An experiment is conducted such that an applied force is exerted on a 5kg object as it travels across a horizontal surface in which frictional forces are NOT considered to be negligible. A graph of the net force exerted on the object as a function of the object’s distance traveled is shown. How could a student use the graph to determine the net work done on the object?

Answers

Answer 1

If an experiment is conducted such that an applied force is exerted on an object, a student could use the graph to determine the net work done on the object.

The  graph of the net force exerted on the object as a function of the object’s distance traveled is attached below.

A student could use the graph to determine the net work done on the object by Calculating the area bound by the line of best fit and the horizontal axis from 0m to 5m

For more information on work done, visit

https://brainly.com/subject/physics

An Experiment Is Conducted Such That An Applied Force Is Exerted On A 5kg Object As It Travels Across
Answer 2

Answer:

D. There is not enough information that is known or can be obtained from the graph to determine the net work done on the object.

Explanation:

it’s the answer For Ap classroom


Related Questions

Question 17 (Essay Worth 5 points)
(02.06 HC)
Choose two spheres of Earth which interact when hot springs are formed. Use complete sentences to explain how they interact during this process
X2
= 12 Source
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Styles
Format
Font
Size
A- A -
Increase Indent

Answers

Answer:

geosphere and hydrosphere

Explanation:

what's the mass of the star rasalas?

Answers

Answer: The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg.

Explanation:

Answer:

The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg. which to calculate using this website is too large. To give idea of size, the Sun is 99.86% the mass of the solar system.

Explanation:

A 0.24 kg mass with a speed of 0.60 m/s has a head-on collision with a 0.26 kg mass that is traveling in the opposite direction at a speed of 0.20 m/s. Assuming that the collision is perfectly inelastic, what is the final speed of the combined masses?

Answers

The  final speed of the combined masses is 0.186m/s

According to the law of collision, the sum of the momentum of the bodies before the collision is equal to the momentum after the collision.

Mathematically;

m1u1 - m2u2 = (m1+m1)v

v is the final speed of the combined masses.

Substituting the given parameters;

0.24(0.6) - 0.26(0.2) = (0.24+0.26)v

0.144 - 0.052 = 0.5v

0.092 = 0.5v

v = 0.092/0.5

v = 0.184m/s

Hence the final speed of the combined masses is 0.186m/s

Learn more on collision here:  https://brainly.com/question/7538238

can someone explain it please ?​

Answers

Answer:

The value of [tex]\theta=63.43^0[/tex]

Explanation:

Range of projectile [tex]\mathrm{R}=\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}[/tex]

Height of projectile [tex]\mathrm{h}=\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}[/tex]

Here we have

[tex]R=2h\\\\\frac{\mathrm{u}^{2} \cdot \sin 2 \theta}{\mathrm{g}}=2\frac{\mathrm{u}^{2} \cdot \sin ^{2} \theta}{2 \cdot \mathrm{g}}\\\\\sin 2 \theta=\sin ^{2} \theta\\\\2\sin \theta\cos \theta=\sin ^{2} \theta\\\\\tan \theta=2\\\\\theta=63.43^0[/tex]

Range be R and height be h

[tex]\boxed{\sf R=\dfrac{u^2sin2\theta}{g}}[/tex]

[tex]\boxed{\sf h=\dfrac{u^2sin^2\theta}{2g}}[/tex]

u=initial velocitytheta is angle of projection.g=acceleration due to gravity

ATQ

[tex]\\ \sf\longmapsto R=2h[/tex]

[tex]\\ \sf\longmapsto \dfrac{u^2sin2\theta}{g}=\dfrac{2u^2sin^2\theta}{2g}[/tex]

Cancelling required ones

[tex]\\ \sf\longmapsto sin^2\theta=sin2\theta[/tex]

sin2O=2sinOcosO

[tex]\\ \sf\longmapsto sin^2\theta=2sin\theta cos\theta [/tex]

[tex]\\ \sf\longmapsto \dfrac{sin^2\theta}{sin\theta cos\theta=2[/tex]

[tex]\\ \sf\longmapsto \dfrac{sin\theta}{cos\theta}=2[/tex]

[tex]\\ \sf\longmapsto tan\theta=2[/tex]

[tex]\\ \sf\longmapsto \theta=tan^{-1}(2)[/tex]

[tex]\\ \sf\longmapsto \theta=63.4°[/tex]

me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car accelerates from 20 m/s to 30 m/s in 10 (a) Calculate the car's acceleration using v=utat. (b) Draw a velocity-time graph to show the car's motion. Find the distance it travels by calculating the area under the graph. (c) Check your answer by using the equation s = ut + hat Grade 9​

Answers

Answer:

5)

Solution

initial velocity = 15 m/s

acceleration = 3m/s^2

time = 4 s

final velocity = 15+3×4

=15+12

=27m/s

A car accelerates from 20m/s to 30m/s in 10 second

T9 be honest I think some part of the second question is missing

A wave has wavelength of 10 m and a speed of 340 m/s. What is the frequency of the wave?
I need the Formula,Known,Substitute & Solve Answer with Units

Answers

Answer:

This is the answer that I got.

Explanation:

Hope it is right.

A 600g toy train completes 10 laps of its circular track in 1 min 20s. If the radius of the track is 1.2 m, Find the speed of the train in m/s.

Answers

Answer:

0.236  m/s² (rounded)

Explanation:

A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back on it with a 68 N horizontal force.
Part A
How much work does Paige do on the crate as it slides 3.0 m down the ramp?

Answers

Answer:

the answer is 69.7687j

Explanation:

W =F sin Φ

Select the correct answer. What are the directions of an object's velocity and acceleration vectors when the object moves in a circular path with a constant speed? A. The question is meaningless, since the acceleration is zero.
B. The vectors point in opposite directions.
C. Both vectors point in the same direction.
D. The vectors are perpendicular.

Answers

The centripetal acceleration which always  act toward the center of the circle. The vectors are perpendicular. The correct answer for this question, is option D

The speed of an object is always constant in a  circular motion while the object keeps changing direction regularly. The velocity will keep changing because of the change in direction.

Whenever there is a change in velocity, there must be acceleration.

When the object is moving in a circular path with a constant speed, the directions of an object's velocity and acceleration vectors will be perpendicular to each other

The reason is because acceleration is centripetal acceleration which always  act toward the center of the circle.

Therefore, the correct answer for this question, is option D

Learn more about circular motion here: https://brainly.com/question/10493657

Heat always moves from hot to cold through the processes of?

Answers

Answer: The processes are conduction, convection and radiation.

Explanation: Unless people interfere, thermal energy — or heat — naturally flows in one direction only: from hot toward cold. Heat moves naturally by any of three means. The processes are known as conduction, convection and radiation. Sometimes more than one may occur at the same time.

if A and B are non zero vectors, is it possible for vector A×vector B and vector A.vector B both to be zero? Justify your answer​

Answers

Answer:

not able to understand the question

A cheetah runs at an average speed of 60mph. find the distance it runs in 30 s

Answers

Answer:60mph means it runs every minute.

Explanation: because it makes sense.

Answer:

  2640 ft, or 1/2 mile

Explanation:

Recognizing that 30 s = 0.5 min, we can convert the units like this.

  distance = speed × time

  distance = (60 mi/h) × (1 h/(60 min)) ×(0.5 min) = 0.5 mi

In feet, that is ...

  (5280 ft/mi)(0.5 mi) = 2640 ft

A cheetah runs 1/2 mile, or 2640 feet in 30 s.

0. Kedija walked 300m from A to B and returned back and walked 200m and then stopped at 'C', what
is her change in position from A to in the figure below
300m
200m
A
С
B
C/-500m
D 100m
B/ -100m
A Soom

Answers

Answer:

100

Explanation:

Displacement is the shortest line between the starting point and the ending point

so , the starting point is "A"

,the ending point is "C"

so "AC" = AB - CB = 300 - 200 = "100"

1)A chocolate bar measures 10 cm long by 2 cm wide and is 2 cm thick
a)Calculate the volume of one bar.

b)How many bars each 2 cm long, 2 cm wide and 2cm thick have the same total volume?

c)A pendulum makes 10 complete oscillations in 8 seconds. Calculate the time period of the pendulum​

Answers

Answer:

40cm³

Explanation:

I only have an answer to 1a

Volume = Length X breadth X height

where;

length = 10cm

breadth = 2cm and;

width = 2cm

*Find*

V = ?

V = L X B X H

V = 10 X 2 X 2

= 40cm³✓

how is one kg mass defined in SI system​

Answers

Answer:

It is originally defined as the mass of one liter (10-3 cubic meter) of pure water.

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.626 070 15 × 10-34 when expressed in the unit J s, which is equal to kg m2 s -1 , where the meter and the second are defined in terms of c and ∆νCs.

The mass of a car is 2000 lbs, and is traveling 100 mi/hr on the freeway, what is its momentum?

Answers

Answer:

momentum= 145999324.8(kg(m/s))

Explanation:

formula for momentum: p=mv

where p= momentum, m=mass, and v=velocity.

p=2000lbs(100mi/hr)

The standard unit for mass is kg

2000lbs=907.2kg

standard unit for velocity is meters/sec

100mi=160934meters.

907.2kg(160934m/s)=145999324.8

Name the force used in removing iron scrap from a heap of mixed scrap. (a) Magnetic Force (b) Electrostatic force (c) Gravitational force (d) Friction Force​

Answers

Answer:

magnetic force

Explanation:

because iron is magnetic so magnet is able to attract iton

define one kilogram mass ​

Answers

Answer:

kg - one thousand grams; the basic unit of mass adopted under the Systeme International d'Unites; "a kilogram is approximately 2.2 pounds"

Explanation:

Read the excerpt from The Building of Manhattan.

A temporary, small narrow-gauge track system was installed on each floor as it was needed. This enabled the material to be moved from the truck at ground level onto dump carts, raised by elevator to the designated floor, wheeled onto the track, and moved quickly to the exact spot needed. Turntables built into the track allowed the carts to be shifted about in any direction.

Which question can be answered only if an illustration accompanies the text?

What did turntables built into the track allow?
How were dump carts raised to designated floors?
When was a track system installed on a floor?
What does a turntable built into a track loo

Answers

Answer: this would be D.) What does a turntable built into a track look like

Explanation:

if a 5kg ball is traveling at 20 m/s and it’s stopped in 4s, what’s the impulse on the ball?

Answers

FT=MV

F(4)=(5)(20)

F= 100/4

F= 25 N

A 2,000 kg car, initially traveling at a speed of 15 m/s, is accelerated by a constant force of 10,000 N for 3 seconds. The new speed of the car is

Answers

Mass (m) = 2000 KgInitial velocity (u) = 15 m/sForce (F) = 10000 NTime (t) = 3 sLet the acceleration be a.We know, F = ma,Therefore, 10000 N = 2000 Kg × a or, a = 10000 N ÷ 2000 Kg = 5 m/s^2Let the final velocity be v.By using the equation of motion, v = u + at, we getv = 15 m/s + 5 m/s^2 × 3 sor, v = 15 m/s + 15 m/s = 30 m/s

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

A 1,500 kg car is traveling at 25 m/s. The driver suddenly applies the brakes causing the car to skids to a stop. If the average braking force between the tires and the road is 7,100 N, how far does the car slide before it comes to rest?​

Answers

By Newton's second law, the car slows down with an average acceleration a such that

-7100 N = (1500 kg) a   ⇒   a ≈ -4.7 m/s²

If we treat the car as accelerating uniformly with this magnitude, then the car slides a distance ∆x such that

0² - (25 m/s)² = 2a ∆x   ⇒   ∆x ≈ 66 m

The car slide before it comes to rest will be 66 m. Newton's second equation of motion is applied in this problem.

What is force?

Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Force is defined as the product of mass and acceleration. Its unit is Newton.

The acceleration is found as;

F=ma

-7100 N = (1500 kg) a

a= -4.7 m/s²

If we assume that the automobile accelerates uniformly with this magnitude, the car slides x distance. From the Newton's second equation of motion;

v²=u²+2as

v²-u²=2as

0² - (25 m/s)² =2×(-4.7) s  

s=66 m

Hence,the car slide before it comes to rest will be 66 m.

To learn more about the force, refer to the link;

https://brainly.com/question/26115859

#SPJ2

The average distance between the Earth and the Moon is 384,000,000 meters. What is the distance in kilometers?

Answers

Answer:

384000

Explanation:

it would be 384000 in km

384000
Because 1 meter is 0.001 kilometer so you multiply 384000000 times 0.001

An EMT raceway contains two 3-phase, 480-volt branch circuits. What minimum size THHN branch circuit conductor is required for one of the circuits when it supplies a noncontinuous load of 27 kW?

Answers

Answer:8 AWG

Explanation: 6 current carrying conductors with 2 - 3 phase branch circuits. Divide 27000 by (480v × 1.732 or square root of 3) and you get 32.46 amps. Now using the code book, divide 32.46 by the adjustment factor of 6 CCC's which is .8 and you get 40.61 amps. Now go to Table 310.16 in the 2020 NEC book and you'll see that in the 90° column that 40.61 amps is above #10 AWG so you size up to #8 AWG.

Which metals can be extracted from following ores (i) Argentite (ii) Haematite (iii) Chalcopyrite (iv) Bauxite​

Answers

Answer

1) iron

2) Aluminium

3) sliver

4) copper

I hope it's helpful for you ☺️

Answer

1) iron

2) aluminium

3) silver

4) copper

what planets experience an eclipse from the sun

Answers

Answer:

Earth

Explanation:

The sun and the moon come together and they seem like one bonded.

HELPPP PLEASE
1) if the distance between two masses are 15 meters and the masses are 350kg and 492 kg
respectively; what is the magnitude of gravitational force?

Answers

Answer:

-8

5.092×10

Explanation:

given,

distance (d) =15m

mass (M1) =350kg

mass(M2) = 492kg

Gravitational constant (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×350×492)÷15^2

= (1.14857×10^-5)÷225

= 5.092×10^-8

Anyone please help thank you

Answers

Answer:

A) earth

B) live

C) live

D) earth

Explanation:

hope i help

is atom on the offficial repository of ubuntu ?

Answers

Answer:

Atom, the cross-platform, open source code editor developed by Github, has become quite popular thanks to its plug-ins and embedded Git Control. ... There are, however, official Atom repositories for some Linux distributions, like Ubuntu, Debian, Fedora, Red Hat, CentOS, and open.

PLEASE HELP also i know this isnt physics but there was no HOPE/Gym subject for me to choose.

Answers

Answer:

Plan B.

Because flexibility is best improved by stretching.

Explanation:

Improving and increasing flexibility is done by having stretching sessions daily which maintains and widens the range of motion in the joints and stretches muscles.

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