A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it to reach the height.
(g= 10m/s)

who gives answer with explanation i will make him braillint

Answers

Answer 1

Answer:

The maximum height it reaches will be 20 m.

The time taken by it to reach the height will be: t = 2 seconds.

Explanation:

We know the equation of the motion under gravity

v² - u² = 2gs

u = initial velocity = 20 m/s

v = final velocity = 0 m/s

[tex]s\:=\:h_{max}[/tex]

so

[tex]v^{2} \:-\:u^{2} \:=\:2gs[/tex]

substituting u = 20 m/s, v = 0 m/s, g = -10 and [tex]s\:=\:h_{max}[/tex]

[tex]\left(0\right)^2-\:\left(20\right)^2=\:2\left(-10\right)\times h_{max}[/tex]

[tex]2\left(-10\right)\times h_{max}=-400[/tex]

[tex]\frac{2\left(-10\right)h_{max}}{-20}=\frac{-400}{-20}[/tex]

[tex]\:h_{max}=20[/tex] m

Therefore, the maximum height it reaches will be 20 m.

We know the equation

u = gt

substitute u = 20, g = 10

20 = 10 × t

t = 20/10

t = 2 seconds

Therefore, the time taken by it to reach the height will be: t = 2 seconds.


Related Questions

Question 2 of 5
This landform is on Mount Callaghan, British Columbia. It
formed as rocks slide down a steep cliff.
What directly led to this landform?

Answers

Answer:

Mass wasting

Explanation:

Took the test

Answer:

Mass wasting

Explanation:

because

Pete Zaria applies a 4.0-N force to a 1.0-kg mug of root beer to accelerate it over a distance of 1.0-meter along the countertop. Determine the work done by Pete on the mug and the mug's final kinetic energy and final velocity. PSYW

Answers

Answer:

Work done = 4 J

Final Kinetic Energy = 4 J

Explanation:

From the question,

Work done = force × distance

W = F×d................... Equation 1

Given: F = 4.0 N, d = 1.0 meter.

Substitute these values into equation 1

W = 4×1

W = 4 Joules.

Also,

Kenetic Energy = 1/2 × mass × velocity×velocity.

K.E = 1/2(mv²)........... (2).

But,

F = ma

Where F = 4 N, m = 1 kg.

a = 4/1 = 4 m/s².

Using,

v² = u² + 2as............. Equation 3

Where u = 0 m/s, a = 4 m/s², s = 1 m.

Substitute into equation 3

v² = 0² +2×4×1

v² = 8

v = √8 m/s.

Substitutting into equation 2

K.E = 1/2(1)(√8)²

K.E = 1/2(8)

K.E = 4 J.

Hence the work done and the Final Kinetic energy are thesame = 4 J

The work done by the Pete is 4.0 J. And its final velocity and kinetic energy are 2.82 m/s and 3.97 J respectively.

Given data:

The force applied by the Pete Zaria is, F = 4.0 N.

The mass of mud is, m = 1.0 kg.

The distance of the countertop is, s = 1.0 m.

The work by the Pete on the mug is equal to the product of applied force and the distance covered by the mug along the rooftop. Therefore,

W = F × s

W = 4.0 × 1.0

W = 4.0 J

Now, apply the third kinematic equation of motion to obtain the final velocity of the mug as,

[tex]v^{2} = u^{2}+2as[/tex]

Here, a is the magnitude of acceleration and its value is,

F = ma

4.0 = (1.0)a

a = 4.0 m/s²

Now,

[tex]v=\sqrt{0^{2}+(2 \times 4 \times 1)}\\\\v = 2.82 \;\rm m/s[/tex]

Now. the kinetic energy of the mug is calculated as,

[tex]KE = \dfrac{1}{2}mv^{2}\\\\KE = \dfrac{1}{2} \times 1.0 \times 2.82^{2}\\\\KE = 3.97 \;\rm J[/tex]

Thus, we can conclude that the work done by the Pete is 4.0 J. And its final velocity and kinetic energy are 2.82 m/s and 3.97 J respectively.

Learn more about the kinetic energy here:

https://brainly.com/question/17858145

An astronaut and his space suit have a combined mass of 157 kg. The
astronaut is using a 5 kg tqol kit to repair a solar panel on the International
Space Station. When the têther connecting the astronaut to the space
station becomes unattached, the astronaut, still holding the tool kit, starts
to float away at 0.2 m/s. Calculate the velocity with which the astronaut
must throw the tool kit in order to float back toward the space station at
0.1 m/s. Show your calculations and include units in your answer.
*

Answers

Answer:

v₃ = 9.62[m/s]

Explanation:

To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.

We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.

Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.

In this way, we can construct the following equation.

[tex]-(m_{1}+m_{2})*v_{1}=(m_{1}*v_{2})-(m_{2}*v_{3})[/tex]

where:

m₁ = mass of the astronaut = 157 [kg]

m₂ = mass of the toolkit = 5 [kg]

v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]

v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]

v₃ = velocity at which the toolkit should be thrown [m/s]

Now replacing:

[tex]-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s][/tex]

The velocity with which the astronaut must throw the tool kit is 9.62 m/s.

The given parameters:

Mass of the astronaut and space suit, m₁ = 157 kgMass of the tool kit, m₂ = 5 kgVelocity of the astronaut and tool kit, v = 0.2 m/sVelocity of the astronaut and space station, u₁ = -0.1 m/s

Apply the principle of conservation of linear momentum to determine the velocity of the tool kit;

[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\-0.1(157) \ + 5u_2 = 0.2(157 + 5) \\\\-15.7 + 5u_2 = 32.4\\\\5u_2 = 32.4 + 15.7\\\\5u_2 = 48.1\\\\u_2 = \frac{48.1}{5} \\\\u_2 = 9.62 \ m/s[/tex]

Thus, the velocity with which the astronaut must throw the tool kit is 9.62 m/s.

Learn more about conservation of linear momentum here: https://brainly.com/question/7538238

Calculate the momentum of a 78 kg cheetah running at 24 m/s.

Answers

Answer:

1872 kg.m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 78 × 24

We have the final answer as

1872 kg.m/s

Hope this helps you

Which diagram best illustrates what happens when electromagnetic waves strike a reflective material?

Answers

Answer:

The second diagram does that

The last diagram below represents what happenes when electromagnetic waves strike a reflective material. The last diagram is showed in the image below.


I have like 3 min !!!

Answers

Answer:

to talk??? i will talk with you

How much power does it take to do 1000 J of work in 8 seconds?

Answers

Power = work/time
1000/8 = 125
Answer: 125 watts

The tubes that go from the trachea into the lungs

Answers

the answer is bronchi

To find motion and distance time graph which formula we have to use please tell.

Answers

Answer:

umm nobody can solve this without a picture of what it is......

Explanation:

paraffin wax is used to make candles
true or false

Answers

Answer:

true

Explanation:

PLS MAKE ME AS BRAINLIST

Photons with the highest energy have the ____

A. strongest positive charge

B. longest period

C. highest amplitude

D. shortest wavelength

Answers

Answer:

D. shortest wavelength

Explanation:

Photons with the highest energy have the shortest wavelength. The shorter the wavelength, the higher the energy of a photon.

A photon is a quantity that transmits electromagnetic energy from one place to the other.

Gamma rays have photons that transmits the highest amount of energy. The rays have the shortest wavelength and highest frequency of all electromagnetic radiations.

Energy, wavelength and frequency of a photon are connected using the expression:

    E =  h f  = [tex]\frac{hc}{wavelength}[/tex]  

E is the energy

h is the Planck's constant

 f is the frequency.

HELP ASAPP!! WILL TRY TO GIVE BRAINLIEST

What is produced in the nucleolus?

Answers

Answer: Image result for What is produced in the nucleolus?

The nucleolus is a region found within the cell nucleus that is concerned with producing and assembling the cell's ribosomes. Following assembly, ribosomes are transported to the cell cytoplasm where they serve as the sites for protein synthesis.

Explanation: hope this helps! PLs mark me as brainliest! Thank you and have a wonderful day/night!

If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?

Answers

Answer:

Its speed will be 280 m/s

Explanation:

Constant Acceleration Motion

It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

[tex]v_f=v_o+at[/tex]

The object accelerates from rest (vo=0) at a constant acceleration of [tex]a=8\ m/s^2[/tex]. The final speed at t=35 seconds is:

[tex]v_f=0+8*35[/tex]

[tex]v_f=280\ m/s[/tex]

Its speed will be 280 m/s


3. Reducing the distance between two objects to 1/2 its original value will
a. Make the gravitational force between the objects twice its original value,
B. Make the gravitational force between the objects 1/4 of its original value,
C) Make the gravitational force between the objects 4 times its original value,
D. Make the gravitational force between the objects of its 1/2 original value,

Answers

Answer:

i my though may it is auestion no B i am not correct may its write

Explanation:

B

A plane is traveling at a velocity of 90 m/s. It accelerates at a constant rate of 1.5 m/s​2 until its velocity reaches 500 m/s. What distance did the plane cover while it was accelerating?

Answers

Answer:

The distance the plane covered while it was accelerating is 80,633.3 m

Explanation:

Given;

initial velocity of the plane, u = 90 m/s

acceleration of the plane, a = 1.5 m/s²

final velocity of the plane, v = 500 m/s

The distance covered by the plane is given as;

v² = u² + 2ad

where;

d is the distance covered by the plane;

500² = 90² + 2(1.5)d

500²  - 90² = 3d

241900 = 3d

d = 241900 / 3

d = 80,633.3 m

Therefore, the distance the plane covered while it was accelerating is 80,633.3 m

Give an example of the Law of Conservation of Energy. Explain your example

Answers

Answer: The law of conservation of energy can be seen in these everyday examples of energy transference: Water can produce electricity. Water falls from the sky, converting potential energy to kinetic energy. This energy is then used to rotate the turbine of a generator to produce electricity.

Explanation: Thats what we learned

Find the mass of an object the accelerates at 3.4 m/s2 when a net force of 25.1 N force is applied to it. Answer in units of kg and include all necessary work.

Help Please

Answers

The mass of the body is 7.38 kg

Given,

Acceleration of the object = 3.4 m/s²Net force = 25.1 N

We need to find,

Mass of the body = ?

Using Newton's first law of motion .

Force = Mass × Acceleration

➵ 25.1 = Mass × 3.4

➵ 25.1 ÷ 3.4 = Mass

Mass = 7.38 kg

What is Newton's third law of motion? Give an example.

Answers

Answer: Examples of Newton's third law of motion are ubiquitous in everyday life. For example, when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air. Engineers apply Newton's third law when designing rockets and other projectile devices.

Explanation: hope this helps :)

What is the mathematical relationship between wavelength and velocity? Inverse, horizontal, linear or quadratic? I NEED MAJOR HELP PLZ HELP ME THANK U

Answers

Answer: Wavelength is the measure of the length of a complete wave cycle. The velocity of a wave is the distance traveled by a point on the wave. In general, for any wave the relation between Velocity and Wavelength is proportionate. It is expressed through the wave velocity formula.

Explanation: For any given wave, the product of wavelength and frequency gives the velocity. It is mathematically given by wave velocity formula written as-

V=f×λ

Where,

V is the velocity of the wave measure using m/s.

f is the frequency of the wave measured using Hz.

λ is the wavelength of the wave measured using m. Velocity and Wavelength Relation

Amplitude, Frequency, wavelength, and velocity are the characteristic of a wave. For a constant frequency, the wavelength is directly proportional to velocity.

Given by:

V∝λ

Example:

For a constant frequency, If the wavelength is doubled. The velocity of the wave will also double.

For a constant frequency, If the wavelength is made four times. The velocity of the wave will also be increased by four times.

Hope you understood the relation between wavelength and velocity of a wave. I truely hope this helps you out tho! Goodluck!

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This is a two part question: What is the force of friction acting on a 100 kg steel slab at rest on a steel floor?
None of the above
725.94N
559.2N
0N
A 5.5kg bowling ball is going down the lane at constant velocity of 30 m/s.What is the net force acting on the bowling ball?
165N
55N
30N
ON

Answers

1) 0N... friction opposes the motion of an object, since the block is at rest there is no motion thus no friction

2) F=ma
= (5.5kg)(30m/s)
=165 N

Dos cargas q1= 5 Milicoulombios y q2 = 6 Milicoulombios, se encuentran separadas 4 cm y sufren una fuerza entre ellas. ¿Cuál será el valor de la fuerza entre ambas cargas? ¿Existirá una fuerza de atracción o de repulsión? ¿Por qué?

Answers

Answer:

El valor de la fuerza entre ambas cargas es 168,750,000 N.

Ambas cargas son positivas, por lo que entre ellas existirá una fuerza de repulsión.

Explanation:

Los responsables de todos los fenómenos eléctricos son los electrones, porque pueden escapar de la órbita del átomo y son mucho más ligeros que las otras partículas.

La carga eléctrica es una propiedad física propia de algunas partículas subatómicas que se manifiesta mediante fuerzas de atracción y repulsión entre ellas. La materia cargada eléctricamente es influida por los campos electromagnéticos, siendo a su vez, generadora de ellos.

Entre dos o más cargas aparece una fuerza denominada fuerza eléctrica cuyo módulo depende del valor de las cargas y de la distancia que las separa, mientras que su signo depende del signo de cada carga.

La fuerza entre dos cargas se calcula como:

[tex]F=k*\frac{Q*q}{d^{2} }[/tex]

donde:

F es la fuerza eléctrica de atracción o repulsión y se mide en Newtons (N). Q y q son lo valores de las dos cargas puntuales y se miden en Culombios (C). d es el valor de la distancia que las separa y se mide en metros (m)k es una constante de proporcionalidad llamada constante de la ley de Coulomb. Depende del medio en el que se encuentren las cargas. Para el vacío k es aproximadamente 9·10⁹ N·m²/C² utilizando unidades en el S.I.

Siendo 1 millicoulomb [mC] = 0,001 coulomb [C] y 100 cm= 1 m, en este caso sabes:

Q= 5 mC= 0.005 Cq= 6 mC= 0.006 Cd= 4 cm= 0.04 m

Reemplazando:

[tex]F=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{0.005C*0.006C}{(0.04m)^{2} }[/tex]

F= 168,750,000 N

El valor de la fuerza entre ambas cargas es 168,750,000 N.

Las cargas del mismo signo se repelen, mientras que las cargas con diferente signo se atraen. En este caso ambas cargas son positivas, por lo que entre ellas existirá una fuerza de repulsión.

help please 10 pts and quick!

Answers

Answer:

B

Explanation:

Answer:

B

Explanation:

if a Man suit a spare at a place where
the sea the fish inside the water is it possible that it will heat the fish give reason​

Answers

Answer:

Yes

Explanation:

Name all of the steps on the Physical Activity Pyramid?

Answers

Answer:

The steps are:-

Moderate physical activityVigorous aerobicsVigorous sport and recreationMuscle fitness exerciseFlexibility exerciseAvoiding inactivityBalancing energy

What is the difference between a vigorous sport and vigorous recreation ?

Answers

Answer:

Explanation:El ejercicio vigoroso previene en mayor medida el síndrome metabólico (un conjunto de enfermedades que aumentan el riesgo cardiovascular         )

mientras que una reacción vigorosa se   produce entre el aluminio y el gas cloro. Como consecuencia de la gran cantidad de energía liberada se producen luz y calor

Which of the four spheres is this pictures/scene?

A) hydrosphere
B) biosphere
C) geosphere
D) atmosphere

Answers

Answer:

I Believe the answer is

[tex]D. \: \: atmosphere[/tex]

Explanation:

I hope how this helps!

A 10 kg wagon is accelerated by a constant force of 60 N from an initial velocity of 5.0 m/s to a final velocity of 11 m/s. What is the impulse received by the wagon? a)15 N s b)60 N s c)17 N s d)70 N s

Answers

The answer is 274774

A person wants to find the width of the lake by shouting and listening for the echo from the far side. If his echo returns after 2 seconds how wide is the lake? (Velocity of sound is 340 m/sec)

Answers

Answer:

The width of the lake is 340 m

Explanation:

Constant Velocity Motion

It occurs when an object travels the same distance every equal interval. For example, if it travels 5 m in one second, then 10 m in two seconds, etc., it has a constant velocity.

The speed of the sound is assumed as v=340 m/s and the person measures the time that a sound goes and comes from the edge of a lake as t=2 seconds. The distance it travels is:

d = v.t

d = 340 m/s * 2 s

d = 680 m

But that distance is twice the width of the lake, the real measured width is 680 m / 2 = 340 m

The width of the lake is 340 m

please help answer brainlest

each rock you need to tell where OK can you find them
like: your backyard or the road

Flakes of brick
Cracks in rocks
Lichen growing on rocks
Roots or plant growth making cracks in concrete
Worn away statues
Exposed rocks
Rust on rocks
Example You Found:

Answers

Answer:

Flakes of brick: Athens, Ohio

Cracks in rocks: Sandston, Mudcracks

Lichen growing on rocks: Antarctica living below the surface

Roots or plant growth making cracks in concrete: In the driveway, sidewalk, or road.

What is the kinetic energy of a 0.150 kg
object moving at a velocity of 100m/s?

Answers

Answer:

750J

Explanation:

Given parameters:

Mass of the object   = 0.15kg

Velocity of the object  = 100m/s

Unknown:

Kinetic energy of the body  = ?

Solution:

The kinetic energy is the energy due to the motion of a body. It is mathematically expressed as;

        K.E  = [tex]\frac{1}{2}[/tex] m v²  

m is the mass of the body

v is the velocity

 Now insert the parameters and solve;

     K.E  = [tex]\frac{1}{2}[/tex]  x 0.15 x 100²   = 750J

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