Answer:
the answer is the rollar coster
Explanation:
because the rollar coster is
ii. Which of these has a heating element with a low melting point?
a, electric bell
c. electric iron
b. fuse
d. all of these
A race car accelerates uniformly from 18.5 m/s in 2.47 seconds m. Determine the acceleration of the car in m/sec^2 and the distance
The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2. The distance traveled is average velocity times time of travel.
With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s
[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]
[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]
[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]
[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]
[tex]\\ \sf\longmapsto s=55+121[/tex]
[tex]\\ \sf\longmapsto s=176m[/tex]
A number line goes from negative 5 to positive 5. Point D is at negative 4 and point E is at positive 5. A line is drawn from point D to point E. What is the location of point F, which partitions the directed line segment from D to E into a 5:6 ratio? Negative one-eleventh One-eleventh Two-fifteenths Fifteen-halves.
The location of the point F that partitions a line segment from D to E ([tex]\overline{DE}[/tex]), that goes from negative 4 to positive 5, into a 5:6 ratio is fifteen halves (option 4).
We need to calculate the segment of the line DE to find the location of point F.
Since point D is located at negative -4 and point E is at positive 5, we have:
[tex] \overline{DE} = E - D = 5 - (-4) = 9 [/tex]
Hence, the segment of the line DE ([tex]\overline{DE}[/tex]) is 9.
Knowing that point F partitions the line segment from D to E ([tex]\overline{DE}[/tex]) into a 5:6 ratio, its location would be:
[tex] F = \frac{5}{6}\overline{DE} = \frac{5}{6}9 = 5*\frac{3}{2} = \frac{15}{2} [/tex]
Therefore, the location of point F is fifteen halves (option 4).
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I hope it helps you!
Answer:
The above answer is actually incorrect - the real answer is B. 1/11
Explanation:
I'm adding a ss below for proof
Hope this helped!
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an airplane flies with a constant speed of 620 miles per hour. how far can it travel in 3 1/2 hours?
Answer:
hi there !
1 hour -------> 620 miles
3 1/2 ---------> ?
the number of miles the airplane travels in 3 1/2 hours
= 3 1/2 × 620 = "2170" miles
HEELPPPP!! A train travels 195 kilometers in 4.0 hours, and then 125 kilometers in 3.0 hours. What is its average speed?
Answer:
Train A has a speed 20 miles per hour greater than that of train B. If train A travels 300 miles in the same times train B travels 220 miles, what are the speeds of the two trains?
2. A woman has a total of $13,000 to invest. She invests part of the money in an account that pays 11% per year and the rest in an account that pays 12% per year. If the interest earned in the first year is $1490 how much did she invest in each account?
Explanation:
Help me answer this question please!
a car dealer sells 4 makes of cars in 5 colors with either standard or automatic transmissions. how many variations does the dealership offer?
The number of variations the dealership have is 40 cars.
Data given;
The number of different product = 4The number of transmission = 2 (standard or automatic)The numbers of colors available = 5Dealership variationThis is the total numbers of cars available in the dealer shop at the moment.
To get that, we simply multiply the numbers of colors available, the number of transmission and the makes of car available.
This is equal to
[tex]4*2*5=40[/tex]
From the above calculation, we can say that the variations the dealership offers is 40
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A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragster? Answer to the nearest hundredth
when an individual charge flies through a *blank* field, a force is exerted on the charge and the path of the charge bends.
Answer:
"electric or magnetic"
F = q E force on charge q due to electric field E
F = q v x B force on charge q due to magnetic field B
a narrow slit is illuminated with sodium yellow light of wavelength 589 nm. if the central maximum extends to ±30.0°, how wide is the slit?
Answer:
because of the gravity of the earth
HELP!!!!!!!!!!!!
9. Estimate the change in the thermal energy of water in a pond with a mass of
1000 kg and a specific heat of 4200 J/(kg. C) if the water cools by 1°C.
Answer:
-4,200,000 J
Explanation:
How did the Agricultural Revolution impact humans? In your opinion, were those changes good or bad? Why?
Answer:
The Agricultural Revolution of the 18th century paved the way for the Industrial Revolution in Britain. New farming techniques and improved livestock breeding led to amplified food production. This allowed a spike in population and increased health. The new farming techniques also led to an enclosure movement
Two lumps of clay approach each other from opposite directions and collide head on inelastically, combing into one large lump after they collide. the first lump has a mass of 0.140kg and has a speed of 3.50 m/s before the Collision. the second lump has a mass of 0.620kg and has a speed of 4.81 m/s before the collison in a direction opposite that of the first lump. what velocity does the combined lump have after the collision?
Answer:
Before collision:
momentum to right = .14 * 3.5 = .49 kg m / s
momentum to left = .62 * 4.81 = 2.98 kg m / s
Total momentum = .49 - 2.98 = - 2.49 to left
M V = -2.49 net momentum to left
V = -2.49 / (.14 + .62) = -3.28 m/s to left
Scientific notation of 1,750
“Applications of thermal expansion in solids, liquids and gases.”
(Two for each states of matter)
Thermal expansion is the tendency of matter to change its shape dimensions, density in response to a change in temperature.
The following are applications of thermal expansion in various matter.SolidsThe principle of thermal expansion is used in thermostat to regulate the temperature of heating device e.g Electric pressing Iron.Rivets are used to hold steel plates together very tightly.
2. Gases
Hot-air balloons are an application of thermal expansionGases turbine3. Liquids
Engine CoolantsVolume of thermometerLearn more about Expansion of matter here:
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calculate the resultant force acting on the object and state its direction
[tex]\\ \sf\Rrightarrow F_{net}=F_1+F_2+F_3+F_4[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=20N+20N+10N-10N[/tex]
[tex]\\ \sf\Rrightarrow F_{net}=40N[/tex]
Direction is east.John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s
The horizontal component of the velocity is equal to: D. 15 m/s.
Given the following data:
Velocity = 30 m/sAngle = 60°To determine the horizontal component of the velocity:
The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.
Mathematically, the horizontal component of velocity is given by the formula:
[tex]V_x = Vcos(\theta)[/tex]
Substituting the given parameters into the formula, we have;
[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]
Horizontal component, Vx = 15 m/s
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Assume ideal behavior. How many moles of are needed to fill a 2000L weather balloon at 210K and 1atm pressure? Round your answer to the nearest mole (use R = 0.082057 L atm mol-1K-1)
Considering the ideal gas law, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.
An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas. The universal constant of ideal gases R has the same value for all gaseous substances.
In this case, you know:
P= 1 atmV=2000 Ln= ?R= 0.082057 [tex]\frac{atmL}{molK}[/tex]T= 210 KReplacing in the ideal gas law:
1 atm× 2000 L = n× 0.082057 [tex]\frac{atmL}{molK}[/tex]× 210 K
Solving:
[tex]n=\frac{1 atmx 2000 L}{0.082057 \frac{atmL}{molK}x 210 K}[/tex]
n=116.06 moles
Finally, 116.06 moles of are needed to fill a 2000 L weather balloon at 210 K and 1 atm pressure.
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https://brainly.com/question/4147359?referrer=searchResultsTwo billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.
This question involves the concepts of the law of conservation of momentum and velocity.
The velocity of the eight ball is "5.7 m/s".
According to the law of conservation of momentum:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]
where,
m₁ = mass of number three ball = 5 g
m₂ = mass of the eight ball = 6 g
u₁ = velocity of the number three ball = 3 m/s
u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)
v₁ = final velocity of the three number ball = - 5 m/s
v₂ = final velocity of the eight ball = ?
Therefore,
(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)
[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]
v₂ = 5.7 m/s
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If the western component of the wind is half of the south, what is the angle of the wind with the south?
Answer this question in details!
Answer is 26.57 or tan^-1 (1/2) or cot^-1 (2)
no links !
Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.
[tex] \tan(x) = \frac{opp}{adj} [/tex]
Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have
[tex] \tan(x) = \frac{ - \frac{a}{2} }{ - a} [/tex]
[tex] \tan(x) = - \frac{a}{2} \times - \frac{1}{a} = \frac{1}{2} [/tex]
Now we take the arctan or inverse tan of 1/2.
[tex] \tan {}^{ - 1} ( \frac{1}{2} ) = 26.57[/tex]
Based on the information about vector components and graph provided, the angle of the wind with the south is 26.57°.
What are the values of the western and southern component of the wind?The western and southern component have a negative displacement as shown in the graph.
Let the southern component be -x
The western component is half of -x = -x/2
What is the angle of the wind with the South?Since the angle is with the south, the trigonometric ratio to be used to find the angle is:
Tan θ = opp/adjTan θ = -×/2 /-x
Tan θ = 1/2
θ = tan^-1(0.5)
θ = 26.6°
Therefore, angle of the wind with the south is 26.57°.
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An object is projected into the air with a vertical velocity of 20 feet per second. At what times will the object be on the ground
Answer:
20 ft/sec / 32 ft/sec^2 = .625 to reach top
2 * .625 = 1.25
It will be on the ground at t = 0 and t = 1.25
You can also solve the equation:
H = 0 = V0 t - 1/2 g t^2
Obviously, at t=0 h = 0
V0 = 1/2 g t is a solution
t = 20 * 2 / 32 = 1.25 sec
A 3 Kg ball at the end of a string is spun in a circle. If the length of the string is 2 m and the velocity of the ball is 6 m/s, what is the centripetal acceleration of the ball? What is the centripetal force on the ball?
Exert a force on the object, what happens to their state of motion
The force might make the object move or bring the object to rest or change in direction of motion
Recoil is noticeable if you throw a heavy ball while standing on roller skates. If instead you go through the motions of throwing the ball but hold onto it, your net recoil velocity will be
Answer:
Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.
The net recoil velocity must be zero.
c. Two persons A and B are pushing a block from opposite sides with
force of 5N and 6N respectively.
[3]
i) Find the magnitude of the resultant force on the block.
ii) Find the direction of resultant force with respect to A and B.
Answer:
1 N
Explanation:
1) You'll just have to sum the force vectors, and since they are opposite, you'll calculate the difference of their magnitudes, in absolute value.
Ftot = |F1 - F2| = 6N - 5N = 1N
2)The direction will be the same as the greater force's direction.
What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.
The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
HOW TO CALCULATE KINETIC ENERGY:
The kinetic energy of a moving body can be calculated by using the following formula:
K.E = ½mv²
Where;
K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:
K.E = ½ × 0.75 × 4²
K.E = 8 × 0.75
K.E = 6J
Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.
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Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass of 0.8 kg. The spring is released and causes the two carts to push off from each other. Which of the following correctly compares the motion and forces acting on the two carts?
A. Cart A experiences a greater force but has the same speed as Cart
B. Cart A experiences a greater force and has a greater speed after the recoil.
C. Both carts experience the same force but Cart A has a greater speed after the recoil.
D. Both carts experience the same force and have the same speed after the recoil.
Both carts experience the same force but Cart A has a greater speed after the recoil.
The given parameters;
Mass of the cart A = 0.4 kgMass of the cart B = 0.8 kgApply the principle of conservation of linear momentum to determine the velocity of the carts after collision;
[tex]m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s[/tex]
According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.
[tex]F_A = -F_B[/tex]
Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."
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Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?
Answer:
2 miles
Explanation:
Paint is an example of which of these?
compound
heterogeneous mixture
homogeneous mixture
none of the above
Answer:
Homogenous Mixture
Explanation:
The composition in paint is uniform so every part of it looks the same throughout the paint.