A student made two patterns to show multiplication of a decimal by powers of ten. the equations shown for both patterns are incorrect. pattern A
3.675. 10 =3.7650
3.675. 100= 3.67500
3.675.1,000= 3.675000
pattern B
3.675. 10=3.0675
3.675.0.01= 3.00675
3.675. 0.001= 3.000675
explain why the equations in each of the patterns are false. Include in your explanation the values that should appear on the right side of each equation in both patterns to make the equations true.

Answers

Answer 1

If a student made two patterns to show multiplication of a decimal by powers of ten. All the value are incorrect. The correct value are: 36.75, 367.5, 3,675, 36.75, 0.03675, 0.003675.

How to find the correct value?

Pattern A

3.675×10 =3.7650 Incorrect

3.675×10 = 36.75 Correct

3.675× 100= 3.67500  Incorrect

3.675×100= 367.5 Correct

3.675×1,000= 3.675000 Incorrect

3.675×1,000 = 3,675 Correct

Pattern B

3.675×10=3.0675 Incorrect

3.675× 10= 36.75 Correct

3.675×0.01= 3.00675 Incorrect

3.675×0.01= 0.03675 Correct

3.675×0.001= 3.000675 Incorrect

3.675×0.001= 0.003675 Correct

The correct value are: 36.75, 367.5, 3,675, 36.75, 0.03675, 0.003675.

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Related Questions

The rate of change increased by about _____ bass per a year. Round to the nearest tenth

Answers

From the exponential function, the average rate of change from year 1 to year 4 is 62.43, the average rate of change from year 5 to year 8 is 67.57 and the rate of change per year is 65

What is Exponential Function

An exponential function is a type of function that involves a variable in an exponent. It is of the form f(x) = a⋅b^x where a and b are constants and b > 0, b ≠ 1. The input to the function, x, is the exponent that the base, b, is raised to. The output, f(x), is the result of raising the base to the exponent.

In this problem, we have to calculate the rate of increase per year.

Data;

rate = 2%

P = 3000

The exponential growth can be calculated by;

A = P(1 + r)ⁿ

In year 1

A = 3000(1 + 0.02)¹

A = 3060

In year 4

A = 3000(1 + 0.02)⁴

A = 3247.3

a)

The average rate of change from year 1 to year 4 will be

A = [3000(1 + 0.02)⁴ - 3000(1 + 0.02)¹] / 4 - 1

A = 62.43

The average rate of change from year 1 to year 4 is 62.43

b)

The average rate of change from year 5 to year 8 is calculated as

A = [3000(1 + 0.02)⁸ - 3000(1 + 0.02)⁵] / 8 - 5

A = 67.57

C)

The rate of change increase can be calculated as;

A = [3000(1 + 0.02)⁸ - 3000(1 + 0.02)¹] / 8 - 1

A =65

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Please help me with this question

Answers

Answer:

Step-by-step explanation:

i have no idea

PLEASE HELP ME 2 QUESTIONS ARE LISTED DOWN BELOW

Answers

A) The linear equation is:

y = (3/4)*x + 3

B) The sets with only positive elements are:

{x| x ∈ N}{y| 0 < y < 1}{y| 3 ≤ y ≤22}

How to write the linear equation?

A general linear equation can be written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

Here, we do know that the y-intercept of the linear equation is (0, 3), then we know that b = 3.

Then the line is something like:

y = a*x + 3

We also know that the line passes through (-4, 0), then we can replace these values in the equation above to get:

0 = a*-4 + 3

4a = 3

a = 3/4

Then the linear equation is:

y = (3/4)*x + 3

In which sets all the numbers are positive?

The sets where all the numbers are positive are:

{x| x ∈ N}

Where N is the set of the natural numbers, these are all the integers equal to or larger than 1, so all are positives.

{y| 0 < y < 1}

There we can see that y must be larger than zero, so all the elements are positive.

{y| 3 ≤ y ≤22}

Here the elements are between 3 and 22, so all of these are positve.

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Question 3
Use the quadratic formula to complete the table. To verify your solutions, graph the equations.
BIU X² X₂ 10pt

Help !!!

Answers

The linear equation in this case is . The [tex]$3 x^2+4 x+4=0$[/tex] answer is [tex]x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex] and [tex]$3 y^2+2 x+4=0: \quad$[/tex]: quadratic [tex](h, k)=(-2,0), p=-\frac {1} {6}[/tex] , is the solution.

What do you meant by quadratic equation ?

[tex]$3 x^2+4 x+4=0 \quad: \quad x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}$[/tex]

[tex]$3 x^2+4 x+4=0$[/tex]

Apply the quadratic formula to the problem. [tex]$x_{1,2}=\frac{-4 \pm \sqrt{4^2-4 \cdot 3 \cdot 4}}{2 \cdot 3}$[/tex]

Simplify [tex]$\sqrt{4^2-4 \cdot 3 \cdot 4}: \quad 4 \sqrt{2} i$\\[/tex]

[tex]$x_{1,2}=\frac{-4 \pm 4 \sqrt{2} i}{2 \cdot 3}$[/tex]

Distinguish the answers

[tex]x_1=\frac{-4+4 \sqrt{2} i}{2 \cdot 3}, x_2=\frac{-4-4 \sqrt{2} i}{2 \cdot 3}\\x=\frac{-4+4 \sqrt{2} i}{2 \cdot 3}: \quad-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}\\x=\frac{-4-4 \sqrt{2} i}{2 \cdot 3}: \quad-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex]

The following are the quadratic equation's solutions:

[tex]x=-\frac{2}{3}+i \frac{2 \sqrt{2}}{3}, x=-\frac{2}{3}-i \frac{2 \sqrt{2}}{3}[/tex]

2) [tex]$3 y^2+2 x+4=0: \quad$[/tex] A parabola with a focal length of and a vertex at (h,k)=(-2, 0) [tex]$|p|=\frac{1}{6}$[/tex]

[tex]$3 y^2+2 x+4=0$[/tex]

[tex]$4 p(x-h)=(y-k)^2$[/tex] is the common formula for a right-to-left parabola with a vertex at (h, k) and a focal length of |p|.

Rewrite [tex]$3 y^2+2 x+4=0$[/tex]  using the proper form: [tex]$4\left(-\frac{1}{6}\right)(x-(-2))=(y-0)^2$[/tex]

The following are characteristics of parabolas:

[tex](h, k)=(-2,0), p=-\frac {1} {6}[/tex]

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hello i need help with question 5 please

Answers

5a) The total cost of buying the car, including the harmonized sales tax (HST) of 13%, is $36,160.

5b) Under the lease, the customer saves $14,760.

5c) The lessee after returning the car has the following lease options:

Lease buyoutLease extensionNew lease contractBuying out the vehicle and then reselling it.

6a) The after-tax cost of the car that Jordan wants to buy is $32,199.35.

6b) The part of the Honda Civic that needs to be financed after the down payment is $26,199.35.

6c) The monthly payment will be $567.26.

6d) After four years, the total amount Jordan had paid for the vehicle is $33,228.48.

Car Financing Options:

A lease is a financing option for the use of capital assets by which the lessee utilizes an asset for a stated period while making periodic payments to the lessor.

A car purchase can also be financed through loans, like home mortgages.

Value of the car = $32,000

Harmonized Sales Tax (HST) = 13%

Cost of the car with HST = $36,160 ($32,000 x 1.13)

Lease Arrangement:

Down payment = $1,000

Financing part = $35,160 ($36,160 - $1,000)

Installment payments = 48

Periodic payments = $425

Total lease cost = $21,400 ($1,000 + 48 x $425)

Savings from leasing = $14,760 ($36,160 - $21,400)

Jordan's Car:

The value of the Honda Civic = $28,495

Harmonized Sales Tax (HST) = 13%

After-tax cost = $32,199.35 ($28,495 x 1.13)

Annual interest rate = 1.9% compounded monthly

Down payment = $6,000

Financing part = $26,199.35 ($32,199.35 -$6,000)

Financing period = 4 years

N (# of periods) = 48 months (4 years x 12)

I/Y (Interest per year) = 1.9%

PV (Present Value) = $26,199.35

FV (Future Value) = $0

P/Y (# of periods per year) = 12

C/Y (# of times interest compound per year) = 12

Results:

Monthly Payments (PMT) = $567.26

Sum of all periodic payments = $27,228.48

Total Interest $1,029.13

Total amount paid by Jordan after 4 years = $33,228.48 ($27,228.48 + $6,000)

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A certain type of fertilizer contains 8% nitrogen. If 2 kilograms of nitrogen are needed to fertilize a lawn, how many kilograms of fertilizer are needed?

Answers

25 kilograms of fertilizer would be needed to fertilize the lawn.

what is the percentage?

In essence, percentages are fractions with 100 as the denominator. We place the percent symbol (%) next to the number to indicate that the number is a percentage.

given, A certain type of fertilizer contains 8 percent of nitrogen. If 2 kilograms of nitrogen are needed to fertilize a lawn.

Since fertilizer contain 8% nitrogen in it

thus for 80 grams of nitrogen = 1 kg of fertilizer

for 1 gram of nitrogen = 1/80 kg fertilizer

for 2000 gram of nitrogen = (1/80)* 2000 kg fertilizer

for 2 kilograms of nitrogen = 25 kg fertilizer

therefore, To fertilize the yard, 25 kg of fertilizer would be required.

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Find the midpoint of the line segment with endpoints:
(9, -5/2) to (-5, -3/2)
Answer must be as a point, using integers or reduced fractions for coordinates.

Answers

Answer:

Step-by-step explanation:

Midpoint formula is x3 = (x1+x2)/2, y3=(y1+y2)/2

so x3=(9-5)/2=2, y3=(-5/2-3/2)/2=-2.

the coordinates is (2, -2).

<
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a translation.
←++
-7-6-5-4-3/2
A translation by
up/down
7-
6+
6543
У
5-
3-
24
2345
-3-
Determine the translation.
Use non-negative numbers.
-5+
-6-
D'
A
34 9/7
B
2
units to the right/left ✓
and
units

Answers

Answer:

1 unit to the left, 3 units down

Step-by-step explanation:

Take any point: I will take D. In order to get to D', you need to travel 1 unit along the x-axis towards the left, then 3 until along the y-axis downwards. The same applies for any other point.

Select the correct answer. What is this equation rewritten in exponential form? log7 343 = 3 A. 37 = 343 B. 73 = 343 C. 343x = 7 D. 343x = 3

Answers

The solution to the equation log₇343 = 3 is 7³ = 343

What is an equation?

An equation is used to show the relationship between numbers and variables.

The logarithm can be defined as the exponent that raises a base to get a particular number. The law of logarithm states:

logₓm = n is the same as xⁿ = m

Given the equation:

log₇343 = 3

Applying the law of logarithm gives:

7³ = 343

The solution to the equation is 7³ = 343

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If the HCF is 5 and the product of the two numbers is 70, find the value of LCM.

Answers

If the HCF is 5 and the product of the two numbers is 70, then the value of LCM is 14.

Do two numbers make a product when they are the LCM of two numbers?

The smallest number that can be divided by both numbers is known as the least common multiple, or LCM, of two numbers. The product of the two numbers is the LCM if their greatest common divisor is 1, in which case their product is 1.

Using the fundamental theorem of mathematics, how do you find the HCF and LCM?

First, multiply both numbers by their prime factors to express them. Then, multiply the common factor with the highest power by the remaining factors to obtain the LCM. Take the common factors with the lowest power and multiply them to determine HCF.

To find the LCM of two numbers, you can use the formula: LCM = (a * b) / HCF.

In this case, we know that the HCF is 5, and the product of the two numbers is 70. Therefore, we can substitute these values into the formula:

LCM = (70) / 5 = 14.

So the LCM of the two numbers is 14.

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1) A publisher wants to determine the thickness of a book they will print soon. The book has a front cover and a back cover, each of which have a thickness of

1/4 in. The publisher can choose on what type of paper to print the book.

Bond paper has a thickness of 1/4 in. per 100 pages.

Write an equation that gives the width `y` of the book, if it has `x`-hundred pages printed on bond paper.


Ledger paper has a thickness of 2/5 in. per `100` pages. Write an equation that gives the width `y` of the book, if it has `x`-hundred pages printed on ledger paper.

2) If the publisher selects front and back covers with a thickness of 1/3 in. each, how would this change the equations you wrote on the previous slides?

Answers

1a) An equation that gives the width `y` of the book, if it has `x`-hundred pages printed on bond paper is; y = ¹/₂ + ¹/₄x

1b) Ledger paper has a thickness of 2/5 in. per `100` pages, the equation is; y = ¹/₂ + ²/₅x

2) The equation will be; y = ²/₃ +¹/₄x

How to solve Algebraic Word Problems?

1) We are told that the front cover and the back cover have a thickness of 1/4 inches and they also have a thickness of 1/4 inch. Thus;

The addition of both gives to the book thickness of;

1/4 + 1/4 = 1/2 inch, despite how many pages the book  has.

We are told that for every hundred pages, a thickness of 1/4 inch is added to the book, then the equation is:

y = ¹/₂ + ¹/₄x

where;

y is the width of the book in inches.

x is every hundred pages printed on bond paper.

1b) If ledger paper has a thickness of 2/5 in. per 100 pages, then the equation is now;

y = ¹/₂ + ²/₅x

2) If both front and back covers now, have a thickness of 1/3 inches instead of 1/4 inches each, then the equation will be;

y = 2(1/3) +¹/₄x

y = ²/₃ +¹/₄x

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If m∠ABJ = 28, ∠ABC ≅ ∠DBJ, find m∠JBC.

Answers

Answer:

Step-by-step explanation:

If m∠ABJ = 28 and ∠ABC ≅ ∠DBJ, then we can set up the following equation:

m∠ABC = m∠DBJ

Since angles ∠ABC and ∠DBJ are congruent, they have the same measure, so the equation above is true.

Since we are trying to find m∠JBC, we can use the fact that the measure of an angle is equal to the sum of the measures of the other two angles in the triangle to set up another equation:

m∠JBC = m∠ABC + m∠ABJ

Substituting the value for m∠ABC from the first equation into the second equation, we get:

m∠JBC = m∠DBJ + m∠ABJ

Substituting the given value of m∠ABJ into this equation, we get:

m∠JBC = m∠DBJ + 28

Since m∠ABJ = m∠DBJ, we can substitute m∠ABJ in for m∠DBJ:

m∠JBC = m∠ABJ + 28

Substituting the given value of m∠ABJ into this equation, we get:

m∠JBC = 28 + 28

Solving this equation, we find that m∠JBC = 56.

Therefore, the measure of angle ∠JBC is 56 degrees.

value of y please help me

Answers

Answer is y= 22

Step by step

We know the triangle dum is equal to 180

One angle is 40, so 180 - 40 = 140

The two angles labeled x are congruent, so 140 / 2 = 70.

X = 70

Now the supplement angle of x and 5y = 180 degrees.

70 + 5y = 180

Subtract 70 from both sides to isolate y

70 - 70 + 5y = 180 - 70
Simplify

5y = 110

Divide both sides by 5 to solve for y

5/5 y = 110/5

y = 22

Solve for x in the triangle. Round your answer to the nearest tenth.

Answers

In the right triangle in the figure the value of x is solved to be 4.5

How to find the value of x

Using SOH CAH TOA for the right triangle

Sin = opposite / hypotenuse - SOH

Cos = adjacent / hypotenuse - CAH

Tan = opposite / adjacent - TOA

The figures show that

hypotenuse = 6

adjacent = x

given angle = 41 degrees

The value of x will be calculated using cos, CAH let the angle be y

cos y = adjacent / hypotenuse

cos 41 = x / 6

x = 6 * cos 41

x = 4.528

x = 4.5

Hence the value of x is 4.5

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Mary is going for a walk. She takes 3 hours to walk 9.6 miles. What is her speed?

Answers

Answer:

3.2 mph

Step-by-step explanation:

If it takes her 3 hours to walk 9.6 miles, we need to divide 9.6 by 3.

To do so, we can remove the decimal point in 9.6, to give us 96.

Then, we can divide 96 by 3 to get 32.

Add the decimal back to 32.

Doing so would give us 3.2, and our answer.

We can check this answer by multiplying 3.2 by 3, which gives us 9.6, telling us our answer is correct.

Find the missing term 2,..,20,29

Answers

Answer:

11

Step-by-step explanation:

29-20= 91

2+9=11

11+9=

It would be 11, and the pattern is +9. 2+9 is 11, 11+9 is 20, 20+9 is 29

- Complete the function table for f(x) = 3x + 2.
groce
x
-2
-1
0
1
opies of graph pap

Answers

The value of the function f(x) at x = - 2, - 1, 0, 1 are - 4, - 1, 2, 5.

What is a function?

A function can be defined as the outputs for a given set of inputs.

The inputs of a function are known as the independent variable and the outputs of a function are known as the dependent variable.

Given, A function f(x) = 3x + 2.

Now,

At x = - 2, f(x) = 3(-2) + 2 ⇒ f(x) = - 4.

At x = - 1, f(x) = 3(-1) + 2 ⇒ f(x) = - 1.

At x = 0, f(x) = 3(0) + 2 ⇒ f(x) = 2.

At x = 1, f(x) = 3(1) + 2 ⇒ f(x) = 5.

This can also be written in the form of ordered pairs

(- 2, - 4), (- 1, - 1), (0, 2), (1, 5).

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Write an addition equation with three equal fractional parts.
15
4
=
+
+

Answers

Step-by-step explanation:

please refer to the sketch

Will mark brainliest (I also need to find the x and y intercepts)

Answers

Answer: downward, (4, -1), x = 4, no x-intercept, y-intercept: -6

Step-by-step explanation:
1. The parabla opens downwards because the y-values only decrease
2. The Vertex is the point with an x-value that creates a line of symmetry and can be noticed as it does not share the same x or y-value with any other point. If you look for it, you will notice that it's (4, -1).
3. As I explained above the x-value of the vertex creates a line of symmetry, therefore you can create the equation for the axis of symmetry by setting it equal to x.
4. X-intercepts are x-values that intersect with the x-axis so look for any points on the x-axis and if there are any, write them down. Y-intercepts are y-values that intersect with the y-axis, so look for any points on the y-axis and if there are any, write them down. If you checked, you should've realized that there are no x-intercepts and that the y-intercept is -6 and it's location is (0, -6).

An item on sale costs 80% of the original price. The original price was 33%

Answers

The sale price of the item is given by the equation A = $ 26.40

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the sale price of the item be represented as A

Now , the equation will be

The original price of the item = $ 33

An item on sale costs 80% of the original price

So , the sale price of the item A = 80 % x original price of the item

Substituting the values in the equation , we get

The sale price of the item A = ( 80 / 100 ) x 33

The sale price of the item A = 0.80 x 33

The sale price of the item A = $ 26.40

Therefore , the value of A is $ 26.40

Hence , the sale price is $ 26.40

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Given that X≈2 is an approximate solution to x^2+2x-2=5, use the graph to find another approximate solution round your answer to the nearest integer. X≈ ___

Answers

The nearest integer that is a solution, gotten through graphing of the quadratic function x² + 2x - 2 = 5, is x = -4

How to find the graphical solution of the function

Quadratic equations when plotted on a graph follows a parabolic path.

To plot the functions there will be table of values that is used in making the graph. The table of values is solved as follows

x² + 2x - 2 = 5 rearranging the equation will result to x² + 2x - 7 = 0

For x = -20,  y = (-20)² + 2 * -20 - 7 = 353

For x = 0,  y = (0)² + 2 * 0 - 7 = -7

For x = 20,  y = (20)² + 2 * 20 - 7 = 433

x      y

-20  353

0      -7

20    433

The graph is plotted and attached. From the graph the solution is

x = -3.828, to the nearest integer = -4

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The weight of the square is 10 grams. How much heavier is the circle than the square?

Answers

By adding the weight of the triangle, the weight of the circle heavier than that of the square.

How to determine how much heavier the circle is than the square

The linear equation that results from examining the weights will contain the following parameters.

Let t stand for the triangle.

Let c stand for the circle.

Let's use the shape square.

left side of the equation = 6s + 3t

right side of the equation = 3s + 3c

equating both sides

6s + 3t = 3s + 3c

6s - 3s + 3t = 3s + 3c

3s + 3t = 3c

3(s + t) = 3c

dividing all through by 3

s + t = c

10 + t = c

Because of the resulting equation, we can conclude that the the circle is weightier than the square by the weight of the triangle

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The diagonals of a quadrilateral ABCD intersects each other at the point O such that AO/BO=CO/DO.Prove that ABCD is a trapezium.​

Answers

Answer:

Step-by-step explanation:

To prove that a quadrilateral ABCD is a trapezium when the diagonals intersect at a point O such that AO/BO=CO/DO, we can use the fact that opposite sides of a trapezium are parallel.

First, let's draw a diagram to represent the given information:

[asy]

pair A, B, C, D, O;

A = (0,0);

B = (2,0);

C = (3,2);

D = (1,2);

O = intersection point(A-C, B--D);

draw(A--B--C--D--cycle);

draw(A-C);

draw(B--D);

label("A", A, W);

label("B", B, E);

label("C", C, E);

label("D", D, W);

label("O", O, N);

label("$\theta_1$", (B+O)/2, NE);

label("$\theta_2$", (O+D)/2, NE);

label("$\theta_3$", (O+C)/2, NW);

label("$\theta_4$", (A+O)/2, NW);

[/asy]

Since the diagonals intersect at point O, the angles formed by the diagonals at O are supplementary (that is, they add up to 180 degrees). In other words, we have:

θ1 + θ2 = 180 degrees

θ3 + θ4 = 180 degrees

Since AO/BO=CO/DO, the triangles AOB and COD are similar. This means that the ratios of their sides are equal. We can write this as:

AO/BO = CO/DO

We can also write this as:

AO/DO = CO/BO

Then, since the angles formed by the diagonals at O are supplementary, we have:

θ1 + θ2 = 180 degrees

θ1 + θ4 = 180 degrees

Subtracting these two equations gives us:

θ2 - θ4 = 0

Since the angles are equal, they are also opposite angles of the quadrilateral ABCD. Therefore, the opposite sides of AB and CD are parallel, which means that ABCD is a trapezium.

All of the quadrilaterals in the shape below are squares. Find the area of the shaded
region.

Answers

Answer: I don't remember how to solve, but, I figured out the lengths of each side in the shaded region:

11, 11, 7, 7, 4, 4

Step-by-step explanation:

Hope this helps!! :D

Area of the shaded region is 105 units²

Find the circumference of a circle with a diameter of 50 centimeters

Answers

Answer:

157.08 is the circumference. Hope it helps you

Step-by-step explanation:

find the mean in the picture

Answers

Hey I think it’s 20 just did it in my head

A train traveled 250 mi in 2 hours. If it traveled at the same rate of speed how long would it take the train to travel 600 mi

Answers

4.8

Divide 250 by 2 which is 125 then do 600 divided by 125. Then your answer should be 4.8.

On Saturday morning, Wendy watched one and a half hours of her favorite shows on television. During the shows there were 27 commercials. What is the unit rate of commercials per hour? 9 hours per commercial 12 commercials per hour
14 commercials per hour 18 commercials per hour

Answers

The unit rate is 18 commercials per hour.

What is Division?

A division is a process of splitting a specific amount into equal parts.

On Saturday morning, Wendy watched one and a half hours of her favorite shows on television.

During the shows there were 27 commercials.

We need to find the unit rate of commercials per hour.

To find this we have to divide 27 by number of hours

27/[tex]1\frac{1}{2}[/tex]

Convert [tex]1\frac{1}{2}[/tex] to improper fraction

27/(3/2)

When whole number is divided by fraction, the denominator is multiplied with whole number

27×2/3

54/3

18

Hence, the unit rate is 18 commercials per hour.

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Answer:18 commercials per hour

Step-by-step explanation:

Pls help! Step by step

Answers

Answer:

x = 55

Step-by-step explanation:

Since the sides of the shape are parallel, AngleC and AngleD will add up to 180° (see "parallel lines cut by a transversal" or maybe you have learned a big pile of parallelogram theorems)

Use this relationship to set up an equation.

2x + 20 + 50 = 180

combine like terms

2x + 70 = 180

subtract 70

2x = 110

divide by 2

x = 110/2

x = 55

x is 55

Answer:

The value of x is 55°

Step-by-step explanation:

GivienTwo adjacent angles of a parallelogram are (2x + 20)° and 50° respectively

Since we know that opposite angles of a parallelogram are equal

m∠C = m∠B = (2x + 20)°m∠D = m∠A = 50°

The sum of any two adjacent angles is supplementary. This means, ∠A + ∠B = 180°, ∠B + ∠C = 180°, ∠C + ∠D = 180°, and ∠D + ∠A = 180.

So,

∠C + ∠D = 180°

(2x + 20)° + 50° = 180°

2x + 70° = 180°

2x + 70° - 70° = 180° - 70°

2x = 110°

2x/2 = 110°

x = 55°

Thus, The value of x is 55°

What is the probability of picking a month at random that starts with the letter “J”

Answers

Answer:

A 1 in 4 chance or a probability of 0.25

Step-by-step explanation:

There is only 3 months that start with J and 12 months in a year so simplify 3/12 you get 1/4 or 0.25

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