A race car makes one lap around a track of radius 180 m in 90.0 s. What is the centripetal acceleration in m/s2?
a
0.5
12.6
Ob
OC
Od
.87
2.
2

Answer:

a heat engine converts heat to mechanical energy.

electric generator

Hi there!

Recall the conservation of momentum for an inelastic collision:

[tex]\large\boxed{m_1v_1 + m_2v_2 = (m_1 + m_2)v_f}}[/tex]

Remember, velocity is a VECTOR and direction must be accounted for. Let the 1000 kg car have a positive velocity and the 1500 kg car have a negative velocity (opposite direction).

Plug in the given values:

[tex](1000)(20) + (1500)(-10) = (1000 + 1500)v_f}}[/tex]

Solve:

[tex]20000 -15000 = 2500v_f}}\\\\5000 = 2500v_f\\\\v_f =\boxed{ 2 m/s}[/tex]

The largest producer of primary air pollution in the United States is what? electricity producing plants.

Answer:

electricity production

Explanation:

Answer:

d and c are the answers :)

Answer:

This is the answer that I got.

Explanation:

Hope it is right.

Answer: this would be D.) What does a turntable built into a track look like

Explanation:

Answer:

25:speed

26:acceleration

27:scalar

28:kinetic

The number of variations the dealership have is 40 cars.

Data given;

This is the total numbers of cars available in the dealer shop at the moment.

To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.

This is equal to

[tex]4*2*5=40[/tex]

From the above calculation, we can say that the variations the dealership offers is 40

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Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

[tex]m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s[/tex]

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

[tex]F_A = -F_B[/tex]

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

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This question involves the concepts of the equations of motion in vertical direction.

The height of the bridge is "116.8 m".

We will use the second equation of motion in vertical direction to find out the height of the bridge.

[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]

where,

h = hieght = ?

vi = initial speed = 0 m/s

t = time taken = 4.88 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]

h = 116.8 m

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The force that cannot be the resultant of these forces is 10N since it is less than both given forces

Given the forces with a magnitude of 12N and 24N, the resultant of these forces must not be less than any of the two forces.

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Answer:

It is originally defined as the mass of one liter (10-3 cubic meter) of pure water.

F = mass × Acceleration ( give Acceleration is 9.8 )

So force of 5 kg mass on A is

F = 5 × 9.8 = 49N

Force of mass 1 kg on A

F = 1 × 9.8 = 9.8 N

Force of mass 10 kg on A is

F = 10 × 9.8 = 98N

Clearly the 10 kg ball experts the most force cause it has more mass

If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.

The  graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.

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Answer:

D. There is not enough information that is known or can be obtained from the graph to determine the net work done on the object.

Explanation:

it’s the answer For Ap classroom

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

The minimum  speed that the second swimmer must have in order to catch up with the first swimmer by the end of the  pool is; 4.04 m/s

We are given the following facts;

Formula for time taken is;

time = distance/speed

Time taken by swimmer 1 for one leg;

t₁ = 50/3.9

t₁ = 12.82 s

Since swimmer 1 has a head start of 0.45 s, then time that swimmer 2 must use in order to catch up is;

t₂ = 12.82 -0.45

t₂ = 12.37 s

Thus, speed of swimmer 2;

v = 50/12.37

v = 4.04 m/s

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Answer:

2000 J

Hope you could get an idea from here.

Doubt clarification - use comment section.

S O L U T I O N:

Here we've been provided with the information i.e

Ans we have given to find out what is work done (W) = ?

The standard formula to calculate work done is given by,

[tex]:\implies\sf{w = f \times s \times cos \theta}[/tex]

[tex]:\implies\sf{w = 20 \times 200 \times cos60}[/tex]

[tex]:\implies\sf{w = 20 \times 200 \times \frac{1}{2} }[/tex]

[tex]:\implies\sf{w = 20 \times 100 \times 1}[/tex]

[tex]:\implies\sf{w = 2000J}[/tex]

Answer:

5) A 200n

F net=0n

6) B 50n

F net=0n

7) C 200n

F net= 900n, up

8) D 80n

F net=60n,left

9) E 300n

F net=60n,left

10)???

11) G 20n

F net=30n,Right

__________________________________

All the answers is hard

correct me if i'm wrong

Answer:

-4,200,000 J

Explanation:

Answer:

MATTER

ARE

OF

THREE

TYPES

SOLID

LIQUID

GAS

Answer:

This above a triangle that models our situation.

Explanation:

We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.

Let the component that travel in the south be the length of a.

According to the problem, the westard component is half of that so let that length be a/2.

Now we must find the angle of the wind in the South.

This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.

[tex] \tan(x) = \frac{opp}{adj} [/tex]

Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have

[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]

[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]

Now we take the arctan or inverse tan of 1/2.

[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]

Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.

The western and southern component have a negative displacement as shown in the graph.

Let the southern component be -x

The western component is half of -x = -x/2

Since the angle is with the south, the trigonometric ratio to be used to find the angle is:

Tan θ = -×/2 /-x

Tan θ = 1/2

θ = tan^-1(0.5)

θ = 26.6°

Therefore, angle of the wind with the south is 26.57°.

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Answer:

100

Explanation:

Displacement is the shortest line between the starting point and the ending point

so , the starting point is "A"

,the ending point is "C"

so "AC" = AB - CB = 300 - 200 = "100"

Thermal expansion is the tendency of matter to change its shape dimensions, density in response to a change in temperature.

  2. Gases

    3. Liquids

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Answer:

(C) Radiation

Explanation:

The weak nuclear forces causes radiation to form.