a truck in a traffic circle travels in a circular path at constant speed v0 while passing through region x of the circle, as shown in figure 1 above. a diagram representing the forces exerted on the truck in region x is shown in figure 2. at a later time a car with less mass than the truck passes through region x at the same speed and the same distance from the center of the traffic circle as the truck. the coefficient of friction between the car’s tires and the ground is the same as that for the truck’s tires and the ground. which of the following diagrams could represent the forces exerted on the car in region x compared to the truck in region x ? assume that the length of each arrow is proportional to the magnitude of the force represented by the arrow.

Answers

Answer 1

The Diagram that represents the forces exerted on the car in region x when compared to the truck in region X is :  Diagram C

Given that the mass of the car is less than the mass of the truck the force due to gravity will be greater on the truck than it could be on the car

i.e. | Fg |car  <  | Fg | truck

also : | Fₙ | car  <  | Fₙ | truck

Since the gravitational force on the car is less than the gravitational force on the truck

| Ff | car < | Ff | truck

where : Ff = frictional force

             Fg = force due to gravity

             Fn  normal force

Therefore from the diagrams attached below the correct diagram that represents the forces exerted on the car in region x when compared to the truck in region X is :  Diagram C.

Learn more about gravitational force : https://brainly.com/question/1550731

Attached below is the missing data related to your question

A Truck In A Traffic Circle Travels In A Circular Path At Constant Speed V0 While Passing Through Region

Related Questions

c. Two persons A and B are pushing a block from opposite sides with
force of 5N and 6N respectively.
[3]
i) Find the magnitude of the resultant force on the block.
ii) Find the direction of resultant force with respect to A and B.

Answers

Answer:

1 N

Explanation:

1) You'll just have to sum the force vectors, and since they are opposite, you'll calculate the difference of their magnitudes, in absolute value.

Ftot = |F1 - F2| = 6N - 5N = 1N

2)The direction will be the same as the greater force's direction.

A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules

Answers

Answer:

this question makes no sense

Explanation:

like how do you get this question

Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.

Explanation:

A car accelerates from 10m/s to 22m/s in 10 seconds. What is the car’s acceleration?

A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s.

Explain please.

Answers

Answer:

See attachment and below

Explanation:

A car accelerates from 10m/s to 22m/s in 10 seconds.

a = (22m/s - 10m/s)/10sec

a = 12m/s/10s

a = 1.2 m/s^2

A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s

a = 98m/s - 0m/s)/10sec

a = 9.8 m/s^2

9.8 meters/sec^2 is the acceleration due to gravity.

you serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 30 m/s. The ball has how much energy

Answers

Answer:

In classical mechanics, kinetic energy (KE) is equal to half of an object's mass (1/2*m) multiplied by the velocity squared. For example, if a an object with a mass of 10 kg (m = 10 kg) is moving at a velocity of 5 meters per second (v = 5 m/s), the kinetic energy is equal to 125 Joules, or (1/2 * 10 kg) * 5 m/s2.

the purpose of many scientific investigations is to test a {n}

Answers

Hypothesis , I believe the answer is hypothesis

Answer:

Scientific investigation is a quest to find the answer to a question using the scientific method.

Explanation:

the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.

Which electromagnetic wave has a lowest frequency?
Group of answer choices

A) x-rays

B) ultraviolet light

C) microwaves

D) infrared light

E) visible light

Answers

Answer:

E.visible lights

Explanation:

hope its attachments

Block A has a mass of 2kg and a speed of 50 m/s along the positive x axis.

Block B has a mass of 4 kg and a speed of 25 m/s along the negative x axis.



The two blocks collide head-on in a perfectly elastic collision.

Determine the velocity of each mass after the collision.

Answers

Momentum is conserved, so

(2 kg) (50 m/s) + (4 kg) (-25 m/s) = (2 kg) v₁' + (4 kg) v₂'

where v₁' and v₂' are the velocities of the two blocks after the collision. Simplifying this gives

100 kg•m/s - 100 kg•m/s = (2 kg) v₁' + (4 kg) v₂'

0 = (2 kg) v₁' + (4 kg) v₂'

v₁' = -2v₂'

Energy is also conserved, so

1/2 (2 kg) (50 m/s)² + 1/2 (4 kg) (-25 m/s)² = 1/2 (2 kg) (v₁')² + 1/2 (4 kg) (v₂')²

Simplifying yields

2500 J + 1250 J = (1 kg) (v₁')² + (2 kg) (v₂')²

3750 J = (1 kg) (v₁')² + (2 kg) (v₂')²

Substitute v₁' = -2v₂' and solve for v₂' :

3750 J = (1 kg) (-2v₂')² + (2 kg) (v₂')²

3750 J = (6 kg) (v₂')²

(v₂')² = 625 J/kg = 625 m²/s²

v₂' = 25 m/s

Then the first block has final velocity

v₁' = -2 (25 m/s)

v₁' = -50 m/s

an airplane flies with a constant speed of 620 miles per hour. how far can it travel in 3 1/2 hours?

Answers

Answer:

hi there !

1 hour -------> 620 miles

3 1/2 ---------> ?

the number of miles the airplane travels in 3 1/2 hours

= 3 1/2 × 620 = "2170" miles

when a rigid body rotates about a fixed axis, all the points in the body have the same

Answers

Hi there!

[tex]\large\boxed{\text{Angular acceleration.}}[/tex]

For a rigid body rotating about a fixed axis, its angular characteristics ⇒ angular acceleration and velocity are constant throughout.

However, its LINEAR velocities/accelerations differ because of the following relationships:

v = ωr

a = αr

Thus, a point closer to the axis of rotation has a smaller linear velocity or acceleration compared to a point along the edge.

An object is projected into the air with a vertical velocity of 20 feet per second. At what times will the object be on the ground

Answers

Answer:

20 ft/sec / 32 ft/sec^2 = .625     to reach top

2 * .625 = 1.25

It will be on the ground at t = 0 and t = 1.25

You can also solve the equation:

H = 0 = V0 t - 1/2 g t^2

Obviously, at t=0 h = 0

V0 = 1/2 g t    is a solution

t = 20 * 2 / 32 = 1.25 sec

HEELPPPP!! A train travels 195 kilometers in 4.0 hours, and then 125 kilometers in 3.0 hours. What is its average speed?

Answers

Answer:

Train A has a speed 20 miles per hour greater than that of train B. If train A travels 300 miles in the same times train B travels 220 miles, what are the speeds of the two trains?

2. A woman has a total of $13,000 to invest. She invests part of the money in an account that pays 11% per year and the rest in an account that pays 12% per year. If the interest earned in the first year is $1490 how much did she invest in each account?

Explanation:

How did the Agricultural Revolution impact humans? In your opinion, were those changes good or bad? Why?

Answers

Answer:

The Agricultural Revolution of the 18th century paved the way for the Industrial Revolution in Britain. New farming techniques and improved livestock breeding led to amplified food production. This allowed a spike in population and increased health. The new farming techniques also led to an enclosure movement

What is the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4 m/s? (Formula: ) 3 J 6 J 12 J 24 J.

Answers

The kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

HOW TO CALCULATE KINETIC ENERGY:

The kinetic energy of a moving body can be calculated by using the following formula:

K.E = ½mv²

Where;

K.E = kinetic energy (J)m = mass (kg)v = velocity (m/s)

According to this question, a toy truck has a mass of 0.75 kg and a velocity of 4 m/s. The kinetic energy is calculated as follows:

K.E = ½ × 0.75 × 4²

K.E = 8 × 0.75

K.E = 6J

Therefore, the kinetic energy of a toy truck with a mass of 0. 75 kg and a velocity of 4m/s is 6J.

Learn more about kinetic energy at: https://brainly.com/question/999862?referrer=searchResults

Which image shows an example of the electromagnetic force in action?

Answers

Answer:

Where are the images?

Explanation:

I can't help if there is no image(s) to this question.

If the density of gold is 19.3 g/mL, what is the mass of 5mL of gold?​

Answers

Answer:

96.5 mL

Explanation:

according to newton's third law, of a sledgehammer hits a wall with a force of 1000 n, how much force does the wall hit the sledgehammer? a - 1000 n b 1000 n c 0 n d 500 n

Answers

The correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Newton's third law

Newton's third law of motion states that for every action or force, there is an equal but oppositely directed force.

Application of the newton's third law

Force with which the sledgehammer hits the wall = 1000 N

From the Newton's third law, an equal but oppositely directed force is exerted on the sledgehammer by the wall.

Thus, the force exerted by the sledgehammer on the wall = -1000 N

The negative sign indicates that the force acts in a direction opposite to that of the sledgehammer.

Thus, the correct option is A: the force exerted on the wall by the sledgehammer is  - 1000 N

Learn more about Newton's third law and force at: https://brainly.com/question/13874955

Paint is an example of which of these?

compound

heterogeneous mixture

homogeneous mixture

none of the above

Answers

Answer:

Homogenous Mixture

Explanation:

The composition in paint is uniform so every part of it looks the same throughout the paint.

hi my name is coolboy123hillok

Answers

Answer:

you should change that name

please change your name

Recoil is noticeable if you throw a heavy ball while standing on roller skates. If instead you go through the motions of throwing the ball but hold onto it, your net recoil velocity will be

Answers

Answer:

Since there is no external force, there is no change (movement) in the center of mass. Internally, the center of mass might change position, but the external result is still zero net velocity.

The net recoil velocity must be zero.

when an individual charge flies through a *blank* field, a force is exerted on the charge and the path of the charge bends.

Answers

Answer:

"electric or magnetic"

F = q E    force on charge q due to electric field E

F = q v x B       force on charge q due to magnetic field B

Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?
answers:
3.26 meters

3.26 minutes

69 meters

69 minutes

Answers

Answer:

69 meters

Explanation:

John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?

a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s

Answers

The horizontal component of the velocity is equal to: D. 15 m/s.

Given the following data:

Velocity = 30 m/sAngle = 60°

To determine the horizontal component of the velocity:

The horizontal component of the velocity represents the influence of velocity  in displacing an object or projectile in the horizontal direction.

Mathematically, the horizontal component of velocity is given by the formula:

[tex]V_x = Vcos(\theta)[/tex]

Substituting the given parameters into the formula, we have;

[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]

Horizontal component, Vx = 15 m/s

Read more on horizontal component here: https://brainly.com/question/24681896

With an initial velocity of 20km per hour a car accelerated at 8m/s2 for 10s,what is the position of the car at the end of 10s

Answers

initial velocity=u=20km/h=5.5m/sAcceleration=a=8m/s^2Time=t=10s

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

[tex]\\ \sf\longmapsto s=5.5(10)+\dfrac{1}{2}(8)(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(5.5)^2[/tex]

[tex]\\ \sf\longmapsto s=55+4(30.25)[/tex]

[tex]\\ \sf\longmapsto s=55+121[/tex]

[tex]\\ \sf\longmapsto s=176m[/tex]

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.

Answers

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]

v₂ = 5.7 m/s

Learn more about the law of conservation of momentum here:

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A racecar was going 60 m/s when it quickly came to a full stop at a pitstop in 8.0 sec. What was the acceleration of the dragster? Answer to the nearest hundredth

Answers

You start by writing down your parameters;
u=60m/s
v=0
t=8s
So acceleration(a)=v-u/t
=0-60/8
=-60/8
=-7.5m/s
To the nearest hundredth will be
-7.5*100
=-750m/s

Connor rode an inner tube down a river. For 4.6 minutes, he moved downriver at 15 meters per minute. During this time, how far did he move?

Answers

Answer:

2 miles

Explanation:

Two lumps of clay approach each other from opposite directions and collide head on inelastically, combing into one large lump after they collide. the first lump has a mass of 0.140kg and has a speed of 3.50 m/s before the Collision. the second lump has a mass of 0.620kg and has a speed of 4.81 m/s before the collison in a direction opposite that of the first lump. what velocity does the combined lump have after the collision?

Answers

Answer:

Before collision:

momentum to right = .14 * 3.5 = .49 kg m / s

momentum to left = .62 * 4.81 = 2.98 kg m / s

Total momentum = .49 - 2.98 = - 2.49 to left

M V = -2.49    net momentum to left

V = -2.49 / (.14 + .62) = -3.28 m/s to left

A book with a. mass of 1 kg is sliding on a table. If the frictional force on the book is 5 N, calculate the book’s acceleration. Is it speeding up or slowing down?

Answers

Force = mass x acceleration:

5N = 1kg x acceleration

Acceleration = 5N / 1 kg

Acceleration  = 5 m/s^2

Acceleration is a positive value so it is speeding up

Draw a nitrogen cycle and explain in short.
please help me ​

Answers

Answer:   biogeochemical process

Explanation:

29) A cheetah can accelerate from rest to 25
m/s in 6 s. Assuming that the cheetah moves
with constant acceleration, what distance does
it cover in the first 3 s

Answers

Answer:

[tex]\huge\boxed{\sf S = 18.75 \ meters}[/tex]

Explanation:

Given Data:

Initial Velocity = Vi = 0 m/s (rest)

Final Velocity for 6 seconds = Vf = 25 m/s

Time (1) = T1 = 6 seconds

Time (2) = T2 = 3 seconds

Required:

Distance for 3 seconds = S = ?

Solution:

For 6 seconds, the acceleration will be:

[tex]\displaystyle a = \frac{Vf-Vi}{t} \\\\a = \frac{25 - 0}{6} \\\\a = 25 / 6\\\\\boxed{a = 4.167 \ m/s^2}[/tex]

Since, acceleration is constant, it will be the same at 3 seconds as well.

Using second equation of motion to find Distance (S) with time being 3 seconds:

[tex]\displaystyle S= Vit+\frac{1}{2} at^2\\\\S = (0)(3)+ \frac{1}{2} (4.167)(3)^2\\\\S = \frac{1}{2} (4.167)(9)\\\\S = \frac{37.5}{2} \\\\\boxed{S = 18.75 \ meters}\\\\\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807
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