.43*10^3m[/tex]
Thus, the force of attraction between these two bodies will be,[tex]F=6.67*10^-11*\frac{8.22*10^9*1.38*10^8}{1.43*10^3} =52.9kN[/tex]
Thus, if two celestial objects are in space: one with a mass of 8.22 x 109 kg and one with a mass of 1.38 x 108 kg and, If they are separated by a distance of 1.43 km, then, the magnitude of the force of attraction (in newtons) between the objects will be 52.9kN.
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Question 5 of 32
According to the periodic table below, which element has the largest average
atomic mass?
OA. Helium (He)
OB. Oxygen (0)
OC. Nitrogen (N)
OD. Neon (Ne)
The forces in (Figure 1) are acting on a 1.0 kg object.What is ax , the x -component of the object's acceleration
The x -component of the object's acceleration is 2 m/s².
What's the resultant force along x- direction?Forces along x axis direction are as follows 4N along +x axis, so it's taken as +4 N2N along -x axis , so it's taken as -2N.Resultant force along x direction = 4N - 2N = 2 N which is along + ve x direction.What's the acceleration along x axis direction?As per Newton's second law, Force = mass × acceleration of the object Force along x axis= mass × acceleration along x axis= 2NAcceleration = 2/ mass = 2/1 = 2 m/s²Thus, we can conclude that the acceleration along x axis is 2 m/s².
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: The forces in (Figure 1) are acting on a 1.0 kg object. What is ax, the x-component of the object's acceleration?
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The total amount of energy it takes to heat 2.0 kg of ice from –18oC to 220oC is
Answer:
Approximately [tex]6.5 \times 10^{3}\; {\rm kJ}[/tex] (or equivalently [tex]6.5 \times 10^{6}\; {\rm J}[/tex]) assuming a melting point of [tex]0\; {\rm ^{\circ} C}[/tex] and a boiling point of [tex]100\; {\rm ^{\circ} C}[/tex].
Explanation:
The total amount of energy required is the sum of five parts:
Energy required to heat ice from [tex](-18\; {\rm ^{\circ} C})[/tex] to [tex]0\; {\rm ^{\circ} C}[/tex].Energy required to melt the ice.Energy required to heat water from [tex]0\; {\rm ^{\circ} C}[/tex] to [tex]100\; {\rm ^{\circ} C}[/tex].Energy required to vaporize the water.Energy required to heat steam from [tex]100\; {\rm ^{\circ} C}[/tex] to [tex]220\; {\rm ^{\circ} C}[/tex].The specific heat of ice is [tex]c(\text{ice}) = 2.09 \; {\rm kJ \cdot K^{-1} \cdot kg^{-1}}[/tex]. Energy required to raised the temperature of [tex]m = 2.0\; {\rm kg}[/tex] of ice by [tex]\Delta T = (0 - (- 18)) \; {\rm K} = 18\; {\rm K}[/tex]:
[tex]\begin{aligned}Q &= c(\text{ice}) \, m\, \Delta T \approx 75.24\; {\rm kJ} \end{aligned}[/tex].
The enthalpy of fusion (melting) of water is approximately [tex]\Delta H = 334\; {\rm kJ \cdot kg^{-1}}[/tex]. The energy required to melt [tex]m = 2.0\; {\rm kg}[/tex] of ice would be:
[tex]Q = m\, \Delta H \approx 668\; {\rm kJ}[/tex].
The specific heat of water is [tex]c(\text{water}) =4.18 \; {\rm kJ \cdot K^{-1} \cdot kg^{-1}}[/tex]. Energy required to raised the temperature of [tex]m = 2.0\; {\rm kg}[/tex] of water by [tex]\Delta T = (100 - 0) \; {\rm K} = 100\; {\rm K}[/tex]:
[tex]\begin{aligned}Q &= c(\text{water}) \, m\, \Delta T \approx836\; {\rm kJ} \end{aligned}[/tex].
The enthalpy of vaporization of water is approximately [tex]\Delta H = 2257\; {\rm kJ \cdot kg^{-1}}[/tex]. The energy required to vaporize [tex]m = 2.0\; {\rm kg}[/tex] of water would be:
[tex]Q = m\, \Delta H \approx 4.51 \times 10^{3}\; {\rm kJ}[/tex].
The specific heat of steam is [tex]c(\text{water}) =2.09\; {\rm kJ \cdot K^{-1} \cdot kg^{-1}}[/tex]. Energy required to raised the temperature of [tex]m = 2.0\; {\rm kg}[/tex] of steam by [tex]\Delta T = (220 - 100) \; {\rm K} = 120\; {\rm K}[/tex]:
[tex]\begin{aligned}Q &= c(\text{steam}) \, m\, \Delta T \approx 920\; {\rm kJ} \end{aligned}[/tex].
Hence, the total amount of energy required is approximately [tex]6.5 \times 10^{3}\; {\rm kJ}[/tex].
with the enterprise of video-gaming technology growing every year, researchers have ercently become interested in the effects of violent video games
Meta-analysis indicates that violent video games increase aggressive thoughts, aggressive affect, and aggressive behavior.
What are the effects of Violent video games ?Children who play violent video games have increased aggressive cognitions, aggressive behavior, psychological arousal as well as antisocial behavior.
Furthermore, exposure to violence in the games leads to desensitization- “a reduction in emotion-related physiological reactivity to real violence”The downside of video games is that the more time children and teens spend playing violent video games the more likely they are to display aggressive behavior.Learn more about Violent video games here:
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Electric forces can be explained using fields that extend through space. We can think of these fields as surrounding any charged object. What is one advantage of thinking about the electric force as a field?
Electric forces can be explained using fields that extend through space. We can think of these fields as surrounding any charged object. The force acting on a charged particle at a spot may be calculated by knowing the electric field there. This is further explained below.
What is one advantage of thinking about the electric force as a field?The electric force is the term used to describe the repulsion or attraction between two charged things. Newton's rules of motion define how a force interacts with a particular body.
In conclusion, Space-spanning fields may be used to explain electric forces. These fields may be thought of as enclosing any charged object. Knowing the electric field at a certain location will allow one to compute the force acting on a charged particle there.
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Answer:
(Choice B, Checked, Correct) A field helps predict how electric forces will affect any charge at any location in the field.
Explanation:
CORRECT (SELECTED)
A field helps predict how electric forces will affect any charge at any location in the field.
Modeling the electric force as a field can help us understand electric forces. For instance, we know that any charge in an electric field will experience an electric force. We don’t need to measure the force on each charge to know its direction.
A canister filled with 1.3 mol of single-atom helium gas has a temperature of 315 K. What is the approximate total internal energy of the gas? (Recall that the equation for kinetic energy due to translation in a gas is: 3/2 nRT; the equation for kinetic energy due to rotation of a molecule in a gas is: nRT; and R = 8.31 J/(mol.K).)
The total internal energy of the gas is 5104 Joule.
What is the internal energy of n mole of monoatomic gases?Internal energy= f/2 × nRTf = degrees of freedom, R= universal gas constant with value 8.31 J/(mol K), T= temperatureFor mono-atomic gas, degrees of freedom is 3. So internal energy= 3/2× nRTWhat is the internal energy of 1.3 mole of helium at 315K temperature?Internal energy of helium gas=
3/2 × 1.3 × 8.31 × 315
= 5104 joule
Thus, we can conclude that the internal energy of the helium gas is 5104 Joule.
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A person sits at rest on a chair. The gravitational force on the person (their weight) is one half of an action-reaction pair. Which force is the other half?
Normal is the other half of an action-reaction pair
If a person is sitting on a chair , there must be a gravitation force acting in downward direction which is equal to the weight of that person . That means the person is exerting a force on the chair equal to its weight . But the person is not falling down the chair , because of newtons third law of motion .
There must be a counter force which is equal and opposite to the force exerted by the person on the chair , in order to make net force equal to zero and to make that man in stationary state ( no movement ) .That force is called Normal force which is been acted by the chair on the person .This implies Normal is the other half of an action-reaction pair
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As keisha runs the generator, which best describes what should happen to the needle that measures electric current? it will move to a large positive value and stay there. it will move back and forth between 0 and a large positive value. it will move back and forth between a large positive and a large negative value. it will move to a large negative value and stay there.
The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.
What is an electric generator?An electric generator is physically equivalent to an electric motor. but it converts mechanical energy into electrical energy.The electrical field generated is dependent on the inclination of the wire with respect to magnetic field lines, and this inclination changes over time,because of that she will experience a varying electrical field, and thus a varying electric current will be zero.
The maximum positive value will occur when the wire is perpendicular to the magnetic field lines after one-fourth of rotation, and then zero.
Hence option C is correct.
The diagram shows a simple electric generator. The needle that measures electric current will move back and forth between a largely positive and a large negative value.
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What’s your favorite stranger things character.
Answer:
none
Explanation:
stranger mid mid mid mid
Answer:
My favorite stranger things character is Eleven also known as Millie Bobby Brown
Explanation:
I hope this helps and have a good day!
A coin slides over a frictionless plane and across an xy coordinate system from the origin to a point with xy coordinates (3.0 m, 4.0 m) while a constant force acts on it. The force has magnitude 2.0 N and is directed at a counterclockwise angle of 100 from the positive direction of the x axis. How much work is done by the force on the coin during the displacement
Work done by the force is 6.802 Joule
Given:
Therefore displacement of coin along x axis,x=3m
displacement of coin along y-axis,y=4m
force has magnitude = 2.0 N
To Find:
Work done by the force
Solution: Work is done whenever a force moves something over a distance. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.
component of force along x-axis, F = 2.0Ncos100
F = 2x(-.173)
F = -(.346)N
component of force in y direction,F₁ = 2.0sin100
F = 2x(.98)
F = 1.96N
work is done by the force on the coin during the displacement will be given as
W = Fx*x + Fy*y
W = -(.346) x 3m + 1.96 x 4
W = 6.802 Joule
Hence, Work done by the force is 6.802 Joule
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A uniform magnetic field cannot exert a magnetic force on a particle in which of the following circumstances
The particle moves parallel to the field
The particle is at rest.
If the magnetic field is uniform and the magnet dipoles are identical (apart from one being north pole and the other south pole) this two forces cancels out.
What is Uniform magnetic field ?A uniform magnetic field is a magnetic field that has the same magnitude and direction throughout the region under consideration, thus the field lines need to be both parallel and spaced out evenly.
It is represented by an equidistant set of parallel linesAn example of the uniform magnetic field over a wide area is the Earth's magnetic field.Learn more about Uniform magnetic field here:
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g The resistance of the wire in the windings of an electric starter motor for an automobile is 2.40 10-2 . The motor is connected to a 13-V battery. What current will flow through the motor when it is stalled (does not turn)
If the resistance of the wire in the windings of an electric starter motor for an automobile is [tex]2.40\times 10^{-2}\text{ } \Omega[/tex] and the motor is connected to a 13-V battery then the amount of current flow through the motor is [tex]5.42 \times10^2\text{ A}[/tex].
Calculation:
Step-1:
It is given that the resistance of the wire in the windings of an electric starter motor for an automobile is [tex]2.40\times 10^{-2}\text{ } \Omega[/tex] and the motor is connected to a 13-V battery. It is required to find the amount of current flow through the motor.
It is known from Ohm's law, it is known that voltage is the multiplication of the current and the resistance of a circuit.
V=IR
Where V is the voltage, I is current, and R is the resistance.
Step-2:
Substituting the given values into the equation to get the value of the current.
[tex]$$\\\begin{aligned}\\V&=IR\\\Rightarrow13 \text{ V}&=I \times 2.40\times10^{-2} \text{ }\Omega\\\Rightarrow I&=\frac{13}{2.40\times10^{-2}} \text{ A}\\ &=5.42 \times10^2\text{ A}\\\end{aligned}\\$$[/tex]
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When attempting to recover your primary second stage underwater, it is acceptable to switch to your alternate air source while you search for your primary. Select one: True False
During primary second stage underwater recovery, it is acceptable to switch to your alternate air source while you search for your primary which makes it a true statement.
What is Primary second stage underwater?This involves the intermediate pressure air from the regulator hose being taken and reduced to ambient pressure.
Switching to your alternate air source will ensure that the diver breathe safely which is why True was chosen.
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An object placed 10.40 cm from a concave spherical mirror produces a real image 7.80 cm from the mirror. If the object is moved to a new position 20.0 cm from the mirror, what is the position of the image
The position of the image, if the object moved to new position 20.0 cm from the mirror is 5.7372 cm.
As per the lens equation,
[tex]\frac{1}{p1} +\frac{1}{q1} =\frac{1}{f}[/tex]
Since, p1 is the position of object initially, q1 is the position of the image initially and f is the focal length of the lens.
[tex]\frac{1}{10.4} +\frac{1}{7.8} =\frac{1}{f}[/tex]
[tex]0.0961+0.1282=\frac{1}{f}[/tex]
[tex]f=4.458[/tex] is the focal length of the given lens.
Then the object moved to second position of p2=20.0 cm from the mirror.
So, [tex]\frac{1}{p2} +\frac{1}{q2} =\frac{1}{f}[/tex]
[tex]\frac{1}{20} +\frac{1}{q2} =\frac{1}{4.458}[/tex]
[tex]\frac{1}{q2}=0.2243-\frac{1}{20}[/tex]
[tex]\frac{1}{q2}=0.1743[/tex]
Hence, q2=5.7372 cm is the new position of the image.
Initially, the object placed 10.40 cm from the mirror, then the image formed at 7.80 cm, then the object moved to 20.0 cm from the mirror, then the new image formed at 5.74 cm.
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derric climbs onto his roof to hang Christmas light. If the roof is 4.3 meters from the ground and derrick gains 2730 J of potential energy while climbing, what is his mass
Mass of Derrick at a height 4.3 m having 2730 joule of energy is 65 Kg.
What is the expression of gravitational potential energy near the earth surface?Mathematically, gravitational potential energy near the earth surface= m×g×hm= mass of Derrick, g= acceleration due to gravity, h= height at which Derrick present Then, mass (m) of Derrick = potential energy/ (g×h)What is the mass of Derrick, if he gains 2730 joule of energy at 4.3m above the ground?Mass of Derrick= 2730/(9.8×4.3)
= 65 kg
Thus, we can conclude that the mass of Derrick is 65 Kg.
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The same bungee jumper from the previous question is now safely back on the ground, but hungry. He eats an apple before going for another jump. What energy transfer is he experiencing?
Group of answer choices
a. Kinetic to chemical
b. Elastic potential to chemical
c. Chemical to gravitational potential
d. Chemical to kinetic
D. The energy transfer he is experiencing is Chemical to kinetic.
Conservation of energy
The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
The apple eaten by the bungee jumper will provide chemical energy which will be converted into kinetic energy of the jumper once he is in motion.
Thus, the energy transfer he is experiencing is Chemical to kinetic.
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What is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second? Assume that no other forces act upon the object.
Group of answer choices
a. 50,000 J
b. 100 J
c. 500 J
d. 1000 J
The kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second is 500J (option C).
How to calculate kinetic energy?The kinetic energy of a body refers to the energy due to the motion of the body. The kinetic energy can be calculated using the following formula:
K.E = ½ × m × v²
Where;
K.E = kinetic energym = massv = speedK.E = ½ × 10 × 10²
K.E = 5 × 100 = 500J
Therefore, the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second is 500J.
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Select each of the following that are recessive alleles represented in the genotype AaBb. Check All That Apply AA BB aa bb
Option (c) and (d) are correct
a and b are the recessive alleles represented in genotype AaBb.
An allele is a different nucleotide sequence that codes for the production of a gene product at the same location on a lengthy DNA molecule.
Recessive Allele : A particular allele that, when present alone, has no effect on the person. The expression of the trait requires the presence of two copies of the allele.
Dominant Allele : A dominant allele is a gene variant that will result in a specific phenotype even when there are other alleles present.
Genotype - The genetic configuration that determines the features that an organism inherits from its parents is known as a genotype.
Phenotype - The term "phenotype" refers to an organism's observable physical characteristics, such as its appearance, growth, and behavior.
Hence (a) & (b) are the recessive alleles represented in the genotype AaBb.
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What is the term for the principal that an object in motion remains in motion until it is met by an outside force?
The term for the principal that an object in motion remains in motion until it is met by an outside force is called inertia
Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force .This principal is named as inertia .
Every matter have inertia , a property to remain in that very position until unless it is been forced on them to change their position .
Inertia is a property of matter that causes it to resist changes in velocity (speed and/or direction). According to Newton's first law of motion, an object with a given velocity maintains that velocity unless acted on by an external force. Inertia is the property of matter that makes this law hold true.
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___________ is defined as intentionally directing someone to or away from specific areas based on the ethnicity of the person or the area.
Steering is defined as intentionally directing someone to or away from specific areas based on the ethnicity of the person or the area.
There are generally three terms used in real estate and that are Steering, Redlining and Blockbusting.
Buyers are guided by steering according to their class.
Redlining mainly refers to the loan industry's discrimination against purchasers.
Blockbusting is the practice of persuading residents of a neighborhood to sell their home because the socioeconomics of the area are deteriorating.
Steering is the act of influencing a buyer's selection of a community based on one of the racial, ethnic, religious, gender, familial, or national origin protected categories listed in the Fair Housing Act.
Hence, Steering is defined as intentionally directing someone to or away from specific areas based on the ethnicity of the person or the area.
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A copper penny has a mass of 3.0 g. A total of 4.0 × 10^12 electrons are transferred from one neutral penny to another. If the electrostatic force of attraction between the pennies is equal to the weight of a penny, what is the separation between them?
Then the separation between the two pennies will be O.354m.
To find the correct answer, we need to know about the electrostatic force of attraction.
What is the separation between the pennies?We have given with the information's,[tex]m=3*10^{-3}kg\\n=4*10^{12}\\[/tex]
As we know that the charge of one electron is 1.6×10^-19C.Thus, the total charge on the penny will be,[tex]Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1[/tex]
We have the expression for electrostatic force of attraction as,[tex]F_e=\frac{kQ_1Q_2}{r^2} =mg\\[/tex] , here given that the electrostatic force equal to the weight of the system.
We have to find the separation between the pennies.[tex]r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m[/tex]
Thus, we can conclude that the separation between the pennies is 0.354m.
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0.354m will be the separation between the two pennies.
We must understand the electrostatic force of attraction in order to arrive at the correct solution.
How far apart are the pennies from one another?One electron has a charge of 1.6 10-19 coulombs, as is common knowledge. Consequently, the total fee for the penny will be,[tex]Q_1=ne=4*10^{12}*1.67*10^{-19}=6.4*10^{-7}C\\Q_2=-Q_1[/tex]
The expression of electrostatic force of attraction is as follows:[tex]F=\frac{kQ_1Q_2}{R^2}=mg[/tex]
Given that the electrostatic force in this instance is equal to the system's weight.
We must determine the distance between the pennies.[tex]R=\sqrt{\frac{kQ_1Q_2}{mg} } =0.354m[/tex]
As a result, we may say that the distance between the pennies is 0.354m.
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A single loop of wire with a radius of 7.5 cm rotates about a diameter in a uniform magnetic field of 1.6 T. To produce a maximum emf of 1.0 V, it should rotate at:
To produce a maximum emf of 1.0 V, the angular speed should rotate at 35.368 rad/s.
What is a uniform magnetic field?A uniform magnetic field is depicted by parallel straight lines that are distributed uniformly. The flux path is the same as the path of a tiny magnet's north-seeking pole. The flux channels are continuous, producing closed loops.
For a single loop of wire with a radius of 7.5 cm that rotates about a diameter in a uniform magnetic field of 1.6T. We need to determine the angular speed of rotation for it to produce a maximum electromotive force (emf) of 1.0 V.
Given that:
The radius = 7.5 cm, to convert it to meters, we will divide it by 100.
= (7.5/100) m
= 0.075 m
The area A of the wire is computed by using the formula:
A = πr²
A = π(0.075)²
A = 0.01767 m²
Imagine a coil with N turns with area A rotating at a constant angular velocity (q) inside a flux density of a (B) of a magnetic field, with its axis parallel to the field.
The maximum e.m.f can be computed by using the formula:
[tex]\mathbf{E_o = BAN \omega}[/tex]
Where;
Magnetic field (B) = 1.6 TMaking the angular speed (ω) the subject of the formula, we have:
[tex]\mathbf{\omega =\dfrac{E}{BNA}}[/tex]
ω = 35.368 rad/s
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Would it be more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 500 C or with a 1 Kg iron bar at 1000 C.
Warming the bed with water is far more efficient than warming the bed with an iron, the difference is the specific heat capacity of water and iron.
The specific heat capacity of a substance can be defined as the amount of the heat required to raise the temperature of the unit mass of a given substance by a given amount (usually one degree).
What is the Specific heat of Water?q = m x C x AT
As the specific heat of water is 4.18 J/g°C and the specific heat of iron is 0.450 J/g°C. Since, the specific heat of water is greater than the specific heat of iron.
Therefore, we can conclude that water is more efficient to warm your bed on a cold night with a hot water bottle that contains 1 kg of water at 50 degrees C.Learn more about Specific heat here:
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A car goes around a curve of radius r at a constant speed v. Then it goes around a curve ofradius 2r at speed 2v. What is the centripetal force on the car as it goes around the secondcurve, compared to the first?
The centripetal force on the car as it goes around the second curve is twice that compared to the first.
What is Centripetal force?
It is the force that is necessary to keep an object moving in a curved path and that is directed inward toward the center of rotation.
The formula of Centripetal force is:
F(c) = (m* v^2) / r
Here,
At the first curve,
The curve of radius = r
The constant speed = v
At the second curve,
The car speed (v')= 2 v
The radius of the curve (r')=2 r
According to the formula of centripetal Force:
As the car goes around the second curve,
F'(c) = m*v'^2 / r'
F'(c) = m* (2*v)^2 / 2r
F'(c) = 2* F
Thus,
The centripetal force on the car as it goes around the second curve is twice that compared to the first.
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The Effect of the Light Intensity and Light Distances of LED and QTH Curing Devices on the Hardness of Two Light-Cured Nano-Resin Composites
Effective polymerization of the composite resin is essential to obtain long term clinical success and has a great importance obtaining improved mechanical properties.
What is the purpose of Effective polymerization of the composite resin ?The purpose of this study was to measure the effect of the light intensity of LED and QTH curing devices in relation to the light distances, on the hardness (KHN) of two light cure nano-resin composite.
Material and Methods: The top and bottom surfaces of the two nanofill composite specimens were evaluated. Two LED and two QTH light curing devices were used at nine different distances. Light intensity was measured with two radiometers placed at these same distances from the curing tip.Learn more about Light intensity here:
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1. Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of uranium-235 to be a mole of “reactions” (molar mass = 235 grams).
2. Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of uranium-235 to be a mole of “reactions” (molar mass = 235 grams).
200 MeV of energy is the energy released per kilogram of fuel used.
E1/E2=7.61=8 (E1 , E2 are energies)
U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.
As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8
In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.
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Answer:
200 MeV of energy is the energy released per kilogram of fuel used.
E1/E2=7.61=8 (E1 , E2 are energies)
U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.
As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8
In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.