Answer:
a = 1.428 [m/s²]
v₀ = 5 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]x=x_{o}+v_{o}*t+\frac{1}{2}*a*t^{2}[/tex]
where:
x = final point [m]
x₀ = initial point [m]
v₀ = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
But we need to use this additional equation.
[tex]v_{f}=v_{o}+a*t[/tex]
where:
vf = final velocity = 15 [m/s]
Now we can use this equation, replacing it, in the first one. We must bear in mind that the difference among x - x₀ is equal to 70 [m]
[tex]x-x_{o}=v_{o}*t+\frac{1}{2}*a*t^{2} \\x-x_{o}=(v_{f}-a*t)*t+\frac{1}{2} *a*t^{2}\\70=(15-a*t)*t+\frac{1}{2}*a*t^{2}\\70=15*t-a*t^{2} +\frac{1}{2}*a*t^{2} \\70=15*t-\frac{1}{2}*a*t^{2}\\70=15*(7)-\frac{1}{2} *a*(7)^{2}\\105-70=0.5*a*49\\35=24.5*a\\a=1.428[m/s^{2} ][/tex]
Now replacing this value in the second equation, we can find the initial velocity.
[tex]15=v_{o}+1.428*7\\v_{o}=5[m/s][/tex]
A density of solid 13g/cm³ at a temperature of 25°c was now heated to a temperature of 150°c find the new density of the solid ? Given linear expansivity to be 2 × 10⁻⁵ ?
Answer:
13.4225 g/cm³
Explanation:
Given that:
Linear expansivity α = 2 * 10^-5
Change in temperature dt = t2 - t1 = (150 - 25)°c = 125°c
Initial density (d1) = 13
New density d2 =?
Using the relation :
α = (d2 - d1) / d1 * dt
d2 - d1 = d1 * dt * α
d2 = d1 + d1*dt*α
d2 = d1(1 + d1*dt*α)
d2 = 13( 1 + (13*125*2*10^-5))
d2 = 13(1 + 0.0325)
d2 = 13(1.0325)
d2 = 13.4225
d2 = 13.4225 g/cm³
A bucket filled with water has a mass of 70kg and is hanging from a rope that is wound around a 0.054 m radius stationary cylinder. If the cylinder does not rotate and the bucket hangs straight down, what is the magnitude of the torque the bucket produces around the center of the cylinder?
Answer:
T = 37.08 [N*m]
Explanation:
We must remember that torque is defined as the product of a force by a distance. This distance is measured from the point of application of force to the center of rotation of the rotating body.
The force is equal to the product of mass by gravitational acceleration.
[tex]F=m*g\\F=70*9.81\\F=686.7[N][/tex]
Now the torque can be calculated:
[tex]T=F*r\\T=686.7*0.054\\T=37.08[N*m][/tex]
23. If a jogger runs 100 meters west and then turns around and runs 30 meters east. What
was the jogger's displacement?
a. 70 meters.
b. 130 meters.
C. 30 meters.
d. 100 meters.
Answer:
A
Explanation:
if he goes to the west, the east is opposite so 100-30
The jogger's displacement was 70 meters. Hence, option (a) is correct answer.
What is displacement?The term "displacement" refers to a shift in an object's position. The symbol for it is an arrow pointing from the initial location to the ending place.
Displacement is a vector quantity as both magnitude and direction are required for defining displacement. SI unit of Displacement is meter.
Given parameter:
The first displacement of the jogger is = 100 meters along west direction.
The second displacement of the jogger is = 30 meters along east direction.
Hence, resultant displacement of the jogger along west direction = 100 meters - 30 meters
= 70 meters.
Hence, the magnitude of jogger's displacement was 70 meters. Hence, option (a) is correct answer.
Learn more about displacement here:
https://brainly.com/question/11934397
#SPJ2
A clown in a circus act swings a 2.7-kg metal ball attached to a 72.0-cm nylon string in a horizontal circle above her head, making one revolution in 0.98 s. What is the tension force, Ft, exerted on the string by the ball?
Answer:
Tension, Ft = 79.91 N
Explanation:
The tension in the string is the resultant force that exists in the string due to the centripetal effect of the swinging ball.
From conservation laws, the tension in the string will be equals to the centripetal force acting on the string.
The tension in a string can be obtained using the formula:
[tex]T=mv^2/R[/tex]
where v = linear velocity of the metal ball which equals to the angular velocity of the ball X the radius of the ball.
The radius of the ball is given as 72 cm = 0.72m and the angular velocity = 1.02 rad/second.
Therefore, linear velocity, [tex]v = 2\pi \times 1.02\times 0.72 =4.616m/s[/tex]
The tension in the string will now be equals to [tex]2.7 \times 4.616^2 /0.72 =79.91N[/tex]
Fig. 2.1 shows the extension-load graph for a spring.
extension
06
load
Fig. 2.1
Dint P is the limit of proportionality.
:) (0) Name the law obeyed by the spring from the origin to P.
[1]
(ii) Describe two features of the graph which show that the law is obeyed.
2.
[2]
-) On Fig. 2.1, sketch a possible continuation of the graph when the spring is loaded
beyond the limit of proportionality.
Answer:
(1) Hooke's law
(2) a) Extension is directly proportional to the applied load
b) The starting point of the graph is the origin (0, 0) or absence of load, no extension
Explanation:
(1) The law obeyed by the spring is known as Hooke's law which states that the extension or compression, x, of a spring proportional to the applied force, F
F = -k × x
Where;
k = The spring constant
(2) Given that the law mathematically is F = -k × x
The two features of the graph that show that the law is obeyed are;
a) The extension increases as the load is increased
b) The extension is zero when the there is no applied load.
A pendulum on earth oscillates with a period of 3.45 seconds. What is the length of the pendulum?
Answer:
The length of the pendulum is 2.954 m.
Explanation:
Given;
period of the pendulum, T = 3.45 s
The period of the pendulum oscillation is given as;
[tex]T = 2\pi \sqrt{\frac{l}{g} } \\\\\frac{T}{2\pi} = \sqrt{\frac{l}{g} }\\\\\frac{T^2}{4\pi ^2} = \frac{l}{g} \\\\l = \frac{gT^2}{4\pi ^2} \\\\[/tex]
where;
L is length of the pendulum
g is acceleration due to gravity on Earth = 9.8 m/s²
[tex]l = \frac{gT^2}{4\pi ^2}\\\\l = \frac{(9.8)(3.45)^2}{4\pi ^2}\\\\l = 2.954 \ m[/tex]
Therefore, the length of the pendulum is 2.954 m.
When the notebook is sitting on the table, what force prevents it from falling into the space below the table? If you don’t know the name of this force, just describe it. What force keeps the notebook from floating in the air?
Answer:
reaction force/normal force (its when the tables kinda pushing from under so it doesnt fall)
and the notebook wont float bc of gravity
Explanation:
theres a quizlet on this if you wanna check it out lol
Answer:
The table surface pushes the notebook from below and prevents it from falling. (This force is called the normal force.) Gravity, or a pull from Earth, keeps the notebook from floating in the air.
Explanation:
How do minerals crystallize or form in veins ?
Answer:
For example, when magma heats water deep underground, elements and compounds in the surrounding rock will dissolve in the water, forming a solution. ... The cooling process causes them to crystalize and form minerals inside the rock. These are called veins
What can the vacuole hold? (check all that apply)
A) water
B) waste
C) nutrients (food)
Answer:
C & A 100000%
Explanation:
i took this test before and i just made sure on safari . Its food (nutrients) and water
A balloon tied up with a wooden piece is moving upward with velocity of 15m/s. At a height of 300m above the ground, the wooden block detached from the balloon. How much time will it take to reach the ground?
Write two different unit in which mass is measured.
Answer:
kilograms and grams
Explanation:
kilograms is the stadard unit for mass according to the SI system.
Grams is another unit for mass.
question is attached!
Answer:
For Bill to dump the water on Tim, Tim should be 7.232 meters from the tree when Bill dumps the water
Explanation:
The given height above the ground at which Bill sits on the tree branch with a bucket of water, h = 4.0 meters
The speed with which Tim is approaching the tree = 8.0 meters per second
The time , t, it will take for the bucket of water to reach the ground is given by the equation of free fall as follows;
h = 1/2·g·t²
Where;
h = Height = 4.0 m
g = The acceleration due to gravity ≈ 9.8 m/s²
t = The time
Making t the subject of the above equation gives;
t = √(h/(1/2·g))
Substituting the known values gives;
t = √(4.0 m/(1/2 × 9.8 m/s²)) ≈ 0.904 s
t ≈ 0.904 seconds
Therefore, for Bill to dump the water on Tim, it should take Tim approximately 0.904 seconds to get to the tree
The distance, d, Tim will be when it will take him 0.904 seconds to get to the tree is given from the kinematic equation of speed, s, as follows;
Distance, d = Time, t × Speed, s
Where;
d = The distance
t = The time = 0.904 s
s = The speed with which Tim is approaching the tree = 8.0 m/s
Substituting the values gives;
d = 0.904 s × 8.0 m/s = 7.232 m
Therefore, the distance Tim should be when Bill throws the water = 7.232 meters
What is the distance between a 2000 kg truck and a 3000 kg truck if the gravitational force between them is 0.00006 N?
A 258
B. 567 m
C 981
D. 15
Answer:
A. 2.58m
Explanation:
Using the formula;
F = GMm/r²
M and m are the masses
G is the gravitational constant
r is the distance between the masses
Substitute
0.00006 = 6.67*10^-11(2000)(3000)/r²
0.00006r² = 6.67*10^-11*6000000
0.00006r² = 40.02*10^-5
0.00006r² = 0.0004
r² = 0.0004/0.00006
r² = 6.66
r = 2.58m
Hence the distance between them is 2.58m
In pulling two identical carry-on bags through the airport, Mr. Myers and his 13 year old grandson, Vincent, do the same amount of work. Who has to use a greater force between gates?
Answer:
Mr Myers and his son use the same force to pull the bags between the gates
Explanation:
The work done by Mr. Myers in pulling the carryon bags = The work done by his 13 year old grandson in pulling the identical bag
Let F₁ represent the force used by Mr Myers, and let F₂ represent the force F₂ used by his grandson
Let d represent the distance through the gate
Therefore, given that Work done, W = Force, F × Distance, we have;
The work done by Mr Myers between the gates, W₁ = F₁ × d
The work done by his grandson between the gates, W₂ = F₂ × d
Where, the work done by both Mr Myers and his grandson are equal, we have;
W₁ = W₂ and therefore, F₁ × d = F₂ × d, which gives;
F₁ = F₂, the force used by both Mr Myers and his son between the gates are equal.
A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling.
Answer:
35 m/s
hope this helpedd
Explanation:
Kinetic Energy 1 upon 2 into mass into velocity square
1 upon 2 into 180 into velocity square=110250
v^2=110250 multiple by 2 and divided by 180
And take square root
A star's brightness as if it were a standard distance from Earth (10 parsecs) is known as what? radiation apparent brightness lighting absolute brightness
Answer:
In contrast, the intrinsic brightness of an astronomical object, does not depend on the distance of the observer or any extinction. The absolute magnitude M, of a star or astronomical object is defined as the apparent magnitude it would have as seen from a distance of 10 parsecs (33 ly).
Explanation:
Can someone look outside and tell me what they see in the sky .The looks like a crystal ball or a mini moon
Answer:
i know it,s the ☁️ it looks like a crystal ball or a mini moon
A student decides to make some extra money during a snow day. As the neighborhood kids are outside sledding, the student offers to pull the students to the top of the hill for one dollar per ride. The sled-puller noticed that it was taking more time to pull older children to the top than with the younger children even though they were pulling with the same force.
Explain why some kids took longer to pull to the top of the hill then other kids despite pulling with the same force. Be sure to address the following for 2 points each:
Identify the formula used to calculate the force of each pull up the hill.
Identify what was different about the older children compared to the younger children that affected the trips up the hill
Explain how this demonstrates Newton's Second Law of Motion
Answer: 5.5 mass
Explanation: The force of gravity pulling the car up the hill = 5.5
Will mark the brainliest
When a car of mass 1000kg is travelling along a level road at a steady speed of 20ms −1
its engine is working at 18kW.
Resultant force = 900N Braking Force = 3100N Gravity = 9.81
By how much does this change if the car is travelling down the same hill at 20ms −1 ?
Answer:
OK draw a diagram - you have the force from (b) acting sown the slope and a component of the weight. Use F=ma to get the deceleration and then use SUVAT. Post your working if this doesn't work.
friction = 900N
braking = 3100N
total = 4000N
w= mxg = 1000*9.81= 9810N
total = 9810 + 4000 = 13810N
force/mass = 13810/1000 = 13.81ms^-2
then using v^2 = u^2 + 2as, i get s as 14 but it is incorrect
Explanation:
Suppose that with a pulley system you need to exert a force of 1,400N to lift a heavy object. But without the pulley system, you need to exert 4,200N to lift the object. What is the MA of the pulley system?
Answer:
Mechanical Advantage is 0.3
Explanation:
Step one:
given data
Load L= 1400N
Effort E= 4200N
Required
The mechanical advantage of the pulley system
Step two:
We know that the expression for the mechanical advantage is
MA= Load/Effort
MA= 1400/4200
MA=0.3
Efficiency is a measure of how much of the work put into a machine is converted into useful output work. Why can efficiency never reach 100%?
A) Acceleration
B) Elasticity
C) Friction
D) Gravity
Answer:
C , Friction
Explanation:
When a hammer strikes a nail, the nail..
exerts balanced forces that helps it from moving.
exerts a force equal to the weight of the hammer..
exerts an unbalanced force that changes its velocity.
exerts an equal and opposite force back on the hammer.
Answer:
Could you possible elaborate on the question more?
Answer:
eH?
Explanation:
Write the newtons formula for the velocity of sound in air .how did Laplace correct this formula ?
Answer:
1: v = √E/ρ where E is the elasticity and ρ is the density. Newton's assumed that sound wave travel in air under isothermal condition
2: He corrected Newton's formula by assuming that, there is no heat exchange takes place as the compression and rarefaction takes place very fast. Thus, the temperature does not remain constant and the propagation of the sound wave in air is an adiabatic process.
I got a new kitten and I dont know how to train them to use a leash. Can anyone help?
A constant horizontal F force began to act on the initially immovable body placed on a horizontal surface. After t time the force ceased to act, and after time 3t from the start of the movement the body stopped. Find the coefficient of friction between the body and the surface if the body mass is m.
Answer:
The coefficient of friction is (F/(19.6·m)
Explanation:
The given parameters are;
The force applied to the immovable body = F
The time duration the force acts = t
The time the body spends in motion = 3·t
The acceleration due to gravity, g = 9.8 m/s²
From Newton's second law of motion, we have;
The impulse of the force = F × t = m × Δv₁
Where;
Δv₁ = v₁ - 0 = v₁
The impulse applied by the force of friction, [tex]F_f[/tex] is [tex]F_f[/tex] × (3·t - t) = [tex]F_f[/tex] × (2·t)
Given that the motion of the object is stopped by the frictional force, we have;
The impulse due to the frictional force = Momentum change = m × Δv₂ = [tex]F_f[/tex] × (2·t)
Where;
Δv₂ = v₂ - 0 = v₂
Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to act, v₁, we have;
m × Δv₂ = [tex]F_f[/tex] × (2·t) = m × Δv₁ = F × t
∴ [tex]F_f[/tex] × (2·t) = F × t
[tex]F_f[/tex] = F × t/(2·t) = F/2
The coefficient of dynamic friction, [tex]\mu _k[/tex] = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)
[tex]\mu _k[/tex] = (F/(19.6·m)
The coefficient of friction, [tex]\mu _k[/tex] = (F/(19.6·m)
what is the relation between distance and speed
by the formula
s=d/t
speed=distance/time
the bigger the distance that has been traveled over a period of time the bigger the speed
Speed = Distance / Time
If time is held constant, then speed is directly proportional to distance. If distance is held constant and time varies, then the speed is inversely proportional to the time taken.
what is meant by momentum?
Answer:
Im afraid i need to to know more on what your asking, are you asking what is momentum?
Explanation:
Because therefore it is the quantity of motion of a moving body, measured as a product of its mass and velocity to the state of motion
or
p = mv
I hope this helps and have a good day, or to best that you can make it <33
Answer:
Momentum can be defined as "mass in motion "OrMomentum is how we measure mass that is in motion ORMomentum,product of mass of particle and its velocityExplanation:
Please mark my answer as a brainliest. Please follow me. ❤❤❤❤❤work done by a gravitational force by lowering the bucket into the well is
Answer:
when we lower a bucket into a well to fetch water, the work done by gravity is positive since force and displacement are in the same direction.
Explanation:
A simple harmonic transverse wave is propagating along a string towards the left direction as shown in the figure. figure shows a plot of displacement as function of position at time t=0.The string tension is 3.6 Newton and it’s linear density is 25GM/M. Calculate
I) the amplitude
Ii) the wavelength
Iii) wave speed
Iv) the period
V) The maximum particle speed in the String
Answer:
Amplitude = 5 cm (Heights)Wavelength (λ) = 40 cm Wave speed (v) = 12 m/s (Approx)Time period (T) = 0.033 s (Approx)Maximum particle speed (V) = 9.43 m/sExplanation:
1) Amplitude
Amplitude = 5 cm (Heights)
2) Wavelength (λ)
Wavelength (λ) = 40 cm
3) Wave speed
Wave speed (v) = √ t / μ
Wave speed (v) = √ 3.6 / [25x10⁻³]
Wave speed (v) = 12 m/s (Approx)
4) Time period (T)
Time period (T) = 1/f = (λ)/v
Time period (T) = 0.40m / 12
Time period (T) = 0.033 s (Approx)
5) Maximum particle speed (V)
Maximum particle speed (V) = Aw
Maximum particle speed (V) = [0.05x2x3.14] / 0.033
Maximum particle speed (V) = 9.43 m/s
the steps of mieosis
Answer:
Since cell division occurs twice during meiosis, one starting cell can produce four gametes (eggs or sperm). In each round of division, cells go through four stages: prophase, metaphase, anaphase, and telophase.
Answer:
here are six stages within each of the divisions, namely prophase, prometaphase, metaphase, anaphase, telophase and cytokinesis
Explanation: