A reaction produces 156 mL of carbon dioxide gas collected
over water at a temperature of 25.0 °C and a pressure of 99.81
kPa. Calculate the volume of CO2 at STP.
mL
Your answer should be rounded to three significant figures. Do not include units
In your answer.

Answers

Answer 1

The volume of the CO₂ produced at STP, given the data is 141 mL

Combined gas equation

P₁V₁ / T₁ = P₂V₂ / T₂

Where

Initial pressure => P₁Initial temperature => T₁Initial volume => V₁New pressure => P₂New temperature => T₂New Volume => V₂

Data obtained from the questionInitial volume (V₁) = 156 mL Initial temperature (T₁) = 25.0 °C = 25 + 273 = 298 KInitial pressure (P₁) = 99.81 KPaNew pressure (P₂) = STP = 101.325 KPaNew temperature (T₂) = STP = 273 KNew volume (V₂) =?

How to determine the volume at P

P₁V₁ / T₁ = P₂V₂ / T₂

(99.81 × 156) / 298 = (101.325 × V₂) / 273

Cross multiply

298 × 101.325 × V₂ = 99.81 × 156 × 273

Divide both sides by 298 × 101.325

V₂ = (99.81 × 156 × 273) / (298 × 101.325)

V₂ = 141 mL

Thus, the volume of the CO₂ produced at STP is 141 mL

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Related Questions

which element is trigonal pyramidal molecular shape ? a) NF3. b) BCL3 c) COCL2 d) CLO3- e) BRF3

Answers

Answer:

A.) NF₃

D.) ClO₃⁻

Explanation:

To determine the molecular shape of the molecules, you need to:

1.) Calculate the total valence electrons in the molecule

-----> The sum of the element's valence electrons

2.) Draw the Lewis structure

the proper answer gets marked brainiest, answer what the question is asking.

What classifies a substance as an element?
What classifies a substance as a compound?

Actually, answer what the question is asking and give a short answer. No copying and pasting.

Answers

A substance is an element if it consists of a single type of atom. A substance is a compound if it is made up of more than one element.

Elements and compounds

In chemistry, an element is defined as all pure substances consisting of the same atom. For example, magnesium and potassium metal are all elements because they consist of magnesium and potassium atoms only.

On the other hand, compounds are defined as substances consisting of 2 or more atoms of different elements. For example, sodium chloride consists of atoms of sodium and chlorine. Hence, it is considered to be a compound.

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ALab Data
78°F
Verify your volume measurement
You have not titrated to the endpoint
Did you report your data to the correct number of
significant figures?
Standardized NaOH (M) 0.4171
Initial volume of buret (mL) 0.50
Volume of vinegar (mL) 10.00
Observations
solution increased.
Final volume of buret (mL)
Volume of NaOH (mL)
Molarity of acetic acid (M)

Answers

The correct number of significant figures are,

Final volume of burette is 38.86ml

Volume of NaOH is 38.36ml

Given data:

Initial volume of burette V(I)= 0.50ml

Molarity of NaOH is M1 = 0.4171M

Volume of Vinegar V2 = 10.00ml

Molarity of acetic acid M2= 1.6M

Final volume of burette V(f)= ?

volume of NaOH V1 = V(f) - V(I) = ?

Determining the moles of acetic acid (CH3COOH)

Molarity = moles of solute / volume of solution

Molarity of acetic acid = moles of CH3C00H / Volume of vinegar

1.6 = moles of CH3C00H / 10.00

moles of CH3C00H = 1.6 * 10.00

Moles of CH3COOH is 16.00mols

Determining the moles of Sodium Hydroxide (NaOH)

In a volumetric titration the amount of Standard solution (titrant) used in the titration is stoichiometrically equivalent to amount of unknown solution (analyte) used for the titration at the endpoint.

Hence,

Moles of NaOH = Moles of CH3COOH

Moles of NaOH is 16.00mols

Determining the volume of Sodium Hydroxide (NaOH)

Molarity of NaOH = moles of NaOH / Volume of NaOH

0.4171 = 16.00 / V(f)-V(I)

0.4171 = 16.00 / V(f)- 0.50

V(f) = ( 16 / 0.4171 ) + 0.50

V(f) = 38.86 ml

Final volume of NaOH V(f) is 38.86ml

Volume of NaOH V1 = 38.86 - 0.50

Volume of NaOH is 38.36ml

DISCLAIMER: Question is incomplete

Initial volume of burette = 0.50ml

Molarity of NaOH = 0.4171M

Volume of Vinegar = 10.00ml

Molarity of acetic acid = 1.6M

Final volume of burette = ?

volume of NaOH = ?

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Abc Which excerpt from an essay about higher education most clearly shows an example of logos? According to recent studies, more women than ever are attending four-year colleges. In fact, 36.6 percent of women attended college in 2019, compared to 35.4 percent of men. O When I went to college in 1994, I was the first person in my family to do so. My mother stood in my dorm room, surrounded by boxes of clothes and trinkets and holding back tears. O I was in awe of my sociology professor, who had studied the historical impacts of food in African American culture for 10 years. She spoke with such passion and energy that it was difficult to take your eyes off her. O Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork. Mark this and return Save and Exit Next Submit

Answers

The excerpt from an essay about higher education that most clearly shows an example of logos is:

Option d: Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.

What is Logos?

The Logos Definition is one that is often argued by a lot of people as people tends to appeal to others emotions and some other times, people do appeal to one's' ethics or morals.

The term logos is a term that connote the use of logic. It also includes the use of deductive reasoning to get to a conclusion.

The excerpt from an essay about higher education that most clearly shows an example of logos is:

Option d: Many college students look to land an exciting internship, believing that it will open doors in their field of study. However, internships can often distract from schoolwork.

Option d is correct because it shows the cause and its effect.

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Copper metal has a face-centered cubic structure with all atoms at lattice points and a density of 8.93 g/cm^3. The edge length of the unit cell is 361.5 pm. Calculate the mass of 1 atom of copper.

Answers

The mass of 1 atom of copper metal in the given face-centered cubic structure is determined as 1.054 x 10⁻²² g.

Mass of 1 atom of copper

The mass of 1 atom of copper is calculated as follows;

mass of 1 atom of copper = molar mass of copper / Avogadro's number

substitute the value of molar mass of copper and Avogadro's number;

mass of 1 atom of copper = (63.5 g/mol) / (6.023 x 10²³)

mass of 1 atom of copper = 1.054 x 10⁻²² g

Thus, the mass of 1 atom of copper is determined as 1.054 x 10⁻²² g.

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Consider the balanced equation:

Mg2Si (s) + 2 H2O (l) ---> 2 Mg(OH)2 (aq) + SiH4 (g)

Calculate the grams of silane gas, SiH4, formed when 8.48 g of Mg2Si react with excess H2O.

2. Consider the balanced equation:

4 NH3 (g) + 7 O2 (g) ---> 4 NO2 (g) + 6 H2O (g)

What is the mass of H2O produced when 109.4 g of NH3 is completely reacted

Answers

1. The mass of silane gas, SiH₄ formed from the reaction is 3.57 g

2. The mass of H₂O produced from the reaction is 173.75 g

1. How to determine the mass of SiH₄ formed

Balanced equation

Mg₂Si (s) + 4H₂O (l) ---> 2Mg(OH)₂ (aq) + SiH₄ (g)

Molar mass of Mg₂Si = (24×2) + 28 = 76 g/mol

Mass of Mg₂Si from the balanced equation = 1 × 76 = 76 g

Molar mass of SiH₄ = 28 + (4×1) = 32 g/mol

Mass of SiH₄ from the balanced equation = 1 × 32 = 32 g

SUMMARY

From the balanced equation above,

76 g of Mg₂Si reacted to produce 32 g of SiH₄

From the above information, we can obtain the mass of SiH₄ produced by the reaction of 8.48 g of Mg₂Si as illustrated below:

From the balanced equation above,

76 g of Mg₂Si reacted to produce 32 g of SiH₄

Therefore,

8.48 g of Mg₂Si will react to produce = (8.48 × 32) / 76 = 3.57 g of SiH₄

Thus, 3.57 g of SiH₄ were obtained from the reaction.

2. how to determine the mass of H₂O produced

Balanced equation

4NH₃ (g) + 7O₂ (g) ---> 4NO₂ (g) + 6H₂O (g)

Molar mass of NH₃ = 14 + (1×3) = 17 g/mol

Mass of NH₄ from the balanced equation = 4 × 17 = 68 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 6 × 18 = 108 g

SUMMARY

From the balanced equation above,

68 g of NH₃ reacted to produce 108 g of H₂O

From the above information, we can obtain the mass of H₂O produced by the reaction of 109.4 g of NH₃ as illustrated below:

From the balanced equation above,

68 g of NH₃reacted to produce 108 g of H₂O

Therefore,

109.4 g of NH₃ will react to produce = (109.4 × 108) / 68 = 173.75 g of H₂O

Thus, 173.75 g of H₂O were obtained from the reaction.

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How many moles of dissolved sodium hydroxide are in 25.0mL of a 6.00 M sodium hydroxide solution?

Answers

0.025L multiply 6mol/L =0.15 mol

if 14.0 g of aluminium reacts with excess sulfuric acid to produce 75.26 g of aluminium sulfate, what is the percent yield?

Answers

Taking into account definition of percent yield, the percent yield for the reaction is 84.88%.

Reaction stoichiometry

In first place, the balanced reaction is:

2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Al: 2 moles H₂SO₄: 3 molesAl₂(SO₄)₃. 1 moleH₂: 3 moles

The molar mass of the compounds is:

Al: 27 g/moleH₂SO₄: 98 g/moleAl₂(SO₄)₃: 342 g/moleH₂: 2 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

Al: 2 moles ×27 g/mole= 54 gramsH₂SO₄: 3 moles ×98 g/mole= 294 gramsAl₂(SO₄)₃: 1 mole ×342 g/mole= 342 gramsH₂: 3 moles ×2 g/mole= 6 grams

Mass of aluminium sulfate formed

The following rule of three can be applied: if by reaction stoichiometry 54 grams of aluminium form 342 grams of aluminium sulfate, 14 grams of aluminium form how much mass of aluminium sulfate?

[tex]mass of aluminium sulfate=\frac{14 grams of aluminium x342 grams of aluminium sulfate}{54 grams of aluminium}[/tex]

mass of aluminium sulfate= 88.67 grams

Then, 88.67 grams of aluminium sulfate can be produced if 14.0 g of aluminium reacts with excess sulfuric acid.

Percent yield

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

[tex]percent yield=\frac{actual yield}{theorical yield} x100[/tex]

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

Percent yield for the reaction in this case

In this case, you know:

actual yield= 75.26 gramstheorical yield= 88.67 grams

Replacing in the definition of percent yields:

[tex]percent yield=\frac{75.26 grams}{88.67 grams} x100[/tex]

Solving:

percent yield= 84.88%

Finally, the percent yield for the reaction is 84.88%.

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PLEASE ANSWER THIS FAST... tysm
●what will happen to the texture off egg shell if you place it in.
1. Coca cola

2. orange juice

3. grape juice

4. normal water

5. a dark coloured sugary drink like sting

Answer all these correctly please

thanks

Answers

Answer:

4. the egg shell you place in normal water

Find the number of moles and the number of atoms of Hydrogen and s in 10 moles of H₂S

Answers

Answer:

See below

Explanation:

H2 S shows that each mole of H2S has two moles of H in it

so 10 moles of H2S would have 20 moles of H

Each mole is Avagadro's Number of atoms

20 moles * 6.022 x10^23 atoms/mole = 120.44 x 10^23 toms of H

H2S has one mole of S for each mole of H2S

there are then 10 moles of S

10 * 6.022 x 10^23 = 60.22 x 10^23 atoms of S

A can of soda is opened at room temperature and a hiss is heard. Which factor has changed inside the container?

Answers

The factor that has changed inside the container would be the pressure.

Pressurized containers

Sodas in cans are preserved using a gas, carbon dioxide to be precise.

The gas is used to preserve the drink and sealed under pressure.

When a can of soda is opened, the first thing that escapes is the carbon dioxide gas. By doing so, the pressure in the can reduces.

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A glass container was initially charged with
3.00 moles of a gas sample at 3.75 atm and
21.7 °C. Some of the gas was released as the
temperature was increased to 28.1 °C, so the
final pressure in the container was reduced to
0.998 atm. How many moles of the gas
sample are present at the end?
Answer in mol

Answers

The number of moles of the gas sample present at the end is 0.78 moles.

Number of moles of the gas

PV = nRT

V = nRT/P

At a constant volume, V;

n₁RT₁/P₁ = n₂RT₂/P₂

n₁T₁/P₁ = n₂T₂/P₂

n₂ = (n₁T₁P₂)/(P₁T₂)

where;

T₁ is initial temperature = 21.7⁰C = 294.7 KT₂ is final temperature = 28.1⁰C = 301.1 K

n₂ = (3 x 294.7 x 0.998)/(3.75 x 301.1)

n₂ = 0.78 moles

Thus, the number of moles of the gas sample present at the end is 0.78 moles.

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Determine the empirical formula of a compound containing 40.6 grams of carbon, 5.1 grams of hydrogen, and 54.2 grams of oxygen.
In an experiment, the molar mass of the compound was determined to be 118.084 g/mol. What is the molecular formula of the compound?
For both questions, show your work or explain how you determined the formulas by giving specific values used in calculations.

Answers

The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

What is Empirical Formula ?

Empirical formula is the simplest whole number ratio of atoms present in given compound.

Element % Atomic mass Relative no. of atoms Simplest whole ratio

C 40.6 12 [tex]\frac{40.6}{12}[/tex] = 3.3 [tex]\frac{3.3}{3.3} = 1[/tex]

H 5.1 1 [tex]\frac{5.1}{1}[/tex] = 5.1 [tex]\frac{5.1}{3.1} = 2[/tex]

O 54.2 16 [tex]\frac{54.2}{16}[/tex] = 3.3 [tex]\frac{3.3}{3.3} = 1[/tex]

The Empirical formula of compound is C₁H₂O₁ or CH₂O

How to find the Molecular formula of compound ?

Molecular formula = Empirical formula × n

[tex]n = \frac{\text{Molecular weight}}{\text{Empirical Formula weight}}[/tex]

[tex]= \frac{118.084}{30}[/tex]

= 4

Molecular formula = n × Empirical formula

= 4 (C₁H₂O₁)

Thus from the above conclusion we can say that The Empirical formula of compound is C₁H₂O₁. The Molecular Formula of the compound is 4 (C₁H₂O₁).

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Identify the parts of the equation by dragging each label below to the correct arrow on the diagram. Drag the items on the left to the correct location on the right.

Answers

The missing labels are:

CuCO₃(s), H₂SO₄(aq): reactants. +: plus sign. CuSO₄(aq), H₂O(l), CO₂(g): products. (s): solid.(aq): aqueous.(l): liquid.(g): gaseous.

What is a chemical equation?

It is a way to represent a chemical reaction.

Let's consider the following chemical equation.

CuCO₃(s) + H₂SO₄(aq) → CuSO₄(aq) + H₂O(l) + CO₂(g)

The missing labels are:

CuCO₃(s), H₂SO₄(aq): reactants. They are on the left side of the equation.+: plus sign. It separates substances.CuSO₄(aq), H₂O(l), CO₂(g): products. They are on the right side of the equation.(s): solid.(aq): aqueous.(l): liquid.(g): gaseous.

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What state of matter is Polaris, the north star?

A. Plasma
B. Liquid
C. Light
D. Gas

Answers

The state of matter of Polaris, the north star is gas.

What are stars made of?

Stars are made up of a mixture of hot gases.

The mixture consists of helium and hydrogen. Hydrogen burns into helium to give starts a shining appearance when observed from a far distance.

Thus, the state of matter of all stars, including the north star, is gas.

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In a calorimetry experiment 2.50 g of methane is burnt in excess oxygen. 30% of the energy released during the combustion is absorbed by 500 g of water, the temperature of which rises from 25°C to 68°C. The specific heat capacity of water is 4.184 J/g°C. What is the total energy released per gram of methane burnt?

Answers

The total energy released per gram of methane burnt is 119,941.3 J/g.

Energy absorbed by water

Q = mcΔθ

where;

m is mass of waterc is specific heat of waterΔθ is change in temperature

Q = (500)(4.184)(68 - 25)

Q = 89,956 J

Total energy released per gram of methane burnt

0.3T = 89,956 J

T = 89,956 J/0.3

T = 299,853.3 J

Total energy per gram of methane, E = T.E/m

E = (299,853.3 J) / (2.5 g)

E = 119,941.3 J/g

Thus, the total energy released per gram of methane burnt is 119,941.3 J/g.

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Volume is: A. Non of these. B. How much matter something contains.

Answers

B. How much matter something contains

The cell membrane is
a)semi permeable
b)selectively permeable

Answers

Answer:

A. Semi Permeable.

Explanation:

Cell membranes are semi permeable.

Research the ecology of your region and find one species that is endangered. Find an estimate of the population of the species in your region. Describe the threats facing that species, especially threats posed by human activities.

Answers

The endangered species in my region with their estimate population are:

Northwestern African Cheetah - 250 West African Lion - 400

What threat faces Northwestern African Cheetah?

This cheetah is said to be an endangered species because of their loss of their habitat and also due to fragmentation, trade and little human-activities.

West African Lion is said to be an endangered species because the lion's historic range in West Africa was said to be lowered by a lot of amount or scale as a result of land use changes and human activities such as falling of trees, buildings, etc.

Hence the endangered species in my region with their estimate population are:

Northwestern African Cheetah - 250 West African Lion - 400

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Explain why the middle portion of ship shows more rust than either the top most or the bottom most part

Answers

Answer:

A ship comprises of both visible as well as invisible parts. . The most forward part of a ship is called a Bow, the left-hand side of . at a topmost accessible height of the ship and just above the bridge . The mast is a rangy spar arrangement which is elevated more or less vertically to the Centre line of a ship .

which gas law is not included in the combined gas law

Answers

Answer:

Watson law is not part of the combined gas law

Gas Laws

There are 5 basic gas laws of ideal gases:

Boyle's Law: volume (V) is inversely proportional to pressure (P)Charles' Law: V is proportional to temperature (T)Gay-Lussac's Law: P is proportional to TDalton's Law: The total pressure exerted by a mixture of ideal gases is equal to the sum of the pressures of the individual gasesAvogadro's Law: All equal volumes of ideal gases contain the same number of gas particles (at constant T and P); V is proportional to moles (n)

The Combined Gas Law

This law features Charles', Boyle's and Gay-Lussac's laws.

Therefore, Dalton's and Avogadro's laws are exluded.

QUESTION 3
List the two ways of determining the chloride content of water

Answers

After removing the particles, the solution's chloride content can be assessed using various techniques, such as titration and photometry.

What is the importance of chloride determination?One of the most prevalent inorganic anions in water and wastewater is chloride, which forms the chloride (Cl-) ion. Sodium chloride, a specific food item that passes through the digestive tract undigested, has a higher chloride concentration in wastewater than in raw water. Due to salt water leaking into the sewage system, coast chloride may be present in high concentrations along the sea. Additionally, industrial processes may cause it to rise.The salty taste caused by chloride concentration in drinkable water varies and depends on the water's chemical makeup. If sodium cation is present, some waters with 250 mg/L Cl- may have a flavor that can be identified as salty. On the other hand, when calcium and magnesium cations predominate, the typical salty taste may be missing in fluids containing as much as 1000 mg/L. A high chloride level may injure developing plants, steel pipelines, and structures.The salinity of various water sources can be determined using the detected chloride ions. It is a crucial parameter for brackish water (or seawater or industrial brine solution) because it indicates how much desalting of the apparatus is needed. Additionally, it affects the COD calculation, necessitating a modification based on the amount present or adding a complexing agent like HgSO4. Additionally, column studies that predict the fate of various pollutants in soil and liquid media use chloride ions as tracer ions.

After removing the particles, the solution's chloride content can be assessed using various techniques, such as titration and photometry.

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GIVING BRAINLIEST!!!!!!!!! (and the rest of my points)
The Himalayan balsam plant makes seeds in pods and releases them when it is ready, while the Surinam toad absorbs its eggs into its own back until they are ready to come out. How are the adaptations of the balsam and the toad similar?

A. They are behaviors that allow the plant and the animal to reproduce through shorter life cycles.
B. They are behaviors that protect the plant and the animal from predators.
C. They are life cycle differences that protect the offspring and help them to survive.
D. They are physical characteristics that allow the offspring to survive in cold weather conditions.

Answers

They are life cycle differences that protect the offspring and help them to survive. The correct option is C.

Life cycle adaption

Some organisms have life cycle features that ensure that their population is perpetuated in subsequent generations.

Such features include ensuring that propagules are only released when they are mature and making sure that eggs are hatched and offspring become viable before they are allowed to move to the environment.

These actions will make sure that the propagules of offspring have what it takes to survive in their new environment.

In other words, these life cycle features are embedded in the genome of organisms as a way to survive the environment.

Thus, the features of the Himalayan balsam plant and that of the Surinam toad are more or less targeted toward the same thing - the survival of their offspring.

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Answer: Option (C) is correct, They are life cycle differences that protect the offspring and help them to survive.

Explanation: Hope it helps!

Good luck!!!

A buffer is prepared by adding 150mL of 0.50 M NH3 to 250mL of 0.50 M NH4NO3. What is the pH of the final solution? (Kb for NH3 = 1.8 x 10^-5)

Answers

From the calculations, the pH of the final solution is 9.04.

What is the pH of the buffer?

We can use the Henderson Hasselbach equation to obtain the final pH of the solution in terms of the pKb and the base concentration.

Number of moles of salt = 250/1000 L * 0.5 M = 0.125 moles

Number of moles of base = 150/1000 L * 0.5 M = 0.075 moles

Total volume of solution = 250ml + 150ml = 400ml or 0.4 L

Molarity of base = 0.075 moles/ 0.4 L = 0.1875 M

Molarity of salt = 0.125 moles/ 0.4 L = 0.3125 M

pOH = pKb + log[salt/base]

pKb = -log(1.8 x 10^-5) = 4.74

pOH = 4.74 + log[0.3125/0.1875 ]

pOH = 4.96

pH = 14- 4.96

pH = 9.04

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characteristic ions of water: OH- and H3O+

Answers

Answer:

H2O

Explanation:

water is made up of 1 hydrogen snd 2 oxygen

Look at Table 4 in the procedure portion of the experiment. Calculate the pH you would expect each of the buffer solutions (A, B, C, D, and E) to be using the Henderson-Hasselbalch equation, assuming that the solutions of acetic acid and sodium acetate are equimolar.

Answers

The pH of the buffer solutions as determined using the Henderson–Hasselbalch equation are:

A. pH = 4.75B. pH = 4.05C. pH = 3.75D. pH = 5.75E. pH = 5.45

What is the pH of the solutions?

The pH of a buffer is determined using the Henderson–Hasselbalch equation shown below:

pH = pKₐ + log([A⁻]/[HA])

A. Volume of acetic acid = 5 mL; Volume of sodium acetate = 5 mL; pka of acetic acid = 4.75