An engineer is trying to determine the height from which she needs to release a 52kg wrecking ball
such that the wrecking ball will be traveling 12.3m/s when it strikes the building at the position
shown. Neglect drag.

Answer:

All but felicia are right I believe?

Explanation:

Answer:

16.6 kg.m/sec^2

Explanation:

force law is mass times acceleration

Answer:

0.62 m down.

Explanation:

Use the formula d= vi*t +1/2 at^2

So the initial speed or vi is -13 m/s and time is 2.7 s and a or acceleration is 9.8 m/s^2 down ( because it's the gravity). So you plugged all the values and you will get 0.62 m. We put the down because the acceleration is saying down. Because displacement is vector quantity you have to show the direction of it.

Answer:

near the equator

Explanation:

the equator is at the center of both hemispheres, and gets the most direct sunlight year round. Therefore, it would be the most tropical.

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (18.0 m/s − 0 m/s) / (6.00 s)

a = 3.00 m/s²

Momentum is mass time velocity.

p = mv

p = (8000 kg) (18.0 m/s)

p = 144,000 kg m/s

When an 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds then the truck’s acceleration would be 3 m/s² and the momentum after it has reached this final velocity would be 144000 kgm/s.

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

Mathematically the formula of the momentum is

P = mv

where P is the momentum of the particle

m is the mass of the particle

v is the velocity by which the particle is moving

As given in the problem An 8000.0 kg truck starts off from rest and reaches a velocity of 18.0 m/s in 6.00 seconds

By using the first equation is given as follows

v = u + at

18 =0 + a×6

a = 3 m/s²

As given in the problem the final velocity of An 8000.0 kg truck is 18 m/s

the momentum is given by the formula

P = mv

P= 8000×18

P = 144000 kgm/s

Thus, the truck’s acceleration would be 3 m/s², and the momentum after it has reached this final velocity would be 144000 kgm/s.

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Answer:

190 is the average velocity.

Explanation:

Just add them together

Answer:

True

Explanation:

An object which moves in the negative direction has a negative velocity. If the object is slowing down then its acceleration vector is directed in the opposite direction as its motion (in this case, a positive acceleration).

Answer:

It is a weighted average of the masses of an element’s isotopes.

Explanation:

The best definition of the atom mass of an element is that it is a weighted average of the masses of an element's isotopes.

 Atomic mass  = ∑m[tex]_{i}[/tex] a[tex]_{i}[/tex]

where m[tex]_{i}[/tex] is the mass of the isotope i

            a[tex]_{i}[/tex] is the abundance of the isotope i

Answer:

none of them

Explanation:

Answer:

Did u forget to add a pic?

Explanation:

Answer:

Gravity, normal force, friction, and air resistance.

Explanation:

Assuming the ball is on earth, there is always gravity acted upon the object.

Since the problem said that the golf ball is moving throughout the air, we can tell that there will be air resistance and friction(air resistance is a type of friction). There is also normal force pushing on the ball as it bumps into the air, as the air is pushing back with an equal and opposite force.

I don't know what you mean by "applied", so I don't think there's that type of force exerted on the ball.

Lastly, tension only occurs when you pull a string/rope. There is no string/rope in this case, so there is no tension exerted on the ball.

I hope this helped you.

The force acting upon the golf ball which is traveling upward and rightward through the air is gravity, normal,  friction, and air resistance, so options A, C, E, and F are correct.

A force that prevents two solid objects from smoothly sliding or rolling over one another is known as friction. Despite the potential benefits of frictional forces, such as the traction needed to walk without slipping, they can still present a sizable amount of resistance to motion. Automobile engines use about 20% of their output to overcome frictional forces in moving parts.

The ball will always be affected by gravity if it is on earth. We can infer that there will be air resistance and friction because the issue said that the golf ball is traveling through the air (air resistance is a type of friction).

The air is pushing back on the ball with an equal and opposite force when it bumps into it, adding to the regular force that is pushing on it. Finally, tension can only be created by pulling a string or rope. Since there is no string or rope present, the ball is not under any tension.

Therefore, the force acting upon the golf ball which is traveling upward and rightward through the air is gravity, normal,  friction, and air resistance.

To know more about Friction:

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Answer:

its d

Explanation:

Answer:

6. Dolphins have two nasal passages

7. In a whale flipper there are:

Limbs: Cetacean flippers have the same bones as the forelimbs of other mammals. The humerus, radius, ulna, carpals, metacarpals and phalanges are all present. However, in cetaceans the radius and ulna (forearm) and humerus (upper arm) are fused.

Hope this helps! :D

Answer:

they have 2 nasal passages

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»Answer

【Contact forces involve push, pull and friction. A contact force is when two interacting objects are touching, for example: when you throw a ball you are using a contact force.】

hope it helps

can u give a thanks

thank you

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Answer:

Explanation:

A stretching routine should target most of the main muscles in the body and at least one stretching exercise per section of the body. Also in a work environment since individual's sizes, ages, and cultures vary you should design a routine that is for beginners and very easy and effective. Regardless, each individual should be able to move at their own pace and push as far as they are physically able. One such routine would be the one in the attached picture below which targets all major areas, is easy and effective. It starts at the neck muscles and works its way down the arms, back, and legs.

The frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct. Frequency is the inverse of the time period.

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

The given data in the problem is;

v is the speed of light =  2 x 10⁸ m/s

[tex]\lambda[/tex] is the wavelength = 2 x 10⁻³ m,

f is the frequency of the wave is to be found;

Frequency is given by the formula as,

[tex]\rm v = \lambda \times f \\\\\ \rm f = \frac{v}{\lambda} \\\\ \rm f = \frac{2 \times 10^8}{2 \times 10^-3} \\\\ \rm f = 1 \times 10^{11} \ Hz[/tex]

Hence the frequency of this wave will be 1 × 10¹¹ Hz. Option d is correct.

To learn more about the frequency reference  the link;

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Answer:

4.    0.12mm

5:

a. screw gauge

b. caliper

Answer:

0.11 mm

vernier calipers

im not sure about the sure about B

Explanation:

Answer:

yes

no

no

yes

Explanation:

Answer:

Power is measured in Watts

Answer:

The firecracker has chemical potential energy that is released when it is ignited.

Explanation:

Answer:

The answer is D.

Explanation:

This is because mass always remains constant and weight is dependent on a gravitational pull.

Answer:

c

Explanation:

Answer:

3

Explanation:

the change in velocity is 15, and if I'm right which I may not be you divide your change in velocity by your speed being 5 and get 3. i googled the equation to find acceleration and found a = v/t. this could be absolutely wrong but I hope it helps

Answer: DNA unzips before step 1

Explanation:

RNA is gotten from DNA.

Answer: (B)

Explanation:

im as shure this answer is right as the world is round and slightly slanted

Answer:

The time taken for the car to stop is 5.43 s.

The initial velocity of the car is 108.6 ft/s

Explanation:

The following data were obtained from the question:

Acceleration (a) = –20 ft/s² (since the car is coming to rest)

Distance travalled (s) = 295 ft

Final velocity (v) = 0 ft/s

Time taken (t) =?

Initial velocity (u) =?

Next, we shall determine the initial velocity of the car as shown below:

v² = u² + 2as

0² = u² + (2 × –20 × 295)

0 = u² + (–11800)

0 = u² – 11800

Collect like terms

0 + 11800 = u²

11800 = u²

Take the square root of both side

u = √11800

u = 108.6 ft/s

Therefore, the initial velocity of the car is 108.6 ft/s.

Finally, we shall determine the time taken for the car to stop as shown below:

Acceleration (a) = –20 ft/s² (since the car is coming to rest)

Final velocity (v) = 0 ft/s

Initial velocity (u) = 108.6 ft/s

Time taken (t) =?

v = u + at

0 = 108.6 + (–20 × t)

0 = 108.6 + (–20t)

0 = 108.6 – 20t

Collect like terms

0 – 108.6 = – 20t

– 108.6 = – 20t

Divide both side by –20

t = – 108.6 / –20

t = 5.43 s

Therefore, the time taken for the car to stop is 5.43 s.