Answer:
A. Provide both heat and power to homes
You will observe the orbits and you have to determine how many planets are in the habitable zone and how many are orbiting successfully. Based on the mass of the star and the placements of the planets, planets may swerve into the star and vanish, collide with each other and vanish, float out of orbit, or all orbit successfully. You will record this information and each planet's orbit in your data table for each trial. If the mass of the sun is 1x, planets will fall into the habitable zone if I place a planet in orbits (Orbit=1,2,3,4,5,6,7,8), and all planets will orbit the sun successfully.
If the mass of the sun is 2x, planets will fall into the habitable zone if I place a planet in orbits (Orbit=1,2,3,4,5,6,7,8), and all planets will orbit the sun successfully.
If the mass of the sun is 3x, planets will fall into the habitable zone if I place a planet in orbits (Orbit=1,2,3,4,5,6,7,8), and all planets will orbit the sun successfully.
Answer:t of orbit, or all orbit successfully. You will record this information and each planet's orbit in your data table for each trial. If the mass of the sun is 1x, planets will fall into the habitable zone if I place a planet in orbits (Orbit=1,2,3,4,5,6,7,8), and all planets will orbit the sun successfully.
If the mass of the sun is 2x, planets will fall into the habitable zone if I place a planet in orbits (Orbit=1,2,3,4,5,6,7,8), and all planets will orbit the sun successfully.
If the mass of the sun is 3x, planets will fall into the habitable zo
Explanation:
what is the name of a mixture that is easily seen and separated???
Answer:
suspension
Explanation:
a mixture in which particles can be seen and easily separated by settling or filtration.
hope this helps
Answer:
Heterogeneous
Explanation:
The difference between Homogeneous and Heterogeneous mixtures are homogeneous are blended evenly and inseparable like soup, while heterogenous are like salads, you can take it apart
A sample of a pure substance with a density of 3 g/mL is separated into two pieces. One piece has a mass of 50 g and the other piece has a mass of 25 g.
What is the density of the larger piece?
Answer: The two pieces have the same density of 3g/mL.
Explanation: the density won't change based on the size or amount of the substance. the density is pre-set (for every X there is y weight, this is always constant).
What are some of the benefits of hydropower? select all that apply
Select 3 correct answer(s)
Question 2 options:
It can also provide flood control and water supply
It is renewable and reliable
It can prevent fish from swimming upstream
It reduces the amount of carbon dioxide released into the atmosphere during energy production
Answer: It can provide flood control and water supply. It is renewable and reliable. It reduces the amount of carbon dioxide released into the atmosphere during energy production. I believe these are the answers.
Weather fronts tend to produce changes in the weather
True
False
Answer:
True
Explanation:
You have a substance with a length of 2 cm, width of 3 cm, and a height of 4 cm. Its density is known to be .5 g/cm3. What is the mass of the sample you have?
Explanation:
They are related by the the density triangle.
Explanation:
They are related by the the density triangle.
mcdn1.teacherspayteachers.com
d =
m
V
m = d×V
V =
m
d
DENSITY
Density is defined as mass per unit volume.
d =
m
V
Example:
A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?
Step 1: Calculate the volume
V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³
Step 2: Calculate the density
d =
m
V
=
433
g
200
c
m
³
= 2.16 g/cm³
MASS
d =
m
V
We can rearrange this to get the expression for the mass.
m = d×V
Example:
If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?
m = d×V = 500 mL ×
1.11
g
1
m
L
= 555 g
VOLUME
d =
m
V
We can rearrange this to get the expression for the volume.
V =
m
d
Example:
What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.
Step 1: Convert kilograms to grams.
14.83 kg ×
1000
g
1
k
g
= 14 830 g
Step 2: Calculate the volume.
V =
m
d
= 14 830 g ×
1
c
m
³
19.32
g
= 767.6 cm³