The range of force exerted at the end of the rope is 285.7 N to 1,000 N.
Net horizontal force of the cylinder
The net horizontal force of the cylinder when it is at equilibrium position is determined by applying Newton's second law of motion.
∑F = 0
F - μFn = 0
F - 0.2(5,000) = 0
F - 1,000 = 0
F = 1,000 N
The strength of the applied force increases as the number of turns of the rope increases.
minimum force = total force/number of turns of rope
minimum force = 1,000/3.5
minimum force = 285.7 N
Thus, the range of force exerted at the end of the rope is 285.7 N to 1,000 N.
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In order to compare the thermal conductivities of two different insulators, a scientist pours hot water into two
beakers.
The different insulators are wrapped around the beakers.
The scientist records the initial temperatures of the hot water.
a) State two factors that should be kept constant in order to make the experiment fair.
An object is pushed at an angle of 42˚ by a force of 135 N through a distance of 829 cm. Find the work done by the object.
The work done by the object is 831.69 J.
What is work?Work can be defined as the product of mass and distance.
To calculate the work done by the object, we use the formula below
Formula:
W = Fdcos∅............ Equation 1Where:
W = Work done by the objectF = Force on the object∅ = Angle.From the question,
Given:
F = 135 Nd = 829 cm = 8.29 m∅ = 42°Substitute these values into equation 1
W = 135×8.29×cos42°W = 831.69 J.Hence, The work done by the object is 831.69 J.
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the refractive index is the blank of the speed of light in a medium to the speed of light in a vacuum
Answer:
ratio
Explanation:
Apex Verified
An archerfish, peering from just below the water surface, sees a grasshopper standing on a tree branch that's just above the water. The archerfish spits a drop of water at the grasshopper and knocks it into the water. The grasshopper's initial position is 0.45 m above the water surface and 0.25 m horizontally away from the fish's mouth. The launch angle of the drop is 630 with respect to the water surface.
A. Find an expression for how fast the drop is moving when it leaves the fish's mouth. (Your expression should only contain symbols of physical quantities. No numbers are needed here. )
B. Find the numerical value for how fast the drop is moving when it leaves the fish's mouth. (Plug the values of physical quantities into your expression from part A (do not forget units!) Evaluate your answer that you found in part B by using it to find the value of a physical quantity given in the problem statement. (This is called evaluating for consistency.) For instance, suppose you knew the initial speed of the water (i.e., your answer in part B), the launch angle ( 63º) and the grasshopper's initial horizontal position (0.25 m). Using this information, find the initial vertical position of the grasshopper. Is this value consistent with the value given in the problem statement?
Answer:
Explanation:
Let the required velocity be V at angle θ with the horizontal . Let time taken in the whole process be t
horizontal component = v cosθ
It will cover .25 m at this velocity
vertical component = v sinθ
It will cover .45 m with this initial velocity and with deceleration g .
v cosθ t = .25
.45 =v sinθ t - 1/2 g t²
putting the values of t from above
.45 = .25 tanθ - g .25² / 2 v² cos²θ
B ) putting the values of θ
.45 = .25 tan63 - 9.8 x .25² / 2 v² cos² 63
.45 = .49 - 1.53 / v²
1.53 / v² = .04
v² = 38.25
v = 6.18 m /s
time taken to cover distance of .25 m
t = .25 / 6.18 cos63 = .089 s
during this period , vertical displacement
= 6.18 sin 63 x .089 - 1/2 x 9.8 x .089²
= .4895 - .04 = .45 m which is consistence with given height .
Bumper car A (296 kg) moving +3.74 m/s makes an
elastic collision with bumper car B (222 kg) moving
+1.85 m/s. What is the velocity of car A after the
collision?
For a bumper car A (296 kg) moving +3.74 m/s, and a bumper car B (222 kg) moving +1.85 m/s, the velocity of car A after the collision is mathematically given as
V1=4.977m/s
What is the velocity of car A after the collision?Generally, the equation for the Velocity of car A is mathematically given as
[tex]V1=\frac{m1-m2v1}{m1+m2}v1 +\frac{2m_2}{m1+m2}v2[/tex]
Therefore
[tex]V1=\frac{296-222}{296+222}*23.74+\frac{2*222}{296+222}*1.85[/tex]
V1=4.977m/s
In conclusion, The velocity of car A after the collision
V1=4.977m/s
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Answer:3.74
Explanation:
it was given same goes for bumper car b
What does refractive index mean?
The driver of a car steps on the brakes, and the velocity drops from 43 m/s due east to 3.38 m/s due east in a time of 70seconds. What is the acceleration?
Answer:
Explanation:
initial velocity, u = 43 m/s
final velocity, v = 3.38 m/s
time, t = 70 sec
acceleration, a = v - u / t
3.38 - 43 / 70
= -39.62/ 70
= -0.56 m/s^2
Hope this helps
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Select the correct answer.
What is proper technique for lifting?
A.
Bend your back
B.
Bend at your knees and lift with your legs.
C.
Focus your power from your back.
D.
None of the above
Answer:
B
Explanation:
Answer:
i think it's either B or C
Explanation:
A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C. Its efficiency is
A. 13%
B. 39 %
C.61%
D. 88 %
E. 90 %
The efficiency of a carnot engine with absorb temperature and exhaust temperature is 13%. The correct option is A.
What is Efficiency?The efficiency is defined as the work done by the engine divided by the heat supplied.
So, efficiency η = 1 - T₁/T₂
Where T₁ is the lower temperature and T₂ is the higher temperature.
A Carnot engine absorbs heat at a temperature of 127 °C and exhaust heat at a temperature of 77 °C
Substitute the value into the expression , we get
η = 1 -(77+273) / (127+273) x 100 %
η = 12.5 %
or
η = 13 %
Thus, the efficiency of the carnot engine is 13%.
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Reuptake means that:
Answer:
it means absorption by a presynaptic nerve ending of a neurotransmitter that it has secreted.
Explanation: I hoped that helped please leave a 5 rate and thanks. Have a great day .
An unbalanced force of 20 N is applied to a 10 kg mass. What is the acceleration of the mass?
Answer:
2 m/s2
Explanation:
Newton's 2nd law:
F=ma
20 N= (10 kg)a
a= 2 m/s2
A force of 10 n acts on a mass of 5 kg producing an acceleration of 1.5 m/s2 what is the magnitude of the force of friction acting on the mass
Given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton
Given the data in the question;
Force acting on the object; [tex]F = 10N[/tex]Mass of the object; [tex]m = 5kg[/tex]Acceleration of the object; [tex]a = 1.5 m/s^2[/tex]Force of friction acting on the mass; [tex]F_k = \ ?[/tex]To determine the magnitude of the force of friction acting on the mass,
From Newton's laws of motion
[tex]F = m\ *\ a[/tex]
Where F is the force applied, m is the mass of the object and a is the acceleration of the object.
Now, we know that Kinetic Friction is always opposite of the direction of motion.
So, in the question, the force applied overcomes the friction to produce an acceleration of [tex]1.5 m/s^2[/tex]
Hence
[tex]F = F_k + ma[/tex]
Where [tex]F_k[/tex] is the kinetic friction
Now, we substitute our given values into the equation
[tex]10N = F_k +\ ( 5kg\ *\ 1.5m/s^2)\\\\10N = F_k +\ 7.5kg.m/s^2[/tex]
We know that, A newton is defined as [tex]1 kg.m/s^2[/tex]
Hence;
[tex]10N = F_k\ *\ 7.5N\\\\F_k = 10N \ -\ 7.5N\\\\F_k = 2.5N[/tex]
Therefore, given the force applied, the magnitude of the force of friction acting on the mass is 2.5 Newton.
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If you apply a force of 200N to an object with a mass of 50kg, what will the acceleration be?
Answer:
Acceleration = 4 m/s
Explanation:
Acceleration = force divided by mass
So;
a = 200 ÷ 50 = 4
If 10 waves come in every 8 seconds with a wavelength of 2 meters, what is the frequency?
Answer:
Explanation:
frequency = 10/8 = 1.125 Hz
what is the acceleration of a 10 kg mass pushed by a 5 newton force?
Answer:
0.5 m/s²
Explanation:
F=ma
F is force
m is mass
a is acceleration
F=ma
5 = 10 x a
a = 5/10
a = 0.5 m/s²
Why is the international system of measurement helpful?
a.
They are not in English.
c.
All scientists can use them.
b.
No scientists can use them.
d.
They are easy to remember.
Please select the best answer from the choices provided
A
B
C
D
International system of measurements in helpful because all scientists can use them
International System of measurement abbreviated SI is the modern most widely accepted system of unit of measurement
Which of the following exerts the most pressure while resting on a floor?
a. a 25 N cube with 1.5 m sides
b. a 15 N cylinder resting vertically with a base radius of 1.0 m
c. a 25 N cube with 2.0 m sides
d. a 25 N cylinder resting vertically with a base radius of 1.0 m
The pressure of the cube that exerts the most pressure while resting on a floor is mathematically given as
P=16.6pascal, Option D is correct
Which of the following exerts the most pressure while resting on a floor?Generally, the equation for the Pressure is mathematically given as
P=force/Area
Therefore, In considering the one with the most pressure we look at the one with the most force/Area
In conclusion, the one with the most Force/Area is a 25 N cube with 1.5 m sides
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difference between text-talk novel and flash fiction?
See the flash fictions are small nov.els with para.graphs where as ch*.t story is a storyline that just look like some c
c.h.*.t.s.
Both "text-talk novels" and "flash fiction" are forms of written literature, but they have distinct characteristics and purposes.
Text-Talk Novel:
A text-talk novel, also known as a "chat novel" or "text-message novel," is a narrative written in the style of text messages or chat conversations. These novels are typically composed of short, informal messages exchanged between characters, presented in a way that resembles conversations on messaging apps. Text-talk novels often use emojis, abbreviations, and informal language to create a sense of immediacy and relatability. They are designed to be read on mobile devices and appeal to readers who are used to communication through texting and social media platforms. Text-talk novels often cater to a younger audience and can cover various genres, from romance to mystery.
Flash Fiction:
Flash fiction, also known as "microfiction," "short-short stories," or "sudden fiction," refers to extremely short works of fiction characterized by their brevity. Flash fiction stories are typically no longer than 1,000 words, and often much shorter. Despite their limited length, flash fiction stories aim to convey a complete narrative, evoke emotions, and leave a lasting impact on the reader. Due to their concise nature, flash fiction stories often focus on a single idea, moment, or theme, and they require skillful crafting to create a meaningful story within a tight word count. Flash fiction can cover a wide range of genres and styles, and its brevity challenges writers to distill their storytelling abilities to essentials.
Hence, a "text-talk novel" is a novel written in the style of text messages or chat conversations, aiming to engage readers familiar with mobile communication. On the other hand, "flash fiction" refers to very short stories that convey complete narratives or ideas within a limited word count, challenging writers to create impactful stories in a condensed format.
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Stars appears to move from east to west because
A. all stars move from east to west
B. the earth rotates from west to east
C. the earth rotates from east to west
D. the background of the stars moves from west to east
Answer:
The earth rotates from West to east
Explanation:
Every planet in our solar system rotates around their axis in West to east direction.Only Venus is the only planet which rotates from east to westAn astronaut is floating in space. There is no rope connecting him to the ship. They have some tools and a
fire extinguisher.
Which action could propel the astronaut back to the ship? (Select two answers)
He could spray the fire extinguisher in the opposite direction of the ship
He could throw a tool in the opposite direction of the ship
He could throw a tool toward the ship
He could point the extinguisher towards the ship and spray it.
Answer:
It's A it is correct trust me and no I didn't copy the other person I just read the answers.
Hope this helps:)
Explanation:
An experiment is set up to determine the speed of charged particles as they move through a region that is traversed by a constant electric and a constant magnetic field. The particles are moving toward the right of the page when they encounter the region. The electric field points toward the top of the page, and the magnetic field points out of the page. Required:
Predict how the positively and negatively charged particles of various speeds will behave in this experiment
The deflection will be toward the backside for bad cost and closer to the pinnacle of the spread page for the high-quality charge.
What are charged particles?Charged particles are simply defined as particles with an electric charge on them. This may sometimes result in being an ion, as a molecule with excess or a reduced amount of electrons relative to protons.
Generally, the Magnetic area points internal the airplane so through fleming left hand rule is
F = q ( V x B). Ie
hence
qVB = qE
V= E/B then no deflection.
V > E/B then magnetic pressure is dominant over electric powered force.
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The space station Babylon 5 has a diameter of 1 miles, and rotated around its long axis to produce artificial gravity for its inhabitants. It completes 1 revolutions/min. Calculate the effective gravitational strength at the outer rim of the station, in units of g. (use g = 9.81 m/s^2)
This question involves the concept of artificial gravity.
The effective gravitational strength at outer rims is "0.9 g".
Artificial GravityThe effective gravitational strength at the outer rims can be given by the following formula:
[tex]v=\frac{1}{2\pi}\sqrt{\frac{a_c}{r}}\\\\a_c=4\pi^2v^2r[/tex]
where,
[tex]a_c[/tex] = effective gravitational strength = ?v = rotational speed = 1 rev/min = 0.0167 rev/sr = radius = diameter/2 = 1 mile/2 = 0.5 miles = 804.672 mTherefore,
[tex]a_c = 4\pi^2(0.0167\ rev/s)^2(804.672\ m)\\a_c =8.82\ m/s^2\\\\In\ terms\ of\ g:\\\\a_c=(8.82\ m/s^2)(\frac{g}{9.81\ m/s^2})\\\\a_c = 0.9g[/tex]
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median of 18 24 17 21 24 16 29 18
Answer:
19.5
Explanation:
16,17,18,18,21,24,24,29
(fourth (18) and fifth(21)) ÷2=
(18+21)÷2=
39÷2=
19.5 is median
A spacecraft passes you at 0.255 the speed of light. By what factor does the relativistic energy increase if its speed doubled and if you subtract out the constant rest energy
The factor increase in the relativistic energy is 0.129.
Relativistic kinetic energy of the spacecraftThe relativistic kinetic energy of the spacecraft is determined as follows;
[tex]K = (\frac{1}{\sqrt{1- \frac{v^2}{c^2} } } )mc^2[/tex]
where;
v is the speed of the spacecraftc is the speed of lightAt 0.255 speed of light, the relativistic kinetic energy is calculated as follows;
[tex]K = (\frac{1}{\sqrt{1- \frac{(0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.065c^2}{c^2} } } )mc^2\\\\K = 1.034mc^2[/tex]
When the speed doubles, v = 2(0.255c)
[tex]K = (\frac{1}{\sqrt{1- \frac{(2 \times 0.255c)^2}{c^2} } } )mc^2\\\\K = (\frac{1}{\sqrt{1- \frac{0.261c^2}{c^2} } } )mc^2\\\\K = 1.163mc^2[/tex]
Increase in energyΔK = 1.163mc² - 1.034mc²
ΔK = 0.129mc²
Thus, the factor increase in the relativistic energy is 0.129.
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which types of star cluster is shown
Open star clusters tend to orbit within the disk. Globular star clusters contain hundreds of thousands of stars, and some – like Omega Centauri, shown above – contain millions of stars. Open star clusters tend to contain only hundreds of stars.
How is the gravitational force related to the distance between two objects?
S
It is directly proportional to the square of the distance.
It is inversely proportional to the square of the distance.
it is directly proportional to the distance.
it is inversely proportional to the distance.
gravitational force is inversely proportional to the square of the separation distance between the two interacting objects
Gravitational force is inversly proportional to the square of the distance. Option B is correct.
What is gravitational force?Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
[tex]\rm F=G\frac{mM}{R^2}[/tex]
Gravitational force is inversly proportional to the square of the distance.
Hence option B is correct.
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If a system absorbs 155.0 kJ of heat from its surroundings and the system does 45.0 kJ of work on its surroundings, what is the change in the internal energy of the system, in kJ
The change in the internal energy of the system is 110 kJ.
What is internal energy?Internal energy is defined as the energy associated with the random, disorder motions of molecules.
calculate the change in internal energy, we apply the formula below.
Formula:
ΔU = Q-W.................... Equation 1Where:
ΔU = Change in internal energyQ = Heat absorbed from the surroundingsW = work done by the systemFrom the question,
Given:
Q = 115 kJW = 45. 0 kJSubstitute these values into equation 1
ΔU = 155-45ΔU = 110 kJHence, The change in the internal energy of the system is 110 kJ.
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Answer:
110.0kJ
Explanation:
The following solution may contain one or more values that are different from the problem provided to you, however, the steps to solve the problem are the same.
.The internal energy (E) of a system can change as heat (q) flows into or out of the system, or work (w) is done on or by the system. The following equation represents the relationship.
ΔE=q+w
In this question, heat is absorbed by the system, so it has a positive sign. Work is done by the system, so it has a negative sign.
ΔE=(155.0 kJ)+(−45.0 kJ)=110.0 kJ
A car driving down a street has a kinetic energy of 32,000 J. If the car has a mass of 1,600kg, at what velocity is the car moving?
Explanation:
The mechanical energy can be expressed as kinetic and potential energy, given by the equation;
ME=KE+PE
but since the car isn't elevated off the ground nor is it subjected to the restoring force of a spring, we can then say PE=0
ME=KE
The equation of KE=0.5mv²
ME=0.5mv²
32 000=0.5(1600)v²
[tex]v {}^{2} = \frac{32 \: 000}{1600 \times 0.5} [/tex]
[tex]v {}^{2} = \frac{32 \: 000}{800} [/tex]
[tex] {v}^{2} = 40[/tex]
[tex]v = \sqrt{40} = 6.324[/tex]
v=6.324 m/s :)
A Home Depot worker pushes a lumber cart loaded with a mass of 115 kilograms of lumber. If he accelerates the cart with an acceleration 5.6m/s^2 what is the amount of force the worker applied.
Answer:
use math.way
Explanation:
i solved it.
An astronaut weighs 104 newtons on the moon, where the strength of gravity is 1.6N/kg. What is her mass?