A wave along a guitar string has a frequency of 540 Hz and a wavelength of 2.5 meters. What is the speed of the wave?

The difference in the power required by the motor at start up and at operating speed is 9778.57

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = voltage (V) × current (I)

P = IV

Power = square voltage (V²) / resistance ®

P = V² / R

P = V² / R

P₁ = 62² / 0.14

P₁ = 27457.14 watts

P = V² / R

P₂ = 37² / 0.14

P₂ = 9778.57 watts

Difference = P₁ - P₂

Difference in power = 27457.14 - 9778.57

Difference in power = 17678.57 watts

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The acceleration of the person is 4.108 m/s^2.

What is acceleration?

The acceleration is the rate of change in the velocity in a unit of time.

Angular velocity: The change in angular displacement in a unit of time is called angular velocity.

Tangential velocity: The tangential velocity can be defined as the velocity of an object which is perpendicular to the radius in the rotational motion.

The relation between angular velocity ω, tangential velocity v, and radius r from the axis when the radius is perpendicular to the tangential velocity is,

v=ω*r

Given r=15 m, and ω=5 turns/minutes, substitute these values in the above formula.

Note: 1 turn/minute = 2π/60 rad/s.

v=(5 turns/minutes)*15 m

v=(5*2π/60 rad/s)* 15 m

v=7.85 m/s

Since the motion is circular, and the person is at the lowest point of the wheel, so the acceleration due to gravity will have no effect as it is perpendicular to tangential velocity here. The acceleration a for rotational motion is given by,

a=v^2/r

Substitute v=7.85 m/s, and r=15 m in this equation and solve it.

a=(2.094)^2/(15)

a=4.108 m/s^2

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Answer:

Approximately [tex]\$ 3.02[/tex].

Explanation:

Note that the electric rate in this question is in the unit dollar-per-[tex]{\rm kWh}[/tex], where [tex]1\; {\rm kWh}[/tex] is the energy to run an appliance of power [tex]1\; {\rm kW}[/tex] for an hour.

Number of minutes for which the air conditioner is running in that day: [tex]15 \times 24 = 360\; \text{minute}[/tex]. Apply unit conversion and ensure that this time is measured in hours (same as the unit of the electric rate.)

[tex]\begin{aligned} \text{time} &= 360\; \text{minute} \times \frac{1\; \text{hour}}{60\; \text{minute}} = 6\; \text{hour} \end{aligned}[/tex].

The power of this air conditioner is:

[tex]\begin{aligned} \text{power} &= \text{voltage} \times \text{current} \\ &= 240\; {\rm V} \times 21\; {\rm A} \\ &= 5040\; {\rm W} \\ &= 5.04\; {\rm kW} \end{aligned}[/tex].

Thus, the energy that this air conditioner would consume would be:

[tex]\begin{aligned}\text{energy} &= \text{power} \times \text{time} \\ &= 5.04\; {\rm kW} \times 6\; \text{hour} \\ &= 30.24\; {\rm kWh} \end{aligned}[/tex].

At a rate of [tex]0.1[/tex] dollar-per-[tex]{\rm kWh}[/tex], the cost of that much energy would be approximately [tex]3.02[/tex] dollars (rounded to the nearest cent.)

when they meet the 40-kg boy will have moved a distance of 6 m.

Friction is the force that resists motion when the surface of one object comes in contact with the surface of another.

It is the average position of all the parts of the system, weighted according to their masses.

here,

masses of the boys

M=40 kg,

m=60 kg

x1 = 10 m

The displacement of the 40 kg boy is calculated from the principle of center mass.

XM = ( mx1 + Mx2) / ( m + M )

X(40) = (60 x 10 +  40 x 0) / (40 kg + 60 kg)

X(40) = (600)/(100)

X(40) = 6 m

X(60) = (60 x 0 + 40 x 10 m) / (40 kg + 60 kg)

X(60) = (400)/(100)

X(60) = 4 m

Thus,

when they meet the 40-kg boy will have moved a distance of 6 m.

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The distance traveled by the sprinter in meters is determined as 1.88 m.

The acceleration of the sprinter is the rate of change of velocity of the sprinter with time.

The acceleration of the sprinter is calculated as follows;

Apply Newton's second law of motion as follows;

F = ma

a = F/m

where;

a = 693 N / 64 kg

a = 10.83 m/s²

The distance traveled by the sprinter is calculated as follows;

s = ut + ¹/₂at²

where;

s = ¹/₂at²

where;

s = (0.5)(10.83)(0.59²)

s = 1.88 m

Thus, the distance traveled by the sprinter in meters is determined as 1.88 m.

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Option b) Stomach is most likely to have the most muscles.

There are five main muscles in stomach pyramidalis, rectus abdominus, external obliques, internal obliques, and transversus abdominis.

Muscles circulate frame parts by contracting after which relaxing. muscular tissues can pull bones, however, they cannot push them to return to their unique role. so they paintings in pairs of flexors and extensors. The flexor contracts to bend a limb at a joint.

The muscle groups that circulate our frame elements are called skeletal muscles, and they're a form of striated muscle. We will actively manipulate those with our brains. another sort of striated muscle is those that maintain our hearts pumping, which we are not able to actively control.

Muscles pull at the joints, allowing us to move. a couple of muscular tissues are used for any sort of motion of a bone. Although we are sitting flawlessly nevertheless, muscle tissues at some point in the frame are constantly shifting.

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It would take 531 minutes for a single electron in the electron sea to drift from one end to the other end of a wire 35 cm long.

What is electric current?

A rate of electric charge flowing past a place or region is called an electric current. A net passage of electric charge through a region creates an electric current.

Here,

ρ is the density of electrons = 8.4×10²⁸ kg/m³

i is the electric current =9.08×10¹⁸ electrons/sec

d is the diameter of the wire =3.6 mm = 0.0036 m

r is radius, r = d/2, r = 1.8 mm = 0.0018 m

l is the length of wire = 34 cm = 0.34 m

v is The volume of the wire

We know that Volume:

V = π r^2* l

V = (3.14* 0.0018^2) 0.34

V = 3.45* 10^-6 m³

Now,

no of electrons= ρ × V

n =  8.4×10²⁸ * 3.45* 10^-6

n = 2.898 * 10^ 23

The time required for the drifting electron is equal to the ratio of the number of electrons to the electric current flows.

T = n/i

T = 2.898 * 10^ 23 / 9.08×10¹⁸

T = 0.3191 * 10^5 s

T = 531 minutes

Hence,

It would take 531 minutes for a single electron in the electron sea to drift from one end to the other end of a wire 35 cm long.

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The most accurate place to conduct a weight check is at safety-stop death, at the end of the dive.

Why is a weight check important in diving?

A weight check before diving helps an individual decide on the right amount of weight needed for each scuba dive.

To do a weight check one must float upright on the surface, head placed above water. The individual then needs to ­release some air from their Buoyancy compensator as they take a deep breath from their regulator.

Now if the individual sinks rapidly below the ­surface, they are overweight and if their head stays above the water surface, then they are underweight. Thus, when an individual sinks up to the mask ­level, then the weight is just right.

Therefore, the most accurate place to conduct a weight check is at safety-stop depth, at the end of the dive.

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Answer: Cytosine is methylated resulting in 5-methylcytosine. Then the gene expression will decrease.

Explanation: To find the answer, we need to know more about the methylation of cytosine.

Thus, we can conclude that, Cytosine is methylated resulting in 5-methylcytosine. Then the gene expression will decrease.

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Answer:  When you cannot stop safely at a yellow traffic light before entering an intersection, enter the intersection carefully and continue across.

Explanation: To find the correct answer, we need to know more about the traffic signal rules.

Thus, we can conclude that, the option C is correct.

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The wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

According to the question

The frequency of a photon of electromagnetic radiation = 151.7 Mhz

By using the Formula of wavelength and frequency

λ = C/f

Where,

λ (Lambda) = Wavelength in meters

C = Speed of Light (c = 3x10⁸ m/s)

f = Frequency

Now, the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is  

1 Mhz = 1000000 Hz

151.7 Mhz = 151.7 * 10⁶ Hz

λ = C/f  

Substituting the value of C and f  

  λ =  [tex]\frac{3*10^{8} }{151.7 * 10^{6} }[/tex]

  λ = 1.978 meter

Hence,  the wavelength of a photon of electromagnetic radiation with a frequency of 151.7 Mhz is 1.978 meter

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She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

What is focal length?

The focal length is a measure of how strongly the system converges or diverges light.

A positive focal length indicates that a system converges light, while a negative focal length indicates that the system diverges light.

For a standard rectilinear lens,

FOV = 2 arctan (x/2f)

FOV ∝ 1 / f

where x is the diagonal of the film.

Focal length (f) and field of view (FOV) of a lens are inversely proportional.

From the equation we can say that,

A shorter focal length gives you a wide angle of view which allows more view to fit in the frame.

Hence,

She should use shorter focal length to fit the entire landscape which she is trying to photograph into her picture.

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For the different wires the values given are

For Wire A,  Area=[tex]A_{A}[/tex], Resistivity=[tex]ρ_{A}[/tex], Length= [tex]L_{A}[/tex], Heat=[tex]H_{A}[/tex], Voltage= V, Time= t, Wire B,  Area=[tex]A_{B}[/tex], Resistivity=[tex]ρ_{B}[/tex], Length= [tex]L_{B}[/tex], Heat=[tex]H_{B}[/tex]

So, [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]=[tex]\frac{V^{2} *t}{\frac{ρ(1)*L_{A} }{A_{A} } }[/tex]/[tex]\frac{V^{2} *t}{\frac{ρ(2)*L_{B} }{A_{B} } }[/tex]

Therefore [tex]H_{A}[/tex]/ [tex]H_{A}[/tex]= [tex]\frac{A_{A}*ρ_{B} *L_{B}}{A_{B}ρ_{A} L_{A} }[/tex]

The type of energy that moves between two materials with varying temperatures is referred to by scientists as heat. Because the average translational kinetic energy per molecule in the two materials varies, an energy transfer takes place. Up until thermal equilibrium is attained, heat is transferred from the substance with the higher temperature to the material with the lower temperature. The joule, with 1 joule equalling 1 newton meter, is the SI unit of heat. Imagine the following situation to better comprehend what happens when this energy transfer takes place: Tiny rubber balls are bouncing all over two distinct containers that are full with them. The difference between the average ball speed in one container and the second container is substantial.

(a) Circular metal wires in electrical circuits may have different cross-sectional areas (different diameters) and different lengths. For a given applied voltage, how would the joule heat vary with these parameters

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option (a)i.e, It is magnetic when the atoms in a magnetic material are lined up.

Magnetic fields can be represented visually using magnetic field lines. In each case, they specify the direction of the magnetic force acting on a north monopole. The lines' density reveals how large the field is. For example, the magnetic field is more intense and dense near a magnet's poles.

The spin and orbital momentum of an atom's electrons produce magnetism. The term "magnetic anisotropy" refers to how an atom's magnetic characteristics change depending on how the orbits of its electrons are oriented in relation to the composition of a substance. Additionally, it gives magnetization directionality and stability

Each atom creates a tiny magnetic field because the orbiting electrons are tiny moving charges. The direction or orientation of these magnetic fields is referred to as the atom's magnetic moment. In a nutshell, an object's atoms behave like a number of small magnets.

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The net electric field at point D is determined as 3.95 x 10⁷ N/C.

E = kq/r²

where;

E(AD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(AD) = 2.16 x 10⁷ i N/C

E = kq/r²

where;

r² = 5²  + 5²

r² = 50

r = √50

r = 7.07 cm

E(BD) = (9 x 10⁹ x 5 x 10⁻⁶)/(0.0707²)

E(BD) = 9 x 10⁶ N/C

in x - direction = 9 x 10⁶ N/C x cos(45) = 6.36 x 10⁶ i  N/C

in y - direction = 9 x 10⁶ N/C x sin(45) = 6.36 x 10⁶j  N/C

E = kq/r²

where;

E(CD) = (9 x 10⁹ x 6 x 10⁻⁶)/(0.05²)

E(CD) = 2.16 x 10⁷ j N/C

Ei = 2.16 x 10⁷ i N/C  + 6.36 x 10⁶ i  N/C

Ei = 2.796 x 10⁷ i N/C

Ej = 2.16 x 10⁷ j N/C  + 6.36 x 10⁶j  N/C

Ej = 2.796 x 10⁷ j N/C

E = √Ei² + Ej²

E = √[(2.796 x 10⁷)² + (2.796 x 10⁷)²]

E = 3.95 x 10⁷ N/C

Thus, the net electric field at point D is determined as 3.95 x 10⁷ N/C.

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F = ma is the formula of Newton's Second Law of Motion. Newton's Second Law of Motion is described as Force is equal to the rate of change of momentum. For a constant mass, force equals mass duration acceleration.

Newton's Second Law of Motion F=ma is very significant because it indicates the relationship between forces and motion. It permits you to calculate the acceleration (and therefore velocity and position) of an object with known forces. This is extremely helpful for scientists, engineers, inventors, etc.

Therefore : F is directly proportional to m×a. This relation F is directly proportional to m×a can be turned into an equation by placing in a constant k.

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Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

The joining of tail of the first vector with the head of the second vector represents the resultant vector whereas the direction of the resultant vector is from the tail of the first vector towards the head of the second.

So we can conclude that Head to tail rule helps us to find the resultant of forces because in this rule we join many vectors with each other forming resultant vector.

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Answer: A satellite with a mass of 110 kg and a kinetic energy of 3.08×10^9 J must be moving at a speed of 7483 m/s.

Explanation: To find the answer we need to know about the kinetic energy of a body.

                                   [tex]KE=\frac{1}{2}mv^2[/tex]

                                   [tex]m=110kg\\KE=3.08*10^9J\\[/tex]

                               [tex]v=\sqrt{\frac{2KE}{m} } =\sqrt{\frac{2*3.08*10^9}{110} } =7.483*10^3 m/s[/tex]

Thus, we can conclude that, the velocity of the satellite will be 7438m/s.

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In order to move at a speed of 7483 m/s, a satellite with a mass of 110 kg and a kinetic energy of 3.08× 10^-9 J must be travelling.

Understanding a body's kinetic energy is necessary in order to determine the solution.

                         [tex]KE=\frac{1}{2}mV^2[/tex]

               [tex]m=110kg\\KE=3.08*10^9J[/tex]

                        [tex]V=\sqrt{\frac{2KE}{m} }=7.48km/s[/tex]

Thus, we can infer that the satellite will move at a speed of 7438 m/s.

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Tuning forks with a frequency of 500 to 1000 hz are most commonly used to measure: hearing loss

A person is said to have hearing loss if they are not able to hear as well as someone with normal hearing, meaning hearing thresholds of 20 dB or better in both ears. It can be mild, moderate, moderately severe, severe or profound, and can affect one or both ears.

High-pitched tuning fork with frequency of 500 to 1000 hertz (Hz) should be used to estimate hearing loss in range of normal speech (300 to 3000 Hz).

The 512-Hz Rinne tuning fork test could be very effective at detecting conductive hearing losses when performed by an experienced tester and when masking was used . Tuning forks  are used to carry Rinne and Weber tests. These tests provide a quick easy method of determining whether a hearing loss is situated in the middle ear or inner ear

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Sport-type motorcycles typically feature a higher than average power-to-weight ratio.

What is scrambler motorcycle?

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Answer:

false

Explanation:

Answer: A small mailbag is released from a helicopter that is descending steadily at 1.53 m/s. Then,

a) after 4s, the speed of the mailbox will be, 40.73m/s downwards.

b)78.4m downwards.

c) v=37.67m/s downward. and d=78.4m downward.

Explanation: To find the answer, we need to know more about the equations of uniformly accelerated motion.

                                [tex]v=u+at\\S=ut+\frac{1}{2}at^2\\ v^2-u^2=2aS\\S=\frac{v+u}{2}t[/tex]

            [tex]v=u+gt=-1.53-(9.8*4)=-40.73 m/s^2[/tex]

           [tex]d_1=ut+\frac{1}{2}gt^2=(-1.53*4)+\frac{-9.8*16}{2} =-84.52 m\\d_2=vt=-40.73*4=-162.92 m\\d=-162,92+84.52=-78.4m[/tex]

                 [tex]v=u+gt=1.53-(9.8*4)=-37.67 m/s[/tex]

                 [tex]d_1=ut+\frac{1}{2}gt^2=(1.53*4)+\frac{-9.8*16}{2} =-72.28 m\\ d_2=vt=-37.67*4=-150.68 m\\d=-150.68+72.28=-78.4 m[/tex]

Thus, we can conclude that, the answers to the question are, a) after 4s, the speed of the mailbox will be, 40.73m/s downwards.

b)78.4m downwards.

c) v=37.67m/s downward. and d=78.4m downward.

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Answer:

Error

Explanation:

Speed= Distance / Time

Speed = 0.1

The pressure in the hose as the speed of water changes from 2.05 m/s to 31.4 m/s as it goes through the nozzle is 5.92 × 10⁵ N/m².

Given:

The flow of water through the hose initially, v₁ = 2.05 m/s

The flow of water through the hose initially, v₂ = 31.4 m/s

Calculation:

From Bernoulli's equation we have:

P₁ + 1/2 ρv₁² + ρgh₁ = P₂ + 1/2 ρv₂² + ρgh₂

where P₁ is atmospheric pressure

           P₂ is the pressure in the hose

           ρ is the density of the fluid

           h₁ is the initial height

           h₂ is the final height

           v₁ is the initial velocity of the fluid

           v₂ is the final velocity of the fluid  and

           g is the acceleration due to gravity

Re-arranging the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (h₁-h₂)

Applying values in the above equation we get:

P₂ = P₁ + 1/2 ρ(v₁²-v₂²) + ρg (0)

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [(31.4m/s)²-(2.05 m/s)²]

    = (1.01 × 10⁵ Pa)+ 1/2 (10³ g/m³) [981.7575]

    = (1.01 × 10⁵ Pa)+ (4.91 × 10⁵ Pa)

    = 5.92 × 10⁵ Pa

    = 5.92 × 10⁵ N/m²

Therefore, the pressure in the hose is 5.92 × 10⁵ N/m².

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The form of precipitation which may occur from this type of clouds is cumulus clouds.

Precipitation cloud is the cloud from which rain falls or looks likely to fall.

Below are some types of precipitation:

Precipitation refers to any or all of the forms of water particles, whether liquid or solid, that fall from the atmosphere such as; rain, hail, snow or sleet).

It is a major class of hydrometeor, but it is distinguished from cloud, fog, dew, rime, frost, etc., in that it must fall. It is distinguished from cloud and virga in that it must reach the ground.

Cloud refers to visible mass of water droplets suspended in the air.

In conclusion, the form of precipitation which may occur from this type of clouds is cumulus clouds

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The new moment of inertia of the gymnast is 9kgm^2.

To find the answer, we need to know about the conservation of angular momentum.

                      I₁×w₁= I₂×w₂

                      I₂= I₁×w₁/w₂

                         = (6×12)/8

                         = 9kgm^2

Thus, we can conclude that the new moment of inertia of the gymnast is 9kgm^2.

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The reading of the scale after 3.6 seconds is 23.79 N.

v = √2gh

v = √(2 x 9.8 x 2.2)

v = 6.57 m/s

mv/t = F = 0.4 x 6.57 = 2.628 N

Wb = 0.72 x 9.8

Wb = 7.056 N

Wa = (RT)g

Wa = (0.4 x 3.6) x 9.8

Wa = 14.11 N

R = Wa + Wb + F

R = 14.11 N  +  7.056 N  +  2.628 N

R = 23.79 N

Thus, the reading of the scale after 3.6 seconds is 23.79 N.

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Answer:

initial velocity is the constant in horizontal projectile

In addition to ozone, the four other greenhouse gases or groups of greenhouse gases are included in nearly all the climate models are Carbon dioxide, water vapor, and methane, nitrous oxide.

Carbon dioxide, absorbs energy at a variety of wavelengths, a range that overlaps with that of infrared energy. As CO2 soaks up this infrared energy, it vibrates and re-emits the infrared energy back in all directions. About half of that energy goes out into space, and about half of it returns to Earth as heat, contributing to the ‘greenhouse effect.’

As methane is emitted into the air, it reacts in several ways. It reacts and  after oxidization methane forms water vapor and carbon dioxide. So, not only does methane contribute to global warming directly but also, indirectly through the release of carbon dioxide.

Nitrous oxide enhances the greenhouse effect by capturing reradiated infrared radiation from the Earth’s surface and subsequently warming the troposphere . It is chemically inert in the troposphere and stays in the troposphere for about 120 years before moving into the stratosphere where it ultimately leads to destruction of stratospheric ozone.

Water vapor does absorb longwave radiation and radiates it back to the surface, thus contributing to warming.

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