A train traveled 250 mi in 2 hours. If it traveled at the same rate of speed how long would it take the train to travel 600 mi

The following statements are true based on the diagram below

When two or more curves, lines, or edges come together, it is called a vertex (plural: vertices or vertexes) in geometry. As a result of this definition, polygonal and polyhedral corners as well as the intersection of two lines to form an angle are referred to as vertices.

The vertex of an angle is the point at which two rays start or meet, where two line segments join or meet, where two lines intersect (cross), or any other suitable arrangement of rays, segments, and lines that results in two straight "sides" coming together at one location.

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Answer:

yes

Step-by-step explanation:

The line passes through the point (-10,1) and has a slope of 3/20 has the equation as: y - 1 = 3/2 (x + 10)

The general form of a linear equation is y - y₁ = m (x - x₁).

It draws attention to the line's slope and one of the line's points (that is not the y-intercept)

The point slope formula is given by y - y₁ = m (x - x₁), where:

y = output value

y₁= the given y coordinate point

m = slope

x = input value

x₁ = the given x coordinate

substituting the point (-10,1) and slope 3/2

y - y₁ = m (x - x₁)

y - 1 = 3/2 (x + 10)

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Answer:

1-3 y

Step-by-step explanation:

Subtract the numbers 4 AND 3 WHICH WOULD EQUAL REWRITING THE ADDITON SO IT CHANGES THE MINUS SIGN TO A PLUS.

Answer:

30

Step-by-step explanation:

x + 2x + 3x = 180 (the total angle of a triangle)
6x = 180
x = 180 : 6 = 30

Answer:

x = 30°

2x = 60°

3x = 90°

Step-by-step explanation:

Internal angles of a triangle sum 180°

Then:

x + 2x +3x = 180

6x = 180

x = 180/6

x = 30°

2x = 60°

3x = 90°

The total area of the recreational area can be represented by the polynomial expression 26x² + 57x + 35.

The area of a rectangle is defined as the product of the length and width.

The area of a rectangle = L × W

Where W is the width of the rectangle and L is the length of the rectangle

The area of the rectangular pool is given by its length times its width, so the area of the pool is (3x - 3) meters × (2x + 7) meters = (6x² + x - 21) square meters.

The area of the patio is given by the length of the pool plus twice the extension (x) on each side, times the width of the pool plus twice the extension on each side, so the area of the patio is (3x - 3 + 2x) meters × (2x + 7 + 2x) meters = (5x + 4) × (4x + 14) = 20x² + 56x + 56 square meters.

The total area of the recreational area is the sum of the areas of the pool and the patio, so it can be represented by the polynomial expression:

20x² + 56x + 56 + 6x² + x - 21 = 26x² + 57x + 35

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Answer: The origins of matrices can be traced back to the 18th century, with the work of mathematicians such as Gabriel Cramer, Leonhard Euler, and Joseph-Louis Lagrange. These mathematicians developed the idea of using arrays of numbers to represent systems of linear equations, which led to the development of the concept of matrices.

The term "matrix" itself was first used by James Joseph Sylvester in 1850, although it had been in use informally for some time before then. In 1858, the English mathematician Arthur Cayley first published a systematic theory of matrices, which further developed the field.

Matrix theory was primarily used in the early days to solve systems of linear equations, but it soon found applications in areas such as linear algebra, multivariate statistics, and even quantum mechanics.

In summary, the origins of matrices can be traced back to the 18th century as an idea to represent systems of linear equations, which developed over time with contributions of many mathematicians over the centuries, and now it plays an important role in many field of mathematics and science.

Step-by-step explanation:

The image for P(9, 1.5) after Translation is P'( 12, 1).

Each point in a figure is moved the same distance in the same direction using a type of transformation known as translation.

For example, this transformation moves the parallelogram to the right 5 units and up 3 units. It is written ( x , y ) → ( x + 5 , y + 3 ) .

Given:

P(9, 1.5) with Translating Vector (3, -0.5).

So, Applying the Translation we get

P(9 + 3, 1.5 + (-0.5))

= P(12 , 1.5- 0.5)

= P(12, 1)

hence, the image is P'( 12, 1).

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Hello there!

Answer:

[tex](9, +\infty)[/tex]

Step-by-step explanation:

It has no real roots only if

[tex] \sqrt{b {}^{2} - 4ac } [/tex]

has no roots. That means that b² - 4ac is smaller than 0:

[tex]b {}^{2} - 4ac < 0 \\ 12 {}^{2} - 4 \times 4 \times k < 0 \\ 144 - 16k < 0 \\ 144 - 144 - 16k < - 144 \\ - 16k < - 144 \\ k > 9 \\ k \: \: \: in \: \: \: (9, +\infty)[/tex]

we can approach this from the standpoint of the discriminant, if the discriminant is negative then we only get complex roots or namely "imaginary" solutions or values, well, let's check before that happens, when the discriminant is 0.

[tex]\qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ y=\stackrel{\stackrel{a}{\downarrow }}{4}x^2\stackrel{\stackrel{b}{\downarrow }}{+12}x\stackrel{\stackrel{c}{\downarrow }}{+k} ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{one solution}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases}[/tex]

[tex]0=(12)^2 - 4(4)(k)\implies 0=144-16k\implies 16k=144 \\\\\\ k=\cfrac{144}{16}\implies k=9\hspace{5em} \stackrel{if~k > 9\textit{, then we land on negative territory}}{{\Large \begin{array}{llll} k > 9 \end{array}}}[/tex]

Answer:

31 hecause the èattern is adding 3

Step-by-step explanation:

Answer: 5/6

Step-by-step explanation:

The reciprocal of a number is 1 divided by that number. The reciprocal of 6/5 is 5/6.

Answer:

5/6

Step-by-step explanation:

Well to find a fraction's reciprocal all you need is to flop it like this

6/5 => 5/6

so 5 takes the place of 6 and 6 takes the place of 5

that's how 6/5 turns into 5/6

Answer: y^2+8x+12

Step-by-step explanation:

Answer:

x = 14

Step-by-step explanation:

2(x + 4) = 3( -2 + x)  distribute the 2 and the 3.

2(x) + 2(4) = 3(-2) + 3(x)

2x + 8 = -6 + 3x  Subtract 2x from both sides

2x - 2x + 8 = -6 +3x -2x

8 = -6 +x  Add 6 to both sides

8 + 6 = 6 - 6 + x

14 = x

Answer: option b), option c), and option e) are correct options.

Step-by-step explanation:

Given:

The area of a rectangular room= 750 square feet

The width of the room = 5 feet less than the length of the room

The length of the room = Y

To find:

Equations that can be used to solve the value of Y i.e. the length of the rectangular room.

Solution:

The equation can be derived from using the following formula:

Area of rectangle = length * width

According to the question,

Length of the rectangular room = Y

Width of the rectangular room = 5 feet less than the length of the room

                                                       = (Y-5)

Since, Area of rectangle = length * width

Area of the rectangular field = length of the room* width of the room

                          750             = Y (Y – 5)                         ………..eqn. (1)

Or, the above equation can be solved a step further and written as

                          750             = Y2 – 5Y                          ………..eqn. (2)

                         750- Y2 + 5Y= 0                                    ………..eqn. (3)

                         750-Y (Y- 5) =0                                    ………..eqn. (4)

Apart from the above equations, if we solve eqn. (2) we get the following equation:

                          750             = Y2 – 5Y

                           Y2 – 5Y- 750= 0

                          Y2 – 30Y + 25Y- 750 = 0

                          Y (Y- 30) + 25 (Y- 30) = 0

                                                                   take Y- 30 common from L.H.S.

                           (Y -30) (Y+ 25)   = 0                            …………….eqn. (5)        

Hence, the correct options are option b), option c), and option e).

Therefore exact coordinates of Centroid  = (0,3/2)

The centroid of a flat figure or solid figure, also known as the geometric center or center of figure, in mathematics and physics, is the arithmetic mean position of all the points on the figure's surface. Any n-dimensional Euclidean object is included by the same definition.

A polygon having three edges and three vertices is called a triangle. It is one of the fundamental geometric forms. Triangle ABC is the designation for a triangle with vertices A, B, and C. In Euclidean geometry, any three points that are not collinear produce a distinct triangle and a distinct plane.

This region is a parabola opening downward, with vertex at (0, 49) and a range of y values from 0 to 49. The region is symmetric about the y-axis, This means that the x-coordinate of the centroid is at 0.

To find the y-coordinate:

Integral from -√(49) to √(49) of (49-x²) x dx = [x²(49-x²)/3] from -√(49) to √(49) = (492√(49))/3 = (98√(49))/3

The area is integral from -√(49) to √(49) of (49-x²) dx = [x(49-x²)/2] from -√(49) to √(49) = (49*(2√(49)) - (2/3)(49^(3/2)))/2 = (49*(2*√(49)) - (98√(49))/3)/2

Therefore Centroid = (0, (98√(49))/(49*(2*√(49)) - (98√(49))/3)) = (0,3/2)

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Answer: To determine which store has the cheaper steak, you need to compare the price per pound of steak at each store. To do this, divide the total price by the number of pounds of steak at each store.

At Store A, the price per pound of steak is $6.38 because 25.50 / 4 = <<25.50/4=6.375>>6.375.

At Store B, the price per pound of steak is $6.71 because 40.25 / 6 = <<40.25/6=6.708>>6.708.

Therefore, Store A is cheaper because it has a lower price per pound of steak. The correct answer is Store A.

Step-by-step explanation:

The function for position x(t) could be x(t) = 3t^2 - 2t + 10.

In mathematics, a function is a relation between two sets that assigns to each element of the first set exactly one element of the second set. In other words, it is a rule that describes how one set of values is related to another set of values. Functions are used to model real-world scenarios and to solve mathematical problems. Examples of functions include linear equations, polynomials, and trigonometric functions.

This is determined by using the equation x'(t) = a(t). Differentiating both sides of the equation, we get x'(t) = 6t - 2. Integrating this equation, we get x(t) = 3t^2 - 2t + C, where C is the constant of integration. Since x(1) = 10, we can substitute this value into the equation and solve for the constant of integration. Therefore, we get x(t) = 3t^2 - 2t + 10.

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Answer:

Step-by-step explanation:

you should give the function, if i haven't it, how can i help you.

i can give u some tips, put 1.5, 2.5, 2 in function respectively. then calculate them, u will get the answer.

Answer:

(0,-4),(1,1)(2,6)

Step-by-step explanation:

Answer:

[tex] \sf \: b) \: 45[/tex]

Step-by-step explanation:

The values given are,

→ u = 7

→ d = 10

→ e = 3.2

Now the expression is,

→ 15(d - u)

Evaluating the expression,

→ 15(d - u)

→ 15(10 - 7)

→ 15 × 3

→ 45

Hence, option (b) is correct.

Answer:45

Step-by-step explanation:

15(10-7)

15(3)

multiply and get 45

On soloing the provided question we can say that - Area of the Circle - Area of the Triangle - Area of the Square is the area of the darkened area. A = 210-123 = 87 sq unit

Three sides and three vertices make up a triangle, which is a polygon. It is among the fundamental forms in geometry. Triangle ABC is a graphical representation of a triangle having vertices A, B, and C. When the three points are not collinear, a unique plane and triangle in Euclidean geometry are found. A triangle is a polygon that has three sides and three corners. The spots where the three sides join end to end make up the triangle's corners. Three triangle angles added together equal 180 degrees.

the sum of the areas of the circle, the triangle, and the square.

Area of the Circle - Area of the Triangle - Area of the Square is the area of the darkened area.

A = 210-123 = 87 sq unit

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Answer:

Below

Step-by-step explanation:

1+2+3+4+5 =15       5 lengths will require   4 cuts

The equilateral triangle ABC have a side length of 2 units of the radius length of the circle tangent to the line AB.

An equilateral triangle have all its side lengths equal so;

line AB = line BC = line AC

At points B and C where the lines AB and AC are tangent to the circle is the a side length BC of the equilateral triangle

Line BC form the diameter of the circle which is 2 radius of the circle so;

line BC = 2 × radius of the circle

line BC = 2 × 1

line BC = 2

Therefore, the side length of the equilateral triangle is 2 units of the radius of the circle tangent at point B and C.

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Answer:

24 miles

Step-by-step explanation:

each distance between points is 6.

6+6+6+6=24 miles

The ordered pair (x, y) for the given line can be obtained from the graph as (-4, 1).

A straight line can be written in the form of an equation as, y = mx + c.

Two straight lines intersect each other only at one point.

When two straight lines are parallel to each other the angle between them is zero.

The graph of the line is given.

In order to find the coordinate of a point do as follows,

Draw a perpendicular line from any point on the line to the x-axis.

The intersection of this line with the x-axis will give the x-coordinate.

Similarly, find the y-coordinate by drawing a perpendicular line to the y-axis.

Applying the above procedure, a point is obtained as (-4, 1).

Hence, the ordered pair for the line shown in the graph is (-4, 1).

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Joey needs to score more than 540 points, to be higher than

70th percentile of all scores.

Percentile is defined as the value below which a given percentage falls under.  

Example: In a group of 20 children, Ben is the 4th tallest and 80% of the children are shorter than you. Hence, it means that Ben is at the 80th percentile.

The percentile formula determines the performance of a person over others. The percentile formula is used in finding where a student stands in the test compared to other candidates. A percentile is a number where a certain percentage of scores fall below the given number.

Given,

Scores of first 9 players:

230, 540, 420, 430, 540, 560, 275, 50, 250

let the score of joey be x.

Scores of all 10 players

230, 540, 420, 430, 540, 560, 275, 50, 250

Dataset in ascending order =

50, 230, 250, 275, 420, 430, 540, 540, 560

70th percentile of the dataset

k = 70

i = the index

n = total number of given data values = 10

i = k/100(n+1)

i = 70/100 (9+1)

i = 70 × 10/100

i = 7

The index of 70th percentile = 7

value of 70th percentile = value of data on index 7.

value of 70th percentile = 540.

Hence, To be higher than 70th percentile of all scores,

Joey should score more than 540.

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The graph's X-intercepts are ((9+55)/2,0) and ((955)/2,0), and its Y-intercept is (0,13).

When locating points or other geometrical objects precisely on a manifold, such as Euclidean space, a coordinate system is a technique that uses one or more integers or coordinates. Locating a point or item on a two-dimensional plane requires the use of coordinates, which are pairs of integers. Two numbers called the x and y coordinates are used to describe a point's location on a 2D plane. a collection of integers that represent specific locations. The figure often has two numbers. The first number denotes the front-to-back measurement, while the second number denotes the top-to-bottom measurement. For example, in (12.5), there are 12 units below and 5 above.

given

Axis of symmetry:

x=9 /2

Vertex (minimum point): (9/2,−55/2)

X-intercepts: ((9+√55)/2,0) and ((9−√55)/2,0)

Y-intercept: (0,13)

The graph's X-intercepts are ((9+55)/2,0) and ((955)/2,0), and its Y-intercept is (0,13).

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[tex]~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill[/tex]

[tex](-6x^3 y^5 + 11x^3 y^2) \div (-2x^2 y^3)\implies \cfrac{-6x^3 y^5 + 11x^3 y^2}{-2x^2 y^3} \\\\\\ \cfrac{-6x^3 y^5}{-2x^2 y^3}+\cfrac{11x^3 y^2}{-2x^2 y^3}\implies \cfrac{-6}{-2}\cdot \cfrac{x^3 y^5}{x^2 y^3}+\cfrac{11}{-2}\cdot \cfrac{x^3 y^2}{x^2 y^3} \\\\\\ 3\cdot x^3 x^{-2}y^5 y^{-3}+\cfrac{11}{-2}\cdot \cfrac{x^3 x^{-2}}{y^3 y^{-2}}\implies 3x^{3-2}y^{5-3}-\cfrac{11}{2}\cdot \cfrac{x^{3-2}}{y^{3-2}} \\\\\\ ~\hfill {\Large \begin{array}{llll} 3x y^2 -\cfrac{11x}{2y} \end{array}}~\hfill[/tex]

Answer: a) The control in the experiment, 0 kHz, or no sound, serves as a baseline against which to compare the other treatments. By using the control with no sound, researchers can determine whether the deer's response to the sound-emitting devices is due to the sound itself or some other factor. Without the control, it would be unclear what caused any differences in the deer's responses to the different sound treatments.

(b)(i) One advantage to keeping the loudness at a constant 60 decibels for all treatments is that it allows researchers to directly compare the deer's responses to the different sound pitches without the added variable of loudness.

(b)(ii) One disadvantage to keeping the loudness at a constant 60 decibels for all treatments is that loudness may also play a role in deer's response. So, it would be unclear if the different in deer's responses are due to sound frequency only or also caused by sound loudness

(c) Based on the results shown in the bar chart, it can be seen that the deer's response to the sound-emitting devices varies depending on the pitch of the sound. At lower pitches, around 0.28 kHz, the deer's response is more likely to be negative or neutral, indicating that they move away from or don't move towards the highway. At higher pitches, around 15 kHz, the deer's response is more likely to be positive, indicating that they move towards the highway. It suggests that the frequency of sound has an impact on the deer's response. So, based on this data, we cannot recommend using a sound-emitting device to keep deer from running across highways without further research on the optimal frequency and loudness that should be used to make sure that it is effective and safe for the deer.

Step-by-step explanation:

The sound-emitting device may have both advantages and disadvantages depending on the pitch. More research is necessary to find the optimal frequency and volume for the device to be effective and safe.

Based on the results of the experiment, it would not be advisable to use a sound-emitting device to prevent deer from running across highways without further research. The experiment showed that the deer's response varied depending on the pitch of the sound. Although the device showed some advantages, such as moving deer away from the highway at lower pitches, it also presented potential disadvantages. At higher pitches, the deer had a tendency to move towards the highway, which could increase the risk of accidents. More research would be needed to determine the optimal frequency and volume to use for the device to be both effective and safe for the deer.

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