Mathematics High School

A sample of n = 22 is taken and the sample mean is =35 and a sample standard deviation of s= 9.38. Construct a 95% confidence interval for the true mean, µ.
(33, 37)
(31.56, 38.44)
(30.84, 39.16)
(25.62, 44.38)

Answers

Answer 1

The answer is (B) (31.56, 38.44) which means we are 95% confident that the true population mean lies between 31.56 and 38.44.

The 95% confidence interval for the population mean, µ, is given by:

CI =  ± tα/2 * (s/√n)

where  is the sample mean, s is the sample standard deviation, n is the sample size, and tα/2 is the t-value with (n-1) degrees of freedom at the α/2 level of significance.

Here,  = 35, s = 9.38, and n = 22. From the t-distribution table with (n-1) = 21 degrees of freedom and a 95% confidence level, we have tα/2 = 2.08.

Plugging in the values, we get:

CI = 35 ± 2.08 * (9.38/√22)

= (31.56, 38.44)

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