Answer:
Fr = 150 [N]
a = 5 [m/s²]
Explanation:
In order to find the resulting force, we must assume that the thrust force is positive to the right, while the friction force is negative to the left.
[tex]F_{r}=200-50\\F_{r}=150[N][/tex]
Now Newton's Second Law tells us that the sum of the forces or the resulting force is equal to the product of mass by acceleration.
F = m*a
[tex]150 = 30*a\\a=150/30\\a = 5 [m/s^{2} ][/tex]
Write two different unit in which mass is measured.
Answer:
kilograms and grams
Explanation:
kilograms is the stadard unit for mass according to the SI system.
Grams is another unit for mass.
A star's brightness as if it were a standard distance from Earth (10 parsecs) is known as what? radiation apparent brightness lighting absolute brightness
Answer:
In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).
Explanation:
Suppose that with a pulley system you need to exert a force of 1,400N to lift a heavy object. But without the pulley system, you need to exert 4,200N to lift the object. What is the MA of the pulley system?
Answer:
Mechanical Advantage is 0.3
Explanation:
Step one:
given data
Load L= 1400N
Effort E= 4200N
Required
The mechanical advantage of the pulley system
Step two:
We know that the expression for the mechanical advantage is
MA= Load/Effort
MA= 1400/4200
MA=0.3
A constant horizontal F force began to act on the initially immovable body placed on a horizontal surface. After t time the force ceased to act, and after time 3t from the start of the movement the body stopped. Find the coefficient of friction between the body and the surface if the body mass is m.
Answer:
The coefficient of friction is (F/(19.6·m)
Explanation:
The given parameters are;
The force applied to the immovable body = F
The time duration the force acts = t
The time the body spends in motion = 3·t
The acceleration due to gravity, g = 9.8 m/s²
From Newton's second law of motion, we have;
The impulse of the force = F × t = m × Δv₁
Where;
Δv₁ = v₁ - 0 = v₁
The impulse applied by the force of friction, [tex]F_f[/tex] is [tex]F_f[/tex] × (3·t - t) = [tex]F_f[/tex] × (2·t)
Given that the motion of the object is stopped by the frictional force, we have;
The impulse due to the frictional force = Momentum change = m × Δv₂ = [tex]F_f[/tex] × (2·t)
Where;
Δv₂ = v₂ - 0 = v₂
Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to act, v₁, we have;
m × Δv₂ = [tex]F_f[/tex] × (2·t) = m × Δv₁ = F × t
∴ [tex]F_f[/tex] × (2·t) = F × t
[tex]F_f[/tex] = F × t/(2·t) = F/2
The coefficient of dynamic friction, [tex]\mu _k[/tex] = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)
[tex]\mu _k[/tex] = (F/(19.6·m)
The coefficient of friction, [tex]\mu _k[/tex] = (F/(19.6·m)
In pulling two identical carry-on bags through the airport, Mr. Myers and his 13 year old grandson, Vincent, do the same amount of work. Who has to use a greater force between gates?
Answer:
Mr Myers and his son use the same force to pull the bags between the gates
Explanation:
The work done by Mr. Myers in pulling the carryon bags = The work done by his 13 year old grandson in pulling the identical bag
Let F₁ represent the force used by Mr Myers, and let F₂ represent the force F₂ used by his grandson
Let d represent the distance through the gate
Therefore, given that Work done, W = Force, F × Distance, we have;
The work done by Mr Myers between the gates, W₁ = F₁ × d
The work done by his grandson between the gates, W₂ = F₂ × d
Where, the work done by both Mr Myers and his grandson are equal, we have;
W₁ = W₂ and therefore, F₁ × d = F₂ × d, which gives;
F₁ = F₂, the force used by both Mr Myers and his son between the gates are equal.
A simple harmonic transverse wave is propagating along a string towards the left direction as shown in the figure. figure shows a plot of displacement as function of position at time t=0.The string tension is 3.6 Newton and it’s linear density is 25GM/M. Calculate
I) the amplitude
Ii) the wavelength
Iii) wave speed
Iv) the period
V) The maximum particle speed in the String
Answer:
Amplitude = 5 cm (Heights)Wavelength (λ) = 40 cm Wave speed (v) = 12 m/s (Approx)Time period (T) = 0.033 s (Approx)Maximum particle speed (V) = 9.43 m/sExplanation:
1) Amplitude
Amplitude = 5 cm (Heights)
2) Wavelength (λ)
Wavelength (λ) = 40 cm
3) Wave speed
Wave speed (v) = √ t / μ
Wave speed (v) = √ 3.6 / [25x10⁻³]
Wave speed (v) = 12 m/s (Approx)
4) Time period (T)
Time period (T) = 1/f = (λ)/v
Time period (T) = 0.40m / 12
Time period (T) = 0.033 s (Approx)
5) Maximum particle speed (V)
Maximum particle speed (V) = Aw
Maximum particle speed (V) = [0.05x2x3.14] / 0.033
Maximum particle speed (V) = 9.43 m/s
When a hammer strikes a nail, the nail..
exerts balanced forces that helps it from moving.
exerts a force equal to the weight of the hammer..
exerts an unbalanced force that changes its velocity.
exerts an equal and opposite force back on the hammer.
Answer:
Could you possible elaborate on the question more?
Answer:
eH?
Explanation:
10 cm^3 of iron have a smaller
mass then 115 cm^3 of wood.
(density of iron 7.9 g/cm^3)
(density of wood 0.7 g/cm^3)
true or false
Explanation:
Mass of iron = (7.9)(10) = 79g
Mass of wood = (115)(0.7) = 80.5g
Therefore iron has a smaller mass than the wood, which is true.
Suppose a candle is burned in a closed system where matter cannot enter or leave. Given this situation,
what is equal to the mass of the original candle?
Answer:
Mass of the melted wax
Explanation:
The mass of the original candle that has been burnt in the closed system is equal to the mass of the melted wax.
A closed system is a system where matter cannot be exchange with the surrounding. As the candle undergoes a phase change during the burning, it melts to liquid wax. Since there is no loss of mass, the amount of matter in the system is conserved. Therefore, the mass of the molten wax will be the same as the mass of the candle originally melted.Give a paragraph on how to become a better leader
Answer:
Anyone can sit in a corner office and delegate tasks, but there is more to effective leadership than that. Effective leaders have major impacts on not only the team members they manage, but also their company as a whole. Employees who work under great leaders tend to be happier, more productive and more connected to their organization – and this has a ripple effect that reaches your business's bottom line
Explanation:
:)
Fig. 2.1 shows the extension-load graph for a spring.
extension
06
load
Fig. 2.1
Dint P is the limit of proportionality.
:) (0) Name the law obeyed by the spring from the origin to P.
[1]
(ii) Describe two features of the graph which show that the law is obeyed.
2.
[2]
-) On Fig. 2.1, sketch a possible continuation of the graph when the spring is loaded
beyond the limit of proportionality.
Answer:
(1) Hooke's law
(2) a) Extension is directly proportional to the applied load
b) The starting point of the graph is the origin (0, 0) or absence of load, no extension
Explanation:
(1) The law obeyed by the spring is known as Hooke's law which states that the extension or compression, x, of a spring proportional to the applied force, F
F = -k × x
Where;
k = The spring constant
(2) Given that the law mathematically is F = -k × x
The two features of the graph that show that the law is obeyed are;
a) The extension increases as the load is increased
b) The extension is zero when the there is no applied load.
help please 10 pts and quick!
can someone write me a short response
Answer:
Explanation:
Pecan 1 and 4 seem the best answer
Michael is biking on a trail and is accelerating at a rate of 1.2 m/s/s for 15 seconds. He began this part of his ride with a velocity of 1.62 m/s. Determine Michael's final velocity?
Answer:
Michael's final velocity is 19.62 m/s.
Explanation:
We can find the final velocity of Michael by using the following kinematic equation:
[tex] v_{f} = v_{0} + at [/tex] (1)
Where:
[tex]v_{f}[/tex]: is the final velocity =?
[tex]v_{0}[/tex]: is the initial velocity = 1.62 m/s
a: is the acceleration = 1.2 m/s²
t: is the time = 15 s
By entering the above values into equation (1) we have:
[tex] v_{f} = 1.62 m/s + 1.2 m/s^{2}*15 s [/tex]
[tex] v_{f} = 19.62 m/s [/tex]
Therefore, Michael's final velocity is 19.62 m/s.
I hope it helps you!
A horizontal disc of radius 45 cm rotates about a vertical axis through its centre. The disc makes one full
revolution in 1.40 s. A particle of mass 0.054 kg is placed at a distance of 22 cm from the centre of the disc.
The particle does not move relative to the disc.
a On a copy of the diagram draw arrows to represent the velocity and acceleration of the particle. [2]
b Calculate the angular speed and the linear speed of the particle. [2]
c The coe cient of static friction between the disc and the particle is 0.82. Determine the largest distance
from the centre of the disc where the particle can be placed and still not move relative to the disc. [3]
d The particle is to remain at its original distance of 22cm from the centre of the disc.
i Determine the maximum angular speed of the disc so that the particle does not move relative to
the disc. [2]
ii The disc now begins to rotate at an angular speed that is greater than the answer in d i. Describe
qualitatively what happens to the particle. [2]
Answer:
a. Please find attached the diagram of the disc, having arrows that represent the velocity and the acceleration of the particle placed on it
b. The angular speed is approximately 4.488 rad/s
The linear speed is approximately 0.987 m/s
c. The largest distance from the center of the disc where the particle can be placed and still not move is approximately 0.399 m from the center of the disc
d. i The maximum angular speed of the disk so that the particle does not move relative to the disk is approximately 6.044 rad/sec
ii When the angular speed with which the disc rotates is more than the the answer of question d i above, the particle slips on the disc, and the disc begins to rotate faster than the particle, while the particle is swung in an outward radial direction off the disc due to the centrifugal forces
Explanation:
The given parameters are;
The radius of the horizontal disc, r = 45 cm = 0.45 m
The time the disc makes one full revolution, T = 1.40 s
The mass of the particle placed on the disc = 0.054 kg
The location on the disc the particle is placed = 22 cm from the disc's center
a. Please find attached the diagram of the disc created with Microsoft Visio, with arrows representing the velocity and the acceleration of the particle placed on the disk
b. The angular speed, ω = 2·π/T = 2 × π/1.4 ≈ 4.488 rad/s
The linear speed, v = ω × r = 4.488 rad/s × 0.22 m ≈ 0.987 m/s
The linear speed, v ≈ 0.987 m/s
c. The given coefficient of static friction = 0.82
Therefore;
The frictional force that prevents motion = Weight of the particle × The coefficient of static friction
The frictional force that prevents motion is [tex]F_f[/tex] = 0.054 × 9.8 × 0.82 ≈ 0.434 N
[tex]F_f[/tex] ≈ 0.434 N
Therefore, for the largest distance from the center of the disc where the particle can be placed and still not move, r, is given by the formula for the centripetal force, [tex]F_c[/tex], acting on the particle as follows;
For static equilibrium, no movement of the particle relative to the disc, we have;
[tex]F_f[/tex] = [tex]F_c[/tex]
Where;
[tex]F_c = \dfrac{m \times v^2}{r} = m \times \omega ^2 \times r[/tex]
Which gives;
[tex]F_c = {0.054 \ kg \times (4.488 \ rad/s)^2} \times r = F_f = 0.434 \ N[/tex]
r = 0.434 N/(0.054 kg × (4.488 rad/s)²) ≈ 0.399 m
The largest distance from the center of the disc where the particle can be placed and still not move, r = 0.399 m from the center of the disc
d. i From the static equilibrium equation where r = 0.22 m, we have;
[tex]F_c = {0.054 \ kg \times \omega ^2} \times 0.22 \ m = F_f = 0.434 \ N[/tex]
ω = √(0.434 N/(0.054 kg × (0.22 m))) ≈ 6.044 rad/sec
The maximum angular speed of the disk so that the particle does not move relative to the disk, ω ≈ 6.044 rad/sec
ii When the angular speed with which the disc rotates is more than the the answer of question d i above, we have
The particle begins to slip on the disc such that the disc rotates faster than the particle and the particle tends to rotate slower than the speed pf the disc and is swung off the disc by centripetal force acting on the particle due to the rotational motion of the disc.
A 750 g ball is raised 3 m off the ground and then thrown. What is the potential energy
of the ball before the throw?
Answer:
22.05 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass in kg
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question
750 g = 0.75 kg
We have
PE = 0.75 × 9.8 × 3
We have the final answer as
22.05 JHope this helps you
I got a new kitten and I dont know how to train them to use a leash. Can anyone help?
Efficiency is a measure of how much of the work put into a machine is converted into useful output work. Why can efficiency never reach 100%?
A) Acceleration
B) Elasticity
C) Friction
D) Gravity
Answer:
C , Friction
Explanation:
A clown in a circus act swings a 2.7-kg metal ball attached to a 72.0-cm nylon string in a horizontal circle above her head, making one revolution in 0.98 s. What is the tension force, Ft, exerted on the string by the ball?
Answer:
Tension, Ft = 79.91 N
Explanation:
The tension in the string is the resultant force that exists in the string due to the centripetal effect of the swinging ball.
From conservation laws, the tension in the string will be equals to the centripetal force acting on the string.
The tension in a string can be obtained using the formula:
[tex]T=mv^2/R[/tex]
where v = linear velocity of the metal ball which equals to the angular velocity of the ball X the radius of the ball.
The radius of the ball is given as 72 cm = 0.72m and the angular velocity = 1.02 rad/second.
Therefore, linear velocity, [tex]v = 2\pi \times 1.02\times 0.72 =4.616m/s[/tex]
The tension in the string will now be equals to [tex]2.7 \times 4.616^2 /0.72 =79.91N[/tex]
Use the drop-down menus to determine which state of matter is described in each statement.
The atoms in a
are closely packed, but able to slide past each other.
The atoms in a
spread as far apart as possible.
A
has a definite shape and volume.
The shape of a
can change, but the volume is definite.
Answer:
Explanation:
There are three states of matter; solid, liquid and gaseous states.
The solid state of matter has it's particles tightly packed with very restricted or no movement within the molecule hence the reason for it's definite shape.
The liquid state of matter has it's particles with a free movement (better than solid but not as free as gases) within the molecule hence it's particles are loosely packed within the molecule. Hence, they (liquids) assume the shape of the container in which they are stored and they move freely when released from the container.
The gaseous state of matter has it's particles totally loosely packed as a result of it's particles moving freely and colliding against one another.
Thus, we can use the above descriptions to answer the statements from the question.
1) The atoms in a ----- are closely packed, but able to slide past each other. Answer: From the description above, it can be deduced that the atoms here are in a solid because the particles within a solid are closely packed.
2) The atoms in a -------- spread as far apart as possible.
Answer: The atoms here are in gaseous form because, as described earlier, they are loosely packed and can thus be as far apart as possible.
3) A ----- has a definite shape and volume.
Answer: As described earlier, a solid substance would have a definite shape and volume because it's particles are tightly packed.
4) The shape of a ----- can change, but the volume is definite.
Answer: The substance here is a liquid because the particles are free (but not as free as gases) and would have a definite volume but will assume the shape of the any container they are placed in (hence they have an irregular shape).
Answer:
The atoms in a
✔ liquid
are closely packed, but able to slide past each other.
The atoms in a
✔ gas
spread as far apart as possible.
A
✔ solid
has a definite shape and volume.
The shape of a
✔ liquid
can change, but the volume is definite.
Explanation:
what is meant by momentum?
Answer:
Im afraid i need to to know more on what your asking, are you asking what is momentum?
Explanation:
Because therefore it is the quantity of motion of a moving body, measured as a product of its mass and velocity to the state of motion
or
p = mv
I hope this helps and have a good day, or to best that you can make it <33
Answer:
Momentum can be defined as "mass in motion "OrMomentum is how we measure mass that is in motion ORMomentum,product of mass of particle and its velocityExplanation:
Please mark my answer as a brainliest. Please follow me. ❤❤❤❤❤Fossils, plants, and animals are what make rocks different from minerals.
true of fales
Can someone look outside and tell me what they see in the sky .The looks like a crystal ball or a mini moon
Answer:
i know it,s the ☁️ it looks like a crystal ball or a mini moon
your stopped at a red light. You've checked the intersection to see that it is clear of vehicles and pedestrians, unless a tells you not, you may then?
Answer:
Unless you are at a red light you may not proceedYou pose a threat to other drivers who are following the instructions and ethics.
[tex]x3n + 5x2n + 12xn + 18 \div xn + 3[/tex]
Answer:
sorry its impossible
Explanation:
a truck of mass 200kg rests on an inclined plane hindered from rolling down the surface by a storing sprint whose force constant is 10^6N/M.neglecting friction,how much work does the truck do on the spring?
Answer:
1.92 J
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 200 Kg
Spring constant (K) = 10⁶ N/m
Workdone =?
Next, we shall determine the force exerted on the spring. This can be obtained as follow:
Mass (m) = 200 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Force (F) =?
F = m × g
F = 200 × 9.8
F = 1960 N
Next we shall determine the extent to which the spring stretches. This can be obtained as follow:
Spring constant (K) = 10⁶ N/m
Force (F) = 1960 N
Extention (e) =?
F = Ke
1960 = 10⁶ × e
Divide both side by 10⁶
e = 1960 / 10⁶
e = 0.00196 m
Finally, we shall determine energy (Workdone) on the spring as follow:
Spring constant (K) = 10⁶ N/m
Extention (e) = 0.00196 m
Energy (E) =?
E = ½Ke²
E = ½ × 10⁶ × (0.00196)²
E = 1.92 J
Therefore, the Workdone on the spring is 1.92 J
How do minerals crystallize or form in veins ?
Answer:
For example, when magma heats water deep underground, elements and compounds in the surrounding rock will dissolve in the water, forming a solution. ... The cooling process causes them to crystalize and form minerals inside the rock. These are called veins
the steps of mieosis
Answer:
Since cell division occurs twice during meiosis, one starting cell can produce four gametes (eggs or sperm). In each round of division, cells go through four stages: prophase, metaphase, anaphase, and telophase.
Answer:
here are six stages within each of the divisions, namely prophase, prometaphase, metaphase, anaphase, telophase and cytokinesis
Explanation:
Write the newtons formula for the velocity of sound in air .how did Laplace correct this formula ?
Answer:
1: v = √E/ρ where E is the elasticity and ρ is the density. Newton's assumed that sound wave travel in air under isothermal condition
2: He corrected Newton's formula by assuming that, there is no heat exchange takes place as the compression and rarefaction takes place very fast. Thus, the temperature does not remain constant and the propagation of the sound wave in air is an adiabatic process.
What is the velocity of a wave with a frequency of 930 Hz and a wavelength of 0.50 m?
Answer:
Hi, thank you for posting your question here at Brainly.
To find the velocity of light or any electromagnetic wave, we use the equation: v = wavelength * frequency. Substituting,
v = 0.5 m * 930 1/s
v = 465 m/s
Brainiest please
Explanation:
Example of first, second and third law of motion.
Examples of Newton's three law of motion.
First law of motion: A rocket being launched up in the atmosphere.
Second law of motion:while riding a bicycle, a bicycle acts as a mass and our legs pushing on the pedals of the bicycle is the force.
Third law of motion:when we jump off from the boat,the boat moves backward.
Hope,it will helpyouu!